Help please urgent
if the gross primary productivity of a desert is 300 gc/m2/year, how much productivity is lost to cellular respiration?

50 gc/m2/year
150 gc/m2/year
250 gc/m2/year
350 gc/m2/year

a. The Aya's weight on Earth is 441 Newtons.

b. The Aya's mass on the moon would still be 45 kg.

c. Aya's weight on the moon is 72 Newtons.

a. Ayas weight on Earth can be calculated using the formula:

Weight = mass * gravitational acceleration

The gravitational acceleration on Earth is 9.8 m/\(s^2\).

Plugging in the given mass:

Weight = 45 kg * 9.8 m/\(s^2\) = 441 N

Therefore, Ayas' weight on Earth is 441 Newtons.

b. Aya's mass remains the same on the moon as it does on Earth. Therefore, Aya's mass on the moon would still be 45 kg.

c. To calculate Aya's weight on the moon, we need to consider the gravitational acceleration on the moon. The gravitational acceleration on the moon is approximately 1.6 m/\(s^{2}\). Using the same formula:

Weight = mass * gravitational acceleration

Weight = 45 kg * 1.6 m/\(s^{2}\) = 72 N

Therefore, Aya's weight on the moon is 72 Newtons.

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Explanation:

What we know:

Sa + Sb = 350 km

Ta + Tb = 4h

S = Vt

With these equations above we can write a system of equations and find Tb, as you see in the picture(s).

After having Tb you can easily find Ta and then Sa and Sb. Hopefully it was clear.

The k-factor for the hexagonal lattice of 1.4 cm radius natural uranium rods and graphite, with a lattice pitch of 20 cm, is approximately 0.907.

To calculate the k-factor for a hexagonal lattice of uranium rods and graphite, we need to determine the number of uranium rods within a given area and the total area of the unit cell.

1. First, let's calculate the area of the hexagonal unit cell:

The lattice pitch is given as 20 cm, which is the distance between the centers of adjacent uranium rods.

The radius of the uranium rods is 1.4 cm, so the distance between their centers is twice the radius, which is 2.8 cm.

The distance between the centers of the graphite rods will also be 2.8 cm.

Now, we can calculate the area of the hexagonal unit cell using the formula:

Area = (3√3/2) * (distance between centers)^2

Area = (3√3/2) * (2.8 cm)^2

Area ≈ 21.2 cm^2

2. Next, we need to determine the number of uranium rods within the unit cell.

The hexagonal lattice arrangement allows for 1 uranium rod at the center and 6 uranium rods surrounding it.

Total number of uranium rods in the unit cell = 1 (center) + 6 (surrounding) = 7 rods

3. Finally, we can calculate the k-factor using the formula:

k = (1 - (ρ_graphite/ρ_uranium)) * (Number of uranium rods/Area)

The density of uranium (ρ_uranium) is approximately 19.1 g/cm^3.

The density of graphite (ρ_graphite) is approximately 2.26 g/cm^3.

k = (1 - (2.26 g/cm^3 / 19.1 g/cm^3)) * (7 rods / 21.2 cm^2)

k ≈ 0.907

Therefore, the k-factor for the hexagonal lattice of 1.4 cm radius natural uranium rods and graphite, with a lattice pitch of 20 cm, is approximately 0.907.

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The maximum work required by the machine is 16420 J.

Work is energy transferred to or from an object via the application of the  force along with the  displacement. Work is the  standard mechanical  quantity. In its simple form, for a constant force aligned with it  direction of motions the work equals the product of the forced by the  strength and to the  distance traveled.

Here mass M is 215 kg

And the height lifted H is 5.65

The energy or workdone needed to lift is W= MgH = 215(9.8)(5.65)= 11904.5 J

The minimum efficiency of to  the machine is 72.5 %

So we can write that

The workdone by machine is

11904.5(100/72.5) = 16420 J ( approx)

So the workdone by machine is 16420 J

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Answer:

C. A Covalent Bond

Explanation:

two covalent bond form between the two oxygen atoms because oxygen requires two shared electrons to fill its outermost shell

The correct statement is B. There is a force acting on the red positive charge that has the same magnitude and direction as the force acting on the black positive charge.

In the given scenario, there are two positive charges, one red and one black, in a simulation. It is stated that the simulation does not show an electrostatic force acting on the red positive charge. Based on this information, we can deduce that the black positive charge exerts an electrostatic force on the red positive charge.

According to Coulomb's law, like charges repel each other, which means that two positive charges will experience a repulsive force. Since the red positive charge is not experiencing any force, it implies that the force acting on it has the same magnitude and direction as the force acting on the black positive charge.

Therefore, statement B is correct. Both charges experience an electrostatic force with the same magnitude and direction, resulting in a repulsive interaction between them. The absence of a force on the red positive charge indicates that the force acting on it is balanced by other forces in the simulation.

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Impulse is important because it is the force that changes an object's momentum.

Momentum is a physical concept that describes the movement of an object due to the product of its mass and velocity. Momentum is a vector quantity, meaning it has both a magnitude and a direction. In classical mechanics, momentum is conserved, meaning that the total momentum of a system remains constant over time.

In the examples given, impulse is what allows the elevator to be hoisted up, the nylon ropes to hold a climber's weight, the runner to move around the track, and the plane to take off from the runway. Without impulse, none of these activities would be possible.

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Assuming the steel deck has a coefficient of linear thermal expansion of 12 x 10-6 m/m/°C, the change in length of the steel deck of the span when the temperature increases from -5.0 degree C to 18.0 degree C is 2.16 m. (1410 m x 12 x 10-6 m/m/°C x 23°C = 2.16 m)

Steel is an alloy made of iron and other elements, and is one of the most widely used materials in the world. Steel structures such as bridges are subject to changes in size and shape due to changes in temperature. When steel is exposed to temperatures higher than 0°C, it expands, and when it is exposed to temperatures lower than 0°C, it contracts.

The coefficient of linear thermal expansion is the rate at which the length of an object changes with temperature. This coefficient can vary depending on the type of steel and other factors. For the Humber Bridge, the steel deck of the span has a coefficient of linear thermal expansion of 12 x 10-6 m/m/°C. Therefore, when the temperature increases from -5.0°C to 18.0°C, the steel deck of the span will expand by 2.16 m.

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Answer: The Coriolis effect results in bending the direction of surface currents to the right in the Northern Hemisphere and left in the Southern Hemisphere. The Coriolis effect causes winds and currents to form the circular patterns. The direction in which they spin depends upon the hemisphere in which they are present.Coriolis Effect is named after the French mathematician and physicist Gaspard-Gustave de Coriolis. It affects the weather patterns of an area, it affects the ocean currents, and it also affects air quality.

Answer:

truck 1 has the most velocity

Explanation:

Because it weights less which means it faster and yea

The speed of sound can be determined using the formula:

v = fλ

where v is the speed of sound, f is the frequency of the tuning fork and λ is the wavelength of the sound wave.

The wavelength of the sound wave can be calculated using the formula:

λ = 4L/n

where L is the length of the tube and n is the harmonic number.

From the given data, we have two tubes with lengths 30.0 cm and 98.0 cm that produce extra loud sounds for a tuning fork with a frequency of 256 Hz. The length of the tube with one closed end and one open end is equal to one-fourth of the wavelength of the sound wave produced by the tuning fork. Therefore, we can calculate the wavelength as follows:

λ = 4L/n

For L = 30.0 cm and n = 1,

λ1 = 4(30.0 cm)/1 = 120.0 cm

For L = 98.0 cm and n = 1,

λ2 = 4(98.0 cm)/1 = 392.0 cm

Since both tubes produce extra loud sounds for a tuning fork with a frequency of 256 Hz, we can assume that this frequency corresponds to the fundamental frequency (n=1). Therefore, we can calculate the speed of sound as follows:

v = fλ

v = (256 Hz)(120.0 cm) = 30720 cm/s

v = (256 Hz)(392.0 cm) = 100352 cm/s

Therefore, according to this data, the speed of sound is approximately 30720 cm/s or 100352 cm/s depending on which tube was used.

The average braking force acting on the car is -690N, So The correct option is b.)

To solve this problem, we can use the following formula:

\(d = (v_f^2 - v_i^2) / (2a)\)

where d is the distance traveled, v_f is the final velocity (0 m/s, since the car comes to a complete stop), v_i is the initial velocity (27 m/s), and a is the average braking acceleration.

We can rearrange this formula to solve for the braking acceleration:

\(a = (v_f^2 - v_i^2) / (2d)\)

Substituting the given values, we get:

\(a = (0^2 - 27^2) / (2 * 578.0) = -6.24 m/s^2\)

The negative sign indicates that the acceleration is in the opposite direction to the car's motion, i.e. it is a deceleration.

Finally, we can use Newton's second law (F = ma) to find the average braking force:

F = ma = (1100 kg)(-6.24 m/s²) = -6854.4 N

Rounding to the nearest 10 N, we get:

F ≈ -690 N

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Answer:

A book on a table before it falls.

A yoyo before it is released.

A raised weight.

Explanation:

These are all examples of potential energy. So I hope you can find something that is comparable from the lab.

Answer:

decreases 1/4 of the original value

If the distance between two charged particles is doubled, the force between them changes by a factor of 1/4.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Force between two charge particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

If the distance between two charged particles is doubled, the force between them changes by a factor of 1/4.

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Answer:

Universe, Galaxy, Sun.

Explanation:

The universe is everything. It contains billions of galaxies.

A galaxy, such as our Milky Way Galaxy, is a collection of solar systems orbiting around a central core. Most galaxies have a supermassive black hole at their centres.

Then the sun smallest.

Answer:

A metric prefix is a unit prefix that precedes a basic unit of measure to indicate a multiple or submultiple of the unit. All metric prefixes used today are decadic. Each prefix has a unique symbol that is prepended to any unit symbol.

Explanation:

In the metric system of measurement, designations of multiples and subdivision of any unit may be arrived at by combining with the name of the unit the prefixes deka, hecto, and kilo meaning, respectively, 10, 100, and 1000, and deci, centi, and milli, meaning, respectively, one-tenth, one-hundredth, and one-thousandth ...

Using Runge-Kutta 2nd order Heun's method, the speed (w) at t = 0.8s is approximately 0.0081.

Given:

Voltage input (V) = 30V

Initial speed (w) = 0

Step size (h) = 0.4s

Time at which speed is to be determined (t) = 0.8s

We need to determine the speed (w) at t = 0.8s using Heun's method.

We have k₁ = f(t₁, W₁) = 0.02 + 0.06w₁ (using the given equation)

At t = 0 and w = 0 (initial conditions), we have:

k₁ = 0.02 + 0.06(0) = 0.02

We have k₂ = f(t₁ + h, w₁ + k₁h) = 0.02 + 0.06(w₁ + 0.02h)

So, at t = 0.4s and w = 0 (initial conditions), we have:

k₂ = 0.02 + 0.06(0.02 * 0.4) = 0.02 + 0.00048 = 0.02048

So, W₂ = w₁ + (k₁ + k₂)(h/2)

   = 0 + (0.02 + 0.02048)(0.4/2)

   = 0.04048(0.2)

   = 0.008096

Therefore, using Runge-Kutta 2nd order Heun's method, the speed (w) at t = 0.8s is approximately 0.0081.

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The complete question is:

The speed of a motor supplied with a voltage input of 30V, assuming the system is without damping, can be expressed as 30 = (0.02)+(0.06)w dt If the initial speed is zero and a step size of h = 0.4 s, determine the speed w at t = 0.8 s by using the Runge-Kutta 2nd order Heun's method. Heun's method: Wi+1=W₁ = w₁ + (-/-^₁ + = -K ₂ ) h where, k₁ = f(t₁, W₁) and k₂ = f(t₁ + h, w₁ + k₁h), the speed (w) at t = 0.8s is approximately 0.0081.

Answer:

C is the answer

Explanation:

Earth is the third planet from the sun

you are cheating on your test, I know

Answer:

C..

Explanation:

I'm not sure about answer...

Option (c) and (d) are correct

a and b are the recessive alleles represented in genotype AaBb.

An allele is a different nucleotide sequence that codes for the production of a gene product at the same location on a lengthy DNA molecule.

Recessive Allele : A particular allele that, when present alone, has no effect on the person. The expression of the trait requires the presence of two copies of the allele.

Dominant Allele : A dominant allele is a gene variant that will result in a specific phenotype even when there are other alleles present.

Genotype - The genetic configuration that determines the features that an organism inherits from its parents is known as a genotype.

Phenotype - The term "phenotype" refers to an organism's observable physical characteristics, such as its appearance, growth, and behavior.

Hence (a) & (b) are the recessive alleles represented in the genotype AaBb.

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The triple point of water is the unique combination of temperature and pressure at which solid ice, liquid water, and water vapor can coexist in thermodynamic equilibrium. It is the point where the sublimation, fusion, and vaporization curves meet on the phase diagram of water. The triple point of water has a value of 273.16 K and a partial vapor pressure of 611.657 pascals

Solid ice form of carbon dioxide that is usually used as a coolant. The advantage of dry ice is that it is at a lower temperature than ice from water and doesn't leave any residue. Dry ice is usually used to keep frozen food cold in places where refrigeration is not available.

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The energy reduction when the two spherical nuclei coalesce to form one spherical nucleus, considering mass conservation and surface energy is ΔE = E_initial - E_final .

To calculate the energy reduction in the process when two spherical nuclei with surface energy (gamma) having radii r1 and r2 coalesce to form one spherical nucleus, follow these steps:
1. Calculate the initial surface area of the two separate nuclei:
A1 = 4πr1^2 and A2 = 4πr2^2
2. Calculate the initial total energy of the two separate nuclei:
E_initial = (A1 + A2) = (4πr1^2 + 4πr2^2)
3. Since mass is conserved, find the total volume of the coalesced nucleus:
V_total = (4/3)πr1^3 + (4/3)πr2^3
4. Calculate the radius (R) of the coalesced nucleus using its volume:
R^3 = (r1^3 + r2^3) (Since the (4/3)π term will cancel out when taking the cube root)
5. Calculate the surface area of the coalesced nucleus:
A_total = 4πR^2
6. Calculate the final total energy of the coalesced nucleus:
E_final = A_total = (4πR^2)
7. Finally, calculate the energy reduction in the process:
ΔE = E_initial - E_final = (4πr1^2 + 4πr2^2) - (4πR^2)
This will give you the energy reduction when the two spherical nuclei coalesce to form one spherical nucleus, considering mass conservation and surface energy .

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Answer: 4 s

Explanation:

Given

The applied force is 70 N

mass of the rock is 28 kg

initial velocity \(u=25\ m/s\)

final velocity \(v=15\ m/s\)

Deceleration provided by force is

\(a=-\dfrac{70}{28}=-2.5\ m/s^2\)

using the equation of motion

\(v=u+at\\\Rightarrow 15=25-2.5t\\\Rightarrow 2.5t=10\\\Rightarrow t=4\ s\)

The radius of gyration determines the point from the center of a flywheel where the mass can be concentrated and be equal to the actual distributed mass. In a rotating object, like a flywheel, the mass is distributed across the entire shape, which affects its rotational inertia.

The radius of gyration is a measure that simplifies this concept by considering an equivalent mass concentrated at a specific distance from the center. This distance is the radius of gyration, which can be calculated using the moment of inertia of the object.

By understanding and optimizing the radius of gyration, engineers can design more efficient and stable flywheels for various applications, such as energy storage and regulation of rotational speed.

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Answer:

I = 6 A

Explanation:

Given that,

Power of an electric heatr, P = 1.38 kW

The voltage of the mains supply, V = 230 V

We need to find the current through the heater. The electric power in terms of  voltage and current is given by :

\(P=V\times I\\\\I=\dfrac{P}{V}\\\\I=\dfrac{1.38\times 10^3}{230}\\\\I=6\ A\)

So, the current through an electric heater is 6 A.

These rules are described by specific examples of the ideal gas formula, PV = nRT, the new volume of nitrogen is approximately 23.2 L.

The chemical industry needs nitrogen to function. It's utilized in the production of explosives, nylon, colors, nitric acid, and fertilizers. The Haber process carries this out.

The atmosphere is the principal single source of nitrogen. An odorless, colorless, harmless gas, which makes up 78% of it, is present in it. Although nitrogen is present in the atmosphere, plants cannot utilize it.

The problem can be solved using Boyle's law, which states that the pressure and volume of a gas are inversely proportional at constant temperature. Mathematically, Boyle's law can be expressed as:

P1V1 = P2V2

where P1 and V1 are the initial pressure and volume, respectively, and P2 and V2 are the final pressure and volume, respectively.

We are given that the initial volume, V1, is 22.5 L, the initial pressure, P1, is 748 mmHg, and the final pressure, P2, is 725 mmHg. We can use Boyle's law to find the final volume, V2:

P1V1 = P2V2

748 mmHg x 22.5 L = 725 mmHg x V2

V2 = (748 mmHg x 22.5 L) / 725 mmHg

V2 ≈ 23.2 L

Therefore, the new volume is approximately 23.2 L.

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For an object to be in equilibrium, the sum of all the forces acting on it must be zero (sum of forces = zero) and the sum of all the torques applied to it must also be zero (sum of torques is zero). Additionally, the object must not be spinning and its speed must be zero (speed is zero).

Equilibrium is a state in which opposing forces or influences are balanced. It can refer to a physical, chemical, or biological system in which there is no net change in the position or direction of motion of its components. In economics, it is a situation in which all participants in the market have no incentive to change their behavior. Equilibrium is a necessary condition for markets to function efficiently. It is a key concept in many areas of economics, including microeconomics, macroeconomics, and international economics.

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The amount of energy (in joules) required to warm 4.37 g of silver by ΔT degrees Celsius can be calculated using the equation Q = 1.0488 * ΔT.

The specific heat capacity (C) of a substance is the amount of energy required to raise the temperature of 1 gram of that substance by 1 degree Celsius. In this case, the specific heat capacity of silver is 0.24 J/g°C.

To calculate the energy required to warm 4.37 g of silver, we need to multiply the mass (m) by the specific heat capacity (C) and the change in temperature (ΔT). The change in temperature is not provided in the question, so we'll assume it is given.

Let's assume the change in temperature is ΔT°C. The formula to calculate the energy (Q) is:

Q = m * C * ΔT

Substituting the given values:

Q = 4.37 g * 0.24 J/g°C * ΔT

The units of grams cancel out, and we are left with:

Q = 1.0488 J/°C * ΔT

So, the amount of energy (in joules) required to warm 4.37 g of silver by ΔT degrees Celsius can be calculated using the equation Q = 1.0488 * ΔT.

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Answer:

58.6 m/s²

Explanation:

Applying,

s = ut+gt²/2............ equation 1

Where s = height of the rock, u = initial velocity, t = time, g = accelration due to gravity of the planet.

From the question,

Given: s = 1.55 m, t = 0.23 s, u = 0 m/s (dropped from an height)

Substitute these values into equation 1

1.55 = (0×0.23)+g(0.23²)/2

1.55 = 0.0529g/2

0.0529g = 3.1

g = 3.1/0.0529

g = 58.6 m/s²

Answer:

I'm guessing life insurance i don't know tho

Explanation: