HELP PLZ I DONT HAVE MUCH TIME!!! 38PTS IS ALL I HAVE PLS ANSWER CORRECTLY!!!

In Ms. Miller's English class, students are given five tests in a semester. At the end of the semester, the scores that a student has earned on the five tests are averaged to obtain that student's class average. So far, DeShawn has taken the first four tests, and his scores are 71%, 90%, 82%, and 77%. Which of the following is the range of all the class averages that DeShawn could possibly receive at the end of the semester?

Answer:

The domain is -7, 0, and 5

The range is -1, 0, and 8

Step-by-step explanation:

The domain of a set of points is the x-value. In this case the x-values are -7, 0, and 5 respectively. The range of a set of points is the y-value so in this case the range is -1, 0, and 8.

To calculate the expected payoff of the raffle we need to find the weighted average of the prize. To do this will sum all the available prizes and divide it by the number of tickets. We have:

The expected payoff of the raffle is $13.4

Okay, here are the steps to find the p-value:

1) The nationwide proportion of Americans who invest in the stock market is 55% (0.55)

2) The test statistic for Georgia is 1.75

3) To calculate the p-value, we need to know the degrees of freedom (df) and the critical value of the test statistic.

4) The df = 1, since we're comparing a single proportion (Georgia) to a fixed value (national average).

5) The critical value at df = 1 and 95% confidence is 3.84 (for a two-tailed test)

6) Since the test statistic of 1.75 is less than 3.84, we look up 1.75 in tables to find the p-value.

7) For a test statistic of 1.75 and df = 1, the p-value is 0.1860.

So the p-value to test if the proportion of Georgians who invest in the stock market is different than the nationwide average is 0.1860.

Let me know if you have any other questions!

Okay, here are the steps to find the p-value:

1) The nationwide proportion of Americans who invest in the stock market is 55% (0.55)

2) The test statistic for Georgia is 1.75

3) To calculate the p-value, we need to know the degrees of freedom (df) and the critical value of the test statistic.

4) The df = 1, since we're comparing a single proportion (Georgia) to a fixed value (national average).

5) The critical value at df = 1 and 95% confidence is 3.84 (for a two-tailed test)

6) Since the test statistic of 1.75 is less than 3.84, we look up 1.75 in tables to find the p-value.

7) For a test statistic of 1.75 and df = 1, the p-value is 0.1860.

So the p-value to test if the proportion of Georgians who invest in the stock market is different than the nationwide average is 0.1860.

Let me know if you have any other questions!

Answer:

\(x=5\)

Step-by-step explanation:

The perimeter of a figure is the sum of all its sides.

The sides are x, (x+3), and (2x). The perimeter is 23, so the sum of the expression equates to 23. Thus:

\(x+(x+3)+(2x)=23\)

Combine like terms:

\(4x+3=23\)

Subtract 3 from both sides:

\(4x=20\)

Divide both sides by 4:"

\(x=5\)

And we're done!

Answer:

36

Step-by-step explanation:

to know the 1/4

divide 48 to 4 = 12

12-48=36

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Answer:

Step-by-step explanation:

We must use PEMDAS for this answer.

First, we must multiply 1000 and 10.

10,000-5000+23-93

Next, we must subtract 10,000 and 5,000

5000+23-93

Add 5000 and 23

5023-93

For our final step, subtract and you get your answer.

4,930

Answer:

\(2 \times 5 = 10 \\ 3 \times 11 = 33 \\ 10 + 33 = 43 \\ 43 {m}^{2} \)

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The sum of angles ∠D and ∠F in quadrilateral DEFG, inscribed in circle P, is equal to 180∘.

To prove that m∠D + m∠F = 180∘, we can use the property of angles inscribed in a circle.

In a circle, an inscribed angle is equal to half the measure of its intercepted arc. Therefore, if we can show that arc DE + arc FG = 360∘, we can conclude that m∠D + m∠F = 180∘.

Let's start the proof:

1. Quadrilateral DEFG is inscribed in circle P. This means that all the vertices of the quadrilateral lie on the circumference of the circle.

2. Let's consider arc DE and arc FG. These arcs are intercepted by angles ∠D and ∠F, respectively.

3. By the property of angles inscribed in a circle, we know that the measure of an inscribed angle is equal to half the measure of its intercepted arc.

4. Therefore, m∠D = 1/2(arc DE) and m∠F = 1/2(arc FG).

5. We want to prove that m∠D + m∠F = 180∘. This is equivalent to showing that 1/2(arc DE) + 1/2(arc FG) = 180∘.

6. Combining the fractions, we have 1/2(arc DE + arc FG) = 180∘.

7. Now, we need to show that arc DE + arc FG = 360∘.

8. Since quadrilateral DEFG is inscribed in circle P, the sum of the measures of all the arcs intercepted by the sides of the quadrilateral is equal to 360∘.

9. This means that arc DE + arc EF + arc FG + arc GD = 360∘.

10. However, we can observe that arc EF and arc GD are opposite sides of the same chord, so they have equal measures. Therefore, arc EF = arc GD.

11. Substituting arc GD with arc EF in the equation from step 9, we have arc DE + arc EF + arc FG + arc EF = 360∘.

12. Simplifying the equation, we get 2(arc DE + arc EF + arc FG) = 360∘.

13. Dividing both sides by 2, we have arc DE + arc EF + arc FG = 180∘.

14. Comparing this result with step 7, we can conclude that arc DE + arc FG = 180∘.

15. Finally, going back to our initial goal, we can now substitute arc DE + arc FG with 180∘ in the equation from step 6: 1/2(180∘) = 180∘.

16. Simplifying, we have 90∘ = 180∘, which is a true statement.

17. Therefore, we have proven that m∠D + m∠F = 180∘.

Thus, we have successfully proved that the sum of angles ∠D and ∠F in quadrilateral DEFG, inscribed in circle P, is equal to 180∘.

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11.2% of the mass of a water molecule is hydrogen

As water is composed of two parts hydrogen and one part oxygen, the total mass of a single molecule may be determined by ascertaining the following:

The Total Mass of Water = (2 x Mass of Hydrogen) + (1 x Mass of Oxygen)

Total Mass of Water = (2 x 1.01u) + (1 x 16.00u)

Total Mass of Water = 18.02u

Consequently, the overall mass of one molecule of water is determined to be 18.02 atomic mass units (u).

% mass of hydrogen = (mass of hydrogen / total mass of water) × 100

% mass of hydrogen = (2.02u / 18.02u) × 100

% mass of hydrogen = 11.2%

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Answer:

  (-∞, -3] or [-3, ∞)

Step-by-step explanation:

You want the largest domain interval(s) on which the function shown in the graph could be one-to-one.

A one-to-one function must pass the horizontal line test. That is, no horizontal line can intersect its graph in more than one place.

For that to be true of the given function, the interval on which it is defined cannot include values on both sides of x=-3, where the graph has a minimum. That is, the domain must be either x ≤ -3, or x ≥ -3, (or some subset of either of these).

The largest intervals on which the function has an inverse are ...

  (-∞, -3]  or  [-3, ∞)

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To make the given function one-to-one and have an inverse, we can restrict its domain to (-∞, a) or (a, ∞), where 'a' is the x-coordinate of the highest or lowest point on the graph.

To make the given function one-to-one and have an inverse, we need to restrict its domain. The largest domains, in interval notation, that can be used are: (-∞, a) or (a, ∞) where 'a' is the x-coordinate of the highest or the lowest point on the graph, depending on the function type.

If the graph has a highest point, the domain is restricted to (a, ∞), where 'a' is the x-coordinate of the highest point. If the graph has a lowest point, the domain is restricted to (-∞, a), where 'a' is the x-coordinate of the lowest point.

For example, if the graph has a highest point at (3, 5), the domain would be restricted to (3, ∞) to make the function one-to-one and have an inverse.

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Solution :

a).

The different three letter initials that people have is :

= 26 x 26 x 26

= \(26^3\)

= \(17576\)

b). The first place to be fill in26 ways.

The second place to be filled in 25 ways

The third place to be filled in 24 ways.

Therefore, total number of three letter initial with no repetition is :

= 26 x 25 x 24

= \(15600\)

c). The total number of three letter initial begin with X = 1 x 26 x 26

                                                                                          = \(676\)

d). The total number of the three letter initials that begin with letter 'F' an end with letter 'D' is = 1 x 26 x 1

                                 = \(26\)

The domain of the relation of the graph representing a relation where x represents the independent variable and y represents the dependent variable is {−4, −2, 0, 3, 5}.

The domain of a relation is the set of all possible input values (independent variable) for which the relation is defined.

Looking at the given points, the x-coordinates are -4, -2, 0, 3, and 5. So, the possible input values are -4, -2, 0, 3, and 5.

Therefore, the domain of the relation is {−4, −2, 0, 3, 5}.

Hence, the correct option is {−4, −2, 0, 3, 5}.

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Answer: I think the answer is 1250.

Step-by-step explanation:

I did 200 divided by 4 which is 50. I then multiplied 50 * 25 and got 1250.

Step-by-step explanation:

a = k/m    or       ma = k    

using 4 and 9     4* 9 = k = 36

then the equation becomes:

    ma = 36    

  using a = 6

      6 * m = 36     shows m = 6 kg

Answer:

(x=2)

Step-by-step explanation:

Answer:

x = 2

Step-by-step explanation:

3(-2) + 7 = 1....its not this one because when we plug in -2 for x we get 1 not 13.

3(2) + 7 = 13...its this one because when we plug in 2 for x we get 13.

3(5) + 7 = 22...its not this one because when we plug in 5 for x we get 22 not 13.

hope this helps

Answer:

first choice: y≥1/3 x+3 and 3x-y>2

Step-by-step explanation:

The system of linear inequalities is: \(y \ge \frac{1}{3}x + 3\) and \(3x -y > 2\)

The equation of the orange line is calculated using:

\(y = \frac{y_2 - y_1}{x_2-x_1} \times (x -x_1) + y_1\)

This gives

\(y = \frac{3- 4}{0-3} \times (x -3) + 4\)

\(y = \frac{- 1}{-3} \times (x -3) + 4\)

\(y = \frac{1}{3} \times (x -3) + 4\)

Open the bracket

\(y = \frac{1}{3}x -1 + 4\)

\(y = \frac{1}{3}x + 3\)

The inequality has a thick line, and the upper region is shaded.

So, the inequality is:

\(y \ge \frac{1}{3}x + 3\)

The equation of the gray line is calculated using:

\(y = \frac{y_2 - y_1}{x_2-x_1} \times (x -x_1) + y_1\)

This gives

\(y = \frac{4- 1}{2-1} \times (x -1) + 1\)

\(y = \frac{3}{1} \times (x -1) + 1\)

\(y = 3 \times (x -1) + 1\)

Open the bracket

\(y = 3x -3 + 1\)

\(y = 3x -2\)

The inequality has a dotted line, and the right region is shaded.

So, the inequality is:

\(y < 3x -2\)

Rewrite as:

\(3x -2 > y\)

So, we have:

\(3x -y > 2\)

Hence, the system of linear inequalities is:

\(y \ge \frac{1}{3}x + 3\) and \(3x -y > 2\)

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Answer:

what drawing

Step-by-step explanation:

Answer:

Refer to the step-by-step explanation, please follow along very carefully. Answers are encased in two boxes.

Step-by-step explanation:

Given the following function, find it's derivative using the definition of derivatives. Evaluate the function when θ=1, 11, and 3/11

\(p(\theta)=\sqrt{11\theta}\)

\(\hrulefill\)

The definition of derivatives states that the derivative of a function at a specific point measures the rate of change of the function at that point. It is defined as the limit of the difference quotient as the change in the input variable approaches zero.

\(f'(x) = \lim_{{h \to 0}} \dfrac{{f(x+h) - f(x)}}{{h}}\)\(\hrulefill\)

To apply the definition of derivatives to this problem, follow these step-by-step instructions:

Step 1: Identify the function: Determine the function for which you want to find the derivative. In out case the function is denoted as p(θ).

\(p(\theta)=\sqrt{11\theta}\)

Step 2: Write the difference quotient: Using the definition of derivatives, write down the difference quotient. The general form of the difference quotient is (f(x+h) - f(x))/h, where "x" is the point at which you want to find the derivative, and "h" represents a small change in the input variable. In our case:

\(p'(\theta) = \lim_{{h \to 0}} \dfrac{{p(\theta+h) - p(\theta)}}{{h}}\\\\\\\Longrightarrow p'(\theta)= \lim_{h \to 0} \dfrac{\sqrt{11(\theta + h)} - \sqrt{11\theta} }{h}\)

Step 3: Take the limit:

We need to rationalize the numerator. Rewriting using radical rules.

\(p'(\theta)= \lim_{h \to 0} \dfrac{\sqrt{11(\theta + h)} - \sqrt{11\theta} }{h} \\\\\\\Longrightarrow p'(\theta)= \lim_{h \to 0} \dfrac{\sqrt{11\theta + 11h} - \sqrt{11\theta} }{h}\\\\\\\Longrightarrow p'(\theta)= \lim_{h \to 0} \dfrac{\sqrt{11}\sqrt{\theta+h} - \sqrt{11}\sqrt{\theta} }{h}\)

Now multiply by the conjugate.

\(p'(\theta)= \lim_{h \to 0} \dfrac{\sqrt{11}\sqrt{\theta+h} - \sqrt{11}\sqrt{\theta} }{h} \cdot \dfrac{\sqrt{11}\sqrt{\theta+h} + \sqrt{11}\sqrt{\theta} }{\sqrt{11}\sqrt{\theta+h} + \sqrt{11}\sqrt{\theta} } \\\\\\\Longrightarrow p'(\theta)= \lim_{h \to 0} \dfrac{(\sqrt{11}\sqrt{\theta+h} - \sqrt{11}\sqrt{\theta} )(\sqrt{11}\sqrt{\theta+h} + \sqrt{11}\sqrt{\theta} )}{h(\sqrt{11}\sqrt{\theta+h} + \sqrt{11}\sqrt{\theta} )} \\\\\\\)

\(\Longrightarrow p'(\theta)= \lim_{h \to 0} \dfrac{11h}{h(\sqrt{11}\sqrt{\theta+h} + \sqrt{11}\sqrt{\theta} )}\\\\\\\Longrightarrow p'(\theta)= \lim_{h \to 0} \dfrac{11}{\sqrt{11}\sqrt{\theta+h} + \sqrt{11}\sqrt{\theta} }\)

Step 4: Simplify the expression: Evaluate the limit by substituting the value of h=0 into the difference quotient. Simplify the expression as much as possible.

\(p'(\theta)= \lim_{h \to 0} \dfrac{11}{\sqrt{11}\sqrt{\theta+h} + \sqrt{11}\sqrt{\theta} }\\\\\\\Longrightarrow p'(\theta)= \dfrac{11}{\sqrt{11}\sqrt{\theta+(0)} + \sqrt{11}\sqrt{\theta} }\\\\\\\Longrightarrow p'(\theta)= \dfrac{11}{\sqrt{11}\sqrt{\theta} + \sqrt{11}\sqrt{\theta} }\\\\\\\Longrightarrow p'(\theta)= \dfrac{11}{2\sqrt{11}\sqrt{\theta} }\\\\\\\Longrightarrow p'(\theta)= \dfrac{11}{2\sqrt{11\theta} }\\\\\\\Longrightarrow p'(\theta)= \dfrac{11}{2\sqrt{11\theta} }\)

\(\therefore \boxed{\boxed{p'(\theta)= \dfrac{\sqrt{11} }{2\sqrt{\theta} }}}\)

Thus, we have found the derivative on the function using the definition.

It's important to note that in practice, finding derivatives using the definition can be a tedious process, especially for more complex functions. However, the definition lays the foundation for understanding the concept of derivatives and its applications. In practice, there are various rules and techniques, such as the power rule, product rule, and chain rule, that can be applied to find derivatives more efficiently.\(\hrulefill\)

Now evaluating the function at the given points.  

\(p'(\theta)= \dfrac{\sqrt{11} }{2\sqrt{\theta}}; \ p'(1)=??, \ p'(11)=??, \ p'(\frac{3}{11} )=??\)

When θ=1:

\(p'(\theta)= \dfrac{\sqrt{11} }{2\sqrt{\theta}}\\\\\\\Longrightarrow p'(1)= \dfrac{\sqrt{11} }{2\sqrt{1}}\\\\\\\therefore \boxed{\boxed{p'(1)= \dfrac{\sqrt{11} }{2}}}\)

When θ=11:

\(p'(\theta)= \dfrac{\sqrt{11} }{2\sqrt{\theta}}\\\\\\\Longrightarrow p'(11)= \dfrac{\sqrt{11} }{2\sqrt{11}}\\\\\\\therefore \boxed{\boxed{p'(11)= \dfrac{1}{2}}}\)

When θ=3/11:

\(p'(\theta)= \dfrac{\sqrt{11} }{2\sqrt{\theta}}\\\\\\\Longrightarrow p'(\frac{3}{11} )= \dfrac{\sqrt{11} }{2\sqrt{\frac{3}{11} }}\\\\\\\therefore \boxed{\boxed{p'(\frac{3}{11} )= \dfrac{11\sqrt{3} }{6}}}\)

Thus, all parts are solved.

Answer:

Second one

Step-by-step explanation:

Answer:

C. A 90° clockwise rotation about the origin

Answer:

CAD= 38°

Step-by-step explanation:

CAD 90°-52°=38°

BDC 90

ACD 52

DCB 38

Answer:

Attached is an example of a circle with a radius of 5 and a diameter of 10.

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Answer:

18

cuz 2×3=6 so 6 ×3 equals 18

Answer:

38 hrs old

Step-by-step explanation:

3 *12 = 36 + 2 years = 38 years old

Answer: the maximum score was 10 feet.

Step-by-step explanation:

here's a step-by-step explanation:

Identify the minimum score: The minimum score is given in the problem as 4 feet.

Identify the range: The range is also given in the problem as 6 feet.

Calculate the maximum score: To find the maximum score, we simply need to add the minimum score and the range.

Maximum score = Minimum score + Range

Maximum score = 4 feet + 6 feet

Maximum score = 10 feet

So the maximum score was 10 feet.

The angles in the parallel lines are as follows;

When parallel lines are cut by a transversal line, angle relationships are formed such as corresponding angles, alternate interior angles, alternate exterior angles, linear angles, vertically opposite angles etc.

Therefore, let's find the angles m∠1 and m∠2.

Hence,

138 + m∠1 = 180(angles on a straight line)

The sum of angles on a straight line is 180 degrees.

m∠1 = 180 - 138

m∠1 = 42 degrees

Therefore,

m∠1 =  m∠2 (alternate exterior angles)

Alternate exterior angles are the pair of angles that are formed on th outer side of the parallel lines but on the opposite side of the transversal.

Alternate exterior angles are congruent.

Therefore,

m∠1 =  m∠2 = 42 degrees.

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The numbers are compared with the inequality symbols as follows:

a. 3 > -3.

b. 12 < 24.

c. -12 > -24.

d. 5 = - (-5).

e. 7.2 > 7.

f. -7.2 < 7.

g. -1.5 = -3/2.

h. -4/5 > -5/4.

i. -3/5 = -6/10.

j. -2/3 < 1/3.

The inequality symbols used in this problem are defined as follows:

The observations to some items are given as follows:

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In conclusion the expression becomes:

1/10 + 81/100 = 0.1 + 0.81 = 0.91

And we can see that the sum is indeed less than 1.

How to solve?

To find the missing numerator, we need to simplify the expression first:

?/10 + 81/100 = ?/10 + 81/10 * 1/10 = ?/10 + 0.81

Now we want the sum to be less than 1, so we can set up the inequality:

?/10 + 0.81 < 1

Subtracting 0.81 from both sides, we get:

?/10 < 0.19

Multiplying both sides by 10, we get:

? < 1.9

So the missing numerator must be a nonzero integer less than 1.9 when multiplied by 10. The only integer that satisfies this condition is 1, so the missing numerator is 1.

Therefore, the expression becomes:

1/10 + 81/100 = 0.1 + 0.81 = 0.91

And we can see that the sum is indeed less than 1.

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Answer:

X=9

Step-by-step explanation: