HELPPPPPPPPPPPPPPPPPPPPPPPPPPPP WILL MARK BRAINLIST THING
I'M DUM DUM

Servings = total amount / serving size

Servings = 5 / 3/4

When dividing by a fraction, reverse the fraction and multiply:

= 5 x 4/3

= 20/3

= 6 2/3 servings

Answer: 6 servings

Step-by-step explanation:

3/4+3/4+3/4+3/4+3/4+3/4=4.5

if you add 3/4 then it will be  5.25 so basically 5 tablespoons

it is 6 full servings

Answer:

4 I think is the answer

Step-by-step explanation:

Answer:

56 kilograms is equal to approximately 123.456 pounds.

120 of the 200 dentists that participated in the survey and recommended Sparkle toothpaste.

If 60% of dentists recommended Sparkle toothpaste, then the remaining 40% did not.

To find out how many dentists recommended Sparkle toothpaste, we can multiply the total number of dentists in the survey (200) by the percentage who recommended it (60% or 0.6):

To solve for x, we can cross-multiply and simplify:

100x = 60 * 200

x = (60 * 200)/100

x = 120

Number of dentists who recommended Sparkle = 0.6 * 200 = 120

Therefore, 120 of the 200 dentists who took part in the survey recommended Sparkle toothpaste.

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The fifth roots of -i in polar form with angles represented in degrees are: 1. Fourth root when k = 3: √2/2 * (cos(315°) + i sin(315°)). 2. Third root when k = 2: (1/√2) * (cos(270°) + i sin(270°)). 3. First root when k = 0: cos(0°/5) + i sin(0°/5). 4. Second root when k = 1: cos(72°/5) + i sin(72°/5). 5. Fifth root when k = 4: cos(288°/5) + i sin(288°/5).

The fifth roots of -i in polar form with angles represented in degrees are as follows:

1. Fourth root when k = 3: The fourth root of -i is given by √(-i) = √2/2 * (cos(45° + 90°k) + i sin(45° + 90°k)). When k = 3, the angle becomes 45° + 90° * 3 = 315°. Therefore, the fourth root of -i when k = 3 is √2/2 * (cos(315°) + i sin(315°)).

2. Third root when k = 2: The third root of -i is given by ∛(-i) = (1/√2) * (cos(30° + 120°k) + i sin(30° + 120°k)). When k = 2, the angle becomes 30° + 120° * 2 = 270°. Therefore, the third root of -i when k = 2 is (1/√2) * (cos(270°) + i sin(270°)).

3. First root when k = 0: The first root of -i is given by (-i)^(1/5) = cos(θ/5) + i sin(θ/5). Since k = 0, the angle θ becomes 0°. Therefore, the first root of -i when k = 0 is cos(0°/5) + i sin(0°/5).

4. Second root when k = 1: The second root of -i is given by (-i)^(1/5) = cos(θ/5) + i sin(θ/5). Since k = 1, the angle θ becomes 360°/5 = 72°. Therefore, the second root of -i when k = 1 is cos(72°/5) + i sin(72°/5).

5. Fifth root when k = 4: The fifth root of -i is given by (-i)^(1/5) = cos(θ/5) + i sin(θ/5). Since k = 4, the angle θ becomes 4 * 360°/5 = 288°. Therefore, the fifth root of -i when k = 4 is cos(288°/5) + i sin(288°/5).

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Answer:

300 girls, 200 boys

Step-by-step explanation:

To find boys: 500 x 0.4 = 200

To find girls: 500 x 0.6 = 300

60% girls

Therefore,  subscript indices must be either positive integers or logical. True

Explanation: The statement "subscript indices must be either positive integers or logicals" is true. Subscript indices are used to identify elements in an array. A positive integer subscript identifies a particular element in an array, while a logical subscript identifies a subset of elements based on a logical condition. For example, if we have an array A, then A(1) would identify the first element of the array, while A(A > 0) would identify all elements in the array that are greater than zero. Subscript indices cannot be negative or non-integer values.

Therefore,  subscript indices must be either positive integers or logical. True

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The picture is represented by the absolute value function g(x) = |x - 5| - 4. (Correct choice: A)

Absolute values are functions defined by the following piecewise function:

The function in the picture is the consequence of the following rigid transformations:

Now we proceed to obtain the image of f(x):

Horizontal translation

f'(x) = |x - 5|

Vertical translation

g(x) = |x - 5| - 4

The picture is represented by the function g(x) = |x - 5| - 4.

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Two standards $6$-sided dice are rolled. The probability that the sum rolled is a perfect square 7/36.

Likelihood is the part of math concerning mathematical portrayals of how likely an occasion is to happen, or how likely it is that a suggestion is valid. Likelihood is the part of science concerning mathematical depictions of how likely an occasion is to happen, or how likely it is that a recommendation is valid. Likelihood and measurements, the parts of science worried about the regulations administering arbitrary occasions, including the assortment, investigation, understanding, and show of mathematical information. While calculation and variable based math were concentrated on by old Greek mathematicians over long time back, the ideas of likelihood just arose in the seventeenth and eighteenth 100 years.

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The solution to the differential equation y''(t) = 1 - t^17 with initial condition y(1) = 12 is:

y(t) = (1/2)t^2 - (1/342)t^19 + (217/18)t + (19805/342)

None of the provided options (a, b, c, d) match the correct solution.

To solve the given differential equation y''(t) = 1 - t^17 with the initial condition y(1) = 12, we can integrate the equation twice.

Integrating the equation once will give us y'(t):

y'(t) = ∫(1 - t^17) dt

y'(t) = t - (1/18)t^18 + C₁

Now, we need to apply the initial condition y(1) = 12 to determine the value of the constant C₁:

12 = 1 - (1/18) + C₁

C₁ = 12 + (1/18) - 1

C₁ = 217/18

Next, we integrate y'(t) to find y(t):

y(t) = ∫(t - (1/18)t^18 + 217/18) dt

y(t) = (1/2)t^2 - (1/342)t^19 + (217/18)t + C₂

Finally, we apply the initial condition y(1) = 12 to determine the value of the constant C₂:

12 = (1/2) - (1/342) + (217/18) + C₂

C₂ = 12 - (1/2) + (1/342) - (217/18)

C₂ = (20619 - 1 + 6 - 819)/(342)

C₂ = 19805/342

Therefore, the solution to the differential equation y''(t) = 1 - t^17 with initial condition y(1) = 12 is:

y(t) = (1/2)t^2 - (1/342)t^19 + (217/18)t + (19805/342)

None of the provided options (a, b, c, d) match the correct solution.

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a) The variable involved in this study is the proportion of Nippa brand paints that meet the VOC content standard limit.b) Hypothesis: The null hypothesis H0: p = 0.85The alternative hypothesis

Ha: p < 0.85Given n = 85, p-hat = 0.80, and α = 0.045At the 4.5% significance level, the critical value of zα is found using normal distribution tables.

Here, α/2 = 0.0225 because the alternative hypothesis is one-tailed. The critical value of zα = -1.70, which separates the middle 95% from the lower tail of 2.5%. Calculating the test statistic:

\(z = \frac{p - p_{\text{hat}}}{\sqrt{\frac{p(1-p)}{n}}}\)\(z = \frac{0.85 - 0.80}{\sqrt{\frac{0.85(1-0.85)}{85}}} = 1.89\)Now, we can compare this test statistic value to the critical value to see if the null hypothesis should be rejected. Because the test statistic is greater than the critical value, we reject the null hypothesis and conclude that there is evidence to support the production manager's estimation that more than 85% of their paint meets the standard limit for VOC content.

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Answer:

\(Pr = \frac{8 - \pi}{8}\)

Step-by-step explanation:

Given

See attachment for square

Required

Probability the \(dart\ lands\) on the shaded region

First, calculate the area of the square.

\(Area = Length^2\)

From the attachment, Length = 6;

So:

\(A_1 = 6^2\)

\(A_1 = 36\)

Next, calculate the area of the unshaded region.

From the attachment, 2 regions are unshaded. Each of this region is quadrant with equal radius.

When the two quadrants are merged together, they form a semi-circle.

So, the area of the unshaded region is the area of the semicircle.

This is calculated as:

\(Area = \frac{1}{2} \pi d\)

Where

\(d = diameter\)

d = Length of the square

\(d =6\)

So, we have:

\(Area = \frac{1}{2} \pi (\frac{d}{2})^2\)

\(Area = \frac{1}{2} \pi (\frac{6}{2})^2\)

\(Area = \frac{1}{2} \pi (3)^2\)

\(Area = \frac{1}{2} \pi *9\)

\(Area = \pi * 4.5\)

\(Area = 4.5\pi\)

The area (A3) of the shaded region is:

\(A_3 = A_1 - A_2\) ---- Complement rule.

\(A_3 = 36 - 4.5\pi\)

So, the probability that a dart lands on the shaded region is:

\(Pr = \frac{A_3}{A_1}\) i.e. Area of shaded region divided by the area of the square

\(Pr = \frac{36 - 4.5\pi}{36}\)

Factorize:

\(Pr = \frac{4.5(8 - \pi)}{36}\)

Simplify

\(Pr = \frac{8 - \pi}{8}\)

Answer:

What? Your not even done.

Step-by-step explanation:

True. The loan-to-value ratio is a calculation that compares the amount of the loan being taken out for a real estate investment project to the value of the property being purchased. This ratio is often used to determine the amount of leverage being used in the investment, with higher ratios indicating more leverage and potentially higher risk.

The LTV ratio indicates the percentage of the property's value that is financed through debt. Higher LTV ratios indicate a higher level of leverage, meaning that a larger portion of the property's value is funded through borrowed money. LTV ratios are commonly used by lenders to assess the risk associated with a real estate investment and determine the terms of the loan.

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Answer:

-50

Step-by-step explanation:

A negitive number would mean debt or owed. A positive number would be a credit of a number.

Answer: 0 and 12

Step-by-step explanation:

Fractions and mixed numbers aren’t rational numbers and pi isn’t a rational number.

Whole numbers are rational numbers, though so 0 and 12 are your answers.

Answer:

0 and 12

Step-by-step explanation:

you cant have mixed numbers and pie is never ending

The expected number of games it will take to win on a slot machine game with a probability of winning of 0.152 is approximately 6.579 games.

The expected number of games can be calculated using the formula for the expected value of a geometric distribution. In this case, the probability of winning on each game is 0.152.

The expected number of games is calculated as the reciprocal of the probability of winning. Therefore, the expected number of games is 1 divided by 0.152, which is approximately 6.579.

This means that on average, it is expected to take approximately 6.579 games to win on the slot machine. However, it's important to note that this is an average value and individual experiences may vary. Some players may win on their first few games, while others may take more games to win. Nonetheless, on average, it is expected to take approximately 6.579 games to achieve a win.

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Answer:

87

Step-by-step explanation:

common difference = d  = 2

an = a1 + (n-1)*d

a43 = 3 + 42*2  = 87

The area of the triangular yard is 7000 ft².

The entire area enclosed by three sides of a triangle is the area of it.

Given,

The base of the triangle is 200 feet and the height of the triangle is 70 feet.

Therefore, the area of the triangle

= (1/2) × base of the triangle × height of the triangle =  (1/2) × 200 × 70 ft² = 7000 ft².

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The image point of (4,-2) after the transformations given is; (2,1).

It follows from the task content that the point given is (4, -2) which first reflects over the y axis and hence, renders the new image to be; (4, 2) after which it undergoes a dilation of with dilation factor, 1/2 and hence, the image point is; (2,1).

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Answer:

The equation simplifies to x

Step-by-step explanation:

(2x + 8) - (x + 8)

2x + 8 - x - 8

x

Hope this helped!

Answer:

I'm not completely sure but I beileve Jackie less than 4

Step-by-step explanation:

good luck tho

Answer:

D

(i scored 100 on the quiz)

Answer:

$72 is the retail price

Step-by-step explanation:

100 x (100-28)/100

Using the master theorem, the Θ-class are: a) T(n) = Θ(n)b) T(n) = Θ(n) and c) T(n) = Θ(√n log n).

a) T(n)=2T(n/2)+n³

To find the Θ class of T(n), we need to apply the Master Theorem. In the Master Theorem, if T(n) = aT(n/b) + f(n) where a >= 1, b > 1, and f(n) is an asymptotically positive function, then:

T(n) = Θ(nᵈ)

where d = logₐ(b).

Here a = 2, b = 2 and f(n) = n³.

So, d = log₂(2)

= 1T(n)

= Θ(nᵈ)

= Θ(n¹)

= Θ(n)

Therefore, the Θ class of T(n) is Θ(n).

b) T(n)=2T(n/2)+3n−2

Similarly to part (a), we can find the Θ class of T(n) by using the Master Theorem.

In this case, a = 2, b = 2 and f(n) = 3n - 2.

Here, d = log₂(2)

= 1T(n)

= Θ(nᵈ)

= Θ(n¹)

= Θ(n)

Therefore, the Θ class of T(n) is Θ(n).

c) T(n)=4T(n/2)+nlogn

For this recurrence relation, a = 4, b = 2 and f(n) = nlogn.

In this case, d = log₄(2) = 0.5.

So,

T(n) is

= Θ(nᵈ)

= Θ(n⁰.⁵)

= Θ(√n log n)

Therefore, the Θ class of T(n) is Θ(√n log n).

Hence, the correct options are:a) T(n) = Θ(n)b) T(n) = Θ(n)c) T(n) = Θ(√n log n).

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Answer:

A.

Step-by-step explanation:

For square one, the dark part added up= 1/4 of the whole big square.

For square 2. the colored in part= 1/4 of the whole big square.

For square 3. The colored part = 1/4 of the whole big square.

Keep in mind that EACH OF THE SEGMENTS THAT INTERSECT THE SIDES OF THE SQUARES INTERSECT AT MIDPOINTS OF THE SIDES.

For number three, make sure to draw in what square two looks like. one line vertical, one horizontal.

THE ANSWER IS A THOUGH.

the rate of change of the radius at the instant the volume equals 36π cm³ is 7 / (36π) cm/sec.

The volume V of a sphere with radius r is given by the formula V = (4/3)πr³. We are given that the rate of change of the volume is 7 cm³/sec. Differentiating the volume formula with respect to time, we get dV/dt =(4/3)π(3r²)(dr/dt), where dr/dt represents the rate of change of the radius with respect to time.

We are looking for the rate of change of the radius, dr/dt, when the volume equals 36π cm³. Substituting the values into the equation, we have: 7 = (4/3)π(3r²)(dr/dt)

7 = 4πr²(dr/dt) To find dr/dt, we rearrange the equation: (dr/dt) = 7 / (4πr²) Now, we can substitute the volume V = 36π cm³ and solve for the radius r: 36π = (4/3)πr³

36 = (4/3)r³

27 = r³

r = 3  Substituting r = 3 into the equation for dr/dt, we get: (dr/dt) = 7 / (4π(3)²)

(dr/dt) = 7 / (4π(9))

(dr/dt) = 7 / (36π)

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