how does newtons law intertia relate to a index card being placed on a cup then a penny ontop of the index then flicking it off?

The Earth is approximately 81 times more massive than the moon. During the gravitational interaction of the Earth and the Moon, the magnitude of the gravitational force acting on the Earth is C) is the same as to the gravitational force acting on the Moon.

Isaac Newton's laws of motion and his law of gravitation state that the force between any two objects in the universe is proportional to the product of their masses and inversely proportional to the square of the distance between their centers. This implies that the gravitational force of the Earth on the moon and the moon on the Earth is of the same magnitude and depends on their masses and distance apart.

In addition, the gravitational pull of the Earth affects more than just the Moon, it affects all objects around it. The Earth's gravitational field can be compared to a rubber sheet stretched out by the Earth's mass, and all other objects are placed on it. The bigger an object's mass, the more it bends the rubber sheet, and other objects roll towards it. This is why the Moon orbits around the Earth while other smaller objects orbit the Sun. So the correct answer is C) is the same as.

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The velocity of the ball when it strikes the ground, given the data is 21.56 m/s

From the question given above, the following data were obtained:

The velocity of the ball when it strikes the ground can be obtained as illustrated below:

v = u + gt

v = 0 + (9.8 × 2.2)

v = 0 + 21.56

v = 21.56 m/s

Thus, the velocity of the ball when it strikes the ground is 21.56 m/s

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The magnitude of the magnetic force is approximately \(1.92 * 10^{-15} N\) .

To calculate the magnitude of the magnetic force acting on an electron moving perpendicular to a uniform magnetic field, you can use the formula:

F = q * v * B

where F is the magnetic force, q is the charge of the electron, v is its speed, and B is the magnetic field strength.

For an electron, q = -\(1.6 * 10^{-19}\) C. Given the speed v = \(3.0 * 10^{4}\) m/s and magnetic field B = 0.40 T, the magnetic force can be calculated as:

F = (-\(1.6 * 10^{-19}\) C) * (\(3.0 * 10^{4}\) m/s) * (0.40 T)

F ≈ -\(1.92 * 10^{-15} N\)

Since we're interested in the magnitude of the force, we can ignore the negative sign and say:

The magnitude of the magnetic force is approximately\(1.92 * 10^{-15} N\)

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God created all things in the beginning of time

Explanation:

He said the things he wanted to make an they came into existence.

Im christian so if u dont like the answer or get mad i'm sorry i couldnt help you

Answer:

Explanation:

A convex mirror is used in automobiles to have a Clear View of the traffic behind because they give an erect, virtual, full size diminished image of distant objects with a wider field of view.

hope it helps :)

Cyclotron to make 1 milligram of the isotope fluorine-18 for use a a diagnostic tool with it PET scanner. It seems that the hospital should plan to make more F-18 the next morning, as the amount remaining at midnight is very small.

The half-life of F-18 is 1.8 hours, so after 1.8 hours, half of the original amount of F-18 will remain. After 3.6 hours, a quarter of the original amount will remain, and so on.

At 3:00 PM (9 hours after the F-18 was made), the hospital will have

= 1/2^(9/1.8)

= 1/2^5

= 1/32

= approximately 0.03125 milligrams of F-18 remaining.

At midnight (18 hours after the F-18 was made), the hospital will have

= 1/2^(18/1.8)

= 1/2^10

= 1/1024

= approximately 0.0009765625 milligrams of F-18 remaining.

While using cyclotron, based on these calculations, it seems that the hospital should plan to make more F-18 the next morning, as the amount remaining at midnight is very small.

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Answer:

Asteroids and comets have a few things in common. They are both celestial bodies orbiting our Sun, and they both can have unusual orbits, sometimes straying close to Earth or the other planets. They are both “leftovers” — made from materials from the formation of our Solar System 4.5 billion years ago. But there are a few notable differences between these two objects, as well. The biggest difference between comets and asteroids, however, is what they are made of.

While asteroids consist of metals and rocky material, comets are made up of ice, dust, rocky materials and organic compounds. When comets get closer to the Sun, they lose material with each orbit because some of their ice melts and vaporizes. Asteroids typically remain solid, even when near the Sun.

Right now, the majority of asteroids reside in the asteroid belt, a region between the orbits of Mars and Jupiter which may hold millions of space rocks of varying sizes. On the other hand, the majority of comets are in the farthest reaches of our Solar System: either 1. in the Kuiper Belt — a region just outside the orbit of the dwarf planet Pluto that may have millions of icy comets (as well as many icy dwarf planets like Pluto and Eris); or 2. the Oort Cloud, a region where trillions of comets may circle the Sun at huge distances of up to 20 trillion kilometers (13 trillion miles).

Answer:

they are both leftovers materials

Explanation:

think about how the solar system is made the comets and asteroids are both rocks and remains of the solar system

Answer:

The energy transported by a wave is directly proportional to the square of the amplitude. So whatever change occurs in the amplitude, the square of that effect impacts the energy. This means that a doubling of the amplitude results in a quadrupling of the energy.

Explanation:

When the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.

The amplitude of a wave may be defined as the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. It is equal to one-half the length of the vibration path.

It is the principle of physics that when the amplitude of the wave is higher, the energy also gets higher. To summarise, waves carry energy. The amount of energy they carry is related to their frequency and their amplitude. The higher the frequency, the more energy, and the higher the amplitude, the more energy.

Therefore, when the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.

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Las respuestas a cada inciso son:

a) La resistencia equivalente de la "escalera" de resistores iguales de 125 Ω que se muestra en la figura adjunta es:

\(R_{t} = 341.7 \: \Omega\)

b) La corriente a través de cada uno de los tres resistores de la izquierda si se conecta una batería de 50.0 V entre los puntos A y B es:

a) En la imagen adjuntada correspondiente a la Figura 26-40, podemos observar que las resistencias 1, 2 y 3 están en serie, por lo tanto la ressitencia equivalente entre estas 3 es:

\( R' = R_{1} + R_{2} + R_{3} \)

De aquí en adelante tendremos presente que las todas las resistencias son iguales entre sí y por ende igual a 125 Ω. Las notaciones del 1 al 9 son para poder mostrar la resolución del problema.  

Entonces:

\( R' = 3R \)

Ahora, esta resistencia está en paralelo con la resistencia R₄, por lo tanto la resistencia equivalente entre estas dos es:

\( \frac{1}{R''} = \frac{1}{R'} + \frac{1}{R_{4}} = \frac{1}{3R} + \frac{1}{R} = \frac{4R}{3R^{2}} \)

\( R'' = \frac{3}{4}R \)

Luego, esta resistencia está en serie con las resistencias R₅ y R₆, por lo tanto:

\( R''' = R'' + R_{5} + R_{6} = \frac{3}{4}R + 2R = \frac{11}{4}R \)

Esta resistencia está ahora en paralelo con R₇, entonces:

\( \frac{1}{R''''} = \frac{1}{R'''} + \frac{1}{R_{7}} = \frac{4}{11R} + \frac{1}{R} = \frac{15R}{11R^{2}} \)

\( R'''' = \frac{11}{15}R \)

Finalmente, esta resistencis está en serie con las resistencias R₈ y R₉, por lo tanto la resistencia total es:

\(R_{t} = R'''' + R_{8} + R_{9} = \frac{11}{15}R + 2R = \frac{41}{15}R = \frac{41}{15}*125 \: \Omega = 341.7 \: \Omega\)

b) Para este inciso debemos usar la Ley de Kirchhoff, pues tenemos tres mallas. Supondremos que las corriente de cada malla fluiran en sentido horario, por lo tanto las ecuaciones de para cada malla serán:

Malla 1

Segun la ley de Ohm tenemos:

\(V-i_{1}R-i_{3}R=0\) (1)

Malla 2

\(-i_{2}R-i_{5}R-i_{2}R+i_{3}R=0\) (2)

Malla 3

\(-i_{4}R-i_{4}R-i_{4}R+i_{5}R=0\) (3)

Recordemos tambien que:

\(i_{1}=i_{2}+i_{3}\) (4)

\(i_{2}=i_{4}+i_{5}\) (5)

Lo que debemos hacer ahora es resolver el sistema de ecuaciones y encontrar los valore de las corrientes. Por lo tanto, los valores de las corrientes serán:

\(i_{1}=3/13\: A\)

\(i_{2}=4/65\: A\)

\(i_{3}=11/65\: A\)

\(i_{4}=1/65\: A\)

\(i_{5}=3/65\: A\)

Finalmente:

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In ten seconds,a total of 5 waves crash onto the shore of the beach .

The distance between each wave crest on the water is 8 meters.

Wave length is the length between two wave crests that is the distance between two wave crests.

We know distance between each wave crest is 8 meters

Total of 5 wave crests, the distance between first and second wave crest is 8 meters

the distance between second and third wave crest is 8 meters

So wave length = 8+8 = 16 meters

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Answer is b

Explanation:

A collection of voltaic cells (or piles) is called a battery.

What are voltaic cells?

Voltaic cells are chemical cells that generate electricity.

A series of voltaic cells connected together in a steel container which produce current as a result of oxidation reduction reaction.

In a voltaic cell there are two compartments where oxidation and reduction occurs simultaneously to produce current.

In each compartment there is an electron. The positively charged electrode is cathode(reduction) and negatively charged in anode (oxidation).

In general, the steel container in which a redox reaction occurs inside a voltaic cell is called a battery.

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Roughly spherical/surface smoothed by gravity and must be within 30 AU of the Sun. Mass is the amount of matter a planet contains and is typically measured in kilograms. Size is the diameter of a planet and is typically measured in kilometers.

Roughly spherical/surface refers to a shape or object that has a generally round or curved shape, but with some irregularities on its surface.

Examples include planets, apples, and even some rocks. This type of shape is often used for objects that need to be able to roll or move in some way, since the curved shape helps it move more easily.

The surface of the Earth is a roughly spherical surface, as it has small bumps and hills, valleys, and other imperfections that make it slightly misshapen .Planet characteristics include their mass, size, surface gravity, orbital period, atmosphere, and distance from the sun.

Surface gravity is the force of gravity on a planet's surface and is typically measured in meters per second squared. Orbital period is the amount of time it takes for a planet to make one full orbit around the sun and is measured in years.

Atmosphere is the gases that make up a planet’s air, such as oxygen, nitrogen, and carbon dioxide, and is measured in pressure.

Therefore, Distance from the sun is the average distance from the center of the sun to a planet and is measured in astronomical units.

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The angle between the first and second interference minima for light of wavelength 485 nm passing through a single slit of width 8.32 x 10^-6 m is approximately 0.034 degrees.

This can be calculated using the formula θ = λ / (m * d), where λ is the wavelength, m is the order of the minimum, and d is the slit width. The formula for the angle θ between interference minima in a single slit diffraction pattern is given by θ = λ / (m * d), where λ is the wavelength of light, m is the order of the minimum (1 for the first minimum, 2 for the second minimum, and so on), and d is the width of the slit. In this case, the wavelength is 485 nm (or 485 x 10^-9 m) and the slit width is 8.32 x 10^-6 m. Plugging these values into the formula, we get θ = (485 x 10^-9) / (2 * 8.32 x 10^-6), which simplifies to approximately 0.034 degrees.

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Answer:

t = 0.5 s

Explanation:

We know that the distance from the batter to the bleachers is 170 m, and we are trying to find the time it takes for the sound of the ball hitting the bat to travel that distance.

We can use the formula v = d/t, where v is the speed of sound in air (we know that sound in air travels at a speed of 340 m/s), d is the distance the sound travels (170 m in this case), and t is the time it takes for the sound to travel that distance.

Rearranging the formula to solve for t, we get t = d/v. Plugging in the values we know, we get:

t = 170 m / 340 m/s

t = 0.5 s

Therefore, it takes 0.5 seconds for the sound of the ball hitting the bat to travel 170 meters from home plate to the bleachers.

The acceleration of the sled is, the acceleration is equal to the acceleration of gravity multiplied by the sine of the angle for a frictionless incline of degree.

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Answer: They CG of a vehicle highly influences manuovereability and performance / dynamic control over vehicle.

Explanation: it was from quora

you are so much welcome

To find the current in the resistor, we can use Ohm's Law and the concept of equivalent resistance. Thus, option A is correct.

First, let's calculate the equivalent resistance of the three cells connected in parallel. When resistors are connected in parallel, the reciprocal of the equivalent resistance is equal to the sum of the reciprocals of the individual resistances:

1/Req = 1/R1 + 1/R2 + 1/R3

Given that R1 = R2 = R3 = 22 Ω (internal resistance of each cell), we can substitute the values:

1/Req = 1/22 + 1/22 + 1/22

1/Req = 3/22

Taking the reciprocal of both sides, we find:

Req = 22/3 Ω

Now we can use Ohm's Law to calculate the current (I) in the resistor. Ohm's Law states that the current flowing through a resistor is equal to the voltage across it divided by its resistance:

I = V/R

Given that V = 1.1 V (emf of each cell) and R = 32 Ω (resistance), we can substitute the values:

I = 1.1/32

Calculating this value, we find:

I ≈ 0.034375 A

Therefore, the current in the resistor is approximately 0.034375 A.

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The maximum force that can be exerted horizontally on the crate without moving it is 499.8 N, considering the static friction between the crate and the wood floor. Once the crate starts to slip, the magnitude of its acceleration will be 2.94 m/s^2 due to the kinetic friction between the crate and the wood floor.

(a) To determine the maximum force that can be exerted horizontally on the crate without moving it, we need to consider the static friction between the crate and the wood floor. The maximum force can be calculated using the formula:

F_max = μ_s * N,

where μ_s is the coefficient of static friction and N is the normal force acting on the crate.

The normal force N is equal to the weight of the crate, which can be calculated as:

N = m * g,

where m is the mass of the crate and g is the acceleration due to gravity.

Substituting the given values, we have:

N = 102 kg * 9.8 m/s^2 = 999.6 N.

Therefore, the maximum force that can be exerted horizontally on the crate without moving it is:

F_max = 0.5 * 999.6 N = 499.8 N.

(b) Once the crate starts to slip, the force of friction changes from static friction to kinetic friction. The magnitude of the crate's acceleration can be calculated using the formula:

a = (μ_k * g),

where μ_k is the coefficient of kinetic friction.

Substituting the given value, we have:

a = 0.3 * 9.8 m/s^2 = 2.94 m/s^2.

Therefore, if the applied force continues once the crate starts to slip, the magnitude of its acceleration will be 2.94 m/s^2.

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The hare is currently 100 meters from the finish line and 895 metres from the starting line. The tortoise is 895 m from the starting line and is travelling at a speed of 0.27 m/s in the direction of the finish line.

The tortoise must go 895 meters whereas the hare must travel only 100 meters to reach the finish line. The tortoise will keep moving towards the finish line and may finally cross it before the hare wakes up if the hare dozes off for a predetermined period of time.

Inertia has an impact on both moving and stationary objects, according to Newton's first law of motion. According to Newton's first law, an item will remain at rest or move straight ahead at a constant speed unless another force is operating on it that is not balanced.

Therefore, If the hare travels at a speed of 15 m/s, he can afford to rest for a maximum of 6.67 seconds without losing the race.

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Wave motion allows for the transfer of energy without the physical movement of matter.

In wave motion, energy is transferred through oscillations that propagate through a medium, such as air or water, or even through a vacuum in the case of electromagnetic waves. As the wave propagates, the particles of the medium vibrate back and forth but do not move in a net direction.

This vibration transfers energy from the source to the receiver without any physical displacement of matter between the two points. Examples of wave motion include sound waves, water waves, and light waves.

This ability to transfer energy without the transfer of matter is crucial for a variety of applications, from communication technologies to medical imaging.

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Answer:

When we have capacitors in series, with capacitances c1, c2, ...., cn, the total capacitance can be obtained from the equation:

1/ct  = 1/c1 + 1/c2 + .......

When we have capacitors in parallel, with capacitances c1, c2, ..., cn, the total capacitance can be obtained from the equation:

ct = c1 + c2 +......

Ok, in this case we have two branches, and in each branch we have two capacitors in series.

So the capacitance of each branch will be:

1/ct = 1/c + 1/c = 2/c

ct = c/2.

Now we can think that we have two capacitors in parallel, each one with capacitance c/2.

So the total capacitance is:

ct = c/2 + c/2 = c.

Answer:

A

Explanation:

Trial and error is basically trying something, if it works, great. If it does not work, try another way.

Answer:

A. Trial and error

Explanation:

The other user is correct.

The maximum speed at which the car could round this particular turn without skidding is approximately 18.1 m/s.

To determine the maximum speed at which the car could round the corner without skidding, we need to calculate the maximum centripetal force that can be provided by the static friction between the car and the road.

The centripetal force is given by the equation:

F = m * v² / r,

where F is the centripetal force, m is the mass of the car, v is the velocity of the car, and r is the radius of the corner.

The maximum static frictional force that can be exerted is equal to the coefficient of static friction multiplied by the normal force acting on the car.

The normal force can be calculated as:

N = m * g,

where N is the normal force, m is the mass of the car, and g is the acceleration due to gravity.

The maximum static frictional force is then:

f = μ * N,

where f is the maximum static frictional force and μ is the coefficient of static friction.

Setting the centripetal force equal to the maximum static frictional force, we have:

m * v² / r = μ * m * g.

Simplifying and solving for v, we get:

v = √(μ * g * r).

Substituting the given values into the equation, with a coefficient of static friction of 0.82, a radius of 66 m, and the acceleration due to gravity as 9.8 m/s², we can calculate the maximum speed:

v = √(0.82 * 9.8 * 66) ≈ 18.1 m/s.

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1. C. Mass and speed

2. B. Speed

3. B. Speed

4. C. 5.7 * 10^5 J

5. C. 71 km/h

The actual momentum of the bus compare with the momentum it would have if classical mechanics were valid due to the fundamental differences between quantum mechanics and classical mechanics.

According to quantum mechanics, particles can exhibit wave-like behavior. When particles have wavelengths that are comparable to the size of objects, they are said to be delocalized, this means that an object can have a wave function that is spread out over a large region of space. This leads to uncertainty in the object's position and momentum. Therefore, in the macroscopic world, we do not observe quantum effects and classical mechanics work very well. On the other hand, classical mechanics deals with objects that are much larger than atoms and particles.

In classical mechanics, the momentum of an object is given by the product of its mass and velocity, it does not depend on the object's wave-like properties. However, in the world of quantum mechanics, the concept of momentum is not as straightforward as it is in classical mechanics. An object's momentum in quantum mechanics is represented by its wave function, which is a complex function that describes the probability of finding the object in a particular state or location.

So, the actual momentum of the bus may not be directly comparable with the momentum it would have if classical mechanics were valid. In conclusion, the actual momentum of the bus may not be directly comparable with the momentum it would have if classical mechanics were valid due to the fundamental differences between quantum mechanics and classical mechanics.

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Answer:

A: It decreased trade because soldiers no longer protected the oases.

I took it on E2020. I hope I've helped. If you need further explanation, please comment below.  

Answer:

Yes it is A

It decreased trade because soldiers no longer protected the oases.

Explanation:

B) The evidence that a chemical reaction has likely occurred is the formation of a precipitate.

A precipitate is a solid that forms from a chemical  response in a liquid  result. This is a clear  suggestion that a chemical  response has taken place because the reactants have  experienced a chemical change to form a new product that's  undoable in the original detergent.   Option A( a liquid  sluggishly losing volume) may be an  suggestion of evaporation or  immersion, but it doesn't  inescapably indicate a chemical  response.

Option C( boiling water releasing) is a physical change caused by a change in temperature, not a chemical  response. Option D( a change in the shape of a solid) could be a sign of a physical change,  similar as melting or breaking, but it isn't a clear  suggestion of a chemical  response.   thus, the  conformation of a precipitate( option B) is the most  dependable  substantiation that a chemical  response has likely  passed.

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Based on the given information, we know that there is an unknown planet with two moons in circular orbits. The table provides hypothetical data about the moons, which we can use to make calculations. To start, we need to look at the table and see what information is given. We have the masses of both moons (m1 and m2), as well as their distances from the planet (r1 and r2). We also have the gravitational constant, which is g = 6.67 × 10^-11 nm^2/kg^2.

Using this information, we can calculate the gravitational force between each moon and the planet using the formula F = G(m1m2)/r^2, where G is the gravitational constant, m1 and m2 are the masses of the moons, and r is the distance between the moon and the planet. Let's start by calculating the gravitational force between the first moon and the planet. We have m1 = 8.0 x 10^22 kg and r1 = 4.0 x 10^5 nm. Plugging these values into the formula, we get:
F1 = (6.67 x 10^-11)(8.0 x 10^22)(5.0 x 10^5)^2
F1 = 1.34 x 10^32 N
Now, let's calculate the gravitational force between the second moon and the planet. We have m2 = 5.0 x 10^22 kg and r2 = 3.0 x 10^5 nm. Plugging these values into the formula, we get:
F2 = (6.67 x 10^-11)(8.0 x 10^22)(4.0 x 10^5)^2
F2 = 4.45 x 10^31 N

Next, we can use the gravitational forces to calculate the orbital velocities of the moons. We can do this using the formula v = (GM/r)^0.5, where G is the gravitational constant, M is the mass of the planet, and r is the distance between the moon and the planet. To calculate the orbital velocity of the first moon, we need to know the mass of the planet. Unfortunately, this information is not given in the table, so we can't make this calculation. However, we can still calculate the orbital velocity of the second moon. Let's assume that the mass of the planet is 5.0x 10^24 kg (which is roughly the mass of Earth). Plugging in the values for F2, G, and r2, we get:
v2 = (GM/r2)^0.5
v2 = ((6.67 x 10^-11)(5.0 x 10^24)/(3.0 x 10^5))^0.5
v2 = 1.98 x 10^3 m/s
So the orbital velocity of the second moon is approximately 1.98 x 10^3 m/s.
Overall, without knowing the mass of the planet, we cannot fully determine the orbital velocities of both moons. However, we were able to calculate the gravitational forces between the planet and each moon using the given data in the table.

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