Answer:
B
Explanation:
Lifeguards have to work outside on the beach.
Hope this helped
Lifeguards are likely to be outdoors at the beach or the outdoor public pool. Though some public pools are indoors.
Lawyers will often be in courthouses or their office, so choice A is out.
Engineers will likely be in their offices as well behind a desk working on a computer to design their latest object (eg: a bridge for instance). So choice C is out.
Pilots will spend all of their time in the air, so choice D is out also.
What are the Major Constraints of public police formulation in South Africa?
Answer:
Public Policy Formulation, Implementation and Evaluation.
The breaking strengths of cables produced by a certain manufacturer have a standard deviation of 92 pounds. A random sample of 90 newly manufactured cables has a mean breaking strength of 1700 pounds. Based on this sample, find a 95% confidence interval for the true mean breaking strength of all cables produced by this manufacturer. Then give its lower limit and upper limit.
Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place.
The 95% confidence interval for the true mean breaking strength of all cables produced by the manufacturer is approximately 1680.9 pounds to 1719.1 pounds. The lower limit is 1680.9 pounds, and the upper limit is 1719.1 pounds.
To calculate the 95% confidence interval for the true mean breaking strength of all cables produced by the manufacturer, we can use the formula:
Confidence Interval = sample mean ± (critical value * standard deviation / √sample size)
The critical value corresponds to the desired level of confidence and the sample size. For a 95% confidence level and a sample size of 90, the critical value is approximately 1.96 (obtained from the standard normal distribution).
Substituting the given values into the formula, we have:
Confidence Interval = 1700 ± (1.96 * 92 / √90)
Calculating the values:
Confidence Interval = 1700 ± (1.96 * 92 / √90)
≈ 1700 ± (1.96 * 92 / 9.4868)
≈ 1700 ± 19.12
Rounding to one decimal place, we get:
Confidence Interval ≈ (1680.9, 1719.1)
Therefore, the 95% confidence interval for the true mean breaking strength of all cables produced by the manufacturer is approximately 1680.9 pounds to 1719.1 pounds. The lower limit is 1680.9 pounds, and the upper limit is 1719.1 pounds.
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What is the median of 12, 9 , 16, 1, 6 , 5, 84
The median of your data would be 9.
First, align the numbers from least to greatest:
1, 5, 6, 9, 12, 16, 84
Next, identify which number is in the middle; if you have a hard time figuring that out you may want to strikethrough numbers on both sides until you have only one number left—that would be your median per se (i.e., 9 is the median of this data set).
\(\huge\text{Hey there!}\)
\(\large\text{When you hear the word \underline{median} think of the question asking you }\\\large\text{what is the MIDDLE number. To find the median/middle number}\\\large\text{you have to put the numbers from descending (least) or ascending}\\\large\text{(greatest) order. }\)
\(\large\text{12, 9, 16, 1, 6, 5, \& 84}\\\large\text{= 1, 5, 6, 9, 12, 16, \& 84}\\\\\large\text{If the numbers are ODD the data will have a single number.}\\\large\text{If the numbers are EVEN the data will have two numbers.}\\\\\large\text{It seems to be even around the number 3 numbers surrounding}\\\large\text{around the number \underline{\underline{9}}. So that could possibly be your median}\\\large\text{or middle number}\\\\\boxed{\boxed{\huge\text{Therefore, your answer is: \bf 9}}}\huge\checkmark\)
\(\huge\text{Good luck on your assignment \& enjoy your day!}\)
~\(\frak{Amphitrite1040:)}\)
Recent research has shown that lecturers are among the most stressed workers. A researcher wanted to know exactly what it was about being a lecturer that created this stress and subsequent burnout. She recruited 75 lecturers and administered several questionnaires that measured: Burnout (high score = burnt out), Perceived Control (high score = low perceived control), Coping Ability (high score = low ability to cope with stress), Stress from Teaching (high score = teaching creates a lot of stress for the person), Stress from Research (high score = research creates a lot of stress for the person), and Stress from Providing Pastoral Care (high score = providing pastoral care creates a lot of stress for the person). The outcome of interest was burnout, and Cooper’s (1988) model of stress indicates that perceived control and coping style are important predictors of this variable. The remaining predictors were measured to see the unique contribution of different aspects of a lecturer’s work to their burnout. What does the scatterplot show?
A scatter plot is a diagram that represents a correlation between two continuous variables. The scatter plot is one of the best-known graphs since it is frequently used in research studies. The scatter plot shows the distribution of the outcome variable on the Y-axis and the predictor variable on the X-axis.
The scatterplot shows the relationship between the predictor variables and the outcome variable. In the given scenario, the predictor variables are Burnout, Perceived Control, Coping Ability, Stress from Teaching, Stress from Research, and Stress from Providing Pastoral Care.
The outcome variable of interest is burnout.The scatter plot shows the relationships among the different predictors and the outcome variable. It also shows whether there is a positive, negative, or no correlation between the predictor and outcome variables.
Scatter plots are usually used to understand whether there is a linear or non-linear correlation between the predictor variables and the outcome variable.In the given case, the scatter plot shows the relationship between burnout and the predictor variables.
This relationship is represented by the scatter plot, and it can be used to predict the impact of each predictor on burnout. The scatter plot can be used to identify the predictor variables that have a significant impact on burnout and which can be targeted to reduce the stress and burnout among the lecturers.
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A sample of 1300 computer chips revealed that 66% of the chips do not fail in the first 1000 hours of their use. The company's promotional literature claimed that above 63% do not fail in the first 1000 hours of their use. Is there sufficient evidence at the 0.10 level to support the company's claim? State the null and alternative hypotheses for the above scenario.
The hypothesis of the question is written below
H0: (p ≤ 0.63)
H1: (p > 0.63)
How to write the hypothesisThe hypothesis for the given scenario can be summarized as follows:
Null Hypothesis (H0): The proportion of computer chips that do not fail in the first 1000 hours of use is 63% or less. (p ≤ 0.63)
Alternative Hypothesis (Ha): The proportion of computer chips that do not fail in the first 1000 hours of use is greater than 63%. (p > 0.63)
The null hypothesis assumes that the company's claim is not supported, suggesting that the proportion of chips not failing within 1000 hours is 63% or lower. T
he alternative hypothesis counters this claim and proposes that the proportion is higher than 63%. The significance level chosen for the test is 0.10, which will be used to evaluate the evidence from the sample data.
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The first psychological therapy was introduced by
Answer:
Sigmund freud
Explanation:
One of the functions of sociology of education is the development of new social patterns (see p5 in SoE). Briefly discuss how this aim could be taught in the classroom. (3)
Teaching the aim of developing new social patterns within the context of the sociology of education requires a comprehensive and interactive approach in the classroom.
Some strategies that could be used to effectively teach this aim:
1)Introduce case studies: Presenting real-life case studies that demonstrate social patterns and their consequences can help students understand the importance of developing new social patterns.
By analyzing these cases, students can identify existing social patterns, evaluate their impacts, and brainstorm potential alternatives.
2)Encourage critical thinking: Foster critical thinking skills by engaging students in discussions and debates about current social patterns and their implications.
Encourage them to question the status quo, challenge existing norms, and explore alternative social arrangements.
This can be done through open-ended questions, group activities, and analyzing conflicting viewpoints.
3)Collaborative projects: Assigning collaborative projects that require students to propose and develop new social patterns can be an effective way to engage them in active learning.
Students can work in groups to identify social issues, research potential solutions, and create action plans for implementing new social patterns.
This hands-on approach encourages creativity, teamwork, and problem-solving skills.
4)Guest speakers and field trips: Inviting guest speakers from various fields, such as sociology, education, and community organizations, can provide students with real-world insights into the development of new social patterns.
Organizing field trips to relevant community organizations or institutions can also give students the opportunity to observe and learn from initiatives that aim to create positive social change.
5)Reflective activities: Incorporate reflective activities, such as journaling, class discussions, or personal presentations, where students can express their thoughts, insights, and personal experiences related to social patterns.
Encourage them to critically reflect on their own behaviors, attitudes, and the potential impact they can have on social patterns.
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Use GSS file for this spss problem. Calculate the 95% confindence interval for the following variables, comparing lower, working, middle, and upper classes, (CLASS) in the GSS sample. Use the explore procedure using class as your factor variable
A confidence interval is the mean of the estimate plus and minus the variation that is in that estimate.
What is a confidence interval?Your information is incomplete as the data is not given. Therefore, an overview will be given. A confidence interval is the range of values you expect your estimate to fall between when you redo your test, within a certain level of confidence.
A 95% confidence interval means that we are to take 100 different samples and compute a 95% confidence interval for each sample, then 95 of the 100 confidence intervals will contain the true mean value.
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A distributor of outdoor yard lights has four suppliers. This past season she purchased 40% of the lights from Franklin Lighting, 30% from Wilson & Sons, 20% from Evergreen Supply, and the rest from A. L. Scott. In prior years, 3% of Franklin's lights were defective, 6% of the Wilson lights were defective, 2% of Evergreen's were defective, and 8% of the Scott lights were defective. When the lights arrive at the distributor, she puts them in inventory without identifying the supplier. Suppose that a defective light string has been pulled from inventory; what is the probability that it was supplied by Franklin Lighting?
Answer:
The probability that a defective light string was supplied by Franklin Lighting is 40%.
3. Manufacturers are required to use clear labeling systems that display the hazards of a substance at a glance.
A) O True
B)O False
Manufacturers are required to use clear labeling systems that display the hazards of a substance at a glance. The given statement is true.
Giving someone or something a label is the act of describing them in a single word or phrase. One who has broken the law, for instance, might be referred to as a "criminal." The labeling hypothesis is a sociological theory that claims that labeling people helps to manage and identify aberrant behavior.
Labeling, often known as labeling, is the process of associating someone or something with a descriptive word or phrase. Putting labels on jars to indicate what is within is one example of labeling. The moniker "Oakie" is used to describe somebody from Oklahoma as an example of labeling.
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Old hens can be bought for Rs. 2 each. but young
ones cost Rs. 5 each. The old hens lay 3 eggs per
week and the young ones 5 eggs per week, each
egg being worth 30 paise. A hen costs Rs. 1.00 per
week to feed. If I have only Rs. 80.00 to spend for
hens, how many of each kind should I buy to give a
profit of more than Rs. 6.00 per week, assuming
that I can not house more than 20 hens.
Formulate this problem as LPP.
Let x be the number of old hens and y be the number of young hens to buy.
The objective is to maximize the profit, which is the total income from selling eggs minus the total cost of buying and feeding the hens:
Maximize Z = 0.3(3x + 5y) - (2x + 5y + (x + y)) - 6
where 0.3 is the price of each egg, 2 is the cost of an old hen, 5 is the cost of a young hen, and 1 is the cost of feeding a hen per week. The term "-6" is subtracted to ensure that the profit is more than Rs. 6.00 per week.
The constraints are:
The total cost of buying hens cannot exceed Rs. 80.00:
2x + 5y ≤ 80
The total number of hens cannot exceed 20:
x + y ≤ 20
The number of old hens cannot be negative:
x ≥ 0
The number of young hens cannot be negative:
y ≥ 0
Now we have formulated the problem as a linear programming problem. The objective is to maximize Z subject to the constraints.
If 7 men 5 women have applied for job and 3 applicants are randomly selected from the probability that 2 are men how many WOmen?
.
The probability of selecting 2 men and a woman is \(\frac{21}{44}\)
The sample space is made up of 7 men and 5 women. So we have a total of 12 people.
If 3 applicants are randomly selected without replacement, there will be three mutually exclusive possibilities;
\(MMW=\text{Event that a Man, then Man, then Woman is selected}\\MWM=\text{Event that a Man, then Woman, then Man is selected}\\WMM=\text{Event that a Woman, then Man, then Man is selected}\\\)
The final probability will have the form
\(P(\text{2 men and 1 woman})=P(MMW)+P(MWM)+P(WMM)\)
because the possibilities are mutually exclusive.
Computing the Probability of each possibilityEach mutually exclusive possibility is made up of dependent events. This is because when selection is done without replacement, it affects the size of the sample space.
The Probability of selecting a Man, then a Man, then a Woman is\(P(MMW)=\dfrac{7}{12}\times\dfrac{6}{11}\times\dfrac{5}{10}\\\\=\dfrac{7}{44}\)
The Probability of selecting a Man, then a Woman, then a Man is\(P(MWM)=\dfrac{7}{12}\times\dfrac{5}{11}\times\dfrac{6}{10}\\\\=\dfrac{7}{44}\)
The Probability of selecting a Woman, then a Man, then a Man is\(P(MWM)=\dfrac{5}{12}\times\dfrac{7}{11}\times\dfrac{6}{10}\\\\=\dfrac{7}{44}\)
Calculate the Probability of getting two men and a womanThe final probability is
\(P(\text{2 men and 1 woman})=P(MMW)+P(MWM)+P(WMM)\\\\=\dfrac{7}{44}+\dfrac{7}{44}+\dfrac{7}{44}\\\\=\dfrac{21}{44}\)
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old yeller sensory frases in page 211 help
Clarence wants to estimate the percentage of students who live more than three miles from the school. He wants to create a
98%
confidence interval which has an error bound of at most
4%
. How many students should be polled to create the confidence interval?
Answer:
847 students must be interviewed.
Explanation:
To reach this result we will use the following formula:
\(n = \frac{z^2*p*(1-p)}{e^2}\)
In this formula the letter "e" is equal to 0.04 (4%). Thus, we must find the values of "p" and "z", to find the "n", which refers to the confidence interval.
The question above did not show us what value should be used in "p". When we do not have information on this value, it is always recommended to use 0.5, which is the sample maximization value.
In the situation shown in the question above, a confidence interval of 98% is presented. Thus, it is implicit that we must adopt in "z" a value among the cumulative values of the z distribution of up to 1% or up to 99%. That way you can use any value between the range of 1% to 99%, you should look for that value in a table of Z, however, to facilitate the calculation we will use a value of the area of 99% in the distribution of z. This value is 2,327.
Now we can replace these values in the formula and find the value of "n".
\(n = \frac{2.327^2*0.5*(1-0.5)}{0.04^2} = 846.08\)
As there are no 0.8 students, we must round the number to 487. So we can say that it will be necessary to interview 847 students to create the confidence interval.
Find the slope of a line perpendicular to the line ax + by=c
Answer:
b/a
Explanation:
ax + by = c
In order to find the slope put the equation in slope-intercept form (y=mx+b):
Solve for y:
ax + by = c
by = c - ax ==> subtract ax on both sides
y = (c - ax) / b ==> divide both sides by b to isolate y
y = c/b - ax/b ==> distribution property
y = -ax/b + c/b ==> turn the equation into y=mx+b format
-ax/b ==> The slope is -a/b
Now that we found the slope of the original line, we need to find the slope of the line perpendicular to it.
Perpendicular lines have slopes that are opposite reciprocals:
An example of opposite reciprocals are -1/2 and 2:
Negate 2 to get -2
-2 = -2/1 ==> any number that is divided by 1 is itself
The reciprocal of -2/1 is -1/2
Hence, the opposite reciprocal of 2 is -1/2
Now apply this concept to the slope -a/b:
Negate -a/b to get -(-a/b) = a/b
The reciprocal of a/b is b/a
Hence, the slope of the perpendicular line is b/a.
To find the slope of a line that is perpendicular to a given line, we can use the negative reciprocal of the slope of the given line.
The slope of a line in the form of ax + by = c is the coefficient of x (a) divided by the coefficient of y (b). In this case, the slope of the line is -a/b.
A line perpendicular to the line ax + by = c will have a slope that is the negative reciprocal of -a/b. So the slope of a line perpendicular to the line ax + by = c is b/a.
Note that when a = 0 or b = 0, the slope is undefined. In this case, the line is a vertical or horizontal line respectively and its perpendicular line is the other type of line.
Therefore, the slope of a line perpendicular to the line ax + by = c is b/a, as long as a is not equal to zero.
If oncoming headlights make it difficult for you to see, look at
the
Answer:
You should always look toward the right edges of your lane to see where you're going, never look directly into the headlights.
Sobre a união de resina e esmalte
Answer: Not sure if you wanted it in english but that means "on the union of resin and enamel."
Explanation:
Race/ethnicity
White
Black
Mexican American
Puerto Rican
Other Hispanic/Latino
Asian/Pacific Islander
American Indian/Alaska Native
Average SAT scores for college-bound seniors, by race/ethnicity: 2004
0 100
200
300
430
427
451
458
457
452
461
400
Average score
465
483
488
500
Verbal
Mathematics
528
531
577
600
700
Make an inference about students who are Asian/Pacific Islander.
800
k
We can infer that based on the average SAT scores for college-bound seniors in 2004, it can be inferred that students who identify as Asian/Pacific Islander tend to perform well academically, particularly in the Mathematics section, as they have an average score of 577.
What is an inference?An inference is a logical conclusion or deduction based on available information, evidence or observations.
It involves the use of reasoning and critical thinking to reach a conclusion that is not explicitly stated or directly provided.
Inferences involve connecting existing knowledge or data to make an educated guess or interpretation about something that is not explicitly stated or observed.
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The following data give the amounts spent on video rentals (in dollars) during 2018 by 100
households who rented videos in 2020.
500
92
96
490
130
115
158
120
480
350
100
245
85
250
95
110
160
300
360
325
105
110
264
360
135
275
165
402
306
380
80
468
85
370
92
150
148
280
390
158
90
105
495
385
140
206
180
320
400
410
120
125
420
405
445
380
450
420
130
422
170
172
542
410
145
180
350
330
460
490
452
210
490
215
120
218
340
230
340
238
205
500
75
420
150
190
346
340
470
168
230
123
240
440
368
200
235
438
240
480
I
You are required to randomly select 40 households from the above data and answer the
following questions
(a)
Construct a frequency distribution table with suitable class width. Number of classes
should be between 5 and 8.
(10 marks)
(b)
Construct a histogram to represent the data.(use graph paper)
(5 marks)
Answer
tell your teacher she's dumb for asking sooooooooo many questions
Explanation:
A box measures 3.12 ft in length, 0.0455 yd in width and 7.87 inches in height. What is its volume in
cubic centimeters?
Question 6 of 20
Signs of test.
include insomnia, headaches, and panic.
OA. exhilaration
O B. anxiety
O C. depression
OD. fatigue
Answer:
B. Anxiety
Explanation:
What is the position of earth on September 23 abc or d
Answer:
The September equinox occurs the moment the Sun crosses the celestial Equator – the imaginary line in the sky above Earth's Equator – from north to south. This happens either on September 22, 23, or 24 every year.
Explanation:
mark me as brainliest
The function of the liver is ____ the all-toxic substances of the body.
Answer:
the livers function is to remove all toxic substances from the body
i hope this helps
please Mark be brainliest answer:)
WHAT IS COUNT DOOKU’S HAIR COLOR
Reading questions
w
Which choice provides the best evidence for the answer to the
previous question?
ast
te tam
le.
A
lines 2-4 ("She stepped ... angle")
..
B
lines 8-12 ("I believe ... else")
lines 12-17 ("Irritated ... excitement")
egrees
which,
mark
2 the
ating
nothing
brity of
ew
ll upon us in
prer than wea
monds
RO
D
lines 20-21 ("She'd gone ... London")
Answer:
the previous question needs to be given in order to answer this question.
Explanation:
Question
Ahmed was reimbursed 75% of his medical bill by his health insurance. What fraction of the medical bill was
he reimbursed?
Ahmed was reimbursed 75% of his medical bill. To express this as a fraction, we can write it as 75/100 or 3/4.
So, Ahmed was reimbursed 3/4 or three-fourths of his medical bill.
Recall that Benford's Law claims that numbers chosen from very large data files tend to have "1" as the first nonzero digit disproportionately often. In fact, research has shown that if you randomly draw a number from a very large data file, the probability of getting a number with "1" as the leading digit is about 0.301. Now suppose you are an auditor for a very large corporation. The revenue report involves millions of numbers in a large computer file. Let us say you took a random sample of n = 225 numerical entries from the file and r = 51 of the entries had a first nonzero digit of 1. Let p represent the population proportion of all numbers in the corporate file that have a first nonzero digit of 1.
Use the value of the sample test statistic to find the corresponding z value. (Round your answer to two decimal places.)
Find the P-value of the test statistic. (Round your answer to four decimal places.)
P-value =
Answer:
We can use the formula for the test statistic for a hypothesis test of a single proportion:
z = (p-hat - p) / sqrt(pq/n)
where p-hat is the sample proportion, p is the hypothesized population proportion (0.301 according to Benford's Law), q = 1 - p, and n is the sample size.
Plugging in the values given, we get:
z = (0.2278 - 0.301) / sqrt(0.301*0.699/225) = -2.83
To find the P-value, we need to find the probability that a standard normal distribution is less than -2.83 (since this is a left-tailed test). Using a standard normal table or calculator, we find this probability to be 0.0023.
Therefore, the P-value is 0.0023.
Explanation:
Methods in electrochemistry that can be used for the separation of proteins and enzymes?
Answer:
redox proteins can be attached to electrode surfaces in a “wired” configuration, that is, one that facilitates direct electron transfer. The feasibility of simple electroactive adsorption onto a range of electrode surfaces is illustrated, with a highlight on the recent advances that have been achieved in biotechnological device construction using carbon materials and metal oxides. The covalent crosslinking strategies commonly used for the modification and biofunctionalization of electrode surfaces are also evaluated. Recent innovations in harnessing chemical biology methods for electrically wiring redox biology to surfaces are emphasized.
Explanation:
many friends does each have?
2) Priscilla sells stuffed animals at a local craft show. She charges $13 for the
small ones and
$12 for the large. She sold $350 worth of animals. After the show she
noticed that she
sold 27 stuffed animals. How many were small and how many were large?
Answer:
7 large stuffed animals and 20 small ones
Explanation:
Solve the system of equations
13S + 12L = 350
S + L = 27
L = 7
S = 20
Students should not file the PROFILE any later than (blank) weeks after the earliest priority date specified by the college or the program. A. eight B. two C. four D. six
Answer:
d
because d is the most reasonable one
Students should not file the PROFILE any later than six weeks after the earliest priority date specified by the college or the program. Thsu the correct option is D.
What is a Student?A student is referred to as any individual who has enrolled themselves in any academic course or educational institution. Many colleges and universities assess a student's eligibility for need-based financial aid using the PROFILE, a standardized financial aid application.
The deadline for submitting the PROFILE in order to be considered for the first round of financial aid is known as the priority date, which varies depending on the college or program.
Prior to the overall priority date, specific colleges and programs may have PROFILE submission deadlines. For each college or program they are considering, students should examine the individual deadlines to make sure they don't miss any crucial dates.
Therefore, option D is appropriate.
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