Answers
Horizontal speed = 24.0 m/s
height of the cliff = 51.0 m
For the initial vertical speed will are considering the vertical component. Therefore,
Since the student fires the canonical ball at the maximum height of 51 m, the initial vertical velocity will be zero. This means
\(\text{ Initial vertical velocity = 0 m/s}\)let's find how long the ball remained in the air.
\(\begin{gathered} 0=51-\frac{1}{2}(9.8)t^2 \\ 4.9t^2=51 \\ t^2=\frac{51}{4.9} \\ t^2=10.4081632653 \\ t=\sqrt[]{10.4081632653} \\ t=3.22 \\ t=3.22\text{ s} \end{gathered}\)Finally, let's find the how far from the base of the building the ball landed(horizontal distance)
\(\begin{gathered} S_x=u_xt+\frac{1}{2}a_xt^2 \\ S_x=24\times3.23 \\ S_x=\text{horizontal distance=77.28 m} \\ \text{note} \\ a_x=0m/s^2 \end{gathered}\)Related Questions
As the shuttle bus comes to a sudden stop to avoid hitting a dog. It accelerates unfirmly at -4.1m/s^2 as it slow down from 9.0m/s to 0.0m/s. Find the interval of acceleration for the bus
Answers
The interval of acceleration of the bus will be 2.19 seconds.
What is acceleration?An object is considered to have been accelerated if its velocity changes. Depending on whether an object is moving faster, slower, or in a different direction, its velocity may change.
Examples of acceleration include a falling apple, the moon orbiting the earth, and a car that has stopped at a stop sign. These examples demonstrate how acceleration occurs whenever a moving object modifies its direction, speed, or both.
Acceleration is a vector quantity.
SI unit of acceleration is m/s.
According to the question, the given values are :
Acceleration, a=-4.1 m/s²
Initial velocity, u=9.0 m/s and,
Final velocity, v=0 m/s
By using Equation of motion, i.e.,
v=u+at
⇒0 m/s=9m/s+(-4.1 m/s²)(t)
⇒-9 m/s=-4.1 m/s²×t
t=(-9 m/s)/(-4.1 m/s²)
t= 2.19 seconds.
Hence, the time interval of acceleration of the bus will be 2.19 seconds.
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A power cable has a resistance of 0.22 and carries
a current of 20A what is power lost as heat?
Answers
Answer:
88 Watts
Explanation:
From the question given above, the following data were obtained:
Resistance (R) = 0.22 Ohm
Current (I) = 20 A
Power (P) =.?
P = IV....... (1)
From ohm's law,
V = IR ........ (2)
Substitute the value of V in equation (2) into equation (1)
P = IV
V = IR
P = I(IR)
P = I²R
With the above formula (i.e P = I²R), we can obtain the power lost to heat as follow:
Resistance (R) = 0.22 Ohm
Current (I) = 20 A
Power (P) =.?
P = I²R
P = 20² × 0.22
P = 400 × 0.22
P = 88 Watts
Thus, the power lost to heat is 88 Watts.
Joaquin mows the lawn at his grandmother’s home during the summer months. Joaquin measured the distance across his grandmother’s lawn as 11.5 meters. If Joaquin mows one length across the lawn from east to west in 7.10 seconds, then what is the velocity of the lawnmower?
Answers
Answer:
Velocity is define as how fast an object is moving, and in what direction, it is a vector quantity, meaning velocity has both magnitude and direction. Anything goes to the left is negative, and anything goes to the right is positive.
a. Direction from east to west, given distance 11.5 meters, and time of 7.10 s
V = displacement/time V = -11.5/7.10 S V = -1.62 m/s (going left)
b. Joaquin reaches his original position. Displacement is now zero.
Velocity of the lawnmower is equal to "zero" but if we calculate for the average speed of the lawn, you just have to add the distance covered and the time it take to go back at the original position or point of origin
Calculate the equivalent resistance for each of the following circuits.
Answers
Answer:
5. 60 Ω
6. 60 Ω
7. 10 Ω
8. 0.625 KΩ
Explanation:
5. Determination of the equivalent resistance.
Resistor 1 (R₁) = 10 Ω
Resistor 2 (R₂) = 20 Ω
Resistor 3 (R₃) = 30 Ω
Equivalent Resistance (R) =?
Since the resistors are arranged in series connection, the equivalent resistance can be obtained as follow:
R = R₁ + R₂ + R₃
R = 10 + 20 + 30
R = 60 Ω
Thus, the equivalent resistance is 60 Ω
6. Determination of the equivalent resistance.
Resistor 1 (R₁) = 10 Ω
Resistor 2 (R₂) = 35 Ω
Resistor 3 (R₃) = 15 Ω
Equivalent Resistance (R) =?
Since the resistors are arranged in series connection, the equivalent resistance can be obtained as follow:
R = R₁ + R₂ + R₃
R = 10 + 35 + 15
R = 60 Ω
Thus, the equivalent resistance is 60 Ω
7. Determination of the equivalent resistance.
Resistor 1 (R₁) = 6 Ω
Resistor 2 (R₂) = 4 Ω
Equivalent Resistance (R) =?
Since the resistors are arranged in series connection, the equivalent resistance can be obtained as follow:
R = R₁ + R₂
R = 6 + 4
R = 10 Ω
Thus, the equivalent resistance is 10 Ω
8. Determination of the equivalent resistance.
Resistor 1 (R₁) = 10 KΩ
Resistor 2 (R₂) = 2 KΩ
Resistor 3 (R₃) = 1 KΩ
Equivalent Resistance (R) =?
Since the resistors are arranged in parallel connection, the equivalent resistance can be obtained as follow:
1/R = 1/R₁ + 1/R₂ + 1/R₃
1/R = 1/10 + 1/2 + 1/1
Find the least common multiple (lcm) of 10, 2 and 1. The result is 10. Divide 10 by each of the denominator and multiply the result obtained by the numerator. This is illustrated below:
1/R = (1 + 5 + 10) / 10
1/R = 16/10
Invert
R = 10/16
R = 0.625 KΩ
Thus, the equivalent resistance is 0.625 KΩ.
3. A missile is launched at a speed of 39.2 m/s at an angle of 30° to the ground. What is its
range? How long does it take to reach its maximum height? How high did it go vertically?
Answers
Time which missile will take to reach its maximum height is 2 seconds. and The maximum height it will reach is 58.8.
What is the relation between time and acceleration?
The time, velocity and acceleration are related in such a way that time is directly proportional to velocity and time is inversely proportional to acceleration.
i.e. t = u/g
As given in the question,
Initial velocity (u) = 39.2 m/s, and angle is 30°
initial vertical velocity = 39.2 sin30° = 19.6 m/s
So, the time taken can be calculated by:
t = u/g
t = 19.6/9.8
t = 2 seconds.
and the maximum height can be calculated by equation:
\(h = ut + \frac{1}{2} at^2\)
\(h = 39.2 + \frac{1}{2} 9.8 (2)^2\)
\(h = 39.2 + 19.6\)
h = 58.8 m
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A person stands on a scale in an elevator. The maximum and minimum scale readings are 908.9 N and 494.7 N, respectively. The acceleration of gravity is 9.8 m/s 2 . Assume the magnitude of the acceleration is the same during starting and stopping, and determine the acceleration of the elevator. Answer in units of m/s 2 .
Answers
The acceleration of the elevator is 9.8 m/s^2, which is equal to the acceleration due to gravity.
The change in the person's weight can be used to calculate the elevator's acceleration.
The change in weight is: 908.9 N - 494.7 N = 414.2 N
Since weight is equal to mass times acceleration (W = m * a), we can rearrange the equation to solve for acceleration:
a = W / m
Where m is the mass of the person, which can be calculated using the acceleration due to gravity:
m = W / g = 414.2 N / 9.8 m/s^2 = 42.3 kg
Substituting the mass into the equation for acceleration:
a = 414.2 N / 42.3 kg = 9.8 m/s^2
So the acceleration of the elevator is 9.8 m/s^2, which is equal to the acceleration due to gravity.
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A machine has a velocity ratio of 5 and the efficiency is 80% what effort would be needed to lift a load of 200N
Answers
Explanation:
To determine the effort needed to lift a load of 200N, given a velocity ratio of 5 and an efficiency of 80%, we can use the formula:
Efficiency = (Output Work / Input Work) * 100
Efficiency can also be calculated as the ratio of the output force to the input force. In this case, the output force is the load being lifted (200N), and the input force is the effort required.
Given that the velocity ratio is 5, it means that for every 5 units of distance the effort moves, the load moves 1 unit of distance. This implies that the effort is exerted over a greater distance than the load.
Let's denote the effort force as "E" and the distance moved by the effort as "dE." Similarly, the load force is "L," and the distance moved by the load is "dL."
Using the velocity ratio, we have the following relationship:
dE / dL = 5
Now, we can calculate the input work (Wi) and the output work (Wo):
Input Work (Wi) = Effort (E) * Distance moved by the effort (dE)
Output Work (Wo) = Load (L) * Distance moved by the load (dL)
Given that the efficiency is 80%, we can rewrite the formula for efficiency as:
0.80 = (Wo / Wi) * 100
Now, let's solve for the effort (E) using the given values:
Load (L) = 200N
Efficiency = 0.80
Velocity Ratio = 5
First, calculate the output work (Wo):
Wo = Load (L) * Distance moved by the load (dL)
Since the velocity ratio is 5, the distance moved by the load (dL) will be 1/5 of the distance moved by the effort (dE):
dL = (1/5) * dE
Wo = L * (1/5) * dE
Wo = 200N * (1/5) * dE
Wo = 40N * dE
Next, calculate the input work (Wi):
Wi = Effort (E) * Distance moved by the effort (dE)
Wi = E * dE
Now, substitute the values into the efficiency formula:
0.80 = (Wo / Wi) * 100
0.80 = (40N * dE) / (E * dE) * 100
0.80 = 40 / E * 100
0.80 * E = 40
E = 40 / 0.80
E = 50N
Therefore, the effort needed to lift a load of 200N with a velocity ratio of 5 and an efficiency of 80% is 50N.
At what height from the surface of earth will the value of 'g' reduced to 64% from the value at the surface? Radius of earth = 6400 Km
Answers
Answer: 1600 km from the surface
Explanation:
\(E = \frac{GM}{R^{2} }\\g1 = \frac{GM}{R1^{2} } \\R1 = 6400 km\\g2 = 0.64g1\\\frac{g1}{g2} = \frac{\frac{GM}{R1^{2} } }{\frac{GM}{R2^{2} } } \\\frac{g1}{0.64g1} = \frac{R2^{2}}{R1^{2} }\\\frac{1}{0.64} = \frac{R2^{2}}{6400^{2} }\\\\\frac{1}{0.8} = \frac{R2}{6400}\\\\R2 = \frac{6400}{0.8}\\R2 = 8000 km\\\)
Therefore, 8000 km - 6400 km = 1600 km from the surface
What is the first job u do on the ISS if u were an astronaut
Answers
If I were an astronaut, the first job I would do on the International Space Station (ISS) would be to familiarize myself with the station and its systems.
What is expected at ISS?I would need to learn how to operate the various equipment and how to maintain the station in good working order. I would also need to learn the procedures for conducting experiments and for performing spacewalks.
Once I had a good understanding of the station and its systems, I would begin working on my assigned tasks. These tasks could include conducting experiments, performing maintenance, or teaching other astronauts new skills. I would also take the opportunity to conduct research on my own and to learn more about the space environment.
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What is the purpose of using an ammeter to demonstrate that a moving
magnet causes an electric current to flow in a wire coil?
A. It detects any current in the wire.
B. It protects the investigators from receiving an electric shock.
C. It increases the strength of the permanent magnet.
D. It takes the place of the battery needed for an electromagnet.
Answers
Answer: A
Explanation:
Answer:
The answer is A. It detects any current in the wire.
Explanation:
I took the quiz.
Given an average cell is ten times the mass of a bacterium. The mass of a bacterium is 10-15 kg. And a person's mass is 65 kg.
Answers
Given the mass of the cell is 1 * 10⁻¹⁴ kg, the number of cells in the 65 kg person is 6.5 * 10¹⁵ cells.
What is the number of cells in a person weighing 65 kg?The number of cells in a human is calculated as follows:
The mass of an average cell is ten times the mass of a bacterium.
The mass of a bacterium = 1 * 10⁻¹⁵ kg
mass of an average cell = 10 * 1 * 10⁻¹⁵ kg = 1 * 10⁻¹⁴ kg
Number of cells = mass of person/mass of cell
Number of cells = 65 kg/1 * 10⁻¹⁴ kg
Number of cells = 6.5 * 10¹⁵ cells.
In conclusion, the number of cells is obtained by dividing the mass of the person by the mass of a average cell.
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Note that the complete question is given below:
Assuming the mass of an average cell is ten times the mass of a bacterium (which is 10⁻¹⁵ kg): Calculate the number of cells in a human assuming the mass of the person is 10² kg.
A student trying to calculate the coefficient of friction between a box and a surface. She measures that the 80kg box will slide if the student pushes with a force greater than 400n.
Answers
Answer:
\(\mu_s=0.51\)
Explanation:
Coefficient of friction
The static coefficient of friction is a measure of the force needed to start moving an object from rest along a rough surface.
It's calculated as:
\(\displaystyle \mu_s=\frac{F_r}{N}\)
Where Fr is the friction force and N is the normal force exerted by the surface over the object.
In the absence of any other vertical force, the normal is equal to the weight of the object:
\(N = W = m.g\)
The box has a mass of m=80 Kg, thus the normal force is:
\(N = 80\ Kg * 9.8\ m/s^2\)
N = 784 N
The student needs to push with a force of 400 N to make the box move. That is the force that barely outcomes the friction force. Thus:
\(F_r=400\ N\)
Calculating the coefficient:
\(\displaystyle \mu_s=\frac{400}{784}\)
\(\mathbf{\mu_s=0.51}\)
Which of these forms due to the force of compression?
A) Anticline
B) Normal Fault
C) Strike-Slip Fault
D) Fault-Block Mountain
Answers
Answer:
anticline
Explanation:
hope u will understand
Answer:
Got it right on edge 2020
Explanation:
anticline
Four friends push on the same block in different directions. Allie pushes on the block to the north with a force of 18 N. Bill pushes on the block to the east with a force of 14 N. Chris pushes on the block to south with a force of 23 N. Debra pushes on the block to the west with a force of 20 N. Assuming it does not move vertically, in which directions will the block move? north and west south and east south and west north and east
Answers
Answer:
South and West
Explanation:
Those people are pushing the hardest. It will move south faster than it moves west.
Gravity causes objects to be attracted to one another. This attraction keeps our feet firmly planted on the ground and causes the moon to orbit the earth. The force of gravitational attraction is represented by the equationF=Gm1m2r2where F is the magnitude of the gravitational attraction on either body, m1 and m2 are the masses of the bodies, r is the distance between them, and G is the gravitational constant. In SI units, the units of force are kgâ‹…m/s2, the units of mass are kg, and the units of distance are m. For this equation to have consistent units, the units of G must be which of the following?Gravity causes objects to be attracted to one another. This attraction keeps our feet firmly planted on the ground and causes the moon to orbit the earth. The force of gravitational attraction is represented by the equation,where is the magnitude of the gravitational attraction on either body, and are the masses of the bodies, is the distance between them, and is the gravitational constant. In SI units, the units of force are , the units of mass are , and the units of distance are . For this equation to have consistent units, the units of must be which of the following?A. kg3mâ‹…s2B. kgâ‹…s2m3C. m3kgâ‹…s2D. mkgâ‹…s2
Answers
Answer:
The S.I unit of G must be m³/kg.s² to keep the equation consistent.
Explanation:
We have the equation:
F = Gm₁m₂/r²
where,
F = Gravitational Force between Two Bodies
G = Gravitational Constant
m₁ = Mass of 1st Body
m₂ = Mass of 2nd body
r = Distance between the Bodies
The S.I Units of the quantities are:
F = Newton = kg.m/s²
m₁ = kg
m₂ = kg
r = meter = m
G = ?
Therefore, to find the units of Gravitational Constant (G), we substitute the known units in the formula:
kg.m/s² = G(kg)(kg)/m²
G = m³/kg.s²
A car is traveling at 14 m/s. By what factor does the car's kinetic energy increase if its speed is doubled to 28 m/s?
Answers
If speed of the car is doubled to 28 m/s, the kinetic energy of it will be four times.
What is kinetic energy?The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes.
Kinetic energy is directly proportional to square of the speed of the object.
Hence, if its speed is doubled to 28 m/s, the kinetic energy of it will be four times.
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what is the full meaning of D.D.T
Answers
A plank AB 3m long weighing 20kg and with center of gravity 2m from the end A carries a load of mass 10kg at the end A it rests on two supports CandD.
1, compute the values of the reaction forces R1 and R2 at C and D.
2, how far from D and on which side of it must a mass of 24kg be placed on the plank so as to make the reactions equal? What are their values.
3,without this 24kg what vertical force applied at B will just lift the plank clear of D? What is then the reaction at C.
Answers
The answers are 1) The value of R2 is not relevant as it implies a downward force on the plank, 2) The reactions at C and D are 66.3 N and 90 N, respectively, and 3) The vertical force at B to lift the plank clear of D is 686.4 N. The reaction at C is zero, and the reaction at D is 61.4 kg.
1) R1 and R2 at C and D respectively are given by the equation R2 = (m1 + m2)g - R1, where m1 and m2 are the masses of the plank and load, respectively, and g is the acceleration due to gravity. Hence, substituting values R2 = (20 + 10) × 9.81 - R1 = 294.3 - R1. Now, taking moments about D, the following equation can be obtained: (20 × 1 + 10 × 3)g = R1 × 2 + R2 × 3 = 2R1 + 3 × (294.3 - R1) = 882.9 - R1, from which R1 = 343.7 N and R2 = 294.3 - 343.7 = -49.4 N. Since the support at D can only push the plank upwards and cannot pull it downwards, a negative value for R2 implies that the plank is actually being pulled downwards by an external force. Therefore, the value of R2 is not relevant. 2) The total weight of the plank and the load acting at the end A is 20 + 10 = 30 kg. For the reactions at C and D to be equal, the 24 kg mass must be placed at a distance x from D such that x × 30 = 24 × 6, from which x = 12/5 = 2.4 m. Since the 24 kg mass is being placed to the left of the plank, it will cause the reaction at C to decrease and that at D to increase. Thus, if R is the vertical force applied at B, then taking moments about D gives 20g × 1 - 10g × 3 + R × 6 = 0, from which R = 90 N. Taking moments about C gives R × 3 - 10g × 2 = 0, from which R = 66.3 N. 3) The vertical force applied at B that will just lift the plank clear of D is the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D. The weight of the plank and the load acting at the end A is 20 + 10 = 30 kg, and the weight of the part of the plank that is to the right of D is 24 × 1.6 = 38.4 kg. Therefore, the vertical force applied at B that will just lift the plank clear of D is (20 + 10 + 38.4)g = 686.4 N. The reaction at C is zero because the plank is not being supported there anymore. The reaction at D is the same as the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D, which is 20 + 10 + 24 × 1.6 = 61.4 kg.For more questions on acceleration
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Humans can hear thunder at different frequencies. These correspond to wavelengths ranging from 2.75 to 16.5 meters. If the speed of
sound is approximately 330 m/s, what frequencies of thunder can humans hear? (1 point)
O 907.5 to 5,445 hertz
O 2.75 to 16.5 hertz
O 20 to 120 hertz
O 0.0083 to 0.05 hertz
Answers
Humans can hear thunder at frequencies ranging from 20 Hz to 120 Hz.
option C.
What is the frequencies heard?
The frequency of a sound wave is given by the equation:
f = v / λ
where;
v is the speed of soundλ is the wavelengthFor the lower frequency of thunder, λ = 16.5 m,
f = 330 m/s / 16.5 m
f = 20 Hz
For the higher frequency of thunder, λ = 2.75 m,
f = 330 m/s / 2.75 m
f = 120 Hz
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2. A 2500 kg car is slowed down uniformly from an initial velocity of 20.0 m/s to
the north by a 6250 N braking force acting opposite the car's motion. Use the
impulse-momentum theorem to answer the following questions:
a. What is the car's velocity after 2.50 s?
b. How far does the car move during 2.50 s?
c. How long does it take the car to come to a complete stop?
Answers
Answer:
13.75m/s; 42.2m; 8s
Explanation:
(a) the car's velocity after 2.50 s is 13.75 m/s
(b) The distance traveled by the car is 42.18 m
(c) the time taken for the car to come to complete stop is 8 s.
The given parameters;
mass of the car, m = 2500 kg
initial velocity of the car, u = 20 m/s
breaking applied on the car, f = 6250 N
The acceleration of the car is calculated as follows;
\(F = ma \\\\a = \frac{F}{m} = \frac{6250}{2500} = 2.5 \ m/s^2\)
(a) Using impulse-momentum theorem, the car's velocity after 2.5 s is calculated as follows;
\(F = \frac{m(u-v)}{t} \\\\m(u-v) = Ft\\\\u-v = \frac{Ft}{m} \\\\v = u - \frac{Ft}{m} \\\\v = 20 - \frac{6250 \times 2.5}{2500} \\\\v = 13.75 \ m/s\)
(b) The distance traveled by the car during the 2.5 s;
\(v^2 = u^2 - 2as\\\\2as = u^2 - v^2\\\\s = \frac{u^2 - v^2}{2a} \\\\s = \frac{20^2 - 13.75^2}{2\times 2.5} \\\\s = 42.18 \ m\)
(c) The time taken for the car to come to a complete stop;
when the car stop's the final velocity, v = 0
v = u - at
0 = 20 - 2.5t
2.5t = 20
\(t = \frac{20}{2.5} \\\\t = 8 \ s\)
Thus, the time taken for the car to come to complete stop is 8 s.
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An airplane traveled for 15 hours at a velocity of 1100 km/hr. What distance
did the airplane travel. *
Your answer
Answers
Answer:
i have no clue
Explanation:
Analysis and Conclusion.
1. Which compound dissolved more easily?
2. Which compound had the lower boiling point?
3. Are the answers to 1 and 2 the same compound? What does this tell you about the strength
of the bonds in this compound?
4. Which compound is the sugar?
5. Which compound is the salt?
Answers
The compound identified as sugar would be the organic compound, such as sucrose (C12H22O11).The compound identified as salt would be the ionic compound, such as sodium chloride (NaCl).
To determine which compound dissolved more easily and had the lower boiling point, we need more specific information about the compounds being compared. However, assuming we are comparing a typical organic sugar compound, such as sucrose (C12H22O11), with a common ionic salt compound, such as sodium chloride (NaCl), we can draw some conclusions.
The salt compound (NaCl) would generally dissolve more easily than the sugar compound (C12H22O11). This is because salt is composed of ions, which readily dissociate in water due to the polar nature of water molecules. Sugar, on the other hand, is a covalent compound and requires breaking of covalent bonds for dissolution, which is typically a slower process.
The sugar compound (C12H22O11) would generally have a higher boiling point compared to the salt compound (NaCl). Covalent compounds tend to have higher boiling points than ionic compounds due to the stronger intermolecular forces between covalent molecules.
No, the answers to 1 and 2 do not refer to the same compound. The strength of the bonds in the sugar compound (covalent) is different from the strength of the bonds in the salt compound (ionic).
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Your physics teacher crumples a piece of paper into a ball and releases it from
rest 1.5 m from the ground. How long does the ball take to hit the ground?
Answers
We have that it takes the ball \(t=0.553sec\) to take to hit the ground
\(t=0.553sec\)
From the Question we are told that
Initial height \(s=1.5m\)
Generally the equation for Time is mathematically given as
\(S=ut+1/2at^2\\\\1.5=0.5*9.8\)
\(t=0.553sec\)
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The paper ball will hit the ground from 1.5 m at 0.55 s.
Here we can use the free fall kinematics equations. Let's see that the paper ball falls from the rest, so the initial velocity will be 0.
\(y=y_{i}+v_{i}t-0.5gt^{2}\)
Here:
y is the final heighty(i) is the initial heightv(i) initial velocity (will be 0)g is the gravity (9.81 m/s²)t the timeNow, the initial height will be 1.5 m, putting our reference system zero in the ball. So, the final height will be 0 m, because it hits the ground.
\(0=1.5-0.5(9.81)t^{2}\)
Therefore, we just need to solve it for t.
\(t=\sqrt{\frac{3}{9.81}}\)
\(t=0.55\: s\)
The ball will hit the ground at 0.55 s.
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1. A 20 Ohm resistor and a 5 Ohm lamp are connected in a single path, with a 50 amps.
What type of circuit is this:
What is the total resistance of the circuit?
What is the total voltage in this circuit?
What is the current?
Answers
The circuit given is a series resistance circuit.
1) The given circuit is a series resistance circuit.
2) Resistance, R₁ = 20 Ω
Resistance, R₂ = 5 Ω
The effective resistance of the circuit is given by,
Reff = R₁ + R₂
Reff = 20 + 5
Reff = 25 Ω
3) Total resistance of the circuit, R = 25 Ω
Current flowing through the circuit, I = 50 A
Therefore, the voltage across the circuit is,
V = IR
V = 50 x 25
V = 1250 V
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a 0.5 kg car is moving at a constant velocity 5 m/s. What is the kinetic energy of the car?
Answers
K=(mv^2)/2 where:
K - kinetic energy
m - mass
v - velocity
Just plug in given numbers, and:
K= (0.5*5^2)/2=6.25 J (Joules)
Consider the broadcasting circuit for an AM radio station which broadcasts at a frequency of 1400 kHz. The free electrons in such a circuit are moving back and forth in simple harmonic motion. (a) How long does it take for the free electrons in this circuit to go back and forth once? Give your answer in microseconds. μs (b) Assuming the average speed of the free electrons is 100 μm/s, what is the range of motion of the electrons as they go back and forth in the wires of the circuit. (HINT: As a free electron goes back and forth, it travels its full range every half cycle.) Give your answer in nanometers. nm (c) What is the wavelength of the electromagnetic radio waves emitted by this broadcasting circuit? Give your answer in meters. m
Answers
a) Time period is given by 0.751 b) Displacement is 0.0751 nm c) The wavelength of the electromagnetic radio waves emitted is 225.56 m
T = 1/f
T = 1/(1330*10^3 Hz)
T = 751.88 ns
Time period T = 0.751 us
b) displacement is given by:
x = velocity * Time
x = 100*10^-6 m/sec*0.751*10^-6 sec
x = 0.0751 nm
c) lambda = c/f
lambda = 3*10^8/(1330*10^3 Hz)
lambda = 225.56 m
Displacement, commonly known as length or distance and denoted by the letters d or s, is a one-dimensional variable that represents the separation between two defined points. In the International System of Units (SI), the meter is the common unit of displacement (m). Transferring unfavorable emotions from one thing or person to another is referred to as displacement and is a defensive tactic. To "take out" their rage on a family member, for instance, a person can yell at them if they are upset with their job. Replace, supersede, and supplant are some frequent alternatives to the word "displace."
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To have the highest magnification in a telescope, the focal length of the objective lens should be _________ and the focal length of the eyepiece lens should be ________. To have the highest magnification in a telescope, the focal length of the objective lens should be _________ and the focal length of the eyepiece lens should be ________. small; small small; large large; small large; large
Answers
Answer:
Large; small.
Explanation:
A telescope can be defined as an optical instrument or device which comprises of a curved mirror and lenses used for viewing distant objects i.e objects that are very far away such as stars and other planetary bodies. The first telescope was invented by Sir Isaac Newton.
To have the highest magnification in a telescope, the focal length of the objective lens should be large and the focal length of the eyepiece lens should be small.
This ultimately implies that, the eyepiece lens has a small focal length while the objective lens has a large focal length.
A large tanker truck carrying Blazblue extract has a capacity of 29053 liters. The density of Blazblue extract is 0.770 grams per milliliter. What is the weight, in pounds, of a full load of Blyzblah extract.
Answers
Answer:
1319.14 lb
Explanation:
From the question above,
Density of the Blazblue extract = mass of Blazblue extract/volume of Blazblue extract.
D = m/v.............. Equation 1
make m the subject of the equation
m = D×v.................... Equation 2
Given: D = 0.770 grams per millilitre, v = 29053 liters = 29053000 millilitres
Substitute these values into equation 2
m = 0.770×29053000
m = 22370810 grams
If,
1 gram = 0.00220462 pounds,
Then,
22370810 grams = (22370810×0.00220462) = 41319.14 lb
We perform an experiment with a 28 cm rod with a mass of .07 kg swinging from its endpoint. The pendulum is allowed to move freely. The pendulum system is then placed on a cart. From rest of both the cart and the pendulum, the cart is push and the acceleration (a) of the cart and the angle of the pendulum is measured. (1): Justify based on theory the maximum displacement angle observed. (2): Do the same, but what if the rod is hung 8 cm from its endpoint?
Answers
For a given length of the pendulum and acceleration of the cart, the maximum displacement angle can be determined using the above formulas.
What is Acceleration?
Acceleration can be positive or negative depending on the direction of the change in velocity. If an object is speeding up, the acceleration is positive, while if it is slowing down, the acceleration is negative.
(1) The maximum displacement angle observed in a pendulum experiment can be determined by the length of the pendulum and the acceleration due to gravity. According to the theory of simple harmonic motion, the period of a pendulum is directly proportional to the square root of its length and inversely proportional to the square root of the acceleration due to gravity.
The formula for the period of a pendulum is:
T = 2π * sqrt(L/g)
where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity (approximately 9.8 m/\(s^{2}\)).
For a given length of the pendulum, the maximum displacement angle occurs when the pendulum is at the highest point in its swing (i.e., when its velocity is momentarily zero). At this point, all of the energy of the pendulum is potential energy (i.e., gravitational potential energy), and the angle is known as the maximum displacement angle or the amplitude.
The maximum displacement angle (θ) can be calculated using the formula:
θ = \(sin^{^-1(a/g)}\)
where a is the acceleration of the cart.
Therefore, for a given length of the pendulum and acceleration of the cart, the maximum displacement angle can be determined using the above formulas.
(2) If the rod is hung 8 cm from its endpoint instead of 28 cm, the length of the pendulum (L) would be 20 cm. Using the same formula as above, the period of the pendulum would be:
T = 2π * sqrt(0.2/9.8) = 0.898 seconds
The maximum displacement angle can be calculated using the same formula as above:
θ = sin^\(sin^{^-1(a/g)}\)
where a is the acceleration of the cart.
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what is the minimum heat if A 500cm³ of water is to be heated from a room temperature (28°C) to 100°C in order to prepare hot cup of coffee