How can the graph of f(x) = 1/(- x) - 9 be obtained from the graph of y = 1/x

The number of strings of three decimal digits that do not contain the same digit three times is 980.

We are to determine how many strings of three decimal digits do not contain the same digit three times.There are ten decimal digits, 0 to 9.

Each digit has to be chosen from these ten digits.

Each digit can be repeated twice or none at all. But it can't be repeated three times.

10 such choices, namely 000, 111, 222, 333, 444, 555, 666, 777, 888, and 999.

The total number of strings of three decimal digits that do not contain the same digit three times is the difference between the total number of all possible strings of three decimal digits and the number of strings of three decimal digits that contain the same digit three times.

The number of all possible strings of three decimal digits is 10 x 10 x 10 = 1000.

Therefore, the number of strings of three decimal digits that do not contain the same digit three times is:1000 – 10 = 990.But we must not include the ten strings containing only one digit three times.

Therefore, the number of strings of three decimal digits that do not contain the same digit three times is 990 – 10 = 980.

Therefore, there are 980 strings of three decimal digits that do not contain the same digit three times.

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Answer:

26.25 bottles

Step-by-step explanation:

A flower garden in the form of trapezoid is shown. The length of longer base is labeled 18 feet, shorter base is 15 feet, height is 4 feet, and one leg is 5 feet.

Formula for perimeter of a trapezoid = Side a + side b + length a + length b

For the trapezium shown, its perimeter step 1,

we have to find the missing length

Length a

We are given height = 4 feet

Length of the longer base = 18 feet

Length of the shorter base = 15 feet

Different would give us the base of the right angle triangle

= 18 - 15 = 3 feet

Using Pythagoras Theorem we can find the side a = c

a² + b² = c²

3² + 4² = c²

9 + 16 = c²

c = √25

c = 5 feet

Hence side a = 5 feet

Perimeter of the Trapezoid shown =

18 feet + 15 feet + 5 feet + 5 feet

= 38 feet.

From the question,

You need two bottles of fertilizer to treat the flower garden shown. How many bottles do you need to treat a similar garden with a perimeter of 105 feet

Hence:

38 feet = 2 bottles

105 feet = x bottles

Cross y

= 38 × x = 105 × 2

= 38x = 105 × 2

x = 105 × 2/38

x = 26.25 bottles

26.25 bottles of fertilizer is needed to treat the garden with a perimeter of 105

Answer:

3x+4

Step-by-step explanation:

The algebraic expression will be :  3x + 4

An expression built up from integer constants , variables and algebraic operations .

Let the number be : x

now , in the algebraic expression for 4 more then 3 times a number

First we need to make the number 3 time  = 3x

then in that expression we need to add 4 , we get = 3x+ 4

The algebraic expression will be :  3x + 4

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Answer:

y=5x/6-10/6

y=5x/6-5/3 ( simplified)

Step-by-step explanation:

5x-6y=10

slope intercept form :

-6y=-5x+10

y=-5x/-6 +10/-6

y=5x/6-10/6

y=5x/6-5/3

The examples of SSS similarity theorem (i.e If all the three sides of a triangle are in proportion to the three sides of another one) are ∆ABC is similar ∆DEF and one large triangle is similar to smaller one as seen in above figure.

SSS Triangle Similarity Examples : 1) How can you use the SSS similarity criterion to show that the following triangles are similar?

Only non-zero angles are specified. SSA is not a measure of triangle similarity, so we cannot say that these triangles are similar by SSA. However, since they are right triangles, you can use the Pythagorean theorem to find the third side of any triangle.

=> x² = 45² - 36² = 2025 - 1296 = 729

=> x = √729 = 27

=> x² = 15² - 12² = 225 - 144 = 81

=> x =√81 = 9

All three pairs of sides are proportional in ratio 3. Therefore, triangles are more similar to SSS~.

2) Are the triangles (that is, ΔABC and ΔDEF) similar?

All triangles have the same three sides. The ratio between each pair of sides is 4x/x = 4. The triangles through SSS~ are similar because the three pairs of sides are proportional.

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Answer:

Height of the kite = 86.60 meter (Approx)

Step-by-step explanation:

The angle of elevation to see a kite from a stone lying to the ground is 60 degrees. If a thread is tied with a kite and a stone, then that thread is 100 meters long, find the height of the kite.

Given:

Length of thread = 100 meter

Angle of elevation = 60°

Find:

Height of the kite.

Computation:

Using trigonometry application:

Height of the kite / Length of thread = Sin 60°

Height of the kite / 100 = √3 / 2

Height of the kite = [√3 / 2]100

Height of the kite = 50√3

Height of the kite = 86.60 meter (Approx)

The average total cost can be found by dividing the total cost by the quantity produced. In this case, the total cost function is given as C = 90 + 35Q + 25Q^2 + 10Q^3, and we want to find the average total cost when Q = 2.

To find the average total cost, we need to calculate the total cost when Q = 2. Plugging Q = 2 into the cost function, we get:
C = 90 + 35(2) + 25(2^2) + 10(2^3)
C = 90 + 70 + 100 + 80
C = 340

Next, we divide the total cost by the quantity produced:
Average Total Cost = Total Cost / Quantity
Average Total Cost = 340 / 2
Average Total Cost = 170

Therefore, the value of average total cost when Q = 2 is $170.

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We need to know about perimeter to solve the problem.The width of the box is 6.5 feet.

Perimeter of a rectangle is the measure of the total length and width of the rectangle. In the question it is said that Ramon wraps a ribbon around the length and width of a rectangular box. The length of the box is 1 foot, the total length of ribbon used is 15 feet, we need to find the width of the box.

perimeter=2(l+b) where l is the length and b is the width

15=2(l+b)

15=2(1+b)

15-2=2b

b=13/2=6.5 feet

Therefore the width of the box is 6.5 feet.

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Answer:

401.22

Step-by-step explanation:

Answer: 5n^2−2n+r+7

Step-by-step explanation:

Using the Laplace transform, the value of y' + y = (t − 1), y(0) = 5 is y(t) = 5e ^ -t + u (t - 1)e^(1-t)

Laplace rework is an critical rework approach that is in particular useful in fixing linear normal equations. It unearths very huge applications in  regions of physics, electrical engineering, control optics, arithmetic and sign processing.

y' + y = (t − 1)

y (0) = 5

Taking the Laplace transformation of the differential equation

⇒sY(s) - y (0) + Y(s) = e-s

⇒(s + 1)Y(s) = (5+ e^-s)/s + 1

⇒y(t) = L^-1{5/s+1} + {e ^-s/s + 1}

⇒y(t) = 5 e^-t + u(t -1)e^1-t

The Laplace remodel method, the feature within the time area is transformed to a Laplace characteristic within the frequency domain. This Laplace feature will be inside the shape of an algebraic equation and it can be solved easily.

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Based on the given information, we can conclude that the spaced schedule for giving rest is more effective in reducing errors compared to the massed schedule.

This is supported by the mean of 26 errors in the spaced schedule, which is lower than the mean of 36 errors in the massed schedule. Additionally, the obtained F value of 4.21 is greater than the critical F value at the 0.05 level of significance, indicating that there is a significant difference between the two schedules. Therefore, we reject the null hypothesis and accept the alternative hypothesis that the spaced schedule is more effective in reducing errors.

Based on the given information, you conducted a study comparing two rest schedules: massed schedule and spaced schedule. You obtained the following results:

- Spaced schedule: 20 observations, mean of 26 errors
- Massed schedule: 14 observations, mean of 36 errors

You performed an F-test with an alpha level of 0.05 and obtained an F-value of 4.21. To determine the appropriate conclusion, you would need to compare the F-value with the critical F-value for the given degrees of freedom and alpha level. Unfortunately, the critical F-value is not provided in your question.

However, if your obtained F-value (4.21) is greater than the critical F-value at α = 0.05, then you would reject the null hypothesis and conclude that there is a significant difference between the massed and spaced rest schedules in terms of the number of errors made. If the obtained F-value is smaller than the critical F-value, then you would fail to reject the null hypothesis and not conclude a significant difference between the two schedules.

Please check the critical F-value for your specific test and degrees of freedom, and compare it to your obtained F-value (4.21) to draw an appropriate conclusion.

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Answer:

umef leaf ninja the frog held a

Step-by-step explanation:

6-11a>-49

-11a>-49-6

-11a>-55

a<5.

Now, according to the question, if it is

W = {0,1,2,3,4}

N = {1,2,3,4}

Z = {...,-2,-1,0,1,2,3,4}

5a+10≥-35

5a≥-35-10

5a≥-45

a≥-9.

Now, according to the question, if it is

W = {-9,-8,-7,-6,-5,-4,-3,-2,-1,01,2,3...}

Z = {-9,-8,-7,-6,-5,-4,-3,-2,-1,01,2,3...}

Now, according to your domain you will do it .

hope this helps you.

The basic function equivalent to the piecewise-defined function f(x) = x if x ≥ 0 and -x if x < 0 is f(x) = |x|, which represents the absolute value of x.

The given piecewise-defined function f(x) has different expressions for different intervals. For x greater than or equal to zero, f(x) takes the value of x. For x less than zero, f(x) is equal to -x. We need to find a basic function that captures this behavior.

Among the options provided, f(x) = |x| is equivalent to the given piecewise function. The absolute value function, denoted by |x|, returns the positive value of x regardless of its sign. When x is non-negative, |x| equals x, and when x is negative, |x| is equal to -x, mirroring the conditions of the piecewise-defined function.

The function f(x) = |x| represents the absolute value of x and matches the behavior of the given piecewise-defined function, making it the equivalent basic function.

In summary, the basic function equivalent to the piecewise-defined function f(x) = x if x ≥ 0 and -x if x < 0 is f(x) = |x|, which represents the absolute value of x.

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Answer:

.

Step-by-step explanation:

The equation is

y = 200+50x

This is not a proportional relationship because it does not go through the origin

If x=0, y does not equal 0

Answer:

p=-1/2

Step-by-step explanation:

4(4p+6)=16

4p+6=4

4p=4-6

4p=-2

P=-2/4

p=-1/2

Answer:

18.5

Step-by-step explanation:

The length of fringe Sharon needs to purchase is: 16 feet

If Sharon gets a new bedsheet of 1.25 feet longer, she will need a new length of fringe of: 18.5 feet

Recall:

Perimeter of a rectangular = 2(length + width)

Given the following:

The length of fringe Sharon will need to purchase = perimeter of Sharon's rectangular bedspread

Perimeter = 2(3 + 5) = 16 feet

For a new bedspread that is 1.25 feet longer, she would get the following length of fringe:

Length = 3 + 1.25 = 4.25 feet

Width = 5 feet

New Perimeter = 2(4.25 + 5) = 18.5 feet

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Answer:

m

=

0.8

¯

3

Step-by-step explanation:

The perimeter of the rectangle is 78 cm. 1. A diagonal path is made across a square field that is 30 meters on a side.

To find the length of the path, we can use the Pythagorean theorem. In a square, the diagonal is the hypotenuse of a right triangle formed by two sides of the square.

Let's denote the length of the path as "d". We have a right triangle with sides of length 30 meters. By the Pythagorean theorem, we can write:

d^2 = 30^2 + 30^2

d^2 = 900 + 900

d^2 = 1800

Taking the square root of both sides, we get:

d = √1800

d ≈ 42.43 meters

Therefore, the length of the diagonal path is approximately 42.43 meters.

2. A tent is 3 meters high at the center. A rope 6 meters long comes to the top of the tent and is fastened to the ground. We need to find how far from the center of the tent the rope is fastened.

Let's denote the distance from the center of the tent to the point where the rope is fastened as "x". We have a right triangle formed by the height of the tent (3 meters), the rope (6 meters), and the distance from the center to the fastening point (x meters).

By the Pythagorean theorem, we can write:

x^2 + 3^2 = 6^2

x^2 + 9 = 36

x^2 = 36 - 9

x^2 = 27

Taking the square root of both sides, we get:

x = √27

x ≈ 5.20 meters

Therefore, the rope is fastened approximately 5.20 meters from the center of the tent.

3. The diagonal of a rectangle is 25 cm long. If its width is 17 cm less than its length, we need to find the perimeter of the rectangle.

Let's denote the length of the rectangle as "L" and the width as "W". We are given that the diagonal is 25 cm, so we can form a right triangle with the length, width, and diagonal as its sides.

By the Pythagorean theorem, we can write:

L^2 + W^2 = 25^2

L^2 + W^2 = 625

We are also given that the width is 17 cm less than the length, so we can write:

W = L - 17

Substituting this into the previous equation, we get:

L^2 + (L - 17)^2 = 625

L^2 + L^2 - 34L + 289 = 625

2L^2 - 34L + 289 - 625 = 0

2L^2 - 34L - 336 = 0

We can solve this quadratic equation to find the value of L. Using factoring or the quadratic formula, we get:

(L - 28)(2L + 12) = 0

Setting each factor equal to zero, we have:

L - 28 = 0   or   2L + 12 = 0

Solving each equation, we get:

L = 28   or   L = -6

Since the length cannot be negative, we take L = 28.

Substituting this back into W = L - 17, we get:

W = 28 - 17

W = 11

Therefore, the length of the rectangle is 28 cm and the width is

11 cm.

To find the perimeter, we can use the formula P = 2L + 2W:

P = 2(28) + 2(11)

P = 56 + 22

P = 78 cm

Therefore, the perimeter of the rectangle is 78 cm.

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Answer:

35 answer

Step-by-step explanation:

I hope it help

Answer:

exact form:

1/4

decimal form:

0.25

116= 1

is correct

wieyrb;ewury b2e;qpwiybrq;wiy

Answer:

The answer is 82,472

Step-by-step explanation:

The nearest estimate of 208.4=208.

The nearest estimate of 396.51 is 396.5

So the product is 82,472

You can use multiplication to check your division answer this way.

In mathematics, multiplying means adding equal groups. The number of things in the group grows as we multiply. A multiplication problem includes the two factors and the product. In the multiplication problem, 6 9 = 54, the numbers 6 and 9 are factors, and 54 is the product.

Addition is one of the four basic arithmetic operations, the others being subtraction, multiplication, and division. When two whole numbers are added together, the total amount or sum of those values is obtained.

Division is one of the four basic operations of arithmetic, which are the methods by which numbers are combined to form new numbers. Addition, subtraction, and multiplication are the other operations.

If there is a remainder, the final subtraction result will be less than the divisor. If this is the case, the remainder is appended to the answer.

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This method can be helpful in catching errors made during the Division process or verifying that the answer obtained is indeed correct.

When dividing two numbers, sometimes there is a remainder. To check the answer to a division problem that has a remainder, you can use multiplication and addition.

Here are the steps to follow:

1. Divide the dividend (the number being divided) by the divisor (the number doing the dividing) and find the quotient (the result of the division) and the remainder.

2. Multiply the divisor by the quotient.

3. Add the remainder to the product obtained in step 2.

4. The result of step 3 should be equal to the dividend. If it is, then the answer is correct. If it is not, then there was an error in the division or in the check.

For example, let's say we want to check the division problem 45 ÷ 7. We get a quotient of 6 and a remainder of 3. To check if the answer is correct, we would follow these steps:

1. Divide 45 by 7 to get a quotient of 6 and a remainder of 3.

2. Multiply 7 by 6 to get 42.

3. Add the remainder of 3 to 42 to get 45.

4. Since the result of step 3 is equal to the dividend of 45, we can be confident that our answer is correct.

This method can be helpful in catching errors made during the division process or verifying that the answer obtained is indeed correct.

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The property of congruence that is used in the given proof is;

A) Transitive property of congruence

We are given that;

∠ABC ≅ ∠DEF and ∠DEF ≅ ∠GHI, then ∠ABC ≅ ∠GHI

Now, looking at the properties of congruence in the options, we can define them as follows;

1) The transitive property of congruence states that “ if two shapes are congruent to the third shape, then all the shapes are congruent to each other.

2) The symmetric property states that if one geometric shape is congruent to another, than the second shape is also congruent to the first.

3) Reflexive property of congruence is when a side is congruent to itself.

In this case, the best option from the definitions will be transitive property of congruence

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The required arc length of sector VW is 8\(\pi\).

Given that, in a circle U, radius  UV = 9 and  central angle of sector m∠VUW = 160°.

To find the arc length of sector VW, we can use the formula:

Arc length = (central angle / 360) x circumference of the circle.

First,  find the circumference of the circle by the  formula for the circumference of a circle is given by:

Circumference = 2 x \(\pi\) x radius.

Circumference = 2 x \(\pi\) x 9 = 18π.

Now, let's find the arc length of sector VW using the central angle of 160 degrees:

Arc length = (160/360) x 18π

Arc length = (4/9) * 18\(\pi\) = 8\(\pi\).

Therefore, the arc length of sector VW is 8\(\pi\).

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Answer:51273.816238

Step-by-step explanation:

Answer:

they have 490 to buy bean bags

If there is no discount, the amount they can buy is 490/40=12,25>10, so they will get a discount

call the bean bag is X we have: X*40*(100%-10%) ≤ 490

⇒X≤13,6

they can buy at most 13 bag and they will have left 490-40*13*90%=22

Step-by-step explanation:

a. State the decision rule. (Round the final answer to 3 decimal places.)

H0 is rejected (rejected or not rejected ) if t > 4.541 .

b. Compute the value of the test statistic. (Round the final answer to 3 decimal places.)

Test statistic: -1.698

c. What is your decision regarding the null hypothesis?

H0 should not be rejected ( be rejected or not be rejected ).

d. Determine the p-value. (Round the final answer to 4 decimal places.)

The p-value is 0.9059.

Given: The data for the last 4 days of the last month and the number of defective samples produced during the day and the afternoon shift.

Let us consider the day shift defective sample production column as x and the afternoon defective sample production as y respectively.

Here n is the total number of samples. So n = 4.

Let us consider d be the difference between the day and the afternoon defective samples.

Therefore the required table is:

Day     x       y       d = y - x     \(d^{2}\)

1          11      9            -2         4

2         12     10           -2         4

3         13     14             1          1

4         19     15           -4         16

Total                          -7         25

To solve the questions, we need to find the following:

First, we need to find the mean over the column d.

The formula of mean is given by

d⁻ = ∑\(\limits^n_i\)\(d_{i}\) / n

= -7 / 4 = -1.75

Second, we need to calculate the sample variable over d and it calculated by the formula:

\(s^{2}_{d}\) = \(\frac{1}{n-1}(\)∑\(\limits^n_id^{2}_{i} - \frac{1}{n} (\)∑\(\limits^n_id}_{i})^2)\)

= \(\frac{1}{4 - 1}(25 - \frac{(-7)}{4}^{2} )\)

= 4.25

Third, the sample standard deviation over d is calculated by the formula:

\(s_{d}\) = \(\sqrt{s^{2}_{d}}\)

= \(\sqrt{4.25}\)

= 2.06155 ≈ 2.0616

For the given study, the null hypothesis (\(H_{0}\)) is constructed in such a way that the population mean difference is less than or equal to zero. The alternative hypothesis (\(H_{a}\)) is that the population mean difference is greater than zero.

The null (\(H_{0}\)) and alternative (\(H_{a}\)) hypotheses are given as follows:

\(H_{0}\): μ\(_{d}\) ≤ 0

\(H_{a}\): μ\(_{d}\) > 0

Here, μ\(_{d}\) is the population mean difference

The degrees of freedom (df) is computed as follows:

df = n−1

= 4−1 = 3

Therefore, we have the necessary information to solve the given questions.  

a. The critical value is computed at α = 0.01 and df = 3 using statistical table for t-distribution. The critical value is 4.541. Decision rule is given as follows:

Decision rule: \(H_{0}\) is rejected if t > 4.541.

b. The test statistic (t) is

t = ( d⁻ - μ\(_{d}\) ) / \(\frac{s_{d}}{\sqrt{n} }\)

= \(\frac{-1.75 - 0}{\frac{2.0616}{\sqrt{4} } }\)

= -1.697711 ≈ -1.698

c. \(H_{0}\) should not be rejected because the test statistic(t) = −1.698 is not more than the critical value = 4.541

d. The p-value is calculated with the help of following tests

Left-tailed test: p-value = cdf(x)

Right-tailed test: p-value = 1 - cdf(x)

Two-tailed test: p-value = 2 * min{cdf(x) , 1 - cdf(x)}

For simplification MS Excel was used to obtain the p-value:

Excel command is "= 1 - T.DIST(-1.697711,3,TRUE)"

The p-value is  0.9059 .

Conclusion: Fail to reject \(H_{0}\) because the p-value is more than α = 0.01.

Therefore, there is no evidence to support the claim that more defects were produced in the afternoon shift.

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Disclaimer: The question is incomplete. The full question is mentioned below:

The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month.

Day                          1 2 3 4

Day shift                 11 12 13 19

Afternoon shift 9 10 14 15

At the 0.01 significance level, can we conclude there are more defects produced on the Afternoon shift?

a. State the decision rule. (Round the final answer to 3 decimal places.)

H0 is _____ (rejected or not rejected ) if t > _____ .

b. Compute the value of the test statistic. (Round the final answer to 3 decimal places.)

Test statistic : _____

c. What is your decision regarding the null hypothesis?

H0 should _____ ( be rejected or not be rejected ).

d. Determine the p-value. (Round the final answer to 4 decimal places.)

The p-value is _____.

Answer:

0.9675sq.cm

Step-by-step explanation:

Find a related diagram attached

Area of the shaded region = Area of rectangle - area of semicircle

Area of rectangle = 3cm * 1.5cm

Area of rectangle = 4.5sq.cm

Given

diameter of the semicircle = 3cm

area = πd²/8

Area of the semicircle = 3.14(3)²/8

Area of the semicircle = 3.5325sq.cm

Area of the shaded region = 4.5 - 3.5325

Area of the shaded region = 0.9675sq.cm