how does changing the voltage of a battery influences the magnetic field?

Hello!

a)
For a car on an incline, we only have the normal force and force of gravity acting on the car.

The car is only experiencing a net force caused by the sine component of the force of gravity vector, which causes it to slide down the incline towards the center of the curve.

Or, as an equation:

\(F_{net} = Mgsin\phi\)

This net force produces a centripetal force. Recall the equation for centripetal force:
\(F_c = \frac{mv^2}{r}\)

In reference to the 15° angle of the incline, the cosine component of the centripetal force is equivalent to the sine component of the force due to gravity (both parallel to the incline). So:
\(F_c cos\phi = Mgsin\phi \\\\\frac{mv^2}{r}cos\phi = mgsin\phi\)

Cancel out 'm' and solve for 'v'.

\(\frac{v^2}{r}cos\phi = gsin\phi\\\\v^2 = gr \frac{sin\phi}{cos\phi}\\\\v = \sqrt{grtan\phi}\)

Plug in the given values and solve.

\(v = \sqrt{(9.8)(85)tan(15)} = \boxed{14.94 \frac{m}{s}}\)

b)
Begin by converting 20.0 km/h to m/s.

\(\frac{20 km}{hr} * \frac{1 hr}{3600 s} * \frac{1000m}{1 km} = 5.556 \frac{m}{s}\)

For this situation, we also have the force of friction present along the axis of the sine component of the force of gravity that contributes to the net force.

Recall the equation of kinetic friction:
\(F_f = \mu_k N\)

In this situation, we have the sine (vertical) component of the centripetal force as well as the cosine component of the force of gravity making up the normal force, so:
\(F_f = \mu_k (\frac{mv^2}{r}sin\phi + mgcos\phi)\)

If a curve is banked at a slower speed than appropriate, the car will tend to slide towards the center. Thus, this force of friction points up the incline, opposite to the force due to gravity. We can do another summation of forces like above.

\(\frac{mv^2}{r} cos\phi= mgsin\phi - \mu_k (\frac{mv^2}{r}sin\phi + mgcos\phi)\)

Cancel out 'm' and simplify the equation further to solve for μ.

\(\frac{v^2}{r} cos\phi= gsin\phi - \mu_k (\frac{v^2}{r}sin\phi + gcos\phi)\\\\\mu_k (\frac{v^2}{r}sin\phi + gcos\phi)= gsin\phi - \frac{v^2}{r} cos\phi\\\\\mu_k = \frac{gsin\phi - \frac{v^2}{r} cos\phi}{(\frac{v^2}{r}sin\phi + gcos\phi)}\)

Plug in values.

\(\mu_k = \frac{9.8sin(15) - \frac{5.556^2}{85} cos(15)}{\frac{5.556^2}{85}sin(15) + 9.8cos(15)} = \boxed{0.2286}\)

Answer:

Sound needs a material medium for their propagation like solid, liquid or gas to travel because the molecules of solid, liquid and gases carry sound waves from one point to another. Sound cannot progress through the vacuum because the vacuum has no molecules which can vibrate and carry the sound waves.

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The electric field is  9 * 10^6 N/m

The electric field of a sphere can be calculated using Coulomb's law, which states that the magnitude of the electric field at a point in space is proportional to the electric charge at that point and inversely proportional to the square of the distance between the point and the charge.

For a uniformly charged sphere, the electric field inside the sphere is zero, and the electric field outside the sphere is given by:

E = kQ / r^2

where:

E is the electric field strength, measured in units of volts per meter (V/m)

k is the Coulomb constant, with a value of approximately 9 x 10^9 N·m^2/C^2

Q is the total charge of the sphere, measured in units of Coulombs (C)

r is the distance from the center of the sphere to the point where the electric field is being measured, measured in units of meters (m).

Given that;

E = Kq/r^2

E = 9 * 10^9 * 1 * 10^-6/(10 * 10^-2)^2

E = 9 * 10^6 N/m

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As No diagram attached I am taking all are connected in series

We know

\(\boxed{\sf C_{eq}=C_1+C_2\dots}\)

\(\\ \sf \longmapsto C_{eq}=12+12+7+15+15+15\)

\(\\ \sf \longmapsto C_{eq}=24+7+45\)

\(\\ \sf \longmapsto C_{eq}=76\mu F\)

Answer:

13.3 pounds.

Explanation:

For a spring of constant K, with an attached object of mass M, the period can be written as:

T = 2*π*√(M/K)

Where π = 3.14

First, we know that the period is 4 seconds, then we have:

4s = (2*π)*√(M/K)

We know that if the mass is reduced by 10lb, the period becomes 2s.

Then the new mass of the object will be: (M - 10lb)

Then the period equation becomes:

2s = (2*π)*√((M-10lb)/K)

So we have two equations:

4s = (2*π)*√(M/K)

2s = (2*π)*√((M-10lb)/K)

We want to solve this for M.

First, we need to isolate K in one of the equations.

Let's isolate K in the first one:

4s = (2*π)*√(M/K)

(4s/2*π) = √(M/K)

(2s/π)^2 = M/K

K = M/(2s/π)^2 = M*(π/2s)^2

Now we can replace it in the other equation.

2s = (2*π)*√((M-10lb)/K)

First, let's simplify the equation:

2s/(2*π) = √((M-10lb)/K)

1s/π =  √((M-10lb)/K)

(1s/π)^2 =  ((M-10lb)/K

K*(1s/π)^2 = M - 10lb

Now we can use the equation: K =  M*(π/2s)^2

then we get:

K*(1s/π)^2 = M - 10lb

(M*(π/2s)^2)*(1s/π)^2 = M - 10lb

M/4 = M - 10lb

10lb = M - M/4

10lb = (3/4)*M

10lb*(4/3) = M

13.3 lb = M

Answer: An jack makes changing a tire easier because it lifts up the car to get the tire off of the ground.

Explanation:

Given data:

* The length of the shorter tube is,

* The frequency of the wave is,

Solution:

As the speed of sound wave is 340 m/s

Thus, the wavelengh of the wave is,

where v is the speed of sound wave, and f is the frequency of the wave,

Substituting the known values,

For the destructive interference,

The path difference between the waves for the first order minima is,

Answer:

The speed of the particle is proportional to:

c. t²

Explanation:

Given;

initial velocity of the particle, u = 0

let the net force on the object = F

Work done on the particle is given by;

W = F x d

W ∝ t

\(Fd \ \alpha \ t\\\\\frac{mv}{t}d \ \ \alpha \ t\\\\mvd \ \ \alpha \ t^2\\\\v \ \ \alpha \ t^2\)

Therefore, the speed of the particle is proportional to t²

The speed of the particle is proportional to t.

It should be noted that work is a change in kinetic energy. Therefore, power will be calculated as:

Power = Work / Time = force × velocity

Power is proportional to t. Since force is a constant, then the velocity will be proportional to t. Therefore, the speed of the particle is proportional to t.

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Answer:

The is: Although it is possible to have more than one state, it is also possible to have only one state.

Explanation:

Hope this helps! ;-)

Answer:

Although it is possible to have more than one state, it is also possible to have only one state.

Explanation:

Answer:

a. 273 K b. 90.1 K c. 5.26 atm d. 0.33 atm

Explanation:

For isothermal expansion PV = constant

So, P₁V₁ = P₂V₂ where P₁ = initial pressure of gas = 1 atm (standard pressure), V₁ = initial volume of gas, P₂ = final pressure of gas and V₂ = final volume of gas,

So, P₁V₁ = P₂V₂

P₂ = P₁V₁/V₂

Since V₂/V₁ = 0.19,

P₂ = P₁V₁/V₂

P₂ = 1 atm (1/0.19)  

P₂ = 5.26 atm

For an adiabatic expansion, PVⁿ = constant where n = ratio of molar heat capacities = 5/3 for monoatomic gas

So, P₂V₂ⁿ = P₃V₃ⁿ where P₂ = initial pressure of gas = 5.26 atm, V₂ = initial volume of gas, P₃ = final pressure of gas and V₃ = final volume of gas,

So, P₂V₂ⁿ = P₃V₃ⁿ

P₃ = P₂V₂ⁿ/V₃ⁿ

P₃ = P₂(V₂/V₃)ⁿ

Since V₃ = V₁ ,V₂/V₃ = V₂/V₁ = 0.19

1/0.19,

P₃ = P₂(V₂/V₃)ⁿ

P₃ = 5.26 atm (0.19)⁽⁵/³⁾

P₃ = 5.26 atm × 0.0628

P₃ = 0.33 atm

Using the ideal gas equation

P₃V₃/T₃ = P₄V₄/T₄ where P₃ = pressure after adiabatic expansion = 0.33 atm , V₃ = volume after adiabatic expansion, T₃ = temperature after adiabatic expansion  P₄ = initial pressure of gas = P₁ = 1 atm , V₄ = initial volume of gas = V₁ and T₄ = initial temperature of gas = T₁ = 273 K (standard temperature)

P₃V₃/T₃ = P₄V₄/T₄

T₃ = P₃V₃T₄/P₄V₄    

T₃ = (P₃/P₄)(V₃/V₄)T₂

Since V₃ = V₄ = V₁ and P₄ = P₁

V₃/V₄ = 1 and P₃/P₄ = P₃/P₁

T₃ = (P₃/P₁)(V₃/V₄)T₂

T₃ = (0.33 atm/1 atm)(1)273 K  

T₃ = 90.1 K

So,

a. The highest temperature attained by the gas is T₁ = 273 K

b. The lowest temperature attained by the gas = T₃ = 90.1 K

c. The highest pressure attained by the gas is P₂ = 5.26 atm

d. The lowest pressure attained by the gas is P₃ = 0.33 atm

The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.

Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.

Cost of operation for 10 hours a day;

Daily consumption = 3kW x 10 hours

Daily Consumption = 30kW

Since 1kWH = 79 francs;

Daily consumption amount = 30 x 79 francs

Daily consumption amount = 2,370 francs

Therefore, the monthly consumption (using 30days) will be;

2,370 francs x 30 = 71,100 francs

In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.

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Answer:

1.3 and 2.5

Explanation:

I did mental math

Answer:

(a) The change in magnetic flux is equal to the product of the magnetic field strength, the area of the coil, and the cosine of the angle between the magnetic field and the surface of the loop. Therefore, the change in magnetic flux is equal to 0.200T x (π x (25.0cm)^2) x cos(45°) = 7.85 x 10^-3 Tesla-square meters.

(b) The induced emf is equal to the change in magnetic flux divided by the time taken for the change to occur. Therefore, the induced emf is equal to 7.85 x 10^-3 Tesla-square meters / 0.250s = 3.14 Volts.

Answer:

7.05479

Explanation:

Answer:

200 grams:     ounces:7.05479239 that's the answer

Explanation:

An electromagnet consists of a conductive wire wrapped around a magnetic core, creating a magnetic field when an electrical current is passed through it.

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Answer:

As the number of bulbs in series increases, both the ammeter reading and bulb brightness should decrease. Using standard ammeters may not give perfect results and if the bulbs are allowed to heat up too much in between adding more bulbs, their resistance will be higher.

Explanation:

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When a substance is heated, it releases energy, which causes the particles to become more active, vibrating, rotating, and even moving faster. If a substance has enough energy, it can overcome the bonding forces that hold the particles together and change state as a result.

Answer:

a scale is used to measure the mass of the body

Answer:

Yes, it would make it back up.

Explanation:

If it has 100,000 Joules of gravitational potential energy at the top of the hill, by the time the cart gets to the bottom, it will become PE = 0, KE = 90,000 since 10% of 100,000 is 10,000. The cart only requires 80,000J to climb back up so it should easily do so.

I didn't quite understand if the 10% energy loss is total, or every time it goes up or down, but it isn't a problem because 10% of 90,000 is 9,000, which means it would have 81,000J of energy on the way back up IF it loses energy due to friction on the way back up also.

The only physical law you need to prove this is the Law of Conservation of Energy: no energy is lost, only transformed; 10% of the energy becomes heat, the rest remains mechanical energy, which is the reason why the reasoning above works.

The time elapsed between the first splash and the second splash is approximately 0.69 seconds.

To calculate this, we consider the motion of two rocks thrown simultaneously from a bridge. Heather throws a rock straight down with a speed of 14 m/s, while Jerry throws a rock straight up with the same speed.

We use the equation for displacement in uniformly accelerated motion: s = ut + (1/2)at^2.

For Heather's rock, which is thrown downwards, the initial velocity (u) is positive and the acceleration (a) due to gravity is negative (-9.8 m/s^2). The displacement (s) is the height of the bridge (46 m).

Solving the equation, we find two possible values for the time (t): t ≈ -4.91 s and t ≈ 1.91 s.

Since time cannot be negative in this context, we discard the negative value and consider t ≈ 1.91 s as the time it takes for Heather's rock to hit the water.

For Jerry's rock, thrown upwards, we use the same equation with the same initial velocity and acceleration. The displacement is also the height of the bridge, but negative.

Solving the equation, we find t ≈ -5.68 s and t ≈ 1.22 s. Again, we discard the negative value and consider t ≈ 1.22 s as the time it takes for Jerry's rock to reach its maximum height before falling back down.

To find the time difference between the first and second splash, we subtract t ≈ 1.91 s (Heather's rock) from t ≈ 1.22 s (Jerry's rock). This gives us a time difference of approximately 0.69 seconds.

Therefore, the time elapsed between the first splash and the second splash is approximately 0.69 seconds.

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A

sry if it's wrong luv <3

Answer:

The loss in rotational kinetic energy due to the collision is 36.585 J.

Explanation:

Given;

mass of the disk, m₁ = 1.64 kg

radius of the disk, r = 0. 61 m

angular velocity of the disk, ω₁ = 17.6 rad/s

mass of the rod, m₂ = 1.51 kg

length of the rod, L = 1.79 m

angular velocity of the rod, ω₂ =  5.12 rad/s (clock-wise)

let the counter-clockwise be the positive direction

let the clock-wise be the negative direction

The common final velocity of the two systems after the collision is calculated by applying principle of conservation of angular momentum ;

m₁ω₁  + m₂ω₂ = ωf(m₁ + m₂)

where;

ωf is the common final angular velocity

1.64 x 17.6    + 1.51(-5.12) = ωf(1.64 + 1.51)

21.1328 = ωf(3.15)

ωf = 21.1328 / 3.15

ωf = 6.709 rad/s

The moment of inertia of the disk is calculated as follows;

\(I_{disk} = \frac{1}{2} mr^2\\\\I_{disk} = \frac{1}{2} (1.64)(0.61)^2\\\\I_{disk} = 0.305 \ kgm^2\)

The moment of inertia of the rod about its center is calculated as follows;

\(I_{rod} = \frac{1}{12} mL^2\\\\I_{rod} = \frac{1}{12} \times 1.51 \times 1.79^2\\\\I _{rod }= 0.4032\ kgm^2\)

The initial rotational kinetic energy of the disk and rod;

\(K.E_i = \frac{1}{2} I_{disk}\omega _1 ^2 \ \ + \ \ \frac{1}{2} I_{rod}\omega _2 ^2 \\\\K.E_i= \frac{1}{2} (0.305)(17.6) ^2 \ \ + \ \ \frac{1}{2} (0.4032)(-5.12) ^2\\\\K.E_i = 52.523 \ J\)

The final rotational kinetic energy of the disk-rod system is calculated as follows;

\(K.E_f = \frac{1}{2} I_{disk}\omega _f ^2 \ \ + \ \ \frac{1}{2} I_{rod}\omega _f ^2\\\\K.E_f = \frac{1}{2} \omega _f ^2(I_{disk} + I_{rod})\\\\K.E_f = \frac{1}{2} (6.709) ^2(0.305+ 0.4032)\\\\K.E_f = 15.938 \ J\)

The loss in rotational kinetic energy due to the collision is calculated as follows;

\(\Delta K.E = K.E_f \ - \ K.E_i\\\\\Delta K.E = 15.938 J \ - \ 52.523 J\\\\\Delta K.E = - 36.585 \ J\)

Therefore, the loss in rotational kinetic energy due to the collision is 36.585 J.

Answer:Weather satellites provide vital information about cloud patterns and ground and sea temperatures. They collect and share information with remote data collecting stations such as weather buoys, and observatories from around the world.

Explanation:

Answer:

Step 1: List the mass and velocity of the object. Step 2: Convert any values into SI units (kg, m, s). Step 3: Multiply the mass and velocity of the object together to get the momentum of the object.

Answer:

I guess the Ans for second one is gravitational force

Answer:

oxygen silicon aluminun iron

Answer:

C - the greatest net force is on c with 25N - 10N = 15N

a = F / M

a = (v2 - v1) / t     so C has the greatest acceleration and will reach the greatest velocity

KE = 1/2 M v^2

The diagrams show four bodies moving in the directions shown. The only forces acting on the bodies are shown in each diagram. The option C body gains the most kinetic energy when moving a distance of 1.0m.

When some amount of force is applied on a object it can store a energy in that object. That is the kinetic energy. Mathematically the mass of the object and its change in acceleration in that object makes the kinetic energy. It is a vector quantity.

To calculate the kinetic energy we are using the formula,

U= (1/2)mv²

U = (1/2) ma²t²

Or, U= (1/2)ma × at²

Or, U= F × (1/2)at²

From this calculation we can see that if there is more force applied on a body that generates more kinetic energy on that object.

According to the question ,

Force of the object of Option A has (F) = f₂ - f₁

                                                                = (20 - 10)

                                                                = 10N

Force of the object of Option B has (F) = 10N

Force of the object of Option C has (F) = f₂ - f₁

                                                                 =(25-10)= 15N

Force of the object of Option D has (F) = f₂ - f₁

                                                                 = (30-30)

                                                                 = 0N

According to the question, option C has the most amount of force and we know the more force generate the more kinetic energy. So it has the more kinetic energy.

We can easily say that,  The option C body gains the most kinetic energy when moving a distance of 1.0m

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A source travelling in the direction of the observer causes Doppler blueshift.

When an object is moving towards us, the light from the object is known as blueshift.

The phrase refers to any relative motion, that causes a decrease in the wavelength and rise in frequency, including those that take place outside of the visible spectrum.

During the motion of the object towards us, blueshift will happen, thus shifting light to shorter wavelengths on the blue side of the spectrum.

This causes the color to shift from the red to the blue end of the spectrum in visible light.

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The total uncertainty in the mass measurement is ± 0.3 g.

Uncertainty as used here means the range of possible values within which the true value of the measurement lies.

So uncertainty in measurement describes the range of possible errors that may result from a given measurement carried out.

The uncertainty in the measurement of  1 g , 2 g , 5 g and 10 g pieces is given as ± 0.1 g

The uncertainty in the measurement of  20 g , 50 g and 100 g pieces is given as ± 0.2 g

The total uncertainty in the mass measurement is calculated as;

the total uncertainty in the mass = ± 0.1 g + ± 0.2 g = ± 0.3 g

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