The particle that should complete the reaction is 2/1H.
What is a nuclear reaction?The term nuclear reaction has to do with the process in which a change occurs in the nucleus of atoms.
We can see that the reaction shown is a nuclear fusion, from the products, we can be able to deduce that the particle that should complete the reaction is 2/1H. The complete reaction equation is therefore; \(\frac{3}{1} H + \frac{2}{1} H ---- > \frac{4}{2} He + \frac{1}{0} n + Energy\)
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A compound contains 1.2 g of carbon, 3.2 g of oxygen and 0.2g of hydrogen. Find the formula of the compound
Answer:
The empirical formula of the compound is \(C_{0.504}HO_{1.008}\).
Explanation:
We need to determine the empirical formula in its simplest form, where hydrogen (\(H\)) is scaled up to a mole, since it has the molar mass, and both carbon (\(C\)) and oxygen (\(O\)) are also scaled up in the same magnitude. The empirical formula is of the form:
\(C_{x}HO_{y}\)
Where \(x\), \(y\) are the number of moles of the carbon and oxygen, respectively.
The scale factor (\(r\)), no unit, is calculated by the following formula:
\(r = \frac{M_{H}}{m_{H}}\) (1)
Where:
\(m_{H}\) - Mass of hydrogen, in grams.
\(M_{H}\) - Molar mass of hydrogen, in grams per mole.
If we know that \(M_{H} = 1.008\,\frac{g}{mol}\) and \(m_{H} = 0.2\,g\), then the scale factor is:
\(r = \frac{1.008}{0.2}\)
\(r = 5.04\)
The molar masses of carbon (\(M_{C}\)) and oxygen (\(M_{O}\)) are \(12.011\,\frac{g}{mol}\) and \(15.999\,\frac{g}{mol}\), then, the respective numbers of moles are: (\(r = 5.04\), \(m_{C} = 1.2\,g\), \(m_{O} = 3.2\,g\))
Carbon
\(n_{C} = \frac{r\cdot m_{C}}{M_{C}}\) (2)
\(n_{C} = \frac{(5.04)\cdot (1.2\,g)}{12.011\,\frac{g}{mol} }\)
\(n_{C} = 0.504\,moles\)
Oxygen
\(n_{O} = \frac{r\cdot m_{O}}{M_{O}}\) (3)
\(n_{O} = \frac{(5.04)\cdot (3.2\,g)}{15.999\,\frac{g}{mol} }\)
\(n_{O} = 1.008\,moles\)
Hence, the empirical formula of the compound is \(C_{0.504}HO_{1.008}\).
AgCl (silver chloride)
a. List the elements by name.
b. How many atoms of each element?
C. How many total atoms in the formula?
Answer:
a. Silver; chlorine
b. One atom of Ag; one atom of Cl
c. Two atoms total
Explanation:
How does the atomic radius of an element is related to its metallic character
Answer:
The large the atomic radius the more the metallic character of elements
Explanation:
The atomic radius is related to the metallic character in a way that the larger the atomic radius, the more metallic a body becomes.
Therefore, as we go down a group, metallic character increases.
Metallic character relies on the ability and willingness of an atom to share its valence electrons. As the size of an atom becomes large, the more metallic it is and the more its metallic character. In some other cases this character is known as electropositivity.A sample of helium has a volume of 3.20x10^2 mL at STP. What will be its new volume (inL) if the temperature is increased to 425.0 K and its pressure is increased to 3.50 atm?
Let's see that the STP represents the conditions for the temperature of 0°C (273 K) and for the pressure of 1 atm.
We have this initial data and a volume of 3.20 x 10 ^(2) mL. To solve this problem, we need to use the ideal gas formula:
\(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2},\)where T is temperature, P is pressure, and V volume. Subindex 1 is the initial data and subindex 2 is the final data.
We want to find the final volume, so clearing for V2 in the formula, we're going to obtain:
\(V_2=\frac{P_1V_1T_2}{T_1P_2}\text{.}\)And the final step is replacing the data that we have, where the final data is 425.0 K and 3.50 atm (remember that the volume must be in liters, 1 liter is 1000 mL, so 3.20 x 10^2 mL is 0.32 L):
\(\begin{gathered} V_2=\frac{1\text{ atm }\cdot\text{ 0}.32\text{ L }\cdot425.0K}{273\text{ K }\cdot\text{ 3.50 atm}}, \\ V_2=0.14\text{ L.} \end{gathered}\)The answer is that the new volume of the sample of helium would be 0.14 L.
Given this reaction 2KClO3 → 2KCl + 3O2. How many particles of O2 are produced for 4 moles of KClO3?
A. 3.61 x 10^24 particles
B. 6.1 x 10^23 particles
C. 6.02 x 10^23 particles
D. 1.61 x 10^24 particles
According to stoichiometry and concept of Avogadro's number there are 3.61×10²⁴ particles for 4 moles of KClO₃.
As 2 moles of potassium chlorate gives 3 moles of oxygen , thus 4 moles of potassium chlorate will give 4×3/2=6 moles , 6 moles have 6×6.023×10²³=3.61×10²⁴ particles.
Thus, there are 3.61×10²⁴ particles for 4 moles of KClO₃.
What is stoichiometry?
It involves figuring out how much of each element or molecule there are in a chemical process. The laws of conservation of mass and combining weights and volumes serve as the foundation for the linked relations.In quantitative analysis, stoichiometry is used to determine the concentrations of the compounds contained in the sample.To know more about stoichiometry, click the link given below:
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Consider the following system at equilibrium where Kc = 9.52×10-2 and H° = 18.8 kJ/mol at 350 K. CH4 (g) + CCl4 (g) goes to 2 CH2Cl2 (g) The production of CH2Cl2 (g) is favored by: Indicate True (T) or False (F) for each of the following: 1. decreasing the temperature. 2. decreasing the pressure (by changing the volume). 3. increasing the volume. 4. removing CH2Cl2 . 5. removing CCl4 .
(1) decreasing the temperature- True, (2)decreasing the pressure (by changing the volume)-False, (3) increasing the volume-True, (4) removing CH2Cl2-False, (5) removing CCl4-False
According to Le Chatelier's principle, if a system at equilibrium is subjected to a change, the system will adjust to reestablish the equilibrium. The production of CH2Cl2 (g) is favored by decreasing the temperature and increasing the volume, and is disfavored by decreasing the volume, removing CH2Cl2, and removing CCl4.
1. True - Decreasing the temperature will shift the equilibrium towards the side with higher enthalpy, which in this case is the production of CH2Cl2 (g).
2. False - Decreasing the pressure (by changing the volume) will cause the system to shift towards the side with a higher number of moles, which in this case is the reactant side. Therefore, it will not favor the production of CH2Cl2 (g).
3. True - Increasing the volume will decrease the pressure and cause the system to shift towards the side with a higher number of moles, which in this case is the production of CH2Cl2 (g).
4. False - Removing CH2Cl2 will cause the system to adjust by producing more CH2Cl2 to reestablish the equilibrium, so it will not favor the production of CH2Cl2 (g).
5. False - Removing CCl4 will cause the system to adjust by producing more CCl4 to reestablish the equilibrium, so it will not favor the production of CH2Cl2 (g).
In summary, the production of CH2Cl2 (g) is favored by decreasing the temperature and increasing the volume, while it is disfavored by decreasing the volume, removing CH2Cl2, and removing CCl4.
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put a y Aluminum in the excess H2SO4 solution, get 13.44 liters of H2 dktc and mg of Salt Calculate a and m?
From the equation of the reaction and the volume of hydrogen gas produced, a = 10.8 g and m = 68.4 g
What mass of salt is produced when aluminium metal reacts with excess H2SO4 solution?The equation of the reaction reaction of aluminium metal in H2SO4 solution is given as follows:
\(2 \: Al(s) + 3 \: H_{2}SO_{4} \rightarrow Al_{2}(SO_{4})_{3} + 3 \: H_{2}(g) \\ \)
2 moles of aluminium produces 3 moles of hydrogen gas.
Moles of hydrogen gas in 13.44 liters =13.44/22.4 = 0.6 moles
Moles of aluminium required = 0.6 × 2/3 = 0.4 moles
Molar mass of aluminium = 27 g/mol
Mass of aluminium = 0.4 × 27 = 10.8 g
Moles of salt produced = 0.6 × 1/3 = 0.2 moles
Molar mass of salt = 342 g/mol
Mass of salt = 0.2 × 342 = 68.4 g
Therefore, a = 10.8 g and m = 68.4 g
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one method of removing phosphate from wastewater effluent is to precipitate it with aluminium sulfate (alum). a possible stoichiometry (but not exact because aluminium and phosphate can form many different chemical materials) is: 2 po43- al2(so4)3 -------> 2 alpo4 3 so42- if the concentration of phosphate (po43-) is 30 mg/l, how many kg of alum must be purchased annually to treat 40l/s of wastewater?
The amount of alum that must be purchased annually to treat 40 liters/second of wastewater is 31,536 kg/year.
Given the concentration of phosphate = 30mg/L
Given that 1 liter of water is equal to 1 kilogram, we can calculate the total amount of water (in kilograms) that needs to be treated annually:
40 liters/second x 60 seconds/minute x 60 minutes/hour x 24 hours/day x 365 days/year = 1,051,200,000 liters/year = 1,051,200,000 kg/year
Now, we need to determine the amount of phosphate that needs to be removed, which can be calculated using the given concentration of phosphate (30 mg/l):
30 mg/L x 1,051,200,000 kg/year = 31,536,000,000 mg/year = 31,536 kg/year
Finally, we can calculate the amount of alum that needs to be purchased to remove this amount of phosphate, using the given stoichiometry:
31,536 kg/year of phosphate x (2 kg of alum/2 kg of phosphate) = 31,536 kg/year of alum
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Kilograms represented by the mass defect for oxygen-16: 2. 20 × 10 -28 kg What is the nuclear binding energy for oxygen-16? 3. 0 × 108 J 6. 60 × 10-20 J 1. 98 × 10 -11 J 3. 69 x 10-24 J.
The nuclear binding energy for oxygen-16 is 1. 98 × 10 ⁻¹¹ J.
The nuclear binding energy is the energy required to completely separate the nucleons (protons and neutrons) in a nucleus. It can be calculated using the mass defect of the nucleus, which is the difference between the mass of the nucleus and the sum of the masses of its individual nucleons.
The mass defect for oxygen-16 is given as 2.20 × 10 ⁻²⁸ kg.
Using the equation E=mc²,
where E is energy, m is mass,
and c is the speed of light, we can calculate the nuclear binding energy.
First, we convert the mass defect to kilograms, which gives 2.20 × 10⁻³¹ kg.
Then, we multiply by the square of the speed of light, which is (3 × 10⁸ m/s)² = 9 × 10¹⁶ m²/s².
This gives an energy of 1.98 × 10⁻¹¹ J.
Therefore, the nuclear binding energy for oxygen-16 is 1.98 × 10 ⁻¹¹ J.
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What is the ph of a solution which is 0. 025 m in weak base and 0. 039 m in the conjugate weak acid ( a = 7. 1 × 10−6)?
The pH of the solution is 4.96.
pH measures the amount of hydrogen and hydroxide ions in a solution and shows how acidic or alkaline it is.
Weak bases are the solutions to substances that do not dissociate completely in water. Conjugate acids are the product formed by the base and have a difference of one proton.
Using the base dissociation constant, Ka
pKa can be calculated as,
\(pKa = - log (Ka)\)
\(= - log (7.1 * 10^-6)\)
\(= 5.15\)
0. 025 M in the weak base and 0. 039 M in the conjugate weak acid.
Therefore, a weak base and its conjugate acid are present in equal proportions in buffer solution. As we are aware, the Henderson-Hasselbalch equation can be used to determine the pH of a buffer solution that comprises a weak base and its conjugate acid.
\(pH = pK + log [\frac{A^-}{HA} ]\\\)
\(= 5.15 + log( \frac{0.025}{0.037})\)
\(=5.15 + log 0.64\)
\(=5.15-0.19\)
\(=4.96\)
Therefore, the pH of the solution is 4.96.
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PLEASE HELP ASAP :)
Which electrode is the anode in a galvanic cell?
A. The electrode that removes ions from solution
Ο Ο
B. The electrode with the highest reduction potential
C. The electrode where a reduction reaction occurs
O O
D. The electrode with the highest oxidation potential
SUBMIT
Answer:
D
Explanation:
I just took the quiz on a pex
The electrode is the anode in a galvanic cell should be option d. The electrode with the highest oxidation potential.
What is an electrode?The electrode should be lies in the left half-cell to represent the anode since oxidation should be arise here.
Here the flow of anions should be in the salt that bridges towards it. In the right half-cell that represent the cathode since the reduction arise here.
Hence, the option d is correct.
And the rest of the options are wrong.
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WILL MARK BRAINLIEST! 100 POINTS!
A solution of 0.2 M sulfuric acid is titrated with a 0.2 M basic solution. In three to five sentences, explain how you can use the results of the titration as evidence for the ratio of sulfuric acid and the base in the balanced chemical reaction for the titration.
(Please answer in three to five sentences)
If there are 0.2 M solutions of both acid and base, the concentrations of hydrogen and hydroxide ions will be equal at equivalence point.
The reaction of sulfuric acid and a basic solution BOH occurs as follows;
H2SO4(aq) + 2BOH(aq) -----> B2SO4(aq) + 2H2O(l)
In the question, we are told that that both the solution of the sulfuric acid and the basic solution are 0.2 M.
The point where all the hydrogen and hydroxide ions have reacted according to the stoichiometry of the reaction. If there is really equimolar amounts of acid and base, the concentration of hydrogen and hydroxide ions will be equal at equivalence point.
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this is a reddish-brown irritating gas that gives photochemical smog its brownish color; in the atmosphere it can also be converted in the atmosphere into an acid that is one of the major component of acid deposition, what is this substance? (if you use the chemical formula don't use subscripts instead just use numbers example c6h12o6)
The substance that gives photochemical smog its brownish color is Nitrogen dioxide.
Nitrogen dioxide (NO2) is a reddish-brown irritating gas that is a prominent air pollutant. In the atmosphere, NO2 can be converted into an acid, which is one of the main components of acid deposition, when it combines with water, oxygen, and other chemicals. Nitrogen dioxide is one of the primary pollutants in urban areas.
When NO2 and other chemicals in the atmosphere come into contact with sunlight, they produce photochemical smog, which is a type of air pollution that appears as a brownish haze.
Nitrogen dioxide is formed when nitrogen oxides (NOx) react with sunlight and other atmospheric compounds. Nitrogen oxides are produced by a variety of natural and human activities. For example, NOx can be produced by vehicle exhaust, power plants, and other industrial sources.
Nitrogen dioxide has a wide range of negative health and environmental consequences. NO2 is also one of the primary constituents of acid rain, which is a type of precipitation that is acidic.
Acid rain has a significant impact on the environment and human health. When it falls to the ground, it can cause damage to plants, animals, and ecosystems. Acid rain can also cause respiratory problems in humans and other animals.
In conclusion, nitrogen dioxide is a reddish-brown irritating gas that is a significant air pollutant. Nitrogen dioxide, along with other pollutants, contributes to the formation of photochemical smog and acid rain, both of which have significant health and environmental consequences.
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How to know when a line spectrum is produced.
A line spectrum is produced when the electron moves from one energy level ___. Fill in the blank PLEASE HELP I WILL GIVE BRAINLEST AND GIVE 5 STAR FOR FIRST RIGHT ANSWER
Answer:
A line spectrum is produced when the electron moves from one energy level to a lower energy level.
Answer:
Explanation:
...from one energy level to a lower energy level
Electrons are subatomic particles that exist
The magnitude of an earthquake is its:
a. strength
b. length
c. origination point
d. location
26. Which type of seismic wave is the first to hit the surface and has the highest frequency?
a. P-wave
b. S-wave
c. Surface wave
d. Body wave
27. Which type of seismic wave compresses and expands like an accordion?
a. P-wave
b. S-wave
c. Surface wave
d. Body wave
28. Which type of seismic wave causes the most damage and destruction associated with earthquakes?
a. P-wave
b. S-wave
c. Surface wave
d. Body wave
29. Which type of seismic wave travels on the Earth’s surface?
a. P-wave
b. S-wave
c. Surface wave
d. Body wave
30. What is the name of the point of an earthquake below the surface where the rock breaks?
a. epicenter
b. focus
c. fault
d. seismic
31. What is the name of the point of an earthquake on the surface directly above the point of breakage?
a. epicenter
b. focus
c. fault
d. seismic
32. Soil is made of several components. Which of the following is NOT one of the components of soil?
A. air
B. oxidation
C. decayed organic matter
D. water
33. Which is NOT organic matter?
A. animal waste
B. dead insects
C. decayed leaves
D. mineral fragments
34. All of the following are examples of erosion EXCEPT:
A. The wind in the desert blows sand against a rock.
B. A glacier picks up a boulder as it moves.
C. A flood washes over a river bank and water carries sediment away.
D. An icy winter causes the pavement in the road to crack.
35. What are biota?
A. all the living organisms in an area
B. all the nonliving organisms in an area
C. only the living organisms in the soil
D. only the nonliving organisms in the soil
36. In the water cycle, the term that describes when plants and trees release water into the atmosphere:
Precipitation
Transpiration
Evaporation
Condensation
37. The process by which water on the ground surface enters the soil:
Infiltration
Condensation
Evaporation
Transpiration
38. How much of Earth’s freshwater is in rivers, lakes, and streams?
a. about ¾
b. less than 3%
c. about 69%
d. less than 1%
39. What happens to solar energy that strikes ice or snow?
a. most of it is absorbed by the ice and snow
b. most of it is reflected back into space
c. half of it is reflected back into space and half of it is absorbed
d. all of it is reflected back into space and none of it is absorbed
40. In the water cycle, water evaporates, then condenses and falls back to the surface as precipitation. What kind of water returns to the surface that has evaporated from oceans?
a. freshwater
b. salt water
c. an even mixture of fresh and salt water
d. mostly freshwater with about 10% salt water mixed in
41. . Alpine glaciers are in:
a. ice shelves
b. ice sheets
c. oceans
d. mountain valleys
42. Which of the following is NOT an advantage of wetlands?
a. Wetlands help control flooding by absorbing runoff from heavy rains.
b. Wetlands provide habitats for many different species of plant and animal life.
c. Wetlands erode channels that carry water and sediment downhill away from the animal habitats.
d. Wetlands provide a natural filtration system by preventing sediments and pollution from reaching streams, lakes, and other bodies of water.
Describe the relationship between weathering and soil.
A. Weathering breaks rock into inorganic matter, which is then decomposed into parent material for soil.
B. Parent material weathers and becomes sediment, which is then decomposed by oxidation into soil.
C. Weathering breaks rock into sediment, which provides the parent material for soil.
D. Oxidation causes chemical weathering, which causes the weathered rock to decompose into soil.
45. Which of the following processes most directly helps create soil from rocks?
A. melting
B. pressure
C. plate tectonics
D. weathering
Answer:
25 size or length.
26 P wave (primary wave)27 P wave28 Surface waves29 Body waves30 Epicentre 31 Epicentre 32 Oxidation33 Mineral Fragments 34 C.35 C.36 Transpiration.37 . infiltration 38. 0.339.C40.D.41.D.42.B.4 3 . weatheringAnswer:
25) Length
26) P-wave
27) P-wave
28) Surface wave
29) Body wave
30) epicenter
And so many more
Prepare 280ml of 35% alcohol from a stock solution of 95% alcohol
Applying the concept of molar concentration to percent solutions, 8.84 ml of 95% alcohol is required to prepare 280ml of 35% alcohol .
What is percent solution?Percent solution is defined as a convenient way to record concentration of solution.It is a expression which relates solute to solvent as,mass of solute/mass of solution ×100.There are two types of percentage solutions percent weight by volume and percent volume by volume .Advantages of using percent solutions is that molecular weight of compound is not required.
In case where a percent solution is to be prepared from another percent solution applying formula C₁V₁=C₂V₂
Substitution in formula gives, 35×280=95×V₂
∴V₂=35×280/95=8.84 ml.
Thus, 8.84 ml of 95% alcohol is required to prepare 280ml of 35% alcohol .
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DOES ANYONE KNOW THE ANSWER?
Answer:
You can only be able to solve two variables, k and x based on what you input as your question
k= -2x+3
x= (3-k)/2
Explanation:
What is the hydrogen ion concentration of a solution with ph = 2. 25?.
Write a balanced chemical equation for the standard formation reaction of gaseous hydrogen bromide (hbr)
\(\\ \sf\longmapsto H_2+Br_2\longrightarrow HBr\)
Balanced equation\(\\ \sf\longmapsto H_2+Br_2\longrightarrow 2HBr\)
On reactant side:-
H=2Br=2On products side
H=2Br=2The balanced chemical equation for the synthesis of hydrogen bromide is \(\rm H_2\;+\;Br_2\;\rightarrow\;2\;HBr\).
What is a balanced chemical equation?The balanced chemical equation has been given as the reaction in which the number of atoms for each element on the product and the reactant side is equal.
The HBr has been formed with the reaction of the hydrogen and the bromine. The balanced chemical equation for the reaction has been:
\(\rm H_2\;+\;Br_2\;\rightarrow\;2\;HBr\)
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An FM radio station broadcasts at a frequency of 107.9 Hz. What is the
wavelength of the radio signal
Answer:
2.78035217*10^6 m
Explanation:
C = v
3.0e8 = (107.9)
= 2.78035217*10^6 m
which of the following correctly represents the radioactive decay of cesium-137?
A(n) _________is a pure chemical substance with its own characteristic atomic structure and chemical properties as a result of its unique arrangement of protons, neutrons, and electrons.
An element is a substance with its own characteristic structure and chemical properties as a result of its unique arrangement of protons, neutrons, and electrons.
What is an element?An element (also called atomic structural compound), is a particular chemical substance that contains a given amount of subatomic particles, which include protons (positive charge), neutrons, and electrons (negative).
In conclusion, an element is a pure chemical substance with its own characteristic atomic structure and chemical properties as a result of its unique arrangement of protons, neutrons, and electrons.
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Matches=from Chemical energy to light energy+heat energy
Explanation:
A matchstick has a lot of chemical energy stored in it. When the match is struck, it burns and the chemical energy in it produces heat energy and light energy.
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Compounds have no charge. True or False
Answer:
False.
Compounds can have a charge. A compound is a substance made up of two or more elements that are chemically bonded together. The charge on a compound depends on the number of electrons in the outermost energy level, or valence electrons, of the atoms that make up the compound. If the compound has an equal number of protons and electrons, it will have no charge, and is called a neutral compound.
However, if there is an unequal number of protons and electrons, the compound will have a charge and is called an ionic compound. For example, the compound sodium chloride, NaCl, is made up of positively charged sodium ions and negatively charged chloride ions, and therefore has an overall charge of neutral.
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empirical formula for C3O6
Answer:
CO2
Explanation:
You have 3 C for 6 O, then the empirical will be 1 C for 2 O
=> CO2
in the standardization part, how would the calculated naoh concentration be affected if some of the acid solution were splashed onto the flask walls and was not rinsed down before reaching the end point? would it be higher than the actual concentration, lower, or would there be no effect? explain.
The outcome won't be exact. Any liquid, including basic and acidic liquids, could contaminate it.
Why do we standardize the NaOH solution ?To determine the precise concentration of a solution whose concentration is unknown, a NaOH solution must be standardized. To obtain an equivalence point and determine the unknown concentration, standardization involves titrating a known volume of NaOH with an acid in a flask.
Purpose of standardizing the NaOH solution :To determine the precise concentration, you will standardize a NaOH solution in this experiment. You will use standardized NaOH to calculate the concentrations of HCl and HC2H3O2 solutions in subsequent experiments. You'll discover various indicators for endpoint detection.
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Consider the following half-reaction balanced for an acidic solution: 2H2O + SeO2 → SeO42- + 4H+ + 2e-. What is the balanced half-reaction for a basic solution?
Answer
\(SeO_2+4OH^-\rightarrow SeO^{2-}_4+2H_2O+2e^-\)Explanation
The given balanced half-reaction for an acidic solution:
\(2H_2O+SeO_2\rightarrow SeO^{2-}_4+4H^++2e^-\)What to find:
Tha balanced half-reaction for a basic solution.
Step-by-step-solution:
To balance the half-reaction for a basic solution;
1. Add OH⁻ ions to BOTH SIDES to neutralize any H⁺
\(2H_2O+SeO_2+4OH^-\rightarrow SeO^{2-}_4+4H^++4OH^-+2e^-\)2. Combine H+ and OH- to make H2O.
\(2H_2O+SeO_2+4OH^-\rightarrow SeO^{2-}_4+4H_2O+2e^-\)3. Simplify by canceling out excess H2O
\(SeO_2+4OH^-\rightarrow SeO^{2-}_4+2H_2O+2e^-\)4. Balance the charges by adding e-
\(SeO_2+4OH^-\rightarrow SeO^{2-}_4+2H_2O+2e^-\)
In an atom, the number of protons equals the number of
A.nuclei.
b. electrons.
neutrons.
d. isotopes.
c.
The number of protons is equal to the number of electrons.
The atom has 2 different types of subatomic particles.
True or False
Answer:
False
Explanation:
There is three