Help me please!!!!!!!!

The melting point of the material, comparing the state of the matter at room temperature, and comparing the viscosity of each substance are the tests that can deduce the strength of the intermolecular forces of the compound.

The intermolecular forces influence a substance's melting point. Therefore, a substance's high melting point indicates that the intermolecular interactions between its particles are also significant.

Similar to this, the condition of substance at ambient temperature specifies what that state of matter is.

The intermolecular forces also affect the viscosity of the substances. When intermolecular interactions between layers of a substance are particularly strong, the viscosity of the substance increases.

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Answer:

1.9992x10^-23

Explanation:

The thing is 6.022*10^23 atoms of carbon is 12g. so 1 atom of carbon will contain:

12/6.022*10^23 = 1.9992x10^-23

hope its clear and helps...

Properties of carbon that explain its presence as a basic element of organic compounds - Catenation and Tetravalent.

Carbon is a chemical element with the symbol C and atomic number 6 (it contains 6 protons in its nucleus). As a member of group 14 in the periodic table, it is non-metallic and tetravalent – ​​making four electrons available to form covalent chemical bonds.

The most common isotope of carbon has 6 protons and 6 neutrons and has an atomic mass of 12.0107 AMU. Its basic electronic configuration is 1s22s22p2.

Properties of carbon that explain its presence as a basic element of organic compounds -

Carbon has the ability to form very long chains of strong and stable interconnecting C-C bonds. This property, called catenation allows carbon to form an almost infinite number of compounds.

Carbon has an affinity for bonding with other small atoms, including other carbon atoms, through the formation of stable covalent bonds. Despite the fact that it is present in a huge number of compounds, carbon is weakly reactive compared to other elements under normal conditions.

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Answer:

a closed series circuit

Answer:

An open series circuit

Explanation:

I'm late but for future people...

I took the test.

Molar mass of Ibuprofen is  206.29 g/mol.

A non-steroidal anti-inflammatory medicine called ibuprofen is used to treat inflammation, fever, and pain. This includes rheumatoid arthritis, migraines, and painful menstrual cycles. It can also be used to close a premature baby's patent ductus arteriosus. It can be administered intravenously or orally. Ibuprofen is a pain reliever that can be purchased without a prescription over-the-counter. It belongs to the class of medications known as non-steroidal anti-inflammatory medicines (NSAIDs) and is used to treat mild to severe pain, including toothache, migraine, and period pain. If you have ever experienced an allergic reaction or signs like wheezing, avoid taking ibuprofen by mouth or applying it to your skin. Ibuprofen is C13H18O2 so

Molar mass= 13*12+ 18*1 + 16*2 = 206

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Answer:

Best regards.

Explanation:

Hello,

In this case, we relate the heat, mass, heat capacity and temperature when a thermal change is carried out as shown below:

\(Q=mCp(T_{final}-T_{initial})\)

Now, for the given data, we compute the absorbed heat (due to the temperature increase) as follows:

\(Q=15.0g*0.900\frac{J}{g^oC}*(350^oC-25^oC) \\\\Q=4.39x10^3J=4.39kJ\)

Best regards.

Answer:

4,387.5 J was absorbed

Explanation:

Calorimetry is the part of physics that is responsible for measuring the amount of heat generated or lost in certain physical or chemical processes.

In this way, there is a direct proportional relationship between heat and temperature. Thus, the amount of heat received or transferred by a body when it undergoes a temperature variation (Δt) without there being a change of physical state (solid, liquid or gaseous) is calculated using the following expression:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case:

Replacing:

Q= 0.900 \(\frac{J}{g*C}\) *15 g * 325 °C

Q=4,387.5 J

4,387.5 J was absorbed

Ribose is an important sugar with a molar mass of 150.15 g/mol and an empirical formula of CH₂O . Its molecular formula is C₅H₁₀O₅

A molecular formula  is defined as the exact number of different atoms present in the molecule of a compound. On the other hand, an empirical formula is defined as the simplest whole number ratio of the different atoms present in a molecule of a compound.

Given here,

molar mass of ribose sugar = 150.15 g/mol

empirical formula = CH₂O

To find: molecular formula

empirical formula mass of ribose sugar

=  (12+ 1×2+ 16) g/mol

= 30 g/mol

molar mass/ empirical formula mass

= 150.15 gmol⁻¹ / 30  gmol⁻¹

=5.005

≈5

we know that

molecular formula

= molar mass/ empirical formula mass  × empirical formula

=5 ×CH₂O

= C₅H₁₀O₅

Thus, the molecular formula is C₅H₁₀O₅

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In a water molecule, hydrogen and oxygen are held together by a polar covalent bond.

Two hydrogen atoms bound together by covalent bonds to one oxygen atom make up a water molecule. The sharing electrons in covalent bonds could be drawn to oxygen atoms because they are electronegative.

Due to the molecule's bent structure, water (\(H_{2} O\)) naturally polar. The shape of the molecule places the majority of the negative charge from the oxygen atoms on one side and the positive charge from the hydrogen atoms on the other. An illustration of a polar covalent bond is this.

Therefore, In a water molecule, hydrogen and oxygen are held together by a polar covalent bond.

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Answer:

There are three types of periods in the modern periodic table: very short periods, short periods, and long periods.

The difference between very short periods and short periods is the number of elements they contain. Very short periods only contain two elements, while short periods contain eight elements. The difference between short periods and long periods is the number of orbitals that can be occupied by electrons in each period. Short periods can only have electrons in the s- and p-orbitals, while long periods can also have electrons in the d-orbital.

Here is a table summarizing the differences between very short periods, short periods, and long periods:

The concentration of the original Ba(OH)₂ solution if 15.0 ml solution of Ba(OH)₂ is neutralized with 22.7 ml of 0.200 m HCl is 151.3 mol/dm³

To determine concentration of the original Ba(OH)₂ solution, we must know he balanced chemical equation for the neutralization reaction is:

Ba(OH)₂ + 2HCl → BaCl₂ + 2H₂O

From the equation above, the stoichiometric ratio of Ba(OH)₂ and HCl is 1:2. That means one mole of Ba(OH)₂ reacts with 2 moles of HCl. The balanced chemical equation also shows that the number of moles of HCl used is the same as the number of moles of Ba(OH)₂. Hence:

moles of HCl = 0.200 mol/dm³ × 22.7 dm³ = 4.54 mol

Using the stoichiometric ratio, the moles of Ba(OH)₂ in the solution can be calculated to be:

moles of Ba(OH)₂ = 4.54 mol ÷ 2 = 2.27 mol

The volume of the Ba(OH)₂ solution is 15.0 mL, which is 0.015 dm³. Therefore, the concentration of the original Ba(OH)₂ solution can be calculated as:

concentration = moles/volume= 2.27 mol ÷ 0.015 dm³= 151.3 mol/dm³

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The concentration of the original Ba(OH)₂ solution is 0.302 M.

Given data

Volume of Ba(OH)₂ solution used = 15.0 ml

Volume of HCl used = 22.7 ml

Molarity of HCl solution used = 0.200 M

We need to calculate the concentration of Ba(OH)₂ solution, which is not known.Molar ratio of HCl and Ba(OH)₂ in a balanced chemical equation of their neutralization is;

HCl + Ba(OH)₂ → BaCl₂ + 2H₂O

The balanced chemical equation tells us that 1 mole of HCl is required to neutralize 1 mole of Ba(OH)₂.

So, the moles of HCl used in the reaction is;

moles of HCl = molarity × volume (in liters)

moles of HCl = 0.200 M × 0.0227 L = 0.00454 mole

Since one mole of HCl reacts with 1 mole of Ba(OH)₂,

so the number of moles of Ba(OH)₂ used is also equal to 0.00454 mole. Since we know the volume of the Ba(OH)₂ solution used, we can calculate the molarity of the solution as;

molarity = moles of solute / volume of solution in liters

Molarity = 0.00454 / (15.0 / 1000) = 0.302 M

Therefore, the concentration of the original Ba(OH)₂ solution is 0.302 M.

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Answer:

The sun is at the (edge) of our solar system

and is much (hotter) than anything else in the solar system (95%) of the entire mass of the solar system is contain in the sun

Answer:

163 L CO₂

Explanation:

Step 1: Find conversion

1 mol = 22.4 L at STP

Step 2: Use Dimensional Analysis

\(7.29 \hspace{2} mol \hspace{2} CO_2(\frac{22.4 \hspace{2} L \hspace{2} CO_2}{1 \hspace{2} mol \hspace{2} CO_2} )\) = 163.296 L CO₂

Step 3: Simplify

We have 3 sig figs

163.296 L CO₂ ≈ 163 L CO₂

Answer:

A lower pH of the mouth creates bad bacteria that eventually lead to decay of the tooth.  

It can be prevented by avoiding food that causes acidity.

Explanation:

Tooth decay is caused by the pH level in the mouth dropping below 5.5, meaning it is acidic. It can be prevented by brushing your teeth as toothpaste is an alkali which will neutralise the pH level in your mouth.

Hope this helps

Answer:

4th phrase

substances in equal amounts in the body

Answer:

D

Explanation: (:

Empirical formula tells us the relative ratios of different atoms in a compound.

The chemical formula for a compound obtained by composition analysis is always the empirical formula.

How to calculate Empirical formula:

Linalyl acetate (bergamot oil):

              Carbon               Hydrogen                  Oxygen

                73.41 %                   10.29 %                  16.30 %

             73.41 / 12               10.29 / 1                   16.30 / 16

               6.11                          10.29                        1.01

            6.11 / 1.01                10.29 / 1.01                1.01 / 1.01

                 6                            10                                1

          Empirical formula : C₆H₁₀O

Thus we can conclude that empirical formula of linalyl acetate is  C₆H₁₀O

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The empirical formula for Linalyl acetate expresses the relative proportions of different atoms in a compound.

Linalyl acetate is a phytochemical found in a variety of flowers and spice plants. It is an important component of bergamot and lavender essential oils. It is the linalool acetate ester, and the two are frequently found together.

Hence, the empirical formula describes the relative proportions of different atoms in a compound. The chemical formula for a compound obtained through composition analysis is always the empirical formula.

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Answer:

1.03 grams / mL

Explanation:

Mass of beaker and sample liquid = 84.64

Mass of beaker                                = 32.344

Mass of the sample (subtract)        =  52.296

Don't do any rounding until you are finished.

mass = 52.296 grams

volume = 50.6 mL

density = mass / volume

density = 52.296/50.6

density = 1.034 grams / mL

Rounding

The volume only has 3 dig digs

So the answer is 1.03 grams / mL

Increasing the concentration of acetic acid in a reaction can lead to a higher percentage of acetic acid reacting and producing \(CH_3CO_2\).

In a chemical reaction, the concentration of reactants plays a crucial role in determining the extent of the reaction. By increasing the acetic acid concentration, more acetic acid molecules will be present in a given volume. This higher concentration leads to a more significant number of collisions between acetic acid molecules, increasing the chances of successful collisions that result in the formation of \(CH_3CO_2\).

Additionally, an increased concentration of acetic acid can shift the equilibrium of the reaction towards the formation of \(CH_3CO_2\). Le Chatelier's principle states that if the concentration of a reactant is increased, the equilibrium will shift in the direction that consumes that reactant. Thus, by increasing the concentration of acetic acid, the equilibrium will favour the forward reaction, resulting in a higher percentage of acetic acid reacting and producing \(CH_3CO_2\).

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Answer:

59.9% is the percent yield for the 4.5 g of produced Al₂S₃

Explanation:

Let's determine the reaction:

3S  +  2Al  →  Al₂S₃

First of all, let's determine the limiting reactant. We need to convert the mass to moles:

4.8 g /32.06g/mol = 0.150 moles of S

5.4 g / 26.98 g/mol = 0.200 moles of Al

3 moles of S react to 2 moles of Al

Then, 0.150 moles of S may react to (0.150 . 2)/3 = 0.1 ,moles of Al

We have 0.200 moles and we only have 0.1. As we have excess of Al, this is the excess reactant. In conclussion, the limiting reagent is S.

2 moles of Al react to 3 moles of S

Then 0.2 moles of Al may react to (0.2 . 3) /2 = 0.3 moles of S. (We only have 0.150 moles)

Let's go to the product, 3 moles of S can produce 1 mol of Al₂S₃

Then 0.150 moles of S, may produce (0.150 . 1) /3 = 0.05 moles.

We convert moles to mass to determine the thoretical yield:

0.05 mol . 150.15g /mol =  7.50g

Percent yield = (Produced yield/Theoretical yield) . 100

% = (4.5g / 7.5g) . 100 = 59.9%

Answer: DNA makes protein molecules to help with almost every cellular process.

i think?

The freezing point of the solution is -11.8 °C.

The boiling point of the solution is 103.31 °C.

To determine the freezing point of the solution, we can use the equation:

ΔTf = Kf * m

where:

ΔTf is the freezing point depression,

Kf is the cryoscopic constant (for water, Kf = 1.86 °C/m),

m is the molality of the solution (moles of solute per kilogram of solvent).

First, let's calculate the molality (m) of the solution:

Molar mass of ethylene glycol (C2H6O2):

C = 12.01 g/mol

H = 1.01 g/mol (x 6) = 6.06 g/mol

O = 16.00 g/mol (x 2) = 32.00 g/mol

Total molar mass = 12.01 g/mol + 6.06 g/mol + 32.00 g/mol = 50.07 g/mol

Number of moles of ethylene glycol (C2H6O2) = mass / molar mass

Number of moles = 30.8 g / 50.07 g/mol = 0.615 mol

Mass of water = volume x density = 96.6 mL x 1.00 g/mL = 96.6 g

Now, let's calculate the molality:

Molality (m) = moles of solute / mass of solvent (in kg)

Molality = 0.615 mol / 0.0966 kg = 6.36 mol/kg

Now we can calculate the freezing point depression (ΔTf):

ΔTf = Kf * m

ΔTf = 1.86 °C/m * 6.36 mol/kg = 11.8 °C

To find the freezing point of the solution, subtract the freezing point depression from the freezing point of pure water (0 °C):

Freezing point = 0 °C - 11.8 °C = -11.8 °C

To determine the boiling point of the solution, we can use the equation:

ΔTb = Kb * m

where:

ΔTb is the boiling point elevation,

Kb is the ebullioscopic constant (for water, Kb = 0.52 °C/m),

m is the molality of the solution (same value as calculated before: 6.36 mol/kg).

ΔTb = 0.52 °C/m * 6.36 mol/kg = 3.31 °C

To find the boiling point of the solution, add the boiling point elevation to the boiling point of pure water (100 °C):

Boiling point = 100 °C + 3.31 °C = 103.31 °C

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By Avogadro's number, the bromine atoms are 2.34 × 10²³ atoms.

We need to know about Avogadro's number to solve this problem. Avogadro's number is the number that explains how many atoms are in one mol. The Avogadro's number is

Na =  6,02 × 10²³ atoms / mol

From the question above, we know that

gr = 31 grams

Mr = 79.9

Find the amount of bromine in moles

n = gr / Mr

n = 31 / 79.9

n = 0.39 mole

By using Avogadro's number, we can calculate how many bromine atoms

N = Na . n

N = 6,02 × 10²³ x 0.39

N = 2.34 × 10²³ atoms

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Answer:

attached

Explanation:

answer attached

hope this helps!

Based on LeChatelier's principle, (option a) Release of CO₂ and (option c) Conversion of NADH to NAD+  are favorable reactions in the context described.

According to LeChatelier's principle, a reaction is favorable when it is driven in the direction that helps to counteract an imposed change. Among the given options:

a. Release of CO₂: LeChatelier's principle would favor this reaction if the system is subjected to an increase in pressure, as the equilibrium would shift towards the side with fewer gas molecules to reduce the pressure.

b. Enol to Keto tautomerization: LeChatelier's principle is not directly applicable to this reaction, as it involves a tautomeric shift between different forms of the same molecule rather than a change in equilibrium.

c. Conversion of NADH to NAD+ : LeChatelier's principle would favor this reaction if the system is subjected to an increase in NADH concentration, as the equilibrium would shift towards the conversion of NADH to NAD+ to counteract the increase.

d. Diffusion of protons down the gradient: LeChatelier's principle is not directly applicable to this process, as it involves the movement of particles along a concentration gradient rather than a change in equilibrium.

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Answer:

the emprircsl formula is: CH2O

Explanation:

Answer:

The answer is given in the picture

Explanation:

The equilibrium composition of CO₂ is determined to be 0.59 kmol.

To solve this problem, we can use the ideal gas law and the equilibrium constant expression for the reaction:

CO + 1/2O₂ ⇌ CO₂

Given the initial number of moles of CO and O₂, we can set up an ICE (Initial, Change, Equilibrium) table. Let's assume that x kmol of CO is consumed and converted to CO₂. Then, the change in the number of moles for each species is:

CO: -x kmol

O₂: -0.5x kmol

CO₂: +x kmol

At equilibrium, the number of moles of CO is (2 - x) kmol, O₂ is (3 - 0.5x) kmol, and CO₂ is x kmol. The equilibrium constant expression can be written as:

Kp = (P_CO₂) / (P_CO * P_O₂(1/2))

Given Kp = 16.461 and the pressure conditions, we can substitute the equilibrium partial pressures into the expression:

16.461 = x / ((2 - x) * (3 - 0.5x)(1/2))

Solving this equation yields x ≈ 0.59 kmol.

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List 1 is the best choice of materials because it has a balance between biotic decomposers and abiotic factors needed for the worms and composting.

Composting is the process whereby remains of organic matter are keep in a favorable environment and conditions in order to allow for decomposition.

Compost consists of the right mix of biotic factors suchas worms and fungi as well as abioticfactors such as water and sun.

Therefore, based in the materials provided, List 1, because it has a balance between biotic decomposers and abiotic factors needed for the worms and composting.

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Answer:

B how much farther does the arrow fly when you use a stronger bow

Explanation:

Option b. How much farther does the arrow fly when you use a stronger bow? represent the new scientific question that can be investigated in the laboratory.

It is a question that may result in a hypothesis for helping out in. It should be answering or figuring out the reason for some kind of observation.

So based on this, we can say that Option b. How much farther does the arrow fly when you use a stronger bow? represent the new scientific question that can be investigated in the laboratory.

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Answer:

4 meters

Explanation:

100 centimeters to meters, so move the decimal 2 spaces left.

400 becomes 4.00