Answer:
25
Step-by-step explanation:
\(\sqrt{15^{2} +20^{2} }=\sqrt{625} \\ =25\)
State whether you agree with the following statement. Explain your reasoning.
A temperature of -11 degrees Fahrenheit is warmer than a temperature of -15 degrees Fahrenheit.
Answer:
I disagree with the statement that a temperature of -11 degrees Fahrenheit is warmer than a temperature of -15 degrees Fahrenheit.
Temperatures are usually compared in terms of their absolute values. In the case of Fahrenheit, the absolute value of a temperature can be obtained by adding 459.67 to the Fahrenheit temperature. Using this conversion, we can see that:
•A temperature of -11 degrees Fahrenheit is equal to 471.47 degrees absolute.
•A temperature of -15 degrees Fahrenheit is equal to 456.67 degrees absolute.
Since 471.47 is greater than 456.67, we can conclude that a temperature of -11 degrees Fahrenheit is colder than a temperature of -15 degrees Fahrenheit in terms of their absolute values. Therefore, a temperature of -15 degrees Fahrenheit is actually warmer than a temperature of -11 degrees Fahrenheit.
Find the volume of the solid that lies within both the cylinder x^2+y^2=1 and the sphere x^2+Y^2+z^2=4
the volume of the solid within both the cylinder and sphere is (8/3)π.
The given cylinder and sphere intersect at a circle on the xy-plane with radius 1. To find the volume of the solid within both shapes, we can use cylindrical coordinates.
First, we set up the limits of integration: z goes from -sqrt(4-x^2-y^2) to sqrt(4-x^2-y^2), r goes from 0 to 1, and theta goes from 0 to 2pi.
The volume integral can then be set up as:
∫(from 0 to 2pi) ∫(from 0 to 1) ∫(from -sqrt(4-x^2-y^2) to sqrt(4-x^2-y^2)) dz r dr dθ
Simplifying this integral, we get:
V = 2π ∫(from 0 to 1) (4-x^2-y^2)^(1/2) r dr
Solving this integral, we get:
V = (8/3)π.
Therefore, the volume of the solid within both the cylinder and sphere is (8/3)π.
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what is the probability that the largest among these random samples is greater than the population median?
The probability that the largest of n random samples is greater than the population median M is bounded above by\(1 - F(M)^(n-1) \times F(X(n))\).
Assumptions about the population and the sampling method.
Let's assume that the population has a continuous probability distribution with a well-defined median, and that we are taking independent random samples from this population.
Let \(X1, X2, ..., Xn\) be the random samples that we take from the population, where n is the sample size.
Let M be the population median.
The probability that the largest of these random samples, denoted by X(n), is greater than M.
Cumulative distribution function (CDF) of the population distribution to calculate this probability.
The CDF gives the probability that a random variable takes on a value less than or equal to a given number.
Let F(x) be the CDF of the population distribution.
Then, the probability that X(n) is greater than M is:
\(P(X(n) > M) = 1 - P(X(n) < = M)\)
Since we are assuming that the samples are independent, the joint probability of the samples is the product of their individual probabilities:
\(P(X1 < = x1, X2 < = x2, ..., Xn < = xn) = P(X1 < = x1) \times P(X2 < = x2) \times ... \times P(Xn < = xn)\)
For any x <= M, we have:
\(P(Xi < = x) < = P(Xi < = M) for i = 1, 2, ..., n\)
Therefore,
\(P(X1 < = x, X2 < = x, ..., Xn < = x) < = P(X1 < = M, X2 < = M, ..., Xn < = M) = F(M)^n\)
Using the complement rule and the fact that the samples are identically distributed, we get:
\(P(X(n) > M) = 1 - P(X(n) < = M)\)
= \(1 - P(X1 < = M, X2 < = M, ..., X(n) < = M)\)
=\(1 - [P(X1 < = M) \times P(X2 < = M) \times ... \times P(X(n-1) < = M) \times P(X(n) < = M)]\)
\(< = 1 - F(M)^(n-1) \times F(X(n))\)
Probability depends on the sample size n and the distribution of the population.
If the population is symmetric around its median, the probability is 0.5 for any sample size.
As the sample size increases, the probability generally increases, but the rate of increase depends on the population distribution.
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PLEASE HELP!! Don’t answer just for points
Hannah is having a birthday party, and each guest gets a bag of party favors. Each goody bag contains one of 2 different toy cars and one of 6 different toy trucks. How many different combinations of party favors can there be in a goody bag?
Answer:
12
Step-by-step explanation:
for everyone 1 toy car there is 6 trucks so 2x6 is 12
What is the formula for the circumference of a circle? c = pi r squared c = 2 pi r c = 2 pi r squared c = pi r cubed
The formula for the circumference of a circle is "c = 2 pi r", where "c" represents the circumference, "pi" represents the mathematical constant pi (approximately equal to 3.14159), and "r" represents the radius of the circle.
This formula relates the distance around a circle to its size, and is useful for calculating various measurements related to circles, such as arc length and sector area. It is important to note that the formula for the circumference of a circle assumes the circle is a perfect, unbroken curve, and thus may not be accurate for circles that are not perfectly round.
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If X =85, standard deviation = 8 and n = 64 construct a 95% confidence interval estimate for the population mean.
95% confident that the true population mean μ lies between 83.04 and 86.96
Confidence Interval
A confidence interval in statistics refers to the probability that a population parameter will fall between a set of values for a certain proportion of times. Analysts often use confidence intervals than contain either 95% or 99% of expected observations.
First need to determine whether dealing with means or proportions in this problem. The sample and population mean, that are dealing with means.
One sample mean, this mean creating a confidence interval for one sample (1 Sample t Interval)
Normally we would check for conditions, but since this is not formulated as a real-world scenario type problem, it is hard to check for randomness and independence. Therefore excluding conditions from this answer.
The formula for constructing a confidence interval for means is as follows:
x ± t ( σ / \(\sqrt{n}\) )
The variables are:
x = 85
σ = 8
n = 64
Plug these values into the formula for the confidence interval
85 ± t ( 8 / \(\sqrt{64}\))
Finding the Critical Value (t)
In order to find t, use this formula:
\(\frac{1 - C}{2} = A\)
The z-score associated with A will give us t
So plug in the confidence interval 95% (.95) into the formula
\(\frac{1 - 0.95}{2} = 0.25\)
Use the calculator or a t-table to find the z-score associated with this area under the curve
t = 1.96
Constructing Confidence Interval
Finish the confidence interval created
= 85 ± 1.96 ( 8 / \(\sqrt{64}\) )
The confidence interval using this formula, to be
(83.04, 86.96)
Interpreting the Confidence Interval
95% confident that the true population mean μ lies between 83.04 and 86.96
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Which point would be a solution to the system of linear inequalities shown below?
y>-4x+6 Y>1/3x -7
(9,-7)
(-12,-2)
(12, 1)
(-12,-7)
The point (9, -7) is the only solution to the system of linear inequalities given.
To determine which point would be a solution to the system of linear inequalities, let's substitute the given points into the inequalities and see which point satisfies both inequalities.
The system of linear inequalities is:
y > -4x + 6
y > (1/3)x - 7
Let's test each given point:
For the point (9, -7):
Substituting the values into the inequalities:
-7 > -4(9) + 6
-7 > -36 + 6
-7 > -30 (True)
-7 > (1/3)(9) - 7
-7 > 3 - 7
-7 > -4 (True)
Since both inequalities are true for the point (9, -7), it is a solution to the system of linear inequalities.
For the point (-12, -2):
Substituting the values into the inequalities:
-2 > -4(-12) + 6
-2 > 48 + 6
-2 > 54 (False)
-2 > (1/3)(-12) - 7
-2 > -4 - 7
-2 > -11 (False)
Since both inequalities are false for the point (-12, -2), it is not a solution to the system of linear inequalities.
For the point (12, 1):
Substituting the values into the inequalities:
1 > -4(12) + 6
1 > -48 + 6
1 > -42 (True)
1 > (1/3)(12) - 7
1 > 4 - 7
1 > -3 (True)
Since both inequalities are true for the point (12, 1), it is a solution to the system of linear inequalities.
For the point (-12, -7):
Substituting the values into the inequalities:
-7 > -4(-12) + 6
-7 > 48 + 6
-7 > 54 (False)
-7 > (1/3)(-12) - 7
-7 > -4 - 7
-7 > -11 (True)
Since one inequality is true and the other is false for the point (-12, -7), it is not a solution to the system of linear inequalities.
In conclusion, the point (9, -7) is the only solution to the system of linear inequalities given.
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Kaitlin paid $16.60 for 33.2 centimeters of wire.
Find the unit price in dollars per centimeter.
If necessary, round your answer to the nearest cent.
Answer:
Step-by-step explanation:
$0.50 per centimeters i think
find the missing side lengths. leave your answers as radicals in simplest form
Using trigonometric relations we can see that:
y = 20
x = 40
How to find the missing side lengths?Here we can see a right triangle and we want to find the missing side lengths, to do so we need to use trigonometric relations.
Remember that:
tan(a) = (opposite cathetus)/(adjacent cathetus)
Replacing what we know we will get:
tan(60°) = 20√3/y
Solving for x:
y = 20√3/(tan(60°)
y = 20
And for the hypotenuse we can use:
sin(a) = (opposite cathetus)/hypotenuse
sin(60°) = 20√3/x
Solving for y:
x = 20√3/sin(60°)
x = 2*20 = 40
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solve for w: x=7w-8z-4
Answer:
W=x/7+ 8z/7 + 4/7
Step-by-step explanation:
Can someone plz help me with this one problem plzzzzz!!!!
Answer:
(answer below)
Step-by-step explanation:
3 - 2
4 - 3
5 - 4
6 - 5
What is the medical term for infection of the gallbladder?
Answer:Cholecystitis
Step-by-step explanation:
Anna and Colin together have $60. Anna has $9 more than twice Colin's amount. How much money does each have?
Answer:
Anna has $43 while Colin has $17.
Explanation:
• Let the amount Anna has = a
,• Let the amount Colin has = c
Together, they have $60.
\(\implies a+c=60\)Anna has $9 more than twice Colin's amount.
\(\begin{gathered} \text{Twice Colin's amount=2c} \\ \$9\text{ more=2c+9} \\ \implies a=2c+9 \end{gathered}\)Substitute a=2c+9 into the first equation:
\(\begin{gathered} a+c=60 \\ (2c+9)+c=60 \\ 2c+c+9=60 \\ 3c=60-9 \\ 3c=51 \\ c=\frac{51}{3} \\ c=17 \end{gathered}\)Next, find the value of a:
\(\begin{gathered} a=2c+9=2(17)+9=34+9 \\ a=43 \end{gathered}\)Therefore, Anna has $43 while Colin has $17.
Adriel has a deck that measures 14 feet by 3 feet. He wants to increase each dimension by equal lengths so that its area is tripled. By how much should he increase each dimension?.
The value of each side has to be increased by 4 to get the area three times.
What is an expression?The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.
Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.
Given that Adriel has a deck that measures 14 feet by 3 feet. He wants to increase each dimension by equal lengths so that its area is tripled.
Let the sides be increased by x. The value of the number will be calculated as,
( x + 4 ) ( x + 3 ) = 126
x² + 17 x -84 = 0
x² - 4x + 21x - 84 = 0
x(x-4) +21(x - 4 ) = 0
(x - 4 ) ( x + 21 ) = 0
x = 4 and x = -21 ignore the negative
Therefore, the value of each side has to be increased by 4 to get the area three times.
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find the global maximum and minimum, if they exist, for the function f(x)=3ln(x)−x for all x>0.
We can then compare those values to determine the global maximum and minimum.
Find the derivative of f(x) using the chain rule: f'(x) = (3/x) - 1For a critical point, f'(x) = 0: (3/x) - 1 = 0 ⇒ 3 = x.
So x = 3 is the only critical point in the domain x>0. We can check that this is a local maximum point by looking at the sign of the derivative on either side of x = 3:When x < 3, f'(x) is negative.
When x > 3,
f'(x) is positive.
So f(x) has a local maximum at x = 3.
To find the values of f(x) at the endpoints of the domain, we can evaluate the function at x = 0 and x = ∞:f(0) is undefined.
f(∞) = -∞.
Therefore, f(x) has no global maximum but it has a global minimum, which occurs at x = e. To show this, we can compare the values of f(x) at the critical point and the endpoint:
e ≈ 2.71828, which is the base of the natural logarithm.
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he found 12 minutes of commercials are between 8 p.m. and 9 p.m. promotions were showing for what fraction of the hour
find the scale factors for the dilation of the small quadrilateral to the large
a. 2
b. 5
c. 4
d.3
Suppose a company wants to introduce a new machine that will produce a marginal annual savings in dollars given by S '(x)= 175 - x^2, where x is the number of years of operation of the machine, while producing marginal annual costs in dollars of C'(x) = x^2 +11x. a. To maximize its net savings, for how many years should the company use this new machine? b. What are the net savings during the first year of use of the machine? c. What are the net savings over the period determined in part a?
a) To maximize its net savings, the company should use the new machine for 7 years. b) The net savings during the first year of use of the machine are $405 (rounded off to the nearest dollar). c) The net savings over the period determined in part a are $1,833.33 (rounded off to the nearest cent).
Step-by-step explanation: a) To determine for how many years should the company use the new machine to maximize its net savings, we need to find the value of x that maximizes the difference between the savings and the costs.To do this, we need to first calculate the net savings, N(x), which is given by:S'(x) - C'(x) = 175 - x² - (x² + 11x) = -2x² - 11x + 175To find the maximum value of N(x), we need to find the critical values, which are the values of x that make N'(x) = 0:N'(x) = -4x - 11 = 0 ⇒ x = -11/4The critical value x = -11/4 is not a valid solution because x represents the number of years of operation of the machine, which cannot be negative. (i.e., not use it at all).However, this answer does not make sense because the company would not introduce a new machine that it does not intend to use. Therefore, we need to examine the concavity of N(x) to see if there is a local maximum in the feasible interval.
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what is the ordered pair for -x-4y=-10
To make orange fizz, Noah mixes 4 scoops of powder with 6 cups of water. Andre mixes 5 scoops of powder with 8 cups of water. Use this information to answer the following 3 questions. What is another example that shows a different amount of powder and water that would taste the same as Andre's mixture?
Answer:
do u still need help on this question
what is equivalent to
Answer : The expression which is equivalent to \(\sqrt[4]{9}^{\frac{1}{2}x}\) is \(9^{(\frac{1}{8}x)}\).
Step-by-step explanation :
The given expression is:
\(\sqrt[4]{9}^{\frac{1}{2}x}\)
As we know that:
\(\sqrt[4]{x} =x^{\frac{1}{4}}\)
So, by solving the above expression, we get:
\(\Rightarrow 9^{(\frac{1}{4}\times \frac{1}{2}x)}\)
By multiplying the power of 9, we get the following expression.
\(\Rightarrow 9^{(\frac{1}{8}x)}\)
Hence, the expression which is equivalent to \(\sqrt[4]{9}^{\frac{1}{2}x}\) is \(9^{(\frac{1}{8}x)}\).
Work out the volume of the frustrum please
Answer:
3744:\p=11756.16 m^2
Step-by-step explanation:
\( {12}^{2} \pi(18 + 9) - {4}^{2} \pi \times 9 = 3744\pi \: \: {m}^{2} \)
HELP ASAP!!!!!
Write a function g whose graph represents the indicated transformation of the graph of f.
f(x)=4x+1; translation 2 units left.
HELP PLEASE
Answer:
The translation of 2 units left in function f (x) = 4x + 1 is 4x + 3.
Here,
Function is given as, f(x)=4x+1
And, translation 2 units left.
We have to find the function after translation.
Now,
Function is given as, f(x)=4x+1
After translation 2 units left the function is;
f (x) = 4x + 1 + 2
f (x ) = 4x + 3
Hence, the function after translation 2 units is f (x) = 4x + 3
Choose the option that best describes the limiting values of T and a under the conditions given. Choose the option that best describes the limiting values of and under the conditions given.
A T=0 and a=0
B T=[infinity] and a=0
C T=mg and a=0
D T=[infinity] and a=g
E T=0 and a=[infinity]
F T=[infinity] and a=[infinity]
Option C best describes the limiting values of T and a under the conditions given. In this case, T represents tension and a represents acceleration.
Without the specific conditions mentioned, it is impossible to determine the exact limiting values of T and a. However, certain options can be ruled out based on common sense and physical laws. For example, option C (T=mg and a=0) is not possible as the tension in a string cannot be equal to the weight of an object. Option E (T=0 and a=[infinity]) is also not possible as a mass cannot have zero tension and infinite acceleration.
Based on these eliminations, the most reasonable options are A (T=0 and a=0) and D (T=[infinity] and a=g). In the former case, the object is not moving and there is no tension in the string. In the latter case, the object is in free fall and the tension in the string is negligible compared to the weight of the object.
However, it is important to note that the exact limiting values of T and a will depend on the specific conditions of the scenario, such as the mass of the object and the angle of the string.
Option C best describes the limiting values of T and a under the conditions given. In this case, T represents tension and a represents acceleration. When T=mg and a=0, it means that the tension in the system is equal to the gravitational force acting on the mass (mg) and the system is in equilibrium with no acceleration. This is a common scenario when an object is hanging from a rope or cable and not moving. The other options do not represent stable or realistic conditions for a physical system.
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The linear mapping x > Ux preserves lengths and orthogonality. Which of the following equalities is/are true about this statement? I. (UX){Uy)=x.y
II. (Ux).(Uy)=x.y
III. (Ux).(Uy)=0x.y=0
(a) I only
(b) II and III only
(c) I and II only
(d) I and III only
The correct answer is (c) I and II only.
Given that the linear mapping U preserves lengths and orthogonality, we can determine the correct equalities.
I. (Ux) · (Uy) = x · y
This equality is true because preserving orthogonality means that the dot product of Ux and Uy is equal to the dot product of x and y.
II. (Ux) · (Uy) = x · y
This equality is also true because preserving lengths means that the dot product of Ux and Uy is equal to the dot product of x and y.
III. (Ux) · (Uy) = 0 · x · y = 0
This equality is not necessarily true. It states that the dot product of Ux and Uy is always zero, which is not necessarily the case. The preservation of lengths and orthogonality does not guarantee that the dot product will always be zero.
Therefore, the correct answer is (c) I and II only.
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Solve for x. Your answer must be simplified. x-24>_9
Answer:
x>33
Step-by-step explanation:
x-24>9
-24 moves to the other side and becomes positive
x>9+24
x>33
Herman prepared 10 kilograms of dough after working 5 hours. How much dough did Herman
prepare if he worked for 8 hours? Assume the relationship is directly proportional.
1) First let's find the ratio or how many kilograms of dough Herman can prepare per hour
10/5 = 2/1 What does this mean? It means that every hour Herman is able to prepare 2 kilograms of dough.2) Now let's create an equation:
y=2xy=kilograms of dough2=kilograms of dough per hourx=hours3) Lets use the equation!
y=2(8)y=16Answer: Herman will prepare 16 kilograms of dough in 8 hours.
Let me know if you have any questions.
Tiana has a cylindrical aquarium for her pet fish. The aquarium has a diameter of 10 inches and a height of 15 inches. Tiana is getting more fish, and wants to buy a larger aquarium. Select the aquariums that have a greater volume than the one Tiana currently has.
1. A cylindrical aquarium with a radius of 6 inches and a height of 15 inches.
2. A spherical aquarium with a diameter of 10 inches.
3.A square prism aquarium with side lengths of 10 nches on it's base and a height of 15 inches.
4.A cylindrical aquarium with a radius of 5 inches and a height of 16 inches.
The cylindrical aquarium with a radius of 6 inches and a height of 15 inches has a greater volume than Tiana's current aquarium
To compare the volumes of the different aquariums, we need to calculate their volumes and compare them to the volume of Tiana's current aquarium.
A cylindrical aquarium with a radius of 6 inches and a height of 15 inches.
The radius of this cylinder is 6 inches and the height is 15 inches. So, the volume of this aquarium is:
V = πr^2h
V = π(6^2)(15)
V ≈ 1696.64 cubic inches
Since this volume is greater than the volume of Tiana's current aquarium, this aquarium has a greater volume than the one Tiana currently has.
A spherical aquarium with a diameter of 10 inches.
The diameter of this sphere is 10 inches, so the radius is 5 inches. The volume of a sphere is given by the formula:
V = (4/3)πr^3
Substituting the value of the radius, we get:
V = (4/3)π(5^3)
V ≈ 523.6 cubic inches
Since this volume is less than the volume of Tiana's current aquarium, this aquarium does not have a greater volume than the one Tiana currently has.
A square prism aquarium with side lengths of 10 inches on its base and a height of 15 inches.
The base of this prism is a square with side length 10 inches, so its area is 10^2 = 100 square inches. The height of the prism is 15 inches. So, the volume of this aquarium is:
V = base area x height
V = 100 x 15
V = 1500 cubic inches
Since this volume is equal to the volume of Tiana's current aquarium, this aquarium does not have a greater volume than the one Tiana currently has.
A cylindrical aquarium with a radius of 5 inches and a height of 16 inches.
The radius of this cylinder is 5 inches and the height is 16 inches. So, the volume of this aquarium is:
V = πr^2h
V = π(5^2)(16)
V ≈ 1256.64 cubic inches
Since this volume is less than the volume of Tiana's current aquarium, this aquarium does not have a greater volume than the one Tiana currently has.
Therefore, the cylindrical aquarium with a radius of 6 inches and a height of 15 inches has a greater volume than Tiana's current aquarium
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use the power series method to determine the general solution to the equation. (1 − x 2 )y ′′ − xy′ 4y = 0.
The values of the coefficients is y = 1 - x^2/3 + x^4/30 - x^6/630 + ... and this is the general solution to the differential equation.
To use the power series method to determine the general solution to the equation (1-x^2)y'' - xy' + 4y = 0, we assume that the solution y can be written as a power series:
y = a0 + a1x + a2x^2 + ...
Then, we differentiate y to obtain:
y' = a1 + 2a2x + 3a3x^2 + ...
And differentiate again to get:
y'' = 2a2 + 6a3x + 12a4x^2 + ...
Substituting these expressions into the original equation and collecting terms with the same powers of x, we get:
[(2)(-1)a0 + 4a2] + [(6)(-1)a1 + 12a3]x + [(12)(-1)a2 + 20a4]x^2 + ... - x[a1 + 4a0 + 16a2 + ...] = 0
Since this equation must hold for all x, we equate the coefficients of each power of x to zero:
(2)(-1)a0 + 4a2 = 0
(6)(-1)a1 + 12a3 - a1 - 4a0 = 0
(12)(-1)a2 + 20a4 + 4a2 - 16a0 = 0
...
Solving these equations recursively, we can obtain the coefficients a0, a1, a2, a3, a4, ... and hence obtain the power series solution y.
In this case, we can simplify the recursive equations by using the fact that a1 = (4a0)/(1!), a2 = (6a1 - 12a3)/(2!), a3 = (6a2 - 20a4)/(3!), and so on. Substituting these expressions into the equation for a0 and simplifying, we get:
a0 = 1
Using this as the starting point, we can compute the other coefficients recursively:
a1 = 0
a2 = -1/3
a3 = 0
a4 = 1/30
a5 = 0
a6 = -1/630
...
Thus, the power series solution to the equation (1-x^2)y'' - xy' + 4y = 0 is:
y = a0 + a1x + a2x^2 + a3x^3 + a4x^4 + a5x^5 + a6x^6 + ...
Substituting the values of the coefficients, we obtain:
y = 1 - x^2/3 + x^4/30 - x^6/630 + ...
This is the general solution to the differential equation.
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What is the negative square root of 25/400?
Answer:
Step-by-step explanation: