How does the body maintain homeostasis? Give two or more examples of how this is accomplished. Provide supporting details. Be detailed in your answer

Answer: A

Explanation:

OD. 2kg of liquid oxygen at -225 *C has the least thermal energy.

The thermal energy for a phase of matter is given by the formula

Q = mCΔT where

m = mass

C = Specific heat constant

T = Temperature

For Oxygen, the Specific heat constant = 0.92 J/gK

Let's calculate the thermal energy for each case, assuming that the initial temperature is 0 Kelvin

OA.

m= 5000 g

ΔT = 303 K

So Q =5000×0.92×303 = 1393800 J = 1393.8 KJ

OB.

m= 5000 g

ΔT = 48 K

So Q =5000×0.92×48 = 220800 J = 220.8 KJ

OC.

m= 2000 g

ΔT = 293 K

So Q =2000×0.92×293 = 539120 J = 539.12 KJ

OD.

m= 2000 g

ΔT = 48 K

So Q =2000×0.92×48 = 88320 J = 88.32 KJ

Therefore, OD 2kg of liquid oxygen at -225 *C has the least thermal energy which is 88.32 KJ.

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Answer:

2 kg of liquid oxygen at -225°C

Explanation:

B has the same temperature, yet it's more mass. So, to use this as an example--B has the most thermal energy. If the mass decreased, then the thermal energy would decrease. More mass=more thermal energy. Hence, why the mass decreasing to 2 kg would equal the least amount of thermal energy.

The friction on a wheel rolling up an incline points up the incline because it acts in the opposite direction to the relative motion between the wheel and the incline. The frictional force prevents the wheel from slipping or sliding down the incline.

The friction on the wheel points up the incline because it acts in the direction opposite to the relative motion between the wheel and the incline. When a wheel rolls up an incline, the point of contact between the wheel and the incline is momentarily at rest, and the direction of motion of the wheel is tangent to the point of contact. The frictional force acts in the opposite direction to the motion of the wheel relative to the incline, which is up the incline, to prevent the wheel from slipping or sliding down the incline.

Therefore , the direction of friction is not necessarily opposite to the wheel's translational motion, but rather opposite to the relative motion between the wheel and the incline.

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Answer:

Abiotic referfers to non-living and biotic factors are living or once living

Explanation:

The correct answer to Brewster’s angle is 48.8 degrees.

What is Brewsters's law?

The Brewster's angle is the angle of incidence at which polarised light travels perfectly through a clear dielectric surface without being refracted. The light that is reflected from the surface when unpolarized light is incident at this angle is therefore perfectly polarised.

This equation's name is Brewster's law, and the angle it specifies is Brewster's angle. For a glass medium in air, Brewster's angle for visible light is around 56° (n2 = 1.5), while it is roughly 53° for an air-water interface (n2 = 1.33)

Brewster's Angle is defined as the inverse tan of n 2 over n 1. The inverse tan of 1.52 divided by 1.33 is thus 48.8 degrees.

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The Witness Experimenter configure options include a Skip field that misses out on a different number of random numbers for each replication (Option D).

Experimenter configure options are some basic settings of a Witness experiment. These settings influence how the experiment would behave and what output is produced. With the help of configure options, you can set the value of random number streams and skip replication.

The skip value misses out on a different number of random numbers for each replication. As a result, this provides some level of control over the replication. By changing the value of the skip, you can control which random numbers should be missed and which should not be missed. In addition, by using the skip field, you can increase the simulation run speed. As a result, you get better output in less time.

Thus, the correct option is D.

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Answer:

Explanation:

540

Answer:

The spring constant is approximately 46.382 newtons per meter.

Explanation:

From Physics, the period (\(T\)), measured in seconds, experimented by an object under Simple Harmonic Motion:

\(T = 2\pi\cdot \sqrt{\frac{W}{g\cdot k} }\) (1)

Where:

\(W\) - Weight, measured in newtons.

\(g\) - Gravitational acceleration, measured in meters per square second.

\(k\) - Spring constant, measured in newtons per meter.

If we know that \(W = 127\,N\), \(g = 9.807\,\frac{m}{s^{2}}\) and \(T = 3.32\,s\), then the spring constant of the system is:

\(\frac{T^{2}}{4\cdot \pi^{2}} = \frac{W}{g\cdot k}\)

\(k = \frac{4\cdot \pi^{2}\cdot W}{g\cdot T^{2}}\)

\(k \approx 46.382\,\frac{N}{m}\)

The spring constant is approximately 46.382 newtons per meter.

The inverse of Janine's equation is r = -120/(t - 120).

An equation is described as a formula that expresses the equality of two expressions, by connecting them with the equals sign.

In algebra, an equation is a mathematical statement that establishes the equality of two mathematical expressions.

The categories for equations are either identities or conditional equations.

For each potential value, the variables provide an identity. Only certain combinations of the values for the variables allow a conditional equation to hold true.

In order to  find the inverse of Janine's equation, we will to solve for r in terms of t.

First, we can rearrange the equation to get

t - 120 = 1/r.

divide both sides of the equation by 1/r to get

t/r - 120/r = 1.

divide both sides of the equation by -120/r to get

r = -120/(t - 120).

Therefore, the inverse of Janine's equation is r = -120/(t - 120).

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Answer: R=120t/120-t

Explanation: edmentum/plato :)

Answer:

1.5 m

Explanation:

Let the distance from the box to the pivot be c.

Let the distance from the pivot to the effort be y.

From the question given above, the following data were obtained:

Effort force (Fₑ) = 7 N

Force of resistance (Fᵣ) = 14 N

Distance from the box to the pivot (c) = 0.75 m

Distance from the pivot to the effort (y) =?

Clockwise moment = Fₑ × y

Anticlock wise moment = Fᵣ × c

Clockwise moment = Anticlock wise moment

Fₑ × y = Fᵣ × c

7 × y = 14 × 0.75

7 × y = 10.5

Divide both side by 7

y = 10.5 / 7

y = 1.5 m

Therefore, the distance from the pivot to the effort is 1.5 m

In the ground state of hydrogen, the radius of the electron's orbit is equal to the Bohr radius, a0.

lThe quantum numbers n=1, l=0, and m=0 characterise the ground state of hydrogen. The Bohr radius is calculated as follows:

a₀ = (4πε₀ħ²)/(me²)

where 0 represents the vacuum permittivity, is the reduced Planck constant, me represents the electron mass, and e represents the elementary charge.

The electron's energy in the ground state of hydrogen is given by:

E = -13.6 eV / n²

where n=1 is the fundamental quantum number.

As a result, in the ground state of hydrogen, the radius of the electron's orbit is:

r = a₀ n² / l(l+1) = a₀

Because l=0 for the ground state.

So, in the ground state of hydrogen, the radius of the electron's orbit is equal to the Bohr radius, a0.

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The temperature at which the collision frequency γ is 1.00 × 109 s-1 per atom in a sample of Ar(σ=36 A˚2) at 1 bar is 198 K.

In kinetic theory, the frequency of collisions among gas molecules is proportional to the number density of the gas and to the average molecular velocity. The collision frequency γ is defined as the average number of collisions per unit time per molecule.

It is given byγ = n⟨v⟩σwhere n is the number density, ⟨v⟩ is the mean speed, and σ is the collision cross-section. The collision cross-section is the effective area that an atom occupies in a collision. The cross-section is usually expressed in units of area, such as square meters or square angstroms.

The collision frequency can also be expressed in terms of the temperature of the gas. The mean speed of a gas molecule is proportional to the square root of its temperature.

Therefore, we can writeγ = n⟨v⟩σ= n (8kT/πm)1/2σwhere k is the Boltzmann constant, T is the temperature, and m is the mass of a gas molecule. For argon gas, the mass is 6.63 × 10-26 kg and the collision cross-section is 36 A2 (square angstroms).

Therefore,γ = n⟨v⟩σ= n (8kT/πm)1/2σ= n (8kT/πm)1/2(36 × 10-20 m2)

The frequency of collisions is γ = 1.00 × 109 s-1 per atom.

The number density is given by the ideal gas law:n = P/RT

where P is the pressure, R is the gas constant, and T is the temperature. The pressure is 1 bar, which is 105 Pa. The gas constant is R = 8.31 J/mol K.

Therefore,n = P/RT= (1 × 105 Pa)/(8.31 J/mol K × 298 K)= 40.2 × 1025 m-3

The collision cross-section is σ = 36 A2 = 3.6 × 10-18 m2.

Substituting the values into the equation for γ, we getγ = n (8kT/πm)1/2σ= 40.2 × 1025 m-3 (8 × 1.38 × 10-23 J/K × T/π × 6.63 × 10-26 kg)1/2 (3.6 × 10-18 m2)= 1.00 × 109 s-1 per atom

Solving for T, we get T = 198 K

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Answer:

The inner planets (C)

Explanation:

I hope this helps and i got this answer right on my test!!!

Answer:

The mechanical advantage (M.A) of a real machine is always less than its velocity ratio(V.R) because mechanical advantage decreases due to the friction and weight of moving parts of the machine whereas the velocity ratio remains constant.

Answer:

a system is a set of some things which helps the good happenings in ousr day to day life. It also helps the astrophysisists to find the planets with a system

Answer:

3000N

Explanation:

divided to get answer

the force needed to accelerate the 1000kg car by 3m/s2 is 3000N

a) pH after 0 mL HCl addition: 11.26

b) pH after 10 mL HCl addition: 10.51

c) pH after 30 mL HCl addition: 9.18

d) pH after 40 mL HCl addition: 8.91

NH₃ is a weak base, and HCl is a strong acid. During the titration, HCl will react with NH₃ to form NH₄⁺ ions and Cl⁻ ions. The pH of the solution will change depending on the amount of HCl added.

a) When 0 mL of HCl is added, there is no change in the solution, so the pH remains at the initial value of NH₃, which is 11.26.

b) After adding 10 mL of HCl, some NH₃ will react with the HCl. The remaining NH₃ will be in excess, resulting in a lower pH of 10.51. The solution is becoming more acidic.

c) As more HCl is added (30 mL), the reaction between NH₃ and HCl is nearly complete. The excess HCl will now start to contribute to the acidity of the solution, resulting in a further decrease in pH to 9.18.

d) After adding 40 mL of HCl, the reaction between NH₃ and HCl is complete, and the excess HCl will dominate. The pH decreases slightly to 8.91, indicating a highly acidic solution.

Overall, as more HCl is added, the pH of the solution decreases, shifting it from being basic (due to NH₃) to acidic (due to the excess HCl).

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The complete question is:

A 10.0−mL solution of 0.780 M NH3 is titrated with a 0.260 M HCl solution. Calculate the pH after the following additions of the HCl:  a)0mL b)10ml c)30mL d)40mL.

Increasing the distance between an electromagnet and the compass will cause the observed effect of the compass to decrease in strength

The strength of the magnetic field produced by an electromagnet decreases as the distance from the electromagnet increases. This means that if the distance between the electromagnet and the compass increases, the magnetic field that the compass is experiencing will weaken.

As a result, the observed effect of the compass will decrease in strength as the distance between the electromagnet and the compass increases.

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Hi there!

We can begin by calculating the impulse exerted on the soccer ball:

I = Δp = mΔv

Plug in the given values:

I = 0.45 × 20 = 9 Ns

I = Ft, so:

I/t = F

9/0.1 = 90 N

Answer:

a. The total momentum of the trolleys which are at rest before the separation is zero

b. The total momentum of the trolleys after separation is zero

c. The momentum of the 2 kg trolley after separation is 12 kg·m/s

d. The momentum of the 3 kg trolley is -12 kg·m/s

e. The velocity of the 3 kg trolley = -4 m/s

Explanation:

a. The total momentum of the trolleys which are at rest before the separation is zero

b. By the principle of the conservation of linear momentum, the total momentum of the trolleys after separation = The total momentum of the trolleys before separation = 0

c. The momentum of the 2 kg trolley after separation = Mass × Velocity = 2 kg × 6 m/s = 12 kg·m/s

d. Given that the total momentum of the trolleys after separation is zero, the momentum of the 3 kg trolley is equal and opposite to the momentum of the 2 kg trolley = -12 kg·m/s

e. The momentum of the 3 kg trolley = Mass of the 3 kg Trolley × Velocity of the 3 kg trolley

∴ The momentum of the 3 kg trolley = 3 kg × Velocity of the 3 kg trolley = -12 kg·m/s

The velocity of the 3 kg trolley = -12 kg·m/s/(3 kg) = -4 m/s

a-The total momentum of the trolleys before separation=0

b.The total momentum of the trolleys after  separation=0

c. The momentum of 2kg trolley after  separation=12kg-m/sec

d. The momentum of 3kg trolley after separation=-12kg-m/sec

e. The velocity of the 3kg trolley=4kg-m/sec

Given-

Trolley A with mass= 2kg

Trolly B with mass= 3kg

Velocity of trolly A =6m/sec

A- Total momentum of the trolleys before separation-

Here, in this problem both the trolleys are in the rest position hence the momentum of both trolleys = 0

B- Total momentum of the trolleys after  separation-

We know that motion never changes in an isolated collection of objects,

hence the momentum of the trolleys before and after the separation=0

C- Momentum of the Trolley A (2kg)-

It is known that momentum= Mass x Velocity

\(P=m\times v\)

\(P=2\times 6\)

\(P=12\)

Hence, the momentum of the 2kg trolley is 12 kg-m/sec

D- Momentum of the Trolley B (3kg)-

As we know that  motion never changes in an isolated collection of an object hence the total moment of after saparation = 0

hance the momentum of the trolley B will be equal and opposite to the momentum of trolley A=

\(P= -12\)

Momentum of trolley B (3kg) is -12kg-m/sec

E- The velocity of the 3kg trolley-

The momentum of trolley A= Momentum of trolley B

\(m_{b} v_{a} =m_{b} v_{a}\)

\(-2\times 6=3\times v_{a}\)

\(v_{a}=-4\)

The value of the velocity of the 3kg trolley is -4m/sec

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The kinetic energy of a non-relativistic free electron is given by the equation:

K = (1/2) mv^2

where K is the kinetic energy, m is the mass of the electron, and v is its velocity.

The de Broglie wavelength of an electron is given by the equation:

λ = h / p

where λ is the wavelength, h is the Planck's constant, and p is the momentum of the electron.

Since the kinetic energy of the electron is given as K, we can write:

K = (1/2) mv^2

The momentum of the electron can be calculated using the equation:

p = mv

Now, let's assume that the initial wavelength of the electron is λ1 and the final wavelength is λ2 (λ2 = 2λ1).

From the de Broglie equation, we have:

λ1 = h / p1

λ2 = h / p2

Dividing these two equations, we get:

λ2 / λ1 = p1 / p2

Since p = mv, we can rewrite the equation as:

λ2 / λ1 = m1v1 / m2v2

Given that the mass of the electron remains constant, we have m1 = m2, so the masses cancel out:

λ2 / λ1 = v1 / v2

Since λ2 = 2λ1, we can substitute this into the equation:

2 = v1 / v2

v1 = 2v2

Now, let's substitute this value of v1 into the expression for kinetic energy:

K = (1/2) m(2v2)^2

K = 4(1/2) mv2^2

K = 2mv2^2

Therefore, the kinetic energy of the electron when its wavelength doubles is 2 times its initial kinetic energy, or 2K.

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Answer:it is unstable and may be fragmented or lie along a fault line

Explanation:

The magnitude of friction is 21.715N and its direction is downward.

Given information:

Weight of the block (W) = 15 kg

Inclined angle (θ) = 10 degrees

Applied force by the hiker (\(F_{applied\)) = 10 N

Static friction coefficient (μ_static) = 0.35

Kinetic friction coefficient (μ_kinetic) = 0.15

The magnitude of the static friction force (F_static) can be calculated using the formula:

F_static = μ_static × N

Where N is the normal force exerted on the block, which is equal to the component of the weight of the block perpendicular to the inclined surface:

N = W × cos(θ)

The magnitude of the applied force (F_applied) should be compared with the magnitude of the maximum static friction force (F_static). If F_applied is greater than or equal to F_static, the hiker can move the wood up the inclined surface.

If the hiker is exerting enough force to move the wood, the magnitude of the friction force (F_friction) can be calculated as:

F_friction = μ_kinetic × N

If the hiker is not exerting enough force to move the wood, the magnitude of the friction force remains zero (since the block remains at rest).

Let's calculate the values:

N = W ×  cos(θ)

N = 15 kg × 9.8 m/s² × cos10°

F_static = μ_static × N

F_static = 0.35 × (15 kg × 9.8 m/s² × cos10°)

= 50.66 N

F_friction = μ_kinetic ×  N

F_friction = 0.15 ×  (15 kg × 9.8 m/s² × cos10°)

= 21.715 N

Static friction is more than kinetic friction. Hence, the direction of the friction is downward.

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Answer:

divide the number of times the event occurs by the length of time.

Explanation:

Answer:

Gases, liquids and solids are all made up of atoms, molecules, and/or ions, but the behaviors of these particles differ in the three phases. ... gas are well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.

Explanation:

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Answer:

Behaviour and uses of electromagnetic waves

Radio waves. Radio waves are used for communication such as television and radio. ...

Microwaves. Microwaves are used for cooking food and for satellite communications. ...

Infrared. ...

Visible light. ...

Ultraviolet radiation.

=> send Brainly to my phone without wires or cables

=> broil a steak in the oven

=> warm the leftover steak in the microwave

=> take pictures of the insides of my teeth

=> open the garage door without getting out of the car

=> change the TV channel without getting up off the couch

=> use it to walk around the room without bumping into things

=> listen to news on the radio

=> read the news in the paper

=> get a sun tan

=> identify cars that are speeding

=> call "CQ" on 10 meters when the band is open

from the perspective of the passengers on the spacecraft, the trip to Alpha Centauri takes approximately 13.782 years.

To calculate the time it takes for the trip to Alpha Centauri from the perspective of the passengers on the spacecraft traveling at a speed of 0.95c (where c is the speed of light), we can use the concept of time dilation in special relativity.

According to special relativity, time dilation occurs when an object is moving at a significant fraction of the speed of light relative to an observer. Time dilation states that as an object's velocity approaches the speed of light, time appears to slow down for that object as observed by a stationary observer.

The formula for time dilation is:

t' = t / √(1 - (v^2 / c^2))

Where:

t' is the time experienced by the moving object (passengers on the spacecraft)

t is the time measured by a stationary observer (the time on Earth)

v is the velocity of the object relative to the observer (0.95c in this case)

c is the speed of light

Given:

Distance to Alpha Centauri (d) = 4.3 light-years

Speed of the spacecraft relative to Earth (v) = 0.95c

First, we need to calculate the time experienced by the passengers (t') on the spacecraft using the time dilation formula:

t' = t / √(1 - (v^2 / c^2))

Since the speed of light is approximately 3.00 × 10^8 m/s, we can substitute the values:

t' = 4.3 years / √(1 - (0.95c)^2 / c^2)

t' = 4.3 years / √(1 - 0.9025)

t' = 4.3 years / √(0.0975)

t' = 4.3 years / 0.312

t' ≈ 13.782 years

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To calculate how long it would take a horizontally launched projectile to hit the ground we will need to know only the height of the projectile. The correct option is 4.

To calculate how long it would take a horizontally launched projectile to hit the ground (the time of flight), we need to use the following equation:  

\( y_{f} = y_{i} + v_{i_{y}}t - \frac{1}{2}gt^{2} \)   (1)

Where:                

t: is the time      

\(y_{f}\): is the final height = 0 (when it hits the ground)

\(y_{i}\): is the initial height

\(v_{i_{y}}\): is the initial vertical speed of the projectile = 0

g: is the acceleration due to gravity = 9.81 m/s²

Hence, by solving equation (1) for t:

\( t = \sqrt{\frac{2y_{i}}{g}} \)  

Hence, we will need only to know the height of the projectile to find the time. The correct option is 4.

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Answer:reactant,active site,enzyme below,substrate,products

Explanation: