homeoffice buys a computer from hewlett-packard. the computer has a $1,220 list price with a 20% trade discount. freight charges are fob destination.a. What is the trade discount amount? Trade discount b. What is the net price of the computer? Net price

It would take Nick 15 hours to complete the task

To determine the value, we need to know that algebraic expressions are defined as expressions that are made up of terms, variables, coefficients, factors and constants.

From the information given, we have that;

Nick and Liv can complete the same task together in 5 hours

Now, let the time of Nick's work be x

So Live worked twice as fast = 2x

Equate the values, we have;

2x + x = 1/ 5

collect the like terms

3x = 1/5

divide by the coefficient

x = 1/15

Then, we have that Nick would work for 15 hours

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A high correlation is insufficient to establish causation on its own.

Answer:

A vesting period is the time an employee must work for an employer in order to own outright employee stock options, shares of company stock or employer contributions to a tax-advantaged retirement plan.

The most appropriate choice for Distance will be given by:

The ball takes \(3s\) to reach a height of \(45\) \(m\).

What is Distance?

The length of the path an object takes without taking into account the direction of motion of the object is known as distance.

If \(s\) is the speed of the object and \(t\) is the time, then

Distance = \(s \times t\)

Here,

\(H(t) = 30t - 5t^2\), \(t\) is the time in seconds

For finding the time taken by the ball to reach a height of \(45\)\(m\), we need to substitute \(H(t) = 45\)

Now putting \(H(t) = 45\)

\(45 = 30t - 5t^2\\5t^2 - 30t+45 = 0\\ 5(t^2 -6t + 9)=0\\t^2 -6t+9=0\\t^2-3t-3t+9=0\\t(t-3)-3(t-3)=0\\(t-3)(t-3)=0\\t-3 = 0\\t = 3s\)

So the ball takes \(3s\) to reach a height of \(45\) \(m\).

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Answer:

x = 2\(\sqrt{5}\)

Step-by-step explanation:

Since the 2 legs are congruent, both 6 then the triangle is isosceles.

The line from the vertex to the base is a perpendicular bisector, dividing the base into 2 parts of 4 units.

Using Pythagoras' identity in one of the right triangles.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² + 4² = 6²

x² + 16 = 36 ( subtract 16 from both sides )

x² = 20 ( take the square root of both sides )

x = \(\sqrt{20}\) = \(\sqrt{4(5)}\) = 2\(\sqrt{5}\)

Answer:

Therefore any set of data that satisfies the 5-Number summary: 16,18,22,26 and 28 can be represented with the box plot.

Step-by-step explanation:

Interpreting Box Plots

We use a box plot to present the 5-Number summary of a set of data.

The values contained in the 5-Number summary are:

In the box plot, the following rules apply:

Using these, we interpret the given box plot

A left whisker extends from 16 to 18, therefore:

The box extends from 18 to 26 and is divided into 2 parts by a vertical line segment at 22.

The right whisker extends from 26 to 28.

Therefore any set of data that satisfies the 5-Number summary: 16,18,22,26 and 28 can be represented with the box plot.

Box plot has boxes with some lines ( called whiskers ).

Box plot on the graphical level tells about 5 points:

There is starting whisker or left whisker denoting point minimum (Q0) and extends from there the line to Q1 ( first quartile).

Then the box starts which starts from Q1 and touched Q3. In the middle it passes through Q2 ( The median of the data ), and thus has a line in it.

At last, there is end whisker or right whisker denoting end quantile or Q4 (the maximum point).

Given data:

Left whisker extends from 16 to 18.

     Thus Q0 = 16

              Q1 = 18

Box plot starts from 18 and extends to 26, and is split by a vertical line segment at 22.

    Thus Q2 = 22

             Q3 = 26

The right whisker or end whisker extends from 26 to 28

    Thus Q4 = 28.

Thus the description of data is given as:

\(Q_0 = Minimum = 16\\Q_1 = First\: quartile = 18\\Q_2 = Second \:quartile = Median= 22\\Q_3 = Third\: quartile = 26\\Q_4 = Maximum = 28\\\)

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Answer:

the train's average rate of speed would be 57.8 mph

Step-by-step explanation:

Divide 1445 with 25 and then you get your answer

brainilest pls

anyway hope this helped have an awesome day bye byeee

Answer:

0.5125

Step-by-step explanation:

4.1 ÷ 4 = 1.025

1.025 = diameter

1.025 ÷ 2 = 0.5125

0.5125 = radius

Answer:

1: 3/1 also just 3

2: 0 also known as the origin

3: y=3x

Step-by-step explanation:

Answer: D

Step-by-step explanation:

Answer:

  9

Step-by-step explanation:

You want the length of the median of an isosceles trapezoid with sides in the ratios 2:1:1:1 and an area of 27√3 square units.

The area of an equilateral triangle is ...

  A = (√3/4)s² . . . . . s = side length

The area of the described figure (shown in the attachment) is that of 3 equilateral triangles. The side lengths of those can be found from ...

  A = 3·(√3/4)s²

  27√3 = (3/4)√3s²

  4/3(27) = s² = 36

  s = 6

The median is the average of the two base lengths:

  m = (1 + 2)/2 · s = 3/2(6)

  m = 9

The length of the median of the trapezoid is 9 units.

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Answer:

the slope is 5/8

Step-by-step explanation:

Answer:

1b 2a 3c

Step-by-step explanation:

Its hegarty right?

Answer:

  E, D, B, A, C

Step-by-step explanation:

Please report this incomplete question to your teacher. You should not have to put up with this nonsense.

__

A. (x, y) ⇒ (3x, y) . . . horizontal stretch by a factor of 3

B. (x, y) ⇒ (x+3, y) . . . translation 3 units right

C. (x, y) ⇒ (x, 3y) . . . vertical stretch by a factor of 3

D. (x, y) ⇒ (x, y+3) . . . translation 3 units up

E. (x, y) ⇒ (3x, 3y) . . . dilation with a scale factor of 3

96% confidence interval for the population mean life of light bulbs produced by the electrical firm to be between 747.63 and 812.37 hours. This can be answered by the concept of standard deviation.

To calculate the confidence interval, we first need to determine the standard error of the mean, which can be calculated using the formula:

Standard Error of Mean = (Standard Deviation of Population) / sqrt(Sample Size)

In this case, the standard deviation of the population is given as 40 hours, and the sample size is 30. Thus, the standard error of the mean can be calculated as:

Standard Error of Mean = 40 / sqrt(30) = 7.32

Next, we need to find the critical value of t for a 96% confidence level with 29 degrees of freedom (n-1). Using a t-distribution table or calculator, we find this to be 2.048.

Using these values, we can calculate the confidence interval using the formula:

Confidence Interval = Sample Mean +/- (Critical Value * Standard Error of Mean)

Substituting the given values, we get:

Confidence Interval = 780 +/- (2.048 * 7.32) = 780 +/- 15.02

Therefore, the 96% confidence interval for the population mean life of light bulbs produced by the electrical firm is between 747.63 and 812.37 hours. This means we can be 96% confident that the true mean life of all light bulbs produced by the firm falls within this interval.

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Answer:

It's A and C, 6x6x6 and 18

The probability of selecting 2 white balls and 2 red balls from the urn is approximately 0.412, which corresponds to option (d).

To solve this problem, we can use the hypergeometric distribution. The probability of selecting exactly k white balls and 4 - k red balls in a sample of 4 balls without replacement is given by:

P(k white balls) = [C(8,k) \(\times\) C(10,4-k)] / C(18,4)

where C(n,r) is the number of combinations of n things taken r at a time.

For the given problem, we want to find the probability of selecting 2 white balls and 2 red balls, so we substitute k = 2 into the formula:

P(2 white balls) = [C(8,2) \(\times\) C(10,2)] / C(18,4)

= [(28 \(\times\) 45)] / 3060

≈ 0.412

Therefore, the probability of selecting 2 white balls and 2 red balls from the urn is approximately 0.412, which corresponds to option (d).

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For the rational function r(x) = (x+1)(x-3)/(x+3)(x-7), the x-intercepts are found by setting the numerator equal to zero and solving for x:

(x + 1)(x - 3) = 0

This gives x=-1 and x=3 as the x-intercepts.

For the same function, the vertical asymptotes are found by setting the denominator equal to zero and solving for x:

(x + 3)(x - 7) = 0

This gives x=-3 and x=7 as the vertical asymptotes.

For the rational function r(x) = (x+1)(x-3)/(x+3)(x-6), the vertical asymptotes are found by setting the denominator equal to zero and solving for x:

(x + 3)(x - 6) = 0

This gives x=-3 and x=6 as the vertical asymptotes.

For the same function, there are no x-intercepts.

For the rational function r(x) = (x+1)(x-3)/(x+3)(x-4), the horizontal asymptote can be found by looking at the degrees of the numerator and denominator. Since the degree of the numerator is 2 and the degree of the denominator is 2, the horizontal asymptote is given by the ratio of the leading coefficients, which is 1/1=1. Therefore, the horizontal asymptote is y=1.

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Answer:

x=120 and y=60

Step-by-step explanation:

As we know, a straight line is 180 degrees.

To find x, you would do 180= 60 + x to get 120.

I forget how but I know y= 60 because its the same angle as 60 degrees.

1. x+12

2. x-8

3. 3*x

4. x^(2)+5

5. (x/2)+7

6. 4*(x+6)

7. (1/2)*x

8. 2x+8

9. x^(2)+3

10. (x/3)+12

Additional activity

1. 2-50

2.20/4=5

3.100-50=50

4.three times two then add to four equals ten

5. the diffrence of eight and four

Answer: Margo does 48 activities in 4 weeks.

Step-by-step explanation:

In the calendar,

Red dots represent homework, yellow dots represent work, and green dots represent practice.

On a typical week , she uses 5 red dots, 3 yellow dots, and 4 green dots.

That means , total activity he does in a week = 5+3+4=12

Then, total activities in 4 weeks = 4 x 12 = 48

Hence, Margo does 48 activities in 4 weeks.

Brahe's concept of the planetary system was most like that of the geocentric model

Brahe suggested a hybrid model that integrated parts of the heliocentric and geocentric systems based on his highly exact and accurate observations and measurements of planetary motion.

Brahe said that while the Sun orbited the Earth, the planets revolved around the Sun.

The Tychonic system was a theory that attempted to balance the planets' known motions with the widely held notion that the Earth was fixed.

Brahe's painstaking observations set the groundwork for our current comprehension of planetary motion, even though his model was subsequently supplanted by the heliocentric theory put forward by Copernicus and improved upon by Kepler.

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Answer:

the answer is (A).......

Answer:

47.21

Step-by-step explanation:

a=47.4

b=0.19

a – b

47.4 – 0.19

=47.21

Answer: 5 yards will be left over.

Step-by-step explanation:

8 * 7 = 56

so then you would minus 56 from 61 which equals 5.  Sorry if that's a weird way to get it but...

Therefore, the solution is,x(t) = e⁻²⁺(c₁ cos(6t) + c₂ sin(6t)) + (10/13)cos(8t) - (4/13)sin(8t), where lim x(t) = 0.

Given information:

Consider the initial value problem mx" + cx' + kx = F(t), x(0) = 0, x'(0) = 0 modeling the motion of a damped mass-spring system initially at rest and subjected to an applied force F(t), where the unit of force is the Newton (N).

Assume that m = 2 kilograms, c = 8 kilograms per second, k = 80 Newtons per meter, and F(t) = 80 cos(8t) Newtons.

The given differential equation is,mx" + cx' + kx = F(t)

Substitute the given values in the equation to get,m(²)/(²) + c()/() + kx = 80cos(8t)

When the system is at rest and an external force F(t) is applied, the general solution isx(t) = xh(t) + xp(t)

Here, xh(t) represents the homogeneous solution and xp(t) represents the particular solution.

Find the homogeneous solution of the equation as,m(²)/(²) + c()/() + kx = 0

We can find the characteristic equation as, ms² + cs + k = 0

Substitute the given values, m = 2 kilograms, c = 8 kilograms per second, and k = 80 Newtons per meter.

2s² + 8s + 80 = 0s² + 4s + 40 = 0 On solving the above equation, we get the roots as,s₁, s₂ = -2 ± 6i Since the roots are complex conjugates, the homogeneous solution is given by

               xh(t) = e⁻²⁺)(c₁ cos(6t) + c² sin(6t))

Where, c₁ and c₂ are constants.Find the particular solution: xp(t)To find the particular solution, we assume that the particular solution takes the form of the forcing function

               xp(t) = Acos(8t) + Bsin(8t)xp'(t)

                           = -8Asin(8t) + 8Bcos(8t)xp''(t)

                       = -64Acos(8t) - 64Bsin(8t)

Substitute xp(t), xp'(t), and xp''(t) in the given differential equation,m(²)/(²) + c()/() + kx

        = 80cos(8t)m(-64Acos(8t) - 64Bsin(8t)) + c(-8Asin(8t) + 8Bcos(8t)) + k(Acos(8t) + Bsin(8t))

                                 = 80cos(8t)

Substitute the given values for m, c, and k and equate the coefficients of cos(8t) and sin(8t) to solve for A and B-128A + 8B + 80A = 080B + 8A + 80B = 0

On solving the above equations, we get A = 10/13 and B = -4/13 Therefore, the particular solution is,xp(t) = (10/13)cos(8t) - (4/13)sin(8t)

Therefore, the general solution is,x(t) = xh(t) + xp(t) Substituting xh(t) and xp(t),x(t) = e^(-2t)(c1 cos(6t) + c2 sin(6t)) + (10/13)cos(8t) - (4/13)sin(8t)

The given function, x(t) is 0→[∞]0.The long-term behavior of the system (steady periodic solution) is,x(t) ≈ Xsp(t) = (10/13)cos(8t) - (4/13)sin(8t)

Therefore, the limit of x(t) as t → ∞ is zero. Hence,lim x(t) = 0

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The additive counterpart of given expressions are (2a+3b), -2a+2(-b+c), and -3(a+2b)+2c=0.

When two numbers may be added together or multiplied, regardless of the order in which they are entered, the result is said to be commutative. There are different formulas available for the conversion of multiplicative expressions to their additive counterparts.

a) The first expression is a²b³. This expression is written as aabbb. This is of the form ab and its corresponding additive counterpart is of the form a+b.

Then, a+a+b+b+b=2a+3b.

b) The second expression is a⁻²(b⁻¹c)². This expression is of the form a⁻¹ and its corresponding additive counterpart is of the form -a.

Then,

\(\begin{aligned}a^{-2}(b^{-1}c)^2&=a^{-1}a^{-1}(b^{-1}c)(b^{-1}c)\\&=-a-a-b+c-b+c\\&=-2a+2(-b+c)\end{aligned}\)

c) The third expression is (ab²)⁻³c²=e. This expression is first expanded as, (ab²)⁻¹(ab²)⁻¹(ab²)⁻¹c²=e. Using property, (xy)⁻¹=y⁻¹x⁻¹.

Then,

\(\begin{aligned}((b^2)^{-1}a^{-1})((b^2)^{-1}a^{-1})((b^2)^{-1}a^{-1})c^2&=e\\(b^{-2}a^{-1})(b^{-2}a^{-1})(b^{-2}a^{-1})c^2&=e\end{aligned}\)

Also, the additive identity to e is zero. And, aⁿ=na.

Then,

(-2b-a)+(-2b-a)+(-2b-a)+2c=0

Simplifying we get,

-3(a+2b)+2c=0.

The answers are  (2a+3b), -2a+2(-b+c), and -3(a+2b)+2c=0.

The complete question is -

Translate each of the following multiplicative expressions into its additive counterpart. assume that the operation is commutative

a. a²b³

b. a⁻²(b⁻¹c)²

c. (ab²)⁻³c²=e

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