HELP! I need some assistance

There are four atoms that are found in the products.

When a molecule of I2 reacts with NaCl, we must first note that no reaction will take place. This is because Iodine is lower than chlorine in the series hence I2 can not displace chlorine from its salt.

Since we are still going to end up with the substances that we started with, we will have a total of four atoms.

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Answer:

2

Explanation:

i looked it up

nrm 4

The velocity of the car will be   \(V=18.18\ \frac{m}{s}\)

As velocity is the movement of the car with respect to time.

It is given that

Mass m  =  1100kg

Momentum= 22000 \(\frac{kgm}{s}\)

The momentum is given as

\(P=mv\)

\(v=\dfrac{p}{m}\)

\(v=\dfrac{22000}{1100} =18.18 \ \dfrac{m}{s}\)

Thus  the velocity of the car will be   \(V=18.18\ \frac{m}{s}\)

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Answer: ?? what moon are you talking about that i have to drag to various locations???

Explanation:

Answer:

i am guessing for reflection but not so sure

(a) The work done by the donkey on the cart is 59,721.9 J.

(b) The work done by the force of gravity on the cart is -48,434.87 J.

(c) The work done on the cart by friction during this time is 11,315.12 J.

(a) The work done by the donkey on the cart is calculated as follows;

Wd = Fd cosθ

where;

Wd = 375 N x 163 m x cos(12.3)

Wd = 59,721.9 J

(b) The work done by the force of gravity on the cart is calculated as;

Wg =  Fg x d x cosθ

Where;

θ = 90⁰ + 4.03⁰ = 94.03⁰

Wg = (431 kg x 9.81 m/s²) x 163 m x cos (94.03)

Wg = -48,434.87 J

(c) The work done on the cart by friction during this time is calculated as;

Wf = Ff x d x cosθ

where;

Ff = μmg cosθ

Ff = 0.0165 x 431 kg x 9.81 x cos (4.03)

Ff = 69.59 N

Wf = 69.59 x 163 x cos (4.03)

Wf = 11,315.12 J

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Answer:

it's from gravity because when you throw something up it goes forward a certain distance

If the dog walked at a constant speed the whole way, the graph of the dog's position versus time would be a straight line. This is because the dog's velocity (which is the derivative of position with respect to time) would be constant, and the acceleration (which is the derivative of velocity with respect to time) would be zero.

A straight line on a position-time graph indicates that the object is moving at a constant velocity. The slope of the line would be equal to the velocity of the dog.

If the graph is a horizontal line, it would indicate that the dog is at rest. If the line slopes upward, the dog is moving in the positive direction (for example, to the right in a position-time graph), and if the line slopes downward, the dog is moving in the negative direction.

In all, A constant speed means a constant velocity and the line is a straight line with a particular slope.

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Answer:

The magnitude of the force that the 6.3 kg block exerts on the 4.3 kg block is approximately 41.9 N

Explanation:

Forces on block 4.3 kg are:

63N to the right and R21 (contact force from the 6.3 kg block) to the left

Net force on 4.3 kg block is: 63 N - R21

Forces on the 6.3 kg block are:

R12 to the right (contact force from the 4.3 kg block) and 11 N to the left.

So net force on the 6.3 kg block is: R12 - 11 N

According to the action-reaction principle the contact forces R21 and R12 must be equal in magnitude (let's call them simply "R").

Then, since the blocks are moving with the SAME acceleration, we equal their accelerations:

a1 = (63 N - R)/4.3 = (R - 11 N)/6.3 = a2

solve for R by cross multiplication

6.3 (63 - R) = 4.3 (R - 11)

396.9 - 6.3 R = 4.3 R - 47.3

369.9 + 47.3 = 10.6 R

444.2 = 10.6 R

R = 444.2 / 10.6

R = 41.90 N

Answer:

greater than.

Explanation:

The energy of a body's mass at rest is calculated as the product of the mass at rest and the square of the speed of light, thus the Rest energy is the energy a body has due to its position at rest, so this statement is true.

Energy is the ability to perform work in physics. It could exist in several different forms, such as potential, kinetic, thermal, electrical, chemical, radioactive, etc. Additionally, there is heat and work, which is energy being transferred from one body to another. Energy is always assigned based on its nature once it has been transmitted. Thus, heat transmitted may manifest as thermal energy while work performed may result in mechanical energy.

The energy of a body's mass, at rest, is calculated as the product of the mass at rest and the square of the speed of light.

Therefore, rest energy is the energy a body has due to its position at rest.

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Answer:

D

Explanation:

Work is not a vector but it is a scalar

Answer:

D

Explanation:

D. its is a vector which is always in the same direction as the displacement

Answer:

1- bounce rule

2- left

3-11,2

4-true

5- whiffle ball

6- kitchen

7-false

8- ping pong

9- true

10- true

Explanation:

I'm pre5sure they are all right. brainliest please

Answer: I had the same quiz too I’m only doing so the other guy can get brainliest

Explanation:Kfkfkfjgjggj

The reaction of load L is 0 (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).

To determine the reactions of the loads L and R, consider the equilibrium of the forces acting on the structure.

First, analyze the vertical equilibrium. The sum of the vertical forces must be zero:

ΣFy = R − 7 kN − 3 kN

ΣFy = 0

This gives:

R = 10kN

Next, analyze the horizontal equilibrium. The sum of the horizontal forces must be zero:

ΣFx = L

ΣFx = 0

This indicates that there is no horizontal force acting on the structure.

Therefore, the reaction of load L is zero (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).

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The following are the correct matches for the waves in Column A and the wave types in Column B:

A mechanical wave is a wave that requires a medium to travel through. The two types of mechanical waves are transverse waves and longitudinal waves. A transverse wave is a wave in which the particles of the medium move perpendicular to the direction of the wave. A longitudinal wave is a wave in which the particles of the medium move parallel to the direction of the wave.

An electromagnetic wave is a wave that does not require a medium to travel through. Electromagnetic waves are made up of electric and magnetic fields that oscillate perpendicular to each other.

A matter wave is a wave that describes the probability of finding a particle at a given location. Matter waves are associated with all particles, including electrons, protons, and neutrons.

A spring wave is a type of mechanical wave that travels through a spring. The particles of the spring move back and forth along the length of the spring.

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Answer:

option (C) is right answer

Explanation:

I think it's helps you

Answer:

Option C is correct

Explanation:

hope it helps you

Calculating the mass of the block requires a bit of work. The formula for the volume of a rectangular solid is V = l*w*h, where V is the volume, l is the length, w is the width, and h is the height. Using the dimensions given, we can calculate the volume of the block as 30*80*60 = 144000 cubic centimeters.

The density of lead is approximately 11.34 grams per cubic centimeter. To calculate the mass of the block, we can use the formula m = V*d, where m is the mass, V is the volume, and d is the density. Plugging in the values we get m = 144000*11.34 = 1,634,400 grams or approximately 1.63 metric tons.

So, the mass of the block of lead is approximately 1.63 metric tons.

If the satellite goes too slow:

If the satellite goes too fast:

Answer:

The correct answer is 4R1

Explanation:

According to the given scenario ,the radius of the tightest curve on the same road without skidding is as follows:

As we know that

Centeripetal Acceleration is

= v^2 ÷ r

In the case when velocity becomes 2 times so the r would be 4 times

So, the radius of the  tightest curve on the same road without skidding is 4R1

Convert to m/s

\(\\ \sf\longmapsto v=20\times 5/18=5.5m/s\)

We know

\(\boxed{\sf \omega=\dfrac{rv}{|r|^2}}\)

\(\\ \sf\longmapsto \omega=\dfrac{0.5(5.5)}{|0.5|^2}\)

\(\\ \sf\longmapsto \omega=\dfrac{2.75}{0.25}\)

\(\\ \sf\longmapsto \omega=11rad/s\)

Answer:

11 km

Explanation:

Given that,

A car travel 4 km east and 7 km west. We need to find the distance traveled by the car from the initial point. We know that the overall path covered is called distance. So,

distance = total path covered

D = 4 km + 7 km

D = 11 km

So, the distance of the car from the initial point is 11 km.

1302200J

Explanation:

To bring water at 70°C to water at 0°C, we use MC∆T.

To convert water at 0°C to ice at 0°C, ML is applicable, where L is the latent heat of fusion and M equals mass. NB: Temperature is constant during fusion.

Again, to raise the temperature of ice to -11°c, we use MC∆T.

Total heat = MCw∆T + ML + MCi∆T

2 ×4200× 70 + 2×334000 + 2× 2100× 11 = 1302200J

Answer:

\(F_o=437Hz\)

Explanation:

From the question we are told that:

Frequency of Turning fork \(F_t=440Hz\)

Number of beats detected \(n=3\)  

Generally the equation for Original frequency \(F_o\) of the string  is mathematically given by

\(F_o=F_t-F_b\)

Where

\(F_b\) Beat frequency

\(F_b=1Hz*n\\F_b=1Hz*3\)

Therefore

\(F_o=440-3\)

\(F_o=437Hz\)

A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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The work done by the lift with a mass of 1050 kg and a gravitational field strength is 10 N/kg and a height of 15m is 157.5kJ

The work done is the amount of work done in lifting the object to a certain distance. The work done is the product of mass, gravitational field, and height.

Work done = m×g×h

mass (m) = 1050 kg

        g     = 10 N/kg

height (h) = 15m

W = m×g×h

   = 1050×10×15

  = 157.5 kJ

Thus, the work done(W) = 157.5 kJ.

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Answer:

3.33s

Explanation:

Given parameters:

Acceleration  = 15m/s²

Initial velocity  = 0m/s

Final velocity  = 50m/s

Unknown:

Time taken for the acceleration  = ?

Solution:

To solve this problem, we must understand that acceleration is the rate of change of velocity with time.

Mathematically;

           a  = \(\frac{v - u}{t}\)  

a is the acceleration

v is the final velocity

u is the initial velocity

t is the time taken

     So;

          15  = \(\frac{50 - 0}{t}\)  

           15t  = 50

              t  = 3.33s

The surface charge density of the isolated charged conductor sphere is approximately 22.15 \(C/m^{2}\)

The surface charge density of an isolated charged conductor sphere can be determined using the formula:

σ = E / (\(4πr^{2}\))

where σ is the surface charge density, E is the electric field strength, and r is the distance from the center of the sphere.

In this case, the electric field strength E is given as 49000 N/C, and the distance from the center of the sphere r is 21 cm (which can be converted to meters as 0.21 m). Plugging these values into the formula, we have:

σ = (49000 N/C) / \((4π * (0.21 m)^{2})\)

Calculating this expression, we find:

σ ≈ 22.15 \(C/m^{2}\)

Therefore, the surface charge density is approximately 22.15 \(C/m^{2}\). This indicates the amount of charge per unit area distributed on the surface of the sphere.

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The vessel can be immersed to a depth of 0.3006 m in the deep vat of mercury without being crushed.

The question requires us to determine the depth to which a closed vessel that can sink to a depth of 41.0 m in water before the external pressure crushes it could be immersed in a deep vat of mercury without being crushed. We can determine this using the concept of pressure.Pressure is defined as the amount of force acting per unit area. Pressure is given by the formula:

P = F/A,

where P is pressure, F is force, and A is area. Since the area remains constant, we can say that pressure is directly proportional to force. Thus, the greater the force acting on an object, the greater the pressure exerted on the object. The pressure exerted by a liquid depends on the density of the liquid, the depth of the liquid, and the acceleration due to gravity. This can be expressed using the formula:

P = ρgh,

where P is pressure, ρ is density, g is acceleration due to gravity, and h is depth. Let us first calculate the pressure exerted by the water at a depth of

41.0 m:ρ of water = 1000 kg/m³g = 9.81 m/s²h = 41.0 m

Substituting these values in the formula, we get:

P = ρgh= (1000 kg/m³)(9.81 m/s²)(41.0 m)= 405570 Pa

Now, we need to determine the depth to which the vessel can be immersed in mercury without being crushed. Let us call this depth "d". The pressure exerted by the mercury at this depth is equal to the pressure exerted by the water at a depth of 41.0 m. Thus, we can equate the two pressure values:

ρ of mercury = 13600 kg/m³g = 9.81 m/s²P = 405570 Pa

Substituting these values in the formula, we get:ρgh = P(13600 kg/m³)(9.81 m/s²)(d) = 405570 PaSolving for d, we get:d = 0.3006 m.

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Answer:

For a given system, there can be particular transformations for which the explicit equations of motion are the same for both the old and new variables. Transformations for which the equations of motion are invariant, are called invariant transformations. It will be shown that if the Lagrangian does not explicitly contain a particular coordinate of displacement  qi, then the corresponding conjugate momentum,  pi, is conserved. This relation is called Noether’s theorem which states “For each symmetry of the Lagrangian, there is a conserved quantity".

The mass rate of change of the space probe is approximately 28.49 kg/s .

To solve this problem, we can use the generalized form of Newton's Second Law, which states that the force acting on an object is equal to its mass times its acceleration:

F = ma

In this case, the force acting on the space probe is the thrust force generated by the rocket motor, which is equal to the rate of change of momentum of the ejected fuel:

F = (Δ m /Δt) * v

where;

Since the space probe is landing on the planet, the net force acting on it should be equal to the force of gravity pulling it down minus the upward thrust force generated by the rocket motor. So we can write:

F_net = m * g - (Δ m /Δt) * v

Plugging in the values and solving for delta m / delta t, we get:

2.00 m/s² = (175,000 kg * 8.25 m/s²) - (Δ m / Δt) * 35,000 m/s

Δ m / Δt = (175,000 kg * 8.25 m/s² - 2.00 m/s² * 35,000 m/s) / 35,000 m/s

Δm / Δt ≈ 28.49 kg/s

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Answer:

74.0 meters

Explanation:

We can use the kinematic equation for displacement with constant acceleration to solve this problem:

Δy = v0t + 1/2at^2

where Δy is the displacement (i.e., the change in height), v0 is the initial velocity (which is 0), a is the constant acceleration, and t is the time taken.

Plugging in the given values, we get:

Δy = 0 + 1/2(71.0 m/s^2)(1.45 s)^2

Δy = 74.0 m

Therefore, the maximum altitude achieved by the rocket is 74.0 meters above the ground.