How does Newton’s second law apply to golf

Answer:

The S.I unit of G must be m³/kg.s² to keep the equation consistent.

Explanation:

We have the equation:

F = Gm₁m₂/r²

where,

F = Gravitational Force between Two Bodies

G = Gravitational Constant

m₁ = Mass of 1st Body

m₂ = Mass of 2nd body

r = Distance between the Bodies

The S.I Units of the quantities are:

F = Newton = kg.m/s²

m₁ = kg

m₂ = kg

r = meter = m

G = ?

Therefore, to find the units of Gravitational Constant (G), we substitute the known units in the formula:

kg.m/s² = G(kg)(kg)/m²

G = m³/kg.s²

Answer:

h(t) = -16t^2 + 1000

Explanation:

The quadratic function that represents the motion of a freely falling ballast bag that starts from a resting position on a balloon 1000 feet above the ground is given by the equation h(t) = -16t^2 + 1000, where h(t) is the height of the ballast bag in feet at time t seconds after it is released, and -16t^2 represents the effect of gravity on the ballast bag as it falls.

Answer:

-16t^2 + 1000

Explanation:

Answer:

The answer is "6:45 and 7:15".

Explanation:

In the given attache file two clocks are added, that's explanation defined as follows:

In the left image, it may assume, that the clock only at the right-hand side of a scene is move-in its previous position, which is shown to the left, as it was at 6:45 on the left but in the right image it will display the time that is 7:15.

Yes, a symptom of depression is a loss of appetite, and eating disorders are often developed as a result of an unhealthy coping mechanism with life; therefore, people with depression can get eating disorders and vice versa. They go hand in hand.

Answer:

NO 21 days wouldn't be enough because it takes at least one month to observe all of the moon's phases.

Explanation:

Hope this helps!!

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

\(k = \frac{1}{2} m {v}^{2} \\ \)

m is the mass

v is the velocity

From the question we have

\(k = \frac{1}{2} \times 8 \times {4}^{2} \\ = 4 \times 16\)

We have the final answer as

Hope this helps you

the answer to your question is 200 J

Answer:

Explanation:

Given:

F = Fₓ·i + Fy·j

S = Sₓ·i + Sy·j

Fₓ = 3 N

Fy = - 2 N

Sₓ = 5 m

Sy = 2 m

_________

A - ?   - Work

α - ? - Angle

F = 3·i - 2·j

S = 5·i + 2·j

The work is numerically equal to the scalar product of the displacement force

A = (F·S) = 3·5 + (-2)·2 = 15 - 4 = 11 J

Modules:

| F | = √ (3² + (-2)² ) = √ (9 + 4) = √ 13

| S | = √ (5² + 2² ) = √ (25 + 4) = √ 29

Angle:

cos α = (F·S) / ( |F| · |S| ) = 11 / ( √13 · √29) ≈ 0,5665

α ≈ 55.5°

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Answer:

The atomic number of the element in this notation is 15.

Explanation:

The X notation for an atom provides information about its atomic number and mass number. The atomic number is the number of protons in the nucleus of an atom, which determines its chemical properties and identity as an element. The mass number is the sum of the number of protons and neutrons in the nucleus.

In the notation "32 on 15 X", the number on the top (32) represents the mass number of the atom, which is the total number of protons and neutrons in the nucleus. The number on the bottom (15) represents the atomic number of the atom, which is the number of protons in the nucleus.

Therefore, the atomic number of the element in this notation is 15.

Answer:

1. Shield volcano

Runny,basaltic magma with low silica and low gas content. Has a broad,low profile.

2. Cinder cone volcano

Thick viscosity andesitic magma with high silica content and high gas content. Rapidly solidifying lava forms high,steep-sided cones.

3. Composite volcano

Medium viscosity rhyolitic magma with medium silicon content and medium gas content.Have flatter domes called cones.

Explanation:

Hope it helps you..

Your welcome in advance..(◍•ᴗ•◍)

Hello and Good Morning/Afternoon:

What makes a unit a fundamental SI unit:

Thus the seven fundamental S.I. units are:

Hope that helps!

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Answer:

6621.75J

Explanation:

In this case, the bell is not in motion. So we are going to calculate its potential energy rather than its kinetic energy since kinetic energy is the energy a body possesses in motion.

The formula for the potential energy is m*g*h, meaning the mass * acceleration due to gravity * height. Here the mass, m = 15kg, the acceleration due to gravity = 9.81m/s^2, and the height, h = 45m

Substituting our values, the answer becomes 15 * 9.81 * 45 = 6621.75J. Hope you understood my explanation?

Let the stick be divided into two parts, A and B, by the point where the two ladybugs are sitting. Let the length of part A be x and the length of part B be (1-x). Then, we have:

x + (1-x) = 1

Let the distance of the midpoint from the end of part A be d. Then, we have:

d = x/2 - (1/7)

Let the mass of the stick be M and the mass of each ladybug be m. Then, we have:M = 7m

The gravitational force acting on the system produces a clockwise moment about the end of part A, which is given by:

Mg(x/2 - d) = Mg(x/2 - (x/2 - 1/7)) = Mg/7

Let the distance of the first ladybug from the end of part A be L1 and the distance of the second ladybug from the end of part A be L2. Then, we have:

L1 = x

L2 = 1 - (1-x) = x

The moments produced by the ladybugs are given by:

mgL1sinθ

mgL2sinθ

mgL1sinθ = mgL2sinθ = Mg/7

Substituting the given values and solving for θ, we get:

sinθ = M/14m = 1/14

θ = 3.87 degrees

Mg(x/2 - d)sinθ

2mgL1sinθ

Substituting the given values and solving for x, we get:

x = 0.315

Substituting this value into the equation for the moment of inertia, we get:

I = 1.08e-5.

Inertia is the property of an object to resist any change in its state of motion. It is a measure of an object's resistance to changes in its velocity, including changes in direction and speed. Objects with more mass have more inertia, and they require more force to be moved or to stop moving. Inertia is described by Newton's first law of motion, which states that an object at rest will remain at rest, and an object in motion will remain in motion with a constant velocity, unless acted upon by an external force.

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Answer:

an acceleration of the boy as it passes through the board and be the total time the boy is in contact with the board solution

The final velocities of the car and truck just after the collision will be as per the conservation of momentum.

Momentum is defined as product of mass and velocity of the body. It is denoted by letter p and it is expressed in kg.m/s. Mathematically p = mv. it discuss the moment of the body. body having zero mass or velocity has zero momentum. The dimensions of the momentum is [M¹ L¹ T⁻¹].

According to conservation of momentum, Initial momentum will be equal to the final momentum. In the elastic collision there is no loss of energy, both energy and momentum is conserved.

if the the car is coming with velocity equal to the mass of the truck and truck is coming with mass of the car, then they have same momentum in opposite direction when they collide each other the final velocity of both car and truck becomes zero.

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( a) The acceleration of the box in the absence of friction is 8.49 m/s².

(b) The acceleration of the box in the presence of friction is 1.7 m/s².

(c) The speed of the box at the bottom of the incline is 18.44 m/s.

The acceleration of the box if no friction is present is calculated by applying Newton's second law of motion.

mg cosθ = ma

g cosθ = a

where;

The acceleration of the box in the absence of friction is calculated as;

a = ( 9.8 ) x ( cos 30 )

a = 8.49 m/s²

The acceleration of the box in the presence of friction is calculated as;

Ff = ma

where;

μmg cosθ = ma

μg cosθ = a

( 0.2 x 9.8 x cos 30 ) = a

1.7 m/s² = a

The speed of the box at the bottom of the incline is calculated as follows;

v² = u² + 2ah

where;

v² = 0 + 2ah

v = √ ( 2ah )

h = L sinθ

v = √ ( 2 x a x L sinθ )

v = √ ( 2 x 1.7 x 200 x sin 30 )

v = 18.44 m/s

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Answer:

Kinematics is the study of how things move while dynamics is the study of forces and motion

The current in a circuit that has a resistance of 30 ohms and a power of 2 watts is 0.2581 Ampere.

Solution:

The power in an electrical circuit is given by the equation:

\(P = I^{2} R\)

I = Current in the circuit

R = Resistance offered by the circuit

P = 2 watts

R = 30 Ω

I =?

2Watts = \(I^{2}\)x30Ω

\(I = \sqrt{\frac{2Watts}{30} }\)

I = 0.2581 Ampere.

The current through a resistor is inversely proportional to its resistance value. Resistance is a measure of resistance to the flow of current in an electrical circuit. Resistance is measured in ohms, represented by the Greek letter omega.

Electric current is the flow of charge through matter. The material or conductor through which current flows is often a metal wire, but current can also flow through some gases, liquids, and other materials. The circuit can be wired in two ways. Current is the speed at which charge flows. Resistance is the tendency of a material to resist the flow of electrical charges.

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The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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Answer:

Below

Explanation:

Fn = mg cos(angle )    <======just plug in the values given

Fn = 43 * 9.81 * cos 35 = ~ 346 N

The frequency of a 1.77-Angstrom x-ray photon is 1.694×10^18hz.

AS, we can see, the wavelength given of x ray photon

\(\lambda\)=1.77-Angstrom = 1.77×10^-10

we know the relationship betwee frequency and lambda

c=λν

ν=c/\(\lambda\)

ν is frequency , \(\lambda\) is wavelength, and c is speed of light

c= 3×10^8m/s

now put the value in equation:

ν= 3×10^8m/s÷1.77×10^-10

ν=1.694×10^18hz

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Answer:

The resistance of 4/0 coated copper conductors is given as 0.0626 ohms per 1000 feet. To find the total resistance of the three 4/0 conductors installed in parallel, we can use the formula for combining resistances in parallel.

Since the total length for each of the three conductors is 323 feet, the resistance of each conductor can be calculated as follows:

Resistance of one conductor = (0.0626 ohms / 1000 feet) * 323 feet

To find the total resistance when the conductors are in parallel, we use the formula:

1/Total Resistance = 1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3

Total Resistance = 1 / (1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3)

Substituting the values, we get:

Total Resistance = 1 / (1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet))

Simplifying the expression will give us the total resistance of the three 4/0 conductors installed in parallel.

Because of location, the Hartsfield Jackson international airport has become a center for transportation. The is also a center for transportation and home to the nation’s busiest airport.

It should be noted that transportation simply means the movement of people and animals from one location to another. It should be noted that there are different means of transportation such as rail, air, road, etc.

In this case, because of location, the Hartsfield Jackson international airport has become a center for transportation. The is also a center for transportation and home to the nation’s busiest airport. This is located in Atlanta Georgia.

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Select the correct answer from each drop-down menu. Because of location, the has become a center for transportation. The is also a center for transportation and home to the nation’s busiest airport.

a. Dallas International Airport.

b. Denver International Airport.

c. John Kennedy International Airport

d. Hartsfield Jackson international airport

The displacement of the runner after four seconds is 78.4 m.

We know that in this case, we are dealing with a case of an object that has a motion under gravity. We are told that the road runner an fell straight down off a cliff. The fact that we have been told that the runner just fell down the cliff means that the initial velocity of the runner would have to be taken in this context as zero since the runner was dropped from a height as shown.

Acceleration of the runner (g) = 9.8 m/s^2

Initial velocity of the runner (u) = 0 m/s

Time take (t) = 4 seconds

We then have;

h = ut + 1/2gt^2

If we then know that the initial velocity of the person is zero, then we have;

h = 1/2gt^2

h = 0.5 * 9.8 * (4)^2

h = 78.4 m

The height is 78.4 m.

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The velocity gradient across the 3.7 mm thick oil layer on the flat plate sliding on the horizontal table is 0.594 m/s/m.

Given:

Surface area of the plate (A) = 1.8 m^2

Thickness of the oil layer (h) = 3.7 mm = 0.0037 m

Force applied on the plate (F) = 2.2 N

Dynamic viscosity of the oil (η) = 0.89 x 10^-3 Ns/m^2

To calculate the velocity gradient across the oil layer, we can use the equation:

τ = η * du/dy

where τ is the shear stress, η is the dynamic viscosity, and du/dy is the velocity gradient.

Since the force (F) applied on the plate is responsible for the shear stress, we can write:

τ = F / A

Substituting the given values, we have:

F / A = η * du/dy

Solving for du/dy, we get:

du/dy = (F / A) / η

Substituting the values, we have:

du/dy = (2.2 N) / (1.8 m^2 * 0.89 x 10^-3 Ns/m^2)

du/dy = 0.594 m/s/m

Therefore, the velocity gradient across the oil layer is 0.594 m/s/m.

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The unit of the potential energy is the same as the kinetic enrgy and it is kg·m²/s².

And the SI unit of the potential energy is Joule. It is represented by the symbol J.

Thus, Joules (J) is the SI unit of the measurement of the potential energy.

Answer:

Explanation:

Let the initial rotational inertia be I and final rotational inertia be I / 6 .

Let the initial angular velocity be ω₁ and final angular velocity be ω₂.

Applying conservation of angular momentum law

I x ω₁ = I / 6 x ω₂

6 ω₁  = ω₂

initial rotational kinetic energy = 1/2 I x ω₁ ²

Final  rotational kinetic energy = 1/2 ( I / 6 ) x ω₂ ²

Final  rotational kinetic energy / initial rotational kinetic energy

= ( 1 / 6 ) x ω₂ ² / ω₁ ²

=  ω₂ ² / 6ω₁ ²

= 36 ω₁ ² / 6ω₁ ²

= 6 .

The ratio will be "6". A further solution is below.

Let,

The initial rotational inertia,

The final rotational inertia,

By applying the conservation of angular momentum law, we get

→ \(1\times \omega_1 = \frac{1}{6}\times \omega_2\)

→    \(6 \ \omega_1 = \omega_2\)

Now,

Initial rotational K.E = \(\frac{1}{2}1\times \omega_1^2\)

Final rotational K.E = \(\frac{1}{2} (\frac{1}{6} )\times \omega_2^2\)

hence,

→ \(\frac{Final \ rotational \ K.E}{Initial \ rotational \ K.E} = \frac{(\frac{1}{6} )\times \omega_2^2}{\omega_1^2}\)

                                  \(= \frac{\omega_2^2}{6 \omega_1^2}\)

                                  \(= 6\)

Thus the answer above is right.

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Although it can be represented in several programming languages, pseudocode cannot be executed by a computer.

She can identify areas in her classmate's software where code is repeated and offer to use a method to wrap up those repeated sections. The code snippet below employs a loop to repeatedly process a list of numbers.

It is employed to create the preliminary design or framework of a program. The flow of a program is streamlined with pseudo code, but supporting data is left out. It is pseudocode, not an actual programming language.

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The wavelength of light that should be used to obtain fringes that are 0.0045 m wide after reducing the distance between the screen and the slit by half is 2.25 * 10^7 Å.

Huygens's Principle states that every point on a wavefront can be considered as a source of secondary spherical wavelets that spread out in all directions with the same speed as the original wave. The new wavefront is formed by the envelope of these secondary wavelets at a later time.

Now, let's consider a Young's double-slit experiment. In this experiment, when light passes through two narrow slits, it creates an interference pattern on a screen behind the slits. The fringe width is the distance between two consecutive bright or dark fringes in the pattern.

Given that the fringe width obtained is 0.6 cm and the wavelength of light used is 4500 Å (Angstroms), we can calculate the wavelength of light required to obtain fringes that are 0.0045 m wide.

We can use the formula for fringe width in Young's double-slit experiment:

w = (λ * D) / d

Where:

w is the fringe width,

λ is the wavelength of light,

D is the distance between the screen and the double slits, and

d is the distance between the two slits.

Let's calculate the value of D/d using the given information:

D/d = w / λ

= 0.006 m / 4500 Å (1 m = 10^10 Å)

= 0.006 * 10^10 / 4500 m^-1

Now, if the distance between the screen and the slit is reduced by half, the new value of D/d would be:

(D'/d) = (0.006/2) * 10^10 / 4500 m^-1

Now, we can rearrange the equation to solve for the new wavelength (λ'):

(λ' * D') / d = (D/d)

λ' = (D/d) * d / D

= [(0.006/2) * 10^10 / 4500] * (4500 / 0.006) Å

= 0.0045 m * 10^10 / 2 Å

= \(0.00225 * 10^{10\) Å

=\(2.25 * 10^7\)Å

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Answer and Explanation:

A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing. Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body.

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A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing.

Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body