HELP PLS MARKING BRANLIST 100 Pts TAKING TEST RN


A sprinter runs the 50 m dash in 5.6 seconds. What is the sprinter's speed?

280 m/s

0.11 m/s

44.4 m/s

8.93 m/s

The y-component of momentum of the 2.40 kg stone after the collision is calculated as 4.32 kg.m/sec.

The system's momentum will remain conserved both before and after the collision because there is no external force acting on the two stones.

Given that:

2.40 kg of stone is moving at 3.60 m/s at 30 degrees CCW from +ve x-axis following the collision, its y-component of momentum will be as follows:

                                            P₁y = m₁ × V₁y

V₁y = y-component of velocity = V₁ ×sin 30°,  

P₁y = 2.40 ×3.60 ×sin 30° = 4.32 kg.m/sec

since momentum is conserved, So

Momentum before collision in y-direction (Pi) = Momentum after collision in y-direction (Pf)

                               Piy = Pfy

there is no motion is y-direction, So Piy = 0 kg.m/sec

                                      So, Pfy = 0

                                       P₁y + P₂y = 0

P₂y = y-momentum of 4.00 kg stone after collision = -P₁y

P₂y = -4.32 kg.m/sec (-ve sign means y-momentum is in -ve y direction)

Part B.

                       P₂y = m₂ × V₂y

V₂y is the y-component of the velocity of a 4.00 kg stone following a collision when the stone is moving 45 degrees clockwise from the +ve x-axis (CW = clockwise, CCW = counterclockwise)

                                = -V₂ × sin 45°

P₂y = m₂ × (-V₂ ×sin 45°)

V₂ = P₂y/(-m₂ × sin 45°)

V₂ = -4.32/(-4.00 × sin 45 °) = 1.52735 m/s

V₂ = 1.53 m/s = speed of 4.00 kg stone after collision

Part C.

x-component of total momentum after collision will be:

                   Pfx = P₁x + P₂x

Pfx = m₁ × V₁x + m₂ ×V₂x

Pfx = m₁ × V₁ ×cos 30° + m₂ × V₂ ×cos 45°

Pfx = 2.40 ×3.60 × cos 30° + 4.00 × 1.52735 × cos 45°

Pfx = 11.80 kg.m/sec

Part D.

Since momentum will also remain conserved in x-direction, So

                                   Pix = Pfx

m₁ × U₁x + m₂ × U₂x = Pfx

U₁x = x-component of the 2.40 kg stone's speed prior to the collision

Because 2.40 kg initially only moves in the x-direction,

                                  U₁x = U₁

U₂x = 0, since initially m₂ was at rest

U₁x = (Pfx - m₂ × U₂x)/m₁

U₁x = (11.80 - 4.00 × 0)/2.40

U₁x = 4.92 m/s = speed of 2.40 kg stone before collision

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Answer:

13.4 m/s^2

Explanation:

40 divided by 3 equals 13.3 repeating.

The parallax method helps astronomers determine the Earth's motion and measure distances to stars.

The parallax method is a powerful technique used by astronomers to measure the distances to stars and determine the Earth's motion. Parallax refers to the apparent change in position of an object when viewed from different vantage points. In the case of astronomy, astronomers observe stars from different positions on Earth as it orbits the Sun, which allows them to measure the parallax angle and calculate the distance to the star.

By observing a star at two different times, when the Earth is at opposite ends of its orbit around the Sun, astronomers can obtain two different perspectives on the star's position. The angular shift observed is the parallax angle. The larger the parallax angle, the closer the star is to Earth. Using trigonometry, astronomers can then calculate the distance to the star based on the known baseline between the two observation points.

The parallax method was first successfully applied by the German astronomer Friedrich Wilhelm Bessel in the 19th century. It revolutionized our understanding of the vastness of the universe and provided a way to measure distances to nearby stars. The accuracy of this method has improved over time with advancements in technology and instrumentation.

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The primary job of a(n) ____

is to increase the power of a modified radio wave.

Answer:

Explanation:

Hope it helps:)

#CarryOnLearning

Answer: Amplifier

Explanation: Edge 2021

Have a great day :D

The specific heat capacity of the liquid is 2.51 x 10³ J/kg⁰C.

The specific heat capacity of the liquid is calculated as follows;

Q = mcΔФ

where;

c = Q/mΔФ

c = (65 x 120)/(0.78 x 3.99)

c = 2.51 x 10³ J/kg⁰C

The complete question is below:

An electrical resistor immersed in a liquid produces 65.0 W of electrical energy for 120 s. The mass of the liquid is 0.780 kg and its temperature increases from 18.55°C to 22.54°C. a) Find the average specific heat capacity of the liquid in this temperature range.

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Answer:

split traction

Explanation:

Power = work / time

Power = 200J / 10 seconds

Power = 20 watts

Answer:

La principal diferencia que existe entre la marcha cuando caminamos y cuando corremos, sea con o sin el balón, es la velocidad: al caminar, la velocidad es mucho menor que al correr, y a su vez, correr sin el balón da la posibilidad de correr mucho más rápidamente, debido a que no se requiere una coordinación entre los pasos y el control del balón.

Por otra parte, además de la velocidad, el ritmo cardiaco que se adquiere al caminar es mucho mas bajo que al correr, donde por causa del esfuerzo se aceleran las pulsaciones, aumentando la frecuencia cardiaca y, por lo tanto, la exigencia cardiovascular.

Answer:

inversely proportional

Explanation:

I know this because I'm learning this right now. My teacher told me that Coulomb's Law is important because it shows us the positive and negative attraction between the two charges. It also tells us that if we have two like charges, then they're going to repel, but the closer they get, the bigger charge it's going to have. Coulomb's Law tells us the force between charged particles is inversely proportional to their charges.

The evidence that there is dark matter beyond the disk of a spiral galaxy is the stellar mass which is distributed does not account for the rotation curve of galaxies.

Dark matter is a hypothetical form of matter thought to account for approximately 85% of the matter in the universe.

The most clear evidence of the existence of dark matter in spiral galaxies comes from their rotational velocities.

It has been shown from latest observations that the universe is not only expanding but that the expansion is accelerating and therefore, this could be the main evidence of the dark matter that the force it is exerting leads to universe expansion.

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No. A dog chasing its tail is just an animal running around in circles.

The dog's MOTION, however, IS accelerated motion, since the DIRECTION of its motion is constantly changing.

A a dog chasing its tail cannot be considered as acceleration.

Acceleration is the rate at which velocity changes over time, both in terms of speed and direction.

A point or object moving in a straight line is accelerated if it accelerates or decelerates. Even if the speed is constant, motion on a circle is accelerated because the direction is constantly changing.

For example, if a car accelerates as it turns a corner at constant speed, it is doing so because its direction is changing.

The faster you turn, the faster you accelerate. When velocity changes in magnitude (increase or decrease in speed), direction, or both, there is an acceleration.

Thus, as there is no change in either speed or direction in scenario in which a dog chases its tail, it is not considered as acceleration.

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Because of Kinetic Theory Postulate, the gas molecule's collision will affect.

Gases can be compressed because most of the volume of gas is an empty space according to Kinetic Molecular theory. If we compress a gas without changing its temperature, the average K.E of the gas particles remains the same. There is no change in the speed of the gas molecules with which the particles move in a container, but the container is smaller. So particles travel from one side of the container to the other in a very small period of time. So it means that they strike the walls mostly. Any increase in the frequency of collisions with the walls must increase the pressure of the gas. from Boyle's law, the pressure of gas becomes more significant as the volume of the gas becomes smaller have opposite relation.

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The magnitude of the angular velocity of the wheel after the block has descended 3.80 m is 5.23 rad/s.

Explanation :

We can use conservation of energy to solve this problem. Initially, the system is at rest and has a total energy of zero. As the block descends, its potential energy is converted into kinetic energy and work done by friction. We can express this as:

\(mgh = (1/2)mv^2 + W_{friction} + (1/2)Iw^2\)

where m is the mass of the block, g is the acceleration due to gravity, h is the height the block descends (3.80 m), v is the velocity of the block at the bottom, W_friction is the work done by friction (−8.50 J), I is the moment of inertia of the wheel, and ω is the angular velocity of the wheel.

Since the wire is wrapped around the rim of the wheel, the distance the block descends (3.80 m) is also the distance the rim of the wheel moves. Therefore, the work done by friction can be expressed as:

\(W_{friction} = -F_{friction} * d = -\)τΘ

where F_friction is the force of friction at the axle, τ is the torque exerted by friction, d is the distance the rim moves, and θ is the angle through which the wheel rotates. Since the wheel rotates through an angle of θ = h/r = 3.80 m/0.190 m = 20.0 rad, we have:

τ = W_friction / θ = -8.50 J / 20.0 rad = -0.425 N*m

Substituting the given values into the energy conservation equation and solving for ω, we get:

\((0.350 kg)(9.81 m/s^2)(3.80 m) = (1/2)(0.350 kg)v^2 - 0.425 N*m + (1/2)(0.470 kgm^2)w^2\)

Simplifying and solving for ω, we get:

ω = √[(2mgh + 2τ)/I]

\(w =\sqrt{[(2)(0.350 kg)(9.81 m/s^2)(3.80 m) + 2(-0.425 Nm)] / 0.470 kgm^2}\)

ω = 5.23 rad/s

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The User Account Control dialog box comes when you access one of your data files. You cannot change the desktop resolution setting because it is fixed.

There is no distinction between a user account and a user profile. Windows 10 Settings has taken the role of Windows Control Panel. The CPU processes instructions through a process known as "fetch-execute." The first instruction in the sequence is retrieved, executed (by, for instance, adding two numbers), and then the next instruction is retrieved, executed, and so on. System modal, modal, and modeless dialog windows are the three distinct varieties. Modal dialog windows are frequently used by programs to display messages and set up software. All open windows will be simultaneously minimized when you click the Show Desktop button.

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The sum of all resistances in the series circuit is known as Equivalent resistance.

where R is the equivalent resistance.

Hence, option 1 is the correct answer.

1/do + 1/di = 1/f

blah blah blah why does the answer have to be 20 characters long

The resistivity of a wire with a diameter of 2.2 mm, carrying a current of 18 A and experiencing an electric field of 0.090 V/m,  is found to be approximately 1.3 x 10^-7 Ωm.

The formula relating resistivity (ρ), diameter (d), current (I), and electric field (E) for a wire is ρ = (E * d) / I. Substituting the given values into the formula, we have ρ = (0.090 V/m * 2.2 mm) / 18 A.

Before calculating the resistivity, it's important to ensure that the units are consistent. Since resistivity is typically measured in ohm-meters (Ωm), we need to convert the diameter from millimeters (mm) to meters (m). Thus, 2.2 mm becomes 0.0022 m.

Substituting the converted values into the formula, we get ρ = (0.090 V/m * 0.0022 m) / 18 A. Calculating this expression, the resistivity of the wire is approximately 1.3 x 10^-7 Ωm.

Therefore, the resistivity of the 2.2-mm diameter wire carrying an 18 A current in the presence of a 0.090 V/m electric field is approximately 1.3 x 10^-7 Ωm.

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Answer:

0.9 m

Explanation:

Hooke’s Law

\(\large\boxed{F = ke}\)

where:

Given values:

Substitute the given values into the formula to find k:

\(\implies 2.0=0.30k\)

\(\implies k=\dfrac{2.0}{0.30}\)

\(\implies k=\dfrac{20}{3}\; \sf N/m\)

To find the extension if the force applied is 6 N, substitute the found value of k and the given value of F into the formula and solve for e:

\(\implies 6=\dfrac{20}{3}e\)

\(\implies 18=20e\)

\(\implies e=\dfrac{18}{20}\)

\(\implies e=0.9\; \sf m\)

Answer:

They will attract when its north and south but will repel when its south and south or north and north

Answer:

v = -\frac{n \ m}{M} \ v'

for the man to return to the ship he must throw the balls in the opposite direction of the ship

Explanation:

For this exercise we can use the conservation of momentum. Let's form a system made up of man and baseballs.

Initial instant. Before throwing the balls

     p₀ = 0

Final moment. After throwing the balls

     \(p_{f}\) = M v + n m v '

where M is the mass of the man, m is the mass of each ball and n is the number of balls , v isthe speed man and v' is the speed ball

Since the forces are internal, the momentum of the system is conserved

     p₀ = p_{f}

      0 = M v + n m v ’

      \(v =- \frac{n \ m}{M} \ v'\)

If we analyze this expression, for the man to return to the ship he must throw the balls in the opposite direction of the ship

Answer:

18m

Explanation:

The student should be 18m away from the teacher

The approximate speed of the roller coaster is 32m/s.  

Considering that the earth and the roller coaster are both parts of one system.

We can use the law of conservation of energy,

This law states that in a system, the sum of total energy is always conserved.

So we can say that the energy at the top of roller coaster will be equal to the energy at the bottom of the roller coaster.

At top, whole energy is potential energy and the bottom whole energy is kinetic energy,

So we can write,

PE = KE

Mgh = 1/2Mv²

Where M is mass of roller coaster,

v is the speed of roller coaster,

g is acceleration due to gravity and,

h is the height of the roller coaster,

Putting all the values,

gh = 1/2v²

v² = 2gh

v² = 2×9.8×51

v² = 999.6

v = 31.61 m/s.

The speed of roller coaster at the end is 32 m/s approx.

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Answer:

To predict future climate, scientists use computer programs called climate models to understand how our planet is becoming different. Climate models work like a laboratory in a computer. They allow scientists to study how the unlike factors interact to influence a region's climate.

Now a new evaluation of global climate models used to project Earth's future global average surface temperatures over the past half-century answers that question: most of the models have been reasonably accurate.

Explanation:

I got a 100% on this assignment copy it and put it on your notes then go sentence by sentence copy but dont highlight any "." you will not be able to paste it into the box add the "." after you paste it, it one sentence.

ONE SENTENCE AT A TIME NO ". ' - or :" AT ALL

An electrical arc blast can approach temperatures of 35,000°F (19,426°C), which vaporizes metal parts and produces an explosive and deadly pressure wave.

An electrical fault with a high fault current or an electric arc fault can result in an explosive release of energy known as an electric arc blast. It's a dangerous situation that could seriously harm nearby equipment and endanger people's safety. The quick release of high-pressure gases, great heat, and intense light that occur during an electric arc blast cause an explosive explosion-like phenomena. The blast may cause the air around it to rapidly expand, creating a shockwave and launching debris into the air.

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The magnitude of the electric field between the plates is 5.58 x 10⁵ N/C.

The electric field between the plates can be calculated using the formula E = σ/ε0, where σ is the surface charge density and ε0 is the permittivity of free space.

First, we need to calculate the surface charge density. The surface area of one plate is A = (18.0 cm)² = 0.0324 m². The number of electrons moved from one plate to the other is 1012, and the charge of one electron is 1.6 x 10⁻¹⁹ C. So the total charge moved is Q = (1012)(1.6 x 10⁻¹⁹ C) = 1.6 x 10⁻⁷ C.

The surface charge density is then σ = Q/A = (1.6 x 10⁻⁷ C)/(0.0324 m²) = 4.94 x 10⁻⁶ C/m².

The permittivity of free space is ε0 = 8.85 x 10⁻¹² F/m.

So the electric field between the plates is E = σ/ε0 = (4.94 x 10⁻⁶ C/m²)/(8.85 x 10⁻¹² F/m) = 5.58 x 10⁵ N/C.

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The Position-Time graph for the given Velocity-Time graph is drawn in the image attached.

From the Velocity-Time graph we can take the information needed.

\(t_{1}\) = 1 s

\(t_{2}\) = 2 s

\(t_{3}\) = 3 s

\(t_{4}\) = 4 s

\(t_{5}\) = 5 s

\(v_{1}\) = 10 m / s

\(v_{2}\) = 20 m / s

\(v_{3}\) = 30 m / s

\(v_{4}\) = 40 m / s

\(v_{5}\) = 50 m / s

v = d / t

d = v * t

\(d_{1}\) = 10 * 1 = 10 m

\(d_{2}\) = 20 * 2 = 40 m

\(d_{3}\) = 30 * 3 = 90 m

\(d_{4}\) = 40 * 4 = 160 m

\(d_{5}\) = 50 * 5 = 250 m

Therefore, the Position-Time graph is drawn in the image attached.

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Answer:

28 m/s

Explanation:

We can use this constant acceleration kinematic equation to find the speed of this beam as it is dropped from 40 m.

Since the object is dropped vertically downwards, we know that the object is in free-fall.

The acceleration of this object is -g, which is -9.8 m/s² since we are making the positive direction upwards and the negative direction downwards.

The initial velocity is 0 m/s since the object is dropped and starts from rest.

The final velocity is what we are trying to solve for.

The displacement in the y-direction is 40 m.

Now we can see which equation contains these 4 variables:

Plug in the known variables.

Simplify this equation.

Take the square root of both sides.

The speed of the 330 kg beam dropped from 40 m is 28 m/s.

Answer:

Explanation:

Given information :

mass = 330kg

height =40m

v = √2gh

Where ;

g = acceleration due to gravity = 9.8 or 10 m/s

h = height

how much total energy of the beam just as it hits the ground =

mgh

\(330\times 10\times 40\\\\\\=132000\)

Speed at which  the beam will hit the ground :

\(v = \sqrt{2\times 10\times40} \\\\=\sqrt{800}\\\\=20\sqrt{2}\\\\v=28.28427\)

The volume of a material is directly related to its temperature in that thermal expansion occurs with an increase in temperature while thermal contraction occurs with a decrease in temperature.

The effect of heat, when applied to a substance, is that it may result in thermal expansion or thermal contraction when heat is removed

Thermal expansion refers to the increase in the size of a material when heat is applied to the substance resulting in temperature increase. Thermal expansion may be an increase in volume, area, or length.

Thermal contraction refers to the decrease in the size of a material when heat is removed from the substance. Thermal expansion may be a decrease in volume, area, or length.

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The distance to your friend is approximately 20 meters. To determine the distance, we can analyze the projectile motion of the baseball.

The initial speed of the baseball is 20 m/s, and it is thrown at an angle of 40 degrees. Since the height of both you and your friend is approximately the same, we can ignore the vertical component of the motion and focus on the horizontal component.

Using the horizontal component, we can calculate the time of flight of the ball. The time it takes for the ball to travel from you to your friend and back is the total time of flight. Since the distance from you to your friend is the same as the distance from your friend to you, we can divide the total time of flight by 2 to get the time it takes for the ball to travel from you to your friend.

Using the equation for the horizontal distance traveled by a projectile, which is given by distance = initial velocity * time, we can calculate the distance. Plugging in the values, we have distance = (20 m/s * (2 * sin(40))) / 2 = 20 m. Therefore, your friend is approximately 20 meters away from you.

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In each pair, the nuclide with the radioactive property is as follows: 47102Ag, 1024Ne, and 90223Th.

What is nuclide?

An atomic nucleus with a particular composition of protons and neutrons is referred to as a nuclide. It can be recognised by its mass number (the total number of protons and neutrons) and atomic number (the quantity of protons). Nuclides can be radioactive or unstable (stable).

Let's examine each pair of nuclides to determine which one is radioactive and which one is stable:

a. 47102Ag or 47109Ag:

In this case, 47102Ag is radioactive, while 47109Ag is stable. The notation "Ag" represents the element silver.

b. 1225Mg or 1024Ne:

Among these nuclides, 1225Mg is stable, while 1024Ne is radioactive. "Mg" represents the element magnesium, and "Ne" represents the element neon.

c. 8120371 or 90223Th:

Between these nuclides, 90223Th is radioactive, while 81203TI is stable. "Th" stands for the element thorium.

To summarize:

a. 47102Ag (radioactive), 47109Ag (stable)

b. 1225Mg (stable), 1024Ne (radioactive)

c. 81203TI (stable), 90223Th (radioactive)

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The complete question is:( Paraphrase)

Select the radioactive nuclide from the following pair as your question's topic area. (One is recognised as radioactive, while the other is stable.)

a.47102Ag or 47109Ag

b. 1225Mg or 1024Ne

c. 81203Tl or 90223Th