Help on this pls. !!!!!

Answer:

Hold the balloon (negatively charged) just above your head so your hair (positively charged) will be attracted to it and stand up on end. ... The can will start to roll towards the balloon without touching it. The negatively charged balloon repels the electrons of the can so that a positive charge is near the balloon.

Explanation:

I gave my explanation along with the answer.

Answer:

d.  There are not enough nonverbal messages to say for sure.

The following most likely describes this person’s situation is  there are not enough nonverbal messages to say for sure.

Nonverbal messages include facial expressions, gestures, loudness or tone of voice, body language, personal space, eye gaze, touch or appearance. These are all the actions taken by the movement of our body parts.

A woman wearing athletic clothing outside. The woman is stretching her legs in a lunge position. Based on the nonverbal messages one sees in the given photograph, the following most likely describes this person’s situation is  there are not enough nonverbal messages to say for sure.

Thus, the correct option is d.

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According to René Descartes, machines could not think because they lacked consciousness or a mind. Descartes proposed a dualistic philosophy, which distinguished between the physical body and the immaterial mind or soul. He believed that the mind, or "res cogitans," was responsible for conscious thought, reasoning, and intellect, while the body, or "res extensa," operated mechanically and lacked consciousness.

Descartes argued that thinking and consciousness were unique attributes of human beings and could not be replicated by machines or animals. He claimed that machines, no matter how complex or advanced, were fundamentally different from human beings because they lacked a conscious mind.

Descartes' view became influential in the philosophy of mind and has been subject to debate and criticism over the years. However, his ideas about the distinction between mind and body and the limitations of machines in thinking were significant contributions to the philosophical understanding of cognition and consciousness.

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The wavelength of the frequency of 25.9 Hz at 33.3°C is 13.57 meters.

To find the corresponding wavelength for a frequency of 25.9 Hz at an air temperature of 33.3°C, we'll first need to find the speed of sound in air at the given temperature, then use the speed of sound to calculate the wavelength.

1: Calculating the speed of sound in air at 33.3°C.
The speed of sound in the air can be calculated using the following formula:
v = 331.4 + 0.6 * T, where v is the speed of sound and T is the temperature in Celsius.

v = 331.4 + 0.6 * 33.3
v ≈ 331.4 + 19.98
v ≈ 351.38 m/s

2: Calculate the wavelength using the frequency and speed of sound.
The relationship between frequency, wavelength, and speed of sound is given by the formula:
v = f * λ, where v is the speed of sound, f is the frequency, and λ is the wavelength.
Rearranging the formula to find the wavelength:
λ = v / f

Substituting the given frequency and calculated speed of sound:
λ = 351.38 m/s / 25.9 Hz
λ ≈ 13.57 m

So, the corresponding wavelength for a frequency of 25.9 Hz at an air temperature of 33.3°C is 13.57 meters.

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here we have to find energy

E

so use formula .

you will get it

Answer:

45 N

Explanation:

From the question given above, the following data were obtained:

Force applied by Brett = 25 N

Force applied by Chris = 20 N

Net force =?

From the question given above, Brett and Chris applied force to the piano in the same direction. Thus the net force acting on the piano will be the sum of the forces applied by Brett and Chris. This can be obtained as follow:

Force applied by Brett = 25 N

Force applied by Chris = 20 N

Net force =?

Net force = 25 + 20

Net force = 45 N

The final velocity of the ball when it is caught is 20.58 m/s

Velocity is the rate of change of displacement.

To calculate the final velocity of the ball when it is caught, we use the formula below.

Formula:

Where:

From the question,

Given:

SUbstitute these values into equation 1

Hence, the  final velocity of the ball when it is caught is 20.58 m/s

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The direction as an angle CCW from the positive x-axis.

θ =55 degrees

Generally,

\($$\begin{aligned}& v=\frac{200}{\sqrt{x^2+y^2}} \\& (x, y)=(2,1,3) \mathrm{m}\end{aligned}$$we know that \\\\ $E=-\left(-\frac{d v}{d x} i+\frac{d v}{d y}\right)$\\\\ $E=-\frac{d v}{d x}$ $\frac{d v}{d x}=-200 /\left(x^2+y^2\right)^{3 / 2}$ \\\\\ $\frac{d v}{d x}=-\frac{-200(2.1 \hat{i}+3 j)}{\left(2.1^2+3^2\right)^{3 / 2}}$\)

\(\begin{aligned}&\begin{gathered}\frac{d v}{d x}=4.0727(2.1 \hat{1}+3 \hat{j}) \\\frac{d v}{d x} \text { at }(2.1,3)=4.0727\left(2.1^2+3^2\right)^{1 / 2} \\E E=14.91 \mathrm{v} / \mathrm{m}\end{gathered}\\&\text { Angle, } \begin{aligned}Tan \theta & =\frac{E_y}{E_x} \\\theta & ={Tan}^{-1}\left(\frac{3}{2.1}\right) \\\theta & =55^{\circ}\end{aligned}\end{aligned}\)

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Answer:

0.4 g/cm^3

Explanation:

The density of an object can be found using the following formula.

d= m/v

where m is the mass and v is the volume.

The mass of the metal is 6 grams and the volume is 15 centimeters^3

m=6 g

v= 15 cm^3

Substitute these into the formula.

d= 6 g/ 15 cm^3

Divide 6 g by 15 cm^3 (6/15=0.4)

d= 0.4 g/ cm^3

The density of the metal is 0.4 grams per cubic centimeter.

Density = (mass) / (volume)

Density = (6 g) / (15 cm³)

Density = (6/15) (g/cm³)

Density = 0.4 g/cm³

This 'metal' has less than half the density of water, and it floats on water !  It cannot be of Earthly origin, and must have been dropped here by aliens.

Either that, or else the metal has been hammered and stretched and beaten out and shaped so that it has an artificially large volume ... something like the way sailing ships are made out of thick plates of steel.

Answer:

A) 12.57 m

B) 5 RPM

C) 3.142 m/s

Explanation:

A) Distance covered in 1 Revolution:

The formula that gives the relationship between the arc length or distance covered during circular motion to the angle subtended or the revolutions, is given as follows:

s = rθ

where,

s = distance covered = ?

r = radius of circle = 2 m

θ = Angle = 2π radians  (For 1 complete Revolution)

Therefore,

s = (2 m)(2π radians)

s = 12.57 m

B) Angular Speed:

The formula for angular speed is given as:

ω = θ/t

where,

ω = angular speed = ?

θ = angular distance covered = 15 revolutions

t = time taken = 3 min

Therefore,

ω = 15 rev/3 min

ω = 5 RPM

C) Linear Speed:

The formula that gives the the linear speed of an object moving in a circular path is given as:

v = rω

where,

v = linear speed = ?

r = radius = 2 m

ω = Angular Speed in rad/s = (15 rev/min)(2π rad/1 rev)(1 min/60 s) = 1.571 rad/s

Therefore,

v = (2 m)(1.571 rad/s)

v = 3.142 m/s

Answer:

I found  

33 ∘ C

Explanation:

i hope this helps :)

The star is moving away from Earth at a velocity of 1.8 x 106 m/s.

The Doppler Effect describes the shift in wavelength of a wave when the source is moving in relation to the observer. The shift can be observed in sound waves, light waves, and other waves.

The Doppler Effect can be used to determine the velocity of objects moving away from an observer, as in the case of stars moving away from Earth.

The velocity of a star moving away from Earth can be determined using the equation:

v = Δλ/λ x c, Where v is the velocity of the star, Δλ is the shift in wavelength of the spectral line, λ is the wavelength of the spectral line measured in the lab on Earth, and c is the speed of light (3.00 x 108 m/s).

In this case, the shift in wavelength of the spectral line is Δλ = 500.3 nm - 500 nm = 0.3 nm.

The wavelength of the spectral line measured in the lab on Earth is λ = 500 nm.

Plugging in these values to the equation above: v = Δλ/λ x cv = (0.3 nm / 500 nm) x (3.00 x 108 m/s) = 1.8 x 106 m/s.

Therefore, velocity of star 1.8 x 106 m/s.

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The speed of the 1.2 kg block after the spring is released is 3 m/s to the left.

According to the question, a 1.2 kg block and a 1.8 kg block are initially at rest on a frictionless, horizontal surface. When a compressed spring between the blocks is released, the 1.8 kg block moves to the right at 2.0 m/s as shown. We need to determine the speed of the 1.2 kg block after the spring is released.The system's initial momentum is zero since the blocks are at rest. The system's final momentum is made up of the 1.2 kg and 1.8 kg blocks' respective momenta. As a result, the conservation of momentum equation becomes:m1i * v1i + m2i * v2i = m1f * v1f + m2f * v2fWhere m1i * v1i is the 1.2 kg block's initial momentum, m2i * v2i is the 1.8 kg block's initial momentum, m1f * v1f is the 1.2 kg block's final momentum, and m2f * v2f is the 1.8 kg block's final momentum.

As the 1.8 kg block moves to the right at 2.0 m/s after the spring is released, its momentum is:m2i * v2i = 1.8 kg * 0 m/s = 0 kg * m/sm2f * v2f = 1.8 kg * 2 m/s = 3.6 kg * m/sTo calculate the final momentum of the 1.2 kg block, we must first determine its final velocity. We can rearrange the conservation of momentum equation above to solve for v1f:m1f * v1f = m1i * v1i + m2i * v2i - m2f * v2fv1f = (m1i * v1i + m2i * v2i - m2f * v2f) / m1fPlugging in the values:v1f = (1.2 kg * 0 m/s + 1.8 kg * 0 m/s - 1.8 kg * 2 m/s) / 1.2 kgv1f = -3 m/s. Therefore, the speed of the 1.2 kg block after the spring is released is 3 m/s to the left.

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A single electron has a charge of 2.8×10−15 z . using zeets and a fictitious unit of mass called the wiggle, w , the charge-to-mass ratio of an electron is 9.7×106 z/w .The mass of an electron in wiggles is approximately 2.88×10^(-22) w.

To find the mass of an electron in wiggles, we can use the charge-to-mass ratio given in zeets and wiggles.

The charge-to-mass ratio of an electron is given as 9.7×10^6 z/w. We know that the charge of an electron is 2.8×10^(-15) z.

Let's assume the mass of an electron in wiggles is represented as m_w. We can set up the following equation:

(2.8×10^(-15) z) / m_w = 9.7×10^6 z/w

To solve for m_w, we can rearrange the equation:

m_w = (2.8×10^(-15) z) / (9.7×10^6 z/w)

Simplifying the expression:

m_w ≈ 2.88×10^(-22) w

Therefore, the mass of an electron in wiggles is approximately 2.88×10^(-22) w.

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Answer:

velocity = 29.4 m/s

Explanation:

We have been told to calculate the velocity of a ball after 3 seconds of freefall. To do this, we can use the following formula:

\(\boxed{v = u + at}\),

where:

• v = final velocity

• u = initial velocity

• a = acceleration

• t = time of freefall

In this case, u = 0 m/s, because the ball is initially stationary before it is released. Also, a = 9.81 m/s² because the ball is falling while inside the Earth, where the acceleration of freefall is 9.81 m/s².

Using the above information along with the formula, we can calculate the velocity of the ball after 3 seconds of freefall:

v = 0 m/s + (9.81 m/s² × 3 s)

  = 29.4 m/s

Explanation:

Find an energy is E=mgh, so E=18*10*10=1800J

To rank the magnitudes of the accelerations, we need to consider the weight of each ball and the direction of its velocity.

The acceleration due to gravity, g, is the same for all five balls since they have the same size and shape. Therefore, the weight of each ball is proportional to its mass:

- Ball C (m50g vy=-20m/s) and Ball D (m100g vy=-20m/s) have the same weight (100 N) and are moving downward, so they have the largest magnitude of acceleration due to gravity (a = g = 9.8 m/s^2) in the downward direction.
- Ball E (m50g vy=20m/s) is moving upward and has the smallest weight (50 N), so it has the smallest magnitude of acceleration due to gravity (a = -g = -9.8 m/s^2) in the upward direction.
- Ball A (m50g vy=0) and Ball B (m100g vy=0) are at rest, so their acceleration due to gravity is zero.

Air resistance is not negligible, so it will affect the motion of the balls. However, we cannot determine the magnitude of the air resistance without more information about the speed and shape of the balls.

Therefore, the ranking of the magnitudes of the accelerations a is:

D > C > E > A = B

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Using part 1 of the fundamental theorem of calculus, we can find the derivative of g(x) as follows: g′(x) = (d/dx)∫[1,x] x7t3 dt = 7x6(x3)1 = 7x9.

The first part of the fundamental theorem of calculus is used for finding the derivative of a function. If a function is defined as the integral of another function, then the derivative of the function is the integrand. Mathematically, it is expressed as: g′(x) = (d/dx) ∫[a, x] f(t) dt

Here, g(x) = x7t3 1 dt  can be written as: g(x) = ∫[1,x] t3 dt

Since the upper limit of integration contains x, we use the chain rule for differentiation: g′(x) = (d/dx) x7t3 1 dt= (d/dx) ∫[1,x] t3 dt= x3(d/dx) [x7]= 7x6(x3)1= 7x9

Therefore, the derivative of g(x) is 7x9.

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Answer:

Well if they playing a game like that

Explanation:

Optics is a branch of physics that is the study of light and vision. ... The branch of physics dealing with the nature and properties of electromagnetic energy in the light spectrum and the phenomena of vision. In the broadest sense, optics deals with infrared light, visible light, and ultraviolet light.

ANYTHING that's dropped near the Earth's surface and isn't affected by air resistance falls 9.8 m/s faster at any time than it did 1 second earlier.

0.5 second after it was dropped with zero speed, it's falling at

(0.5) x (9.8 m/s)  =  4.9 m/s .

It makes no difference which building it was dropped from.

In the given scenario, we are asked to identify the regions where the electric field on the dashed line vanishes at a finite distance from the charges. The electric field is caused by the presence of charges and can be found by using Coulomb's law. The direction of the electric field is given by the direction of the force experienced by a test charge placed at that point.

Based on the given information, we can assume that there are at least two point charges placed in the vicinity of the dashed line. It is also given that the electric field vanishes at infinity and at two different points a finite distance from the charges. This implies that the electric field is non-zero in some regions and zero in others.

To identify the regions where the electric field is zero, we need to analyze the geometry of the configuration. From the figure, we can see that the two point charges are placed symmetrically with respect to the dashed line. This implies that the electric field on the dashed line will be zero at the midpoint between the charges. Therefore, we can say that the region between points A and B is where the electric field is zero.

Similarly, we can analyze the other regions to identify where the electric field is zero. Since the electric field vanishes at two different points, we can assume that the other region where the electric field is zero lies to the left of point A or to the right of point C. However, without additional information, we cannot determine the exact location of this region.

In conclusion, based on the given information, we can say that the electric field on the dashed line vanishes at a finite distance from the charges between points A and B. The location of the other region where the electric field is zero cannot be determined without additional information.

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Answer: I'm pretty sure that you just have to make sure that all of the elements have the same charge on both sides.

Explanation: Example: 2CO2+ 4CO2----- C6O10

Answer:

The answer Is B.

Explanation:

The cats acceleration is decreased

by air resistance.

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Answer:

0 Newtons

Explanation:

The velocity of the object does not change, it is a constant 54 km/hr. When velocity does not change, acceleration is zero. Using the formula Force = mass x acceleration, we find:

mass = 1200 kg

acceleration = 0

F  = (1200)(0) = 0

There would be two force vectors shown on a free-body diagram if the crane lifts the beam using a single cable that are tension in the single cable and weight of the beam.

The net force on the beam will be resulting to zero when the steel beam is moving at constant speed without any acceleration acting on it. The two force vectors such as : tension and weight act opposite to each other. Tension is the force the crane is exerting on the beam in order to lift it, while the weight is exerted by the gravitational force of earth on the steel beam acting downwards to the tension of cable. Hence, these two force vectors would be shown in the free body diagram.

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Answer: \(0.708\ mA\)

Explanation:

Given

\(E_o=20\ V/m\)

\(\omega =10^7\ s^{-1}\)

Cross-sectional area \(A=0.40\ m^2\)

Current density is given by

\(J=\epsilon_o \dfrac{dE}{dt}\)

Displacement current

\(\Rightarrow I=JA\\\Rightarrow I=8.854\times 10^{-12}\times 20\times 10^7\times 0.4\\\Rightarrow I=0.708\times 10^{-3}\ A\)

The required value of the maximum displacement current of the given space is  \(7.08 \times 10^{-4} \;\rm A\).

Given data:

The intensity of electric field is, \(E_{0}=20 \;\rm V/m\).

The angular frequency of electric field is, \(\omega=1.0 \times 10^{7} \;\rm s^{-1}\).

The cross-sectional area of space is, \(A =0.40 \;\rm m^{2}\).

In the given problem, the instantaneous electric field is given by \(E = E_{0} \times cos(\omega t)\)

So, the expression for the current density is,

\(J= \epsilon_{0} \times \dfrac{dE}{dt}\)

Here, \(\epsilon_{0}\)  is the permittivity of free space. Solving as,

\(J= \epsilon_{0} \times \dfrac{d(E_{0} \times cos(\omega t))}{dt}\\\\J= -\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)\)

And the expression for the maximum displacement current is,

\(I = J \times A\)

And the maximum displacement current is possible only when, J is positive and J will be positive for  \(sin(\omega t)=-1\).

Then solving as,

\(I = (-\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)) \times A\\\\I = (-8.85 \times 10^{-12} \times 20 \times (1.0 \times 10^{7}) \times (-1)) \times 0.40\\\\I = 7.08 \times 10^{-4} \;\rm A\)

Thus, we can conclude that the required value of the maximum displacement current of the given space is  \(7.08 \times 10^{-4} \;\rm A\).

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The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)

The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.

To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).

The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).

In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).

Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.

If co > co_critical, the system is considered overdamped (Option E).

If co = co_critical, the system is considered critically damped (Option D).

If co < co_critical, the system is considered underdamped (Option C).

Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.

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The gas that will condense at the lowest pressure is Ethane.

The given gases;

At constant temperature, condensation will occur at the lowest pressure for the gas with the strongest intermolecular force or interactions.

Thus, the gas that will condense at the lowest pressure is Ethane.

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