His final velocity at the end of the 2.6 seconds will be 25.48 m/s
given
time = 2.6 seconds
initial velocity = u = 0
acceleration = acceleration due to gravity = 9.8 \(m/s^{2}\) (since , it is a free fall )
final velocity = ?
using kinematics equation
v = u + at
v = u - g*t
v = - 9.8 * 2.6 = - 25.48 m/s
His final velocity at the end of the 2.6 seconds will be 25.48 m/s in downward direction
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Explain newton 2nd law ???
Explanation:
Newton's second law simply says that the net force on an object is equal to the object's mass times its acceleration.
∑F = ma
For example, think of a game of tug-of-war, in which two teams pull on a rope in opposite directions.
If the forces are equal (balanced), then the net force is 0 N, so Newton's second law tells us that the rope's acceleration is 0 m/s².
If the forces are not equal (unbalanced), then the net force is not 0 N, and the rope will accelerate in the direction of the net force.
A highway curves to the left with radius of curvature of 44 m and is banked at 16 ◦ so that cars can take this curve at higher speeds. Consider a car of mass 1563 kg whose tires have a static friction coefficient 0.72 against the pavement. How fast can the car take this curve without skidding to the outside of the curve?
The car can take this curve without skidding to the outside of the curve with a speed of 23.47 m/s.
Given that,
Radius of the track r = 44 m
Inclination θ = 16°
Mass of car m = 1563 kg
Coefficient of kinetic friction μ = 0.72
By analysing the free body diagram, we get,
N cos θ - fr - m g = 0 ----(1)
where, N is normal reaction
fr is friction
N cos θ + fr cos θ = mv²/r ----(2)
fr = μ N ----(3)
From (1), (2) and (3) we get maximum velocity without skidding as,
v = √(g r ) × √( tanθ +μ )/(1 - μ tanθ) = √(9.8× 44 ) ×√( tan 16°+ 0.72)/(1 - 0.72 tan 16°) = 20.77 × √1.007/0.79 = 20.77 × 1.13 = 23.47 m/s
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20 kg rodsis on the edge of a 80 m high de What is the rodes gracional potencial energy?
Answer:
Gpe = 15680 Joules
Explanation:
Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.
Mathematically, gravitational potential energy is given by the formula;
G.P.E = mgh
Where;
G.P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
Given the following data;
Mass = 20 kg
Height = 80 m
We know that acceleration due to gravity is equal to 9.8 m/s²
To find the gravitational potential energy;
Gpe = mgh
Gpe = 20 * 80 * 9.8
Gpe = 15680 Joules
Which statement compares the attractive forces that hold particles together?
A. Covalent bonding and Van der Waals forces join separate
molecules together, while ionic and hydrogen bonding produce
compounds.
B. Covalent and hydrogen bonding produce compounds, while ionic
bonding and Van der Waals forces join separate molecules
together.
C. lonic and covalent bonding produce compounds, while hydrogen
bonding and Van der Waals forces join separate molecules
together.
D. Ionic and covalent bonding join separate molecules together, while
hydrogen bonding and Van der Waals forces produce compounds.
Answer:
Ionic and covalent bonding produce compounds, while hydrogen bonding and Van der Waals forces join separate molecules together.
Ur welcome:)
Answer:
C) lonic and covalent bonding produce compounds, while hydrogen bonding and Van der Waals forces join separate molecules together.
Explanation:
Explain how light and
heavy elements are
created within stars?
Great question! Your answer is below.
They were created prior to the formation of our solar system, thus...
Huge, gigantic stars had to have existed, perished, and burst, releasing the materials they produced into the universe. These materials subsequently gathered via gravity to form our solar system and perhaps dozens or hundreds of others.
Our Sun is currently fusing hydrogen into helium; when hydrogen runs out, the Sun will compress a little, and the added pressure on the core will cause the helium to start fusing into carbon for a short while; then, the sun will die, and that will be that. Stars fuse lighter materials into heavier ones.
But with large stars, the outer layer may be made of hydrogen, which will be fusing into helium underneath it along a boundary. The helium layer will fuse into the carbon layer, the carbon layer will fuse into the calcium layer, and so on, up to the iron layer.
When iron production in a star's core starts, the star is doomed. The creation of elements *heavier* than Iron *takes* energy* Iron is the heaviest element ever formed that will release energy. Therefore, the star will eventually stop fusing, and its powerful gravitational pull will lead it to collapse. The abrupt in-falling mass generates the energy required for fusing the heavier metals, such as lead, gold, and uranium, after which the star's mass rebounds, resulting in the explosion known as a supernova. Before the formation of our solar system, all of this took place.'
Thanks!
- Eddie
In the picture below, two light beams are traveling through water. If the frequency of one light beam is greater than the other, what can be said about their wavelengths?
Select one:
a. The light beam with the higher frequency has the longer wavelength.
b. The light beam with the higher frequency has the shorter wavelength.
c. Wavelength does not depend on frequency therefore the wavelengths could be equal.
d. Not enough information is given to tell.
. heat engine takes in 6.0 kj from heat and produces waste heat of 4.8 kj. what is its efficiency?
The efficiency of the heat engine can be calculated by using the formula. Efficiency = (Useful work output / Heat input) x 100%. And The efficiency of the heat engine is 20%.
Here, the useful work output is the difference between the heat input and the waste heat produced:
Useful work output = Heat input - Waste heat produced
= 6.0 kj - 4.8 kj
= 1.2 kj
Therefore, the efficiency of the heat engine can be calculated as:
Efficiency = (1.2 kj / 6.0 kj) x 100%
= 20%
So, the efficiency of the heat engine is 20%.
I'd be happy to help you with your question about a heat engine. To determine the efficiency of a heat engine that takes in 6.0 kJ of heat and produces waste heat of 4.8 kJ, follow these steps:
Step 1: Calculate the work done by the engine.
Work = Total Heat Input - Waste Heat
Work = 6.0 kJ - 4.8 kJ
Work = 1.2 kJ
Step 2: Calculate the efficiency of the heat engine.
Efficiency = (Work Done / Total Heat Input) × 100%
Efficiency = (1.2 kJ / 6.0 kJ) × 100%
Efficiency = 0.2 × 100%
Efficiency = 20%
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xa steel ball (65 g) located at 100 cm above the ground is shot in the horizontal direction. it travels 350 cm in the horizontal direction before it hits the ground. calculate the momentum of the steel ball in the horizontal direction
The momentum of the steel ball in the horizontal direction is 10425.1066 g.cm/s
Consider vertical component of motion:
\(Sy = U_{y} t + 1/2 (at^{2} )\)
Therefore,
\(1.03 = 0 + 1/2 (9.81* t^{2} )\)
t = 0.4582 s
Consider horizontal component:
\(V_{x} = x * t\)
= 3.5 * 0.4582
\(V_{x}\) = 1.603 m/s
Momentum,
P = mv
= 65 * 1.603 * \(10^{2}\)
P = 10425.1066 g.cm/s
momentum, which is the result of a particle's mass and velocity. It has both magnitude and direction since momentum is a vector variable. According to Isaac Newton's second rule of motion, the force pushing a particle has an equal and opposite effect on the temporal rate at which its momentum changes.
According to Newton's second law, if a particle is subjected to a constant force for a specific amount of time, the impulse, which is the product of the force and the time interval, is equal to the change in momentum.
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determine the weights of 1 kg, 1 slug, and 1 lbm on mars (the gravitational acceleration on mars is 38% of that on earth).
The weight of 1 kg on Mars would be 0.38 N, 1 slug would be 3.72 N, and 1 lbm would be 0.17 N.
The weight of an object is determined by its mass and the force of gravity acting upon it. On Earth, the acceleration due to gravity is 9.8 m/s^2. However, on Mars, the acceleration due to gravity is 38% of that on Earth, or 3.71 m/s^2.
To calculate the weight of an object, we multiply its mass by the acceleration due to gravity. So, the calculation would be:
For 1 kg on Mars:
1 kg * 3.71 m/s^2 = 3.71 N
For 1 slug on Mars:
1 slug * 3.71 m/s^2 = 14.59 N
For 1 lbm on Mars:
1 lbm * 3.71 m/s^2 = 0.82 N
Therefore, the weight of 1 kg on Mars is 3.71 N, 1 slug is 14.59 N, and 1 lbm is 0.82 N.
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Using the model above, which letter represents the position of the earth when the northern hemisphere is experiencing the shortest hours of daylight
A
B
C
D
Answer:
At position "B" the northern hemisphere is tilted the most from the earth-sun direction and will experience the shortest hours of daylight, (and also the most indirect sun rays).
TRUE OR FALSE : is rate of crystallization higher when solution is more saturated
The given statement that “rate of crystallization is higher when a solution is more saturated" is true.However, we must first understand the meaning of "crystallization" and "saturation" before answering the question.The process by which a solid forms from a liquid or gas phase is known as crystallization.
A solution is saturated if it contains the maximum quantity of solute that may dissolve in the solvent at a particular temperature and pressure. A solution can be classified as unsaturated if it contains less than the saturation level, and supersaturated if it contains more than the saturation level. What is the relationship between crystallization and saturation.
When a solution reaches its saturation point, the solute is no longer soluble in the solvent. As a result, any extra solute added to the solution will form crystals. Furthermore, when a solution is highly saturated, the crystals will form at a faster rate than when it is not as concentrated. As a result, the statement "rate of crystallization is higher when a solution is more saturated" is true.
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An electric field exerts force of 2.60 N on a 3.40 x 10-8 C charge. What is the magnitude of the electric field?Group of answer choices7.65 x 107 N/C8.43 x 107 N/C9.05 x 107 N/C12.0 x 107 N/C
ANSWER
\(7.65\cdot10^7N\/C\)EXPLANATION
We want to find the magnitude of the electric field.
To do this, we have to apply the formula for electric field:
\(E=\frac{F}{q}\)where F = force exerted on the charged particle
q = electric charge on the particle
Hence, the magnitude of the electric field is:
\(\begin{gathered} E=\frac{2.60}{3.40\cdot10^{-8}} \\ E=7.65\cdot10^7N\/C \end{gathered}\)The correct answer is the first option.
you walk 12 meters north, then 10 meters west. What is your displacement
Answer:
Your displacement is 15.62m NW
Explanation:
We can use the Phytagorean theorem to determine the displacement:
a^2+b^2=c^2
12^2+10^2=c^2
144+100=c^2
244=c^2
15.62=c
So your displacement is 15.62m NW
Name two elements that we need to build and maintain bones in our body
The distance from one crest to the next is the ________.
Answer:
Wavelength.
Explanation:
1 period, or wavelength, is measured from one crest to another or from one trough to another.
7. True or False : All the energy in the universe that exists right now is all there
ever will be
how much force is required to lift a 49-newton object with an acceleration of 9.8 m/s2?
480.0 Newtons force is required to lift a 49-newton object with an acceleration of 9.8 m/s2/. The explaination is mentioned below:
To calculate the amount of force required to lift a 49-newton object with an acceleration of 9.8 m/s2, we need to use the formula F = ma, where F is the force required, m is the mass of the object (in this case, 49 newtons), and a is the acceleration (in this case, 9.8 m/s2).
Plugging in the values, we get:
F = 49 x 9.8
F = 480.2 Newtons
Therefore, the amount of force required to lift a 49-newton object with an acceleration of 9.8 m/s2 is 480.2 Newtons.
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a 7.0-g bullet is fired into a 1.5-kg ballistic pendulum. the bullet emerges from the block with a speed of 200 m/s, and the block rises to a maximum height of 12 cm. find the initial speed of the bullet. (please do not include units in your answer)
The initial speed of the bullet is 200 m/s.
What is Conservation of momentum?Conservation of momentum is a law of physics which states that the total momentum of a system remains constant over time. This means that when two or more objects interact, the total momentum of the system remains the same before and after the interaction. The law of conservation of momentum is applicable to both isolated systems and systems that interact with external forces. It is an important concept in a variety of applications ranging from collisions of particles to the motion of galaxies. Conservation of momentum also plays an important role in the field of quantum mechanics.
The initial speed of the bullet can be calculated using the conservation of momentum equation:
m₁v₁ + m₂v₂ = m₁v′₁ + m₂v′₂
where m₁ is the mass of the bullet, v₁ is the initial speed of the bullet, m₂ is the mass of the pendulum, v₂ is the initial speed of the pendulum, v′₁ is the final speed of the bullet, and v′₂ is the final speed of the pendulum.
In this problem, m₁ = 7.0 g, v₁ = ?, m₂ = 1.5 kg, v₂ = 0 m/s, v′₁ = 200 m/s, and v′₁ = 0 m/s.
Substituting this into the equation, we get:
7.0 g x v₁ + (1.5 kg)(0 m/s) = 7.0 g(200 m/s) + (1.5 kg)(0 m/s)
Solving for v₁, we get:
v₁ = 200 m/s
Therefore, the initial speed of the bullet is 200 m/s.
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which constellation is in contrast with ursa major
Answer: Ursa Major (/ˈɜːrsə ˈmeɪdʒər/; also known as the Great Bear) is a constellation in the northern sky, whose associated mythology likely dates back into prehistory. Its Latin name means "greater (or larger) she-bear," referring to and contrasting it with nearby Ursa Minor, the lesser bear.
Bordering constellations: Draco; Cameloparda...
Brightest star: ε UMa (Alioth) (1.76m)
Meteor showers: Alpha Ursa Majorids; Leonid...
Symbolism: the Great Bear
When you are swimming in a pool or lake at night, the water may feel pleasantly warm, even when the air is quite cool. Why?
When you are swimming in a pool or lake at night, the water may feel pleasantly warm, even when the air is quite cool because warm water is less dense than cold water, so the surface water loses heat to the air less rapidly than it would if the water were cold.
Why does the water feel warm at night?
The water may feel pleasantly warm when you are swimming in a pool or lake at night, even when the air is quite cool. This is because warm water is less dense than cold water, so the surface water loses heat to the air less rapidly than it would if the water were cold. This causes the water to retain its warmth longer and feel warmer than the air.
When the air temperature cools down, the colder water is denser, so it rises to the surface while the warmer water moves down, and since the warmer water is closer to the body, the body feels warmer. Furthermore, if the water temperature is higher than the air temperature, it is more likely to feel warmer to a swimmer even in cold temperatures.
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The harmfulness of a germ is called?
The calculated value of static friction
A) increases as force increases
B) is the amount of friction present for an object at rest
C) causes a net acceleration
D) is the maximum value possible
Particle q1 has a charge of 2. 7 μC and a velocity of 773 m/s. If it experiences a magnetic force of 5. 75 × 10–3 N, what is the strength of the magnetic field? T In the same magnetic field, particle q2 has a charge of 42. 0 μC and a velocity of 1. 21 × 103 m/s. What is the magnitude of the magnetic force exerted on particle 2? N.
To determine the strength of the magnetic field, we can use the equation for magnetic force and rearrange it to solve for the magnetic field strength.
The equation for the magnetic force on a charged particle moving in a magnetic field is given by the formula F = qvB, where F is the magnetic force, q is the charge of the particle, v is the velocity of the particle, and B is the magnetic field strength.
In the first scenario, particle q1 has a charge of 2.7 μC (2.7 × 10^-6 C) and a velocity of 773 m/s. It experiences a magnetic force of 5.75 × 10^-3 N. We can rearrange the formula to solve for the magnetic field strength:
F = qvB
B = F / (qv)
Substituting the known values:
B = (5.75 × 10^-3 N) / (2.7 × 10^-6 C)(773 m/s)
B ≈ 8.46 T (Tesla)
Therefore, the strength of the magnetic field in the first scenario is approximately 8.46 T.
In the second scenario, particle q2 has a charge of 42.0 μC (42 × 10^-6 C) and a velocity of 1.21 × 10^3 m/s. We can use the same formula to find the magnitude of the magnetic force exerted on particle q2:
F = qvB
Substituting the known values:
F = (42.0 × 10^-6 C)(1.21 × 10^3 m/s)(8.46 T)
F ≈ 0.43 N
Therefore, the magnitude of the magnetic force exerted on particle q2 is approximately 0.43 N.
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9. An object moving at a constant velocity accelerates at a constant rate of 20 m/s for a distance of
100 m. At the end of the acceleration the object has a velocity of 80 m/s. What was its velocity
before accelerating?
Answer:
I believe the answer is roughly 49m/s
Explanation:
List all given variables:
Accel=20m/s^2
Dist=100m
Final velocity=80m/s
Initial velocity=?
Using the equation i=sqrt(f^2-2a*d) where i =initial velocity, f=final velocity, a=acceleration, and d=distance, we can plug in the known values and solve for initial velocity
i=sqrt(80^2-2*20*100)
i=sqrt(6400-4000)
i=sqrt(2400)
i=48.99, rounded up to 49m/s as the initial velocity
This is my speculation about this answer would appreciate if anyone can confirm this.
An object with a kinetic energy of 1125J has a
mass of 250kg. What is its velocity?
Answer:
3 m/s
Explanation:
Kinetic energy of a body is given by the formula \(K= {1\over2} m v^2\). Let's replace everything we have and solve for what's left.
\(1125J = {1\over2}\cdot 250 kg \cdot v^2\)
\(v^2 ={ 1125 \cdot 2 \over 250}}\) or \(v= 3 {m \over s}\)
An object has a weight of 350N on Earth. What is its mass?
Answer:
Below
Explanation:
F = m a
F/a = m
350 N / 9.81 m/s^2 = 35.7 kg
if An object has a weight of 350N on Earth Then the mass of the object is approximately 35.67 kg.
The weight of an object is the force exerted on it due to gravity. The weight is given by the formula:
Weight = mass × acceleration due to gravity
On Earth, the acceleration due to gravity is approximately 9.81 m/s^2. Therefore, we can calculate the mass of the object by rearranging the formula:
mass = weight/acceleration due to gravity
Substituting the given weight of 350N, we get:
mass = 350 N / 9.81 m/s²
mass ≈ 35.67 kg
Therefore, the mass of the object is 35.67 kg.
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The work function for magnesium is
3.70 eV. What is its cutoff frequency?
Hint: 1 eV 1.60 x 10-19 J
[ ? ] × 10⁰ ² ) Hz
]
The cut off frequency of the magnesium atom is obtained as 8.9 * x 10^18 Hz.
What is the cut off frequency?The cut off frequency is the lowest frequency of the incident ray at which photoelectric effect occurs.
Given that;
1 eV gives 1.60 x 10-19 J
3.70 eV gives 3.70 eV * 1.60 x 10-19 J/1 eV
= 5.92x 10^-19 J
Now;
Wo = hfo
fo = Wo/h
fo = 5.92x 10^-19 J/6.6 * 10^-34
fo = 8.9 * x 10^18 Hz
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according to the laws of thermal radiation, hotter objects emit photons with
a) Higher frequency and longer wavelength
b) Higher frequency and shorter wavelength
c) Lower frequency and longer wavelength
d) Lower frequency and shorter wavelength
b) Higher frequency and shorter wavelength
According to the laws of thermal radiation, hotter objects emit photons with higher frequency and shorter wavelength. This relationship is described by Planck's law and the Stefan-Boltzmann law. As the temperature of an object increases, the average energy of its emitted photons also increases, resulting in higher frequencies and shorter wavelengths. This phenomenon is commonly observed in everyday life, where hotter objects like a glowing red-hot piece of metal or a flame emit light that appears bluish-white, indicating a higher frequency and shorter wavelength compared to cooler objects that emit light in the red or orange spectrum.
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The 5.0-m-long rope in (Figure 1) hangs vertically from a tree right at the edge of a ravine. A woman wants to use the rope to swing to the other side of the ravine. She runs as fast as she can, grabs the rope, and swings out over the ravine.
When she's directly over the far edge of the ravine, how much higher is she than when she started?
Given your answer to Part A, how fast must she be running when she grabs the rope in order to swing all the way across the ravine?
She is 1.0 m higher than she is when she started. The speed at which the woman must be running when she grabs the rope is 4.427 m/s
Suppose we consider the Figure 1 to be a right-angle triangle;
where;
the hypotenuse is the rope = (5.0 m),the opposite side is the ravine = (3.0 cm) and;the adjacent is the slant imaginary distance = (x)∴
Using Pythagoras rule;
(hyp)² = opp² + adj²
5.0² = 3.0² + x²
x² = 25 - 9
x² = 16
x = √16
x = 4 m.
When she is directly over the far edge of the ravine, the height at which she is far higher than where she started is:
= 5cm - 4cm
= 1 cm
The speed at which the woman must be running when she grabs the rope can be determined by taking both the potential energy and kinetic energy of the system, which can be computed as:
mgh = 1/2 mv²Making the speed the subject of the formula, we have:
\(\mathbf{v = \sqrt{2gh}}\)
\(\mathbf{v = \sqrt{2\times 9.8 \times 1.0}}\)
v = 4.427 m/s
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witch two conditions would result in the weakness electric force between objects
Answer: the greater the electric force. distance between the charges.
Explanation:
The greater the charge, the greater the electric force. The second factor is the distance between the charges.