Help: The diagram below illustrates a light ray bouncing off a surface. Fill in the boxes with the correct terms.

Answer:

Held

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Answer:

1. 12 g/cm³

2. 0.5 m

Explanation:

1.

The weight of the gold is 240 g

The volume is 20 cm³

Density = Mass/ volume

Density = 240 / 20 = 12 g/cm³

2.

The formula for moment of a force is ;

Force * distance perpendicular  between force and the turning point of force

Given that the moment of force is 12.5 Nm and force is 25 N  then the perpendicular distance between the force and the turning point will be;

12.5 = 25 * d

12.5/25 = d

0.5 = d

d= 0.5 m

Angle 32rad turn during that time if the angular acceleration is constant.

What is acceleration?

acceleration, rate at which the velocity changes with time, in terms of both speed and the direction. A point or else it's an  object moving in a straighten line is accelerated if it is  speeds up or slows down. Motion on a circle is the accelerated even if the  speed is constant, because of  the direction is continually changing.

Sol-  In an uniformly accelerated circular motion, the angle traveled by the object is given by- ∆=wf+wo/2×t
Here  wf is the final angular speed.
It is the initial angular speed and t is the time of the motion. Replacing the given values-

∆= 12 rad/s + 4 rad/s /2 (4s)

∆= 32rad .

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EM energy is like a wave as well as a particle. The concept of wave-particle duality is accounted for in the Quantum Mechanical model.

How is EM energy like a wave?

EM energy is like a wave in a way that it travels from one place to another. This travel is similar to the waves found in a water body that travel from one place to another.

In other words, it travels as a disturbance in a medium or even vacuum that doesn’t need a medium.

In addition, EM waves have features of waves like diffraction, reflection, and interference.

How is EM energy like a particle?

EM energy is also like a particle as it can also act like a particle. An example of this is the photon. Photons are energy particles that have wave-particle duality.

These particles can have particle-like behavior such as being emitted from a source, hitting a target, and interacting with the environment like other particles.

Thus, they act like a wave as well as a particle.

What model accounts for both of these characteristics? The Quantum Mechanical model accounts for both these characteristics, the wave-like and particle-like behavior of EM energy.

It explains that the energy of EM waves is quantized and its energy comes in packets known as photons. These photons can act as particles as well as waves in different situations.

The wave-particle duality is thus accounted for in the Quantum Mechanical model.

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1.  a) no charge

2. a) a transverse wave

3. d) all of the above.

4. a) greater than that of radio waves.

5. b) lower than that of radio waves.

6. d) all of the above.

7. d) all of the above.

8. d) all of the above

9. a) exist for all particles

10. a) modifies classical results

11.  b) the returnee is younger

12. d) all of the above statements are correct.

1. An electromagnetic wave consists of oscillating electric and magnetic fields that propagate through space. It does not carry any net charge.

2. Electromagnetic waves are transverse waves, meaning that the direction of the electric and magnetic fields is perpendicular to the direction of wave propagation.

3. Light exhibits both wave-like and particle-like behavior, as described by the wave-particle duality principle in quantum mechanics.

4. Gamma rays have a higher frequency than radio waves, which means they have more oscillations per unit of time.

5. Gamma rays have a shorter wavelength than radio waves, indicating that the distance between successive wave crests is smaller.

6. When a tree is located 20 meters from a convex lens with a focal length of 10 cm, the image formed is inverted (upside down), diminished (smaller in size compared to the object), and real (can be projected on a screen).

7. An arrow placed 2 cm from a convex lens with a focal length of 5 cm will produce an erect (upright), virtual (cannot be projected on a screen), and magnified (larger in size compared to the object) image.

8. A parabolic mirror, such as a parabolic reflector or a parabolic antenna, has the property of focusing all parallel rays of light (or electromagnetic waves) to a single point called the focus. It also reflects rays originating from the focus in a parallel direction, which is useful for applications like satellite dish antennas. Furthermore, parabolic mirrors can work for a wide range of electromagnetic waves, including radio waves.

9. De Broglie waves, proposed by Louis de Broglie, suggest that particles, such as electrons and protons, exhibit wave-like properties. They are not limited to sound waves or specific particles like hydrogen. De Broglie waves play a crucial role in understanding the wave-particle duality of matter.

10. The Lorentz factor, denoted as γ (gamma), is a term in special relativity. It modifies classical results as objects approach the speed of light, accounting for time dilation, length contraction, and relativistic mass increase. It is a key factor in understanding the effects of high-speed motion and is not limited to geometric optics.

11. In the Twin Paradox scenario, the traveling twin experiences time dilation due to their high velocity, causing them to age slower compared to the twin who stays at home. Thus, when they reunite, (b) the returnee is younger. This phenomenon is a consequence of special relativity and has been confirmed by experiments and observations.

12. Bohr's atomic model describes electrons in discrete energy levels or orbits. According to the model, electrons can jump to lower orbits, emitting photons in the process. They can also spontaneously jump to higher orbits. Additionally, the model suggests that the electron orbit would eventually decay, resulting in the electron spiraling into the proton. However, this aspect is not consistent with modern understanding and is considered a limitation of Bohr's model.

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Answer:

I would think the first and the third answer

Answer:

i would say 3rd cause other may slightly effect

The magnitude of gravitational force acting on the space junk by the satellite is determined by the masses of the objects and the distance between them.

To calculate the magnitude of the gravitational force acting on the space junk by the satellite, you need to use the formula for gravitational force: F = G × (m1 × m2) / r² where: - F is the gravitational force, - G is the gravitational constant (approximately 6.674 × 10⁻¹¹ N m²/kg²), - m1 and m2 are the masses of the satellite and space junk, respectively, - r is the distance between the centers of mass of the satellite and space junk.

The larger the masses and the closer the objects are, the stronger the gravitational force. However, it is important to note that space junk is typically not in orbit around a satellite and therefore not subject to its gravitational force. Instead, space junk is affected by the gravitational force of the Earth and other celestial bodies, as well as other forces such as atmospheric drag and solar radiation pressure.

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If a space rover has a mass of 3900 kg on Earth, then its mass when it lands on Mars will be the same i.e. 3900 kg.

Mass is the amount of matter present in the object.

The mass of the object is always constant, anywhere it is on the Earth or Moon or any other planet.

Thus, If a space rover has a mass of 3900 kg on Earth, the mass on Mars when it lands will be 3900kg.

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Answer:6000

Explanation:

Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2. We use Joules, kilograms, and meters per second as our defaults, although any appropriate units for mass (grams, ounces, etc.) or velocity (miles per hour, millimeters per second, etc.) could certainly be used as well - the calculation is the same regardless.

The efficiency of this machine is 66.67%.

What is efficiency?

Efficiency is a measure of how well a machine or system is able to convert input energy into useful output energy. It is a ratio of the output energy to the input energy, expressed as a percentage.

An efficient machine or system is one that is able to convert a large portion of the input energy into useful output energy, with minimal energy loss. Conversely, an inefficient machine or system is one that loses a significant portion of the input energy as waste heat, sound, or other forms of energy that are not useful to the desired output.

The efficiency of a machine can be calculated using the formula:

Efficiency = (Energy Output / Energy Input) x 100%

In this case, the energy input is 7.55 and the energy output is 5.05, so we can calculate the efficiency as follows:

Efficiency = (5.05 / 7.55) x 100% = 66.67%

Therefore, the efficiency of this machine is 66.67%.

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\(\boxed{\sf v^2-u^2=2gh}\)

\(\\ \sf\longmapsto h=\dfrac{v^2-u^2}{2g}\)

\(\\ \sf\longmapsto h=\dfrac{0^2-15.5^2}{2(10)}\)

\(\\ \sf\longmapsto h=\dfrac{240.25}{20}\)

\(\\ \sf\longmapsto h=12.012m\)

A radio wave travels at the speed of light, which is equal to approximately 300,000 km/s.

So, to travel a distance of 998.25 km, the time needed is:

Therefore the time required is approximately 3327.5 microseconds.

a) The weight of the box of textbooks can be calculated as follows;

Weight of

box= mass × acceleration due to gravity

Where mass= 55 kg

Acceleration due to

gravity= 9.8 m/s²Thus, the weight of the box of textbooks is given by;

Weight of

box= 55 kg× 9.8 m/s²= 539 N

the weight of the box of textbooks is 539 N.

b) The coefficient of friction can be calculated using the formula;Coefficient of friction= frictional force/ Normal forceWhere, frictional force is the force required to keep the box moving at constant velocity and normal force is the force acting on the box perpendicular to the surface on which the box is resting.

The force F of the student pushing the box can be resolved into its horizontal and vertical components as follows;

F_x= 320 N (this is the horizontal component of the force)F_y=

(This is the vertical component of the force)Thus, the normal force on the box is given by;

F_y= Normal forceNormal force= weight of box= 539 NThe frictional force is given by.

F_f= F_x= 320 NThe coefficient of friction is given by;Coefficient of friction= frictional force/ Normal forceCoefficient of friction= F_f/ F_yCoefficient of friction= 320 N/ 539 NCoefficient of friction= 0.593Therefore, the coefficient of friction is 0.593.

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Answer:

Radio waves

Explanation:

The wavelength of the microwave, given that it is moving at a speed of 3.6×10⁸ m/s is 3 m (last option)

From the question given above, the following data were obtained:

The wavelength of the microwave can be obtained as shown below:

Velocity (v) = wavelength (λ) × frequency (f)

3.6×10⁸ = wavelength × 1.2×10⁸

Divide both sides by 1.2×10⁸

Wavelength = 3.6×10⁸ / 1.2×10⁸

Wavelength = 3 m

Thus, from the above calculation, we can conclude that the wavelength of the microwave is 3 m (last option)

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A surface low-pressure center is generally associated with a trough on an upper level isobaric chart.

A constant pressure chart, sometimes referred to as an upper-level isobaric chart, shows the distribution of atmospheric pressure at a particular height in the atmosphere, usually above the surface. Isobars, or lines of equal pressure, are displayed on this graph to show the pressure distribution at that level.

When we have a surface low-pressure centre, it denotes a region with relatively lower surface pressure than the surrounding areas. This surface low-pressure system often corresponds to a trough on the upper-level isobaric chart in terms of the vertical structure of the atmosphere.

On an upper-level chart, a trough is an area with relatively lower heights or pressure. The contour lines that reflect the height or pressure field have a curvature or a dip that defines it. The contour lines have a dip in them, which indicates a surface low-pressure system beneath.

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Answer:

A=4

B=3

c=2

D=1

Explanation:

since the person moving in opposite direction so displacement =distance in east/west - distance in west/east

The  semi-major axis of an elliptical planetary orbit is equal to the distance between the planets and the Sun at aphelion.

The term semi major axis refers to a half of the of the distance from middle of an ellipse to another end of the ellipse.

Recall that the solar system has the sun at the center if the ellipse. Hence, the  semi-major axis of an elliptical planetary orbit is equal to the distance between the planets and the Sun at aphelion.

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Answer:

because  of the mass so that would help

Explanation:

The velocity of the ball after it hits the bottle is 15.8 m/s

Let m₁ represent the mass of the ball, m₂ the mass of the bottle, u₁ the velocity of ball before impact, u₂ the velocity of bottle before impact, v₁ the velocity of ball after impact and v₂ the velocity of bottle after impact.

Given that:

m₁ = 0.7 kg, m₂ = 0.15 kg, u₁ = 22 m/s, u₂ = 0, v₂ = 29

momentum before impact = momentum after impact, hence:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

0.7(22) + 0.15(0) = 0.7v₁ + 0.15(29)

0.7v₁ = 11.05

v₁ = 15.8 m/s

Therefore the velocity of the ball after it hits the bottle is 15.8 m/s

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Answer: A satellite with a mass of 110 kg and a kinetic energy of 3.08×10^9 J must be moving at a speed of 7483 m/s.

Explanation: To find the answer we need to know about the kinetic energy of a body.

                                   \(KE=\frac{1}{2}mv^2\)

                                   \(m=110kg\\KE=3.08*10^9J\\\)

                               \(v=\sqrt{\frac{2KE}{m} } =\sqrt{\frac{2*3.08*10^9}{110} } =7.483*10^3 m/s\)

Thus, we can conclude that, the velocity of the satellite will be 7438m/s.

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In order to move at a speed of 7483 m/s, a satellite with a mass of 110 kg and a kinetic energy of 3.08× 10^-9 J must be travelling.

Understanding a body's kinetic energy is necessary in order to determine the solution.

                         \(KE=\frac{1}{2}mV^2\)

               \(m=110kg\\KE=3.08*10^9J\)

                        \(V=\sqrt{\frac{2KE}{m} }=7.48km/s\)

Thus, we can infer that the satellite will move at a speed of 7438 m/s.

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Answer:

6.35hours

Explanation:

s=vt

t=s/v=502/79=6.35hours

Answer:

3.125×10²¹ N/C

Explanation:

Electric Field: This can be defined as the force experienced per unit charge. The S.I unit of electric Field is N/C

Applying,

E = F/q.................. Equation 1

Where E = Electric Field, F = Force experienced, q = Charge of an electron.

From the question,

Given: F = 500 N, q = 1.6×10⁻¹⁹ C

Substitute these values into equation 1

E = 500/(1.6×10⁻¹⁹)

E = 312.5×10¹⁹

E = 3.125×10²¹ N/C

The object moved a displacement of 1125 m.

Velocity of an object is defined as the time rate of change of its displacement.

Here,

Velocity of the object, v = 75 m/s

Time taken for travelling, t = 15 s

We know that, the velocity is the displacement covered per unit time.

v = d/t

Therefore, the displacement covered by the object,

d = v x t

d = 75 x 15

d = 1125 m

Hence,

The object moved a displacement of 1125 m.

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Answer:

Momentum = 2,400 Pa

Explanation:

Given:

Total mass = 60 kg

Distance travel = 200 m

Time = 5 sec

Find:

Momentum

Computation:

Velocity = Distance / time

Velocity = 200 / 5

Velocity = 40 m/s

Momentum = Mass x Velocity

Momentum = 60 x 40

Momentum = 2,400 Pa

Answer:

One would need to know how far apart the towns are:

T = SA / 40      time it takes for first cyclist to travel S1

T = SB / 60       time it takes for cyclist B to travel distance S2

SA + SB = S     the distance between the towns

SB = 60 / 40 SA = 1.5 SA

SA + 1.5 SA = S

S = 2.5 SA where cyclist travels distance SA

The time will depend on the separation of the towns.