How long should the Sun's core generate energy at present rates?
Answers
Answer: The Sun's core generates energy through nuclear fusion, specifically the fusion of hydrogen nuclei (protons) into helium nuclei. This process releases a tremendous amount of energy in the form of light and heat, which is what makes the Sun shine.
The current estimate for the age of the Sun is about 4.6 billion years, and it is currently in the middle of its main sequence phase, where it is burning hydrogen into helium in its core. It is estimated that the Sun has been in this phase for about 4.6 billion years, and it will continue to burn hydrogen in its core for another approximately 5 billion years, based on our current understanding of stellar evolution.
So, at the present rates of energy generation in the Sun's core, it is estimated that the Sun will continue to generate energy for another 5 billion years. However, it is worth noting that as the Sun ages, it will gradually evolve and change, eventually entering a phase of expanding into a red giant, and ultimately shedding its outer layers to become a white dwarf. The exact timeline and details of these changes are still a subject of ongoing scientific research and investigation.
Related Questions
A city gets its electricity from a dam, where water is stored in a reservoir. How does the water provide the city with its power?(1 point) Responses
Answers
Water in the dam provides the city with its power through the water turning the turbines and the generator converting the mechanical energy into electricity.
What is a Dam?This is referred to as a type of a barrier that stops or restricts the flow of surface water and is used for various types of purposes.
The water which is present in the dam has kinetic energy which is converted to mechanical energy when the turbines are turned. The generator then converts the mechanical energy into electricity which is used by the inhabitants of trhe city to power their appliances.
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Answer:
(Question) A city gets its electricity from a dam, where water is stored in a reservoir. How does the water provide the city with its power?
(Answer) Potential energy in the water becomes kinetic energy as it moves through turbines, which turn kinetic energy into mechanical energy that spins a generator, which changes mechanical energy into electricity.
(Question) An acorn rolls off a roof and falls to the ground. Which statement best describes the change in energy?
(Answer) The acorn’s potential energy decreases as its kinetic energy increases.
(Question) An airplane carries 320 passengers from Phoenix to Los Angeles flying at an average speed of 490 miles per hour. On the return flight, the plane carries 164 passengers and travels at the same average speed. What happens to the plane’s kinetic energy?
(Answer) On the return flight, the plane has less kinetic energy.
(Question) A racehorse is running at 42 miles per hour, equivalent to 18.8 meters per second. The horse and its jockey have a combined mass of 512 kilograms. How much kinetic energy do they have?
(Answer) 90,480.6 J
(Question) Which object has kinetic energy?
(Answer) balloon rising in the sky
(Question) Mr. Starr pushed a cart full of groceries to his car. After emptying the cart, he pushed it back to the store. He pushed the cart at a speed of 2 meters per second each way. Which is the best prediction?
(Answer) When it was empty, the cart had less kinetic energy.
(Question) A student fires a toy rocket into the sky. When does the rocket have the most potential energy?
(Answer) when the rocket reaches its highest point
(Question) What is the best description of one billiard ball hitting a second billiard ball?
(Answer) Most of the kinetic energy in the first ball is transferred to the second ball.
(Question) A roller-coaster car is at the top of a hill. The car and its passengers have a combined mass of 1,088 kilograms. If the hill is 62 meters tall, how much potential energy does the car have?
(Answer) 661,068.8 J
(Question) A roller-coaster is at the top of a 62-meter hill. The car and its passengers have a total mass of 1,088 kilograms. By the time the car reaches the bottom of the hill, its speed is 74 miles per hour (33 meters per second). How much kinetic energy does the car have at the bottom of the hill?
(Answer) 592,416 J
(Question) A diagram is drawn showing a swing set with a swing pulled backward prior to release. The diagram shows how the swing will move forward and then backward after it is initially released. At which point in the diagram is all of the energy gravitational potential energy?
(Answer) when the swing is pulled back prior to release
(Question) essay
(Answer) good luck
(Question) essay
(Answer) good luck
Explanation:
I just finished this assignment.
a cook holds a 2.37 kg carton of milk at arm’s length. 25.2 cm 8 cm fb 61.7 ◦ w what force fb must be exerted by the biceps muscle? the acceleration of gravity is 9.8 m/s 2 . (ignore the weight of the forearm.) answer in units of n.
Answers
According to the given statement the force (fb) that must be exerted by the biceps muscle is 23.226 N.
To find the force (fb) that must be exerted by the biceps muscle, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration.
First, let's convert the length of the arm from centimeters to meters. 25.2 cm is equal to 0.252 meters.
Next, we need to calculate the weight of the carton of milk.
Weight is equal to mass multiplied by the acceleration due to gravity.
The mass of the carton is given as 2.37 kg, and the acceleration due to gravity is 9.8 m/s².
Therefore, the weight of the carton is:
Weight = mass * acceleration due to gravity
Weight = 2.37 kg * 9.8 m/s²
Weight = 23.226 N
Since the carton is held at arm's length, the force exerted by the biceps muscle must counteract the weight of the carton.
Therefore, the force exerted by the biceps muscle is also 23.226 N.
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Describing Simple Machines
Match each simple machine with its description.
lever
is a ramp
inclined plane
+
similar to a seesaw, can lift an object
pulley
uses a rope; can change the direction
of a force
wheel and axle
reduces the amount of friction when
an object is being moved
wedge
t
can split apart an object
Answers
Answer:
A wedge can split an object apart
A lever is the seesaw
inclined plane is a ramp
a pulley can reduce the amount of friction
wheel and axle is the rope one
Explanation:
Following are the matches:
lever: similar to a seesaw, can lift an objectinclined plane: is a ramppulley: uses a rope; can change the direction of a forcewheel and axle: reduces the amount of friction when an object is being movedwedge: can split apart an objectWhat are simple machines?Simple machines are basic mechanical devices that can help make work easier by reducing the amount of force or effort needed to do a task. They are usually the most basic forms of machines, often made up of only one or two parts, and are used to change the direction or magnitude of a force.
There are six types of simple machines:
Lever: A rigid bar that pivots around a fixed point, called a fulcrum, to move a load. Examples include a seesaw, crowbar, and scissors.Inclined Plane: A sloping surface used to move a load from a lower level to a higher level. Examples include a ramp and stairs.Pulley: A wheel with a grooved rim used to change the direction or magnitude of a force by pulling a rope or cable. Examples include a crane and a flagpole.Wheel and Axle: A wheel with a rod or axle at its center used to move a load. Examples include a car wheel and a doorknob.Wedge: A triangular-shaped tool that can split or separate objects. Examples include a knife and an ax.Screw: An inclined plane wrapped around a cylinder or cone used to hold objects together or to lift or move them. Examples include a bolt and a jar lid.Simple machines are the building blocks for more complex machines, and they are used in many everyday devices and equipment to make work easier and more efficient.
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Describe the components of the universe.
3-4 sentences
Answers
Answer:
The Universe is thought to consist of three types of substance: normal matter, 'dark matter' and 'dark energy'. Normal matter consists of the atoms that make up stars, planets, human beings and every other visible object in the Universe.
Explanation:
Answer:
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Explanation:
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According the NASA's StarChild Website, "The universe is a vast open space which contains all of the matter and energy in existence. The universe contains all of the galaxies, nebulae, stars, and planets. The exact size of the universe is unknown. Scientists believe the universe is still expanding outward.
The Universe is thought to consist of three types of substance: normal matter, 'dark matter' and 'dark energy'. Normal matter consists of the atoms that make up stars, planets, human beings and every other visible object in the Universe.
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Describe 2 potential problems or limitations of ratio
analysis.
Answers
2. Overlooking External Factors: Ratio analysis primarily focuses on internal operations of a company, but there are various external factors like market conditions, industry trends, and economic cycles that can significantly impact a company's performance. These factors might not be reflected directly in the financial ratios, thus potentially leading to an incomplete understanding of the company's overall situation.
Determine the quantity of charge on a plastic tube which has been rubbed with animal fur and gained 3. 8 x 10^9 electrons
Answers
The quantity of charge on a plastic tube that has been rubbed with animal fur and gained 3. 8 x 10^9 electrons is The quantity of charge on the plastic tube is 3.8 x 10^9 electrons.
The quantity of charge on the plastic tube is 3.8 x 10^9 electrons. To calculate this value, we can use the equation q = n*e, where q is the charge, n is the number of electrons and e is the elementary charge (1.6 x 10^-19 C). Substituting in the values given, we get q = 3.8 x 10^9 * 1.6 x 10^-19 = 6.08 x 10^-10 C. This means that the plastic tube has gained a charge of 6.08 x 10^-10 Coulombs, which is equivalent to 3.8 x 10^9 electrons.
This can be explained by the process of triboelectricity, which is the transfer of electrons between two materials due to rubbing them together. In this case, the animal fur must have had a higher electron affinity than the plastic, which caused electrons to be transferred from the fur to the plastic tube.
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Conductor resistance causes a(n)_____between the voltage source and the connected load.
Answers
Answer: decrease in current, power loss, and voltage drop
Create 5 Examples about Problem Solving about Speed
(MUST APPLY GRESA METHOD)
Given
Required
Equation
Solution
Answer
Answers
Answer:
Explanation:
Sure, here are five examples of problem-solving using the GRESA method for speed:
Example 1:
Given: A car travels 240 km in 4 hours.
Required: What is the average speed of the car?
Equation: Speed = Distance / Time
Solution: Speed = 240 km / 4 hours = 60 km/hour
Answer: The average speed of the car is 60 km/hour.
Example 2:
Given: A train travels at a speed of 100 km/hour for 2 hours, and then at a speed of 80 km/hour for the next 3 hours.
Required: What is the total distance traveled by the train?
Equation: Distance = Speed x Time
Solution: Distance = (100 km/hour x 2 hours) + (80 km/hour x 3 hours) = 200 km + 240 km = 440 km
Answer: The total distance traveled by the train is 440 km.
Example 3:
Given: A cyclist travels at a speed of 30 km/hour for 2 hours, and then at a speed of 40 km/hour for the next 3 hours.
Required: What is the average speed of the cyclist for the entire journey?
Equation: Average speed = Total distance / Total time
Solution: Total distance = (30 km/hour x 2 hours) + (40 km/hour x 3 hours) = 60 km + 120 km = 180 km
Total time = 2 hours + 3 hours = 5 hours
Average speed = 180 km / 5 hours = 36 km/hour
Answer: The average speed of the cyclist for the entire journey is 36 km/hour.
Example 4:
Given: A boat travels upstream at a speed of 10 km/hour, and downstream at a speed of 20 km/hour. The speed of the current is 5 km/hour.
Required: What is the speed of the boat in still water?
Equation: Speed of boat in still water = (Speed downstream + Speed upstream) / 2
Solution: Speed downstream = 20 km/hour, Speed upstream = 10 km/hour
Speed of current = 5 km/hour
Speed of boat in still water = (20 km/hour + 10 km/hour) / 2 = 15 km/hour
Answer: The speed of the boat in still water is 15 km/hour.
Example 5:
Given: A car travels a distance of 90 km in 2 hours. If the speed of the car had been 10 km/hour more, it would have taken 1 hour less to cover the same distance.
Required: What is the original speed of the car?
Equation: Distance = Speed x Time
Solution: Let the original speed of the car be x km/hour
Distance traveled at original speed = 90 km
Time taken at original speed = 2 hours
Distance traveled at increased speed = 90 km
Time taken at increased speed = 2 - 1 = 1 hour
Using the equation Distance = Speed x Time, we get:
90 = x * 2
90 = (x + 10) * 1
Solving these equations simultaneously, we get:
x = 40 km/hour
Answer: The original speed of the car is 40 km/hour.
Like the Kelvin scale, the Rankine scale is an absolute temperature scale: Absolute zero is zero degrees Rankine (0∘R). However, the units of this scale are the same size as those on the Fahrenheit scale (∘F) rather than the Celsius scale (∘C).
A) Given that water at standard pressure freezes at 0∘C, which corresponds to 32∘F, and that it boils at 100∘C, which corresponds to 212∘F, calculate the temperature difference ΔT in degrees Fahrenheit that corresponds to a temperature difference of 1 K on the Kelvin scale.
B) What is the numerical value of the triple-point temperature Ttriple of water on the Rankine scale?
Answers
The temperature difference of 1 K on the Kelvin scale is equivalent to the temperature difference of (5/9)°F on the Fahrenheit scale. Triple-point temperature of water is approximately 491 degrees Rankine.
The unit of scales on the Rankine scale is the same as those on the Fahrenheit scale. Hence, from the freezing point of water (0⁰C) to the boiling point of water(100⁰C) , Rankine scale is divided into 180 scales.
The absolute zero is zero degrees Rankine. In Celsius scale, absolute zero is −273 °C.
A). A unit scale on the Kelvin scale is the same size as a unit scale in the Celsius scale. Hence,
ΔT 1 K = ΔT 1°C
The ratio of Celsius and Fahrenheit scale is 5/9, therefore:
K/F = C/F = 5/9
Hence,
ΔT 1 K = ΔT (5/9)°F
B) Triple-point temperature of water is approximately 0 °C. Since zero degrees Rankine is equivalent to −273 °C, hence:
0 °C = 0 - (9/5)(-273) = 491 degrees Rankine.
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Before going in for an annual physical, a 70.0-{\rm kg} person whose body temperature is 37.0{\rm ^{\circ} C} consumes an entire 0.355-{\rm liter} can of a soft drink (which is mostly water) at12.0{\rm ^{\circ} C}.
A.)What will be the person's body temperature T_final after equilibrium is attained? Ignore any heating by theperson's metabolism. The specific heat capacity of a human body is3480 {\rm J/kg \cdot K} .
B.)Is the change in the person's body temperature great enoughto be measured by a medical thermometer? (A high-quality medicalthermometer can measure temperature changes as small as0.1{\rm ^{\circ}C} or less.) yes or no
Answers
Answer:
A) The person's body temperature T_final after equilibrium is attained = 36.85°C
B) The change in the person's temperature after equilibrium is attained = 0.15°C
A high-quality medical thermometer can measure temperature changes as small as 0.1°C, hence, YES, it would detect the minute drop by 0.15°C too.
Explanation:
If we assume that the soft drink has the same density as water (since it is stated in the question that it is mostly water).
Density of water = 1 g/mL = 1 kg/L
Ignoring any heating by the person's metabolism,
A) So, heat lost by the human body = heat gained by the soft drink as it attains thermal equilibrium with the human body
Let the final temperature of the human body + soft drink set up be T
Heat lost by the human body = mCΔT
m = mass of the human body = 70.0 kg
C = Specific heat capacity of the human body = 3480 J/kg.K
ΔT = Temperature change of the human body = 37 - (Final temperature) = 37 - T
Heat lost by the body = 70 × 3480 × (37 - T)
= (9,013,200 - 243,600T) J
Heat gained by soft drink = mCΔT
m = mass of the soft drink = density × volume = 1 × 0.355 = 0.355 kg
C = specific heat capacity of the soft drink = specific heat capacity of the soft drink = 4182 J/kg.K
ΔT = (final temperature) - 12 = (T - 12)
Heat gained by the soft drink = 0.355 × 4182 × (T - 12) = (1,484.61T - 17,815.32) J
heat lost by the human body = heat gained by the soft drink as it attains thermal equilibrium with the human body
(9,013,200 - 243,600T) = (1,484.61T - 17,815.32)
9,013,200 + 17,815.32 = 1,484.61T + 243,600T
9,031,015.32 = 245,084.61T
T = (9,031,015.32/245,084.61)
= 36.8485614825 = 36.85°C
B) The change in the person's temperature = 37 - 36.85 = 0.15°C
A high-quality medical thermometer can measure temperature changes as small as 0.1°C, hence it would detect the minute drop by 0.15°C too.
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The equilibrium temperature is required and to find whether the temperature change can be measured by a thermometer is required.
The temperature is 310 K.
Yes, the thermometer can measure the temperature difference.
\(m_1\) = Mass of person = 70 kg
\(c_1\) = Specific heat of person = 3480 J/kg K
T = Equilibrium temperature
\(T_1\) = Temperature of person = \(37\ ^{\circ}\text{C}+273.15 =310.15\ \text{K}\)
\(1\ \text{L}=1\ \text{kg}\) of water
\(m_2\) = Mass of water = \(0.355\ \text{kg}\)
\(c_2\) = Specific heat of soft drink mostly water = \(4186\ \text{J/kg K}\)
\(T_2\) = Temperature of soft drink = \(12\ ^{\circ}\text{C}=285.15\ \text{K}\)
The heat equation is
\(m_1c_1(T-T_1)=m_2c_2(T_2-T)\\\Rightarrow m_1c_1T-m_1c_1T_1=m_2c_2T_2-m_2c_2T\\\Rightarrow T=\dfrac{m_2c_2T_2+m_1c_1T_1}{m_1c_1+m_2c_2}\\\Rightarrow T=\dfrac{0.355\times 4186\times 285.15+70\times 3480\times 310.15}{70\times 3480+0.355\times 4186}\\\Rightarrow T=310\ \text{K}\)
The temperature difference is \(T_1-T=310.15-310=0.15\ \text{K}=0.15\ ^{\circ}\text{C}\)
Yes, the thermometer can measure the temperature difference.
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The fact that quasars can be detected from distances where even the biggest and most luminous galaxies cannot be seen means that Select one: A. they must be in directions where intergalactic absorption by dark matter is minimum, allowing us to see them. B. they must be intrinsically far more luminous than the brightest galaxies. C. they have not been as redshifted by their motion as have galaxies, and hence they can still be seen. D. they must be in directions where gravitational focusing by the masses of nearer galaxies makes them visible from Earth.
Answers
Answer:
B. they must be intrinsically far more luminous than the brightest galaxies.
Explanation:
Quasar is famous for being an intergalactic object which is billions of years away from the earth yet can still be seen, unlike the other star body, unlike giant galaxies.
Hence, the fact that quasars can be detected from distances where even the biggest and most luminous galaxies cannot be seen means that "they must be intrinsically far more luminous than the brightest galaxies."
This condition, including other related evidence gotten in recent years concerning our galaxy, has shown that quasars are probably the central nuclei of very distant, very active galaxies.
What would a wave with a low amplitude sound like? Question 3 options: It would sound quiet. It would sound loud. It would sound squeaky. It would sound deep
Answers
Answer:
it would be loud
Explanation:
it would be loud
how do initial velocity and final velocity differ
Answers
Does the evidence that Andromeda is moving toward the Milky Way disprove the big bang theory?
Answers
Answer:
yes it does
Explanation:
andromeda is another galaxy heading towards us. this proves that it didnt all happen with just one point growing larger.
plz give brainliest
Answer:
No, due to Neighboring galaxies being normal in the universe. This happens due to gravitational attractions of each galaxy. The big bang theory clearly states that the universe started with a intensily hot point that expaded and created cosoms and more. The Andromeda and Milky Way galaxy are being attracted to each other due to their density. Density is a big role in this explation due to density helping create gravitational pulls/fileds.
dExplanation:
I need to know which answer is correct
Answers
For the displacement field u(x,t)=u
i
e
i
with components given below, calculate the full three dimensional strain at the point p=e
1
+2e
2
+10e
3
u
1
=0.1x
1
x
2
u
2
=0.1x
2
+5
u
3
=500
Answers
The full three-dimensional strain tensor at the point
\(p = e_1 + 2e_2 + 10e_3\: is\: :\\epsilon =\left[\begin{array}{ccc}0.05x_2&0.05x_1&0\\0.05&0&0\\0&0&0\end{array}\right]\)
To calculate the full three-dimensional strain at the point \(p = e_1 + 2e_2 + 10e_3\), we need to find the components of the strain tensor \(\epsilon_m_n\).
The strain tensor εₘₙ can be calculated using the formula:
εₘₙ = (0.5) * (∂uₘ/∂xₙ + ∂uₙ/∂xₘ)
Given the displacement field u(x, t) with components:
u₁ = 0.1x₁x₂
u₂ = 0.1x₂ + 5
u₃ = 500
We can calculate the components of the strain tensor as follows:
\(\epsilon_1_1 = (1/2) * (\delta u_1/\delta x_1 + \delta u_1/\delta x_1)\\= (1/2) * (0.1x_2 + 0)\\= 0.05x_2\)
\(\epsilon_1_2 = (1/2) * (\delta u_1/\delta x_2 + \delta u_2/\delta x_1)\\= 0.05x_1\)
\(\epsilon _1_3 = (1/2) * (\delta u_1/∂x_3 + \delta u_3/\delta x_1)\\= (1/2) * (0 + 0)\\= 0\)
\(\epsilon_2_1 = (1/2) * (\delta u_2/\delta x_1 + \delta u_1/\delta x_2)\\= (1/2) * (0 + 0.1)\\= 0.05\)
ε₂₃ = (1/2) * (∂u₂/∂x₃ + ∂u₃/∂x₂)
= (1/2) * (0 + 0)
= 0
ε₃₁ = (1/2) * (∂u₃/∂x₁ + ∂u₁/∂x₃)
= (1/2) * (0 + 0)
= 0
ε₃₂ = (1/2) * (∂u₃/∂x₂ + ∂u₂/∂x₃)
= (1/2) * (0 + 0)
= 0
ε₃₃ = (1/2) * (∂u₃/∂x₃ + ∂u₃/∂x₃)
= (1/2) * (0 + 0)
= 0
Therefore, the full three-dimensional strain tensor at the point
\(p = e_1 + 2e_2 + 10e_3\: is\: :\\epsilon =\left[\begin{array}{ccc}0.05x_2&0.05x_1&0\\0.05&0&0\\0&0&0\end{array}\right]\)
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1. A student adds water and sugar to a jar and seals the jar so that nothing can get in or out. The
student then finds the mass of the jar containing the water and sugar. After some sugar dissolves, the
student finds the mass of the jar and its contents again.
Water
Sugar
and
Water
Sugar
Sugar
Before
After
Vhat will happen to the mass of the jar containing the water and sugar after some of the sugar
issolves?
a. The mass will stay the same
b. The mass will increase
c. The mass will decrease
The moon will donend on how much sunar dissolves
Answers
Answer:
The mass will stay the same throughout time
#1)
A 500 Hz triangular wave with a peak amplitude of 50 V is applied to
the vertical deflecting plates of a CRO. A 1 kHz saw tooth wave with a
peak amplitude of 100 V is applied to the horizontal deflecting plates.
The CRO has a vertical deflection sensitivity of 0. 1 cm/V and a
horizontal deflection sensitivity of 0. 02 cm/V. Assuming that the two
inputs are synchronized, determine the waveform displayed on the
screen?
[2 Marks]
Answers
The CRO (Cathode Ray Oscilloscope) will display a triangular wave that is vertically stretched and horizontally compressed.
The vertical deflection plates will cause the triangular wave to be displayed with a peak-to-peak amplitude of\(100 cm (50 V * 0.1 cm/V)\), while the horizontal deflection plates will cause sawtooth wave to be displayed with a peak-to-peak amplitude of \(5000 cm (100 V * 0.02 cm/V).\) The synchronization of the two inputs will ensure that the triangular wave and the sawtooth wave are displayed in a coordinated manner, with each cycle of the sawtooth wave corresponding to five cycles of the triangular wave. The resulting display will show a pattern of diagonal lines that gradually rise and then quickly drop back to the starting position, with each line representing a cycle of the sawtooth wave.
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Urgent, Please help! Will give brainliest!
Answers
Answer:
between B and D
I I srongly recommend B
una caja en reposo se traslada 93 cm con un peso de 67N en un tiempo de 9,89h.¿cual es la aceleración la masa y la fuerza de dicho objeto
Answers
Answer:
a. Acceleration, a = 1.47 * 10^{-9} m/s²
b. Mass = 4.57 * 10^{10} kilograms
c. Force = 67.12 Newton
Explanation:
Given the following data;
Distance = 93 cm to meters = 93/100 = 0.93 meters
Weight = 67 N
Time = 9.89 hours to seconds = 35604 seconds
Initial velocity = 0 m/s (since it's starting from rest)
Acceleration due to gravity, g = 9.8 m/s
a. To find the acceleration, we would use the second equation of motion;
\( S = ut + \frac{1}{2} at^{2} \)
Where;
S is the distance covered or displacement of an object.
u is the initial velocity.
a is the acceleration.
t is the time.
Substituting the values into the equation, we have;
\( 0.93 = 0*35604 + \frac{1}{2} * a*35604^{2} \)
\( 0.93 = 0 + \frac{1}{2} * 1267644816a \)
\( 0.93 = 633822408a \)
\( Acceleration, a = \frac{0.93}{633822408} \)
Acceleration, a = 1.47 * 10^{-9} m/s²
b. To find the mass
Weight = mass * acceleration due to gravity
67 = mass * 1.47 * 10^{-9}
\( Acceleration, a = \frac{67}{1.47 * 10^{-9}} \)
Mass = 4.57 * 10^{10} kilograms
c. To find the force;
Force = mass * acceleration
Force = 4.57 * 10^{10} * 1.47 * 10^{-9}
Force = 67.12 Newton
why is the time every 15° eastward one hour ahead?..
Answers
Explanation:
The reason time zones are 15 degrees wide is because there are 24 hours and 360/24 = 15. As you move east by 15 degrees the sun’s position in the sky changes relative to us and it looks an hour later in the day, so we advance our clocks to match the sun’s position.
So every 15° eastward one hour ahead.
when two charged particles interact there is an ____how do the coils impact the strength of the magnetic field
Answers
when two charge particles interact
2. List five parallel circuits you use at home.
Answers
Answer:
Blinds
Mirror Frame
A/C Vents
Rubik's Cube
Shelf
give the velocity vector for wind blowing at 5 km/hr toward the northwest. (assume north is the positive y-direction.)
Answers
The velocity vector for wind blowing at 5 km/hr toward the northwest will be :
\(v_{x} =-\frac{5}{\sqrt{2} }i\) ; \(v_{y}=\frac{5}{\sqrt{2} } j\)
The velocity vector for wind can be written as sum of the vector components in x and y direction respectively.
\(v=v_{x}i +v_{y} j\)
∴ Velocity vector, v = |v| cosθ + |v| sinθ
Now, it is given, magnitude of wind velocity, |v| = 5 km/hr
Given that the wind is blowing towards the northwest i.e., direction of wind is making an angle of 45° with the x-axis.
Since, the direction of wind is northwest the horizontal component of the vector will be in the negative x-axis.
∴ The Velocity vector will be,
v = |v| cosθ -i + |v| sinθ j
= -5 cos(45°) + 5sin(45°)
= -(5/√2)i + (5/√2)j
Therefore, the components of velocity vector of wind will be,
component in the x-direction,\(v_{x} =-\frac{5}{\sqrt{2} }i\)
component in the x-direction,\(v_{y}=\frac{5}{\sqrt{2} } j\)
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write two examples of machine which changes the direction of force
Answers
Answer:
Washign machine and swingset
Explanation:
Please help me with thus question (picture) D:
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well thanks for the Information
Explanation:
Torque = Force * Perpendicular distance of the force = 10N * 0.8m = 8Nm.
In diagram A, both torques are acting in a clockwise direction. Hence the net torque is 2N * 1m + 4N * 1m = 6Nm, clockwise.
In diagram B, the torques are acting in opposite directions. For the clockwise one, its torque is 5N * 4m = 20Nm. For the anticlockwise one, its torque is 2N * 10m = 20Nm. Since they are in opposite directions and are equal, they cancel out each other.
Hence net force = 0N and net torque = 0Nm.
14) Calculate the magnitude and direction of the magnetic force on a particle of charge q= 13C that
is moving with a velocity of v= -20m/s x (to the left) in a magnetic field of B= 0.5 T 2
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The magnitude and direction of the magnetic force on a particle of charge is - 2.21 in the opposite direction.
What is magnetic force?Magnetic force is defined as the electrically charged particles that are in motion and exhibit either attraction or repulsion. The interaction between moving and stationary charged particles is explained by the electromagnetic force, commonly known as the Lorentz force.
The magnitude and direction of the magnetic force can be calculated as
F = q v B sinθ
Given q = 13 C
v = - 20 m/s
B = 0.5 T²
F = 13 C x - 20 m/s x 0.5 T² sinθ
F = - 130 sinθ
Let θ is equal to 1
Then, F = 130 sin1
F = - 130 x 0.017
F = - 2.21
Thus, the magnitude and direction of the magnetic force on a particle of charge is - 2.21 in the opposite direction.
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A satellite weighing 5,400 kg is launched into orbit 30,000 km above sea level. The mass of Earth is 6.0 × 1024 kg and its radius is 6,400 km. The gravitational constant is 6.673 × 10–11 N•m2/kg2. What is the gravitational force of Earth on the satellite in scientific notation with two decimals.
A satellite weighing 5,400 kg is launched into orbit 30,000 km above sea level. The mass of Earth is 6.0 × 1024 kg and its radius is 6,400 km. The gravitational constant is 6.673 × 10–11 N•m2/kg2 . What is the gravitational force of Earth on the satellite in scientific notation with two decimals.
–1.6 × 103 N
–1.63 × 103 N
–2.4 × 103 N
–5.27 × 104 N
Answers
The gravitational force of Earth on the satellite, given that the satellite is launched into orbit 30000 km above sea level is 1.63×10³ N
How do I determine the gravitational force?The gravitaional force between two objects can be obtained by using the following formula:
F = GM₁M₂ / r²
Where
F is the gravitaional force G is the gravitational constant M₁ and M₂ are the masses of the objects r is the distance apartThe following data were obtained from he question:
Mass of satellite (M₁) = 5400 = 5.4×10³ KgHeight (h) = 30000 km = 30000 × 1000 = 30000000 mMass of Earth (M₂) = 6.0×10²⁴ KgRadius of Earth (R) = 6400 km = 6400 × 1000 = 6400000 mDistance apart (r) = R + h = 6400000 + 30000000 = 36400000 mGravitational constant (G) = 6.673×10¯¹¹ Nm²/Kg²Gravitational force (F) =?The gravitaional force can be obtained as shown below:
F = GM₁M₂ / r²
F = (6.673×10¯¹¹ × 5.4×10³ × 6.0×10²⁴) / (36400000)²
F = 1.63×10³ N
Thus, the gravitational force is 1.63×10³ N
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sara, who weighs 69.0 kg, enjoys a 513-calorie (513 kcal) breakfast of pancakes loaded with fruits, cream, and syrup. she wishes to maintain her weight, so she decides to work out before going to her fitness group's weekly meeting. if the height of a single stair is 12.0 cm, and her body is only 33% efficient in converting chemical energy to mechanical energy, determine the number of stairs sara must climb to cancel out the calories consumed.
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Sara must climb approximately 7000 stairs to cancel out the 513-calorie breakfast she consumed.
First, we need to convert the number of calories consumed (513 kcal) into units of energy in joules.
1 kcal = 4184 J
So, 513 kcal = 513 * 4184 J = 2143172 J
Next, we need to determine the work done by Sara in climbing stairs, which is given by the equation:
W = m * g * h
Where W is the work done, m is Sara's mass (69.0 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the stairs (12.0 cm converted to meters).
h = 12.0 cm = 0.12 m
So, the work done by Sara in climbing one stair is:
W = 69.0 kg * 9.8 m/s^2 * 0.12 m = 822.56 J
Since the efficiency of Sara's body in converting chemical energy to mechanical energy is only 33%, the number of stairs she needs to climb to cancel out the calories consumed can be calculated as follows:
n = 2143172 J / (822.56 J / 33%)
= 2143172 / (822.56 * 0.33)
= 6999 stairs (approximately 7000 stairs)
Mechanical energy is the sum of kinetic energy and potential energy in a mechanical system. It refers to the energy associated with the motion and position of an object. Kinetic energy is the energy an object possesses due to its motion, while potential energy is the energy stored within an object due to its position relative to other objects.
Mechanical energy can be transferred from one object to another, for example, when two objects collide. It can also be transformed from one form of energy to another, such as when a roller coaster car converts potential energy into kinetic energy as it moves downhill.
Conservation of mechanical energy states that in a closed system, the total mechanical energy remains constant as long as no external forces are acting upon the system. This principle is commonly used in physics to understand the behavior of physical systems and to solve problems related to energy and motion.
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What is the net force on a bathroom scale when a 110 pound person stands on it? How do you know?