How can we identify a proportional relationship on a graph?

Answer:

B or D

Step-by-step explanation:

The value of x in the given diagram is 6 (option d).

There are two right triangles in the given image. <PR'Q' and <PQR are right triangles. A right triangle is a triangle that has an angle that measures 90 degrees.

The principle of similar triangles would be used to solve for the required values.

x/9 = 10 / 15

In order to determine the value of x, cross multiply:

15x = 9 x 10

15x = 90

Divide both sides of the equation by 15

x  = 90 / 15

x = 6

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Answer:

Mexico to the United States in 1947

Step-by-step explanation:

The formula derived from the sentence will be 4(f + g) = 6g.

A statement, principle, or policy that creates the link between two variables is known as a function. Functions are found all across mathematics and are required for the creation of complex relationships.

Translate the sentence into an equation or formula.

The sentence is given below.

Four times the sum of f and g is identical to six times g. Then the equation will be

The sum of f and g will be given as (f + g). And identical means equal sign, then we have

4(f + g) = 6g

The formula derived from the sentence will be 4(f + g) = 6g.

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Answer:

The answer to this is 2000.

Step-by-step explanation:

I hope it helps! :)

Answer:

2000

Step-by-step explanation:

Just do it.

Answer:

x = 45

Step-by-step explanation:

y is the score on the test. To find the amount of time to study he needs to get a score of 90 on his next test, we need to find x ("y=1/5x+81 models his score after studying for x minutes.")

Initial equation
\(y = \frac{1}{5}x + 81\)

Replace y with 90
\(90 = \frac{1}{5}x + 81\)

Find for x
\(90 - 81 = \frac{1}{5}x\)
\(9 = \frac{1}{5}x\)
\(5 * 9 = 5 * \frac{1}{5}x\)
\(45 = x\)

Therefore, Jonas needs 45 minutes to get 90 on his next test.

To find the average quarterly loads for the rest of the years, you can use the formula below:

Average Quarterly Load = Total Annual Load  4 For example, let's say the total annual load for Year 1 is 800.

To find the average quarterly loads for Year 1, we would divide 800 by 4 to get an average quarterly load of 200. Then, you can use this average quarterly load to find the seasonal indices for each quarter of each year.To find the seasonal index for a given quarter and year, you would divide the actual quarterly load by the average quarterly load for that year.

For example, let's say the actual load for Quarter 1, Year 1 is 240. To find the seasonal index for this quarter and year, we would divide 240 by 200 to get a seasonal index of 1.2. You would repeat this process for each quarter and year to find the seasonal indices for all quarters and years.

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We know the function is a sin wave

y = A sin ( bx+c) +d

A is the amplitude = ( max - min) /2 = ( 2- -2) /2 = 4/2 = 2

b is the period = 2 pi/ b = distance it repeates = 2pi / b = 4 so b = 2pi/4 = pi/2

c is the phase shift = c/b =0 since this is a sin wave and is 0 at 0 and goes up

d is the vertical shift and the wave is not shifted up or down but has a zero midline

y = 2 sin ( pi/2 x)

Answer:

d^2 - 16.

Step-by-step explanation:

First, let's apply the distributive property to both terms inside the parentheses:

(-d)(-d) + (-d)(-4) + 4(-d) + 4(-4)

Simplifying each term, we get:

d^2 + 4d - 4d - 16

Now, let's combine like terms:

d^2 + 0d - 16

Finally, we can simplify further:

d^2 - 16

So, the product of (-d + 4)(-d - 4) is d^2 - 16.

The Square Root of Numbers.

The correct answer for the square root of 64 is 8 or -8 (option A)

If PQ = 18,  OP is equal to 72.

In a dilation, the ratio of corresponding lengths is equal to the scale factor. So, we have:

OP / PQ = scale factor

Substituting the given values, we have:

OP / 18 = 4

To find OP, we can multiply both sides of the equation by 18:

OP = 4 * 18

OP = 72

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The values of x for which the function f(x) = x³ + 3x² - 9x + 7 is increasing are (-∞, -3) and (1, +∞).

To find the values of x for which the function f(x) = x³ + 3x² - 9x + 7 is increasing, we need to take the derivative of the function and determine where the derivative is positive.

f(x) = x³ + 3x² - 9x + 7

f'(x) = 3x² + 6x - 9

To find where f(x) is increasing, we need to find the values of x where f'(x) > 0.

3x² + 6x - 9 > 0

Simplifying this inequality, we get

x² + 2x - 3 > 0

Factoring the left side of the inequality, we get

(x + 3)(x - 1) > 0

The critical points of f(x) occur when f'(x) = 0 or when the denominator of f'(x) is undefined. The denominator of f'(x) is always defined, so we only need to find where f'(x) = 0

3x² + 6x - 9 = 0

Dividing both sides by 3, we get

x² + 2x - 3 = 0

Factoring the left side of the equation, we get

(x + 3)(x - 1) = 0

So the critical points of f(x) are x = -3 and x = 1.

Now we can use a sign chart to determine the intervals where f'(x) > 0.

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The given question is incomplete, the complete question is:

What are all values of x for which the function f is defined by f(x)= x³ +3x² -9x +7 is increasing?

Answer:

y = 30

Step-by-step explanation:

y ∝ 1/x

y = k/x     →         y = 60/x

12 = k/5               y = 60/2

60 = k                 y = 30

I hope this helped you :)

Answer:

oh, well, sorry

Step-by-step explanation:

Answer:

1/3

Step-by-step explanation:

Slope is rise over run.

The derivative dy/dx of the equation ysin(x^2) = xsin(y^2) is given by (sin(y^2) - ycos(x^2)2x) / (sin(x^2) - 2yxcos(y^2)).

In the given equation, y and x are both variables, and y is implicitly defined as a function of x. To find dy/dx, we differentiate each term using the chain rule and product rule as necessary.

Differentiating the left-hand side of the equation, we apply the product rule to ysin(x^2). The derivative of ysin(x^2) with respect to x is dy/dxsin(x^2) + ycos(x^2)*2x.

Differentiating the right-hand side of the equation, we apply the product rule to xsin(y^2). The derivative of xsin(y^2) with respect to x is sin(y^2) + x*cos(y^2)2ydy/dx.

Now we have two expression for the derivative of the left and right sides of the equation. To isolate dy/dx, we can rearrange the terms and solve for it.

Taking the derivative of ysin(x^2) = xsin(y^2) with respect to x using implicit differentiation yields:
dy/dxsin(x^2) + ycos(x^2)2x = sin(y^2) + xcos(y^2)2ydy/dx.

By rearranging the terms, we can solve for dy/dx:
dy/dx * (sin(x^2) - 2yxcos(y^2)) = sin(y^2) - y*cos(x^2)*2x.

Finally, we can obtain the value of dy/dx by dividing both sides by (sin(x^2) - 2yxcos(y^2)):
dy/dx = (sin(y^2) - ycos(x^2)2x) / (sin(x^2) - 2yxcos(y^2)).

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The parallel line has an equation of y = 2x - 21

The equation is given as

y = 2x + 3

The equation of a line can be represented as

y = mx + c

Where

slope = m

By comparing the equations, we have:

m = 2

The slopes of parallel lines are equal

This means that the slope of the other line is 2

i.e. m = 2

Recall that:

The equation of a line can be represented as

y = mx + c

Where

slope = m = 2

Also, we have

(x, y) = (6, -9)

So, we have

-9 = 2 * 6 + c

This gives

c = -9 - 12

Evaluate

c = -21

So, we have

y = 2x - 21

Hence, the equation of the parallel line is y = 2x - 21

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Answer:

a because it is the one that makes the most sense

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Answer:

18 cm^2

Step-by-step explanation:

The legs of a right triangle are the base and height of the triangle.

Since C is a right angle, AB is the hypotenuse.

AC and BC are the legs and the base and height.

sin 75 = BC/12

BC = 12 sin 75

cos 75 = AC/12

AC = 12 cos 75

area = bh/2 = (12 sin 75)(12 cos 75)/2

area = 18 cm^2

Answer:

20

Step-by-step explanation:

240 divided by 12 = 20

Answer:

$205

Step-by-step explanation:

20+15+10+15+25+10+15+22+18+15+20+20= 205

When the eccentricity becomes zero, the ellipse becomes a circle.

The eccentricity of an ellipse is a measure of how much it deviates from a circular shape. When eccentricity is zero, it means that the distance between the foci is zero and the ellipse becomes a circle.

A circle is a special case of an ellipse in which the eccentricity is zero. In a circle, all points on the perimeter are the same distance from the center. The eccentricity of a circle is always zero because the distance between the two foci is zero. As a result, a circle can be seen as an ellipse with an eccentricity of zero.In summary, when the eccentricity becomes zero, the ellipse becomes a circle.

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The appropriate difference test for Principal Jones to use when the population standard deviation is unknown and the data is measured on an interval scale is a single-sample t-test (option c).

This test is suitable because it allows for inference about the population mean based on a sample mean when the population standard deviation is not known. The t-test takes into account the sample size and the sample standard deviation, providing a more accurate estimate of the population mean.

In contrast, a chi-square goodness-of-fit test is used to analyze categorical data, a single-sample z test assumes knowledge of the population standard deviation, and a between-subjects ANOVA is used to compare means across multiple groups. The correct option is c.

The complete question is:

Principal Jones collects data on how students in her school performed on a standardized test that is measured on an interval scale. If the population standard deviation is not known, the appropriate difference test for Principal Jones to use is:

a) a chi-square goodness-of-fit test

b) a single-sample z test

c) a single-sample t test

d) a between-subjects ANOVA

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Answer:

11 1/2 miles per hour is the answer I believe

ANSWER

1.08p = t

x = m/4

V = 12s^2

EXPLANATION

The proportional relationship between the quantity y and the quantity x has a constant of proportionality k and is expressed by the equation y = kx. If the equation can be rewritten in other forms as above, it is proportional.

Equation 1.

120 - x = L.

This cannot be rewritten as y = kx

Equation 2:

1.08p = t

This can be rewritten as y = kx

Equation 3

x = m/4

This can be rewritten as y = kx

Equation 4

V = 12s^2

This can be rewritten as y = kx

Hence, 1.08p = t, x = m/4 and V = 12s^2 equations represent proportional relationships.

Answer:

y=21

Step-by-step explanation:

y= 9 cos x =3 so y=3 when x=1 on the base level so if x=7 would be x=1 on the base level * 7 then y=3 on the base level * 7 would be y = 21

Answer:

No

Step-by-step explanation:

No, because s is less then 2. 7 is not less then 2.

‘Hope that helps! :)

Answer:

no

Step-by-step explanation:

s<2

s=7

7>2

Using the second derivative tests, we can determine the intervals of concavity for the function y = -2x³ - 6x² and find the points of inflection. We can then sketch the graph with this information.

To determine the intervals of concavity, we need to find the second derivative of the function. Let's start by finding the first derivative of y = -2x³ - 6x².

The first derivative is dy/dx = -6x² - 12x. To find the second derivative, we differentiate the first derivative with respect to x.

Taking the derivative of the first derivative, we get d²y/dx² = -12x - 12.

To find the intervals of concavity, we need to determine where the second derivative is positive (concave up) or negative (concave down).

Setting -12x - 12 equal to zero and solving for x, we find x = -1.

By choosing test points within intervals on either side of x = -1, we can determine the concavity of the function. For example, if we plug in x = -2 into the second derivative, we get a positive value, indicating concave up. Similarly, if we plug in x = 0, we get a negative value, indicating concave down.

Next, to find the points of inflection, we set the second derivative equal to zero and solve for x.

-12x - 12 = 0

-12x = 12

x = -1

So, x = -1 is a potential point of inflection. To confirm if it is a point of inflection, we can check the concavity of the function around this point.

Finally, armed with the intervals of concavity and the points of inflection, we can sketch the graph of y = -2x³ - 6x², indicating the concave up and concave down intervals and the point of inflection at x = -1.

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Answer:

3 x³ + 5x²

Step-by-step explanation:

that is the procedure above

Based on the given information, we know that the medium-sized jet has a fuselage diameter of 3.8 meters and a loaded mass of 85,000 kilograms. The drag on the airplane is primarily due to the cylindrical shape of the fuselage, and its aerodynamic shaping gives it a drag coefficient of 0.37.

To calculate the drag force on the airplane, we can use the formula:

Drag Force = 1/2 x Density x Velocity^2 x Surface Area x Drag Coefficient

The surface area of a cylinder is given by:

Surface Area = 2 x π x (diameter/2) x length

Assuming a length of 30 meters for the fuselage, we can calculate the surface area as:

Surface Area = 2 x π x (3.8/2) x 30 = 426.43 square meters

Using the given drag coefficient of 0.37 and assuming a cruising speed of 800 km/h (or 222.22 m/s), we can calculate the drag force as:

Drag Force = 1/2 x 1.225 kg/m^3 x (222.22 m/s)^2 x 426.43 m^2 x 0.37
Drag Force = 5,641,613 Newtons

Therefore, the drag force on the medium-sized jet is approximately 5.64 million Newtons. This drag force must be overcome by the jet's engines to maintain its cruising speed.

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Answer:24 kids

Step-by-step explanation: a dozen is equal to 12 so 12+12=24