Hey Everyone I was asking anyone can help with this problem it would really appreciated.

Answer:

Step-by-step explanation:

open the page below

Answer:

please read through the ten symbols of logic mathematics

Answer:

\(x = \left ( \dfrac{ \left (3 ^{\frac{2}{3} } + 1 \right ) ^2}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } =\dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } }\)

\(\dfrac{9 \cdot x + 10}{3} = \left ( \dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } } \right )^3 } = x^3\)

Therefore;

\(x = \sqrt[3]{\dfrac{9 \cdot x + 10}{3}}\)

Step-by-step explanation:

Given that we have;

\(x^2 - 2 = 3 ^{\frac{2}{3} } + 3 ^{-\frac{2}{3} }\)

\(x^2 = 3 ^{\frac{2}{3} } + 3 ^{-\frac{2}{3} } + 2 = \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } = 3 ^{-\frac{2}{3} } \times \left ( 3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} } \right )\)

\(x^2 = 3 ^{-\frac{2}{3} } \times \left ( 3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} } \right )\)

\(x = 3 ^{-\frac{1}{3} } \times \left ( 3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} } \right )^{\frac{1}{2} }\)

\(x = \sqrt{ \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } } = \left ( \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} }\)

\(x = \sqrt{ \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } } = \left ( \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } = \left ( \dfrac{3 ^{\frac{4}{3} } + 2 \times 3 ^{\frac{2}{3} } + 1}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} }\)

\(x = \sqrt{ \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } } = \left ( \dfrac{3 ^{\frac{4}{3} } + 2 \times 3 ^{\frac{2}{3} } + 1}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } = \left ( \dfrac{ \left (3 ^{\frac{2}{3} } + 1 \right ) ^2}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} }\)

\(x = \left ( \dfrac{ \left (3 ^{\frac{2}{3} } + 1 \right ) ^2}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } =\dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } }\)

\(\dfrac{9 \cdot x + 10}{3} = 3 \cdot x + \dfrac{10}{3} = 3 \times \dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } } +\dfrac{10}{3} = \dfrac{ 3 ^{\frac{5}{3} } + 3 }{3 ^{\frac{1}{3} } } + \dfrac{10}{3}= \dfrac{ 3 ^{\frac{7}{3} } + 3 ^{\frac{2}{3} }\times3+ 10 }{3 } } }\)

\(\dfrac{9 \cdot x + 10}{3} =\dfrac{ 3 ^{\frac{7}{3} } + 3 ^{\frac{2}{3} }\times3+ 10 }{3 } } } = \dfrac{ 3 ^{\frac{7}{3} } + 3 ^{\frac{5}{3} }+ 10 }{3 } } } = \left ( \dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } } \right )^3 } = x^3\)

Therefore;

\(x^3 = \dfrac{9 \cdot x + 10}{3}\)

\(x = \sqrt[3]{\dfrac{9 \cdot x + 10}{3}}\)

The required work done in stretching the spring from its natural length to 0.6 feet beyond its natural length is 0.18 foot-pounds.

Given data: Force required to hold the spring stretched = 2 pounds

Stretch beyond natural length = 0.4 feet

To find the work done to stretch beyond natural length to 0.6 feet beyond natural length.

Let's determine the work done in stretching the spring from its natural length to 0.6 feet beyond its natural length.

Step 1: Work done in stretching the spring from its natural length to 0.4 feet beyond its natural length is:

W1 = (1/2) k x1²

Where, k = force constant of the spring, x1 = stretch beyond natural length

W1 = (1/2) × Force × (Stretch beyond natural length)²

∴ W1 = (1/2) × 2 pounds × (0.4 feet)²

W1 = 0.16 foot-pounds.

Step 2: Work done in stretching the spring from 0.4 feet beyond its natural length to 0.6 feet beyond its natural length :

W2 = (1/2) k (x2² - x1²)

Where, k = force constant of the spring,x2 = Stretch beyond natural length to 0.6 feet beyond natural length,

x1 = Stretch beyond natural length

W2 = (1/2) × Force × (Stretch beyond natural length to 0.6 feet beyond natural length)² - (1/2) × Force × (Stretch beyond natural length)²

∴ W2 = (1/2) × 2 pounds × (0.6 feet - 0.4 feet)² - (1/2) × 2 pounds × (0.4 feet)²= (1/2) × 2 pounds × (0.2 feet)²

W2 = 0.02 foot-pounds.

The work done in stretching the spring from its natural length to 0.6 feet beyond its natural length is

W = W1 + W2

=> 0.16 + 0.02 = 0.18 foot-pounds.

Thus, the required work done in stretching the spring from its natural length to 0.6 feet beyond its natural length is 0.18 foot-pounds.

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Answer

5x+y=8

Step-by-step explanation:

\(y + 5x = 8\) is a standard form of equation.

What is standard form?

The standard form for linear equations in two variables is Ax+By=C. For example, 2x+3y=5 is a linear equation in standard form. If the equation is given in this form, finding both points of intersection (x and y) is quite easy. This form is also very useful for solving systems of two linear equations.

By some examples,we can understand the concept more easily.

Example -1,

\(2x + 3y = 2\) is a standard form of equation.

Example -2,

\(5x + 7y = 2\) is a standard form of equation.

Example -3,

\(5x = y - 5\) is not a standard form of equation.

Given equation is \(y = - 5x + 8....(1)\)

We want to find standard form for the given equation.

Now,

\(y = - 5x + 8\)

We are separating variable and constant part.

\(y + 5x = 8\)

According to rule,it is a standard form of equation.

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Answer:

Answers?

Step-by-step explanation:

A translation does NOT

-change the shape of the figure

-change the size of the figure

-change the angle of the figure

IT ONLY CHANGES THE LOCATION of the FIGURE!

Answer:

B isa the answer for me it might be wrong for you or switch them

Step-by-step explanation:

Recapturing a higher percent of marked alligators affects the estimated total population by making it high enough to support an accurate estimate.

This is referred to as the total number of species or organisms in an area at a given period of time.

Recapture rates are high enough to support an accurate estimate. The Lincoln-Peterson calculation tends to overestimate the population size, especially if the number of recaptures is small.

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The two equations that represent circles with a diameter of 12 units and a center that lies on the y-axis are:

(x - 4)² + y² = 36

(x + 6)² + y² = 144

(x - 4)² + y² = 36:

This equation represents a circle with center (4, 0) since the x-coordinate of the center is 4, indicating it lies on the y-axis. The radius of this circle is √36 = 6 units. Therefore, it satisfies the given conditions.

(x + 6)² + y² = 144:

This equation represents a circle with center (-6, 0) since the x-coordinate of the center is -6, indicating it lies on the y-axis. The radius of this circle is √144 = 12 units. Hence, it also satisfies the given conditions.

x² + (y - 3)² = 36:

This equation represents a circle with center (0, 3) since the y-coordinate of the center is 3, indicating it does not lie on the y-axis. Therefore, it does not meet the given conditions.

x² + (y + 8)² = 36:

This equation represents a circle with center (0, -8) since the y-coordinate of the center is -8, indicating it does not lie on the y-axis. Thus, it does not fulfill the given conditions.

x² + (y - 5)² = 6:

This equation represents a circle with center (0, 5) since the y-coordinate of the center is 5, indicating it does not lie on the y-axis. Hence, it does not meet the given conditions.

Based on this analysis, the equations that represent circles with a diameter of 12 units and a center that lies on the y-axis are options 1 and 2:

(x - 4)² + y² = 36

(x + 6)² + y² = 144.

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Based on the information, Paulo will need to find a larger mailer or use a different method to ship the plaque to the winner of the chess tournament.

The mailer is a triangular prism with 4-inch equilateral triangle bases, which means that each side of the triangle is 4 inches long. Since it is a triangular prism, the height of the mailer is not given, but it doesn't matter for this calculation.

The plaque is 31 inches high. We don't know the width or depth of the plaque, but we only need to worry about the height, since that is what will determine whether it fits through the opening.

The opening of the mailer is the triangular shape formed by the three sides of the triangle that form the base. To calculate the size of this opening, we need to know the length of each side of the triangle. Since it is an equilateral triangle, all sides have the same length of 4 inches.

To see whether the plaque will fit through the opening, we need to compare the height of the plaque (31 inches) to the height of the opening. The height of the opening is the height of an equilateral triangle, which can be calculated using the formula:

height = ✓(3)/2 * length

where "length" is the length of one side of the equilateral triangle. In this case, the length is 4 inches, so we have:

height = ✓(3)/2 * 4 = 2*sqrt(3) inches ≈ 3.5 inches

Therefore, the height of the opening is approximately 3.5 inches. Since the plaque is 31 inches high, it is clearly too large to fit through the opening of the mailer. Therefore, Paulo will need to find a larger mailer or use a different method to ship the plaque to the winner of the chess tournament.

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Answer:

2.5002 × 10^3 i think, dont quote me on that

Step-by-step explanation:

Answer:

A,B,D,E

Step-by-step explanation:

On a number line, all of these would be closer to the positives than -3

Hope this helps! :)

Answer:

The answer is 0.037433155

Step-by-step explanation:

well, since the y-intercept is at -5, or namely when the line hits the y-axis is at -5, that's when x = 0, so the point is really (0 , -5), and we also know another point on the line, that is (-1 ,6), to get the equation of any straight line, we simply need two points off of it, so let's use those two

\(\stackrel{y-intercept}{(\stackrel{x_1}{0}~,~\stackrel{y_1}{-5})}\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{6}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{6}-\stackrel{y1}{(-5)}}}{\underset{run} {\underset{x_2}{-1}-\underset{x_1}{0}}} \implies \cfrac{6 +5}{-1} \implies \cfrac{ 11 }{ -1 } \implies - 11\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-5)}=\stackrel{m}{- 11}(x-\stackrel{x_1}{0}) \implies y +5 = - 11 ( x -0) \\\\\\ y+5=-11x\implies {\Large \begin{array}{llll} y=-11x-5 \end{array}}\)

162 mm2
To solve this problem, we will use the concept of similar figures and their ratios. Given that the volumes of two similar figures are 729 mm³ and 2744 mm³, and the surface area of the larger figure is 392 mm², we need to find the surface area of the smaller figure.

Step 1: Find the ratio of volumes.
The ratio of the volumes is 729 mm³ / 2744 mm³, which simplifies to 1/4.

Step 2: Find the cube root of the volume ratio.
The cube root of 1/4 is 1/2 (since (1/2)^3 = 1/8).

Step 3: Calculate the ratio of surface areas.
The ratio of surface areas for similar figures is the square of the ratio of their corresponding lengths. So, the ratio of surface areas is (1/2)^2 = 1/4.

Step 4: Find the surface area of the smaller figure.
Let x be the surface area of the smaller figure. Since the surface area of the larger figure is 392 mm², we have the equation:
x / 392 = 1/4

Step 5: Solve for x.
Multiply both sides of the equation by 392:
x = 392 * (1/4)
x = 98 mm²

So, the surface area of the smaller figure is 98 mm².

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The answer is H-16! Hope this helps! :-)

Answer:

F:64

Step-by-step explanation:

64 divided by 4 is 16.

Answer:

(2,6)

Step-by-step explanation:

x+2y = 14

y = x+4

Substitute x+4 into the first equation for y

x+2(x+4) = 14

Distribute

x+2x+8 = 14

3x+8 = 14

Subtract 8 from each side

3x+8-8 = 14-8

3x = 6

Divide by 3

3x/3 = 6/3

x = 2

Now solve for y

y = x+4

y =2+4

y =6

(2,6)

Answer:

D. (2, 6)

Step-by-step explanation:

Put y as x+4 in the first equation and solve for x.

x + 2(x + 4) = 14

x + 2x + 8 = 14

3x = 14 - 8

3x = 6

x = 2

Put x as 2 in the second equation and solve for y.

y = 2 + 4

y = 6

Answer:

42cm²

Step-by-step explanation:

*internal screaming* okay, let's go:

So, at this point, I don't even know what I'm doing, so I'm not going to guarantee that this is right, I'm sorry, but let's do some random math:

So we know that the length (the top and bottom) of the rectangle is 7 cm, we just have to figure out the width (the sides), and we're gonna do that by:

0.5 x 2 = 1

7 - 1 = 6

So now we just do the basic rectangle area calculation:

7 x 6 = 42

So, I hope that the area of the shaded area is 42cm²

if this is wrong, let me know so I can fix it

hope this helps:/

Answer:

6.45

Step-by-step explanation:

I am not staring at zero.  I am starting at 6.4, so I take 6.4 and add that to half way between 6.5 and 6.4.

6.4 + 1/2(6.5-6.4)  Combine in the parentheses

6.4 + 1/2(.5)  Take half of .5

6.4 + .05  add

6.45

While adding predictor variables to a multiple regression model can potentially decrease the adjusted R², it can also increase it if the added predictors contribute significantly to the explained variance. The statement is not entirely correct.

The statement "adding predictor variables to a multiple regression model can only decrease the adjusted R²" is not entirely correct. Let me explain why:
When you add a predictor variable to a multiple regression model, the R² value, which represents the proportion of the variance in the dependent variable that is explained by the predictor variables, may increase or stay the same. However, it cannot decrease.
The adjusted R², on the other hand, takes into account the number of predictor variables in the model and adjusts the R² value accordingly.

As we add more predictors, there's a chance that the adjusted R² may decrease if the additional predictors do not contribute significantly to the explained variance.
However, it is not true that adding predictors can "only" decrease the adjusted R².

If the added predictor variables provide substantial power and improve the model, the adjusted R² can increase.

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The student's statement that "adding predictor variables to a multiple regression model can only decrease the adjusted R2" is not entirely correct.

While it is true that adding irrelevant predictor variables can decrease the adjusted R2, adding relevant predictor variables can increase or at least maintain the adjusted R2. This is because the adjusted R2 measures the goodness of fit of a regression model, taking into account the number of predictor variables and sample size. Therefore, if the added predictor variable has a significant relationship with the dependent variable, it can improve the model's ability to explain variance and increase the adjusted R2.

In summary, the effect of adding predictor variables on adjusted R2 depends on their relevance to the dependent variable and the existing predictor variables in the model.

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Answer:

$100 profit, $300 cost

Step-by-step explanation:

So 25% of $400 is $100, now we know she made $100 on the article

and the other $300 was the amount used to make the article i'm asuming

A woman sold an article for 400.00

made a profit of 25%

Cost price and profit​ is $100 profit, $300 cost.

There are four levels of profit or profit margins: gross profit, operating profit, pre-tax profit, and net profit.

These are reflected on a company's income statement in the following sequence: A company takes in sales revenue, then pays direct costs of the product of service.

Profit is a term that often describes the financial gain a business receives when revenue surpasses costs and expenses. For example, a child at a lemonade stand spends one quarter to create one cup of lemonade. She then sells the drink for $2. Her profit on the cup of lemonade amounts to $1.75.

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Answer:

Step-by-step explanation:

\( \sin( \theta) = \frac{7}{10} \)

\( \theta = asin( \frac{7}{10} )\)

\( \theta = 44.4^{o} \)

Answer:

\(3\frac{1}{3}\)

Step-by-step explanation:

Dividing fractions is like multiplying the reciprocal of the second number

For example: \(\frac{36}{3}\) divided by \(\frac{24}{6}\)

Multiply the reciprocal, which is 6/24

\(\frac{36}{3} * \frac{6}{24} ,\) Find divisible diagonal factors. Divide by 3 diagonally and divide by 12 diagonally

\(\frac{3}{1} * \frac{2}{2} = 3\)

You can check by making 36/3 to 12 and 24/6 to 4.

12/4 = 3

In the same way:

\(\frac{4}{3} /\frac{2}{5} = \frac{4}{3} * \frac{5}{2} =\)

Divide by 2 diagonally

\(\frac{2}{3} * \frac{5}{1} =\frac{10}{3} = 3\frac{1}{3}\)

The answer is \(3\frac{1}{3}\)

Hope this helps :)

Have a nice day!

Answer:

Find the unit rate of each printing machine and compare.

Step-by-step explanation:

Answer:

2400

Step-by-step explanation:

Answer:

Option 2: 5x - 3y = 30

Step-by-step explanation:

Step 1: Find slope

(0-(-5))/(6-3) = 5/3

Step 2: Find b

y = 5/3x + b

0 = 5/3(6) + b

b = -10

Step 3: Write in slope-intercept form

y = 5/3x - 10

Step 4: Move x over

-5/3x + y = -10

Step 5: Multiply by -3 on both sides

5x - 3y = 30

And we have our final answer!

Step-by-step explanation:

calculate the difference in level of water : (68.1-52.5)mL = 15.6mL ( volume)

mass of the rock = 27.69g

density = mass/volume

=> (ρ) = 27.69/15.6 = 1.775g/mL or 1.775g/cm³(1cm³=1mL).

hope this helps you.

The total surface area of the sphere with a radius of 6cm, correct to 3 significant figures, is approximately 452 cm^2.

The formula for the surface area of a sphere is:

A = 4πr^2

where A is the surface area and r is the radius.

Substituting π = 3.142 and r = 6cm, we get:

A = 4 x 3.142 x 6^2

= 452.39 cm^2

Rounding to 3 significant figures gives:

A ≈ 452 cm^2

Therefore, the total surface area of the sphere with a radius of 6cm, correct to 3 significant figures, is approximately 452 cm^2.

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Answer:

(I)3548 ,,,,,,48.35

(ii) 4807,,,,,,7.48

(iii)1397,,,,,,,97.13

Answer:

-3

Step-by-step explanation:

The answer is -3 because -3 *-3 * -3 would equal -27

Hope this helps:)

Answer:

77.4

Step-by-step explanation:

Answer:

1.2

Step-by-step explanation:

Delta math :)