Help me please what is 25,473+13,648+15,306

Answer:

Portanto, o Sofia pode fazer 6 tamanhos diferentes

Step-by-step explanation:

A fim de sermos capazes de determinar efetivamente quantos quadrados de diferentes tamanhos podem ser formados a partir do triângulo isósceles 52, resolvemos isso usando a fórmula

2 (n + 1) Onde n = 0 e todos os inteiros positivos

em outro para obter um tamanho diferente para os quadrados, temos que adicionar mais triângulos para aumentar o tamanho

a) quando n = 0

2 (0 + 1) = 2 × 1 = 2 triângulos isósceles iguais

A união de 2 triângulos isósceles forma um quadrado. Este é o primeiro quadrado

= 1 quadrado

b) quando n = 1

2 (1 + 1) = 2 × 2 = 4 triângulos isósceles iguais = 1 quadrado

c) quando n = 2

2 (2 + 1) = 2 × 3 = 6 triângulos isósceles iguais = 1 quadrado

d) quando n = 3

2 (3 + 1) = 2 × 4 = 8 triângulos isósceles iguais = 1 quadrado

e) quando n = 4

2 (4 + 1) = 2 × 5 = 10 triângulos isósceles iguais = 1 quadrado

f) quando n = 5

2 (5 + 1) = 2 × 6 = 12 triângulos isósceles iguais = 1 quadrado

Adicionamos o número total de triângulos usados

2 + 4 + 6 + 8 + 10 + 12 = 42 triângulos

42 triângulos de 52 triângulos formariam 6 quadrados com tamanhos diferentes

Vamos fazer mais um, onde n = 6

g) quando n = 6

2 (6 + 1) = 2 × 7 = 14 triângulos isósceles iguais = 1 quadrado

2 + 4 + 6 + 8 + 10 + 12 + 14 = 56 triângulos

Isso já excedeu o número dado de triângulos em questão.

Portanto, o Sofia pode fazer 6 tamanhos diferentes de quadrados usando 42 triângulos isósceles iguais

Answer:

y=10x-4

Step-by-step explanation:

Answer:

y=10x-4

Step-by-step explanation:

It all depends on how you want your hamburger. If you're serving it as a main dish, 300 hamburger patties (each around 4 ounces) should be plenty to feed 300 people. If you utilize hamburger meat as a topping or filler in a meal, you'll need a different amount.

Arithmetic operations is a field of mathematics that studies numbers and the operations on numbers that are helpful in all other disciplines of mathematics. It consists mostly of operations like addition, subtraction, multiplication, and division. Arithmetic Operator is used to conduct mathematical operations on the supplied operands such as addition, subtraction, multiplication, division, modulus, and so on. The four basic arithmetic operations are addition, subtraction, multiplication, and division. Arithmetic mean is a number calculated by dividing the sum of a set's elements by the number of values in the set.

Here,

It all depends on how you want to eat the hamburger. If you're serving it as a main course, 300 hamburger patties, each weighing around 4 ounces, should plenty to satisfy 300 people. It will need a different quantity of hamburger meat if you use it as a topping or filler in a dish.

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Complete question:

How much hamburger will it take to make 300 three oz patties with a 20% shrinkage?

Answer:

They celebrated it on March 14 at 1:59 because...

The first few digits of pi are --- 3.14159

The date of March 14 is 3/14. Then you add the 1:59 it makes the first few digits of pi.

Step-by-step explanation:

The tradition to celebrate Pi Day on 14th March started in the late 80's, when the physicist Larry Shaw organized the first Pi Day celebration at the San Francisco Exploratorium. Since then, Pi Day has become a popular way for mathematicians, educators, and students to celebrate and share their interests in mathematics. Many schools, universities, and math clubs around the world host events, such as pi recitation contests, pi-themed games, and pie-eating contests, to celebrate this day.

Eating pie is also a way to join the celebration, as the word "pi" sounds like "pie". People often eat different types of pie on Pi Day, such as pizza pie, sweet pies, and savory pies to celebrate the mathematical constant pi and its connection to the word “pie”.

Rite a partial decay series for At-217 undergoing the following sequential decays,

α decay:

217  At    ​→        4 α  + 213 Bi

85                    2          83

In order to change into a more stable state, a radioactive atom will naturally produce radiation in the form of energy or particles. It is necessary to distinguish between radioactive material and the radiation it produces. Beta, gamma, and alpha decay are the three kinds of radioactivity.

"Alpha decay," a common form of radioactive decay, happens when a nucleus emits an alpha particle (a helium-4 nucleus). During the usual radioactive decay process known as beta decay, a nucleus generates beta particles. The child nucleus will possess a greater atomic mass than the parent nucleus.

α decay:

217  At    ​→        4 α  + 213 Bi

85                    2          83

β decay:

213 Bi     →       0 e  +  213 Po

83                   -1           84

α decay:

213 Po    →        4 α  + 209 Tl

84                    2           82

β decay:

209 Tl     →        0 e  + 209 Pb

82                    -1          83

Therefore,

Rite a partial decay series for At-217 undergoing the following sequential decays,

α decay:

217  At    ​→        4 α  + 213 Bi

85                    2          83

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Answer:

D

Step-by-step explanation:

The diagonals of a rhombus bisect the angles, thus

∠ ABC = ∠ CBD = 5x - 18 and

∠ BAC = ∠ DAC = x

The diagonals are perpendicular bisectors of each other, thus

the angles round the intersection of the diagonals = 90°

Consider the triangle on the left of the rhombus, then

5x - 18 + x + 90 = 180 ( sum of angles in a triangle )

6x + 72 = 180 ( subtract 72 from both sides )

6x = 108 ( divide both sides by 6 )

x = 18 → D

mass of the penny in pounds is 0.00220462 pounds.

To explain this, we can use unit analysis to convert the mass from grams to pounds. We know that there are 453.592 grams in one pound, so we can set up a conversion factor:
1 pound / 453.592 grams
To convert the mass of the penny in grams to pounds, we can multiply the given value by this conversion factor:
( X grams ) * ( 1 pound / 453.592 grams )
Simplifying this expression, the grams unit cancels out, leaving us with the mass of the penny in pounds:
( X / 453.592 ) pounds
Plugging in the given mass of the penny in grams, we get:
( Y grams ) * ( 1 pound / 453.592 grams ) = ( Y / 453.592 ) pounds

the mass of the penny in pounds is ( Y / 453.592 ) pounds, which is approximately 0.00220462 pounds.

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Answer:

mean = 85, standard deviation = 3.5

Step-by-step explanation:

The empirical rule states that for a normal distribution, 68% of the data falls within one standard deviation of the mean, 95% falls within two standard deviation of the mean and 99.7% falls within three standard deviation of the mean.

From the diagram since the shaded are is approximately 95% of the data. Hence 95% falls within two standard deviations of the mean.

σ = standard deviation, μ = mean

Hence; μ ± 2σ = (78, 92)

μ - 2σ = 78       (1);  

μ + 2σ = 92       (2)

Adding equation 1 and 2, gives 2μ = 170

μ = 85

μ - 2σ = 78

85- 2σ = 78

2σ = 7

σ = 3.5

Answer:

3/5, 1, 8/5, 8

Step-by-step explanation:

Answer:

0, 35, 8/5, 8.  I think

Step-by-step explanation:

hope this helps :3

im sorry if im wrong

Answer:

26.29 cu. in.

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

\(x^2-2x \\x=4\\(4)^2-2(4)\\16-8\\8\)

Answer:

What is the total number

Step-by-step explanation:

Answer:

\(36\)

Step-by-step explanation:

Given

\(x^2 - 12x = 21\)

Required

Make a perfect square

First, get the coefficient (k) of x

\(k = -12\)

Divide by 2

\(\frac{k}{2} = \frac{-12}{2}\)

\(\frac{k}{2} = -6\)

Square this result:

\((\frac{k}{2})^2 = (-6)^2\)

\((\frac{k}{2})^2 = 36\)

Hence, 36 when added to the left-hand side makes it a perfect square trinomial

Answer:

$21,560.00

Step-by-step explanation:

SI = 14,000 x 0.06 x 9

SI = $7,560

$14,000 + $7,560 = $21,560.00

Step-by-step explanation:

h≈16.01

is the answer mske me brainlist

Answer:

Step-by-step explanation:

Hi there!

Given;

Total surface face (TSA)= 660cm²

Radius (r) = 5cm

Now;

TSA= 2πr( r + h)

   660cm²= 2*(22/7)*5 (5+h)

 660cm² = \(\frac{220}{7}\)(5+h)

\(\frac{660}{\frac{220}{7} }\)= 5+h

h = 21-5

Therefore, the height of 16 cm.

Hope it helps!

True. In a regression model, the dependent variable is the variable that we aim to predict or explain using one or more independent variables.

In a regression model, the dependent variable is indeed the variable that we aim to predict or explain. It represents the outcome or response variable that we are interested in understanding or analyzing. The purpose of the regression analysis is to examine the relationship between this dependent variable and one or more independent variables. By identifying and quantifying the influence of the independent variables on the dependent variable, regression analysis allows us to make predictions or explanations about the behavior or value of the dependent variable.

The regression model estimates the relationship between the variables based on observed data and uses this information to infer how changes in the independent variables impact the dependent variable.

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The f(x) is given by a power series. f'(0) = 0, f''(0) = -2/3, so f has a local maximum at x=0. The Taylor series of f(1) approximated by 1-(1/3!)  with error less than 1/100. The differential equation is xy' + y = cos(x) has solution y(x) = sinx .

To find f'(0), we differentiate the power series term by term

f'(x) = ∑n=1^∞ (-1)^(n-1) x^(2n-1) / (2n)!

Then, we substitute x=0 to get

f'(0) = ∑n=1^∞ (-1)^(n-1) (0)^(2n-1) / (2n)! = 0

To find f''(0), we differentiate the power series for f'(x)

f''(x) = ∑n=1^∞ (-1)^(n-1) (2n-1) x^(2n-2) / (2n)!

Then, we substitute x=0 to get

f''(0) = ∑n=1^∞ (-1)^(n-1) (2n-1) (0)^(2n-2) / (2n)! = 0

Since f'(0) = 0 and f''(0) = 0,

f has a local maximum at x=0

To show that 1-(1/3!) approximates f(1) with error less than 1/100, we first note that

|f(1) - (1 - 1/3!)| = |∑n=2^∞ (-1)^(n-1) / (2n+1)!| ≤ ∑n=2^∞ 1/(2n+1)!

We can use the inequality 1/(n!) < 1/2^n to bound the series

∑n=2^∞ 1/(2n+1)! < ∑n=2^∞ 1/2^(2n-1) = 1/4

Therefore, |f(1) - (1 - 1/3!)| < 1/4, which is less than 1/100.

To show that y=f(x) is a solution to the differential equation xy' + y = cosx, we first find y'

y(x) = ∑n=0^∞ (-1)^n x^(2n) / (2n+1)!

y'(x) = ∑n=1^∞ (-1)^(n-1) x^(2n-1) / (2n)!

Then, we substitute y and y' into the differential equation

x ∑n=1^∞ (-1)^(n-1) x^(2n-1) / (2n)! + ∑n=0^∞ (-1)^n x^(2n) / (2n+1)! = cosx

We can simplify this equation by combining the series

∑n=0^∞ [(-1)^n x^(2n) / (2n+1)! - (-1)^n x^(2n+1) / (2n+2)!] = cosx / x

Recognizing the series on the left-hand side as the power series for sinx, we have

sinx / x = cosx / x

Therefore, y(x) = sinx is a solution to the differential equation.

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The harmful use of animals in experiments is not only cruel but also often ineffective. Animals do not get many of the human diseases that people do, such as major types of heart disease, many types of cancer, HIV, Parkinson's disease, or schizophrenia.

Answer:

3  1/2

Step-by-step explanation:

Put '3' where 'y' is and compute :

[12 -3(3) ] / 2   + 3 [ (2(3)-4 )/3) =

   3/2              +   2  

    =   3  1/2

The total amount that would be found in the account after 4 years, would be $ 641. 69

The total amount after 4 years in Arik's account can be found by the formula :

= A = Amount invested x ( 1 + r /n )ⁿ

The variables are:

Amount invested = $ 500

r = 6.25% = 0. 0625

n = 12

t = 4 years

The total amount is then :

A = 500 x ( 1 + 0. 0625 / 12 ) ^ ⁽¹² ˣ ⁴ ⁾

A = $ 641. 69

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Angular velocities: ω_D = v_D/R and ω_AB = v₀/(2R) and  Angular accelerations: α_D = 0 and α_AB = 0

At the instant shown, we can analyze the motion of disk D and bar AB in terms of their angular velocities and angular accelerations.
1. For disk D:
As the disk rolls without slipping, its linear speed at the point of contact with the ring is equal to the product of its radius (R) and its angular velocity (ω_D). Since the inner radius of the fixed ring is 2R, the linear speed of the disk is v_D = ω_D * R.
2. For bar AB:
Since pin B is moving with a constant speed (v₀), we can relate this to the angular velocity of bar AB (ω_AB) as v₀ = ω_AB * 2R.
Now, let's compute the angular accelerations of disk D and bar AB.
1. For disk D:
The disk is rolling without slipping, so its linear acceleration at the point of contact with the ring is equal to the product of its radius (R) and its angular acceleration (α_D). As the disk is at its lowest position and moving with constant speed, its linear acceleration is zero. Therefore, α_D = 0.
2. For bar AB:
Since the pin at B is moving with a constant speed (v₀), the linear acceleration of point B is zero. This implies that the angular acceleration of bar AB (α_AB) is also zero.
In summary, at the given instant:
- Angular velocities: ω_D = v_D/R and ω_AB = v₀/(2R)
- Angular accelerations: α_D = 0 and α_AB = 0

To begin, we can use the fact that the disk is rolling without slipping inside the fixed ring to relate the speed of the disk to the speed of the pin at B. Specifically, we know that the speed of any point on the rim of the disk is equal to the speed of the pin at B, which we'll call vo. Next, we can use the geometry of the system to relate the angular velocities of the disk and bar AB to the speed of the pin at B. Let's start with the disk. The disk is rolling without slipping, so its speed can be related to its angular velocity, which we'll call ωd. Specifically, we know that the speed of any point on the rim of the disk is equal to the product of its radius (R) and its angular velocity (ωd). So, we have:
vo = R * ωd
Solving for ωd, we get:
ωd = vo / R
Next, let's consider bar AB. Since it is pin-connected to the centre of the disk, its angular velocity is equal to the angular velocity of the disk. So, we have:
ωAB = ωd = vo / R
Now, let's compute the angular accelerations of the disk and bar AB. We can do this using the component system given in the problem. Specifically, we can use the fact that the net torque on each component must be equal to its moment of inertia times its angular acceleration.
Let's start with the disk. The only torque acting on the disk is due to the force of gravity, which is trying to rotate the disk clockwise. This torque is equal to the product of the force of gravity (mg) and the distance from the centre of the disk to the point where the force is applied (which is R/2 since the force is applied at the centre of mass of the disk). So, we have:
τd = (mg) * (R/2)

On the other hand, the moment of inertia of the disk can be found using the formula for a solid cylinder rotating about its central axis, which is:
Id = (1/2) * m * R²
Setting these two expressions equal and solving for the angular acceleration of the disk, we get:
τd = Id * αd
(mg) * (R/2) = (1/2) * m * R² * αd
Simplifying, we get:
αd = (2*g) / R
where g is the acceleration due to gravity.
Finally, let's compute the angular acceleration of bar AB. Since it is pin-connected to the centre of the disk, it experiences no net torque. Therefore, its angular acceleration is zero.
In summary, at the instant shown, the angular velocities and angular accelerations of the disk and bar AB are:
ωd = vo / R
ωAB = vo / R
αd = (2*g) / R
αAB = 0

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Answer:

Read below

Step-by-step explanation:

For the first row, the inequality is x ≤ -5.

For the second row, the inequality is x < -5.

For the last row, the inequality matching the graph is x ≥ -5.

A trick to remember the sign is if the point on the graph is empty, then the sign would be either < or >, and if it's filled, it would be ≤ or ≥.

Also, x is less is on the left (negative) and x is more is on the right (positive).

Answer:

24>-16

Step my step explanation:

Step-by-step explanation:

"bisects" means "cuts in half".

that is the whole "secret" for that problem.

now we know, that both line segments are equally long (exactly half of the total length of UV).

so,

4x - 9 = 2x + 5

2x = 14

x = 7

TCP provides error checking to ensure reliable data delivery, making option A the correct answer. Only the propagation delay is not caused by the store-and-forward strategy employed by switching devices.

TCP (Transmission Control Protocol) provides error checking as part of its services. It ensures reliable data delivery by using acknowledgments and sequence numbers to detect and recover from packet loss, errors, or out-of-order delivery. When a TCP receiver receives data, it sends an acknowledgment (ACK) back to the sender to confirm the successful reception of packets. If the sender does not receive an ACK for a particular packet within a specified timeout period, it assumes the packet was lost or damaged and retransmits it.

TCP provides error checking to ensure reliable data delivery, making option A the correct answer.

The propagation delay is the time it takes for a signal to travel from the source to the destination. It is determined by the physical distance between the devices and the speed of signal propagation in the transmission medium. The propagation delay is an inherent characteristic of the medium and cannot be eliminated by switching devices or other strategies.

The other three options—processing delay, queuing delay, and transmission delay—are all caused by the store-and-forward strategy used by switching devices. Processing delay refers to the time taken to examine and process the packet headers. Queuing delay occurs when packets have to wait in a queue before being transmitted. Transmission delay is the time it takes to push the bits onto the transmission medium.

Among the given options, only the propagation delay is not caused by the store-and-forward strategy employed by switching devices.

3. The correct answer is A. The system is very well-engineered.

In a statistical multiplexing system, the queuing delay is the delay experienced by packets waiting in a queue before being transmitted. If the average queuing delay is very close to zero, it indicates that the system is well-engineered and efficiently managing its resources. A well-designed system can minimize or eliminate queuing delays by appropriately allocating resources and ensuring efficient scheduling algorithms.

Traffic intensity, which represents the ratio of the average traffic load to the transmission capacity, does not directly determine the queuing delay. It is possible to have low queuing delays even with high traffic intensity if the system is well-designed.

When the average queuing delay is close to zero, it suggests that the system is well-engineered and efficiently utilizing its resources, as stated in option A.

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Answer:

less than

Step-by-step explanation:

Answer:

n ≤ 25

Step-by-step explanation:

n - 8 ≤ 17

n - 8 (+8) ≤ 17 (+8)

n ≤ 25

n ≤ 25 is your answer

Hope this helps <3

Answer:

13.01

Step-by-step explanation:

The zero next to the 7 is the hundredths place.

13.007

Drop the 7.

Now you have 13.00

Since 7 is from 5 to 9, the last zero goes up 1 to 1.

Answer: 13.01

Answer:

13.01

Step-by-step explanation:

13.00|7

When the number is 5 or higher round up

13.01

Answer:

Step-by-step explanation:

a=3/4