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Answer:

4.46

Explanation:

1.24 ml= 0.00124 L

3600 s=1 hr

0.00124 x 3600=4.46

Matter are anything that is made up of atoms. The quantity of matter can be observed only on the basis of mass and volume calculation. Therefore,  the rate of the water leak in L/hr is 4.46L/hr.

Matter is a substance that has some mass and can occupy some volume. The matter is mainly used in science. Matter can be solid, liquid or gas.

Matter is anything that is made up of atoms. Anything around us that can be physically seen and touched are matter. Ice, water and water vapors are example of matter.

So as we saw that matter has some mass so mass can be measured in gram only. Mass can also be represented as number of molecules. We also saw that matter occupy some volume and that volume is measured only in liter.

1.24 ml= 0.00124 L

3600 s=1 hr

0.00124 x 3600=4.46L/hr

Therefore,  the rate of the water leak in L/hr is 4.46L/hr.

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Answer: Density, Volume, Shape

Answer:

Model

Explanation:

A model of anything is something you make to represent it in it's physical world form

We can conclude as chlorine is the excess reactant and potassium bromide is the solute. Just 31.3 g of KCl, the mass produced from solute, can be made by 50.0 g of chlorine & 50.0 grams of potassium bromide.

The substance which is present when a chemical reaction first begins is known as a reactant. Products refer to the material or substances to a right of the arrow. A substance that's also present following a chemical reaction is known as a product.

In the first, sodium (Na) and chlorine (Cl) are the reactants, and the finished product being sodium chloride, called table salt (NaCl N a C l ).

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Answer:

True

Explanation:

Any substance dissolving a solid (salt) in liquid (water) is a physical change.

Salt in water, is a physical change because only the state of the matter has changed.

Answer:

true

Explanation:

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Answer:

Helium and Neon have similar chemical properties because both of them completely fill the outer shell of their atoms' electrons, so there is nothing to share with other atoms, neither with the same element nor with any other element.

Explanation:  

Helium and Neon are both  noble gases . As elements react, their atoms, by losing, acquiring, or sharing electrons, complete their outer shells. Noble gas atoms already have full outer shells, so there is no tendency for them to lose, gain, or share electrons. There are incomplete outer shells of atoms of group 1 and 7 elements (so they are reactive)

Chemical properties of HELIUM and NEON -:

Hence, helium and neon have similar chemical properties as they are the most stable due to having the maximum number of valence electrons their outer shell can hold.

The structures of the aldol addition and condensation products of pentanal are attached as an Image with this answer.

What is Aldol Addition ?

An aldol addition is a reaction that occurs between the enolate of an aldehyde or ketone and the alpha-carbon of another aldehyde or ketone to form a beta-hydroxy aldehyde or ketone.

The term aldol condensation has to do with a reaction in which a nucleophile attacks the carbonyl group of an aldehyde or a ketone to convert it to the enolate from which attacks another aldehyde or ketone at the carbonyl carbon to form the required product.

The product obtained in the process is shown in the image attached with the answer.

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WHne the helium gas occupies 12.4 L at 23°C and 0.956 atm,  then at 40°C and 0.956 atm the volume of the helium gas is 13.1 L.

We can use the combined gas law to solve this problem, which relates the pressure, volume, and temperature of a gas in a closed system. The well-known expression for the combined gas law is:

(P₁ x V₁) / T₁ = (P₂ x V₂) / T₂

We are given that P₁ = P₂ = 0.956 atm, V₁ = 12.4 L, T₁ = 23°C = 296 K, and T₂ = 40°C = 313 K. Putting  these values into the gas formula, we obtain the following:

(0.956 atm x 12.4 L) / 296 K = (0.956 atm x V₂) / 313 K

Solving for V₂, we get:

V₂ = (0.956 atm x 12.4 L x 313 K) / (296 K x 0.956 atm) = 13.1 L

Therefore, the volume of the helium gas at 40°C and 0.956 atm is 13.1 L.

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The mass of oxygen gas required to occupy a volume of 6 L at a pressure of 20.9 kPa and a temperature of 37°C is 0.155 g, which is closest to option 2 (1.56 g). Option 2 is correct.

To solve this problem, we can use the ideal gas law, which relates the pressure, temperature, volume and the number of moles of a gas:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, as well as T is the temperature. We rearrange this equation to solve for the number of moles of gas:

n = PV/RT

We know the pressure (20.9 kPa), volume (6 L), temperature (37°C = 310 K), and we are looking for the number of moles of oxygen gas. The gas constant R is 8.31 J/(mol·K). Molar mass of oxygen gas (O₂) will be 32 g/mol.

n = PV/RT = (20.9 kPa)(6 L)/(8.31 J/(mol·K) × 310 K)

= 0.00487 mol

To calculate the mass of oxygen gas, we can use the molar mass:

mass = n × molar mass

= 0.00487 mol × 32 g/mol

= 0.155 g

Hence, 2. 1.56 g is the correct option.

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Answer + Explanations

Calculate heat absorption using the formula:

Q = mc∆T

Q means the heat absorbed, m is the mass of the substance absorbing heat, c is the specific heat capacity and ∆T is the change in temperature.

The heat absorbed is calculated by using the specific heat of water and the equation ΔH=cp×m×ΔT. 4. Water is vaporized to steam at 100oC. The heat absorbed is calculated by multiplying the moles of water by the molar heat of vaporization.

You can do this easily: just multiply the heat capacity of the substance you're heating by the mass of the substance and the change in temperature to find the heat absorbed.

To calculate the amount of heat released in a chemical reaction, use the equation Q = mc ΔT, where Q is the heat energy transferred (in joules), m is the mass of the liquid being heated (in kilograms), c is the specific heat capacity of the liquid (joule per kilogram degrees Celsius), and ΔT is the change in ...

Q = mc∆T. Q = heat energy (Joules, J) m = mass of a substance (kg) c = specific heat (units J/kg∙K) ∆ is a symbol meaning "the change in"

Precisely, water has to absorb 4,184 Joules of heat (1 calorie) for the temperature of one kilogram of water to increase 1°C. For comparison sake, it only takes 385 Joules of heat to raise 1 kilogram of copper 1°C.

A reaction that absorbs heat is endothermic. Its enthalpy will be positive, and it will cool down its surroundings. This reaction is exothermic (negative enthalpy, release of heat).

Quantitative experiments show that 4.18 Joules of heat energy are required to raise the temperature of 1g of water by 1°C. Thus, a liter (1000g) of water that increased from 24 to 25°C has absorbed 4.18 J/g°C x 1000g x 1°C or 4180 Joules of energy.

The amount of energy needed to raise the temperature of 10 g of gold from 30°C to 40°C is 12.9 joules.

To calculate the amount of energy needed to raise the temperature of a substance, we can use the following formula;

Q = m × c × \(Δ_{T}\)

Where Q is the amount of energy (in joules), m is the mass of the substance (in grams), c is the specific heat capacity of the substance (in joules per gram per degree Celsius), and \(Δ_{T}\) is change in temperature (in degrees Celsius).

The specific heat capacity of gold is 0.129 joules per gram per degree Celsius.

Using this information, we can calculate the amount of energy needed to raise the temperature of 10 g of gold from 30°C to 40°C;

Q = 10 g × 0.129 J/g°C × (40°C - 30°C)

Q = 10 g × 0.129 J/g°C × 10°C

Q = 12.9 J

Therefore, the amount of energy needed is 12.9 joules.

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Answer:

11.67 lbs

Explanation:

Potential energy : energy obtained due to height or position (the force of gravity)

 PE = mhg

g = acceleration due to gravity  (m/s²)

h = height (m)

m = mass (kg)

1. Known

m = 0.5 kg

h = 1 m

g = 9.8 m/s²

then :

\(\tt PE=0.5\times 1\times 9.8=4.9~J\)

Kinetic energy is the energy gained by an object's motion

KE = 1/2 mv²

2. To find KE, the required data are the mass and velocity

in this table, you do not display the velocity

Answer:

For hydrogen. H

Explanation:

Atomic number is 1

Proton number is 1

Mass number is 2

Neutron number is 1

Answer:

what is the quetion.......

Explanation:

Answer: the answer is 35.6

Explanation:

Look up the answer but take out you must show all your work and resources should pop up I’m on the same question now for chemistry so I’m putting 35.6L

because im in a filed of dandelions wishing on everyone that youll be mine

The concentration of the acetic acid before titration is 0.128M

For weak acid and strong base titration-

Moles of acetic acid =  moles of NaOH

Given concentration of NaOH = 0.1067M

Volume of NaOH = 30.07ml = 0.03007L

Using the formula, Concentration = Moles/Volume

Moles of NaOH = concentration X volume = 0.1067 X 0.03007 = 0.0032

Therefore, moles of acetic acid  = 0.0032mole

Using the formula, Concentration = Moles/Volume

Concentration of acetic acid =  0.0032/0.025 = 0.128M

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In a polar covalent bond, electrons are shared unequally. The correct alternative is option b.



A polar covalent bond is a type of bond in which electrons are shared unequally between two atoms. This unequal sharing of electrons results in a partial negative charge on one side of the bond and a partial positive charge on the other side.

This charge separation creates a dipole, which is a molecule with two poles.

The unequal sharing of electrons is due to the difference in electronegativity between the two atoms. The atom with the higher electronegativity will have a greater attraction for the electrons and will therefore have a partial negative charge, while the atom with the lower electronegativity will have a partial positive charge.

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The mass of the sample of the material is 0.1664 g.

The amount of energy needed to raise the temperature of one gram of a substance by one degree Celsius.

By the formula of specific heat

\(Q = mc \Delta T\)

Given, that the specific heat (c) of material is 0.416 J/gC

The difference in temperatures is 30°C to 50°C

The mass=?

Q = heat, 50 J

Putting the values in the equation

\(\rm 50\;J = m \times 0.416 J/g^\circ C \times (50 - 30)\\\\m = \dfrac{0.416 J/g^\circ C \times 20}{50} = 0.1664 g\)

Thus, the mass of the samples is 0.166 g.

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Answer:

Explanation:

V/t

When the chemicals in the reaction are in aqueous solution, the half-reaction approach performs better than the oxidation-number method. Because the aqueous solution is usually acidic or basic, hydrogen ions or hydroxide ions are present. In general, the half-reactions are first balanced independently by atoms.

The overall cell reaction given in the question is

\(O{2}\)(g)+ 4H+(aq)+ 2Zn(s) → 2\(H_{2} O\)(l)+ 2\(Zn_{2}\)+(aq)

So Zn (s) is oxidized to \(Zn^{2+}\) at anode. Since anode is the half cell where oxidation happens.

At anode:  2 Zn (s) → 2\(Zn^{2+}\)+(aq)+ 4e-

At cathode reduction will happen. Here, \(O_{2}\) (g) is reduced by 4e- electrons and combine with 4H+ to form 2\(H_{2}O\).

Thus, cathode half cell reaction can be represented as

At cathode: O2 (g) + 4H+ (aq)+ 4e- → 2\(H_{2}O\)

Thus, overall reaction is

\(O_{2}\)(g)+ 4H+(aq)+ 2Zn(s) → 2\(H_{2}O\)(l)+ \(Zn^{2+}\)(aq)

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The half-reaction occurring at Cathode indicate  Zn (s) is oxidized to Zn2+ at anode. Since anode is the halfcell where oxidation happens.

The overall cell reaction given in the question is

O2(g)+ 4H+(aq)+ 2Zn(s) → 2H2O(l)+ 2Zn2+(aq)

An oxidation or reduction reaction is a half-cell process. We lose electrons in one and acquire electrons in the other. These processes occur in an electrochemical cell in which we lose electrons at the anode where oxidation occurs and gain electrons at the cathode where reduction occurs.

So Zn (s) is oxidized to Zn2+ at anode. Since anode is the halfcell where oxidation happens.

At anode:  2 Zn (s) → 2Zn2+(aq)+ 4e-

At cathode reduction will happen. Here O2 (g) is reduced by 4e- electrons  and combine with 4H+ to form 2H2O.

Thus cathode half-cell reaction can be represented as

At cathode: O2 (g) + 4H+ (aq)+ 4e- → 2H2O

Thus, overall reaction is O2(g)+ 4H+(aq)+ 2Zn(s) → 2H2O(l)+ 2Zn2+(aq)

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The false statement about buffers is: d) a buffer always consists of a weak acid and a soluble ionic salt of the weak acid.

Buffers are solutions that can resist changes in pH when small amounts of acids or bases are added. They typically consist of a weak acid and its conjugate base (or a weak base and its conjugate acid). The weak acid and its conjugate base are present in equilibrium, allowing the buffer to accept or donate protons to maintain a relatively constant pH. Option d is false because a buffer can consist of a weak acid and its conjugate base, or a weak base and its conjugate acid. It is not necessary for a buffer to always include a soluble ionic salt.

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The previous day's barometer reading when the gas was collected would have been 100.7 kPa. The difference in volume (57.9 ml - 56.1 ml = 1.8 ml) indicates a decrease in gas volume.

Since the temperature remained constant, according to Boyle's Law, the pressure and volume of a gas are inversely proportional. Therefore, the decrease in volume caused an increase in pressure. By subtracting the change in pressure (1.3 kPa) from the current barometer reading (99.4 kPa), we find the previous day's barometer reading to be 100.7 kPa.  Given that the volume increased from 56.1 ml to 57.9 ml while the temperature remained constant, the pressure decreased. According to Boyle's Law, the pressure and volume of a gas are inversely proportional. By calculating the difference in volume (57.9 ml - 56.1 ml = 1.8 ml) and assuming an ideal gas, we can determine that the previous day's barometer reading was 100.7 kPa (99.4 kPa + 1.3 kPa).

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Answer:

TRUE!!!!!!!!!!

Explanation:

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