How can a position-time graph be used in order to determine the speed and direction of an object ?

Answers

Answer 1

Answer: by seeing how much the speed increasing

Explanation:


Related Questions

What does it mean for a hypothesis to be testable?
O A. It must be able to reject biased data.
O B. It must be supported by peer review.
O C. It must be able to be supported or refuted by data.
O D. It must be what the scientist is hoping is the result.

Answers

C. It must be able to be supported or fefuted by data

Answer:

The answer is C

Explanation:

Testable meaning experiments can be conducted to support or refute the hypothesis. This is done through data.

. What voltage is required to move 2mA through 0.5kΩ?mm DS m. M m m. Feed

Answers

Answer: The voltage required to move a current of 2mA through a resistor with a resistance of 0.5 kΩ can be calculated using Ohm's law, which states that the voltage across a resistor is equal to the current flowing through it multiplied by the resistance:V = I * RV = 2mA * 0.5 kΩV = 1VSo, the voltage required to move 2mA through 0.5 kΩ is 1 Volt.

if a person pulls on a cart to the right with a force of 10n and a second person pulls to the left with a force of 3n, what is the net force direction on the cart?

Answers

The net direction on the cart, if a person pulls on a cart to the right with a force of 10n and a second person pulls to the left with a force of 3n, is 7n to the right.

The net force direction can be determined by finding the net vector sum of the forces acting on it.

Since the first person pulled the cart to the right with a force of 10n,

Assuming the right direction as positive, this force can be represented as a vector ⇒(+)10n

Similarly, as the second person pulls the cart to the left, the force can be represented as a vector ⇒ (-)3n,

Net force = Net vector sum of the forces

                   =(+10n) + (-3n)

Net force = +7n

Thus, the net direction on the cart, if a person pulls on a cart to the right with a force of 10n and a second person pulls to the left with a force of 3n, is 7n to the right.

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Answer: 7n

Explanation:

For a group class project, students are building model roller coasters. Each roller coaster needs to begin at the top of the first hill, where a horizontal spring that is initially compressed 0.25 m will push a small car forward.

A hill with a compressed spring at the top. There is a car sitting against the compressed spring. The portion of the hill is vertically colored orange, the middle section is vertically colored yellow and the last section colored green.
Each group of students will choose a car and a spring to push the car and then build a track. The assignment is to make the car go 5.0 m/s when it reaches the bottom of the first hill. Four groups of students choose springs and build tracks as described in the table.

A 4 column table with 4 rows. The first column is labeled group with entries A, B, C, D. The second column is labeled car mass in kilograms with entries .75, .60, .55, .84. The third is labeled spring constant in newtons per meter with entries 65, 35, 40, 32. The last column is labeled hill height in meters with entries 1.2, .90, 1.1 , .95.
Which group’s roller coaster will most likely make the car travel closest to 5.0 m/s when it is at the bottom of the first hill?

A
B
C
D

Answers

The group that will make the car travel closest to 5 m/s when it is at the bottom of the first will is of:

Group C.

How to obtain the velocity for each car?

The velocity that each car will assume at the bottom of the hill is given by the equation presented as follows:

v = square root (2gh + kx²/m).

The parameters are given as follows:

g = 9.8 m/s is the acceleration relative to the gravity.h is the height of the hill.k is the spring constant.x = 0.25 represents the initial compression of the spring.m is the mass of the car.

The parameters are given by the table in this problem, hence the velocities of each car are given as follows:

Group A: v = square root(2 x 9.8 x 1.2 + (65 x 0.25²)/0.75) = 5.38 m/s.Group B: v = square root(2 x 9.8 x 0.9 + (35 x 0.25²)/0.6) = 4.61 m/s.Group C: v = square root(2 x 9.8 x 1.1 + (40 x 0.25²)/0.55) = 5.05 m/s. -> closest to 5 m/s.Group D: v = square root(2 x 9.8 x 0.95 + (32x 0.25²)/0.84) = 4.58 m/s.

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Answer: group C

Explanation:

a 500 kg car is moving at 28 m/s. the driver sees a barrier ahead. if the car takes 95 m to come to rest, what is the magnitude of the average force necessary to stop?

Answers

The driver sees a barrier ahead. if the car takes 95 m to come to rest, what is the magnitude of the average force necessary to stop66,666.67 N

To find the magnitude of the average force necessary to stop the car, we can use the equation:

Force = (mass × change in velocity) / time

The change in velocity is the initial velocity (28 m/s) since the car comes to rest, and the time is given as 95 m. Rearranging the equation, we have:

Force = (mass × (-28 m/s)) / 95 m

Substituting the mass of 500 kg and calculating, we find the magnitude of the average force necessary to stop the car is approximately 66,666.67 N.

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redshift-based estimates of the look-back time to distant galaxies based on a steady expansion rate have been

Answers

Redshift-based estimates of the look-back time to distant galaxies, assuming a steady expansion rate, have been a valuable tool in understanding the history and evolution of the universe. By studying the redshift of light emitted from distant galaxies, astronomers can infer the time it took for that light to reach us, providing insights into the past.

Redshift is a phenomenon where light from distant objects, such as galaxies, appears shifted towards longer wavelengths due to the expansion of the universe. The greater the redshift, the farther away the object is and the longer the light has traveled to reach us. Based on the assumption of a steady expansion rate, astronomers have been able to use redshift measurements to estimate the look-back time to distant galaxies.

By analyzing the redshift of the light from these galaxies, scientists can determine how much the universe has expanded since the light was emitted. This expansion can be used to calculate the time it took for the light to travel from the distant galaxy to Earth. These estimates provide a way to study the universe at different stages of its history, allowing us to observe and understand the evolution of galaxies and the universe as a whole.

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What is the gravitational force of attraction between two asteroids in space, each with a mass of 50,000 kg, separated
by a distance of 3800 m?

Answers

Answer:

1.16 x 10⁻⁸N

Explanation:

Given parameters:

Mass of the two asteroids  = 50000kg

Distance between the asteroids  = 3800m

Unknown:

Gravitational force between the two asteroids = ?

Solution:

To solve this problem, we apply the newton's law of universal gravitation:

  Fg  = \(\frac{G mass 1 x mass 2}{r^{2} }\)  

 G is the universal gravitation constant

 r is the distance between them

So;

       Fg  = \(\frac{6.67 x 10^{-11} x 50000 x 50000}{3800^{2} }\)   = 1.16 x 10⁻⁸N

In the sketch to the right, a long straight wire is in the plane of a rectangular conducting wire loop. The current in the straight wire is up. At some point the current in the straight wire starts to increase in magnitude. This increased current leads to an induced current in the wire loop. In which direction will the induced current in the wire loop be? Explain how you reached this conclusion. How would your answer be different if the wire loop was on the left side of the wire instead of the right side?

Answers

The direction of the induced current in the wire loop is anti-clockwise.

The direction of the induced current if the wire loop was on the left side of the wire is clockwise.

Lenz's law and the direction of the induced current are the key concepts needed to address this issue.

To determine the direction of the induced current under various circumstances, use Lenz's law.

The induced emf of the coil is proportional to the negative of the rate of change of magnetic flux, according to Faraday's law.

The following expression represents the typical emf that is generated in the coil during the course of the time period: \($$\varepsilon=-\frac{\Delta \Phi}{\Delta t}$$\)

Here, \($\varepsilon$\) is the average emf that is induced in the coil during the time interval and \($\Delta \Phi / \Delta t$\) is the rate of change of magnetic flux.

A magnetic field is induced in the rectangular loop as a result of the current in the wire. The plane is the intended target of this magnetic field.

As the current in the wire grows, the magnetic flux in the rectangular coil rises.

An emf and current are induced by Faraday's law.

Following is noted from Lenz's law:

The inwards growing flux is opposed by the generated current. Therefore, the induced current must flow counterclockwise in order to meet this.

When the rectangular loop is kept to the left of the wire, the magnetic flux will be directed outward.

If the wire loop was on the left side of the wire, the induced current would flow clockwise.

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In the sketch to the right, a long straight wire is in the plane of a rectangular conducting wire loop.

if a ray of light traveling in the liquid has an angle of incidence of 34.0 ∘ at the interface with respect to the normal, what angle does the refracted ray in the air make with the normal?

Answers

The angle that the refracted ray in the air makes with the normal is 36.37° or approximately 21.64°.

Explanation:-

When a ray of light traveling in the liquid has an angle of incidence of 34.0 ° at the interface with respect to the normal, the angle that the refracted ray in the air makes with the normal is 21.64°.

Explanation:

Given,

Angle of incidence of light ray in liquid, i = 34.0°

Speed of light in the liquid, v1 = 2.00 × 10⁸ m/s

Speed of light in air, v2 = 3.00 × 10⁸ m/s

Let the angle that the refracted ray in air makes with the normal be r.

Applying Snell's law of refraction, we have,

`n₁sin i = n₂sin r`

Where `n₁` and `n₂` are the refractive indices of the liquid and air respectively.

Therefore,

`sin r = (n₁ / n₂) × sin i`

We know that,

`n = c / v`

where `c` is the speed of light in vacuum, and `v` is the speed of light in the medium.

Substituting the values of speed of light in liquid and air, we get,

`n₁ = c / v1 = (3 × 10⁸) / (2 × 10⁸) = 1.5``n₂ = c / v2 = (3 × 10⁸) / (3 × 10⁸) = 1`

Hence,

`sin r = (n₁ / n₂) × sin i``sin r = 1.5 × sin 34.0°``sin r = 0.809`

Therefore,

`r = sin⁻¹ 0.809``r = 53.63°`

The angle that the refracted ray in the air makes with the normal = (90° - r)`= (90° - 53.63°)`= 36.37°

Therefore, the angle that the refracted ray in the air makes with the normal is 36.37° or approximately 21.64°.

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what is the diameter of an aluminum sphere with the same mass as 11 l of water? the densities of water and aluminum are 1000 kg/m3 and 2700 kg/m3 , respectively.

Answers

Diameter of the aluminum sphere is ∛ 7.77 m with the same mass as 11 l of water.

Mass of aluminum =11 L

Density of the aluminum=2700 kg/m³

Mass of water=11 L

Density of water=1000 kg/m³

Thickness is characterized as the mass per unit volume. In an article material is firmly pressed. This make sense of how firmly a material is stuffed together.

        Density= M/V

          V=M/density

           =  11 /2700 kg/m³= 4.07m³

The sphere's volume is the amount of space it occupies. This indicates how much space or air a sphere contained. The letter V stands for it. Diameter is the straight distance between the sides of the sphere. It is measured in cubic units and is denoted by d.

Putting the values into the sphere's volume expression,    

     V= π/6 .d³

   4.07 m³  = π/6 .d³

   d³ =4.07 m³ .6/3.14= 7.77 m³

   d= ∛7.77 m

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What is the mass of an object that has a weight of 110N ?

Answers

Weight (W) = 110 NAcceleration due to gravity (g) = 9.8 m/s^2Let the mass of the object be m.By using the formula, W = mg, we get,110 N = 9.8 m/s^2 × mor, m = 110 N ÷ 9.8 m/s^2or, m = 11.2 Kg

Answer:

The mass of the object is 11.2 Kg.

Hope you could get an idea from here.

Doubt clarification - use comment section.

The mass of an object that has a weight of 110 N is 11.2kg.

What is Weight?

The weight of an object is defined as the force that acts on the object due to gravity. It is a vector quantity in some cases such as when the force of gravity acts on an object but it is also a scalar quantity where the force of gravity has a magnitude.

Weight is the gravitational force of attraction on an object due to the presence of another heavy object, such as the Earth or the Moon. It is expressed by multiplying the mass by the gravitational acceleration.

In above case,

Weight (W) = 110 N

Acceleration due to gravity (g) = 9.8 m/s^2

Let the mass of the object be m.

By using the formula,

W = mg,

\(110 N = 9.8 m/s^2 *m\\m = 110 N/ 9.8 m/s^2\)

so, m = 11.2 Kg

Thus, the mass of an object that has a weight of 110 N is 11.2kg.

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Transfer Functions of Electrical Systems (Special assignmen 3) There are 4 possible types of transfer functions for electrical systems. 1) Voltage Gain H_V(s) Vi(s) Electrical System V.(s) 2) Transfer Admittance H_Y(s) Vi(s) + +1 Electrical System I.(s) 3) Current Gain H_I(s) L(S) (1) 4) Transfer Impedance H_Z(s) L(S) (1) Electrical System Electrical System V.(s) I.(s) R = 12.50, L= 4H, C = 0.01F R + Vi(t) L CT Vo(t) 1) Find Vc(s)/Vs(s). 2) Show the pole-zero map. 3) Find the response to Vs(t) = u(t)V. 4) Find the response to Vs(t) = o(t)V.

Answers

The transfer function is Vc(s)/Vs(s) = (R + 1/(sC)) / (sL + R + 1/(sC)), the pole-zero map includes poles at -R/L and zeros at -1/(sC), the response to Vs(t) = u(t)V can be calculated using inverse Laplace transform techniques and the response to Vs(t) = o(t)V can also be determined using inverse Laplace transform techniques.

To find Vc(s)/Vs(s), we need to consider the given electrical system with components R, L, and C. By applying Kirchhoff's laws and solving for the output voltage Vc(s) and input voltage Vs(s) in the Laplace domain, we can derive the transfer function as (R + 1/(sC)) / (sL + R + 1/(sC)).

The pole-zero map provides insights into the stability and behavior of the system. In this case, the transfer function has poles at -R/L, indicating a time constant associated with the system's dynamics. The transfer function also has zeros at -1/(sC), which affect the frequency response characteristics.

To find the response to Vs(t) = u(t)V, where u(t) represents the unit step function, we can apply inverse Laplace transform techniques to the transfer function Vc(s)/Vs(s). This will yield the time-domain response of the system to a step input.

Similarly, to find the response to Vs(t) = o(t)V, where o(t) represents the unit impulse function, we can use inverse Laplace transform techniques on the transfer function Vc(s)/Vs(s). This will give us the time-domain response of the system to an impulse input.

By calculating the inverse Laplace transforms of the transfer functions in cases 3) and 4), we can obtain the time-domain responses of the electrical system to the respective inputs.

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5. How will you separate water from petrol?

Answers

Answer:

by a seprating funnel or let it stand it will settle on its own

Explanation:

Answer:

How will you separate water from petrol?

Please help me i give 60 point i need help now

Please help me i give 60 point i need help now

Answers

Answer:

How many questions should be answered??

Need help please????????!!!!!!!!!!

Need help please????????!!!!!!!!!!

Answers

Answer:

Your education back ground

forces can be________. What phrase completes the sentence.
1.Pushes only
2.Pushes or pulls
3.Pulls only​

Answers

Answer:

pushes or pulls

Explanation:

hope this helps....

I sneezed on my iPad

Answers

Answer:

clean that off bro

Explanation:

u dont wanna give people that corona

Answer:

oh man i hate germs

Explanation:

A leftward force of 50 N is applied to an 8 kg
object to move it across a rough surface with a
leftward acceleration of 5 m/s/s. Determine the
gravitational force, normal force, frictional
force, net force, and the coefficient of friction
between the object and the surface.

Answers

A leftward force of 50 N is applied to an 8 kg object to move it across a rough surface with a leftward acceleration of 5 \(m/s^{2}\) , its

gravitational force = 78.4 N

normal force = 78.4 N

frictional force = 10 N rightward

net force =  40 N leftward

coefficient of friction = 0.128

given

force = 50 N

mass = 8 kg

acceleration = 5 \(m/s^{2}\)

gravitational force = mg = 8 * 9.8 = 78.4 N

normal force = mg = 78.4 N ( as N= mg )

- F (applied) + frictional force  = - F (net )

F (applied)  - fr = F (net )

50 - fr = mass * acceleration

50 - fr = 8 * 5

fr = 10 N

Fnet = ma = 8 * (-5) = -40 N

Frictional force = mu * N

10 = mu * 78.4

mu (coefficient of friction ) = 10 / 78.4 = 0.128

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HELP ASAP physics projectile motion, look at the picture

HELP ASAP physics projectile motion, look at the picture

Answers

The first answer is 0

do muscle and bone weigh more than fat

Answers

Answer: . You may have heard that muscle weighs more than fat. However, according to science, a pound of muscle and a pound of fat weigh the same. The difference between the two is density.

Explanation:

Muscle weighs more than fat. "In simple terms, a pound of muscle weighs the same as a pound of fat," Heimburger tells WebMD. "The difference is that muscle is much more dense than body fat. Therefore, a pound of muscle will take up much less room in your body than a pound of fat.

Are two atoms of the same element identical?

Answers

Answer:

Nope

Explanation:

No. Two atoms of the same chemical element are typically not identical. First of all, there is a range of possible states that the electrons of an atom can occupy. Two atoms of the same element can be different if their electrons are in different states.

Will give brainiest if right

Will give brainiest if right

Answers

The answer would be C

A 40kg dog is sitting on top of a hillside and has a potential energy of 1,568 J. What is the height of the hill side?

Answers

Answer:

39.2 m

Explanation:

The height of the hill side can be found by using the formula

\(h = \frac{p}{m} \\ \)

p is the potential energy

m is the mass

From the question we have

\(h = \frac{1568}{40} = \frac{196}{5} \\ \)

We have the final answer as

39.2 m

Hope this helps you

Answer: 4.0m

Explanation:

A 40kg dog is sitting on top of a hillside and has a potential energy of 1,568 J. What is the height

effects of gravitational force ​

Answers

Answer:

The force that propels a toddler down a slide. The force that causes the moon to revolve around the Earth. The force that keeps Jupiter's moons located around the planet. The force from the moon that causes the tides of the ocean.

Explanation:

the condition in which certain colors are diminished as depth increases is called:

Answers

The condition in which certain colors are diminished as depth increases is called color attenuation. This refers to a phenomenon where colors become less vibrant and fade as the distance between the observer and the object increases.

This happens due to the scattering of light by particles in the atmosphere, which reduces the intensity of the light and alters the color perception of the viewer.
As a result, the colors of objects that are far away appear less vivid and washed out, while those that are closer look brighter and more saturated. This effect is particularly noticeable in outdoor scenes where the distance between objects is significant.
The degree of color attenuation depends on the distance between the viewer and the object, the angle of incidence of the light, the quality of the atmosphere, and the presence of any obstructions that might block or reflect light.
Color attenuation is a common phenomenon in outdoor photography and can be used to create depth and dimension in images. Photographers often use color correction techniques to compensate for the loss of color and contrast that occurs when shooting at a distance.
In conclusion, color attenuation is the condition in which certain colors are diminished as depth increases. It is caused by the scattering of light by particles in the atmosphere, which reduces the intensity of light and alters the color perception of the viewer. This phenomenon is particularly noticeable in outdoor scenes and is commonly observed in photography.

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A biker begins to move from an initial speed of 0.0 m/sec to a final speed of 25 m/sec in 10 sec. what is the acceleration of the skater?

Answers

a=change in v/t

25/10

a=2.5 m/s ^2

is a solenoid a magnet or no ??​

Answers

Answer the term solenoid refers to a long, thin loop of wire, often wrapped around a metallic core, which produces a magnetic field when an electric current is passed through it. Solenoids are important because they can create controlled magnetic fields and can be used as electromagnets

I hope it is helpful

An air conditioner operating at steady state maintains a dwelling at 70oF on a day when the outside temperature is 90oF. If the rate of heat transfer into the dwelling through the walls and roof is 30,000 Btu/h, might a net power input to the air conditioner compressor of 3 hp be sufficient? If yes, determine the coefficient of performance. If no, determine the minimum theoretical power input, in hp.

Answers

30000 btuh /3413 btuh/kw. = 8.8 kw

8.8 kw/.746 kw/hp = 11.8 hp if COP is 1

11.8/3 hp (COP coefficient of performance) = 3.99 COP

>>>So yes a 3.0 hp compressor with a nominal COP of 4 will handle the 30,000 btuh load.

3.2 to 4.5 is expected COP range for an air cooled heat pump or a/c unit.

The power input of 3hP might be sufficient and the coefficient of performance will be "3.93".

According to the question,

In order to maintain the dwelling at 70°F with,

\(Q_{in} = 30000 \ Btu/h\)

The COP,

→ \(\beta \leq \ \beta_{max}\)

or,

→ \(\beta \leq \frac{T_c}{T_H-T_c}= \frac{530^{\circ} R}{(550-530)^{\circ}R}\)

                     \(= 26.5\)

or,

→ \(\frac{Q_{in}}{W_c} \leq 26.5\)

→  \(W_c \geq \frac{3000 \ Btu/h}{26.5}\times \frac{1 \ hP}{2545 \ Btu/h}\)

→  \(W_c \geq 0.445 \ hP\) (minimum required power)

hence,

The corresponding COP will be:

→ \(\beta = \frac{Q_c}{W}\)

      \(= \frac{30000}{3\times 2545}\)

      \(= 3.93\)

Thus the response above is correct.

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Astronomers will never directly observe the first few minutes of the universe because?

Answers

Astronomers will never directly observe the first few minutes of the universe because at that time the universe was actually opaque or too dark. There was the absence of photons and other important essentials of light formation.

In the later stages of the universe formation, when few elements essential for the light formation and transfer started appearing, the universe became too cold to allow the light to pass through, hence it still remained invisible.

Apart from the temperature being low at the time and the absence of photons, there were several other factors that made the universe quite invisible to astronomers at that time. some of the factors include the size of the universe and the energy formed by the galaxies throughout the different eras.

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Please help me! Yes, I know the quality SUCKS I have an old Android lol​

Please help me! Yes, I know the quality SUCKS I have an old Android lol

Answers

Answer:

top to 2\

next to top

then to up one

next to up

Explanation:

Mass: amount of matter in an object
Weight: downward pull on an object
Balance: tool used to measure mass
Scale: tool used to measure weight
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