HELP PLEASE
A charity needs to report its typical donations received. The following is a list of the donations from one week. A histogram is provided to display the data.


5, 5, 6, 8, 10, 15, 18, 20, 20, 20, 20, 20, 20


A graph titled Donations to Charity in Dollars. The x-axis is labeled 1 to 5, 6 to 10, 11 to 15, and 16 to 20. The y-axis is labeled Frequency. There is a shaded bar up to 2 above 1 to 5, up to 3 above 6 to 10, up to 1 above 11 to 15, and up to 7 above 16 to 20.


Which measure of variability should the charity use to accurately represent the data? Explain your answer.


The range of 13 is the most accurate to use, since the data is skewed.

The IQR of 13 is the most accurate to use, since the data is skewed.

The range of 20 is the most accurate to use to show that they have plenty of money.

The IQR of 20 is the most accurate to use to show that they need more money.

y=10

If you divide 8 by 2 you'll get 4. Now do the opposite of division. multiply5 by 2 you'll get 10

The solution in interval notation b ∈ (-∞ , -7)

-5 times b is no less than 35.

5b  ≥ 35

n order to isolate the variable in this linear inequality, we need to get rid of the coefficient that multiplies it.

-\(\frac{5b}{5} = \frac{-35}{5}\)

This can be accomplished if both sides are divided by .

Notice that the inequality sign has changed.

b ≤ -7

We need to reduce this fraction to the lowest terms.

This can be done by dividing out those factors that appear both in the numerator and in the denominator.

In our example, this is the common factor:5

b ∈ (-∞ , -7)

We have already found the solution to the inequality, but since we want to represent the solution in interval notation, we have changed it.

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The line integral is 32.3110. The process of calculating this has been explained below.

Our line segment has a slope that is given by = m = 6 - 1 / 3 - 1

= m = 5/2

From this, we use a line's point-slope form and write this in the form -

= y−1=5/2(x−1)

= y  = 5/2x−3/2

From this, we get x ∈ [3,1]. Now, we will -

= dy/dx = d/dx(5/2x−3/2) =5/2

From this, we can conclude that the line element is going to be -

= ds = \(\sqrt{\frac{dy}{dx}^{2} + 1dx }\)

= ds = \(\sqrt{\frac{5}{2}^{2} + 1dx }\)

= ds = \(\sqrt{29}\)/2 dx

No, we integrate the given integral -

= \(\int\limits^1_3 {[3x^{2} - 2(\frac{5}{2}x - \frac{3}{2} ) ]\frac{\sqrt{29}}{2} } \, dx\)

By integrating this, we get -

= 32.3110

The complete question that you might be looking for is -

Evaluate the line integral of \int (3x^2-2y)ds over the line segment from (3,6) to (1,1).  Use the equation of the line (y=mx+b) to solve.

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Answer:

f^-1(x) = (x+20) / 12

Step-by-step explanation:

f(x) = 4(3x-5)

Let y be the image of f.

y = 4(3x-5)

y = 12x-20

y+20 = 12x

x = (y+20) / 12

f^-1(y) = (y+20) / 12, so

f^-1(x) = (x+20) / 12

Answer:

b. \( 68 + 17h = 357 \)

f. 17 hours

Step-by-step explanation:

Charges for coming to my house = $68 (this will be the constant of the equation)

Amount charged per hour labor = $17

hours = h

Total amount paid to Mike = 357

The equation that represents this situation can be expressed as:

\( 68 + 17h = 357 \)

Solve for h

\( 68 + 17h - 68 = 357 - 68 \) (subtraction property of equality)

\( 17h = 289 \)

\( \frac{17h}{17} = \frac{289}{17} \) (division property of equality)

\( h = 17 \)

Mike was in my house for 17 hours.

The values of the trigonometric function of the angle are:

sin(2x) = 120/169, cos(2x) = -119/169, and tan(2x) = -120/119

Trigonometry is a branch of mathematics dealing with the relationship between the ratios of the sides of a right-angled triangle with its angles.

tan(x) = 12/5  (tangent = opposite / adjacent)

hypotenuse = √(12²+5²) = √169 = 13 units   (Pythagoras)

In quadrant III, opposite and adjacent are negative:

sin(x) = -12/13 (Sine = opposite / hypotenuse)

cos(x) = -5/13 (cosine = adjacent / hypotenuse)

Now we can use the double angle formulas to find sin(2x), cos(2x), and tan(2x):

sin(2x) = 2sin(x)cos(x) = 2(-12/13)(-5/13) = 120/169

cos(2x) = cos²(x) - sin²(x) = (-5/13)² - (-12/13)² = -119/169

tan(2x) = sin(2x) / cos(2x) = (120/169) / (-119/169) = -120/119

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Therefore, to ensure with probability 0.9 that the class average would be within 5 of 60, the professor would need 118 students to take the final exam.

The Central Limit Theorem states that the distribution of the sum or average of a large number of independent, identically distributed variables will be approximately normal, regardless of the underlying distribution.

Therefore, in this example we can use the Central Limit Theorem to approximate the mean of the test scores of the students taking the final exam. If the professor knows that the mean of the test scores is 60 and the standard deviation is 16, then the professor can calculate the sample size necessary to ensure that the class average is within 5 of 60 with a probability of 0.9.

Using the formula \(n = (zα/2 * σ/ε)2\), where zα/2 is the z-score associated with a confidence level of 0.9, σ is the standard deviation of the population, and ε is the margin of error desired, we can calculate the sample size necessary for this professor.

\(n = (1.645 * 16/5)2 = 118.03\)
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Answer:

The capital of California is Sacramento (I cannot really give a paragraph for you but I can provide information.

- Located in the north-central part of the state

- Found on 9 September 1850

Step-by-step explanation:

The expected value of the number of people selected before and including the first time a woman has a turn is 1.6667 and the standard error is 0.7454.

It should be noted that the expected value will be:

1[p(x = 1)] + 2[p(x = 2)] + 3[p(x = 3)]

= 1(0.5) + 2(0.3333) + 3(0.1667)

= 1.6667

Var(X) = E(X²) - E(X)2

= 3.3335 & (1.6667)²

= 0.555611

The standard error will be:

= ✓0.555611

= 0.7454

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Answer:

Step-by-step explanation:

\(5\frac{1}{6}=\frac{(5*6)+1}{6}=\frac{31}{6}\)

Answer:

31/6 (improper fraction).

Step-by-step explanation:

5 1/6 = (6 × 5) + 1/6 = 31/6

31/6 is the improper fraction.

Answer:

distributive property

Step-by-step explanation:

they distribute the 1 to the 3 and 7 to make it easier

hope this helps

The expression 1 x (3 + 7) = (1 x 3) + (1 x 7)  is an example of the distributive property of the addition.

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

This property states that multiplying the total of two or so more arithmetic operations by a number will provide the same outcome as multiplying each required infrastructure by the number separately and then joining the results together.

The expression is given below.

1 x (3 + 7) = (1 x 3) + (1 x 7)

The expression is an example of the distributive property of the addition.

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Answer:

the slope is 5. 5/1

Step-by-step explanation:

Use rise over run to find slope. It is the easiest way to find slope

You rise 5 and 1 to the right

Answer:

The slope is 5

Step-by-step explanation:

So you're just trying to find the slop. We're going to choose 2 points to use which are already marked on the graph.

(0, 2) and (-1, -3)

So to find the slope, we have to find (the difference in y) / (the difference in x)

So we're going to do

-3-2/-1-0

Which is

-5/-1

So since there are two negatives, it become positive, and it'll simplify into 5.

So the slope of the line is 5

Answer:

18

Step-by-step explanation:

It is 18. Just simply count the dots and sum them all up together, and you get 18. Unless there is a specific thing needed.

The solution to the differential equation dy/dt + 2y = 0 where y(0) = 3 is y = 3e^(-2t).

The solution to the differential equation dy/dt + 2y = 0 can be found by separating the variables and integrating both sides.

First, separate the variables:
dy/dt = -2y

Next, integrate both sides:
∫dy/y = ∫-2dt

This gives us:
ln(y) = -2t + C

Now, solve for y:
y = e^(-2t+C)

Since we know that y(0) = 3, we can plug in 0 for t and 3 for y to solve for C:
3 = e^(C)
C = ln(3)

So the solution is:
y = e^(-2t+ln(3))

Simplifying further gives us:
y = 3e^(-2t)

Therefore, the solution to the differential equation dy/dt + 2y = 0 where y(0) = 3 is y = 3e^(-2t).

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The implied cash price of the vehicle, considering a 5-year lease with $400 monthly payments and a 1.9% monthly interest rate, is approximately $39,919.35, including the residual value.



To find the implied cash price of the vehicle, we need to calculate the present value of the lease payments and the residual value at the end of the lease.First, we need to calculate the present value of the lease payments. The monthly lease payment is $400, and the lease term is 5 years, so there are a total of 5 * 12 = 60 monthly payments. We'll use the formula for the present value of an ordinary annuity:

PV = PMT * (1 - (1 + r)^(-n)) / r,

where PV is the present value, PMT is the monthly payment, r is the monthly interest rate, and n is the number of periods.Using the given values, the monthly interest rate is 1.9% / 100 / 12 = 0.0015833, and the number of periods is 60. Plugging these values into the formula, we find:

PV = 400 * (1 - (1 + 0.0015833)^(-60)) / 0.0015833 ≈ $21,919.35.Next, we need to add the residual value of $18,000 at the end of the lease to the present value of the lease payments:

Implied Cash Price = PV + Residual Value = $21,919.35 + $18,000 = $39,919.35.Therefore, the implied cash price of the vehicle is approximately $39,919.35.

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Answer:

  (d)  ∞

Step-by-step explanation:

The expression can be simplified to one that is not indeterminate:

  \(\dfrac{(1+x)^{24}}{x}-\dfrac{1}{x}=\dfrac{(1+x)^{24}-1}{x}=\dfrac{1+24x+\dots+24x^{23}+x^{24}-1}{x}\\\\=\dfrac{24x+\dots+24x^{23}+x^{24}}{x}\\\\=24+\dots+24x^{22}+x^{23}\)

A polynomial with a positive leading coefficient will tend to infinity as x goes to infinity.

Answer:

where is the image to solve

Step-by-step explanation:

hint: all angles should equal to 180 added up

3)  since we don't have the information about the interest paid (I), we cannot determine the rate of interest at this time.

(1) To find the total amount Adrian paid in 36 months, we can multiply the monthly installment by the number of installments:

Total payment A = Monthly installment * Number of installments

              = $375 * 36

              = $13,500

Therefore, Adrian paid a total of $13,500 over the course of 36 months.

(2) In the simple interest formula I = Prt, the letters used represent the following variables:

I: Interest (the amount of interest paid)

P: Principal (the initial amount, or in this case, the car worth)

r: Rate of interest (expressed as a decimal)

t: Time (in years)

(3) To find the rate of interest in percentage, we need more information. The simple interest formula can be rearranged to solve for the rate of interest:

r = (I / Pt) * 100

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Answer:

1,268,620

Step-by-step explanation:

Multiply 1,852×685

Answer:

1268620 meters

Step-by-step explanation:

685x1852= 1268620

Answer:

The length of the pool is 462 m.

Step-by-step explanation:

The length of the pool is 462 m. We know this is the answer because, if we plug in the known width and known perimeter into the equation for the perimeter of a rectangle, we get:

73 * 462 = 336

Therefore, the length of the pool is 462 m.

Answer:

525

Step-by-step explanation:

Set up a ratio 35/140=?/2100. Solve this to get the answer.

The given geometric series is convergent, and its sum is 100.


1. Identify the common ratio (r): To determine if the given series is convergent or divergent, we first need to find the common ratio between the terms. In this case, we can divide the second term (9) by the first term (10) to get the common ratio, r.

  r = 9/10

2. Check for convergence: A geometric series converges if the absolute value of the common ratio, |r|, is less than 1. In this case:

  |r| = |9/10| = 9/10 < 1

Since |r| < 1, the series is convergent.

3. Find the sum (S): For a convergent geometric series, the sum can be calculated using the formula:

  S = a / (1 - r)

  where a is the first term, and r is the common ratio.

  In our case, a = 10 and r = 9/10. Plugging these values into the formula, we get:

  S = 10 / (1 - 9/10) = 10 / (1/10) = 100

The given geometric series is convergent, and its sum is 100.

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The value of the expression (x + a) (x + b) (x + c) will be x^3 + (b + c + a)x^2 + (ab + ac + bc)x + abc.

The value of the second expression will be x^3 + 22x^2 + 147x + 270

It should be noted that to expand the expression (x + a) (x + b) (x + c), we can use the distributive property of multiplication as follows:

(x + a) (x + b) (x + c)

= x³ + (b + c + a)x² + (ab + ac + bc)x + abc

Similarly, we can expand (x + 9) (x+3)(x + 10) as follows:

(x + 9) (x+3)(x + 10)

= (x + 9) ((x+3) (x + 10))

= x³ + 22x² + 147x + 270

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X is the variable that we have assigned the agriculture column of swiss to. Running this code would give us the interquartile range of x.

a. To calculate the sample median of x, we can use the median function in R. So, the code would be:
median(x)
where x is the variable that we have assigned the agriculture column of swiss to. Running this code would give us the sample median of x.
b. To find the .34 quantile of x, we can use the quantile function in R. The code would be:
quantile(x, 0.34)
where x is the variable that we have assigned the agriculture column of swiss to, and 0.34 represents the desired quantile. Running this code would give us the value of the .34 quantile of x.
c. To calculate the interquartile range of x, we can use the IQR function in R. The code would be:
IQR(x)
where x is the variable that we have assigned the agriculture column of swiss to. Running this code would give us the interquartile range of x.

The "fertility", "Switzerland", and "x <- swiss $ agriculture" terms.
a. To calculate the sample median of x (the agriculture column in the Swiss dataset), use the following R command:
median_x <- median(swiss$agriculture)
b. To find the 34th percentile (0.34 quantile) of x using the R quantile function, use the following R command:
quantile_x <- quantile(swiss$agriculture, probs = 0.34)

c. To calculate the interquartile range of x (the agriculture column in the Swiss dataset) using R, use the following R commands:
Q1 <- quantile(swiss$agriculture, probs = 0.25)
Q3 <- quantile(swiss$agriculture, probs = 0.75)
IQR_x <- Q3 - Q1
This will give you the interquartile range (IQR) of the agriculture column in the Swiss dataset.

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The length of arc QS is approximately 7.85 units. to explain, the length of an arc can be calculated using the formula: L = 2πr(m/360), where r is the radius and m is the measure of the central angle in degrees. In this case, the central angle measure is 78 degrees, and the radius is not given. Without the radius, we cannot determine the exact length of the arc.

To find the length of an arc, we need two pieces of information: the measure of the central angle and the radius of the circle. In this case, we are given the measure of the central angle, which is 78 degrees, but the radius is not provided. Without the radius, we cannot directly calculate the length of the arc. The formula to find the length of an arc is L = 2πr(m/360), where L is the length of the arc, r is the radius, and m is the measure of the central angle. If we had the radius, we could substitute the values into the formula and calculate the exact length of the arc. However, without the radius, we cannot provide an exact value and can only give a general explanation.

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Based on the given information, the operating characteristics of Willow Brook National Bank's drive-up teller window can be determined and the probability of customers having to wait for service can be calculated.

The arrival rate for the drive-up teller window is 0.5 customers per minute, while the service rate is 0.75 customers per minute. Since both arrival and service times follow exponential distributions, we can use the formulas for an M/M/1 queue to calculate the operating characteristics.

(a) The probability of having no customers in the system can be found using the formula P0 = 1 - (λ/μ), where λ is the arrival rate and μ is the service rate. Plugging in the values, P0 = 1 - (0.5/0.75) = 0.3333.

(b) The average number of customers waiting can be calculated using the formula Lq = (\(\lambda ^2\)) / (μ(μ - λ)). Plugging in the values,

Lq = (\(0.5^2\)) / (0.75(0.75 - 0.5)) = 0.6667.

(c) The average number of customers in the system is given by L = λ / (μ - λ). Plugging in the values, L = 0.5 / (0.75 - 0.5) = 1.

(d) The average waiting time for a customer can be calculated using the formula Wq = Lq / λ. Plugging in the values, Wq = 0.6667 / 0.5 = 1.3333 minutes.

(e) The average time a customer spends in the system is given by W = Wq + (1 / μ). Plugging in the values, W = 1.3333 + (1 / 0.75) = 2.6667 minutes.

(f) The probability that arriving customers will have to wait for service can be calculated using the formula Pw = λ / μ. Plugging in the values, Pw = 0.5 / 0.75 = 0.6667.

These calculations provide the operating characteristics of the drive-up teller window at Willow Brook National Bank.

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Answer: 90 cups

Step-by-step explanation:

This is about ratios. Whatever you do to one part, you have to do to the others. 4x10=40, and 2x10=20. 30+40+20=90