The analysis of the bank statement thus, given below. Since the result is negative, this means that Andre would still have a negative balance after depositing $100, and therefore would still be in debt.
What is bank statement analysis?1. If we put withdrawals and deposits in the same column, they can be represented as positive and negative values in a single column. Deposits would be represented with positive values, and withdrawals would be represented with negative values.
2. Andre's new balance would be $16.37. We can calculate this by subtracting $40 (the withdrawal) from his previous balance of $56.37:
$56.37 - $40 = $16.37
3. If Andre deposits $100 in this account, he will no longer be in debt. We can calculate his new balance by adding his previous balance and the deposit, and then subtracting any withdrawals:
$56.37 + $100 = $156.37 (balance after the deposit)
$156.37 - $28.50 - $37.91 - $16.43 - $42.00 - $72.50 - $45.00 - $50.00 - $10.03 - $62.47 = -$49.47
Since the result is negative, this means that Andre would still have a negative balance after depositing $100, and therefore would still be in debt.
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Use the properties of kites to answer the questions.
a. If AB = 8x-2, and AD = 6x+4, solve for AD.
b. If mPlease show your work.
The values of the length and angle are;
AD = 22 units
m < ADC = 106 degrees
How to determine the valuesThe properties of a kite are given as;
It has one pair of opposite angles that are equalThe shorter diagonal forms two equal isosceles trianglesThe longer diagonal forms two equal or congruent trianglesThe diagonals are perpendicular to each otherIt has two adjacent and equal sidesFrom the information given, we have that;
AB = 8x - 2
AD = 6x + 4
Equate the sides
8x - 2 = 6x + 4
collect like terms
2x = 6
x = 3
AD = 22 units
Also,
m < ABC = m < ADC
Substitute the values
12x + 10 = 15x - 14
collect like terms
-3x = -24x
x = 8
m < ADC = 106 degrees
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Answer: AD = 22 units
Step-by-step explanation:
m < ADC = 106 degrees
AB = 8x - 2
AD = 6x + 4
Equate any sides
8x - 2 = 6x + 4
Collect terms
2x = 6
x = 3
AD = 22 units
m < ABC = m < ADC
Substitute the values
12x + 10 = 15x - 14
Collect terms
-3x = -24x
x = 8
m < ADC = 106 degrees
15. Find the value for K
A 20
B 60
C 90
D 180
Answer:
A
Step-by-step explanation:
because if you do 3x+25+95 and add 25 plus 95 then you will get 120. then you divide 120 by 3 and should get 30 as k
Please help this is due soon and I'm struggling!
1)
a. 4
b. 9
c. -7
d. -23
2)
a. F
b. F
c. T
d. F
3)
a. 100 -66 =34
b. 78 x 3 = 234
c. 36 + 24 = 60
d. 4 x 17 x 3 = 204
21)
a. -9 + (-12)
= - 9 - 12
= - 21
b. -17 + (3)
= -17 + 3
= - 14
c. 24 + ( -11 )
= 24 - 11
= 13
d. - 15 + (-10)
= - 15 - 10
= - 25
e. - 63 + ( -42) + 8
= - 63 - 42 + 8
= - 97
f. 101 + ( -11 ) + ( -100 )
= 101 -11 - 100
= - 10
How much is 1 plus 1 when adding odd numbers
The value of 1 plus 1 when adding odd numbers is 2.
What are off numbers?Odd numbers simply means the numbers that cannot be divided into pairs. They include 1, 3, 5, 7, 9, ,etc.
In this case, 1 plus 1 will be:
= 1 + 1
= 2
It's important to note that the addition of two odd numbers will give a even number.
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6% means a ratio of rise and run is 6/100 what is the angle of inclination
Answer: 3/50
Step-by-step explanation: 6/100 reduced is 3/50.
Analytically show that the equations below represent trigonometric identity statements. 1. sec²θ (1-cos²θ) 2. cosx(secx-cosx) = sin²x 3. cosθ + sinθtanθ = secθ 4. (1- cos∝)(cosec∝+cot∝)= cos∝ tan∝
To show that the given equations represent trigonometric identity statements, we will simplify each equation and demonstrate that both sides of the equation are equal.
Starting with sec²θ(1 - cos²θ):
Using the Pythagorean identity sin²θ + cos²θ = 1, we can rewrite sec²θ as 1 + tan²θ. Substituting this into the equation, we get:
(1 + tan²θ)(1 - cos²θ)
= 1 - cos²θ + tan²θ - cos²θtan²θ
= 1 - cos²θ(1 - tan²θ)
= sin²θ
Thus, the equation simplifies to sin²θ, which is a trigonometric identity.
For cosx(secx - cosx) = sin²x:
Using the reciprocal identities secx = 1/cosx and tanx = sinx/cosx, we can rewrite the equation as:
cosx(1/cosx - cosx)
= cosx/cosx - cos²x
= 1 - cos²x
= sin²x
Hence, the equation simplifies to sin²x, which is a trigonometric identity.
Considering cosθ + sinθtanθ = secθ:
Dividing both sides of the equation by cosθ, we obtain:
1 + sinθ/cosθ = 1/cosθ
Using the identity tanθ = sinθ/cosθ, the equation becomes:
1 + tanθ = secθ
This is a well-known trigonometric identity, where the left side is equal to the reciprocal of the right side.
Simplifying (1 - cos∝)(cosec∝ + cot∝):
Expanding the expression, we have:
cosec∝ - cos∝cosec∝ + cot∝ - cos∝cot∝
= cot∝ - cos∝cot∝ + cosec∝ - cos∝cosec∝
= cot∝(1 - cos∝) + cosec∝(1 - cos∝)
= cot∝tan∝ + cosec∝sec∝
= 1 + 1
= 2
Thus, the equation simplifies to 2, which is a constant value.
In summary, we have analytically shown that the given equations represent trigonometric identity statements by simplifying each equation and demonstrating that both sides are equal.
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The graph shows the distance y (in miles) that a bus travels in x hours. Find and interpret the slope of the line. a) Find the slope of the line b) What is the speed of the bus? (mph)
Answer:
a) 60
b) 60 mph
Step-by-step explanation:
(a)
Let :-
x¹ = 1
x² = 2
y¹ = 60
y² = 120
Slope of a line = \(\frac{Rise}{Run}\)
where \(Rise=y^2 - y^1\\\) & \(Run=x^2 - x^1\\\)
So , putting all the values in the formula gives :-
\(Slope = \frac{y^2-y^1}{x^2-x^1}= \frac{120-60}{2-1} = 60\)
(b)
In a distance - time graph , slope represents the speed .
In the first bit , we found the value of slope. So,
Speed of the bus = 60 mph
The slope and speed of displayed by the graph is :
Slope = 60Speed = 60 mphThe slope of the line is the ratio of the rise and the run.
Rise = y2 - y1 = (120 - 60) = 60Run = x2 - x1 = (2 - 1) = 1The slope = (Rise / Run) = (60 / 1) = 60
The slope means that the distance moved per hour by the bus during the trip is 60 miles
The speed is the distance moved per hour
The speed can be calculated thus :
(120 ÷ 2) = 60 mphTherefore, the slope is 60 and the speed is 60 mph.
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a concave mirror has a focal length of 16 cm . at what object distance will the magnification be -2.0?
The object distance is 0, which implies that the object is at the focus of the concave mirror.
For a concave mirror, the magnification is given by the formula:
m = -di/do
where m is the magnification, di is the image distance, and do is the object distance. Since we are given that the magnification is -2.0, we can write:
-2.0 = -di/do
Simplifying this expression, we get:
di = 2do
We can also use the mirror formula for a concave mirror:
1/f = 1/do + 1/di
where f is the focal length of the mirror. Substituting di = 2do and f = -16 cm (since the mirror is concave), we get:
1/-16 = 1/do + 1/(2do)
Multiplying both sides by -16do, we get:
do - 2f = -32
Substituting f = -16 cm, we get:
do - (-32) = -32 + 32
do = 0
This means that the object distance is 0, which implies that the object is at the focus of the concave mirror. This is a valid result, since a concave mirror can form a real, inverted image for an object placed at a distance equal to its focal length. In this case, the magnification would be -1, not -2. So, it is not possible to have a magnification of -2 for an object distance in front of a concave mirror with a focal length of 16 cm.
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Find the probability that a randomly chosen client requested a haircut given they requested a permanent.
Given that the client requested a permanent haircut, there is a 66.66% chance that he would request a haircut.
The following calculation must be performed in order to determine the probability that a randomly selected client requested a haircut given that he has requested a permanent: Given that a salon owner noted what types of services its clients requested last week, the results showed that 5% requested dye only, 30% haircut and dye, 35% requested haircut only, 10% hair cut and permanent, 5% permanent only, and 15% other.
Add all of the options that include a perm, and then use a cross multiplication to figure out how many of those options include a haircut.
10 (permanent and haircut) x 5 (permanent only) = 15 15 = 100 10 = X 10 x 100/15 = 66.66 = X
Thus, the probability that a randomly selected client would have requested a haircut given that he had previously requested a permanent is 66.66%.
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Full Question = a salon owner noted what types of services its clients requested last week. Here are the results. 5% dye only, 30% haircut and dye, 35% haircut only, 10 % haircut and permanent, 5% permanent only, and 15% other. Find the probability that a randomly chosen client requested a haircut given the requested a permanent. P(haircut l permanent).
What is the y-intercept of the line graphed on the grid?
(9,2)
(-5,-5)
Help pleaseeee besties
the ratio of roses to lillies is 3 to 2 if lillies and roses are the only flowers in the garden, what percentage of the garden are roses
Therefore, if roses and lilies are the only flowers in the garden, approximately 60% of the garden consists of roses.
To determine the percentage of the garden that consists of roses, we need to calculate the fraction of roses relative to the total number of flowers in the garden.
Given that the ratio of roses to lilies is 3 to 2, we can assume that for every 3 roses, there are 2 lilies. This ratio implies that the total number of flowers in the garden is a multiple of 5 (3 + 2).
Let's assume that there are 5 units of flowers in the garden. In this case, there would be 3 units of roses and 2 units of lilies.
To find the percentage of roses, we divide the number of roses (3 units) by the total number of flowers (5 units) and multiply by 100:
Percentage of roses = (3 / 5) * 100 = 60%
Therefore, if roses and lilies are the only flowers in the garden, approximately 60% of the garden consists of roses.
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in ∆PQR, p= 6.7 inches, r=2 inches and
The Law of sines states:
\(\frac{\sin (\angle P)}{p}=\frac{\sin (\angle R)}{r}\)Substituting with data, and solving for angle P, we get:
\(\begin{gathered} \frac{\sin(\angle P)}{2}=\frac{\sin(142)}{6.7} \\ \frac{\sin(\angle P)}{2}=\frac{0.615}{6.7} \\ \sin (\angle P)=0.091\cdot2 \\ \angle P=\arcsin (0.182) \\ \angle P=10.6\text{ \degree} \end{gathered}\)Solve the inequality:
-3a<9
Answer:
8(46/1^59×6=6,789 this is the answer
true or false: if you are given a graph with two shiftable lines, the correct answer will always require you to move both lines.
False. if you are given a graph with two shif table lines, the correct answer will always require you to move both lines.
In a graph with two shiftable lines, the correct answer may or may not require moving both lines. It depends on the specific scenario and the desired outcome or conditions that need to be met.
When working with shiftable lines, shifting refers to changing the position of the lines on the graph by adjusting their slope or intercept. The purpose of shifting the lines is often to satisfy certain criteria or align them with specific points or patterns on the graph.
In some cases, achieving the desired outcome may only require shifting one of the lines. This can happen when one line already aligns with the desired points or pattern, and the other line can remain fixed. Moving both lines may not be necessary or could result in an undesired configuration.
However, there are also situations where both lines need to be shifted to achieve the desired result. This can occur when the relationship between the lines or the positioning of the lines relative to the graph requires adjustments to both lines.
Ultimately, the key is to carefully analyze the graph, understand the relationship between the lines, and identify the specific criteria or conditions that need to be met. This analysis will guide the decision of whether one or both lines should be shifted to obtain the correct answer.
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If ∠AOB, ∠BOC, and ∠COD are supplementary angles, then what is the value of x and m∠COD?
A.
x = 20; m∠COD = 50°
B.
x = 20; m∠COD = 70°
C.
x = 50; m∠COD = 20°
D.
x = 30; m∠COD = 80°
Answer:
B
Step-by-step explanation:
x=180-90-20-50=20
m∠COD=20+50=70
Answer:
B
Step-by-step explanation:
∠ AOB + ∠ BOC + ∠ COD = 180° ( AOD is a straight line ) , then
20 + 90 + x + 50 = 180 , that is
x + 160 = 180 ( subtract 160 from both sides )
x = 20
Then
∠ COD = x + 50 = 20 + 50 = 70°
Evaluate the gradient of f(x, y, z) = log(x2 + y2 + z2) at (1, 0, 1)
The gradient of f(x, y, z) = log(x2 + y2 + z2) at (1, 0, 1) is (2/1, 0, 2/1)
This gradient is a vector that points in the direction of the greatest rate of increase of the function f(x, y, z) = log(x2 + y2 + z2). To evaluate this gradient, the partial derivatives of the function with respect to x, y, and z must be calculated.
The partial derivative of the function with respect to x is (2x / (x2 + y2 + z2)). When x is 1, this simplifies to 2/1. Similarly, the partial derivative with respect to y is 0, and the partial derivative with respect to z is (2z / (x2 + y2 + z2)), which simplifies to 2/1 when z is 1. Therefore, the gradient of f(x, y, z) = log(x2 + y2 + z2) at (1, 0, 1) is (2/1, 0, 2/1).
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It is known that 60 percent of all registered voters in the 42nd Congressional District are Republicans. Three registered voters are selected at random from the district. Compute the probability that exactly 2 of the 3 selected are Republicans, using: The rules of probability
Answer:
0.11
Step-by-step explanation:
Let x be a random variable representing the number of registered voters in the congressional district. This is a binomial distribution since the outcomes are two ways. It is either a randomly selected registered voter is a conservative or not. The success would be that a randomly selected voter is a conservative. The probability of success, p = 60/100 = 0.6
The probability of failure, q would be 1 - p = 1 - 0.6 = 0.4
Given n = 10, we want to determine P(x = 4)
From the binomial distribution calculator,
P(x = 4) = 0.11
Standing in your tree house, 50 feet off the ground, you look down at a 60° angle and notice a Frisbee. Approximately how many feet from the base of the tree is the Frisbee? Draw a picture to help you!
Answer:
About 29 feet.
Step-by-step explanation:
tan 60 = 50 / h
h = 50/ tan 60
= 28.87 ft
A piece of wire of length 60 is cut, and the resulting two pieces are formed to make a circle and a square. Where should the wire be cut to (a) minimize and (b) maximize the combined area of the circle and the square? (a) Let x be the amount of wire used for the circle. What is the function A, the combined area of the circle and square, in terms of x? (Type an expression. Type an exact answer, using π as needed.) The interval of interest of the objective function is (Simplify your answer. Type your answer in interval notation.) To minimize the combined area, the wire should be cut so that a length of is used for the circle and a length of is used for the square. Round to the nearest thousandth as needed.) (b) To maximize the combined area, the wire should be cut so that a length ofis used for the circle and a length of is used for the square. (Round to the nearest thousandth as needed.)
a) We will cut the wire \($=60-4\left(\frac{60}{4+\pi}\right)$\) =26.3940
b) For the maximum area, we can not cut the wire anywhere.
Length of wire =Perimeter of circle +Perimeter of square
\($$\begin{aligned}& 2 \pi r+4 x=60 \\& r= \frac{60-4 x}{2 \pi}=\frac{30-2 x}{\pi}\end{aligned}$$\)
Let the side of squares x and r is the radius of the circle.
\($$\begin{aligned}\text { Area } & =\pi r^2+x^2 \\& =\pi\left[\frac{30-2 x}{\pi}\right]^2+x^2 \\A(x) & =\frac{1}{\pi}[30-2 x]^2+x^2 \\A^{\prime}(x) & =\frac{2}{\pi}(30-2 x)(-2)+2 x \\A^{\prime}(x) & =0 \Rightarrow \frac{2}{\pi}(30-2 x)(-2)+2 x=0 \\& x=\frac{60}{4+\pi} \approx 8.40\end{aligned}$$\)
A'(5) = -15.464, A'(9)=2.72
Since \($A^{\prime}(x)$\) the change negtive to positive at \($x=\frac{60}{4+\pi}$\), so its minima.
\(r=\frac{30-2\left(\frac{60}{4+\pi}\right)}{\pi}=\frac{30}{4+\pi}\)
a) for the minimum area the side of the square should be \($\frac{60}{4+\pi}$\) which is approximately equal to 8.40.
We will need to cut the wire 4 times the side of the square
So we will cut the wire \($=60-4\left(\frac{60}{4+\pi}\right)$\) =26.3940
b) for the maximum area the problem is defined into \(0 \leqslant x \leqslant 15\)
So, when x=0 the square shrinks to 0 and the whole 60 wire is made into a circle.
When x=15 making the parameter of the. square 60 and the whole circle shrink to 0
So for the maximum area, we can not cut the wire anywhere.
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EASY ANSWER!! Which ordered pair is a solution of y<-4x – 5?
Answer:
5x -4 ?
Step-by-step explanation:
Find the value of of 5x-3y when x=5|2 and y=2|3
Answer:
21/2 or 10.5
Step-by-step explanation:
5x - 3y
5(5/2) - 3(2/3)
25/2 - 2
25/2 - 4/2
21/2
A coin is flipped five times. find the number of possible sets of heads and tails that have 2 heads.
The number of possible sets of heads and tails that have 2 heads is 11.
Given,
There is one coin and it is flipped five times.
First, we have to list out the outcome when we toss the coin five times.
(HHHHH), (HHHHT), (HHHTT), (HHTTT), (HTTTT), (TTTTT), (TTTTH), (TTTHH), (TTHHH), (THHHH), (THTHT), (HTHTH), (THHTT), (THHHT), (HTTTH), (HTTHH), (HTHHH), (THTTT), (TTHTH), (TTTHT), (TTHHT), (HHTHH), (TTHTT), (HHTTH), (HHTHT), (HTHTT), (THTHH), (THTTH), (HTHHT), (HHHTH)
Now, we can list out the possible sets with 2 heads.
(HHTTT), (TTTHH), (THTHT), (HTTHT), (HTTTH), (THHTT), (TTHHT), (TTHTH), (HTHTT), (THTTH), (HTHTT)
So, the number of possible sets of heads and tails that have 2 heads is 11.
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A nurse caring for a client following a right femoral angiogram is unable to palpate the right pedal pulse. What should the nurse do next
The nurse should take immediate action by assessing the client's circulation further and notifying the healthcare team.
The absence of the right pedal pulse following a right femoral angiogram may indicate a potential complication, such as arterial occlusion or impaired blood flow to the lower extremities. To ensure prompt and appropriate care, the nurse should take the following steps:
Assess Circulation: The nurse should assess the client's circulation further by checking for other peripheral pulses, such as the dorsalis pedis or posterior tibial pulses. This can help determine if the absence of the right pedal pulse is localized or if it suggests a larger issue with blood flow.
Check Skin Color and Temperature: The nurse should also assess the color and temperature of the client's lower extremities. Pallor, coolness, or cyanosis may indicate compromised circulation and require immediate attention.
Notify Healthcare Team: It is essential for the nurse to promptly communicate their findings and concerns to the healthcare team, including the primary healthcare provider or interventional cardiologist. This allows for timely intervention and further evaluation of the client's condition.
By taking these steps, the nurse ensures a proactive approach to assessing and managing any potential complications following a right femoral angiogram, promoting the client's safety and well-being.
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Rewrite with Common Denominator
-⅗ + -7/10
By multiplying 2 on both the numerator and denominator of \(\frac{-3}{5}\) .
The expression \(\frac{-3}{5}\) + \(\frac{-7}{10}\) with a common denominator can be written as
\(\frac{-6}{10}\) + \(\frac{-7}{10}\)
What is a fraction?A fraction is written with a numerator and a denominator where the numerator is less than the denominator.
Example: 1/3 is a fraction
We have,
\(\frac{-3}{5}\) + \(\frac{-7}{10}\)
We have different denominators and we need to make the denominator the same.
We will multiply 2 on both the numerator and denominator of \(\frac{-3}{5}\).
= \(\frac{2 \times -3}{2 \times 5}\)
= \(\frac{-6}{10}\)
We see that,
The denominator in \(\frac{-6}{10}\) and \(\frac{-7}{10}\) is the same.
i.e 10.
Now,
\(\frac{-3}{5}\) + \(\frac{-7}{10}\) can be written as \(\frac{-6}{10}\) + \(\frac{-7}{10}\)
Thus,
By multiplying 2 on both the numerator and denominator of \(\frac{-3}{5}\) .
The expression \(\frac{-3}{5}\) + \(\frac{-7}{10}\) with a common denominator can be written as
\(\frac{-6}{10}\) + \(\frac{-7}{10}\)
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question is attached!
Answer:
$3,000 was invested in the account that gained 13%
$17,500 was invested in the account that lost 10%
Step-by-step explanation:
Let the amount in both accounts be x and y
x for the first and y for the second
Adding both is 20,500
x + y = 20,500 •••••(i)
First account earned 13% profit
= 13/100 * x = 0.13x
Second account, a loss of 10%
= -10/100 * y = -0.1y
Total loss of -1,360
This is;
-0.1y + 0.13x = -1,360 •••••••(ii)
From i, x = 20,500-y
Insert this into ii
-0.1y + 0.13(20,500-y) = -1,360
-0.1y + 2665 -0.13y = -1360
-0.23y = -1360-2665
-0.23y = -4025
y = -4025/-0.23
y = 17,500
To get x, we have
x = 20,500 -y
x = 20,500- 17,500
x = 3,000
M +(5x 2xy = 6x + 9xy y−
I assume you want to simplify the expression: M + 5x + 2xy = 6x + 9xy - y
To do this, we can group the terms that contain the same variables together on each side of the equation. First, let's group the terms on the left-hand side:
M + 5x + 2xy = (5x + 2xy) + M
Now, let's group the terms on the right-hand side:
6x + 9xy - y = (9xy - y) + 6x
So the equation becomes:
(5x + 2xy) + M = (9xy - y) + 6x
Next, we can simplify both sides by combining like terms:
5x + 2xy + M = 9xy - y + 6x
Subtracting 5x and 2xy from both sides, we get:
M = 7xy - y + 1x
So the simplified equation is:
M = x(7y + 1) - y
Therefore, M is equal to x times the sum of 7y and 1, minus y.
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an unpressurized aircraft with 20 occupants other than the pilots will be cruising at 14,000 feet msl for 25 minutes. for how many, if any, of these occupants must there be an oxygen supply?
There is no requirement for supplemental oxygen.
All 20 occupants can fly without oxygen supply.
Calculation of the oxygen requirements for an unpressurized aircraft flying at high altitudes:As the altitude increases, the atmospheric pressure decreases, which in turn reduces the partial pressure of oxygen in the air. This reduction in oxygen availability can cause hypoxia, which can lead to impaired judgment, vision, and coordination, and can be fatal in extreme cases.
The calculation of oxygen requirements can involve estimating the total oxygen consumption based on the number of occupants, their age, and their physical condition, and then determining the appropriate type and quantity of oxygen delivery systems to be carried on board the aircraft.
Here we have
An unpressurized aircraft with 20 occupants other than the pilots will be cruising at 14,000 feet msl for 25 minutes.
According to the Federal Aviation Regulations, if an aircraft is flying at an altitude above 12,500 feet MSL for more than 30 minutes,
then oxygen must be supplied to the occupants if:
The cabin pressure altitude exceeds 14,000 feet MSL, or
The cabin pressure altitude exceeds 15,000 feet MSL for any period of time.
In this case, the aircraft is flying at 14,000 feet MSL for 25 minutes, which is less than 30 minutes.
Therefore,
There is no requirement for supplemental oxygen.
All 20 occupants can fly without oxygen supply.
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Write and solve an equation to determine how many degrees the temperature T fell. The temperature at 5 P.M. Is 20∘F. The temperature at 10 P.M. Is −5∘F.
Temperature fell 25° \(\\\)
5 PM => 20
10 PM => -5
Find the difference between both temperatures at 5 PM and 10 PM
T = 20 - ( -5) = 20 + 5 = 25
The reason we subtracted 10 PM from 5 PM (20 - ( -5)) and not the other way around is because 5 PM obviously comes before 10 PM.
a coordinate grid with 2 lines. the first line is labeled y equals 0.5 x plus 3.5 and passes through (negative 3, 1), (negative 2.7, 2.1), and (0, 3.5). the second line is labeled y equals negative startfraction 2 over 3 endfraction x plus startfraction 1 over 3 endfraction and passes through the points (negative 4, 3), (negative 2.7, 2.1), and (startfraction 1 over 3 endfraction, 0). which is the approximate solution to the system y
We are given a coordinate grid with two lines. The first line is labeled y = 0.5x + 3.5 and passes through (-3,1), (-2.7,2.1), and (0,3.5). The second line is labeled y = (-2/3)x + (1/3) and passes through (-4,3), (-2.7,2.1), and (1/3,0).The approximate solution to the system of equations is the point of intersection between the two lines intersect at the point (-1,2)
We are to find the approximate solution to the system y. We can do this by graphing the two lines on the same coordinate grid and finding the point of intersection.
Graph of the two lines can be shown as below:
[Graph illustration showing the two lines intersecting]
We can see that the two lines intersect at the point (-1,2). Therefore, the approximate solution to the system y is (-1,2).
Therefore, the required is (-1,2).
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Answer: (2.7, 2.1)
Step-by-step explanation: took the test
the factory buys the new machine to replace the other two, which of the following expressions show the increase in sate?
А
050x
B
100x
С
in
Answer:
can you change this picture?