Answer:
2. C
3. BCEF
4. C
Step-by-step explanation:
2. In a function, the x value cannot have two y values (for example: if the points are (1,2) and (1,3) then that is not a function).
In this question, none of the x values repeat with multiple y values, so it is a function. the answer is C.
It is not D, because not all straight lines are functions. If the straight line is vertical, then there is only one x value and it has infinitely many values for y. So, not all straight lines are necessarily functions.
3. Range is the y values. The points are (3,4), (-2,3), (7,1), (2, 1/2)
Here, the y values are 4, 3, 1, and 1/2
Choices B,C,E,F are the answers.
4. If the domain is x\(\geq\)0, then 0 is the lowest we can plug into x.
y=2(0)+6
y=6
So, the answer is C. y\(\geq\)6
You were on the right track :)
20 points!!!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!20 points!!!!!!!!!! In an animal shelter, the ratio of dogs to cats is 5 to 3. There are 25 dogs. Write and solve a proportion to find the number c of cats. due in 40 min
help
There are 15 cats in the animal shelter.
What is equation?An equation in which is the highest power of to the variables 1 is knowns as the linear equation. Mathematically: it is an algebraic equations that can be also written in the form of ax + b = 0 or ax + by + c = 0, where a, b and c are definitely real numbers and x and y are variables with the highest power one.
In order to solve this problem, we must set up a proportion. Proportions are an equation that states that two ratios are equal. In this case, we are looking for the number of cats (c) in the animal shelter.
Let's set up the proportion.
5/3 = 25/c
We can then solve for c by multiplying both sides by c.
5c/3 = 25
c = 15
Therefore, there are 15 cats in the animal shelter.
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In KLM, KM is extended through point M to point N,
(3x +19)°, m/LMN = (7x + 5)°, and
m/KLM = (2x+8)°. What is the value of x?
The value of the variable "x" is 11.
We have a triangle. The vertices of the triangle are K, L, and M. The side KM is extended from point M to point N. The measures of the angles MKL, LMN, and KLM are (3x + 19)°, (7x + 5)°, and (2x + 8)°, respectively. We need to find out the value of the variable "x".
The angles LMK and LMN form a linear pair. It means they are supplementary angles. The sum of the angles is 180°.
∠LMK + ∠LMN = 180°
∠LMK + (7x + 5)° = 180°
∠LMK = 180° - (7x + 5)°
In the triangle KLM, we will use the angle sum property of a triangle. The sum of all the angles in a triangle is equal to 180°.
∠K + ∠L + ∠M = 180°
(3x +19)° + (2x + 8)° + [180° - (7x + 5)°] = 180°
3x +19 + 2x + 8 + 180 - 7x - 5 = 180
-2x + 22 = 0
2x = 22
x = 11
Hence, the value of the variable "x" is 11.
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Write an integer that describes a deposit of $145.
Answer:
below
Step-by-step explanation:
Deposit means you are giving money to the bank for them to save for you. Essentially, you are losing $145 you have on you but the bank is gaining that money for you to take out at any time necessary. Keep in mind that interest may be applied to that money monthly so all that money may not always be there.
Best of Luck!
I need help finding the exact perimeter. Special right triangles.
Answer:
The exact perimeter of the square is;
\(56\sqrt[]{2}\)Explanation:
Given the square in the attached image.
The length of the diagonal is;
\(d=28\)Let l represent the length of the sides;
\(\begin{gathered} l^2+l^2=28^2 \\ 2l^2=784 \\ l^2=\frac{784}{2} \\ l^2=392 \\ l=\sqrt[]{392} \\ l=14\sqrt[]{2} \end{gathered}\)The perimeter of a square can be calculated as;
\(\begin{gathered} P=4l \\ P=4(14\sqrt[]{2}) \\ P=56\sqrt[]{2} \end{gathered}\)Therefore, the exact perimeter of the square is;
\(56\sqrt[]{2}\)y-5x 7x + xy x = 0 and y = 4
Answer:
x(7y)x(7y)
Step-by-step explanation:
The given expression: 7(xy)7(xy)
i.e. a product of 7 and xy.
The operation used here: Multiplication.
Commutative property of multiplication :-
a\times b=b\times aa×b=b×a for any numbers a and b.
Associative property of multiplication :-
a\times(b\times c)=(a\times b\times c)a×(b×c)=(a×b×c) for any numbers a , band c.
Now, 7(xy)=(7x)y7(xy)=(7x)y [Associative property of multiplication]
=(x7)y=(x7)y [Commutative property of multiplication]
=x(7y)=x(7y) [Associative property of multiplication]
Consider the line 3x+2y=-1.
Find the equation of the line that is perpendicular to this line and passes through the point (5, 3).
Find the equation of the line that is parallel to this line and passes through the point (5, 3).
Note that the ALEKS graphing calculator may be helpful in checking your answer.
Equation of perpendicular line:
Equation of parallel line:
0
Jeremiah has $10 to spend at the football
game. Pizza costs $3 per slice, and soft drinks
cost $2 each. Suppose p represents the number
of slices of pizza and d represents the number
of drinks. The equation 3p + 2d = 18
represents this situation. If the domain (d) is
{0,3,6}, what is the range (p)?
Answer:
if;
d=0 p=6
d=3 p=4
d=6 p=2
Step-by-step explanation:
just substitute the value into d and use algebra rules to solve!
SSS vs SAS please helpppp
Answer:
SAS is where two sides(S) of a triangle are equal and one angle(A) is equal
SSS is where all three sides(S) of a triangle are equal
I knw don't know how to make
Answer:
Step-by-step explanation:
m∠AXB = this is the question
Answer:
Need a figure or more information to answer this question
WEEK 2 Direction: Answer the following problems. 1. Jun wanted to know how much ice cream he got in on scoop. The radius of a scoop is 2 inches. Find the volum Use 3.14 for pi. (SHOW YOUR SOLUTION) a) What is asked in the problem? b) What are the given facts? c) What is the formula to be used? d) Number Sentence e) Final answer. (show your solution pls)
We are given the radius of the scoop and asked to find the volume of ice cream in one scoop. By using the formula for the volume of a sphere and substituting the given radius, we can calculate the volume. The final answer is approximately 33.49 cubic inches.
a) The problem asks for the volume of ice cream in one scoop.
b) The given fact is that the radius of the scoop is 2 inches.
c) The formula to be used is the volume of a sphere, which is given by V = (4/3)πr³, where V is the volume and r is the radius.
d) Number Sentence:
- Given: Radius (r) = 2 inches
- Formula: V = (4/3)πr³
- Substituting the value: V = (4/3)π(2)³
- Simplifying: V = (4/3)π(8)
- Evaluating: V = (4/3)(3.14)(8)
- Multiplying: V = 33.49333333 (approx.)
e) Final answer: The volume of ice cream in one scoop is approximately 33.49 cubic inches.
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y = (x - 5) (x + 2) , when x=3
Answer:
-10
Step-by-step explanation:
y = (x - 5) (x + 2)
y = (3 - 5) (3 + 2)
y= (-2) (5)
y= -2 x 5
y= -10
Find the Unit Rate, 15 degrees in 2 hours
Complete this sequence of numbers such that the difference between any two adjacent numbers is the same : 3/k, _, _, 9/2k.
The completed sequence is: 3/k, 3/k, 3/k, 9/2k.To complete the sequence of numbers with a constant difference between adjacent numbers, we can calculate the common difference by subtracting the first term from the second term.
Let's denote the missing terms as A and B.
The given sequence is: 3/k, A, B, 9/2k.
The common difference can be found by subtracting 3/k from A or B. Therefore:
A - 3/k = B - A = 9/2k - B.
To simplify, we can equate the two expressions for the common difference:
A - 3/k = 9/2k - B.
Next, we can solve for A and B using this equation.
Adding 3/k to both sides gives:
A = 3/k + 9/2k - B.
Now, we can substitute the value of A into the equation:
3/k + 9/2k - B - 3/k = 9/2k - B.
Simplifying further, we have:
9/2k - 3/k = 9/2k - B.
Cancelling out the common terms, we find:
-3/k = -B.
Multiplying both sides by -1, we get:
3/k = B.
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Please help me out with these questions
Answer:
38 cm-13 cm
4 ft. x 4 ft.
3 in. + 4 in.
Step-by-step explanation:
That is from rounding to the nearest tenth.
PLEASE HELP
Suppose that the functions fand g are defined for all real numbers x as follows.
f(x) = 5x
g(x)=4x-4
Write the expressions for (g.f)(x) and (g-f)(x) and evaluate (g+f)(2).
(g•f)(x) =
(g-f)(x) =
(g+r) (2)=
The store bought a pair of shoes for $50 and sold them for $80. What percentage was the markup?
Answer: They resold them for $30 more than the original price.
Answer: 37.5%
Step-by-step explanation:
$80 - $50 = $30,
$30/$80 = 0.375 > 37.5%
LOOK AT PICTURE, WHOEVER HAS CORRECT ANSWER, I WILL MARK BRAINIEST :)
Answer:
b
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
A woman deposits $300 in a savings account that pays 6% annually. If she withdraws all the money in the account after 120 days, how much does she withdraw (rounded to the nearest dollar)?
The woman will withdraw $300 given 6% interest rate annually.
We can use the formula for simple interest to solve this problem:
I = Prt
where I is the interest earned, P is the principal (initial deposit), r is the annual interest rate as a decimal, and t is the time in years. Since the interest rate is given as an annual rate, we need to convert it to a daily rate by dividing by 365:
r = 0.06/365 = 0.00016438356
The time in years is 120/365 = 0.3287671233 years. Now we can plug in the values and solve for I:
I = 300 * 0.00016438356 * 0.3287671233 = 0.01699999999
The interest earned is $0.017, which is negligible. Therefore, the woman will withdraw the entire principal plus any interest earned, which is:
300 + 0.017 = $300.02
Rounding to the nearest dollar, the woman will withdraw $300.
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10. Prime numbers from 1 to 100 are running a restaurant - PRIME SPOT, near a tourist point. On a winter holiday, 1 and the composite numbers up to 100 enter the restaurant for dinner after their picnic at the same point. The dining hall has tables with seating capacity 15 for each. If they occupy tables without leaving any chair free, how many tables are required? If each prime number attender has to serve equal number of customers, how many customers should each one get to serve?
6 tables are required. Each prime number attender should serve 3 customers each.
The prime numbers between 1 and 100 are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97.
All the numbers other than prime numbers are composite numbers.
The composite numbers from 1 to 100 are: 1, 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24, 25, 26, 27, 28, 30, 32, 33, 34, 35, 36, 38, 39, 40, 42, 44, 45, 46, 48, 49, 50, 51, 52, 54, 55, 56, 57, 58, 60, 62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77, 78, 80, 81, 82, 84, 85, 86, 87, 88, 90, 91, 92, 93, 94, 95, 96, 98, 99, 100.
Now, as there are 25 primes and 75 composites in the group that visited the restaurant, we can calculate the number of tables required by dividing the number of people by the seating capacity of each table.
Each table has a seating capacity of 15, so the number of tables required will be: Number of tables = (Number of customers)/(Seating capacity of each table)Number of customers = 25 (the number of primes) + 75 (the number of composites) = 100Number of tables = 100/15 = 6 tables
Therefore, 6 tables are required.
Now, as each prime number attender has to serve an equal number of customers, we need to calculate how many customers each one should serve.
Each prime attender has to serve 75/25 = 3 customers each, as there are 75 composites and 25 primes.
Thus, each prime number attender should serve 3 customers each.
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The function f(x) is shown on the graph.
What is f(0)?
0 only
-6 only
–2, –1, 1, and 3 only
–6, -2,-1, 1 and 3 only
The function f(x) has five intercepts at -6 only, -2, -1, 1, and 3 only.
The correct answer is D.
The function f(x) has some specific characteristics as shown in the graph.
The graph of f(x) has five intercepts, as can be seen from the graph.
The intercepts of f(x) can be determined by observing where the graph of f(x) crosses the x-axis.
The function f(x) intercepts the x-axis at five different points: -6 only, -2, -1, 1, and 3 only.
At these points, f(x) = 0.
Furthermore, the graph of f(x) is increasing from -∞ to -6, then decreasing from -6 to -2.
The graph of f(x) then increases from -2 to -1, decreases from -1 to 1, increases from 1 to 3, and finally decreases from 3 to +∞.
Hence, we can deduce that the graph of f(x) has a local maximum point at x = -6, a local minimum point at x = -2, and another local minimum point at x = 3.
We can also conclude that f(x) is an odd function, meaning that f(-x) = -f(x).
This can be deduced from the symmetry of the graph about the origin.
Finally, we can see from the graph that the function f(x) is continuous everywhere except at x = -2 and x = 3.
At these points, f(x) is not defined.
The function f(x) has five intercepts at -6 only, -2, -1, 1, and 3 only.
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Question 4:
Nathan has three quarters, two nickels, and eleven pennies. How much money does he have?
Answer:
96Step-by-step explanation:
quarters = 25 cents so 3 quarters is 75
nickels= 5 cents so 10
pennies= 11
11+10+75
Answer:
96¢
Step-by-step explanation:
25+25+25=75
75+5+5=85
85+1+1+1+1+1+1+1+1+1+1+1=96
Therefore Nathan has 96¢
Hope that helps! If you have any further questions comment down below or message me! Good luck!
Step-by-Step Example: Sketch a graph for a situation.
A carnival game booth begins the evening with 40 prizes.
In the first 30 minutes that the booth is open, no one wins
a prize. In the next hour, 8 prizes are won. In the next 45
minutes, 10 prizes are won. During the next 45 minutes,
the booth owner brings in 16 additional prizes. In the next
2 hours, 12 prizes are won. An hour later, 4 prizes are
won, and the carnival closes for the evening.
Sketch a graph that shows the number of prizes the booth
had over the time it was open.
By using the method subtraction, Total prizes are left over are 52- 34= 18
What is subtraction?To subtract in mathematics is to take something away from a group or a number of objects. The group's total number of items decreases or becomes lower when we subtract from it. The components of a subtraction issue are the minuend, subtrahend, and difference. An arithmetic operation called subtraction simulates the process of deleting items from a collection. The action of subtracting a matrix, vector, or other quantity from another according to predetermined rules in order to find the difference.
Given that,
A carnival game booth begins the evening with 40 prizes.
In the first 30 minutes that the booth is open, no one wins
a prize.
In the next hour, 8 prizes are won. In the next 45
minutes, 10 prizes are won.
During the next 45 minutes, the booth owner brings in 16 additional prizes.
In the next 2 hours, 12 prizes are won.
An hour later, 4 prizes are won, and the carnival closes for the evening.
Total prizes are 52 prizes.
Total prizes given are 34 prizes
Total prizes are left over are 52- 34= 18
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Combine these radicals. -3sqrt(of81)+sqrt(of16)
Answer:
-23
Step-by-step explanation:
HELP ME PLZ I NEED AN ANSWER FAST
Evaluate 6 (p-q)divided by(p-1),
when p=13 and q=3
Answer:
5
Step-by-step explanation:
\(\frac{6(p-q)}{p-1}\)
1. Substitue values into equation
2. Simplify
Work:
\(\frac{6(13-3)}{13-1}\)
\(\frac{6(10)}{12}\)
\(\frac{60}{12}\)=5
.3d-1/3 1/3=.84:7/15 I WILL GIVE BRAINLIST TO WHO EVER CAN GET THIS
Answer:
d = 23 1/3
Step-by-step explanation:
You want to solve the proportion (0.3d -1)/(3 1/3) = (0.84)/(7/15).
Solution\(\dfrac{0.3d-1}{3\dfrac{1}{3}}=\dfrac{0.84}{\dfrac{7}{15}}\qquad\text{given}\\\\\\\dfrac{3(0.3d-1)}{10}=\dfrac{15(0.84)}{7}\qquad\text{invert and multiply}\\\\0.09d -0.3=1.8\qquad\text{simplify}\\\\0.09d = 2.1\qquad\text{add 0.1}\\\\d=\dfrac{2.10}{0.09}=\dfrac{70}{3}\qquad\text{divide by 0.09}\\\\\boxed{d=23\dfrac{1}{3}}\)
__
Check
(0.3·(70/3) -1)/(3 1/3) = 0.84/(7/15)
(7 -1)/(10/3) = 1.8
6(3/10) = 1.8 . . . . . . true
Answer: 23 1/3
Step-by-step explanation:
NEED HELP ASAP FREE BRAINLIST
Answer:
G
Step-by-step explanation:
Answer:
The answer is H
Step-by-step explanation:
The mean and standard deviation of the maximum loads supported by 60 cables are 11.09 tons and 0.73 tons, respectively. Find (a) 95%, (b) 99% confidence limits for the mean of the maximum loads ofall cables produced by the compan
Answer:
The 95% confidence interval is \( 10.91 < \mu <11.28 \)
The 99% confidence interval is \( 10.85 < \mu <11.33 \)
Step-by-step explanation:
From the question we are told that
The sample mean is \(\= x = 11.09 \ tons\)
The standard deviation is \(\sigma = 0.73 \ tons\)
The sample size is n =60
From the question we are told the confidence level is 95% , hence the level of significance is
\(\alpha = (100 - 95 ) \%\)
=> \(\alpha = 0.05\)
Generally from the normal distribution table the critical value of \(\frac{\alpha }{2}\) is
\(Z_{\frac{\alpha }{2} } = 1.96\)
Generally the margin of error is mathematically represented as
\(E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }\)
=> \(E = 1.96 * \frac{ 0.73 }{\sqrt{n60 }\)
=> \(E = 0.1847 \)
Generally 95% confidence interval is mathematically represented as
\(\= x -E < \mu < \=x +E\)
=> \( 11.09 - 0.1847 < \mu <11.09 + 0.1847 \)
=> \( 10.91 < \mu <11.28 \)
From the question we are told the confidence level is 99% , hence the level of significance is
\(\alpha = (100 - 99 ) \%\)
=> \(\alpha = 0.01/tex]
Generally from the normal distribution table the critical value of \(\frac{\alpha }{2}\) is
\(Z_{\frac{\alpha }{2} } = 2.58 \)
Generally the margin of error is mathematically represented as
\(E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }\)
=> \(E = 2.58 * \frac{ 0.73 }{\sqrt{n60 }\)
=> \(E = 0.2431 \)
Generally 95% confidence interval is mathematically represented as
\(\= x -E < \mu < \=x +E\)
=> \( 11.09 - 0.2431< \mu <11.09 + 0.2431 \)
=> \( 10.85 < \mu <11.33 \)
The confidence limits for the mean of the maximum loads of all cables produced by the company are: for 95%, it is [10.935,11.245]. For 99%, it is [10.87 ,11.309].
What is the margin of error for large samples?Suppose that we have:
Sample size n > 30Sample standard deviation = sPopulation standard deviation = \(\sigma\)Level of significance = \(\alpha\)Then the margin of error(MOE) is obtained as
Case 1: Population standard deviation is knownMargin of Error = \(MOE = Z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}\)
Case 2: Population standard deviation is unknown\(MOE = Z_{\alpha/2}\dfrac{s}{\sqrt{n}}\)
where \(Z_{\alpha/2}\) is critical value of the test statistic at level of significance
The confidence interval for specific level of significance \(\alpha\) is:
\([\overline{x} - |MOE|, \overline{x} + |MOE|]\)
where \(\overline{x}\) is the sample mean.
For this case, we are given that:
Sample size = n = 60Sample mean = \(\overline{x}\) = 11.09 tonsSample standard deviation = s = 0.73 tonsCalculating the confidence limits of given confidence level:
Case 1: Confidence interval of 95%The level of significance = \(\alpha = 100 - 95\% = 5\% = 0.05\)
The critical value of Z at this level of significance is \(Z_{\alpha/2} = Z_{0.05/2} = \pm 1.645\)
Thus, the confidence interval is:
\([\overline{x} - |MOE|, \overline{x} + |MOE|] = [11.09 - 1.645 \times \dfrac{0.73}{\sqrt{60}}, 11.09 + 1.645 \times \dfrac{0.73}{\sqrt{60}}]\\\\\approx [11.09 - 0.155, 11.09 + 0.155] = [10.935,11.245]\)
Thus, the confidence interval at 95% is [10.935,11.245]
Case 2: Confidence interval of 99%The level of significance = \(\alpha = 100 - 99\% = 1\% = 0.01\)
The critical value of Z at this level of significance is \(Z_{\alpha/2} = Z_{0.05/2} \approx \pm 2.33\)
Thus, the confidence interval is:
\([\overline{x} - |MOE|, \overline{x} + |MOE|] = [11.09 - 2.33 \times \dfrac{0.73}{\sqrt{60}}, 11.09 + 2.33 \times \dfrac{0.73}{\sqrt{60}}]\\\\\approx [11.09 - 0.1847, 11.09 + 0.1847] = [10.87 ,11.31]\)
Thus, the confidence interval at 99% is [10.87 ,11.309]
Thus, the confidence limits for the mean of the maximum loads of all cables produced by the company are: for 95%, it is [10.935,11.245]. For 99%, it is [10.87 ,11.309].
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Find the limit of the difference quotients for f(x) = x2+2x+1 if a= -1
The limit of the difference quotients for f(x) = x^2 + 2x + 1 as x approaches -1 is indeterminate.
To find the limit of the difference quotients for the function f(x) = x^2 + 2x + 1 as x approaches -1, we need to evaluate the following expression:
lim(x→-1) [f(x) - f(-1)] / (x - (-1))
First, let's substitute the values into the expression:
lim(x→-1) \([(x^2 + 2x + 1) - (-1^2 + 2(-1) + 1)] / (x + 1)\)
Simplifying further:
lim(x→-1) \([(x^2 + 2x + 1) - (1 - 2 + 1)] / (x + 1)\)
lim(x→-1)\([x^2 + 2x + 1 - 0] / (x + 1)\)
lim(x→-1) \((x^2 + 2x + 1) / (x + 1)\)
Now, we can directly substitute x = -1 into the expression:
\((-1^2 + 2(-1) + 1) / (-1 + 1)\)
(1 - 2 + 1) / (0)
0 / 0
We have obtained an indeterminate form of 0/0. This indicates that we need to further simplify the expression or use other techniques, such as L'Hôpital's rule, to evaluate the limit. However, without additional information or simplification, we cannot determine the precise value of the limit at x = -1.
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Roger has two golden retrievers, Sadie and Buddy. buddy weighs 14 pounds more than Sadie. If their total weight is 136 pounds, how much does Sadie weigh
Answer:
Sadie weighs 61 pounds.
Step-by-step explanation:
This question can be solved using a system of equations.
I am going to say that:
Sadie's weight is x.
Buddy's weight is y.
Buddy weighs 14 pounds more than Sadie.
This means that \(y = x + 14\)
Their total weight is 136 pounds.
This means that
\(x + y = 136\)
Since \(y = x + 14\)
\(x + x + 14 = 136\)
\(2x = 122\)
\(x = \frac{122}{2}\)
\(x = 61\)
Sadie weighs 61 pounds.