Answer:
hi
Explanation:
how r u today
An metal rod weighing 123 g with a temperature of 100.°C is placed in 75 mL of water at 25.0 °C. If the final
temperature of the metal and water is 29.0 °C, what is the specific heat capacity of the metal? (Assume that
the density of water is 1.0 g/mL and specific heat capacity of water is 4.184 J/g°C.)
O 0.23 J/gºC
O 0.14 J/gºC
O 3.6 J/gºC
O 1.6 J/gºC
The specific heat capacity of the metal rod weighing 123g is 0.14 J/gºC (option B).
How to calculate specific heat capacity?The specific heat capacity of a metal substance can be calculated using the following formula:
Q = mc∆T
Where;
Q = heat absorbed or releasedm = mass of substancec = specific heat capacity∆T = change in temperatureHowever, in a calorimeter, the metal and water relationship is given as follows:
Q (water) = - Q (metal)
mc∆T (water) = - mc∆T (metal)
Mass of water = density × volume
Mass of water = 1g/mL × 75mL = 75g
75 × 4.184 × {29°C - 25°C} = - {123 × c × (29 - 100)}
1255.2 = 8733c
c = 1255.2/8733
c = 0.144J/g°C
Therefore, the specific heat capacity of the metal rod weighing 123g is 0.14 J/gºC.
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Question 1
Sodium chloride is a liquid at 900 °C.
How are the particles arranged and how do the particles move in sodium chloride at 900 °C?
Answer:
Particles is a gas are well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.
Explanation:
An argon ion laser emits visible radiation with photons of energy 4.071 x 10-19 J. What is the
wavelength of the radiation?
The wavelength of the radiation emitted by the argon ion laser is \(4.854 * 10^-7 m\).
Wavelength is a property of any type of wave that refers to the distance between two adjacent points on the wave that is in phase, i.e., at the same point in their respective cycles. It is usually denoted by the Greek letter lambda (λ) and is measured in units of length, such as meters or nanometers.
The energy carried by the photon (E) is related to the wavelength (\(\lambda\)) through the following equation:
\(E=hc/\lambda\); where 'h' is the Plank's Constant and 'c' is the speed of light which is \(3* 10^{-7} m/s\).
We can say that
\(\lambda - hc/E\)
Now after substituting the given values, we get:
\(\lambda = (6.626 * 10^{-34} J.s * 3.00 * 10^8 m/s) / (4.071 * 10^{-19} J)\\\lambda = 4.854 * 10^-7 m\)
Therefore the wavelength of the radiation emitted by the argon ion laser is \(4.854 * 10^-7 m\).
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if 2.62 g of argon gas occupies a volume of 5.18L, what volume with 1.25 moles of argon gas occupy under the same temp and pressure
Answer: 98.7 L
Explanation:
Since the atomic mass of argon is 39.948 g/mol, 2.62 grams of argon gas is the same as moles.
We can now set up a proportion to solve for the volume.
\(\frac{V}{1.25}=\frac{5.18}{0.065585260839091}\\\\V=98.7 \text{ } L\)
9. When 1.10 g of magnesium reacted with unlimited amount of HCl, the products were
hydrogen gas and magnesium chloride. What volume of hydrogen gas would be collected
if the reaction had been run at STP?
As per the balanced equation of the reaction one mole of Mg give s one mole of H2. 1.10 g of magnesium is 0.045 moles. Thus it gives 0.045 moles of H2 which is 1.02 litres.
What is magnesium chloride?Magnesium chloride is an ionic compound formed by the reaction of magnesium metal with two moles of hydrochloric acid. The reaction also produce one mole hydrogen gas.
The atomic mass of magnesium is 24 g/mol. Thus number of moles in 1.10 g is 1.10/24 = 0.045 moles.
As per the reaction equation one mole of magnesium gives one mole of hydrogen gas. Thus 0.045 moles of magnesium gives 0.045 moles of hydrogen gas.
At STP, the volume of one mole of any gas will be equal to 22.4 L. Thus volume of 0.045 moles of hydrogen at STP is:
volume = 0.045 × 22.4
=1.02 L.
Hence, the volume of hydrogen produce here is 1.02 L.
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Justification of Subaquatic soil if it is sediment or soil (on the point of view of a geologist)
Subaquatic soil can be classified as sediment or soil based on its geological properties and formation processes.
Sediment refers to any material that is transported and deposited by water, wind, ice, or gravity. Sediments can be composed of various materials, such as minerals, rocks, organic matter, and even human-made debris.
Sediments can accumulate in different environments, such as rivers, lakes, oceans, and deserts, and can be deposited in layers over time.
Subaquatic soil can be classified as sediment or soil based on its geological properties and formation processes. If it has primarily formed through sediment deposition, it is more appropriate to classify it as sediment.
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which element has the highest ionization energy?B, Al, Ga, In
Answer:
BORON
Ionization energy decreases down the group and going from left to right the period,
Luckily you have the elements from the same group that is Group III A also called boron family,
The position of Elements in this group are
Boron (B)Aluminium (Al)Gallium (Ga)Indium(In)ThalliumNihoiumso keeping rules in mind the first element in the group has highest I.E. that is boron
Cathodic protection of iron involves using another more reactivemetal as a sacrificial anode. Classify each of thefollowing metals by whether they would or would not act as asacrificial anode to iron.
a. Sn
b. Cu
c. Zn
d. Au
e. Pb
f. Ag
g. Mg
An old iron beam was coated with an unknown metal. There is a crackon the coating and it is observed that the iron is rusting at thefracture. The beam is in a structure that experiences high stress,resulting in frequent fractures to the coating.
What was the old metal coating likely made of and what metal youwould use to repair the fractures to avoid further corrosion?
Choices: tin, aluminum, gold
1. The old coating was made of __________________.
2. __________________would be a good choice for repairing thefracture.
Answer:
1.) zinc and aluminum
2.)
a.) The old coating was made of tin.
b.) Aluminum would be a good choice for repairing the fracture.
I need help with this please fast
4) The volume of the HCl used is 9.500 mL while the volume of the NaOH used is 3.800 mL.
5) Molarity of sodium hydroxide is obtained from; Molarity of HCl * 1/2
What is titration?By reacting an unknown component with a known quantity of a different chemical known as a titrant, titration is a laboratory procedure used to measure the concentration of an unknown substance, often a solute dissolved in a liquid.
The endpoint of a titration can be detected in a number of ways, depending on the specific titration being performed.
4)
Volume of the Acid used = Initial reading - Final reading = 25.00 - 15.50 = 9.500 mL
Volume of the base used = 8.80 - 5.00 = 3.800 mL
5)
We know that the mole ratio is 1:2 and the implication of this is that the set up to obtain the molarity of the sodium hydroxide solution is Molarity of HCl * 1/2
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study this chemical reaction: 2 Zn+ O2= 2 ZnO then, write balanced half-reactions describing the oxidation and reduction that happen in this reaction.
The balanced half reaction for the redox reaction of Zn with O2 is,
Oxidation: 2 Zn -------> 2 Zn+2 + 4 e-
Reduction: O2 + 4 e- ---------> 2O-2
What is redox reaction?
Redox reaction includes both oxidation and reduction happening simultaneously where the number of electrons lost in the oxidation is equal to the number of electrons gained in the reduction. There is change in oxidation number of the species involved in redox reaction.
The half cell reaction for redox reaction can be written as,
Zn -------> Zn+2 + 2 e-
Here Zn is undergoing oxidation by losing 2 electrons.
O2 + 4 e- ---------> 2O-2
Here O2 is undergoing reduction by gaining electrons. To make the number of electrons equal the oxidation half cell reaction is multiplied by 2.
Therefore, the redox reaction can be written in half cell reaction as,
Oxidation: 2 Zn -------> 2 Zn+2 + 4 e-
Reduction: O2 + 4 e- ---------> 2O-2
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3) What mass of ethanol could burn in 100 g of oxygen? C2H5OH + 3 02 2 CO2 + 3 H2O
LEEN was observing the physical properties of elements in order to classify them as either a metal, non-metal, metalloid or any other type of element. The first element was dull, brittle, and did not conduct heat. What would its classification be
Metal
Non-metal
Metalloid
Radioactive element
Answer:
Non-metal
Explanation:
A non-metal is a substance that possesses the following characteristics:
- It is brittle i.e can break easily
- It does not conduct heat and electricity
- It is not lustrous i.e does not shine when polished.
According to this question, LEEN was observing the physical properties of elements in order to classify them. He found that the first element was dull, brittle, and did not conduct heat. This makes it a NON-METAL.
The work is due in 6 pm Wednesday 1st March. Please upload your work to Moodle 1) A peak observed at 1690 cm in the mid-IR spectrum of guanine is assigned to the carbonyl stretching vibration. a) Convert 1690 cm into um. (1 mark) b) Predict the approximate position of the first overtone peak from this vibration (give your answer in cm1), and comment on the intensity of this overtone peak compared to the fundamentall at 1690 cm-1. (2 marks) c) Where would you expect to observe a peak due to the carbonyl stretching vibration in the vibrational-Raman spectrum of guanine, if the 514.5 nm line of an argon ion laser was used as the incident light source? Express your answer in both relative reciprocal centimetres (relative cm-¹) and in nanometers (nm). (3 marks) d) i) What would the peak position be if the 488 nm line from the argon-ion laser was used instead of the 514.5 nm line? Give you answer in both nm and in relative cm¹. i) What would the relative intensity of the peak be if the 488 nm line from the argon-ion laser was used instead of the 514.5 nm line? (Assume that the power output of the laser was the same at both wavelengths.) (4 marks)
The conversion of 1690 cm^-1 to µm is 6µm
The first overtone is 3380cm^-1
How to solvea. Given that:
We want to make a conversion from cm^-1 to µm
Wave numbers in cm^-1 is 10,000/µm
Let x and y be two numbers
xcm^-1 = 10^4/Yµm
Yµm= 10^4/xcm^-1
Expanding
10^4/1690
=6µm.
b. If the fundamental frequency is 1690 cm^-1
The first overtone is equal to the second harmonic
If the fundamental frequency is F
First overtone = F2
Then F2 = 2F
Therefore, the first overtone is 2 x 1690 =3380cm^-1
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pOH of the 0.001M NaOH solution is
The pOH of the 0.001 M NaOH solution is approximately 3.
To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.
In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.
The pOH is calculated using the equation:
pOH = -log[OH-]
Substituting the concentration of hydroxide ions, we have:
pOH = -log(0.001)
Using a calculator, we can evaluate the logarithm:
pOH ≈ 3
Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.
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Find the mass of 2 moles of carbon tetrachloride
Answer:
The mass of 2 moles of carbon tetrachloride is
307.646 grams
Explanation:
The chemical formula for Carbon tetrachloride is \(\ce{CCl_4}\). It contains 1 carbon atom and 4 chlorine atoms.
Carbon tetrachloride is formed due to the covalent bond between one carbon atom with four chlorine atoms.
In order to find the mass of 2 moles of \(\ce{CCl_4}\) we need to determine the molar mass.
The molar mass of carbon is 12.011 g/mol.
The molar mass of chlorine is 35.453 g/mol.
As stated before we have 1 carbon atom and 4 chlorine atoms. So the molar mass can be evaluated by
\(\left(1*12.011\right)+\left(35.453*4\right)=153.823\)
The molar mass of \(\ce{CCl_4}\) is 153.823 g/mol.
You can multiply that by 2 to get the mass in grams of 2 moles of carbon tetrachloride.
\(2*153.823 =307.646\)
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A sample of N2 has 1.70 moles and occupies 3.80 L at 25°C. How many moles are in a sample that occupies 1.45 L? Answer should be numbers only, no units, to 2 decimal places
The concept Avogadro's law is used here to determine the moles of gas present in the sample. Avogadro's law is also known as the Avogadro's principle or Avogadro's hypothesis. It is closely related to the ideal gas equation.
According to Avogadro's law, equal volumes of all gases under similar conditions of temperature and pressure contain equal number of molecules. It follows that the volume of the gas is directly proportional to the number of molecules.
The equation is:
V₁n₁ = V₂n₂
n₂ = V₁n₁ / V₂
3.80 × 1.70 / 1.45 = 4.45
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An EpiPen, used to treat anaphalactic allergic reactions, contains 0.30 mg of epinephrine. The concentration of epinephrine in each syringe is 1.0 mg/mL. What is the volume, in milliliters (mL), of solution in each syringe
Answer:
0.3mL
Explanation:
Mass = 0.30mg
Concentration = 1.0 mg/mL
Volume = x
The relationship between the three parameters is given as;
Concentration = Mass / Volume
Making Volume our subject of interest we have;
Volume = Mass / Concentration
Substituting the values we have;
Volume = 0.30 mg / 1 mg/mL = 0.3mL
b. How many kJ of heat are needed to completely vaporize 50.0g of water at 100°C? [Ans:113. kJ]
The amount, in kJ, of heat needed to completely vaporize 50.0g of water at 100°C is 118.8 kJ.
Heat of vaporization of waterThe heat needed to completely vaporize 50.0g of water at 100°C can be calculated using the following formula:
q = m x Hv
where:
q is the heat needed in joules (J)m is the mass of water in grams (g)Hv is the heat of vaporization of water which is approximately 40.65 kJ/mol at standard temperature and pressure.First, we need to convert 50.0g to moles by dividing by the molar mass of water which is approximately 18.015 g/mol3:
moles of water = 50.0 g / 18.015 g/mol moles of water = 2.776 mol
Thus:
q = (2.776 mol) x (40.65 kJ/mol) q = 112.8 kJ
In other words, 112.8 kJ of heat is needed to completely vaporize 50.0g of water at 100°C.
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Which short-term environmental change would a very small asteroid or comet impact on Earth most likely cause? flooding extinction surface craters weather pattern changes
The correct answer is C. Surface craters
Explanation:
Short-term environmental changes involve temporary changes and effects in the ecosystem, which are mainly minor. In the case of a small asteroid or comet, this will likely lead to surface craters or changes in the surface of the impact zone. This is because the craters and asteroids impact the surface at hight speed. Also, because this is a minor event it might lead to the death of some organisms but not the extinction of these and it is not expected this has major effects such as changes in weather. Thus, the short-term effect that this will most likely cause is "surface craters."
Answer:
surface
Explanation:
Calculate the number of hydrogen atoms present in 40g of urea, (NH2)2CO
Answer: There are \(16.14 \times 10^{23}\) atoms of hydrogen are present in 40g of urea, \((NH_{2})_{2}CO\).
Explanation:
Given: Mass of urea = 40 g
Number of moles is the mass of substance divided by its molar mass.
First, moles of urea (molar mass = 60 g/mol) are calculated as follows.
\(Moles = \frac{mass}{molar mass}\\= \frac{40 g}{60 g/mol}\\= 0.67 mol\)
According to the mole concept, 1 mole of every substance contains \(6.022 \times 10^{23}\) atoms.
So, the number of atoms present in 0.67 moles are as follows.
\(0.67 mol \times 6.022 \times 10^{23} atoms/mol\\= 4.035 \times 10^{23} atoms\)
In a molecule of urea there are 4 hydrogen atoms. Hence, number of hydrogen atoms present in 40 g of urea is as follows.
\(4 \times 4.035 \times 10^{23} atoms\\= 16.14 \times 10^{23} atoms\)
Thus, we can conclude that there are \(16.14 \times 10^{23}\) atoms of hydrogen are present in 40g of urea, \((NH_{2})_{2}CO\).
What is the molality of a solution of 12.9 g of fructose (C6H12O6) in 31.0 g of water?
Answer:
2.31 \(m\) C₆H₁₂O₆
Explanation:
Hope this helps
The molality of a fructose will be 2.31 M.
What is molality?
The term "total moles of a solute present in a kilogram of a solvent" is used to describe molality. The terms "molality" and "molal concentration"
Molality can be determined by the formula:
Molality = solute (n) / solvent (w) Kg
Given data:
Mass of fructose = 12.9 g
Mass of solvent = 31.0 g
Now, put the value of given data in molality equation.
Molality = 12.9/180 × 31 × \(10^{-3}\)
Molality = 0.00231 × \(10^{-3}\)
Molality = 2.31 M
Therefore, the molality of a fructose will be 2.31 M.
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what is the mass in grams of 0.40 moles of sodium borohydride nabh4
Answer:
15.12g
Explanation:
Given parameters:
Number of moles = 0.4moles
Unknown:
Mass of the compound = ?
Solution:
To solve this problem;
Mass = number of moles x molar mass
Molar mass of NaBH₄ = 23 + 10.8 + 4(1) = 37.8g/mol
Mass of the compound = 0.4 x 37.8 = 15.12g
Answer:
The answer is 15.12 g but if you are taking this test on ck12 make sure you round it to 15 like it says on the directions :) good luck
An instantaneous dipole occurs when a molecule's moving electrons are briefly more concentrated in one place than another, causing the molecule to become temporarily polarized.
True
False
An instantaneous dipole occurs when a molecule's moving electrons are briefly more concentrated in one place than another, causing the molecule to become temporarily polarized.
The correct option is True.
What are dipoles?Dipoles refer to a separation of charges where one end of a substance has a positive charge while the other end has a negative charge.
In chemical compounds, dipoles occur within a molecule that has covalently bonded atoms or atoms that share electrons in the covalent bond.
The dipole may be permanent dipoles or temporary dipoles.
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- Preparation of NaPO4 solution (So): A solution (So) of sodium phosphate is to be prepared of molar concentration 0.1 mol/L. mL. 100 Given M(Na3PO)=164 g/mol. and a volume 1.1- Calculate the mass of sodium phosphate needed to prepare this solution. Deduce its mass concentration (Cm). 1.2 - Write the materials and glassware needed. 1.3- Write the equation of dissolution of sodium phosphate. 1.4- Determine the molar concentration of Na ions in this solution
Answer:
Explanation:
1.1 we have to find mass of Na3PO4;
for that we have to Calculate the moles of Na3PO4 needed:
volume is 100mL = 0.1L
Molar concentration = Moles of solute / Volume of solution in L
0.1 mol/L = Moles of Na3PO4 / 0.1 L
Moles of Na3PO4 = 0.1 mol/L * 0.1 L
Moles of Na3PO4 = 0.01 mol
Now, Calculate the mass of Na3PO4 needed:
so, Mass = Moles of Na3PO4 * Molar mass of Na3PO4
Mass = 0.01 mol * 164 g/mol
Mass = 1.64 g of Na3PO4.
1.2 materials and glassware needed:
1.64 g Sodium phosphate (Na3PO4)
100 mL volumetric flask
weighing balance
Distilled water
Glass rod
Pipette and burette
1. In a heterogeneous mixture, the substances
A. can be physically separated.
B. are chemically combined.
C. can only be separated through chemical
processes.
D. break down into new substances.
Please answer
Question 4 (1 point)
If the decomposition of (NH4)2(CO3) is a first-order process with a rate constant of
0.196 s-1, how much ammonium carbonate would remain after 39.0 s, starting from
a concentration of 0.957 M?
Your Answer in units:
The final concentration of the reactant of a first order reaction can be determined from the rate constant equation. The concentration of ammonium carbonate after 39 s will be 0.003 M.
What is rate constant?Rate constant of a reaction is the rate of reaction when one molar concentration of the reactant is involved in the reaction. The expression for the rate constant k for first order reaction is :
k = 1/t ln (C0/Ct)
Where C0 be the initial concentration and Ct be the concentration after t seconds.
Given that C0 of ammonium nitrate = 0.957 M
rate constant = 0.196 /s
t = 39 s.
The concentration after 39 seconds is calculated as follows:
0.196 /s = 1/39s ln (0.957 M / Ct)
Ct = 0.957 / (ln⁻¹ (0.196 × 39))
= 0.003 M.
Therefore, the concentration of ammonium carbonate after 39 seconds will be 0.003 M.
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One kilometre equals to what centimeter
Answer:
100,000
Explanation:
1 kilometer equals 100,000 centimeters
You multiply the length value by 100,000
Answer:
One kilometre is 100,000 centimeters
Explanation:
How does the structure of a carbon atom enable it to form largr molecule
Answer:
Carbon is the only element that can form so many different compounds because each carbon atom can form four chemical bonds to other atoms ,and because the carbon atom is just the right ,small size to fit in comfortably as parts of a very large molecules.
hope this helps :) !!!
What is the boiling point of liquid c when the
Answer:
100 degree is the answer of given statement
which 2 criteria are the most important of engineers to consider when developing a procsses to produce
Two key criteria that engineers must prioritize are efficiency and safety. By emphasizing efficiency and safety during process development, engineers can create robust and reliable processes that not only maximize productivity but also prioritize the well-being of personnel and the environment.
When developing a process, engineers need to consider several important criteria. Two key criteria that engineers must prioritize are efficiency and safety.
Efficiency is crucial in process development to ensure optimal use of resources, time, and energy. Engineers strive to design processes that maximize productivity, minimize waste, and reduce costs. This involves optimizing reaction conditions, streamlining workflow, and implementing automation where possible. Efficiency considerations also extend to energy consumption, raw material utilization, and overall process sustainability.
Safety is another critical aspect that engineers must prioritize. They need to identify and mitigate potential hazards associated with the process, ensuring the safety of both personnel and the environment. This involves conducting thorough risk assessments, implementing safety protocols, and designing equipment and systems with safety features. Engineers must also consider the safe handling and storage of materials, as well as potential risks during transportation and disposal.
By emphasizing efficiency and safety during process development, engineers can create robust and reliable processes that not only maximize productivity but also prioritize the well-being of personnel and the environment.
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