how far should the front of the camera be from her friend?express your answer to two significant figures and include the appropriate units.express your answer to two significant figures and include the appropriate units.-long pinhole camera for a science fair project. she wants to photograph her 160-cm -tall friend and have the image on the film be 5.4 cm high.

The characteristics of image formed is a real, inverted, highly magnified image and at infinity.

The following are the general properties of image formed by a convex lens when the object is placed at focal point of the lens;

Thus, when an object is placed at the focal point of a convex lens, the image formed is a real, inverted, highly magnified image and at infinity.

These properties can be seen in the ray diagram attached to this solution.

To construct the ray diagram, draw a line from the top of the image through the focal point and principal axis.

If you look at the lens diagram carefully, you will notice that;

So the object is placed at the focus of the lens.

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Answer:

D. Upward force on the shuttle

Explanation:

The hot gas from space shuttles released downward causes an upward force on the shuttle and propels it up the more.

Long-term exposure to loud noises can indeed damage hearing. If a loud machine produces sounds with an intensity level of 110dB, and the intensity were reduced by a factor of 5, the new intensity level would be 92dB. It's important to protect our hearing from loud noises to prevent damage and preserve our ability to hear well.

Long-term exposure to loud noises can indeed damage hearing. If a loud machine produces sounds with an intensity level of 110 dB, and the intensity is reduced by a factor of 5, you would calculate the new intensity level as follows:
New intensity (in watts/m²) = Original intensity / 5
First, you need to convert the original 110 dB to watts/m² using the formula:
Intensity (in watts/m²) = 10^(dB/10) = 10^(110/10) = 10^11 watts/m²
Next, divide the original intensity by 5:
New intensity (in watts/m²) = 10^11 / 5 = 2 x 10^10 watts/m²
Finally, convert the new intensity back to decibels:
New intensity level (in dB) = 10 * log10(new intensity) = 10 * log10(2 x 10^10) ≈ 103 dB
So, the new intensity level would be approximately 103 dB if the intensity were reduced by a factor of 5.

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Answer:

FALSE

Explanation:

You breath in oxygen and your blood takes it through your body then you breath it out as carbon dioxide

Answer: Half of an object's mass (1/2*m) multiplied by the velocity squared

Explanation:

In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.  

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Explaination

the maximum hight is reached by the arrow is 4.40m

From Newton's second law and third equation of motion, the maximum speed of the arrow at the instant it leaves the bow is 11.8 m/s and the maximum height reached by the arrow in its flight into the air is 7.08 m

According to Newton's second law: The rate of change in momentum is directly proportional to the force applied. That is,

F = ma

Given that an archer uses an average force of 50.0 N to draw the string of his bow through a distance of 0.412 m. Then, he fires a 297 g arrow straight up into the air.

The parameters given are;

The maximum speed of the arrow at the instant it leaves the bow can be calculated by first calculating the acceleration.

F = ma

Substitute all the necessary parameters

50 = 0.297a

a = 50 / 0.297

a = 168.4 m/\(s^{2}\)

by using third equation of motion

\(V^{2}\) = \(U^{2}\) + 2as

Since it is starting from rest, U = 0

\(V^{2}\) = 2 x 168.4 x 0.412

\(V^{2}\) = 138.72

V = \(\sqrt{138.72}\)

V = 11.8 m/s

The maximum height reached by the arrow in its flight into the air will be calculated by the same formula where acceleration a = g

\(V^{2}\) = \(U^{2}\) - 2gH

At maximum height, final velocity V = 0

0 = \(11.8^{2}\) - 2 x 9.8 H

138.7 = 19.6H

H = 138.7 / 19.6

H = 7.08 m

Therefore, the maximum speed of the arrow at the instant it leaves the bow is 11.8 m/s and the maximum height reached by the arrow in its flight into the air is 7.08 m

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Answer:

3 m/s

Explanation:

rbsbdvebzvsvehdhdbd

Your speed is (36m)/(12sec).

That's 3 m/s. (Choice-A)

There's not enough information to determine your velocity.

Answer:

i think its  Russia, USA, Germany.

Answer:

2nd bscause there is a reaction

This question is incomplete

Complete Question

In the United States, a standard letter-sized piece of paper is 8.5 inches wide by 11 inches long. The international standard for a letter-sized piece of paper is different. The international standard is based on SI units: 21.0 cm wide by 29.7 cm long.

a. Convert 21.0 cm to inches. Show your dimensional analysis setup.

b. Convert 29.7 cm to inches. Show your dimensional analysis setup.

c. State the dimensions, in inches, of the international standard for a letter-sized piece of paper.

d. Which piece of paper is longer: a U.S. letter-sized piece of paper, or an international letter-sized piece of paper?

Answer:

a) 8.267721 inches ≈ 8.3 inches

b) 11.6929197 inches ≈ 11.7 inches

c) It's dimensions in inches for the international standard for letter - sized for paper = 8.3 wide inches by 11.7 inches long

d) The International standard letter - sized paper is longer.

Explanation:

a. Convert 21.0 cm to inches. Show your dimensional analysis setup.

1 cm = 0.393701inch

21 cm =

Cross Multiply

21 cm × 0.393701inch/ 1 cm

= 8.267721 inches

Approximately 8.3 inches

b. Convert 29.7 cm to inches. Show your dimensional analysis setup.

1 cm = 0.393701inch

29.7 cm =

Cross Multiply

29.7 × 0.393701 inch/ 1 cm

= 11.6929197 inches

Approximately 11.7 inches

c. State the dimensions, in inches, of the international standard for a letter-sized piece of paper.

The international standard for a letter-sized has dimensions 21.0 cm wide by 29.7 cm long.

Where

21.0cm = 8.267721 inches

≈ 8.3 inches

29.7cm = 11.6929197 inches

≈ 11.7 inches

Hence, it's dimensions in inches = 8.3 inches by 11.7 inches.

d. Which piece of paper is longer: a U.S. letter-sized piece of paper, or an international letter-sized piece of paper?

U.S letter - sized paper = 8.5 inches wide by 11 inches long

International standard letter- sized paper = 8.3 wide inches by 11.7 inches long.

Hence, the International standard letter - sized paper is longer.

Answer:

C. a small charged particle.

Explanation:

typically beta radiation emits an electron which is a small negativity charged particle.

hope it helps. :)

Answer:

A small charged particle.

Explanation:

The following equation can be used to calculate the final velocity of the enemy warrior:

v_f = (m_1 v_1 + m_2 v_2)/(m_1 + m_2)

where:

v_f is the final velocity of the enemy warrior

m_1 is the mass of the enemy warrior (85 kg)

v_1 is the initial velocity of the enemy warrior (6.2 m/s)

m_2 is the mass of the spear (2.8 kg)

v_2 is the initial velocity of the spear (41 m/s)

Plugging in the known values, we get:

v_f = (85 kg)(6.2 m/s) + (2.8 kg)(41 m/s))/(85 kg + 2.8 kg) = 6.3 m/s

Therefore, the enemy warrior is slowed to a final velocity of 6.3 m/s.

It is important to note that this is just an estimate, as the actual final velocity of the enemy warrior will depend on a number of factors, such as the exact point of impact and the material of the spear.

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The magnitude of the induced current is, (I=9 /R). The principal of ohm's law is employed in the given problem.

Emf is the production of a potential difference in a coil as a result of changes in the magnetic flux passing through it.

When the flux coupling with a conductor or coil changes, electromotive force, or EMF, is said to be induced.

The given data in the problem is;

B is the magnetic field,= 2t^2−3.

t(time)=3 sec

The induced EMF is found as;

\(\rm E= \frac{d \phi}{dt} \\\\\ \rm E= \frac{d(2t^2-3)}{dt} \\\\\ E=4t-3\\\\\ t= 3 sec \\\\ E=12-3 \\\\\ E= 9 \ V\)

From ohm's law;

E=IR

I=E/R

I=9 /R

Hence,the magnitude of the induced current is, (I=9 /R).

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Answer: Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces. So as two objects are separated from each other, the force of gravitational attraction between them also decreases.

Explanation:

well, you get some DNA from both of your parents, so when you hear the phrase, "You have your mother's eyes!" That means you have some of your mother's DNA that gave you her eye color. The DNA you get from your parents help determine how you look today

The most highly redshifted electromagnetic radiation that astronomers have detected to date is from the radiation left over from the Big Bang.

Radiation travels in waves and possesses both an electric and magnetic field. Both natural and artificial sources contribute to it. The energy levels of electromagnetic radiation can range from low to high. It consists of x-rays, gamma rays, infrared light, visible light, ultraviolet light, radio waves, and microwaves. Also known as EMR, electromagnetic radiation (EMR) is a category of energy carried by waves of the electromagnetic (EM) field that travel across space. These waves include radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. The electromagnetic spectrum includes all of these waves. Electromagnetic radiation is often made up of electromagnetic waves, which are coordinated oscillations of electric and magnetic fields. Due to the periodic alteration of the electric or magnetic field, electromagnetic radiation or waves are produced.

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Answer:Take into account the the Earths gravity is 9.8 meters a second

Explanation:

Gravity pulls down on the ball at g=-9.81 m/s^2. Up is positive, down is negative.The ball started at a certain initial velocity of Vi m/s. Time it took is t=4s. Final velocity is Vf=0 m/s, because at the highest point the ball stops moving.

Vf=(g*t)+Vi

Rearrange for Vi.

Vi=Vf-(g*t)

Vi=0-(-9.81*4)=39.24 m/s (upward)

Think about it this way for the non-mathematical approach. The ball stops at the top. The initial velocity gets reduced by 9.81 m/s every second, and reaches 0 m/s at the top. It took 4 seconds, so 9.81*4 is equal to the initial upward velocity.

Answer:

hmmmmm

Explanation:

I am gonna say D.

if I am right plz give me a brainliest

Answer:

it is push or pull and it is machanical energy but the arrows are going out so it means it is pull

the reason is because it the arrows are going out that means they are using mecanichal energy bc they using hands the evedance is that we can identify the energy

This question can be solved using the concept of friction energy.

The thermal energy change is b "258.4 J".

The change in thermal energy will be equal to the friction energy produced during the motion of the box.

\(Change\ In\ Thermal\ Energy = E = Friction\ Energy\\\\E = \mu fd\)

where,

μ = coefficient of kinetic friction = 0.4

f = force applied = 38 N

d = distance traveled by the box = 17 m

Therefore,

\(E = (0.4)(38\ N)(17\ m)\)

E = 258.4 J

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When considering the pairs of astronomical objects separated by the same distance d, and assuming identical and relatively small asteroids, the ranking of the gravitational force acting on the asteroid on the left, from strongest to weakest, depends on the mass and proximity of the objects involved.

The strength of the gravitational force depends on two main factors: the mass of the objects and the distance between them. Based on this, we can rank the pairs as follows:

1. Pair with the highest mass and closest proximity will have the strongest gravitational force on the asteroid on the left.

2. Pair with the second-highest mass and closer proximity than the remaining pairs will have the second-strongest gravitational force.

3. Pair with the third-highest mass and closer proximity than the remaining pairs will have the third-strongest gravitational force.

4. Pair with the fourth-highest mass and closer proximity than the remaining pairs will have the fourth-strongest gravitational force.

5. Pair with the lowest mass and/or greater distance than the remaining pairs will have the weakest gravitational force.

By considering the mass and proximity of the objects in each pair, we can determine the relative ranking of the gravitational forces acting on the asteroid on the left, from strongest to weakest.

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Answer:It is not clear from the question what "eel" is being referred to, so I cannot provide a specific answer.

However, I can provide some general information on how to calculate the electric field generated by a charged object. The electric field is a vector field that describes the strength and direction of the force that would be exerted on a small positive test charge placed at any given point in space.

If the charged object is a point charge Q located at a distance r from the point of interest, the electric field E at that point is given by:

E = k * Q / r^2

where k is Coulomb's constant (k = 9 x 10^9 N·m^2/C^2).

If the charged object is not a point charge but has a finite size, the electric field at any given point can be calculated by summing up the contributions from all the individual charge elements that make up the object. This can be a complex calculation depending on the geometry of the object.

In the specific case described in the question, we are given the potential difference between two electrodes and the distance between them. The electric field can be calculated from these values using the equation:

E = V / d

where V is the potential difference and d is the distance between the electrodes. Substituting the given values, we get:

E = 5.6 V / 0.01 m = 560 V/m

So the electric field generated by the charged object (which is not specified in the question) is approximately 560 V/m.

Explanation:

The electric field generated by the eel is 560 V/m.

An electric field is a physical field that surrounds an electrically charged object and exerts a force on other charged objects within its vicinity. It is a fundamental concept in physics that helps explain the behavior of charged particles and the interactions between them.

Electric fields are created by electric charges, which can be either positive or negative. A positive charge creates an electric field that points away from the charge, while a negative charge creates an electric field that points towards the charge. The strength of an electric field is proportional to the amount of charge that creates it and inversely proportional to the distance from the charge.

Electric fields can be visualized using field lines, which indicate the direction and strength of the electric field at each point in space. The field lines point away from positive charges and towards negative charges, and the density of the field lines indicates the strength of the field.

Electric fields are important in many areas of physics, including electromagnetism, electrostatics, and electronics. They play a crucial role in the operation of electronic devices, such as capacitors, transistors, and integrated circuits, and are also used in medical imaging technologies, such as MRI and EEG.

Here in the Question,

Assuming that you are referring to the electric eel, we can use the formula for electric field generated by a point charge to estimate the approximate electric field generated by the eel:

E = k * Q / r^2

where E is the electric field, k is Coulomb's constant (k = 9.0 x 10^9 N*m^2/C^2), Q is the electric charge, and r is the distance from the charge.

We can estimate the charge of the eel based on the potential difference measured between the two electrodes:

V = E * d

where V is the potential difference, E is the electric field, and d is the distance between the electrodes.

Rearranging the formula, we get:

E = V / d

Substituting the values given in the problem, we get:

E = 5.6 V / 1.0 cm = 560 V/m

Therefore, the approximate electric field generated by the eel is 560 V/m.

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The Jovian planets are formed from materials different from the terrestrial planets for the reason that gaseous Jovian planets, formed farther away from the heat of the Sun, are formed from light weight nebulae "dust."

A Jovian planet, also known as a gas giant, is a huge planet that has a primarily gaseous composition. The Jovian planets include Jupiter, Saturn, Uranus, and Neptune. They are primarily made up of hydrogen and helium, and they have enormous atmospheres.Jovian planets are formed farther away from the heat of the Sun, so they are formed from lighter-weight nebulae "dust." Terrestrial planets, on the other hand, are formed nearer to the Sun, so they are formed from heavier-weight nebulae "dust." The density of the materials that make up the Jovian planets is lower than that of the terrestrial planets due to this. This means that the Jovian planets have lower densities and a greater volume than the terrestrial planets.

Hence, the correct option is d. Gaseous Jovian planets, formed farther away from the heat of the Sun, are formed from light weight nebulae "dust."

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The coefficient of kinetic friction between the bag and the ground is found to be 0.0251. It represents the ratio of the frictional force to the normal force acting between them.

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Answer:

im pretty sure its d

Explanation:

Answer:

(c) displacement

sure answer...

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the answer is EQUAL because a force on another object the second force is equal

The change in  frequency observed by the driver when the car is approaching a radio station at a speed of 25.0 m/s broadcasting at a frequency of 74.5 MHz is 74.59 MHz.

The formula for finding the observed frequency when the source is moving towards the observer is given by;

f′=f (v±v0/c)

Where, f is the frequency of the source, v is the velocity of light, v0 is the velocity of the source observed by the observer, c is the speed of light.

In this case, given that, v0 = 25.0 m/sf = 74.5 MHz, v = 3.0 x 108 m/s, c = 3.0 x 108 m/s

Putting the values in the formula, we get,

f′=74.5×(3.0×10^8+25.0×1000/3.0×10^8)=74.59 MHz (approx)

Hence, the change in frequency observed by the driver when the car is 74.59 MHz (approx).

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a)The work done by the shopkeeper on cart move is 2655.300J.

b)kinetic energy is to be zero.

c)The work done is less than before case.

(a) Consider the formula for work done of shopper is given by

Fcos0 x1        (1)

Here, F-Force

θ -Theta makes angle between force and direction

L -Length of the cart

Substitute force for '57' and θ for '25' and / for '51.4' in equation(1)

57x cos(25)x51.4 = 2655.300J

Thus,

The work done by the shopper on the cart moves is 2655.300J

(b):Here, Consider, the net work done of cart is to be zero.

So, the change in kinetic Energy is to be zero.

C) Consider,

Force(F)= ug + uFcosθ=f

Here,

Mg-weight of the cart

θ -makes angle between the force and direction

Thus umg

Force(F)= (1-sine)

Here,

He pushes the cart is to be horizontally so theta will be zero. θ = 0

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