Since the Boston marathon began in 1897, the finish time has been incrementally decreasing. The mean finish time to date is 231 minutes with a standard deviation of 40 minutes. Based on this information, what would allow us to use a Z-score in order to construct a confidence interval to estimate the mean finishing time of the most recent Boston Marathon with a sample size of 40 participants. Choose all that apply.
Answer:
hello your question lacks the required options but i will provide a general answer to your question
answer : The mean value and the standard deviation would allow us use a Z-score
Step-by-step explanation:
mean value = 231 minutes
standard deviation ( std ) = 40 minutes
sample size = 40
The parameters that would be applicable while use Z-score are : The given mean value and the standard deviation
This is because the value of a z-score gives us an information on how far we are from the mean score i.e. number of standard deviations
+Zscore means that the score is above the average value
-Zscore means that the score is below the average value
Find the doubling time of an investment earning 8% interest if interest is compounded continuously. The doubling time of an investment earning 8% interest if interest is compounded continuously is ____ years.
Answer:
Step-by-step explanation:
Using FV = PV(1 + r)^n where FV = future value, PV = present value, r = interest rate per period, and n = # of periods
1/PV (FV) = (PV(1 + r^n)1/PV divide by PV
ln(FV/PV) = ln(1 + r^n) convert to natural log function
ln(FV/PV) = n[ln(1 + r)] by simplifying
n = ln(FV/PV) / ln(1 + r) solve for n
n = ln(2/1) / ln(1 + .08) solve for n, letting FV + 2, PV = 1 and rate = 8% or .08 compound annually
n = 9
n = ln(2/1) / ln(1 + .08/12) solve for n, letting FV + 2, PV = 1 and rate = .08/12 compound monthly
n = 104 months or 8.69 years
n = ln(2/1) / ln(1 + .08/365) solve for n, letting FV + 2, PV = 1 & rate = .08/365 compound daily
n = 3163 days or 8.67 years
Alternatively
A = P e ^(rt)
Given that r = 8%
= 8/100
= 0.08
2 = e^(0.08t)
ln(2)/0.08 = t
0.6931/0.08 = t
t= 8.664yrs
t = 8.67yrs
Which ever approach you choose to use,you will still arrive at the same answer.
Andre ran 345 meters with the track club. If there are 1000 meters in one kilometer, how many kilometers did he run?
A. 0.0345 km
B. 3.45km
C. 34.5 km
D. 0.324km
All bots and links will be reported. Please do not message if this account did anything before as for this account has been given to me today.
Answer:
None of them are correct as the correct one is 0.345 (maybe you made a typo when typing the options)
Step-by-step explanation:
We can make:
\(\frac{345}{1000}\) which equals 0.345 km
Ali, Basti and Cian stand at three points A, B and C respectively. Suppose that the measure of angle ABC is 50 degrees , the measure of angle BAC is 60 degrees and Ali is exactly 150 ft away from Basti. Find the distance between Basti and Cian.
To find the distance between Basti and Cian, we can use the law of sines in triangle ABC. The law of sines states that the ratio of the length of a side to the sine of the opposite angle is constant for all sides and their corresponding angles in a triangle.
Let's label the distance between Basti and Cian as "x". We know that the measure of angle ABC is 50 degrees and the measure of angle BAC is 60 degrees. We also know that Ali is exactly 150 ft away from Basti.
Using the law of sines, we can set up the following equation:
sin(50°) / 150 = sin(60°) / x
To solve for "x", we can rearrange the equation:
x = (150 * sin(60°)) / sin(50°)
Using a calculator, we can evaluate the expression:
x ≈ (150 * 0.866) / 0.766
x ≈ 168.4 ft
Therefore, the distance between Basti and Cian is approximately 168.4 ft.
Please help me understand this handwriting can some pls re write and label I DONT UNDERSTAND CURSIVE :(
Answer:
7:01
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Conditions " humanitarian groups Salahiel 1-1-1, 1-1-2, 1-2-3 1-R-5, 2-L-2, 2-L-3, 2-14, 2-1-5, 2-RI
Flores 1-30
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Gumbon 1-1-3 CDP 1-1-3
Status oppose ending 742 Montoya 1-1, 1-2, 1-3
federal courts challenge
Gamboa 1-R-2 Custom 1-7
CDP 1-L-36, 1-2-4
de Vogue 1-2-1, 2-1-5, 2-L-6
7 expulsions at boders
root causes textul Amer.
Cop 1-L-34, 1-1-2, 1-R-4
Border Report 1-2
CDP 1-R-2, 1-R-3 Montoya 1-8
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Hopes this helps :)
Help me with my homework fast pls
Answer:
2211.68
Step-by-step explanation:
V=πr^2h
V=π64*22
V=2211.68
The pounds of bananas sold each week at all Metro Seattle Alberstons stores as a function of price, p, in dollars/pound(lb.) is given by.
q(p) = 100e^(1.5(5-p))
1. What is the price elasticity of demand for bananas at $.20/lb. ?
(nearest 0.01)
2. What is the price elasticity of demand for bananas at $1/lb. ?
3. At what price is the maximum revenue per week achieved?
+/- $0.01
4. What is that maximum revenue per week?
5. How many pounds will be sold each week at that optimal price
140.55 pounds will be sold approximately each week at the optimal price of $0.67/lb.
How will you solve all the parts of this question?To find the price elasticity of demand for bananas at $0.20/lb, we need to use the formula:
According to the given data:
E(p) = -p(q'/q(p))
where q' is the derivative of q(p) with respect to p.
First, we need to find q'(p):
\(q'(p) = -225e^(1.5(5-p))\)
Then, we can plug in the values:
E(0.20) = -0.20(q'(0.20)/q(0.20))
= \(-0.20(-225e^(1.5(5-0.20)) / 100e^(1.5(5-0.20)))\)
= 2.70
Therefore, the price elasticity of demand for bananas at $0.20/lb is 2.70.
To find the price elasticity of demand for bananas at $1/lb, we can use the same formula:
E(p) = -p(q'/q(p))
First, we need to find q'(p):
\(q'(p) = -225e^(1.5(5-p))\)
Then, we can plug in the values:
E(1) = -1(q'(1)/q(1))
= \(-1(-225e^(1.5(5-1)) / 100e^(1.5(5-1)))\)
= 0.68
Therefore, the price elasticity of demand for bananas at $1/lb is 0.68.
To find the price that maximizes revenue, we need to find the value of p that makes revenue, R(p), maximum.
Revenue is given by:
R(p) = pq(p)
= \(p100e^(1.5(5-p))\)
To maximize revenue, we need to find the critical point of R(p) by taking its derivative and setting it equal to zero:
\(R'(p) = 100e^(1.5(5-p)) - 150pe^(1.5(5-p)) = 0\)
Simplifying this expression, we get:
\(2e^(1.5(5-p)) - 3pe^(1.5(5-p)) = 0\)
2 = 3p
p = 2/3
Therefore, the price that maximizes revenue is $0.67/lb.
To find the maximum revenue per week, we can plug this price back into the revenue equation:
\(R(2/3) = (2/3)*100e^(1.5(5-2/3))\)
= $167.56
Therefore, the maximum revenue per week is $167.56.
To find how many pounds will be sold each week at the optimal price of $0.67/lb, we can plug this price back into the demand equation:
\(q(2/3) = 100e^(1.5(5-2/3))\)
= 140.55
Therefore, approximately 140.55 pounds will be sold each week at the optimal price of $0.67/lb.
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f(x) = 1/3x + 1 if x=-18
Answer:
7
Step-by-step explanation:
1/3*(-18) + 1 = 7
Just plug in the x which is -18, and solve with a calculator.
Hope this helps!
What happens if you can write a function as a composite in different ways? Do you get the same derivative each time? The Chain Rule says you should. Find
dy/dx if y=x by using the Chain Rule with y as a composite of the following functions. Complete parts (a) and (b) below.
Using the Chain Rule, we have: dy/dx = f'(g(x)) * g'(x) = 1 * 1 = 1.The derivative of y with respect to x is 1.
When we compose a function, it may be possible to write it in a variety of different ways. Differentiating such functions can result in different derivatives, but the Chain Rule indicates that the derivatives of the compositions should be the same regardless of how the function is written, if the function is continuous and differentiable.For instance, consider the function f(x) = sin(x²). It can be written as f(g(x)) where g(x) = x² and f(x) = sin(x). Furthermore, it can be written as f(h(x)) where h(x) = x² and f(x) = sin(x). These are both compositions of functions, but they are different compositions that lead to different derivatives.However, if the function is a composite of differentiable functions, the Chain Rule tells us that the derivative of a composite function is the derivative of the outer function multiplied by the derivative of the inner function.
To find dy/dx if y = x using the Chain Rule with y as a composite of the following functions, we must first rewrite y as a composite function: y = f(g(x)) where g(x) = x and f(x) = x. This composite function can be written in a variety of different ways, such as y = f(h(x)) where h(x) = x and f(x) = x, or y = f(k(x)) where k(x) = x and f(x) = x. However, regardless of how we write it, the Chain Rule tells us that the derivative of y is equal to the derivative of the outer function (f(x) = x) multiplied by the derivative of the inner function (g(x) = x).
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the length of a rectangle exceeds the width by 14 cm the perimeter of the rectangle is 160 cm find the Length and width of the rectangle
Answer:
width 14 perimeter 160 (l=66 cm)
Simplify the expression
Answer:
\( \frac{1}{x {}^{2} y {}^{4} }\)
Step-by-step explanation:
\( \frac{x {}^{ - 2} }{y {}^{4} } = x {}^{ - 2} \times \frac{1}{y {}^{4} } \)
\(x {}^{ - 2} = \frac{1}{x {}^{2} } \)
\(therefore \: \frac{x {}^{ - 2} }{y {}^{4} } = \frac{1}{x {}^{2} } \times \frac{1}{y {}^{4} } \\ = \frac{1}{x {}^{2}y {}^{4} }\)
Roselyn is driving to visit her family, who live 150 kilometers away. Her average speed is 60 kilometers per hour. The car's tank has 20 liters of fuel at the beginning of the drive, and its fuel efficiency is 6 kilometers per liter. Fuel costs 0.60 dollars per liter. How long can Roselyn drive before she runs out of fuel?
Roselyn can drive a distance until she runs out of fuel for a time of 2.5 hours or until she spends all the fuel, whichever comes first.Roselyn can travel 120 km before running out
Distance travelled with 20 l of petrol in solution and final answer.
Roselyn's average speed is 60 kilometers per hour, and she needs to travel 150 kilometers to reach her family's place. Therefore, she will require a total of 150/60 = 2.5 hours to complete the journey.
The car's fuel efficiency is 6 kilometers per liter, meaning it consumes 1/6 liters of fuel per kilometer. To determine the total fuel required, we multiply the fuel consumption rate by the total distance: 150 * (1/6) = 25 liters of fuel.
Since the car's tank has 20 liters of fuel at the beginning of the drive, Roselyn will need an additional 25 - 20 = 5 liters of fuel to complete the journey.
As fuel costs 0.60 dollars per liter, Roselyn will need to spend a total of 5 * 0.60 = 3 dollars to purchase the necessary fuel.
Therefore, Roselyn can drive until she runs out of fuel for a time of 2.5 hours or until she spends all the fuel, whichever comes first.
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if a₁=3 and aₙ=5aₙ-₁ then find the value of a₅
Answer:
The value of a₅ is 1875.
Step-by-step explanation:
Given:
a₁ = 3
aₙ = 5aₙ₋₁
To find the value of a₅, we can apply the recursive formula to compute each term successively:
Step 1: Compute a₂
a₂ = 5a₁ = 5(3) = 15
Step 2: Compute a₃
a₃ = 5a₂ = 5(15) = 75
Step 3: Compute a₄
a₄ = 5a₃ = 5(75) = 375
Step 4: Compute a₅
a₅ = 5a₄ = 5(375) = 1875
fifteen minutes past eight in the evening on a 24 hour clock
Answer: The time is 20:15 on a military time clock.
Step-by-step explanation:
let $l$ be the line with equation $\dbinom{10}{3} \dbinom{-2}{1}t$. let $\mathbf{v}$ be a vector from the origin to a point on $l$. find the minimum value of $\|\mathbf{v}\|$.
The minimum value of \($\|\mathbf{v}\|$\) is zero.
The minimum value of \($\|\mathbf{v}\|$\) is zero, as it is the distance between the origin and a point on the line. To solve this problem, the formula \($\|\mathbf{v}\| = \sqrt{x^2 + y^2}$\) can be used, where x and y are the coordinates of the point on the line. Since the equation of the line is \($\dbinom{10}{3} \dbinom{-2}{1}t$\), the coordinates of the point on the line can be found by substituting \($t = 0$: $x = 10 \cdot 0 - 2 \cdot 0 = 0$, and $y = 3 \cdot 0 + 1 \cdot 0 = 0$\) . Substituting these values into the formula for \($\|\mathbf{v}\|$ gives $\|\mathbf{v}\| = \sqrt{0^2 + 0^2} = 0$\). Therefore, the minimum value of \($\|\mathbf{v}\|$\) is zero.
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Pls help 10 ptsssssssssssss
NO LINKS
Answer:
the answer is 16
Step-by-step explanation:
8/2=4
4*4=16
Malcolm has $50 gift card to a local car wash and order is the ultimate car wash each visit is $8.95
The amount cheaper is the car washes Malcolm orders than the car washes Martha's order is $13.
The correct answer choice is option B.
How much cheaper is the car washes Malcolm orders than the car washes Martha's order?Malcolm's gift card = $50.
Cost Malcolm's car wash per visit = $7
Martha's gift card = $180
Cost Martha's car wash per visit = Difference between gift card balance of first and second visit
= $180 - $160
= $20
How cheap is the car washes Malcolm orders than the car washes Martha's order = $20 - $7
= $13
Therefore, Malcolm's car wash is cheaper than Martha's car wash by $13
The complete question is attached in the diagram.
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Is. She analyzes
st.
Martha graphs the data for the number of bracelets made, a, and the number of beads used,
y, and draws a line through the points.
Number of Beads Used
600
500
400
300
200
100
0
Bracelets Made
versus Beads Used
(31, 651)
(23, 483).
(10, 210)
5 10 15 20 25 30 35
Number of Bracelets Made
Write an equation that represents the relationship between the number of bracelets made
and the number of beads used. Show or explain how you found the slope and y-intercept.
Enter your equation and your work or explanation in the space provided.
You may use the drawing box to add a drawing to help explain your answer.
A
7
44
▶
Exhibits
P
The equation for the relationship between the number of bracelets made and the number of beads is y = 21x.
First, the rate of change
= (483 - 210) / (23 - 10)
= 273 / 13
= 21
So, the equation for the relationship between the number of bracelets made and the number of beads used.
(y - 210) = 21 (x- 10)
y - 210 = 21x - 210
y = 21x
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Find the missing coefficient
Answer:
To fill in the blank, let's first expand the left-hand side of the equation:
(2d-5)(2d-4)
= 2d * 2d + 2d * (-4) -5 * 2d -5 * (-4) (using the distributive property)
= 4d^2 - 8d - 10d + 20
= 4d^2 - 18d + 20
Now, we can compare this with the right-hand side of the equation, which is 4d^2 + blank d + 20.
Comparing the coefficients of the like terms, we can see that the blank should be filled with -18, since the coefficient of d on the left-hand side is -18 (from -8d - 10d) and the coefficient of d on the right-hand side is blank.
So, the filled-in equation becomes:
(2d-5)(2d-4) = 4d^2 - 18d + 20
Brainlyest!?
Answer:
Step-by-step explanation:
(2d - 5) x (2d - 4)
= 4d^2 - 8d - 10d + 20
= 4d^2 - 18d + 20
Therefore Answer is -18.
HEREEEEEEEEEEEEEElollll
Answer:
Hey there!
Your answer would be 4/50. The total times she drawed a purple tile was 4, and she drawed 50 times.
Hope this helps :)
Suppose that the functions s and t are defined for all real numbers x as follows.s (x) = 4x + 4t(x) = 3xWrite the expressions for (s + t)(x) and (s – t)(x) and evaluate (s.t)(3).(s + 1)(x) = 1(s - 1)(x) = 1(sot) (3) = 1Х?
Answer:
(s+t)(x) = 7x+4
(s-t)(x) = x + 4
s(t(3)) = 40
Step-by-step explanation:
We are given the following function:
s(x) = 4x + 4
t(x) = 3x
(s + t)(x)
Addition of functions: We add the common terms:
So
(s+t)(x) = 4x + 4 + 3x = 4x + 3x + 4 = 7x + 4
(s-t)(x)
Same logic as above, just now we subtract
(s-t)(x) = 4x + 4 - 3x = 4x - 3x + 4 = x + 4
Composite:
s(t(x)) = s(3x) = 4(3x) + 4 = 12x + 4
When x = 3
s(t(3)) = 12*3 + 4 = 40
In how many ways can a sample of 6 keyboards be selected so that exactly two have an electrical defect
Answer:
15ways
Step-by-step explanation:
This is a combination question since combination has to do with selection. Hence the number of ways sample of 6 keyboards can be selected so that exactly two have an electrical defect is expressed as;
6C2 = 6!/(6-2)!2!
6C2 = 6!/4!2!
6C2 = 6×5×4!/4!×2
6C2 = 6×5/2
6C2 = 30/2
6C2 = 15
Hence this can be done in 15ways
Evaluate u+xy for u=17 x=4 and y=8
In 2021 a 30-second commercial during the Super Bowl cost $5.6 million and the CPI was approximately 271.4. Assuming that price changes are simply due to inflation, what would the same 30 second commercial have cost during the first Super Bowl in 1967, when the CPI was 33.4? Round your answer to the nearest hundred dollars.
In 2021 a 30-second commercial during the Super Bowl cost $5.6 million and the CPI was approximately 271.4. Assuming that price changes are simply due to inflation, when the CPI was 33.4 the estimated cost of a 30-second commercial during the first Super Bowl in 1967 would be approximately $68,900.
To calculate the cost of the 30-second commercial during the first Super Bowl in 1967, we can use the concept of inflation and the Consumer Price Index (CPI).
The CPI measures the average price change of a basket of goods and services over time. By comparing the CPI values of two different years, we can estimate the relative increase in prices due to inflation.
Given data:
Cost of a 30-second commercial in 2021 = $5.6 million
CPI in 2021 = 271.4
CPI in 1967 = 33.4
To calculate the cost in 1967, we need to adjust the 2021 cost for inflation using the CPI ratio:
Cost in 1967 = (Cost in 2021) * (CPI in 1967 / CPI in 2021)
Cost in 1967 = ($5.6 million) * (33.4 / 271.4)
Cost in 1967 ≈ $0.689 million
To round the cost to the nearest hundred dollars, we can multiply the cost by 100 and round it to the nearest whole number:
Cost in 1967 ≈ $68,900
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Suppose CDF for a discrete random variable X is given as following: FCO) = 0, F(1)=.15, F(2) = .45, F(3)=.55, F(4)=.85, F(5) = 1. What is the probability that x=3?
The probability that a discrete random variable X takes on a particular value x is equal to the probability mass function (PMF) of X evaluated at x. The PMF of a discrete random variable X is defined as the derivative of its cumulative distribution function (CDF) with respect to x.
Given the CDF for X as F(x), the PMF for X is denoted as f(x) and can be computed as follows:
f(x) = F'(x) = dF(x)/dx
In this case, the CDF for X is given as:
F(0) = 0
F(1) = .15
F(2) = .45
F(3) = .55
F(4) = .85
F(5) = 1
To find the probability that x = 3, we need to compute the PMF of X at x = 3. Using the formula above, we have:
f(3) = F'(3) = dF(3)/dx
Since the CDF for X is a discrete function, we can compute the derivative by taking the difference between the values of the CDF at x = 3 and x = 2:
f(3) = F(3) - F(2) = .55 - .45 = .1
Therefore, the probability that x = 3 is .1.
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answer this please!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
200
Step-by-step explanation:
\(a^{2}\) + \(b^{2}\) = \(c^{2}\)
\(120^{2}\) + \(160^{2}\) = \(c^{2}\)
14400 + 25600 = \(c^{2}\)
40000 = \(c^{2}\)
\(\sqrt{40000}\) = \(\sqrt{c^{2} }\)
200 = c
Jesus love you.
Use the grouping method to factor the polynomial below completely.
3x3 + 6x2 + 5x + 10
A. (3x2 +5)(x+2)
B. (3x2 + 5)(x + 5)
C. (3x2 + 2)(x + 5)
D. (3x2 + 2)(x + 2)
Answer:
its A
Step-by-step explanation:
i did the test
1. 2a+b-c
A. O
B. 1
C. 3
D. 4
Answer:
i think C correct me if im wrong pls
Step-by-step explanation:
Please help me with this
Step-by-step explanation:
Flip f(x) about the x-axis by multiplying it by -1
- f(x)
the squish it skinnier by multiplying it by 4
g(x) = - 4 f(x) = -4 x^2
Identify the graph of the inequality 2(2x-1)+7< 13 or -2x+5-10.
From the resulting solution, the correct linear inequality graph is Graph C.
Solving inequality expressionGiven the inequality equation below:
2(2x-1)+7< 13 or -2x+5 ≤ -10.
Simplify the expression
2(2x-1)+7< 13
Expand
4x - 2 + 7 < 13
4x + 5 < 13
4x < 13 - 5
4x < 8
x < 2
For the inequality -2x+5 ≤ -10.
-2x+5 ≤ -10
-2x ≤ -15
x ≥ 7.5
Hence the solution to the given system of inequalities are x < 2 and x ≥ 7.5
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