how are compressions and rarefactions produced by the tuning fork?

The energy that is associated with the emission line is given as 2.97 x 10^-19 J

The fomula for the energy associated with an electromagnetic wave is given by the equation:

E = h*f

definition of the terms in the definition

we have E = energy

H is the plancks constant. This constant is 6.626 x 10^-34 J*s

F is the frequency

Since f = 4.47x10^14 s^-1.

we have to multiply the values that we have to get the Emission line

This is given as

E = (6.626 x 10^-34 J*s) * (4.47 x 10^14 s^-1)

E = 2.97 x 10^-19 J

Therefore, the energy associated with the emission line is 2.97 x 10^-19 Joules.

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This question involves the concept of binding energy.

The amount of energy released by this reaction is "a) 1.22 x 10¹³ m/s".

The amount of energy that is released during the radioactive decay of any element is known as binding energy. This can be given by using the following formula:

\(E=\Delta mc^2\)

where,

Therefore,

E = (1.35 x 10⁻⁴ kg)(3 x 10⁸ m/s)²

E = 1.22 x 10¹³ m/s

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Answer:

The highly unstable pure sodium or potassium wants to lose an electron, and this splits the water atom, producing a negatively charged hydroxide ion and hydrogen and forming an explosive gas that ignites.

Explanation:

Answer:

2:3:2

Explanation:

answer from VNese

Explanation:

So if V œ T, then V = kT ; if we solve for k under different conditions of volume and temperature......

\( \frac{v1}{t1} = \frac{v2}{t2} \)

temperature is measured in degrees Kelvin.

And

\( v2 = \frac{v1}{t1} \times t2 = \frac{275 . ml}{298 \: . \: k } \times 403 \: . \: k = ?\)

?mL

0.403 L is the new volume where the initial volume is 275 mL and the initial temperature is 273 K.

Gas laws relate to the pressure, volume, and temperature of a gas. Boyle's law—named for Robert Boyle—states that, at constant temperature, the pressure P of a gas varies inversely with its volume V, or PV = k, where k is a constant.

The relationship between volume and temperature is: \(\frac{V_1}{T_1} =\frac{V_2}{T_2}\) where \(V_1\)and \(T_1\) are the initial volumes and \(V_2\) and \(T_2\) are the final volumes.

\(\frac{V_1}{T_1} =\frac{V_2}{T_2}\)

Given data:

\(V_1 =\) 275 mL, \(T_1 =\) 0

\(V_2 =\) 275 mL, \(T_2 =\) 130

Putting all the values in the equation:

\(\frac{V_1}{T_1} =\frac{V_2}{T_2}\)

\(\frac{0.275}{273} =\frac{V_2}{403}\)

\(V_2 =\) 0.403 L

Hence, 0.403 L is the new volume.

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Answer:

Explanation:

The two electrons in the outer orbit, together with the other negatively charged electrons, repel each other and that make the diameter of the O^2- ion larger.

Answer:

The answer is D. Hydroelectric

Answer:

natural gas

Explanation:

The total volume of gas produced by the complete decomposition of 1.44 kg k g of ammonium nitrate is 33.5 L.

The decomposition reaction of ammonium nitrate is given by:

NH4NO3(s) → N2(g) + 2H2O(g)

From the balanced chemical equation, we can see that 1 mole of ammonium nitrate produces 1 mole of nitrogen gas and 2 moles of water vapor. The molar mass of NH4NO3 is 80.04 g/mol, so 1.44 kg of NH4NO3 is equal to 18 moles.

To find the volume of gas produced, we can use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to convert the temperature from Celsius to Kelvin:

T = 127°C + 273.15 = 400.15 K

Next, we need to convert the pressure from mmHg to atm:

747 mmHg / 760 mmHg/atm = 0.981 atm

Now we can plug in the values and solve for V:

V = nRT/P = (1 mole N2)(0.08206 L·atm/mol·K)(400.15 K)/0.981 atm

= 33.5 L

Therefore, the total volume of gas produced by the complete decomposition of 1.44 kg of ammonium nitrate at 127°C and 747 mmHg is 33.5 L.

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The total volume of gas produced by the complete decomposition of 1.44 kg of ammonium nitrate at 127°C and 747 mmHg is 960.4 L.

Explanation: To solve this problem, we need to use the ideal gas law, PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin. We can first find the number of moles of gas produced by calculating the amount of ammonium nitrate in moles (1.44 kg divided by the molar mass of NH4NO3), then multiplying by the stoichiometric ratio of gas produced per mole of ammonium nitrate (2 moles of gas per mole of NH4NO3).

Next, we can use the given temperature and pressure to convert the number of moles of gas into volume using the ideal gas law. It's important to note that the given temperature is in Celsius, so we need to convert it to Kelvin by adding 273.15. After plugging in the values and solving for V, we get a total volume of 960.4 L.

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The mass of the aqueous solution in grams is obtained by subtracting mass of the 10.0 mL graduated cylinder alone from  the mass of the cylinder + solution. Therefore mass of the solution is 2.951 g.

We have from the question, the following information;

Mass of empty 10.0 mL graduated cylinder to be 23.099 g

Mass of 10.0 mL graduated cylinder +  3.09 mL of solution to be 26.050g

Mass of aqueous solution in grams = mass of the cylinder + solution - mass of the 10.0 mL graduated  cylinder alone

= 26.050g - 23.099 g

= 2.951 g

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The major reaction pathway for the given reaction, which involves bromine (Br), potassium iodide (KI), and acetone as the solvent, is the S_N2 (bimolecular nucleophilic substitution) pathway. In this reaction, iodide ion (I-) from KI acts as a nucleophile and displaces the bromide ion (Br-) from the substrate. Acetone, as a polar aprotic solvent, helps stabilize the transition state and promotes the S_N2 mechanism. The S_N2 pathway is favored over E2, S_N1, and E1 due to the better nucleophilicity of the iodide ion and the solvent choice.

The major reaction pathway for the given reaction is the Sn2 mechanism. This is because the reaction is taking place in acetone, which is a polar aprotic solvent. This type of solvent favors the Sn2 mechanism as it helps to stabilize the transition state by solvating the nucleophile and leaving group. Additionally, the reagents used (Br and KI) are both good leaving groups, which also supports the Sn2 pathway. The E2 mechanism can be ruled out because there is no strong base present, and the Sn1 mechanism is unlikely because it requires a carbocation intermediate, which is not formed under these conditions.
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Answer:

True,When fluorine gas is put into contact with calcium metal at high temperatures, calcium fluoride powder is created in an exothermic reaction.

"Fog forms in a valley", a physical process called condensation occurs when a gas or vapour transforms into a liquid state.

On a chilly soda can, water gathers. As the air cools around the container, water vapor in the atmosphere reaches its dew point and condenses into liquid droplets. Condensation is the conversion of water vapor into liquid. On the outside of a chilly glass or container, water vapor condenses and turns into liquid water (sweat).

Aldol condensation, Knoevenagel condensation, Claisen condensation, and Dieckman condensation (intramolecular Claisen condensation) are a few examples of common condensations that produce alcohols as a by-product.

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Answer:

[He]2s2  2p1.

that is the answer have an amazing day. Remember your an amazing person for who you are.

When the two atoms form a covalent bond the energy is released to gain stability. Therefore, option (B) is correct.

A covalent bond can be described as a chemical bond that involves the sharing of electrons to create electron pairs between atoms. These shared electron pairs are bonding pairs.

For many molecules, the sharing of electrons permits each atom to gain the equivalent of a complete valence shell, corresponding to a stable electronic configuration.

Atomic orbitals have directional properties leading to different kinds of covalent bonds. Sigma bonds are known to be the strongest covalent bonds and are due to the head-on overlapping of orbitals. Pi (π) bonds are weaker due to sidewise overlaps between p (or d) orbitals.

When a covalent bond forms, then the energy is released and two atoms form a bond by sharing their electrons with the liberation of heat.

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Answer:

A flame test could help by seeing what things it could catch on fire from or the things that could happen with acids etc. I would test the medicine by asking someone who has had it in their life, asking doctors or I would maybe use it myself maybe. (I don’t know about c, sooo sorry)

Answer:

First one is true and the second select all of them

Explanation:

lemme know if it's correct

Answer:

Any group larger than hydrogen is more stable at the equatorial position. Thus, option D is correct.

Explanation:

The equatorial bonds of cyclohexane are those that extend from the perimeter of the ring.

When groups are axial, the dispersion forces between them are repulsive and thus unstable. There is generally less repulsion when any group larger than hydrogen is equatorial rather than axial and thus more stable.

When one ring substituent group is larger than the other, the larger group equatorial will be more stable due to steric and spacial reasons.

Thus option D is correct which is tertiary and the largest group of all.

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To assign formal charges to the atoms in a Lewis structure, you need to count the number of electrons around each atom and compare it to the number of electrons it would have in an isolated (neutral) atom of the same element.

In the hydrogen cyanide (HCN) molecule, nitrogen (N) is the central atom and has five electrons in its valence shell. Hydrogen (H) atoms each have one electron in their valence shell. To form a stable Lewis structure, N must have an octet of electrons (eight electrons in its valence shell), so it must share electrons with the hydrogen atoms.

Here's the calculation for each atom:

Nitrogen: In an isolated N atom, there would be 5 electrons in its valence shell. In the HCN molecule, N has 5 shared electrons and 8 electrons in total, giving it a formal charge of 0.

Hydrogen: In an isolated H atom, there would be 1 electron in its valence shell. In the HCN molecule, each H has 1 shared electron, giving it a formal charge of 0.

So, the Lewis structure of HCN has formal charges of 0 on all atoms, which means it is a neutral species

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Gases in ascending order of density at NH3, N2, Ar, and N2O4. When the temperature of a gas rises, its density rises as well..

By examining the four major gases you're monitoring for—oxygen (O2), carbon monoxide (CO), hydrogen sulfide (H2S), and methane (CH4)—a 4 gas monitor can help you protect your employees in any setting.

When there is more water vapor than the air can hold, clouds form. The water is what gives the cloud its visual appearance once the water vapour (gas) condenses to create minute water droplets (liquid). Due to their tiny size, these droplets float in the air.

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The root-mean-square (rms) speed of the molecules of a sample of N2 gas at a temperature of 32.9° C is approximately 448 m/s.

The root-mean-square speed (rms) of molecules in a sample of diatomic nitrogen (N2) gas at a temperature of 32.9° C is given as follows.

The formula for the rms speed of gas molecules is:

vrms = √3kT/m

Boltzmann's constant, denoted as k, has a value of 1.38 × 10−23 J/K.

T is the temperature in Kelvin, and

The mass of the gas molecules is represented by the variable m.

The root mean square (rms) speed of the gas molecules is denoted as v.

Using the provided values of the temperature, the molecular mass of nitrogen, and Boltzmann's constant, we have the following:

Temperature of N2 gas,

The temperature T, originally measured at 32.9°C, can be converted to 305.9 K by adding 273 to the Celsius value.

Mass of N2 molecules, m = 28 × 10−3 kg/mol

Using these values, we can now calculate the rms speed of the N2 molecules in the gas sample:

rms speed,

v = √3kT/m

= √(3 × 1.38 × 10−23 × 305.9)/(28 × 10−3)

= 448 m/s (approx.)

Therefore, the root-mean-square speed of the molecules of a sample of N2 gas at a temperature of 32.9° C is approximately 448 m/s.

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Answer:

To separate sand and table salt you would add water. Table salt dissolves in water leaving salt water and sand. The sand then will go through the process of filtration leaving salt water and sand separated.

Explanation:

Answer:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\(n = \frac{N}{L} \\ \)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

\(n = \frac{4.5 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 7.47508...\)

We have the final answer as

Hope this helps you

Yes, benzoyl peroxide and salicylic acid can be used together. When used together, these two ingredients can be very effective in treating acne-prone skin.

Benzoyl peroxide is a powerful antibacterial agent that helps to reduce the number of bacteria on the skin, while salicylic acid is a keratolytic agent, meaning it helps to break down dead skin cells and unclog pores. Together, these two ingredients work to reduce the number of bacteria on the skin, unclog pores, and reduce inflammation associated with acne. It is important to note that these two ingredients should not be used in a single product. Instead, they should be applied separately at different times of the day. For example, benzoyl peroxide should be applied in the morning and salicylic acid should be applied at night. Additionally, it is important to be mindful of the concentration of each ingredient, as using too much of either can be irritating and cause dryness. Overall, using benzoyl peroxide and salicylic acid together can be a very effective way to reduce acne and clear up blemishes.

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Answer:

just a few days later this morning and Video is a bit more than

Explanation:

free fire in a good place for me to do it all in a great time for

Answer:

108.32

Explanation:

dalton's law

Pgas1 = x1 * Ptotal

Pgas1 = (mole fraction of a gas) * Ptotal

Ptotal = (mole fraction of a gas) ÷ Pgas1

1 torr = 0.133 kpa kilopascal

A reaction to be spontaneous,overall cell potential must be positive.

(A)The metabolite which would spontaneously reduce oxaloacetate (OAA) is:

alpha-ketoglutarate

(B)The two half cell reactions are as follows:

Reduction half reaction:

Oxaloacetate + 2 H+ + 2 e- --> malate

Oxidation half reaction:

alpha-ketoglutarate --> Succinate + CO2 + 2 H+ + 2 e-

Overall resulting balanced reaction for the reduction of OAA :

Oxaloacetate +alpha-ketoglutarate --> malate + Succinate + CO2

(C)the standard reduction potential for the reaction chosen in (B):

+0.67-0.17 = +0.50 V

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To make 1 liter of a 10% NaCl solution from a solid stock, you will require the following materials and containers.MaterialsSolid NaClDistilled water1-Liter volumetric flask250-mL volumetric flask 2-beakersProcedureTo prepare 1 liter of a 10% NaCl solution, the following procedure should be followed:Measure out 100g of NaCl using a balance.

Measure the weight of an empty 250-mL volumetric flask.Add the NaCl to a 250-mL beaker and add a small amount of distilled water to it to dissolve the NaCl.Carefully pour the dissolved NaCl solution into the 250-mL volumetric flask. Add distilled water to the mark on the flask to make up the volume. Stopper the flask and invert it several times to mix the solution.Measure the weight of the 1-Liter volumetric flask.Add the 250-mL volumetric flask solution to a 1-Liter volumetric flask.Add distilled water to the mark on the flask to make up the volume.

Stopper the flask and invert it several times to mix the solution.The final volume of the solution will be 1 liter of a 10% NaCl solution.PrecautionsEnsure the NaCl has completely dissolved before adding more water to avoid making a less concentrated solution.Measure the weight of the volumetric flask before and after adding the solution to calculate the volume of solution that was added.Use distilled water to prepare the solution.

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