HELPPPPPP PLZZZZ OMG :(

Using cosine rule, angle x In the triangle is

The angles are found first using cosine rule by the formula

cos A = (b² + c² - a²) ÷ 2bc

Solving for the angle x

substituting the values

cos x = (7² + 5² - 3²) ÷ 2 * 7 * 5

cos x = (65) ÷ 70

x = arc cos ( 0.9286 )

x = 21.79 degrees

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To determine the points of intersection we first equate the expressions, then we solve for x. Once we have the values of x for which the functions are equal we plu them on one of the function to find its corresponding value of y.

a)

Let's equate the functions and solve for x:

Now we find the corresponding values of y for each value of x; to do this we use the second equation.

When x=3:

Hence the functions intersect at (3,11)

When x=2:

Hence the functions intersect at (2,6)

Therefore the function intersect at the points (3,11) and (2,6).

b)

Let's equate the functions and solve for x:

Now we find the corresponding values of y for each value of x; to do this we use the second equation.

When x=7:

Hence the functions intersect at (7,-26)

When x=-1:

Hence the functions intersect at (-1,-2)

Therefore the function intersect at the points (7,-26) and (-1,-2).

Anova (Analysis of Variance) first tests for an overall difference between the means, known as a "global" or "omnibus" test.

The purpose of this test is to determine if there is a statistically significant difference in means among multiple groups or treatments. It evaluates whether there is evidence to suggest that at least one of the group means is different from the others.

The Anova test compares the variation between groups to the variation within groups to assess if the differences in means are greater than what would be expected by chance.

If the test yields a significant result, it indicates that there is sufficient evidence to conclude that the means of the groups are not all equal.

In summary, Anova serves as a preliminary test to determine if there is an overall difference between the means before conducting further analyses to identify specific group differences.

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Consider that 1 km = 1000 m, then, you have:

7 km = 7(1000 m) = 7000 m

Hence, Kay swam 7000 meters

Answer:

0.7 km = 700 meters

Step-by-step explanation:

1 km = 1000m, so 0.7 km is 7/10 of a km, or 700 m.

Answer:

I believe it would be $52.29

Step-by-step explanation:

You put $45.00 with 15% in a percentage calcuator, (math w ay might work,) which gives you 6.75 and you put the tax of 8% in a tax calculator which gives you 7.29.

Then you just add $45.00 + 7.29 = $52.29!

Hope this helps lol

Answer:

what?

Step-by-step explanation:

can you give me some more details

Answer:

30 gallons/hr

Step-by-step explanation:

180/60 = 30

Answer:

55 tickets for adults

Step-by-step explanation:

Start by setting up two equations. One equation will be the total amount of money spent and the other is the total amount of tickets sold. a is the # of adult tickets and c is the # of children tickets sold.

7a+4c=469

a+c=76

Now solve for c in the second equation. Then use that to substitute for c in the first equation.

c=76-a

7a+4(76-a)=469

7a+ 304-4a =469

7a+4a=165

3a=165

a=165/3

a=55

Answer:

picture #1 - 50.27 square units

picture #2 - 113.10 square units

picture #3 - 380.13 square units

Step-by-step explanation:

picture #1 - area = πr^2 -> π*4^2 = 50.27 square units

picture #2 - area = πr^2 -> π*6^2 = 113.10

picture #3 - area = πr^2 -> π*11^2 = 380.13

Answer:

the first and fourth quadrants

Step-by-step explanation:

We have that the time found hours is given on the x-axis and that the temperature is represented on the y-axis.

Let's first analyze time:

Time cannot be negative, therefore, the x coordinate cannot be negative therefore, for the x axis, we can use the first and fourth quadrants

Second let's analyze the temperature:

The temperature can be negative, therefore, the coordinate and can be positive or negative therefore, that for the y axis, we can use all four quadrants.

If we combine the two previous conditions, we can deduce that we can only use the first and fourth quadrants to represent the required data.

The distributive property indicates that multiplying a number by the sum of two addends is equal to multiplying each addend individually by the number and then adding the products together.

In general terms:

‎      ‏‏‎

In this exercise:

Let's apply the distributive property:

\(\mathsf{2(3w - 5y)}\)

\(= \mathsf{2(3w) - 2(5y)}\)

\(= \boxed{\mathsf{6w - 10y}}\)

‎      ‏‏‎

‎      ‏‏‎

TRUE statements regarding the transmission of pathogens via environmental surfaces are the statements in option A and B.

Pathogens can be referred to as microscopic organisms which can cause diseases and illness. They are bacteria, fungi, virus or other disease causing organisms.

These pathogens can be transmitted via environmental surfaces especially by coming in contact with contaminated surfaces. Some pathogens survive longer on surfaces, while some only survive for few minutes.

If someone is placed in a room previously occupied by an infected person, the chances of contacting that same disease is high.

Thus, the statements that are TRUE regarding the transmission of pathogens via environmental surfaces are the statements in option A and B.

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Answer:

no because she would get the same total if she added it before or after

Step-by-step explanation:

Answer:

a: The experimental probability that Mrs Patel will have to stop at this set of lights tomorrow is 32/50 = 0.64.

b: The experimental probability that she will not have to stop at the lights next Wednesday is 1 - 0.64 = 0.36.

Step-by-step explanation:

The probabilities of an event occurring based on the outcomes of an experiment is known as the experimental probability.

The experiment in this scenario involves Mrs. Patel driving herself to work every day. She stopped 32 times at this set of traffic signals during the course of the experiment's 50 working days. The experimental likelihood that she will have to stop at this set of lights tomorrow is 0.64 based on these findings.

The experimental probability is usually more accurate than the theoretical probability because it is based on actual data. However, the experimental probability can be affected by chance.

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Answer:

300%

Step-by-step explanation:

Your technically just multiplying by 3. Hope this helps

Answer:

20hm

Step-by-step explanation:

→ Remember rule a × b = ab

4h × 5m = 20hm

a least squares linear trend line is just a simple regression line with the years recoded  then it is a true statement

The simple linear regression model is;

y = mx + c

Where,

y = dependent variable

m is the slope

x is the independent variable

c is the y- intercept

The long-term trend only Least-Squares Regression Model also follows the same format except y becomes Yt and x becomes t.

The long-term trend only Least-Squares Regression Model is therefore the same as a simple linear regression only with different variable terms.

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Answer:

The answer is True. Just trust me on this one.

The measure of m∠5 = m∠6, and this equality can be justified by the Vertical Angles Theorem.

The Vertical Angles Theorem states that when two lines intersect, the pairs of vertical angles formed are congruent. In other words, if two lines intersect at a point, then the angles opposite each other (across the intersection) are equal in measure. This theorem is based on the geometric property that vertical angles are formed by a pair of opposite rays.

Given, that m∠5 = m∠6.

The measure of the numbered angle is not provided in the question, so it cannot be determined without additional information. However, if we assume that m∠5=m∠6, then the theorem that justifies this work is the Vertical Angles Theorem. According to the Vertical Angles Theorem, when two lines intersect, the vertical angles formed are congruent.

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Yes, you can find the standard error now by taking the standard deviation divided by the square root of the sample size.

The standard deviation in a data set is the mean deviation of the data from their mean.

For sample size n for a data set with data points X1, X2, X3……..Xn for exact standard deviation:

1. Calculates the arithmetic mean M of the set data by adding them all and dividing by n.

M = ( X1+X2+ X3+…..+Xn) / n

2. Calculate the deviation (D) for each data point from the mean M

D = (Xi-M) for all

3. Squaring and sum of all deviations, sum of squares (SS)

4. Divide SS by n.This quantity is the sample variance V

5. Take the square root of V.

6. This quantity is the sample standard deviation, SD.

There are some specific terms and issues to consider. If you are estimating the standard deviation of a population from a sample and the population mean $ is not known, M serves as an unbiased estimate of $. Again, SS is divided by (n-1), not n.

The resulting standard deviation is an unbiased estimate of the population standard deviation based on the sample size, n. If the population mean is known, use that mean instead of the sample mean. , and the SD of the sample is only calculated for n through SS dives.

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Answer:

answer is 3ZSM 1

Step-by-step explanation:

it has a Brainly question for something experimentable:-)

The number of one-to-one functions from f from the set {1,2,... , n} to the set {1,2,... , n} so that f(x) = x for some 1 ≤ x < n and f(n) ≠ n is \((n-1) * (n-1)! * n * (n-1)^{(n-1)}\).

To count the number of one-to-one functions satisfying the given conditions, we can break it down into two cases:

Case 1: f(x) = x for some 1 ≤ x < n

In this case, we have (n-1) choices for the value of x. Once we select x, we can assign any value from {1, 2, ..., n} except x to f(n) since f(n) ≠ n. So, there are (n-1) choices for f(n). The remaining (n-2) elements can be assigned to any of the remaining (n-2) elements. Thus, the number of such functions for this case is (n-1) * (n-1)!

Case 2: f(n) ≠ n

In this case, we have n choices for the value of f(n) since it can take any value from {1, 2, ..., n-1}. For the remaining (n-1) elements, we have (n-1) choices for each element since f(x) cannot be equal to x. Thus, the number of such functions for this case is \(n * (n-1)^{(n-1)}\).

To find the total number of functions satisfying both cases, we need to multiply the number of functions from each case. Therefore, the total number of such functions is:

Total = \((n-1) * (n-1)! * n * (n-1)^{(n-1)}\)

Note: The symbol "!" denotes the factorial function, which means multiplying all positive integers from 1 to that number. For example, 5! = 5 * 4 * 3 * 2 * 1 = 120.

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If combination requires 3 numbers ranging from 0 to 4 then number of combinations is 10.

Given A combination lock contains three numbers from 0 to 4.

Combinations refers to a technique that determines the number of possible arrangements in  a collection of items where the order of the selection does not matter.

Total numbers available to be selected are 5 from 0 to 4.

In this 0 is also included because it is also a number.

Numbers to be filled in the combination lock =3

So to calculate the combinations we need to use nCr formula in which n=5 and r=3.

Combinations=5C3

=5!/3!*(5-3)!

=5!/3!*2!

=5*4*3!/3!*2!

3! will be cancelled from numerator and denominator

=5*4/2

=10

Hence the number of possible combinations are 10.

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Answer:

x = 4 and y = 0

Step-by-step explanation:

Using the elimination method:

4(-x + 5y=-4) --> -4x + 20y = -16.

Now we add -4x + 20y = 016 and 4x + 3y = 16. This gives us 23y = 0 or just y =0.

Now we can find x by plugging in y.

-4x + 0 = -16.

Divide by -4 on both sides -> x = 4.

If you want to double check you can plug your values into -4x + 20y = -16.

-4(4) +20(0) = -16.

Answer:

Dilate by a scale factor of 0.5 with the origin as the center of dilation.

Rotate 90° clockwise about the origin

Step-by-step explanation:

Polygon ABCD:

Dilate by a scale factor of 0.5 with the origin as the center of dilation (pink polygon on attached diagram).

This means multiply the x and y values of the points by 0.5:

A → (-1, 2)

B → (-4, 1)

C → (-2, 4)

D → (-1, 3)

Rotate 90° clockwise about the origin: (x, y) → (-y, x)

A' = (-2, 1)

B' = (-1, 4)

C' = (-4, 2)

D' = (-3, 1)

So the transformations are: