help pls thx!!!!!!!
this is my last question i hope!

Answer:

Yes, the driver traveled far enough to reach the office.

Explanation:

We can use the formula

\(v=\frac{x}{t}\)

We are given

\(x=30\) KM

\(t=45\) min

\(v=50\) KM/H

Lets convert minutes to hours.

To convert minutes to hours divide the speed by 60.

\(\frac{45}{60} =\frac{3}{4} =0.75\)

Now we have

\(x=30\) KM

\(t=0.75\) H

\(v=50\) KM/H

\(v=\frac{x}{t}\)

Solve for x.

\(x=vt\)

Lets substitute our values into the equation.

\(x=50*0.75\)

\(x=37.5\)

\(37.5 > 30\) So the answer is yes;  the driver traveled far enough to reach the office.

The driver has to travel 35 km to reach the office. The distance he covered with a speed of 50 km/h within 45 minutes or 0.75 hour is 37.5 km. Hence, he travelled enough to reach the office.

Velocity of a moving body is the measure of distance it covered within unit time. The velocity is a vector quantity and have a magnitude and direction. The units of velocity are km/h, m/s etc.

Velocity is the ratio of change in distance to the change in time. Hence, distance can be calculated by multiplying the velocity with time.

Given that, velocity of the driver = 50 Km/h

time taken = 45 minutes = 45/60 =0.75 hr

Therefore, the distance = 0.75 hr × 50 km/h = 37.5 km

The distance to the office is 30 km. Therefore, the driver traveled far enough to reach the office.

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The magnetic field at a point due to wires with distance r = C cm and carrying the current I is 2 mA is 0.29 T.

The magnetic field is produced over the magnet or current-carrying conductor. The Biot-Sarvat law is defined as the magnetic field produced due to the current-carrying conductor. The magnetic field is the vector quantity and the unit of the magnetic field is Tesla. It is the vector quantity.

Magnetic field, B = μ₀/2π (I/R), where  μ₀ is the permeability of the magnetic field, I is current, and R is the distance between two points.

B₁= μ₀/2π (I/R)

 = (1.26×10⁻⁶)×2×10⁻³/(2π×1.35m)

 = 0.29T

B₂ = 0.29T

The net magnetic field is B=B₁+B₂=0.58T.

Thus, the magnetic field is 0.29T. The left wire carries the current outward direction and the right wire carried the current inward direction and hence the direction magnetic field given by the right-hand thumb rule is inside.

B) By using the equation, F=q(v×B), where q is the charge, v is the velocity and B is the magnetic field. Path b is followed by a neutron as it is not deflected by a Magnetic field. The path a is the upward path followed by a negatively charged particle(electron) and Path C is the downward path followed by a positively charged particle(proton).

C) The circular conductor undergoes thermal expansion while it is a uniform magnetic field the direction of the current is a clockwise direction given by the Right-hand thumb rule.

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\($\begin{aligned} (a) &=1 m^{3} \\ V_{1} &=110 \times 10^{3} \mathrm{~Pa} \\ T_{1} &=15+273=288 \mathrm{~K} \end{aligned}$\)

\($c_{p}=1005 \frac{\mathrm{J}}{\mathrm{kg} K}$\)

\($P_{2}=1400 \times 10^{3} \mathrm{~Pa}$\)

\((i)$$P_{1} V_{1}^{1 / 3}=P_{2} V_{2}^{1 / 3}$$\)

\($\Rightarrow \quad\left(\frac{110}{1400}\right)=\left(\frac{V_{2}}{1}\right)^{\$ 1 \cdot 3} \Rightarrow V_{2}=A \cdot 85 \times 10^{4} / \ln ^{3}$\)

\($\Rightarrow \quad V_{2}=0.1413 \mathrm{~m}^{3}$\)

\($T_{2}=T_{1}\left(\frac{p_{2}}{p_{1}}\right)^{\frac{1 \cdot 3 \cdot 1}{1 \cdot 3}}=$\) \($288\left(\frac{1400}{110}\right)^{\frac{1 \cdot 3-1}{1 \cdot 3}}=518 \mathrm{~K}$\)

\((ii) $W=\frac{P_{1} v_{1}-P_{2} V_{2}}{n-1}=\frac{\left(110 \times 10^{3} \times 1\right)-\left(1400 \times 10^{3}\right)(0.1413)}{1.3-1}$\)

\($\Rightarrow W=-292.73 \mathrm{~kJ}$\)

\((iii) $\quad \Delta U=m C_{V} \Delta T$\)

\($=\frac{p_{1} V_{1}}{p_{1}}\left( R-C_{p}\right) \times\left(T_{2}-T_{1}\right)$\)

\($=\frac{110 \times 10^{3} \times 1(-287+1005)(518-288)}{287 \times 288}$\)

\($\Delta U=219.77 \mathrm{~kJ}$\)

\((iv)$$Q-W=\Delta U$$\)

\($\Rightarrow Q-(-292.73)=219.7 7$\)

\($\Rightarrow Q=-72.96 \mathrm{~kJ}$\)

\($\rightarrow$\) Heat is flowing form surrounding

(b) Since, Tempererature is contant So, change in Internal energy \($\Rightarrow \Delta U=m C_{v} \Delta T^{\circ} \Rightarrow \Delta U=0$\)

What is Internal energy ?

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Answer:

22.505 seconds

Explanation:

V =19.8m/s

V = a*to

t1 = 19.8/3.3

= 6seconds

Distance travelled during acceleration

= 1/2 x 3.3 x 6²

= 59.4m

X_total = x1 + x2

X2 = 373-59.4

X2 = 313.6m

t2 = x2/v

= 313.6/19.8

= 16.505

Total = 16.505 + 6

= 22.505 seconds

the minimum time in which an elevator can travel the 373 m from the ground floor is 22.505 seconds.

Answer:

Its  the temperature and density of that element in the star

Explanation:

Answer:

α = 36.21 °

β = 143.79°

Explanation:

To do this, we need to know the expression to calculate the angle.

In this case:

α₁ = tan⁻¹ (Fy₁/Fx₁)   (1)

Now, let's analize the given data.

We have a charge q₁ at the origin of the cartesian coordinate system, so, it's at the 0. The charge q₂ is 20 cm above q₁, meaning is on the y-axis. Finally q₃ it's 20 cm to the right, meaning it's on the x-axis.

Knowing this,we can calculate the force that q₂ and q₃ are exerting over q₁. As these forces are in the x and y-axis respectively, we also are calculating the value of the forces in the x and y axis, that are needed to calculate the direction.

The expression to calculate the force would be Coulomb's law so:

F = K q₁q₂ / r²    (2)

The value of K is 9x10⁹ N m² / C². Let's calculate the forces:

F₁₂ = Fy = 9x10⁹ * (7.1x10⁻⁴) * (6.5x10⁻⁴) / (0.020)²

Fy = 1.04x10⁷ N

F₁₃ = Fx = 9x10⁹ * (7.1x10⁻⁴) * (8.9x10⁻⁴) / (0.020)²

Fx = 1.42x10⁷ N

Now that we have both forces, we can calculate the magnitude of the force:

F = √(Fx)² + (Fy)²

F = √(1.04x10⁷)² + (1.42x10⁷)²

F = 1.76x10⁷ N

Finally, the direction would be applying (1):

α = tan⁻¹ (1.04x10⁷/1.42x10⁷)

α = 36.21 °

And counter clockwise it would be:

β = 180 - 36.21 = 143.79°

Hope this helps

The force 1 is tension force.

To find the correct statement among all the options, we need to know more about friction, tension, normal force and weight.

Thus, we can conclude that the correct option is (B).

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So, the speed of the ball after 2 seconds after free fall is 20 m/s.

Hi ! I'm Deva from Brainly Indonesia. In this material, we can call this event "Free Fall Motion". There are two conditions for free fall motion, namely falling (from top to bottom) and free (without initial velocity). Because the question only asks for the final velocity of the ball, in fact, we may use the formula for the relationship between acceleration and change in velocity and time. In general, this relationship can be expressed in the following equation :

\( \boxed{\sf{\bold{a = \frac{v_2 - v_1}{t}}}} \)

With the following conditions :

We know that :

What was asked :

Step by step :

\( \sf{a = \frac{v_2 - v_1}{t}} \)

\( \sf{(a \times t) + v_1 = v_2} \)

\( \sf{(10 \times 2) + 0 = v_2} \)

\( \boxed{\sf{v_2 = 20 \: m/s}} \)

So, the speed of the ball after 2 seconds after free fall is 20 m/s.

The instantaneous current at the same moment in the RL circuit can be expressed as I = Imaxsin(150), where Imax represents the maximum current.

1. Given that the instantaneous voltage at a specific moment in the RL circuit is V = Vmaxsin(150).

2. We can express the current at the same moment using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.

3. In an RL circuit, the resistance is represented by the symbol R, and it is typically associated with the resistance of the wire or any resistors in the circuit.

4. However, the given equation does not explicitly mention resistance.

5. Since we are considering an RL circuit, it suggests the presence of inductance (L) along with resistance (R).

6. In an RL circuit, the voltage across the inductor (VL) can be expressed as VL = L(di/dt), where L is the inductance and di/dt represents the rate of change of current.

7. At any given instant, the total voltage across the circuit (V) can be expressed as the sum of the voltage across the resistor (VR) and the voltage across the inductor (VL).

8. Therefore, V = VR + VL.

9. Since the given equation represents the instantaneous voltage (V), we can deduce that V = VR.

10. By comparing V = VR with Ohm's Law (V = IR), we can conclude that I = Imaxsin(150), where Imax represents the maximum current.

The specific values of Vmax, Imax, and the phase angle have not been provided in the question, so we are working with the general expression.

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Answer:

A transformer is a passive electrical device that transfers electrical energy from one electrical circuit to another, or multiple circuits.

Explanation:

Hope it helps

Answer:

A transformer with eletric abilities.

Explanation:

Bohr's work demonstrates the importance of communication in science by making use of works communicated by other scientists.

Bohr's work on atomic structure and the quantization of energy demonstrated the importance of communication in science by highlighting the need for clear and effective communication between scientists from different fields.

Bohr's theory was based on the work of other scientists, including Planck and Einstein, and required collaboration and communication between physicists, chemists, and mathematicians.

By effectively communicating his ideas and working with others, Bohr was able to develop a groundbreaking theory that revolutionized the understanding of atomic structure and paved the way for future advances in physics and chemistry.

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According to Chargaff's rule, the amounts of adenine (A), thymine (T), and guanine (G) in the DNA molecule are equal to each other. The amounts of cytosine (C) and guanine (G) are also equal.

Erwin Chargaff was a biochemist, author, Bucovinian Jew who immigrated to America during the Nazi era, and professor of biochemistry at Columbia University's medical school.

Chargaff found patterns among the four bases, or chemical building blocks, of DNA, which are directly related to DNA's function as the genetic material of living things.

He was born in Austria-Hungary. Heraclitean Fire: Sketches from a Life Before Nature, an autobiography he penned, received positive reviews.

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The initial volume of the liquid is 31.4 cm³. The volume coefficient of thermal expansion of the liquid is 0.002 per degree Celsius. A temperature increase of 109.5°C is needed for the liquid to rise to a height of 49cm.

The initial volume of the liquid can be found using the formula for the volume of a cylinder:

V = πr²h

where r is the radius (half the diameter), h is the height, and π is approximately 3.14. Plugging in the given values, we get:

V = π(0.5 cm)²(40 cm)

V = 31.4 cm³

The volume coefficient of thermal expansion (β) is defined as the fractional change in volume per degree Celsius change in temperature. It can be calculated using the formula:

β = ΔV/(VΔT)

where ΔV is the change in volume, V is the initial volume, and ΔT is the change in temperature. We can rearrange this formula to solve for ΔV:

ΔV = βVΔT

We know that ΔT = -10°C (a decrease of 10°C) and that the height decreased from 40cm to 37cm, or by 3cm. The change in volume can be found using the formula for the volume of a cylinder again, with the new height of 37cm:

ΔV = π(0.5 cm)²(40 cm - 37 cm)

ΔV = 0.59 cm³

Plugging in all the values, we get:

0.59 cm³ = β(31.4 cm³)(-10°C)

β = 0.002

To find the change in temperature needed for the liquid to rise to a height of 49cm, we can use the same formula as before, but solve for ΔT:

ΔT = ΔV/(βV)

We know that ΔV is the difference between the initial volume and the volume at the new height, which is:

ΔV = π(0.5 cm)²(49 cm - 40 cm)

ΔV = 6.86 cm³

Plugging in all the values, we get:

ΔT = 6.86 cm³/(0.002)(31.4 cm³)

ΔT = 109.5°C

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The work done if the forklift is operating at full capacity is 11,900 J.

We have to recall that power is defined as the rate of doing work. The rate of doing work is defined as;

Power = Work done/time taken

When;

Power = 4950 W

Time taken = 2.40 s

Work done = Power × time taken

Work done = 4950 W × 2.40 s

Work done = 11,900 J

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Answer:The answer will be B :) hope this helps!

Explanation:

A Stone Is Dropped Into a Deep Water Well. The Sound of The Stone Hitting The Water Is Heard After 3.4 Seconds. then The Depth of The Water Well is 56.6 m.

In terms of physics, sound is a vibration that travels through a transmission medium like a gas, liquid, or solid as an acoustic wave. Sound is the receipt of these waves and the brain's perception of them in terms of human physiology and psychology. Only acoustic waves with frequencies between about 20 Hz and 20 kHz, or the audio frequency range, may cause a human to have an auditory sensation. These correspond to sound waves in air with an atmospheric pressure of 17 metres (56 ft) to 1.7 centimetres (0.67 in) in wavelength. Ultrasounds are sound waves with a frequency higher than 20 kHz that are inaudible to humans. Infrasound refers to sound frequencies below 20 Hz. Animals of different species have different hearing ranges. Acceleration of the stone is 9.8 m/s²

according to kinematics,

s = ut + 1/2 at²

s =  1/2 ×9.8×3.4²

s = 56.6 m

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The top acceleration is 16.884 m/s2. The front wheels can go around at will. Leave exclude the wheels' mass from your calculations. 1.72 is the coefficient of friction.

By condition of equilibrium, we can find the Load at each wheel as

Rear load Wr= 224lb=224*4.45=996.8N

Front-load Wf= 261lb=261*4.45=1161.1N

CG of the entire mass will be located at (2.30, 1.62).

CG location Can be found by

x=sum(Wi*xi) /sum(Wi)

Load transfer due to acceleration is given by

DW=m*a*(h/L)

Where h= height of CG= 1.62ft=0.486m

            L= wheel base=5ft=1.5m

m= total mass in kg=(335+150) *0.45=212.25kg

For the front wheel to be lifted,

dW=Wf

solving we get the acceleration value as

a= 16.884m/s² of acceleration will be the max for tipping of the vehicle.

We know that,

Tractive force = ma

Gives us tractive force as T=212.25*16.88=3582.78N

This will be accomplished when the rear end's friction force is at its maximum tractive state. Static friction force equals trajectories.

T= Friction force= (coefficient of friction) *N

Where N= Wf+Wr for tipping condition

Coefficient of friction= 3582.78/(Wf+Wr) =1.72

We require a coefficient of friction greater than or equal to 1.72 for a vehicle to tip.

Since when tipping the load will be transferred to the back wheel, I have assumed the total weight in the coefficient of friction equation.

Since both are inversely proportional, the rider should hunch down to boost acceleration. This will lower the height of the center of gravity (CG) above the ground.

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Answer:

pictures please

Explanation:

I need a picture so I can tell you

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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OD

Explanation:

both gravitational force and speed will increase

The gravitational force will increase and speed will decrease. So, the correct option is c.

Any two objects in the universe are attracted towards each other by the gravitational force, regardless of whether their masses are equal or not.

Here,

Newton's universal law of gravitation states that the force of attraction between any two bodies is inversely proportional to the square of the distance between them and directly proportional to the product of their masses.

So, the gravitational force of the satellite,

F ∝ 1/R²

where R is the radius of the circular orbit.

The equation for speed of the satellite is given by,

v = √Rg

where g is the acceleration due to gravity.

So, the speed is directly proportional to the square root of the radius of the orbit.

v ∝ √R

Therefore, as a result of the decrease in the radius of the orbit, the gravitational force of the satellite will increase, and its speed will decrease.

Hence,

The gravitational force will increase and speed will decrease.

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The way in which one atom interacts with another atom is mostly influenced by the configuration of the electrons farthest from the nucleus.

Option A.

An atom can be defined as the smallest part of a substance that cannot be broken down chemically. Each atom has a nucleus (center) made up of protons (positive particles) and neutrons (particles with no charge).

The arrangement of electrons in orbitals and shells around the nucleus is referred to as the electronic configuration of the atom.

Thus, we can conclude that the way in which one atom interacts with another atom is mostly influenced by the configuration of the electrons farthest from the nucleus.

The remaining options do not fit the empty space properly, and they include;

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The magnitude of velocity A is 3.06 m/s and the magnitude of velocity B is 3.5 m/s.

The magnitude of velocity  A and B in the given figure is determined by applying parallelogram law of vector addition.

Vr² = Va² + Vb²  - 2(Va)(Vb) cosθ

where;

The angle between the two velocities is calculated as follows;

θ = 180 - (23⁰ + 26.5⁰)

θ = 130.5⁰

Apply sine rule and determine the values of each of the velocities.

Va / sin(23) = V(tot) / sin(130.5)

Va / sin(23) = 5.96 / sin(130.5)

Va = 5.96 (sin 23 / sin 130.5)

Va = 3.06 m/s

Vb / sin(26.5) = V(tot) / sin(130.5)

Vb = 5.96 (sin 26.5 / sin 130.5)

Vb = 3.5 m/s

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It means that a material transmits waves can pass through the material and propagate or travel through it. without being absorbed or reflected.

When a material is said to transmit waves, it means that the wave can pass through the material and propagate or travel through it. The material allows the wave to pass through it without being absorbed or reflected. This means that the wave maintains its amplitude, frequency and wavelength as it travels through the material, and it doesn't lose energy. For example, light waves can pass through a transparent material such as glass and air, while they are absorbed by opaque materials such as wood and metal. Solids, liquids, and gases can all be penetrated by sound waves. Some materials, such as anisotropic materials, can transmit waves in different directions. For example, a material that is more conductive in one direction than in another, a wave that is propagating through it will travel differently depending on the direction it's coming from. The properties of a material that allow it to transmit waves are determined by the material's elastic and electromagnetic properties, density, and structure.

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The following is the correct statement about the motion of particle : it cannot move / reach to either x0 or x2. And as this particle is having only one joule of kinetic energy it cannot overcome the required potential energy.

Conservative force is the force done in moving a particle from one point to another, such that force is independent of the path taken by  particle. It depends on initial and final position of the particle. Gravitational and elastic spring forces are two examples of conservative forces.

Total work done by conservative force is independent of the path resulting in given displacement and is equal to zero when path is a closed loop.

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The particle will oscillate between -1J and -2J in potential energy and will never reach the points x0 and x2.

If two objects collide, the total momentum before and after the collision will be the same if no external force acts on the colliding objects, according to the principle of conservation of momentum.

In x1, potential energy  U(x1) = -2J

                kinetic energy is V(x1) = 1 J

Total energy = U(x1) + V(x1) = -2J + 1 J = -1 J

Since the force is conserved then the total energy will also remain conserved.

That is, U(x1) = -1J - V(x1)

           Since, kinetic energy ≥ 0

           U(x1) ≤ -1J

Therefore from the graph we will be able to say that the particle will oscillate between  range of potential energy that is -1J to -2J and also it will never reach the point x0 and x2 .

The graph is attached below:

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Answer:

The centre of gravity (COG) of the human body is a hypothetical point around which the force of gravity appears to act. It is a point at which the combined mass of the body appears to be concentrated.

The centre of gravity (COG) of an object is the point at which weight is evenly dispersed and all sides are in balance. A human's centre of gravity can change as he takes on different positions, but in many other objects, it's a fixed location.

a}The work is done by the piston in the process is 199 cal.

b) The increase in internal energy of the gas is  703 cal

c) The heat was supplied to the gas is  3771 J

(a) To calculate the work done by the piston, we can use the formula:

Work = P * ΔV

Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:

Work = P * (\(V_2 - V_1\))

Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:

PV = nRT

\(V_1 = (nRT_1) / P_1\)

\(V_2 = (nRT_2) / P_2\)

Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).

Substituting the values into the equation, we have:

V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal

V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal

Therefore, the work done by the piston is:

Work = 1 atm * (796 cal - 597 cal) = 199 cal

(b) The increase in internal energy of the gas can be calculated using the equation:

ΔU = n * C * ΔT

Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).

Substituting the values into the equation, we have:

ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal

(c) The heat supplied to the gas can be calculated using the equation:

Q = ΔU + Work

Substituting the values calculated in parts (a) and (b), we have:

Q = 703 cal + 199 cal = 902 cal

Since 1 cal = 4.184 J, the heat supplied to the gas is:

Q = 902 cal * 4.184 J/cal ≈ 3771 J

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Answer:

z=60

Explanation:

60/4=15+22=37<38

Answer:

z=60

Explanation:

YEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEET!

Answer:

12/30

Explanation:

v=ir

i=v/r

12/30=i

Answer:

It is (B) Stimuli must be sensed in order to produce a response.

Explanation:

ANSWER

The mass of the student is 53.00kg

EXPLANATION

Given that;

The weight of the student = 520N

Follow the steps below to find the mass of the student

Step 1: Define weight

Weight s defined as the force acting on an object due to acceleration due to gravity

Step 2: Write the formula linking the mass and the acceleration due to gravity together

Where

W is the weight of the body

m is the mass of the body

g is the acceleration due to gravity

Step 3: Substitute the given data into the formula in step 2

Hence, the mass of the student is 53.00kg