Help me please :) .
I’ll mark you as a brainliest.

Answer:  

Slope-int form: y = mx + b

x/10 + y/1000 = 1

y/1000 = -x/10 + 1

y = 1000(-x/10 + 1)

y = -100x + 1000

Step-by-step explanation:

Answer:

volume = 4710 ft³

Step-by-step explanation:

base area = πr² = (3.14)(10²) = 314 ft²

volume = base area x height = 314 x 15 = 4710 ft³

The equation cos (α - β) × cos (α + β) ≠ cos² α - cos² β. Then the given equation is incorrect.

Trigonometry deals with the relationship between the sides and angles of a right-angle triangle.

The equation is given below.

cos (α - β) × cos (α + β) = cos² α - cos² β

Then show whether the equation is correct or incorrect.

Taking the left-hand side, then we have

\(\cos(\alpha-\beta)*\cos(\alpha +\beta) = (\cos \alpha \cos\beta + \sin \alpha \sin \beta ) (\cos \alpha \cos\beta - \sin\alpha \sin\beta )\\\\\cos(\alpha-\beta)*\cos(\alpha +\beta) = \cos ^2 \alpha \cos ^2\beta - \sin ^2 \alpha \sin ^2\beta\)

The left-hand side does not equal to the right-hand side.

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Answer:

Step-by-step explanation:

a^2+b^2=c^2

c^2-b^2=a^2

2^2-1^2=c^2

c^2=3

c=\(\sqrt{3}\)

espero que esto te ayude, pero no se si esta correcto lo siento

At t = 0.4, the velocity of the particle is zero. This indicates that the particle is momentarily at rest at this time.

To determine whether there is a time interval during which the particle is not moving, we need to examine the velocity of the particle. The velocity of the particle is the derivative of its position with respect to time.

The given position function is y = 0.20 + 8.0t - 10t^2.

To find the velocity function, we take the derivative of the position function with respect to time (t):

v(t) = d/dt (0.20 + 8.0t - 10t^2)

= 8.0 - 20t

The velocity function v(t) represents the rate of change of the position of the particle with respect to time. If the velocity is zero at any point in time, it means the particle is momentarily at rest.

Setting the velocity function equal to zero, we have:

8.0 - 20t = 0

Solving for t, we find:

20t = 8.0

t = 0.4

So, at t = 0.4, the velocity of the particle is zero. This indicates that the particle is momentarily at rest at this time.

Therefore, there is a time interval during which the particle is not moving, specifically at t = 0.4. Before and after this time point, the particle is in motion either upward or downward along the y-axis.

It's worth noting that we should consider the full domain of the position function (y) to determine if there are any other time intervals during which the particle is not moving. In this case, the given function does not specify any constraints on time, so the time interval t = 0.4 is the only time interval during which the particle is at rest.

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Answer:

5?

Step-by-step explanation:

There is no value for x, but the y value for 0 would be 5.

A quadratic expression x² + 6x + 5 into the form  a(x - h)² + k is (x + 3)² - 4    

The correct answer is an option (c)

Here the quadratic expression is: x² + 6x + 5

We need to write this quadratic expression into the form a(x - h)² + k

Comparing above expression with ax² + bx + c we get,

a = 1, b = 6 and c = 5

We use completing the square method to write above expression into  a(x - h)² + k form.

We add and subtract (b/2)² from above expression.

(b/2)² = (6/2)²

         = 3²

         = 9

So, the expression becomes:

x² + 6x + 5

= x² + 6x + 9 + 5 - 9

= (x + 3)² - 4               ........((x + 3)² = x² + 6x + 9)

This expression is in the form a(x - h)² + k with a = 1, h = -3 and k = -4

Therefore, the required expression is:  (x + 3)² - 4    

The correct answer is an option (c)

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The complete question is:

Complete the square to transform the expression x² + 6x + 5 into the form  a(x - h)² + k

a). (x + 6)² + 4

b) (x + 6)² - 4

c) (x + 3)² - 4

d) (x + 3)² + 4

Answer:

Option F

Step-by-step explanation:

F). x + y = 3 -------(1)

    x - 3y = -2 --------(2)

    Equation (1) minus equation (2)

    (x + y) - (x - 3y) = 3 - (-2)

    4y = 5

    y = 1.25

    Hence, y is positive.

G). x + y = 3 --------(1)

    x + y = -2 --------(2)

    Both the equations represent parallel lines.

    There are no solutions of the given equations.

H). x - 3y = -2 -------(1)

     x + y = -2 -------(2)

    Equation (2) minus equation (1)

    (x + y) - (x - 3y) = -2 - (-2)

     4y = 0

     y = 0

    Since, 0 is neither positive nor negative, y will be neither positive nor negative.

J). x + y = 3 -------(1)

    x - y = 3 --------(2)

    Equation (1) - Equation (2)

    (x + y) - (x - y) = 3 - 3

    2y = 0

    Hence, y is neither negative nor positive.  

    Therefore, Option F is the answer.

Answer:

a grocery store

Step-by-step explanation:

it seems strange that most of those would request a report card at all

The modified equation for the fish population taking into account harvesting is dB/dt = 0.25B(1 - B/500) - 20. With an initial fish population of 150 tons, the model predicts a gradual increase in the fish population over time.

The fish population dynamics can be described by the modified equation dB/dt = 0.25B(1 - B/500) - 20, where B represents the fish population in tons and t represents time in years. The first term, 0.25B(1 - B/500), represents the intrinsic growth rate of the fish population without any harvesting. The term (1 - B/500) accounts for the self-limiting effect as the fish population approaches the carrying capacity of the lake, which is 500 tons.

Considering the harvesting rate of 20 tons/year, we subtract 20 from the growth rate term to account for the removal of fish due to harvesting. This modification to the equation reflects the impact of harvesting on the fish population dynamics.

Given an initial fish population of 150 tons, we can plot a graph of the fish population trajectory over time. Starting from 150 tons, the model predicts a gradual increase in the fish population as it approaches the carrying capacity of 500 tons. However, the rate of increase slows down as the population nears the carrying capacity due to the self-limiting effect. The population stabilizes around the carrying capacity with fluctuations over time.

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\( {3}^{ - 2} \times {3}^{ - 5} = {3}^{ - 7} \)

Answer:

A) 3^-7

Step-by-step explanation:

Applying law of sine and law of cosine, the unknown values x and y are 16.2 units and 37.1 degrees respectively.

To determine the value of x and y in the given triangle, we can use law of sine or law of cosine depending on the variables available and what we need to determine.

Applying law of cosine;

x² = 15² + 10² - 2(15)(10)cos78

x² = 225 + 100 - 300cos78

x² = 225 + 100 - 62.4

x² = 262.6

x = √262.6

x = 16.2 units

From this, we can apply law of sine to determine y;

x / sin X = y / sin Y

Substituting the values into the formula above;

16.2 / sin78 = 10 / sin y

Cross multiply both sides and solve for y;

16.2siny = 10sin78

sin y = 10sin78 / 16.2

sin y = 0.6038

y = sin⁻¹ (0.6038)

y = 37.14°

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Answer:

8(3j-2) and 4(6j−4)

there you go!!

ANSWER:

STEP-BY-STEP EXPLANATION:

We have the following expression:

When it is a quotient, and it is the same base, the exponents are subtracted, therefore

a.Angle BAC=53°

b.Angle BDC=53°

c. Angle BFE=90°

d. Angle EBC=37°

Answer:

Solution given:

<BOC+254°=360°[complete turn]

<BOC=360°-254°

<BOC=106°

now

<BAC=½ *<BOC[inscribed angle is half of central angle]

<BAC=½*106°=53°

again

<BDC=<BAC=53°

<BFE=90°[inscribed angle on a semi circle is 90°]

Now.

again in ∆BOC

<B=<C[base angle of isosceles triangle]

<B+<C+<O=180°[sum of interior angle of a triangle is 180°]

<C+<C+106°=180°

2C°=180°-106°

<C=74°/2

<C=37°

First, we need a few things.

The first term = 26

The common difference = 22 - 26 = -4

26 - 4(n - 1) is our equation.

Let's plug 50 into n to find a50

a50 = 26 - 4(50 - 1)

a50 = 26 - 4(49)

a50 = 26 - 196

a50 = -170

The only transformation that would carry rectangle ABCD onto itself is a single rotation of 180 degrees in a parallelogram.

Rectangle ABCD's characteristics and how each transformation affects its orientation and location must be examined in order to identify the collection of reflections and rotations that would carry the rectangle onto itself of a parallelogram.

First, using the provided coordinates, let's determine the sides of the rectangle: AB is parallel to DC, and AD is parallel to BC. Also, we can observe that the lengths of AB and AD are equal to DC and BC, respectively, indicating that the opposite sides are congruent.

The rectangle is first suggested to be rotated 180 degrees. This transformation simply maps each point to its corresponding point on the rectangle; the rectangle's orientation is left unchanged. Hence, rectangle ABCD would be carried onto itself by this transformation alone.

The rectangle is first reflected over the x-axis, rotated 180 degrees, and then reflected once more over the x-axis is the second transformation suggested. This series of transformations flips the rectangle's orientation while mapping each point to its equivalent point on the other side of the rectangle. Hence, the rectangle ABCD would not be carried onto itself by this transformation sequence.

The third suggested transformation involves reflecting the rectangle first over the y-axis, then over the line y = x, and then back over the y-axis. The rectangle's orientation is maintained but its position is altered by this series of modifications. Hence, the rectangle ABCD would not be carried onto itself by this transformation sequence.

The rectangle is to be rotated 180 degrees, reflected over the line y = x, and then reflected over the x-axis as the fourth transformation suggested. Each point is moved and mapped to a point on the other side of the rectangle via this series of transformations. The rectangle's orientation is also altered, though. Hence, the rectangle ABCD would not be carried onto itself by this transformation sequence.

Hence, a single 180° rotation is the only transformation that could turn rectangle ABCD upon itself.

In conclusion, we studied the features of the rectangle and the consequences of each transformation on its orientation and location to find the set of reflections and rotations that would transport rectangle ABCD onto itself. In contrast to the other suggested transformations, we discovered that only a single rotation of 180 degrees would keep the rectangle's orientation and location intact.

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Most of the kinetic energy of the water is transferred into the water, then the thermal energy will increase. Hence, option C is correct.

Kinetic energy is the term used in physics to describe the force that a moving item has. It is described as the amount of effort necessary to accelerate anybody with a particular mass from rest to a given velocity. Except variations in speed, the body retains the kinetic energy it gains during acceleration.

The body uses exactly the same amount of energy when slowing down from its current rate to a state of rest. Formally, kinetic energy refers to any term in a system's Lagrangian that has a derivative with respect to time.

As per the given information in the question,

When the kinetic energy of the diver is transferred into the water, the thermal energy will increase.

The entity's thermal energy grows as the average kinetic energies of its particles rise. As a result, an object's thermal energy rises as its temperature does.

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Answer:

What is the question?

Put your question in the replies of this answer and I'll gladly answer you

Step-by-step explanation:

May I have brainliest please? :)

Answer:

The answer will be A because you start at 4 and in between 4 and 5 you will go up to 7 and that will be your answer

Answer:

The answer is B

Step-by-step explanation:

Answer:

521

365 *10 = 3650

365/7 = 521.4

Step-by-step explanation:

Answer: i.d.k but 149

Step-by-step explanation:

The probability of the center of a circle being contained within a randomly formed triangle using three points along its perimeter is 1/4 or 25%. This probability remains the same for any size of the circle.

The probability that the center of the circle is contained within the triangle formed by selecting three random points along its perimeter is 1/4 or 25%. This is because any triangle that contains the center of the circle must have all of its vertices on the circumference of a smaller circle with half the radius of the original circle. The probability of selecting three random points on the circumference of this smaller circle is 1/4 or 25%.

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Answer:

1/3

Step-by-step explanation:

We can calculate the slope using 2 points: (3,0) and (0,-1).

\(\frac{y_2-y_1}{x_2-x_1}=\frac{0- -1}{3-0}\)=

\(\frac{1}{3}\)

Answer:

\(8x+46\)

Step-by-step explanation:

Insert the original values of C and D into the new expression:

\(2(x+8)+3(2x+10)\)

Simplify the expression. Use the distributive property:

\(2(x)+2(8)+3(2x)+3(10)\\\\2x+16+6x+30\)

Combine like terms:

\((2x+6x)+(16+30)\\\\8x+46=2C+3D\)

:Done

a) Mass of the Death Star: To find the mass of the death star, the given density function will be integrated over the entire volume of the star. Mass of the death star=∫∫∫ρ(r,θ,ϕ)dV =4π/15×r15 .

where dV=r2sinθdrdθdϕ As we have ρ(r,θ,ϕ)=r3ϕ2, so the integral will be

Mass of the death star=∫∫∫r3ϕ2r2sinθdrdθdϕ

Here, the limits for the variables are given by r = 0 to r

= r1;

θ = 0 to π; ϕ

= 0 to 2π.

So, Mass of the death star is given by:

Mass of the death star=∫02π∫0π∫0r1r3ϕ2r2sinθdrdθdϕ

=1/20×(4π/3)ρ(r,θ,ϕ)r5|02π0π

=4π/15×r15

b) Total energy of Obi Wan's home planet:

Total energy of Obi Wan's home planet can be obtained using the relation

E=∫4/3πρr3dVUsing the same limits as in part (a),

we haveρ(r,θ,ϕ)

=Mr33/3V

=∫02π∫0π∫0RR3ϕ2r2sinθdrdθdϕV

=4π/15R5 So,

E=∫4/3πρr3dV=∫4/3π(4π/15R5)r3(4π/3)r2sinθdrdθdϕE

=16π2/45∫0π∫02π∫0Rr5sinθdϕdθdr

On evaluating the integral we get,

E=16π2/45×2π×R6/6=32π3/135×R6

a) Mass of the death star=4π/15×r15, b) Total energy of Obi Wan's home planet=32π3/135×R6

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The margin of error associated with the confidence interval is 0.02.

The 95% confidence interval for the population proportion is defined as:

p ± z(0.05 / 2) × √[p ( 1 − p )/ n]

We have,

p − z(0.05 / 2) × √[ p ( 1 − p )/ n ] = 0.73                                     ----------- ( 1 )

p + z(0.05 / 2) × √[ p ( 1 − p )/ n ] = 0.77                                    ----------- ( 2 )

Adding the above two equations,

p − z(0.05 / 2) × √[ p ( 1 − p )/ n ] + p + z(0.05 / 2) × √[ p ( 1 − p )/ n ] = 0.73 + 0.77

2p = 0.73 + 0.77

2p = 1.5

p = 0.75

Now, Subtracting the equations ( 1 ) and (2),

We get,

p − z(0.05 / 2) × √[ p ( 1 − p )/ n ] - p - z(0.05 / 2) × √[ p ( 1 − p )/ n ] = 0.73 - 0.77

−2 × z(0.05 / 2) × √[ p ( 1 − p )/ n ] = -0.44

z( 0.10 / 2) × √[ p ( 1 − p )/ n] = 0.02

The margin of error is defined by the formula:

M E = z(0.05 / 2) × √[ p ( 1 − p )/ n]

Therefore, The margin of error will be:

M E = 0.02

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