how density of substance change with change in temperature?

Answer:

protects the surface from meteoroids and comets

Explanation:

Have a nice day

protects the surface from meteoroids and comets

The gauge pressure in the water at the foot of the dam is E) 1.09 x 10⁶ Pa.

To calculate the gauge pressure at the foot of the Aswan High Dam, we can use the formula:

Gauge pressure = Density × Gravity × Height

Given that the density of water is 1000 kg/m³ and the height of the dam is 111 meters, we can plug in the values and use the standard acceleration due to gravity (approximately 9.81 m/s²):

Gauge pressure = (1000 kg/m³) × (9.81 m/s²) × (111 m)

Gauge pressure = 1,089,100 Pa

This value is closest to option E, so the correct answer is:

E) 1.09 x 10⁶ Pa

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Answer:

...................

Explanation:

When you set a heavy bag down on the ground, you are doing negative work on it.

The energy for the transition of an electron from the n = 5 level to the n = 8 level of a hydrogen atom is 8.44 x 10^-20 J.

Given that the transition of an electron from the n = 5

level to the n = 8 level of a hydrogen atom and

the energy for the transition of an electron from the n = 5 level to the n = 8 level of a hydrogen atom is to be calculated.

We know that the energy for the transition of an electron from the n = i level to the n = f

level of a hydrogen atom is given by the formula:ΔE = -2.18 x 10^-18 (1/nf² - 1/ni²)

where,ΔE = Energy for the transition of an electronn = Principal Quantum number

f = Final Statei = Initial state

Therefore, substituting the given values in the formula, we get;ΔE = -2.18 x 10^-18 (1/8² - 1/5²)ΔE = -2.18 x 10^-18 (1/64 - 1/25)ΔE = -2.18 x 10^-18 [(25 - 64)/1600]

ΔE = -2.18 x 10^-18 [- 39/1600]

ΔE = 8.44 x 10^-20 J

The energy for the transition of an electron from the n = 5 level to the n = 8 level of a hydrogen atom is 8.44 x 10^-20 J.

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The speed of a wave is calculated using the formula: speed = wavelength x frequency.

In this scenario, we know the distance between Larry and Carrie is 10 m, and the wave creates two loops between them. Therefore, the wavelength is twice the distance between them, which is 20 m. To find the frequency of the wave, we need to use the time it takes for one oscillation, which is 2.2 seconds. The frequency is the inverse of the time, so frequency = 1 / 2.2 = 0.45 Hz. Now we can use the formula to calculate the speed of the pulse: speed = wavelength x frequency. Plugging in the values, we get:
speed = 20 m x 0.45 Hz = 9 m/s

Therefore, the speed of the pulse in the zinc-coiled spring is 9 m/s.

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The primary distinction between infrared and ultraviolet radiation is that while the wavelength of ultraviolet radiation is shorter than that of visible light, that of infrared radiation is longer.

The part of the electromagnetic spectrum known as ultraviolet radiation spans from the violet, or short-wavelength, end of the visible light spectrum to the X-ray region. High-temperature surfaces, like the Sun's, emit ultraviolet radiation in a continuous spectrum, whereas atomic excitation in a gaseous discharge tube emits it as a discrete spectrum of wavelengths. Both a sterilization method and a research tool, ultraviolet light has several applications. It can also be utilized in fluorescent lights, which use less energy than incandescent bulbs to provide artificial light.

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As there is no figure provided, I cannot provide a specific answer to this question. However, I can explain the concept of equilibrium and the conditions necessary for an object to be in equilibrium.

When an object is in equilibrium, it means that it is not accelerating and its net force is zero. There are two types of equilibrium: static equilibrium and dynamic equilibrium.

Static equilibrium is when the object is at rest and its net force is zero. Dynamic equilibrium is when the object is moving at a constant velocity and its net force is zero.

For an object to be in static equilibrium, two conditions must be met:

The net force acting on the object must be zero.

The net torque (rotational force) acting on the object must be zero.

In order to determine the magnitudes of the forces F_u1 and F_u2, we would need more information about the object and the forces acting on it.

We would need to know the direction and magnitude of all the forces acting on the object, as well as the distance between the forces and the point of rotation (if there is any).

Without this information, it is not possible to determine the magnitudes of F_u1 and F_u2.

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Hi there!

We can begin by calculating the distance remaining after the reaction time.

Δd = vt

Calculate the distance traveled within this time:

Δd = (16)(.79) = 12.64 m

Subtract from the total distance:

150 - 12.64 = 137.66 m remaining

We can use the following equation to solve for the acceleration necessary:

vf² = vi² + 2ad, where vf = 0 since the train will have slowed down to rest.

Rearrange in terms of "a":

0 = vi² + 2ad

(-vi²) = 2ad

(-vi²)/2d = a

Plug in the given values:

(-(16²))/2(137.66) = a

-256/275.32 = -.9298 m/s²

Answer:

i) 196J ii) 78.3J iii) 14m/s

Explanation:

i) Formula for gravitational potential energy is

Eg = mgh

Eg = (2)(9.8)(10)

Eg = 196J

ii) Formula for kinetic energy is

Ek = (mv^2)/2

We need to find the velocity first by using one of the key equations of accelerated motion

v^2 = vi^2+2aΔd

v = √vi+2aΔd

v = √2(9.8)(4)

v = 8.85 m/s

Ek = ((2)(8.85^2))/2

Ek = 78.3J

iii)

v = √vi+2aΔd

v = √2aΔd

v = √2(9.8)(10)

v = 14 m/s

Answer:

\(\huge\boxed{Divide\ distance \ by \ time}\)

Explanation:

Speed = Distance / Time

So, to find distance, we actually divide distance by rime.

Answer:

\(\large \boxed{\mathrm{divide \ distance \ by \ time}}\)

Explanation:

Using the formula to calculate speed:

\(\displaystyle \sf speed =\frac{distance}{time}\)

We divide the distance by the time taken to get the average speed.

Answer:

Below

Explanation:

135 lbs  *  1 kg/2.2 lb  = ~ 61.4 kg

there are 1000 mg in each gram

5.3 mg   *  1 gm / 1000 mg = .0053 g

Answer:

It helps prevents falls and supports your body. So having a strong core is beneficial to everyone because it allows your body to function properly. Improved Balance and Stability. Core exercises train the muscles in your pelvis, lower back, hips and abdomen to work together.

Answer:

false

Explanation:

because oil is thicker than water

Answer:

answer is false

Explanation:

water is more dense than oil so they can't mix . Oil float above the water

Answer:

Alpha decay forms new element with two fewer protons and two fewer neutrons, Beta decay forms new element with one more proton and one fewer neutron. Gamma decay forms NO new element, but now the element has less energy because energy is released as gamma rays.

Explanation:

ANSWER AND EXPLAINATION:
Gamma decay differs from alpha and beta decay in several ways:

1. Particle emitted: In gamma decay, no particles are emitted. Instead, a high-energy photon called a gamma ray is released. Alpha decay involves the emission of an alpha particle, which consists of two protons and two neutrons. Beta decay involves the emission of either a beta-minus particle (an electron) or a beta-plus particle (a positron).

2. Mass and charge: Gamma decay does not change the mass or atomic number of the nucleus since no particles are emitted. Alpha decay reduces the atomic number by 2 and the mass number by 4, as an alpha particle is emitted. Beta decay changes the atomic number, with beta-minus decay increasing it by 1 and beta-plus decay decreasing it by 1. The mass number remains the same in beta decay.

3. Penetrating power: Gamma rays have the highest penetrating power among the three types of decay. They can pass through most materials and require dense shielding (e.g., lead or concrete) to attenuate them. Alpha particles have low penetrating power and can be stopped by a sheet of paper or a few centimeters of air. Beta particles have intermediate penetrating power and can be stopped by a few millimeters of aluminum.

4. Energy release: Gamma decay releases energy in the form of high-energy photons. Alpha decay releases a significant amount of energy since an alpha particle carries substantial kinetic energy. Beta decay releases energy in the form of the kinetic energy of the emitted beta particle.

gamma decay is a process that involves the emission of high-energy photons, while alpha and beta decay involve the emission of particles with mass and charge. Gamma rays have higher penetrating power and do not cause changes in the mass or atomic number of the nucleus, distinguishing them from alpha and beta particles.

Answer:

elastic collision

Explanation:

Complete question is;

The abc battery company claims that their batteries last 100 hours, on average. You decide to conduct a test to see if the company's claim is true. You believe that the mean life may be different from the 100 hours the company claims. you decide to collect data on the average battery life (in hours) of a random sample of n = 20 batteries. some of the information related to the hypothesis test is presented below:

Test of H0: μ = 100 versus H1: μ ≠ 100

Sample mean: 98.5

Std error of mean: 0.777

Assuming the life length of batteries is normally distributed, what is the p-value associated with this test?

Answer:

p-value =  0.00001

Explanation:

We are given;

Null hypothesis; H0: μ = 100

Alternative Hypothesis; H1: μ ≠ 100

Sample mean: x = 98.5

Standard error of mean; s = 0.777

To find the test statistic, we will use the formula;

t = (x - μ)/(s/√n)

t = (98.5 - 100)/(0.777/√20)

t = -1.5/0.1737

t = -8.64

Now, from online p-value from t-score calculator attached, using t = -8.64; DF = n - 1 = 20 - 1 = 19; two tail distribution;significance level of 0.05; we have;

The p-value =  0.00001

Answer:

\(2\times 10^{8}\ \text{m/s}\)

Explanation:

\(n\) = Refractive index of glass = 1.5

\(c\) = Speed of light in vacuum = \(3\times 10^8\ \text{m/s}\)

Refractive index is given by

\(n=\dfrac{c}{v}\\\Rightarrow v=\dfrac{c}{n}\\\Rightarrow v=\dfrac{3\times 10^8}{1.5}\\\Rightarrow v=2\times 10^{8}\ \text{m/s}\)

The speed of light in the glass is \(2\times 10^{8}\ \text{m/s}\).

The law that governs the conservation of electric charge in a closed system is known as the law of conservation of charge.

According to this law, the total amount of electric charge in a closed system remains constant and cannot be created or destroyed. As for how objects can change their charges in a closed system, it is because the distribution of electric charge can change.

For example, when two objects with different electric charges are brought into contact, electrons can flow from one object to the other until both objects have the same electric potential. This transfer of electrons results in a change in the charge of each object, but the total charge remains the same.

Another way objects can change their charges is through the process of ionization, where an atom loses or gains electrons, resulting in a change in the electric charge of the atom. Again, the total charge remains constant, as the lost or gained electrons must go somewhere.

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The voltage across the primary of the transformer, VP = 120VThe voltage across the secondary of the transformer, VS = 5VThe number of turns in the primary of the transformer, NP = 480 turnsThe number of turns in the secondary of the transformer, NS can be calculated using the following formula;

`VP / VS = NP / NS`.

Substituting the values in the above formula,`120 / 5 = 480 / NS`Solving for NS;`NS = (5 × 480) / 120 = 20 turns`Therefore, the number of turns in the secondary is 20 turns.Question 10The distance between the parallel wires, d = 6.8 cm = 0.068 mThe current flowing through each of the parallel wires, I = 23.8 AThe force per unit length between the wires can be determined using the following formula;`

F / L = (μI1I2) / (2πd)`

where F is the force between the wires, L is the length of the wire and μ is the permeability of free space.Substituting the values in the above formula;

`F / 1 = (4π × 10^-7 × 23.8^2) / (2 × π × 0.068)`

Simplifying the above expression;`F = 2.00 × 10^-4 N/m`Therefore, the force per unit length exerted by one of the wires on the other is 2.00 × 10^-4 N/m.

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For a successful final touch of a construction venture, key stakeholders consisting of the consumer/proprietor, architect/layout group, and creation contractor are crucial. Risk management is necessary to perceive and mitigate capacity risks, ensuring project success and minimizing disruption

The 3 important stakeholders for the development of a new mall in Alexandra are:

During the construction of an avenue in a particular network, the network is represented by:

Local Authorities: The local authorities, which include the municipal or city council, represent the community's pastimes. Their duties consist of engaging with the network to apprehend their needs and issues associated with the road construction project.

Before any sort of Civil Engineering mission is executed, the subsequent steps want to be taken to ensure the viability of the challenge:

The hierarchy of running for a contractor sporting out the development of a bridge typically consists of the subsequent degrees:

To draw the bar chart (also referred to as a Gantt chart) for a 50 km street creation undertaking with a duration of 10 days, the chart could represent the obligations and their respective intervals. However, a standard bar chart for an avenue creation undertaking may also include duties including surveying, excavation, laying subbase, paving, and street markings, amongst others.

The horizontal axis represents the timeline (in days), and the vertical axis represents the responsibilities. Each undertaking is represented with the aid of a horizontal bar that suggests its length.

Question 2 (10):

2.1 Risk control is vital in a venture for the following motives:

Overall, change management is important for figuring out, analyzing, and responding to risks in a systematic and proactive manner. It enables ensuring task success by using lowering uncertainties and maximizing opportunities for task delivery within the preferred parameters.

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Answer:

The change in momentum of the car is 16380.8 kg.m/s

Explanation:

Given;

mass of the car, m = 1600 kg

time of motion, t = 4.20s

force of friction on the car, F = 3900 N

final velocity of the car after the brakes were applied, v = 0

The initial velocity of the car during the motion is calculated as;

\(F = ma = \frac{mu}{t} \\\\mu = Ft\\\\u = \frac{Ft}{m} \\\\u = \frac{3900\times 4.2}{1600} \\\\u = 10.238 \ m/s\)

The change in momentum of the car is calculated as;

ΔP = mu

ΔP = 1600 x 10.238

ΔP = 16380.8 kg.m/s

The time it takes the spaceship to complete one full period of orbit is 4270.1 s

Since a spaceship of 3.20 × 10⁷ kg travels around another planet, of

6.34 x 10²⁵ kg and the distance between them is 12,500 km, we require the time for one full orbit which is its period.

The period of orbit is the time it takes to complete one full cycle of orbit

To calculate the period, we use the equation for the speed of an orbiting object.

v = √(GM/R) where

Also, since the orbit is a circular orbit, its speed, v = 2πR/T where

So, v = √(GM/R)

2πR/T = √(GM/R)

Making the period, T subject of the formula, we have

T = 2π√(R³/GM)

Substituting the values of the variables into the equation, we have

T = 2π√(R³/GM)

T = 2π√((1.25 × 10⁷ m)³/{6.67 × 10⁻¹¹ Nm²/kg² × 6.34 × 10²⁵ kg})

T = 2π√((1.953125 × 10²¹ m³/42.2878 × 10¹⁴ Nm²/kg)

T = 2π√((0.04619 × 10⁷ mkg/N)

T = 2π√((0.4619 × 10⁶ mkg/N)

T = 2π√((0.4619 × 10⁶ mkg/N)

T = 2π(0.6796 × 10³ s)

T = π(1.3592 × 10³ s)

T = 4.27009 × 10³ s

T = 4270.09 s

T ≅ 4270.1 s

So, it take the spaceship 4270.1 s to complete one full orbit

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Answer:

I would like to attach options to the question above for clarity.

Jasmine is investigating the effect force has on the motion of an object. She predicts if she puts a strong force on pushing a bowling ball, it will travel a farther distance than when a weak force is applied. Is her prediction correct?

A. No, a weak or a strong force applied to the ball is unable to affect the motion of the ball.

B. No, the force applied to the bowling ball should be a strong force.

C. Yes, the force applied to the bowling ball affects the motion of the ball.

D. Yes, the ball will travel a longer distance when a weak force is applied.

The correct option is C (Yes, the force applied to the bowling ball affects the motion of the ball).

Explanation:

First, a force is any effort either push or pull that causes an object to undergo a change.

A bowling ball can remain at rest or in motion except a force acts on it. This brings us to the question above, the mass which affects force is not mentioned which means it is uniform or negligible. Recall that force = mass X acceleration. So the greater the force that is applied to the bowling ball the further distance it will travel. From the question, she applied a forward force (pushing), so the more force she applies the further the bowling ball will travel.

Answer:

Large above ground mausoleums were not common in the elite Shang burials.

Explanation:

Large, above the ground mausoleums were not common so the answer is option B.