Help please I’m gonna fail

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Let h and s represent the numbers in the House and Senate, respectively. Then we have ...

  h + s = 88

  h - s = 54

Subtracting the second equation from the first gives ...

  (h +s) -(h -s) = (88) -(54)

  2s = 34 . . . . . simplify

  s = 17 . . . . . . . divide by 2

  h = 88 -17 = 71 . . . . find the other value using the sum equation

There were 71 females in the House of Representatives, and 17 females in the Senate.

Answer:

Step-by-step explanation:

The coordinates of point Y are (9 , 12)

Step-by-step explanation:

* Lets explain how to solve the problem

- If point (a , b) divides a line whose end points are (c , d) and (e , f) at

ratio p : q from the point (c , d), then

 and

∵ Segment XY has one endpoint at X (0 , 0)

∵ Point (3 , 4) is 1/3 of the way from X to Y

∴ Point (3 , 4) divides the segment XY,  where the distance from X

 to the point (3 , 4) is 1 part and from point (3 , 4) to Y is 2 parts

∴ Point (3 , 4) divides segment XY to the ratio 1 : 2 from X

- Let point (a , b) is (3 , 4)

- Let point (c , d) is X (0 , 0)

- Let point (e , f) is Y

- Let p : q = 1 : 2

* Lets find e and f

∵

∴

∴

- Multiply both sides by 3

∴ 9 = e

∴ The x-coordinate of point Y is 9

∵

∴

∴

- Multiply both sides by 3

∴ 12 = f

∴ The y-coordinate of point Y is 12

* The coordinates of point Y are (9 , 12)

The measure of distance x, that is, the distance between a point P and the point of horizon, is equal to 284.372 miles.

In this problem we must determine the distance between a point P located about earth's circumference and the point of horizon, located on earth's circumference. Since the line between these two points is tangent to earth, then, distance x can be found by Pythagorean theorem:

x = √[(3959 mi + 10.2 mi)² - (3959 mi)²]

x = 284.372 mi

The distance x is equal to 284.372 miles.

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Answer: The Brown family ate 1.85 pies in all

Step-by-step explanation: If you think about it all you have to do is 0.75+0.5= 1.25 and then you do 1.25+ 0.6  and then get 1.85 so they ate 1.85 pies in all

Hope this helped!!!!

The quotient is 2x² - 7 and the remainder is -12.

How to perform polynomial division?

To perform this polynomial division, we use the long division method, where we divide the leading term of the dividend by the leading term of the divisor to obtain the first term of the quotient. Then, we multiply the entire divisor by this term and subtract the result from the dividend. We repeat this process with the new dividend until we obtain a remainder of degree less than the divisor.

Here is the long division:

2x² - 7

--------------------

x² + 1 | 2x⁴ + 0x³ + 0x² - 7x - 12

- (2x⁴ + 0x²)

--------------

-7x² - 7x

+ ( -7x² - 7x)

--------------

-12

Therefore, the quotient is 2x² - 7, and the remainder is -12.

So we can express the division as:

2x⁴ - 7x - 12 = (x² + 1)(2x² - 7) - 12

Hence, the quotient is 2x² - 7 and the remainder is -12.

This is a problem of division.

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Answer:

\(21.7 x 10^5\)

Step-by-step explanation:

(6.2 x 10²) x (3.5 x 10³)

First, multiply the coefficients: 6.2 x 3.5 = 21.7.

Then, add the exponents: 10² x 10³ = 10^(2+3) = 10^5.

Therefore, the result is 21.7 x 10^5.

Answer:

3286000

Step-by-step explanation:

The function h(x) = 5 square root x e^-x is increasing on the interval (0, ∞) and decreasing on the interval (-∞, 0).

1. Calculate h'(x) = 5 (1/2 x^-1/2 e^-x - x^1/2 e^-x)

2. Set h'(x) = 0 to find the critical points.

3. Since h'(x) < 0 for x < 0 and h'(x) > 0 for x > 0, h(x) is decreasing for x < 0 and increasing for x > 0.

4. Therefore, h(x) is increasing on the interval (0, ∞) and decreasing on the interval (-∞, 0).

The derivative of h(x) = 5 square root xe^-x is h'(x) = 5 (1/2 x^-1/2 e^-x - x^1/2 e^-x). Setting h'(x) = 0 gives the critical points of the function. Since h'(x) is negative for x < 0 and positive for x > 0, this tells us that the function is decreasing for x < 0 and increasing for x > 0. So, h(x) is increasing on the interval (0, ∞) and decreasing on the interval (-∞, 0). We can also conclude from the graph of the function that it is concave down for x < 0 and concave up for x > 0.

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(a) It looks like you're saying

\(\displaystyle F(x) = \int_0^x (t - 3t^2 + 7) \, dt\)

Find the critical points of F(x). By the fundamental theorem of calculus,

F'(x) = x - 3x² + 7

The critical points are where the derivative vanishes. Using the quadratic formula,

x - 3x² + 7 = 0   ⇒   x = (1 ± √85)/6

Compute the second derivative of F :

F''(x) = 1 - 6x

Check the sign of the second derivative at each critical point.

• x = (1 + √85)/6 ≈ 1.703   ⇒   F''(x) < 0

• x = (1 - √85)/6 ≈ -1.370   ⇒   F''(x) > 0

This tells us F attains a minimum of

\(F\left(\dfrac{1-\sqrt{85}}6\right) \approx \boxed{-6.080}\)

(b) Split up the domain of F at the critical points, and check the sign of F'(x) over each subinterval.

• over (-∞, -1.370), consider x = -2; then F'(x) = -7 < 0

• over (-1.370, 1.703), consider x = 0; then F'(x) = 7 > 0

• over (1.703, ∞), consider x = 2; then F'(x) = -3 < 0

This tells us that

• F(x) is increasing over ((1 - √85)/6, (1 + √85)/6)

• F(x) is decreasing over (-∞, (1 - √85)/6) and ((1 + √85)/6, ∞)

(c) Solve F''(x) = 0 to find the possible inflection points of F(x) :

F''(x) = 1 - 6x = 0   ⇒   6x = 1   ⇒   x = 1/6

Split up the domain at the inflection point and check the sign of F''(x) over each subinterval.

• over (-∞, 1/6), consider x = 0; then F''(x) = 1 > 0

• over (1/6, ∞), consider x = 2; then F''(x) = -11 < 0

This tells us that

• F(x) is concave up over (-∞, 1/6)

• F(x) is concave down over (1/6, ∞)

Answer:

35

Step-by-step explanation:

The largest prime less than 50 is 47

The smallest composite number greater than 10 is 12

47 - 12 = 35

Answer:

yes it is the irrational number

Answer:

31/13 could be tested by dividing it and obtaining its decimal expansion and if it has a decimal expansion that is terminating [it has limited decimal places] or repeating[the same number repeat with a pattern till infinity] it will be a rational number. And if it doesnt end or repat with a pattern, 31/13  will be  an irrational number.

So lets divide 31 by 13 to get its DECIMAL EXPANSION

31/13 = 2.384615384615..............................

here in the answer we see that decimals 384615 repeats till infinity, so its a NON-TERMINATING[non-stopping or unlimitted]  but REPEATING decimal expansion... thus 31/13 is a rational number

NOTE: SEE THE ATTACHMENT TO UNDERSTAND THE DIVISION PART AND I DONT RECOMMEND YOU USE A CALCULATOR FOR THESE SUCH QUESTIONS AS THE CALCULATORS GIVE U EXCAT RESULT BUT NOT THE FULL ONE LIKE IN THIS CASE AND ALL YOU WONT EVEN KNOW IF IT TERMINATES OR REPEATS SO BETTER DO IT IN PAPER AND SEE THE RESULT

The value of the container's contents is approximately $983.25

To find value of the contents, we must calculate its volume first.

Volume = length x width x height

Volume = 4.5 ft x 11.5 ft x 10.5 ft

Volume = 534.375 cubic feet

The container is full and its contents have a volume of 534.375 cubic feet. If its contents weigh 0.4 pounds per cubic, then, total weight of the contents is:

= Volume x Weight per cubic foot

= 534.375 cubic feet x 0.4 pounds per cubic foot

= 213.75 pounds

If the contents are worth $4.60 per pound on average, then the total value of the contents is:

= Weight x Value per pound

= 213.75 pounds x $4.60 per pound

= $983.25.

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Answer:

\(\frac{1}{4845}\) probability that you and your 3 friends will be selected.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question, the order in which the volunteers are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

\(C_{n,x}\) is the number of different combinations of x objects from a set of n elements, given by the following formula.

\(C_{n,x} = \frac{n!}{x!(n-x)!}\)

Desired outcomes:

You and the 3 friends(4 people), from a set of 4. So

\(D = C_{4,4} = \frac{4!}{4!0!} = 1\)

Total outcomes:

20 people from a set of 20. So

\(T = C_{20,4} = \frac{20!}{4!16!} = 4845\)

Probability:

\(p = \frac{D}{T} = \frac{1}{4845}\)

\(\frac{1}{4845}\) probability that you and your 3 friends will be selected.

Answer:

The answer is rational.

Step-by-step explanation:

It won' be irrational.

4.125 and 3 are rational.

Answer: The sum is a non-repeating

Step-by-step explanation:

Answer:

Step-by-step explanation:

.In this case (16)2 / (6)2 or 7.1111The larger pizza has (7.1111)(610) calores

Answer:

To solve this problem, we first need to understand that the number of calories in a pizza doesn't depend on its diameter but on its area. The reason is simple: the more pizza there is, the more calories it contains. And the area of a pizza (or any circle) increases with the square of the radius.

The area of a circle is given by the formula πr^2, where r is the radius.

The 6-inch pizza has a radius of 3 inches, so its area is π(3^2) = 9π square inches.

The 16-inch pizza has a radius of 8 inches, so its area is π(8^2) = 64π square inches.

The 16-inch pizza is 64π/9π = 64/9 ≈ 7.11 times the area of the 6-inch pizza, and therefore should have roughly 7.11 times the calories, assuming the pizzas are made with the same proportions of ingredients.

So, the 16-inch pizza should have approximately 610 calories * 7.11 = 4337.1 calories.

If the 16-inch pizza is cut into 8 slices, each slice would have approximately 4337.1 calories / 8 = 542.14 calories.

Keep in mind this is an estimate as it assumes that the distribution of ingredients (and therefore the distribution of calories) is uniform across the pizza, which might not be the case in reality. But it gives a good first approximation.

Answer:

Step-by-step explanation:

$8,000.00 was loaned at 3% annual interest, and $17,000.00 (25,000 - 8,000) was loaned at 9% annual interest.

Let x be the amount loaned at 3% annual interest and y be the amount loaned at 9% annual interest.

According to the problem, we know that:

x + y = 25,000

0.03x + 0.09y = 1,770.00

We can use these two equations to solve for x and y.

One way to do this is to solve for one of the variables in terms of the other in the first equation, and  substitute that expression into the second equation.

y = 25,000 - x

Substituting this expression for y into the second equation, we get:

0.03x + 0.09(25,000 - x) = 1,770.00

Simplifying and solving for x, we get:

0.03x + 2,250 - 0.09x = 1,770.00

-0.06x = -480.00

x = 8,000.00

Therefore, $8,000.00 was loaned at 3% annual interest, and $17,000.00 (25,000 - 8,000) was loaned at 9% annual interest.

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Answer:

19/99

yes this is the answer

Answer:1700

Step-by-step explanation: you can do 2000-300=1700 tickets they need to sell to reach their goal trust me I love math.

The intersection points are: (0, -3) and (10, 2)

The bounded area is -20.83 unit²

(a) The  intersection points of the line and curve are the points where the line and curve meet. Thus, the intersection points are:

(0, -3) and (10, 2)

(b) The integral terms of y which gives the area bound are:

a = -3, b = 2 (These are the y values of the intersection points)

Since we have x = y² + 3y and x = 2y + 6, we can say:

y² + 3y = 2y + 6

y² + 3y - 2y - 6 = 0

y² + y - 6 = 0

Thus, h(y) =

Using a = -3 and b = 2  with h(y) = y² + y - 6, we have the bounded area as:

\(Area = \int\limits^b_a {y} \, dy\)

\(Area = \int\limits^{2}_{-3} {(y^{2} + y - 6}) \, dy\)

Integrating the area:

Area = [y³/3 + y²/2 - 6y + C]²₋₃

Area = [2³/3 + 2²/2 - 6(2)] - [(-3)³/3 + (-3)²/2 - 6(-3)]

Area = [8/3 + 2 - 12] - [-9 + 4.5 + 18]  

Area = [-22/3] - [27/2]

Area = -125/6

Area = -20.83 unit²

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Answer:

4x² + 24x + 36

Step-by-step explanation:

(2x + 6)² = (2x + 6)(2x + 6) = 4x² + 12x + 12x + 36 = 4x² + 24x + 36

Answer:

2.06

Step-by-step explanation:

The formula for critical value = Margin of Error / Standard Error

Margin of Error = z × Standard deviation/√n

Mean for the month of March = $305.30

Standard deviation = $46.50

n = number of samples = 26 homes

z score for 95% confidence interval = 1.96

= 1.96 × $46.50/√26

= 17.874024556

Standard error = standard deviation/√n

= $46.50/√26

= 9.1194002839

Critical value = Margin of Error/Standard Error

= 17.874024556/9.1194002839

= 2.06

The expression in the options which is equivalent to the given expression is D. (22x + 48) / (x² - 36).

Given expression is,

[15 / (x - 6)] + [7 / (x + 6)]

Cross multiplying the two fractional expressions,

= [15 (x + 6) + 7 (x - 6)] / [(x - 6) (x + 6)]

= [15x + 90 + 7x - 42] / [x² - 6²]

= (22x + 48) / (x² - 36)

Hence the equivalent expression is D.

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Answer:

Step-by-step explanation:

(x₁, y₁)= (-6,1)  and (x₂,y₂) = (0,4)

Slope = \(\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\)

          \(= \dfrac{4-1}{0-[-6]}\\\\=\dfrac{3}{0+6}\\\\=\dfrac{3}{6}\\\\=\dfrac{1}{2}\)

Slope of line perpendicular to it = -1/m  

                                                     \(= \dfrac{-1}{\dfrac{1}{2}}\\\\=-1*\dfrac{2}{1}=-2\)

Equation : y =mx +b

y = -2x + b

Plugin x = -2 and y =7 in the above equation

7 = -2*(-2) + b

7 = 4 + b

7-4=b

3 = b

Equation: y =-2x + 3

Answer:

Angle DEA

Step-by-step explanation:

It lies in the same line

Step-by-step explanation:

A manufacturer of computer memory chips produces chips in lots of 1000. If nothing has gone wrong in the manufacturing process, at most 7 chips each lot would be defective, but if something does go wrong, there could be far more defective chips. If something goes wrong with a given lot, they discard the entire lot. It would be prohibitively expensive to test every chip in every lot, so they want to make the decision of whether or not to discard a given lot on the basis of the number of defective chips in a simple random sample. They decide they can afford to test 100 chips from each lot. You are hired as their statistician.

There is a tradeoff between the cost of eroneously discarding a good lot, and the cost of warranty claims if a bad lot is sold. The next few problems refer to this scenario.

Problem 8. (Continues previous problem.) A type I error occurs if (Q12)

Problem 9. (Continues previous problem.) A type II error occurs if (Q13)

Problem 10. (Continues previous problem.) Under the null hypothesis, the number of defective chips in a simple random sample of size 100 has a (Q14) distribution, with parameters (Q15)

Problem 11. (Continues previous problem.) To have a chance of at most 2% of discarding a lot given that the lot is good, the test should reject if the number of defectives in the sample of size 100 is greater than or equal to (Q16)

Problem 12. (Continues previous problem.) In that case, the chance of rejecting the lot if it really has 50 defective chips is (Q17)

Problem 13. (Continues previous problem.) In the long run, the fraction of lots with 7 defectives that will get discarded erroneously by this test is (Q18)

Problem 14. (Continues previous problem.) The smallest number of defectives in the lot for which this test has at least a 98% chance of correctly detecting that the lot was bad is (Q19)

(Continues previous problem.) Suppose that whether or not a lot is good is random, that the long-run fraction of lots that are good is 95%, and that whether each lot is good is independent of whether any other lot or lots are good. Assume that the sample drawn from a lot is independent of whether the lot is good or bad. To simplify the problem even more, assume that good lots contain exactly 7 defective chips, and that bad lots contain exactly 50 defective chips.

Problem 15. (Continues previous problem.) The number of lots the manufacturer has to produce to get one good lot that is not rejected by the test has a (Q20) distribution, with parameters (Q21)

Problem 16. (Continues previous problem.) The expected number of lots the manufacturer must make to get one good lot that is not rejected by the test is (Q22)

Problem 17. (Continues previous problem.) With this test and this mix of good and bad lots, among the lots that pass the test, the long-run fraction of lots that are actually bad is (Q23)