Answer:
p=mv
v=p/m
v=28/1
v=28 m/sec
9. When air or water is cools it...
A.) Sinks
B.) Becomes less dense
Answer:
when air or water cools it sinks
Please help
Physics is so confusing
Answer:
below
Explanation:
sin a = 4/5
a = 53.1
tan theta = 3/4
theta = 36.89
Object A has mass of M and is moving in the +x direction. It collides with object B which has mass of 2M and is initially at rest. After the collision; object B has a final velocity of v in the + direction. Which of the following best describes the impulse object B exerts on object A during the collision? 2Mv Mv +Mv +2Mv
mass of 2M and is initially at rest answer is -2Mv
2v0 following best describes the impulse object B exerts on object A during the collision 2Mv Mv +Mv +2Mv
Why do you use the term "collision"?
In physics, collision, which is also known as impact, is the abrupt, powerful coming together in close proximity of two bodies, such as two pool cues, a golf club and a ball, a hammer and What do the terms collision and example mean?
noun collision (ACCIDENT)
a collision that occurs when two vehicles collide violently: On the southbound section of the road, there has been an accident. Last night, a head-on (= direct) collision between a car and a cab resulted in the deaths of two drivers.a nail, two railroad cars when linked, or a falling object and a floor.
2Mv Mv +Mv +2Mv
2Mv Mv = Mv -2Mv
2(Mv)= Mv
Mv= -2Mv
-2Mv
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The moon Umbriel orbits Uranus (mass = 8.68 x 10^25 kg) at a distance of 2.66 x 10^8 m. What is Umbriel's orbital period (in hours)?
Answer:
T = 99.51 hour
Explanation:
Mass of Uranus, \(M=8.68\times 10^{25}\ kg\)
The moon Umbriel orbits Uranus at a distance of \(2.66\times 10^8\ m\)
We need to find Umbriel's orbital period. Let it is T. Using Kepler's third law of motion to find it.
\(T^2\propto r^3\\\\T^2=\dfrac{4\pi^2r^3}{GM}\\\\T^2=\dfrac{4\pi^2\times (2.66\times 10^8)^3}{6.67\times 10^{-11}\times 8.68\times 10^{25}}\\\\T=358244.51\ s\)
As 1 hour = 3600 s
358244.51 s = 99.51 hour
Hence, Umbriel's orbital period is 99.51 hour.
Answer:
Explanation:
its 99.51 im not just saying that because of the person on top of me but i have all my notes from physics and from chemistry and from biology from when i was on acellus! but the top of me is right :)
find a vector(s) of length √15m in the x-z plane that is perpendicular to the vector A= (2i+3j+k) m
The vector that is perpendicular to the original vector is vector B = (√3 i - 2√3 k )
What is the vector that is perpendicular to the original vector?The vector that is perpendicular to the original vector is calculated as follows;
Let the vector = B = (xi + 0j + zk)
The dot product of A and B must be equal to zero.
A . B = (2i + 3j + k) . (xi + 0j + zk)
A.B = 2x + z = 0
2x = - z
The product of the vector must be √15 and it is calculated as;
√ (x² + z²) = √15
x² + z² = 15
Substitute the value of x for z;
x² + (-2x)² = 15
x² + 4x² = 15
5x² = 15
x² = 15/5
x² = 3
x = √3
z = - 2x
z = -2√3
The vector B = (√3 i - 2√3 k )
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A truck accidentally rolls down a driveway for 8.0\,\text m8.0m8, point, 0, start text, m, end text while a person pushes against the truck with a force of 850\,\text N850N850, start text, N, end text to bring it to a stop. What is the change in kinetic energy for the truck?
Answer:
Explanation:
According to work energy theorem
change in kinetic energy of truck = work done against it
work done against it = force x displacement
= - 850 x 8 = 6800 J
change in kinetic energy of truck = - 6800 J .
energy will be reduced by 6800 J
Answer:-6800
Explanation:
ASSIGNMENT what is the length of wire whose resistivity 3x10^-6ohm with the r=0.2mm with a given Value of 15.552 Resistance.
The length of wire whose resistivity is 3 x 10^-6ohm, and radius is 0.2 mm, with a given value of 15.552 resistance is 6.5268 m.
Given data: r = 0.2 mm = 0.2 x 10^-3m Resistivity = 3 x 10^-6 ohm R = 15.552 ohm
Formula Used: Resistivity (ρ) = (RA)/L
Where, R is resistance, A is the area of cross-section, L is the length of the wire.
Resistance (R) = ρ (L/A)
Multiplying A on both sides, we get
Resistance (R) x A = ρ L ... equation (1)
Area of the cross-section of a wire of radius (r) is given by, A = πr^2
where, π is a constant whose value is 3.14
Substituting the given values, we get
A = πr^2= π (0.2 x 10^-3m)^2= 1.2566 x 10^-7 m^2
Substituting the values of R, A and ρ in equation (1), we get
Length of wire (L) = (Resistance x Area) / Resistivity= (15.552 ohm x 1.2566 x 10^-7 m^2) / (3 x 10^-6 ohm)= 6.5268 m
Therefore, the length of wire whose resistivity is 3 x 10^-6ohm, and radius is 0.2 mm, with a given value of 15.552 resistance is 6.5268 m.
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Replace the incandescent bulb with the Voltage meter and return loop # to 3. What happens when you move the bar magnet back-n-forth through the loop? Does this appear to be creating a Direct Current or an Alternating Current? How do you know?
If we replace the incandescent bulb with a voltage meter and return the loop to its original configuration, then moving the bar magnet back and forth through the loop will induce an electrical current in the loop, as described by Faraday's law of electromagnetic induction.
What is magnet?A magnet is a material or object that produces a magnetic field, which is a force that can attract or repel certain other materials, such as iron or steel. The magnetic field is created by the motion of electric charges within the magnet, which align in such a way that they produce a net magnetic field. Magnets can be made from a variety of materials, including iron, cobalt, nickel, and certain alloys. They come in many different shapes and sizes, including bars, discs, horseshoes, and rings.
Here,
The type of current that is generated depends on the direction and rate of the magnet's motion. If the magnet is moved back and forth with a constant speed and in a straight line, the current induced in the loop will be an alternating current (AC), because the direction of the current will reverse every time the magnet changes direction. This can be observed by the voltage meter reading a voltage that periodically changes in direction.
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magnetism/ magnetic field ana magnetic forces
Answer:
Magnetism is a physical phenomenon that manifests itself in a force acting between magnets or other magnetized or magnetisable objects, and a force acting on moving electric charges, such as in current-carrying cables. The force action takes place by means of a magnetic field, which is generated by the objects themselves or otherwise. There are natural and artificial magnets. All magnets have two poles called the north pole and the south pole. The north pole of one magnet repels the north pole of another magnet and attracts the south pole of another magnet; the same with south poles.
Nitrogen makes up about what percent of a human's body weight?
Answer:
the answer is 3.3 %
Explanation:
Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.
The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J
How do i determine the quantity of heat energy?First, we shall list out the given parameters from the question. This is shown below:
Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?The quantity of heat energy that must be transferred can be obtained as follow:
Q = MCΔT
= 2.25 × 394 × 220
= 195030 J
Thus, we can conclude quantity of heat energy that must be transferred is 195030 J
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Compare the movement of four cars. Car A covered a distance of 60 km in 1hr.
Car B covered a distance of 30 km in 30 minutes. Car C covered a distance of 20
km in 15 minutes, Car D covered a distance of 10 km in 7 minutes, which car had
the highest velocity?"
Answer:
car D
Explanation:
1) before to compare all the values of the velocities, they must be in the same units of measurement. It means:
for car A: V=60km / 1h=60km/h;
for car B: V=30km / 0.5h=60km/h;
for car C: V=20km / 0.25h=80km/h;
for car D: V=10km / (7/60)h≈85.7km/h.
2) according to the values calculated in item 1 the car D had the highest velocity.
Answer:
Below
Explanation:
We can use this formula to find the velocity of an object
velocity = displacement / change in time
*note I converted all distances to meters and all times to seconds, its not necessary though**
CarAvelocity = 60,000 m / 3600 sec
= 16.66667 m/s
CarBvelocity = 30,000 m / 1800 sec
= 16.66667 m/s
CarCvelocity = 20,000 m / 900 sec
= 22.2222 m/s
CarDvelocity = 10,000 m / 420 sec
= 23.80952 m/s
Therefor, car D has the highest velocity
Hope this helps!
the diagram shows a cuboid of density 2000kg/m³. the dimensions of the block are 5m by 4m by 10m. calculate the mass
of the block
Explanation:
Volume ( L X W X D) * density = mass
(5 * 4 * 10) m^3 * 2000 kg/m^3 = 400 000 kg
( see how the ' m^3' cancels out and you are left with kg as your answer units?)
The image below shows sound waves traveling through air.
Which point is the source of the sound?
The point on the image that is the source of the sound / sound waves travelling would be B. 2.
Where do sound waves originate ?When a sound is produced, such as a musical note or spoken word, it initiates a disturbance at the source, which sets the surrounding particles in motion. As these particles oscillate back and forth, they generate regions of compression and rarefaction, resulting in the formation of longitudinal waves.
The propagation of sound waves emanates from a central source, radiating outward in a spherical pattern, thereby creating an expanding wavefront. This fundamental principle of wave behavior stems from the point-source nature of sound waves, wherein they originate from a central locus and disperse in all directions.
This central source in the image is 2.
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4. A rock is thrown from the edge of the top of a 100 m tall building at some unknown angle above the horizontal. The rock strikes the ground at a horizontal distance of 160 m from the base of the building 5.0 s after being thrown. Determine the speed with which the rock was thrown.
Answer:
Explanation:
Let the velocity of projectile be v and angle of throw be θ.
The projectile takes 5 s to touch the ground during which period it falls vertically by 100 m
considering its vertical displacement
h = - ut +1/2 g t²
100 = - vsinθ x 5 + .5 x 9.8 x 5²
5vsinθ = 222.5
vsinθ = 44.5
It covers 160 horizontally in 5 s
vcosθ x 5 = 160
v cosθ = 32
squaring and adding
v²sin²θ +v² cos²θ = 44.4² + 32²
v² = 1971.36 + 1024
v = 54.73 m /s
Answer:
55.42 m/s
Explanation:
Along the horizontal direction, the rock travels at constant speed: this means that its horizontal velocity is constant, and it is given by
u_x = d/t
Where
d = 160 m is the distance covered
t = 5.0 s is the time taken
Substituting, we get
u_x =160/5 = 32 m/s.
Along the vertical direction, the rock is in free-fall - so its motion is a uniform accelerated motion with constant acceleration g = -9.8 m/s^2 (downward). Therefore, the vertical distance covered is given by the
\(S=u_yt+\frac{1}{2}at^2\)
where
S = -100 m is the vertical displacement
u_y is the initial vertical velocity
Replacing t = 5.0 s and solving the equation for u_y, we find
-100 = u_y(5) + (-9.81)(5)^2/2
u_y = 45.25 m/s
Therefore, the speed with which the rock was thrown u
\(u= \sqrt{u_x^2+u_y^2} \\=\sqrt{32^2+45.25^2}\\ = 55.42 m/s\)
One statement of the first law of thermodynamics is that:___________.
a. the amount of work done on a system is dependent of pathway.
b. the total work done on a system must equal the heat absorbed by the system.
c. the heat flow in or out of a system is independent of pathway.
d. the total energy flow in or out of a system is equal to the sum of the heat transferred to or from the system and the work done by or on the system.
e. in any chemical process the heat flow must equal the change in enthalpy.
Answer:
a. the amount of work done on a system is dependent of pathway
Explanation:
The first law of thermodynamics states that the change in internal energy of a system equals the net heat transfer into the system minus the net work done by the system.
ΔU = Q - W
Where;
Q, the net heat transfer into the system depends on the pathway
W, the net work done by the system also depends on the pathway
But, ΔU, the change in internal energy is independent of pathway
Therefore, the correct option is "A"
a. the amount of work done on a system is dependent of pathway
Part A
Choose the correct free body diagram for the case when the ball is at its lowest point
The correct free body diagram for the case when the ball is at its lowest point is tension pointing upwards and weight of the object pointing downwards.
What is the tension in the string at the lowest point in circular path?
The tension in the string at the lowest point in a circular path is equal to weight added to centripetal force required.
Mathematically, the formula for the tension in the string is given as;
T = W + ma
where;
W is the weight on the stringm is the mass of the objecta is the acceleration of the objectAt the lowest point the acceleration of the object is zero, a = 0. The new equation becomes the following;
T = W
The free body diagram of the tension and the weight of the object is given as;
↑ T
Ф
↓ W
Thus, the correct free body diagram consist of the tension force pointing upwards and the weight of the object pointing downwards.
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Calculate the amount of air in a room 6m long, 5m wide and 3mm high.
Answer:
0.09kg of air
Explanation:
The dimensions of the room are given
change the height to meters by dividing it by thousand.
For the volume multiplying the length,width and height (all should be in the same unit most suitable being meters).
Volume refers to the amount of space inside a box or a object.
The amount of air is equal to the volume.
Answer:
90 m^3
Explanation:
Volume of the room:
6 m * 5 m * 3 m = 90 m^3 <=====( I changed 3mm to 3 m)
if 3mm is not a typo mistake
volume becomes ( 3 mm = .003 m)
6 m * 5 m * .003 m = .09 m^3 ( though unlikely )
what is the force acting on point O? Check picture for diagram! please and thank you
The magnitude of the force acting at point O is determined as 240 N.
What is the magnitude of the force at point O?The magnitude of the force at point O is calculated by applying the principles of moment as shown below.
sum of the clockwise moment = sum of the anticlockwise moment
F₀(2 m + 2m + 2m) = 260 N (2m + 2 m ) + 200 N ( 2 m )
where;
F₀( is the force at point O6F₀ = 260 (4) + 200(2)
6F₀ = 1,440
F₀ = 1440 / 6
F₀ = 240 N
Thus, the magnitude of the force acting at point O is determined as 240 N.
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what is the value of pi(8.104)^2 written with correct significant numbers
Answer:206.3
Explanation:
A car is moving east along a straight, level road at a constant velocity. Which forces form an action/reaction force pair?
A) the force of the tires against the road and the force of the road on the tires
B) the weight of the car and the force of the road pushing up on the car
C) the force of the engine on the car and the force due to friction on the car
D) the normal force on the car and the force of the car pulling on Earth
Answer:
The force of the tires against the road and the force of the road on the tires
Explanation:
right on edge(2021)
A car is moving east along a straight, level road at a constant velocity. The force of the tires against the road and the force of the road on the tires. Thus option A is correct
What is force?Force is defined as an outside force that has the power to alter the motion or rest of a body.
It can be defined as a push or pull exerted on an object as a result of the interaction of the object with another object.
It can also be defined as a push or a pull that modifies or tends to modifies an object's uniform motion, state of rest, or modifies the object's direction or shape It either accelerates items or increases their overall pressure.
The joule is the accepted unit of energy in electronics and most other branches of science. The amount of energy expended when a force of one newton is applied across a displacement of one meter is known as a joule.
There are seven types of force.
Applied forceFrictional forceNormal forceGravitational forceAir resistance forceTension forceSpring forceThus, a car is moving east along a straight, level road at a constant velocity. The force of the tires against the road and the force of the road on the tires. Thus option A is correct
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You see a boat sitting at the end of a dock. Ten minutes later you see the same boat in a cove to the right of the dock. You did not see the boat move.
However, you know that the boat moved because its
relative to the dock changed.
The boat must have moved, despite not being seen to move, because its relative position to the dock has changed. This phenomenon is known as relative motion .
Everything is always in motion, but the way we perceive it depends on our frame of reference.
In this scenario, the dock was the frame of reference for the initial position of the boat. When the boat moved to the cove, its position relative to the dock changed, and the dock was no longer an appropriate frame of reference. The boat's motion is now relative to the cove instead.
It is important to note that relative motion depends on the chosen frame of reference. If we were to choose the boat as the frame of reference, then it would be the dock that appears to move, not the boat. This is because motion is always relative to a chosen frame of reference.
In conclusion, the boat must have moved because its position relative to the dock changed. The concept of relative motion reminds us that motion is always relative to a chosen frame of reference, and that the way we perceive motion depends on our chosen frame of reference.
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After rolling halfway down an incline a marble's kinetic energy is
A. impossible to determine
B. the same as its potential energy
C. greater than its potential energy
D. less than its potential energy
Suppose that 2 J of work is needed to stretch a spring from its natural length of 24 cm to a length of 42 cm. (a) How much work is needed to stretch the spring from 32 cm to 34 cm
Answer:
Workdone = 0.025 Joules
Explanation:
Given the following data;
Workdone = 2J
Extension = 42 - 24 = 18 cm to meters = 18/100 = 0.18m
The workdone to stretch a string is given by the formula;
Workdone = ½ke²
Where;
k is the constant of elasticity.
e is the extension of the string.
We would solve for string constant, k;
2 = ½*k*0.18²
2 = ½*k*0.0324
Cross-multiplying, we have;
4 = 0.0324k
k = 4/0.0324
k = 123.46 N/m
a. To find the workdone when e = 32, 34.
Extension = 34 - 32 = 2 to meters = 2/100 = 0.02m
Workdone = ½*123.46*0.02²
Workdone = 61.73 * 0.0004
Workdone = 0.025 Joules
Therefore, the amount of work (in J) needed to stretch the spring from 32 cm to 34 cm is 0.67.
calculate the resistance if a potential difference of 3v exists when a current of 2A flows through the conductor
Answer:
Resistance = 1.5 ohms
Explanation:
Given:
Potential difference = 3v
Current flow = 2 A
Find:
Resistance
Computation:
Resistance = Potential difference / Current flow
Resistance = 3 / 2
Resistance = 1.5 ohms
the object that emit light when they are hot called.......
What’s the experimental value of specific heat capacity experiment
The highest experimental value of the specific heat capacity is
11.29 J/Kg.
The amount of heat required to raise the temperature of one gram of a substance by one degree Celsius is known as the specific heat capacity of the substance.
The value of specific heat capacity may be used as the measure of the capacity of a substance to absorb heat because it is constant for every substance.
The value of specific heat capacity of an object or substance is measured by using a device known as the calorimeter.
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How is thermal energy being transferred when steam rises from a beaker of boiling water?
O A. Conduction
• B. Radiation
O c. Translation O D. Convection
Answer:
d. convention
Explanation:
hope this helped
Drag is usually ignored because its effect on the horizontal velocity is usually negligible due to the short time of flight.
An object's surface area and geometry, along with the object's surrounding wind speed will affect the drag force.
In most cases, drag force will cause the object to land horizontally closer to the predicted landing point as drag is a resistive force.
Drag is ignored in projectile predictions because projectiles usually have a relatively short time of flight.
The surface area of the object, the wind speed, as well as the relative velocity of the airplane will affect the drop of relief packages.
The drag force will cause the projectile to take a longer time to land and may cause to land far from its expected drop point.
What is drag?Drag is a force that acts in opposition to the motion of an object moving through a fluid.
Drag can be thought of as friction in fluids because similar to friction, it acts in an opposite direction of the relative motion of a moving object.
For example, airplanes moving through air experience a drag; ships and boats moving through water experience drag too.
Drag also occurs in projectiles moving through the air. However, because of the relatively short time of flight, it is usually ignored in projectile motion.
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Complete question:
While studying projectile motion, we consider ideal scenarios, where the projectile travels along its trajectory only under the influence of gravity. In real-world situations, however, other forces act on the projectile.
Consider a cargo plane that is dropping relief packages to flood victims. In predicting and studying this motion, we might consider gravity, but ignore the horizontal and vertical forces associated with drag (or air friction). Discuss this simplification. Specifically address these questions:
•Why do we often ignore drag in projectile predictions?
•What conditions (of the object, its surroundings, and its launch) do you think might make drag a significant factor in the relief package drop?
•How would drag affect the projectile's motion if it really were a significant factor in the relief package drop?
A car speeds up from 45 mph to 65mph to pass a truck.if this requires 6s. What is the average acceleration of the car
Answer: the average acceleration of the car is 3.33 mph/s.
Explanation:
To find the average acceleration of the car, we can use the formula:
average acceleration = (final velocity - initial velocity) / time
In this case, the initial velocity of the car is 45 mph, the final velocity is 65 mph, and the time taken to reach the final velocity is 6 seconds.
Substituting these values in the formula, we get:
average acceleration = (65 mph - 45 mph) / 6 s
average acceleration = 20 mph / 6 s
average acceleration = 3.33 mph/s (rounded to two decimal places)
Therefore, the average acceleration of the car is 3.33 mph/s.
Answer:
110
Explanation:
45+65=110