How long will it take an investment to double with a 5% annual interest rate compounded monthly?

Answer:

Step-by-step explanation:

from the pic

cos(30deg) = 4√3 / y = √3 / 2

y = 4 * 2 = 8

sin(30deg) = x/y = 1/2

x = y/2 = 8/2 = 4

ans is x = 4, y = 8

Answer:

Step-by-step explanation:

As the given triangle is a right-angled triangle,

tan(30degree) = x / (4√3) = 1/√3

x = 4

sin(30degree) = x / y = 1/2

y = 8

The within-group estimate of variance is the estimate of the variance of the population of individuals based on the variation among the scores in each of the actual groups studied.

The within-groups estimate of variance is the estimate of the variance of the population of individuals based on the variation among the:
Scores in each of the actual groups studied.
This estimate represents the variation within each group and helps in understanding the population's variance by looking at individual differences within the groups.

The estimated within-group variance is the sum of the within-group variances for each group in the model. Effectively, this is the sum of the variance of each value (j) from its group (i) divided by the sample size minus one.

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The exact angles in radians and in the interval π/6 [0, π] are:

\(cos^{-1}\)(-√(3)/2) = 7π/6

\(cos^{-1}\)(0) = π/2

\(cos^{-1}\)(√(2)/2) = π/4

The cosine inverse function, also known as the arccosine function, is the inverse function of the cosine function. It takes a value between -1 and 1 and returns the corresponding angle between 0 and π (or 0 and 180 degrees) whose cosine is that value. The notation for the cosine inverse function is cos⁻¹ or arccos.

For example, cos⁻¹(1/2) = π/3, since the cosine of π/3 is 1/2.

\(cos^{-1}\)(-√(3)/2) is in the second quadrant where cosine is negative. Using the unit circle, we can see that this angle is π/6 + pi = 7π/6.

\(cos^{-1}\)(0) is in the first and second quadrants where cosine is 0. This means the possible angles are π/2 and 3π/2. However, since we are only considering angles in the interval pi/6 [0, pi], the answer is π/2.

\(cos^{-1}\)(√(2)/2) is in the first quadrant where cosine is positive. Using the unit circle, we can see that this angle is π/4.

Therefore, the exact angles in radians and in the interval π/6 [0, pi] are:

\(cos^{-1}\)(-√(3)/2) = 7π/6

\(cos^{-1}\)(0) = π/2

\(cos^{-1}\)(√(2)/2) = π/4

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The exact angles in radians and in the interval π/6 [0, π] are:

\(cos^{-1}\)(-√(3)/2) = 7π/6

\(cos^{-1}\)(0) = π/2

\(cos^{-1}\)(√(2)/2) = π/4

The cosine inverse function, also known as the arccosine function, is the inverse function of the cosine function. It takes a value between -1 and 1 and returns the corresponding angle between 0 and π (or 0 and 180 degrees) whose cosine is that value. The notation for the cosine inverse function is cos⁻¹ or arccos.

For example, cos⁻¹(1/2) = π/3, since the cosine of π/3 is 1/2.

\(cos^{-1}\)(-√(3)/2) is in the second quadrant where cosine is negative. Using the unit circle, we can see that this angle is π/6 + pi = 7π/6.

\(cos^{-1}\)(0) is in the first and second quadrants where cosine is 0. This means the possible angles are π/2 and 3π/2. However, since we are only considering angles in the interval pi/6 [0, pi], the answer is π/2.

\(cos^{-1}\)(√(2)/2) is in the first quadrant where cosine is positive. Using the unit circle, we can see that this angle is π/4.

Therefore, the exact angles in radians and in the interval π/6 [0, pi] are:

\(cos^{-1}\)(-√(3)/2) = 7π/6

\(cos^{-1}\)(0) = π/2

\(cos^{-1}\)(√(2)/2) = π/4

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Answer:s

12 weeks

Step-by-step explanation:

if keith starts with $500 and wants to end with (at least) $200

he can withdrawn up to $500-$200=$300

if he withdraws $25 week the $300 will last $300 $25 week =12 weeks

so this is the solution to the problem.

Money that Keith has  at the beginning of the summer = $ 500 )

Money that keith  wants to have at the end of the summer = At least $200

Money that Keith withdraws every week =$25

Let w to represent the number of weeks in the summer

In consequence , the correct inequality should be:

Amount at the beginning of the summer- money withdrawn every week ≥ money at the end of the summer

Replacing with the values we know:

500-25w≥200. The correct answer is A.

PLEASE MARK ME BRAINLIEST

The optimal parenthesization for the matrix chain with dimensions <10, 5, 10, 4, 8> is ((M1 x (M2 x M3)) x (M4 x M5)). The computational complexity is O(n^3) and the real cost depends on the dimensions and order of multiplication of the matrices involved.

Matrix Chain Multiplication Algorithm:

Let's denote the sequence of dimensions as D = <10, 5, 10, 4, 8>. We define two matrices: M, for storing the minimum number of scalar multiplications, and S, for storing the optimal split positions.

a) Initialize the matrices M and S with appropriate dimensions based on the size of the sequence D.

b) Set the diagonal elements of M to 0 since multiplying a single matrix requires no scalar multiplications.

c) Perform a bottom-up evaluation of M and S, filling in the values based on the recurrence relation:

M[i, j] = min{M[i, k] + M[k+1, j] + D[i-1] * D[k] * D[j]}, for i ≤ k < j

The optimal parenthesization can be obtained by backtracking through the S matrix.

Optimal Parenthesization for the given sequence D = <10, 5, 10, 4, 8>:

After applying the matrix chain multiplication algorithm, the optimal parenthesization is as follows:

((M1 x (M2 x M3)) x (M4 x M5))

Computational Complexity and Real Cost:

The computational complexity of calculating the matrix chain product using the optimal parenthesization depends on the size of the matrix chain. In the matrix chain multiplication algorithm, we have to fill in the entries of the M and S matrices, which takes O(n^3) operations, where n is the number of matrices in the chain.

The real cost of calculating the matrix chain product involves performing scalar multiplications and additions. The number of scalar multiplications required is equal to the minimum number of scalar multiplications stored in the M matrix, i.e., M[1, n-1]. The real cost can be calculated by summing the products of the dimensions of the matrices involved in the optimal parenthesization.

For example, if we have three matrices with dimensions A[10x5], B[5x10], and C[10x4], and the optimal parenthesization is (A x B) x C, then the real cost is (10510) + (10104) = 500 + 400 = 900.

In general, the real cost of calculating the matrix chain product depends on the dimensions and the order of multiplication of the matrices involved.

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The diver's velocity during the first 2 sec of fall using the modified Euler method with Ar= 0.2 is 62.732 mph.

Given data: Initial velocity, u = 0 ft/sec

Acceleration, a = g = 32.2 ft/sec²

The maximum rate of fall, vmax = 80 mph

Time, t = 2 seconds

Air resistance constant, Ar = 0.2

We are supposed to determine the sky diver's velocity during the first 2 seconds of fall using the modified Euler method.

The governing equation for the velocity of the skydiver is given by the following:

ma = -m * g + k * v²

where, m = mass of the skydive

r, g = acceleration due to gravity, k = air resistance constant, and v = velocity of the skydiver.

The equation can be written as,

v' = -g + (k / m) * v²

Here, v' = dv/dt = acceleration

Hence, the modified Euler's formula for the velocity can be written as

v1 = v0 + h * v'0.5 * (v'0 + v'1)

where, v0 = 0 ft/sec, h = 2 sec, and v'0 = -g + (k / m) * v0² = -g = -32.2 ft/sec²

As the initial velocity of the skydiver is zero, we can write

v1 = 0 + 2 * (-32.2 + (0.2 / 68.956) * 0²)0.5 * (-32.2 + (-32.2 + (0.2 / 68.956) * 0.5² * (-32.2 + (-32.2 + (0.2 / 68.956) * 0²)))

v1 = 62.732 mph

Therefore, the skydiver's velocity during the first 2 seconds of fall using the modified Euler method with Ar= 0.2 is 62.732 mph.

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Answer: 80 ways

Step-by-step explanation:

If 8 tee shirts can be worn in 8 ways  

similarly for 2 belts = 2 ways

five pair of jeans= 5 ways  

so total number of ways=5*2*8=80 ways

If the temperature is -5 degrees in one city and it is four degrees less in another city, the temperature in the other city would be -9 degrees.

This is because subtracting four from -5 results in a decrease of four units, giving us -9 degrees.

In the given scenario, the temperature in the other city is four degrees less than the temperature in the first city. When we subtract four from the original temperature of -5 degrees, we obtain -9 degrees.

Thus, the temperature in the other city is -9 degrees, indicating that it is colder by four degrees compared to the first city.

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Step-by-step explanation:

(3 + 2i)(1 + iy)

= 3 + (3y + 2)i - 2y (because i² = -1)

For this to be real, (3y + 2) = 0. => y = -2/3

For this to be imaginary, y can be any real or complex number (except -2/3)

Answer: its C

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Teniendo en cuenta la regla de tres simple, el cartero reparte 64.200 cartas en un semestre.

La regla de tres es una forma de resolver problemas de proporcionalidad entre tres valores conocidos y un valor desconocido, estableciendo una relación de proporcionalidad entre todos ellos.

Es decir, lo que se pretende con ella es encontrar el cuarto término de una proporción conociendo los otros tres.

Si la relación entre las magnitudes es directa, es decir, cuando una magnitud aumenta, la otra también (o cuando una magnitud disminuye, la otra también), se debe aplicar la regla de tres directa.

Para resolver una regla de tres directa se debe seguir la siguiente fórmula, siendo a, b y c datos conocidos y x la variable a calcular:

a ⇒ b

c ⇒ x

Entonces: \(x=\frac{cxb}{a}\)

En este caso, se puede aplicar la regla de tres de la siguiente manera: Entonces, si el cartero en un mes reparte 10.700 cartas, ¿en 6 meses (un semestre) reparte cuántas cartas?

1 mes ⇒ 10.700 cartas

6 meses ⇒ ×

Entonces: \(cantidad de cartas=\frac{6 mesesx10.700 cartas}{1 mes}\)

Resolviendo:

cantidad de cartas= 64.200 cartas

En resumen, el cartero reparte 64.200 cartas en un semestre.

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The numerical value of each expression,

a. cosh(ln(5)) = 2.50258.

b. cosh(5) = 74.20995.

(a) Using the identity cosh(x) = (\(e^x\) + \(e^{(-x)}\))/2 and substituting x = ln(5), we get:

To find cosh(ln(5)), we first evaluate ln(5) which is approximately equal to 1.60944.

cosh(ln(5)) = (\(e^{(ln(5)}\)) + \(e^{(-ln(5)}\)))/2

= (5 + 1/5)/2

= 2.50258

Therefore, cosh(ln(5)) = 2.50258 (rounded to five decimal places).

(b) Using the identity cosh(x) = (\(e^x\) + \(e^{(-x)}\))/2 and substituting x = 5, we get:

cosh(5) = (\(e^5\) + \(e^{(-5)}\))/2

= (148.41316 + 0.00674)/2

= 74.20995

Therefore, cosh(5) = 74.20995 (rounded to five decimal places).

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============================================

Work Shown:

3 & 1/2 = 3 + 1/2 = 3 + 0.5 = 3.5

3.5% = 3.5/100 = 0.035

r = 0.035 is the decimal form of \(3\frac{1}{2}\%\) which is used along with

to get the following

A = P*(1+r/n)^(nt)

A = 500*(1+0.035/12)^(12*0.5)

A = 508.81405074594

A = 508.81

Extra info: Gabe earned A-P = 508.81 - 500 = 8.81 dollars in interest.

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Below is the answer to the questions:

Q 12.

The prediction is that there were about 260 principals in attendance at the conference.

Q13.

The best prediction is that the college will have about 480 students who prefer cookies.

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Answer:

The perimeter of the triangle is 30 cm.

The perimeter of the rectangle is also 30 cm.

Step-by-step explanation:

The perimeter of the triangle is 30 cm.

The perimeter of the rectangle is also 30 cm.

distance ≈ [v(0) + v(0.5) + v(1) + v(1.5)]Δt = 0 + 260 + 520 + 780 = 655 miles. Therefore, the distance traveled by the vehicle over the first two hours is approximately 655 miles.

For the first part, we can use a left sum with 4 rectangles to approximate the distance traveled by the vehicle over the first two hours. The velocity function is v(t) = 520t, so the distance traveled is given by the definite integral of v(t) from 0 to 2:

\(distance = \int\limits^2_0 \, v(t) dt\)

Using a left sum with 4 rectangles, we have:

distance ≈ [v(0) + v(0.5) + v(1) + v(1.5)]Δt = 0 + 260 + 520 + 780 = 655 miles

Therefore, the distance traveled by the vehicle over the first two hours is approximately 655 miles.

For the second part, we are asked to compute the left and right sums for the area between the function f(x) = 2 - 0.5x² and the x-axis over the interval [-1, 2] using 3 rectangles. We can use the formula for the area of a rectangle to find the area of each rectangle and then add them up to find the total area.

Using 3 rectangles, we have Δx = (2 - (-1))/3 = 1. The left endpoints for the rectangles are -1, 0, and 1, and the right endpoints are 0, 1, and 2. Therefore, the left sum is:

AL = f(-1)Δx + f(0)Δx + f(1)Δx = [2 - 0.5(-1)²]1 + [2 - 0.5(0)²]1 + [2 - 0.5(1)²]1 = 5

The right sum is:

AR = f(0)Δx + f(1)Δx + f(2)Δx = [2 - 0.5(0)²]1 + [2 - 0.5(1)²]1 + [2 - 0.5(2)²]1 = 72

Therefore, the left sum is 5 and the right sum is 72 for the area between the function f(x) = 2 - 0.5x² and the x-axis over the interval [-1, 2] using 3 rectangles.

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32 - 7 = 25/5 = 5

so, we have 5 products being purchased, since the 7 sec check-out doesn't count as product time.

hope it helps :)

Answer:

5 items

Step-by-step explanation:

32 - 7 = 25

25 / 5 = 5

This means that 5 items are being purchased.

Hope it helps c:

Given that a = 8 cm and b = 21 cm, the value of A is 20.9 degrees

The complete question is added as an attachment

From the question, we have the following parameters that can be used in our computation:

a = 8 cm and b = 21 cm

Using the tangent function, we have

tan(A) = a/b

So, we have

tan(A) = 8/21

Evaluate

tan(A) = 0.3810

Take the arctan of both sides

A = 20.9 degrees

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Answer:

there is no question. but these are two of the same lines with different Y-intercepts.

The linear equations are x + y = 679, 4x + 7y = 3370 and  586 non-students attended the play.

What is a linear equation, exactly?

A linear equation is a mathematical equation that describes a straight line when plotted on a graph. It is an equation in which the highest power of the variable is one. Linear equations are commonly written in the form of y = mx + b, where "x" and "y" are variables, "m" is the slope of the line, and "b" is the y-intercept. Linear equations can be used to model many real-world situations, such as distance and speed, cost and revenue, and temperature and time.

Now,

a) Let x = student tickets sold and y = number of non-student tickets sold. Then we have the following system of linear equations:

x + y = 679 (the total number of tickets sold is 679)

4x + 7y = 3370 (the total revenue from ticket sales is $3370)

b) To solve for y, we can use the first equation to get:

y = 679 - x

then,

4x + 7(679 - x) = 3370

Simplifying and solving for x, we get:

3x = 2363

x = 787

So 787 student tickets were sold. To find the number of non-student tickets sold, we can use the equation y = 679 - x:

y = 679 - 787 = -108

Since it doesn't make sense to have a negative number of non-student tickets sold, we made an error somewhere. Looking at the problem again, we realize that the equation should be:

x + y = 679 (the total number of tickets sold is 679)

4x + 7y = 3370 (the total revenue from ticket sales is $3370)

where y represents the number of student tickets sold and x represents the number of non-student tickets sold. With this correction, we get:

y = 679 - x

4(679 - x) + 7x = 3370

Simplifying and solving for x, we get:

3x = 1759

x = 586.33

x = 586

So 586 non-student tickets were sold.

Which means 586 non-students attended the play.

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Answer:

B

Step-by-step explanation:

The area of the biggest rectangle =

\((9x - 2)(2x + 7) = 18 {x}^{2} + 63x - 4x - 14 = 18 {x}^{2} + 59x - 14\)

The area of the of the smallest rectangle inside=

\(3x(x + 12) = 3 {x }^{2} + 36x\)

Then the area of the shaded region =

\(18 {x}^{2} + 59x - 14 - (3 {x}^{2} + 36x) = 18 {x}^{2} + 59x - 14 - 3 {x}^{2} - 36x = 15 {x}^{2} + 23x - 14\)

So, we choose B.

Answer:

40 and 16 for 8 servings

25 and 10 for 5 servings

15 and 6 for 3 servings

Step-by-step explanation:

Answer:

40 and 16 for 8 servings

25 and 10 for 5 servings

15 and 6 for 3 servings

Step-by-step explanation:

Hope its right :)

An equation highlighting the discount: y = (65 - 7)x

A simpler equation: y = 58x

The coordinates of the point N dividing the line LM, with L(-3, 1) and N(4, 9) in the ratio 2:3, found using the internal section formula is \(\left(-\frac{1}{5} ,\, \frac{21}{5} \right)\)

A ratio indicates the number of times one quantity a is contained in another quantity b.

The coordinates of the point L = (-3, 1), the coordinates of the point M = (4, 9)

The ratio in which the point N divides LM = 2:3

The specified ratio of the sides are;

\(\dfrac{LN}{MN} = \dfrac{2}{3}\)

The coordinates of the points N is found using the internal section  formula as follows;

\(C(x, y) = \left(\frac{m\times x_2 + n\times x_1}{m+n} , \,\frac{m\times y_2 + n\times y_1}{m+n} \right)\)

Where;

(x₁, y₂), and (x₂, y₂) are the endpoints of the line

m:n is the ratio the point C divides the line

Which indicates;

\(N(x, y) = \left(\frac{2\times 4 + 3\times (-3)}{2+3} , \,\frac{2\times 9 + 3\times 1}{2+3} \right) = \left(-\frac{1}{5} ,\, \frac{21}{5} \right)\)

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Answer:

Step-by-step explanation:

f(x) * g(x) = (5x**2) * (x**3 + 2x**2 - 5x) using distribution of 5x**2 to all terms

              = 5x**5 + 10x**4 - 25x**3

              = 5x**3(x**2 + 2x - x)

Answer:

its either got to be c or b but id go with the one that you thank it is

Step-by-step explanation:

Answer:

Option B - Darin scores in a basketball game is 19 Points

Step-by-step explanation:

Darin scores in a basketball game = 3s + 2t + u

where s is the number of three-point field goals made,

t is the number of two-point field goals made,

u is the number of free throws made.

Darin scores in a basketball game = 3(2) + 2(5) + 3

= 6 + 10 + 3

= 19 Points

Hope this helps!

When a transversal cuts two parallel lines, 8 angles are created.

When two lines do not cross one another, they are said to be parallel. In addition, parallel lines are two lines that cross each other at infinity.

A transversal line is one that crosses two other lines at two different locations. Line l meets a and b in the image below at two different locations, P and Q. Line l is the transversal line as a result.

Corresponding angles are those that are created when two parallel lines and a transversal intersect, also known as matching corners or corresponding corners.

∠1 and ∠6

∠4 and ∠8

∠2 and ∠5

∠3 and ∠7

When a transversal connects two coplanar lines, alternate interior angles are created.

∠4 and ∠5

∠3 and ∠6

However, each pair of alternate interior angles is equal if a transversal meets two parallel lines.

∠4 = ∠5

∠3 = ∠6

The pair of angles that are created on the outer side of two lines but on the other side of the transversal are known as alternate exterior angles.

Consecutive interior angles, related angles, and co-interior angles are other names for interior angles that are on the same side of the transversal.

∠3 and ∠5

∠4 and ∠6

When a transversal cuts two parallel lines, 8 angles are created.

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∠1 and ∠6

∠4 and ∠8

∠2 and ∠5

∠3 and ∠7

When a transversal connects two coplanar lines, alternate interior angles are created.

∠4 and ∠5

∠3 and ∠6

However, each pair of alternate interior angles is equal if a transversal meets two parallel lines.

∠4 = ∠5

∠3 = ∠6

Consecutive interior angles, related angles, and co-interior angles are other names for interior angles that are on the same side of the transversal.

∠3 and ∠5

∠4 and ∠6