help.. please... my due is in 5 minutes ​

Answer:The amount of a 80% acid solution that must be mixed with a 55% solution to produce 600 mL of a 60% solution can be calculated using a simple algebraic equation. Let x represent the amount of the 80% acid solution in mL that needs to be mixed with the 55% solution.

The equation can be set up as follows:

0.80x + 0.55(600 - x) = 0.60(600)

Step-by-step explanation: The left-hand side of the equation represents the total amount of acid in the mixture. The first term, 0.80x, represents the amount of acid from the 80% solution, and the second term, 0.55(600 - x), represents the amount of acid from the 55% solution. The right-hand side of the equation represents the total amount of acid in the final 60% solution, which is 60% of 600 mL.

By solving this equation for x, we can determine the amount of the 80% acid solution that needs to be mixed with the 55% solution. Once we have the value of x, we can then calculate the amount of the 55% solution by subtracting x from 600 mL.

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Let x=amount of 80% solution needed

Then 600-x=amount of 30% solution needed

Now we know that the pure acid in the 80% solution (0.80x) plus the amount of pure acid in the 30% solution ((0.30)(600-x)) has to equal the amount of pure acid in the final mixture(0.40*600), so our equation to solve is:

0.80x+0.30(600-x)=0.40*600 get rid of parens

0.80x+180-0.30x=240 subtract 180 from each side

0.80x+180-180-0.30x=240-180 collect like terms

0.50x=60 divide each side by 0.50

x=120 ml---------------------amount of 80% solution needed

600-x=600-120=480 ml---------------amount of 30% solution needed

CK

120*0.80+480*0.30=0.40*600

96+144=240

240=240

The probability that a randomly selected integer from the first 100 positive integers is divisible by 3 or 5 is 47/100. The events of choosing an integer divisible by 3 and choosing an integer divisible by 5 are not independent.

To find the probability that a randomly selected integer from the first 100 positive integers is divisible by 3 or 5, we need to count the number of integers in this range that are divisible by 3 or 5, or both.

There are 33 integers in the range from 1 to 100 that are divisible by 3: 3, 6, 9, ..., 99. Similarly, there are 20 integers in this range that are divisible by 5: 5, 10, 15, ..., 100. However, some of these integers are divisible by both 3 and 5, which means we have counted them twice. To find the total number of integers that are divisible by 3 or 5, we need to subtract the number of integers that are divisible by both 3 and 5 (which are the multiples of 15):

33 + 20 - 6 = 47

So, there are 47 integers out of the first 100 positive integers that are divisible by 3 or 5.

To find out whether the two events of choosing an integer divisible by 3 and choosing an integer divisible by 5 are independent, we need to check whether the probability of one event changes if the other event has already occurred.

Let A be the event of choosing an integer divisible by 3, and B be the event of choosing an integer divisible by 5. We can find the probabilities of these events as follows:

P(A) = 33/100

P(B) = 20/100

To check for independence, we need to compare the probability of A given that B has occurred (i.e., the probability of choosing an integer divisible by 3, given that we know it is also divisible by 5) with the probability of A without any information about B:

P(A|B) = P(A and B) / P(B)

Since the multiples of 15 are the only integers that are divisible by both 3 and 5, we have:

P(A and B) = P(15) / 100 = 1/20

So,

P(A|B) = (1/20) / (20/100) = 1/4

This means that if we know an integer is divisible by 5, the probability that it is also divisible by 3 is 1/4.

Now, let's compare this with the probability of A without any information about B:

P(A) = 33/100

Since P(A|B) ≠ P(A), we can conclude that the events of choosing an integer divisible by 3 and choosing an integer divisible by 5 from the first 100 positive integers are not independent.

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Answer:

26.46

Step-by-step explanation:

24.50 x .08 = 1.96 (this is our sales taxes)

1.96 + 24.50 = 26.46

0:5 and 0:20 are equivalent. You multiply both 0 and 5 by 4 to get 0 and 20.

Answer:

The set D has 5 elements - 3, 6, 9, 12, and 15, all of which are multiples of 3.

\(\textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\\\ \begin{array}{llll} \textit{logarithm of factors} \\\\ \log_a(xy)\implies \log_a(x)+\log_a(y) \end{array} ~\hspace{4em} \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} \\\\[-0.35em] ~\dotfill\)

\(12^3~~ = ~~x^4 y^3 z^6\implies \log_{12}(x^4 y^3 z^6)=3 \\\\\\ \log_{12}(x^4)~~ + ~~\log_{12}(y^3)~~ + ~~\log_{12}(z^6)~~ = ~~3 \\\\\\ 4\log_{12}(x)~~ + ~~3\log_{12}(y)~~ + ~~6\log_{12}(z)~~ = ~~3\)

The triangles are similar by SSS congruence of triangles.

What is SSS congruence of triangles?

The two triangles are congruent if the three sides of one triangle are the same as the corresponding three sides (SSS) of the other triangle.

We are given two triangle ABC and PQR.

In order to see whether these are similar or not, we will use the SSS congruence of triangles.

The ratio of sides are:

⇒AB : PQ = 8 : 6

⇒AB : PQ = 4 : 3

Similarly,

⇒BC : QR = 12 : 9

⇒BC : QR = 4 : 3

Similarly,

⇒AC : PR = 12 : 9

⇒AC : PR = 4 : 3

Since, the ratio of all the sides is same so, the triangles are similar.

Hence, the triangles are similar by SSS congruence of triangles.

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Since, there are multiple questions so, the question answered above is attached below

Answer:

2

Step-by-step explanation:

15/3=5

25/5 = 5

10/2 = 5

Answer:

2

Step-by-step explanation:

You have to find the "pattern."

for 15 and 3, you have to divide 15 by 5 and thats 3.

for 25 and 5, 25/5 is 5, so 10/5 is 2.

Answer:

\(2*log(x)+log(y)\)

Step-by-step explanation:

So, there are two logarithmic identities you're going to need to know.

Logarithm of a power:

   \(log_ba^c=c*log_ba\)

   So to provide a quick proof and intuition as to why this works, let's consider the following logarithm: \(log_ba=x\implies b^x=a\)

   Now if we raise both sides to the power of c, we get the following equation: \((b^x)^c=a^c\)

   Using the exponential identity: \((x^a)^c=x^{a*c}\)

    We get the equation: \(b^{xc}=a^c\)

    If we convert this back into logarithmic form we get: \(log_ba^c=x*c\)

    Since x was the basic logarithm we started with, we substitute it back in, to get the equation: \(log_ba^c=c*log_ba\)

Now the second logarithmic property you need to know is

The Logarithm of a Product:

    \(log_b{ac}=log_ba+log_bc\)

    Now for a quick proof, let's just say: \(x=log_ba\text{ and }y=log_bc\)

    Now rewriting them both in exponential form, we get the equations:

    \(b^x=a\\b^y=c\)

    We can multiply a * c, and since b^x = a, and b^y = c, we can substitute that in for a * c, to get the following equation:

    \(b^x*b^y=a*c\)

   Using the exponential identity: \(x^{a}*x^b=x^{a+b}\), we can rewrite the equation as:

   \(b^{x+y}=ac\)

   taking the logarithm of both sides, we get:

   \(log_bac=x+y\)

   Since x and y are just the logarithms we started with, we can substitute them back in to get: \(log_bac=log_ba+log_bc\)

Now let's use these identities to rewrite the equation you gave

\(log(x^2y)\)

As you can see, this is a log of products, so we can separate it into two logarithms (with the same base)

\(log(x^2)+log(y)\)

Now using the logarithm of a power to rewrite the log(x^2) we get:

\(2*log(x)+log(y)\)

\(\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ a^2+o^2=c^2\implies o=\sqrt{c^2 - a^2} \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{11}\\ a=\stackrel{adjacent}{6}\\ o=\stackrel{opposite}{RT} \end{cases} \\\\\\ RT=\sqrt{ 11^2 - 6^2}\implies RT=\sqrt{ 121 - 36 } \implies RT=\sqrt{ 85 }\implies RT\approx 9.22\)

Answer:

Well I think you have to do 20% times 8 then divide it 100

Step-by-step explanation:

Answer:

x^2-2x-48

Step-by-step explanation:

FOIL

Firsts = x*x = x^2

outside = x*-6 = -6x

inside = 8*x = 8x

lasts = 8*-6 = -48

add all together x^2-6x+8x-48 = x^2-2x-48

Answer:

x² + 2x - 48

Step-by-step explanation:

( x + 8 ) ( x - 6 )

=  x ( x - 6 ) + 8 ( x - 6 )

= x*x - 6*x + 8*x + 8*( - 6 )

= x² - 6x + 8x  - 48

= x² + 2x - 48

The evaluation of the two more bids Bruno received, and the equations, table and graph obtained from the bids are as follows;

x = The number of books

y = The total charge based on the pricing

The equations are;

Bid 7: y = 15·x + 3

Bid 8: y = 10·x + 40

Please find the completed table in the following explanation part

Part B;

Please find attached the graph of the two equations, created with MS Excel

An equation is a mathematical statement indicating that the quantity, magnitude or values of two expressions are the same.

The amount Bid 7 charges per book = $15

Amount paid upfront for Bid 7 = $5

Amount Bid 8 charges upfront = $40

Amount Bid 8 charges per book = $10

The variables are;

The equations are;

The table of values can be presented as follows;

                   Bid 7               \({}\)        Bid 8

x             \({}\) y = 15·x + 5              y = 10·x + 40

0               \({}\)       5               \({}\)          40

3               \({}\)       50               \({}\)        70

5               \({}\)       80               \({}\)        90

7               \({}\)       110               \({}\)        110

10               \({}\)     155               \({}\)       140

Part B;

Please find attached the required graph of the two equations, showing the legend and the scale for the x and y axis created with MS Excel.

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Solution:

Given the following data:

The mean is expressed as

Thus, we have

Hence, the mean is evaluated to be

The rate of change of the simple index over one day is approximately 12.78%.

To calculate the rate of change of the simple index over one day, we need to determine the percent change in the total value of the index between Monday's opening and Tuesday's opening.

On Monday, Stock A has 5000 shares at $2.75 per share, so its total value is:

Total value of Stock A on Monday = 5000 * $2.75 = $13,750

Similarly, on Monday, Stock B has 3000 shares at $4.30 per share, so its total value is:

Total value of Stock B on Monday = 3000 * $4.30 = $12,900

The total value of the index on Monday is the sum of the values of Stock A and Stock B:

Total value of the index on Monday = $13,750 + $12,900 = $26,650

On Tuesday, Stock A opens at $3.10 per share, and Stock B opens at $4.85 per share. Both stocks still have the same number of shares as on Monday.

The total value of Stock A on Tuesday is:

Total value of Stock A on Tuesday = 5000 * $3.10 = $15,500

The total value of Stock B on Tuesday is:

Total value of Stock B on Tuesday = 3000 * $4.85 = $14,550

The total value of the index on Tuesday is the sum of the values of Stock A and Stock B:

Total value of the index on Tuesday = $15,500 + $14,550 = $30,050

To calculate the percent change in the index, we use the formula:

Percent Change = ((New Value - Old Value) / Old Value) * 100

Percent Change = (($30,050 - $26,650) / $26,650) * 100 ≈ 12.78%

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The coupon rate of the bonds by King of Diamonds Industries would be 7 %.

The formula for the bond price shows the coupon payment and so can be used to find the coupon rate:

= (Coupon payment  x ( 1 - ( 1 + r ) ^ ( - number of years till maturity ) ) ) / r + Face value /  (1  + rate )^ number of years

1,482.01 = (C x (1 - (1 + 0.07 )^ (- 14) ) ) / 0.07 + F / (1 + 0.07 ) ^ 14

103.7407 - 0.07 x (F / (1 + 0.07) ^14 ) = C x  (1 - ( 1 + 0.07) ^ ( - 14) )

Using a calculator, C is $ 70.

This means that the coupon rate is:

= 70 / 1, 000

= 7 %

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\(\\ \sf\longmapsto ∆AED=∆ABO\)

\(\\ \sf\longmapsto \dfrac{AE}{AB}=\dfrac{AD}{AO}\)

\(\\ \sf\longmapsto \dfrac{AD}{AE}=\dfrac{AB}{AO}\)

Explanation:

Given that

In ∆ ABC, DE is a line drawn on AB and AC

In ∆ ADE and ∆ ABC

∠ AED = ∠ ABC = 70°

∠ AED = ∠ BAC (Common vertex angle )

By AA similarity criteria

∆ ADE and ∆ ABC are similar triangles

⇛ ∆ ADE ~ ∆ ABC

We Know that

If two polygons of same number of sides are said to be similar,

If the corresponding angles are equal.

If the corresponding sides are in the same ratio or in proportion.

So, The corresponding angles are mist be in proportion

⇛ AD / DB = AE/EC

Key Knowledge:-

Note :-

Answer:

2.89 MB

Explanation:

From the question, we're told that a standard MP3 file at 128 bits per second (Kbps) results in a 0.96 MB file size per minute of audio play, so if the music in the file played for 3.01 minutes, we can go ahead and determine the size.

Let x represent the size of the file, we can go ahead and solve for as seen below;

The time in minutes at which a pyroclastic flow will reach the town  is 0.3 minutes and the functions are t = 30/r, r = 30/t and d = 30r

Here, we have:

Distance = 30 kilometers

Rate = 100 kilometers per minute

The time is calculated as:

Time = Distance/Rate

So, we have

Time = 30/100

Evaluate

Time = 0.30

Hence, the time in minutes at which a pyroclastic flow will reach the town  is 0.3 minutes

Here, we have

Distance = 30 kilometers

Rate = r

The time is calculated as:

Time = Distance/Rate

So, we have

t = 30/r

Hence, the function for time is t = 30/r and the domain is r > 0

Here, we have

Distance = 30 kilometers

Time = t

The time is calculated as:

Time = Distance/Rate

So, we have

t = 30/r

The maximum speed is 10 km/min

So, we have:

t = 30/10 = 3

Rewrite t = 30/r as:

r = 30/t

Hence, the function for rate is r = 30/t and the domain is 0 < t < 3

Here, we have

time = 30 minutes

Rate = r

The time is calculated as:

Time = Distance/Rate

So, we have

30 = d/r

So, we have

d = 30r

Hence, the function for time is d = 30r and the domain is r > 0

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Answer:

c

Step-by-step explanation:

Where is it located?

Answer:

D

Step-by-step explanation:

Answer:

this list

Step-by-step explanation:

1×12000=12000

2×6000=12000

3×4000=12000

4×3000=12000

5×2400=12000

6×2000=12000

8×1500=12000

10 ×1200=12000

12 ×1000=12000

It would take 370 days to build the wall with the given conditions.

If 60 men can build a wall in 40 days, then the total man-days required to build the wall is:

60 men x 40 days = 2400 man-days

However, 55 men quit every ten days, which means that after 10 days, there are only 60 - 55 = 5 men left to work on the wall. After 20 days, there are only 5 - 55 = -50 men left, which means that the remaining 5 men cannot work any faster than they were already working. Therefore, we can assume that the remaining 5 men complete the wall on their own.

The number of man-days required for the first 10 days is:

60 men x 10 days = 600 man-days

The number of man-days required for the second 10 days is:

5 men x 10 days = 50 man-days

The total number of man-days required for the first 20 days is:

600 man-days + 50 man-days = 650 man-days

The remaining work can be completed by the 5 men in:

2400 man-days - 650 man-days = 1750 man-days

Therefore, the total time needed to build the wall is:

20 days + 1750 man-days / 5 men = 20 + 350 days = 370 days

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Computing the total number of counters in the class as 1,108, the mean number of counters that the 46 children have is 24.

The mean refers to the average value.

The average is the quotient of the total value divided by the number of items in the data set.

The number of boys in the class = 26

The number of girls in the class = 20

The total number of boys and girls in the class = 46

The mean number of counters that the boys have = 28

The total number of counters that the boys have = 728 (28 x 26)

The mean number of counters that the girls have =19

The total number of counters that the girls have = 380 (19 x 20)

The total number of counters that the class has = 1,108 (728 + 380)

The average or mean number of counters in the class = 24 (1,108 ÷ 46)

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Answer:

3

Step-by-step explanation:

15x+6=10x+21

5x=15

x=3

Answer: x=3

Step-by-step explanation:

\(15x+6=10x+21\\5x+6=21\\5x=15\\x=3\)

Answer:11

Step-by-step explanation:

Answer:

m > 4

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Step-by-step explanation:

Step 1: Define

11 + m > 15

Step 2: Solve for m

Here we see that any value m greater than 4 would work as a solution to the inequality.