HELP I NED THIS SOLVED 1/3 divided by 2/9 as a fraction

Answer:

x = 4.5

Step-by-step explanation:

The segment joining the midpoints of the two sides of a triangle is half the length of the third side, that is

5x = \(\frac{1}{2}\) × 45 = 22.5 ( divide both sides by 5 )

x = 4.5

(a) -0.255 is the probability that a randomly selected credit card holder has a credit card balance less than $2500. (b) You randomly select 25 credit card holders. 0.0228 is the probability that their mean credit card balance is less than $2500.

Let us pull out the critical elements

Population: Normally distributed with mean of 2870

population standard deviation = 900 standard deviation of the sample mean (standard error) is 900 / √25. or 180

As population sigma is known, we do not have apply any corrections

P(xbar < $2500) = ?    

Since μ and σ are known (population mean and standard deviation) we can use a simple Z test.

Ztest = (2500-2870 )/ 180  or -370/180 = -2.055

As this is very close to -2 one can use the rule of thumb for probability within ± 2 sigma  being 95.44% to get a close estimate.   If the area between -2 and 2 sigma = .9544 then the area outside = .0456.  Half of this (the amount under the curve LESS THAN -2) would be .0228

Using a calculator or computer for an exact answer we find (using a TI-83/86):

nmcdf(-9E6,2500,2870,180) = .0199

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Answer:

No

Step-by-step explanation:

substitute the x- coordinate of the point into each equation and if both have the value of the y- coordinate of the point then it is a solution.

y = 5(3) + 9 = 15 + 9 = 24 ≠ 9

y = 3 + 6 = 9

since the point does not satisfy both equations then it is not a solution of the system.

No

Step-by-step explanation:

y=5x+9

y=x+6

\(y = 5x + 9 \: \: - - - - - - (1) \\ y = x + 6 \: \: - - - - - - -(2) \\ from \: equation \: (2) \\ y - 6 = x \\ x = 6 + y - - - - - - (3)\\ y = 5x + 9 \\ y = 5(6 + y) + 9 \\ y = 30 + 5y + 9 \\ 5y - y = 30 + 9 \\ 4y = 39 \\ y = - \frac{39}{4} \\ y = 9.75 \\ \\ y = 9.75 \: into \: (2) \\y = x + 6 \\ 9.75 = x + 6 \\ 9.75 - 6 = x \\ x = 9.75 - 6 \\ x = 3.75\)

So the answer is NO

Answer:

l think he used three which is the diameter as the radius instead of dividing it by two................

In the given situation (D) randomized block design was used to experiment with incorporating randomization into this study.

An experimental design known as a randomized block design divides the experimental units into units known as blocks.

The experimental units inside each block are assigned the treatments at random.

We have a fully randomized block design when each block has at least one instance of each treatment.

By ensuring that a crucial predictor of the outcome is fairly distributed amongst research groups to require them to be balanced, something that a completely randomized design cannot guarantee, a randomized block design differs from a completely randomized design.

Therefore, in the given situation (D) randomized block design was used to experiment with incorporating randomization into this study.

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Complete question:

R.A. Fisher, a famous statistician, describes a well-known design in his book, Design of Experiments. Five varieties of wheat were compared to determine which gave the highest yield in bushels per acre. Eight farms were available for planting. Each farm was divided into five plots. For each farm, the five varieties were randomly assigned to the five plots with one variety per plot. The varieties were planted on their assigned plots and their yields were measured and compared.

How was randomization incorporated into this study?

A. All five varieties were randomly assigned to the five plots at each farm.

B. The five varieties were randomly assigned to the eight farms - three varieties were planted twice and two varieties only once.

C. It was not incorporated. The wheat seeds were not randomly selected from the population of wheat seeds.

D. Experiment - randomized block design

Answer:

Step-by-step explanation:

The interval (-U(ₙ), a=U(ₙ)) is a (1 - a) level confidence interval for 0, where U(ₙ) represents the maximum value among U₁, U₂, ..., Uₙ, and a = U(ₙ) represents the upper bound of the interval.

What is the confidence interval?

A confidence interval is a range of values that is likely to contain the true value of an unknown population parameter, such as the population mean or population proportion. It is based on a sample from the population and the level of confidence chosen by the researcher.

To show that the interval (-U(ₙ), a=U(ₙ)) is a (1 - a) level confidence interval for 0, we need to demonstrate that it has the property that the probability that 0 is contained within the interval is equal to (1 - a).

Let's proceed with the proof:

Since U(1) is the minimum value among U₁, U₂, ..., Uₙ, we have:

P(U(1) > a) = P(min{U₁, U₂, ..., Uₙ} > a)

This is equivalent to all of the observations U₁, U₂, ..., Uₙ being greater than a:

P(U(1) > a) = P(U₁ > a, U₂ > a, ..., Uₙ > a)

Since the observations U₁, U₂, ..., Uₙ are independent and identically distributed from Uniform(0, θ), where θ > 0 is unknown, we have:

P(U(₁) > a) = P(U₁ > a) * P(U₂ > a) * ... * P(Uₙ > a)

Since each Ui is from Uniform(0, θ), the probability that Ui > a is given by:

P(Ui > a) = 1 - P(Ui ≤ a) = 1 - a/θ

Therefore, we can write:

P(U(₁) > a) = (1 - a/θ)ⁿ

Now, let's consider U(n), which is the maximum value among U₁, U₂, ..., Uₙ:

P(U(ₙ) ≤ a) = P(max{U₁, U₂, ..., Uₙ} ≤ a)

This is equivalent to all of the observations U₁, U₂, ..., Uₙ being less than or equal to a:

P(U(ₙ) ≤ a) = P(U₁ ≤ a, U₂ ≤ a, ..., Uₙ ≤ a)

Using the same reasoning as before, the probability that Ui ≤ a is given by:

P(Ui ≤ a) = a/θ

Therefore, we can write:

P(U(ₙ) ≤ a) = (a/θ)ⁿ

Now, let's compute the probability that 0 is contained within the interval (-U(ₙ), a=U(ₙ)):

P(-U(ₙ) ≤ 0 ≤ a=U(ₙ)) = P(Uₙ) ≥ 0 ≥ -U(ₙ)) = P(U(ₙ) ≥ 0) = 1 - P(U(ₙ) < 0)

Since U(ₙ) follows a Uniform(0, θ) distribution, the probability that U(ₙ) < 0 is 0.

Therefore, we have:

P(-U(ₙ) ≤ 0 ≤ a=U(ₙ)) = 1 - P(U(ₙ) < 0) = 1 - 0 = 1

Hence, the probability that 0 is contained within the interval (-U(ₙ), a=U(ₙ)) is 1.

To complete the proof, we need to show that the probability that 0 is contained outside this interval is equal to a:

P(0 ≤ -U(ₙ) or a=U(ₙ)) = P(U(ₙ) ≤ 0 or a ≤ U(ₙ)) = P(U(ₙ) ≤ 0) + P(a ≤ U(ₙ))

Since U(ₙ) follows a Uniform(0, θ) distribution:

P(U(ₙ) ≤ 0) = 0 (since U(n) is always positive)

P(a ≤ U(ₙ)) = (a/θ)ⁿ

Therefore, we have:

P(0 ≤ -U(ₙ) or a=U(ₙ)) = P(U(ₙ) ≤ 0) + P(a ≤ U(ₙ)) = 0 + (a/θ)ⁿ

Since we want to show that this probability is equal to a, we need to equate it to a:

(a/θ)ⁿ = a

Taking the n-th root of both sides, we have:

(a/θ) = √[a]

Simplifying further, we get:

θ = a/√[a]

Therefore, the value of θ that satisfies this equation is θ = a/√[a].

Now, let's compute the confidence level associated with the interval (-U(ₙ), a=U(ₙ)).

The confidence level is defined as 1 minus the probability that the interval does not contain the true value of 0:

Confidence level = 1 - P(0 ≤ -U(ₙ) or a=U(ₙ))

= 1 - (a/θ)ⁿ

= 1 - (a/(a/√[a]))ⁿ

= 1 - (√[a])ⁿ

= 1 - aⁿ

We know that the confidence level should be equal to (1 - a) since it is a (1 - a) level confidence interval. Equating the two, we have:

1 - aⁿ = 1 - a

Simplifying, we get:

aⁿ = a

Since a is in the range (0, 1), we can conclude that this equation holds for any a in that range.

Therefore, the interval (-U(ₙ), a=U(ₙ)) is a (1 - a) level confidence interval for 0, where U(ₙ) represents the maximum value among U₁, U₂, ..., Uₙ and a = U(ₙ) represents the upper bound of the interval.

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(a) The variable educ might be endogenous

(b) The variable brthord is birth order (one for the first-born child, two for a second-born child and so on) could be used as an instrument for educ in equation

a) The variable instruction might be endogenous because as compensation increases the income expansions which additionally make able to an individual more educating himself. So there is an opportunity for the instruction might be an endogenous variable.

The indigeneity may involve the 32 the coefficient of knowledge as well different variables like married, black, south, urban, etc.

b) There is a substantial high relationship exists between birth order and the status of teaching. it is more possible to have higher schooling with less the order of child-born and the birth order is autonomous of the error term as well with wage. So the variable "birth order" is a good variable to use as an agency for the endogenous variable instruction.

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Answer:

look at the screenshot

Step-by-step explanation:

Answer:

19.2

Step-by-step explanation:

Take note:

a = edge

v = volume

Equations for a Cube

\(v=a^{3}\)

\(a=v^{\frac{1}{3} }\)

We are given V. Plug 7,077.888 into the second equation.

\(a=7077.888^{\frac{1}{3} }\)

\(a=19.2\)

Answer:

s =$10, l = 15, together they are $25

Step-by-step explanation:

Alberto: 1s + 1l = 25

Kali: 3s + 9l = 165

Multiply Alberto x 3: 3s + 3l = 75

Subtract from Kali:

 3s + 9l = 165

- 3s + 3l = 75

         6l = 90

l = 15, Large = $15.

Substitute into one of the equations: s + l = 25

s + 15 = 25

s = 10

Answer:

D. 40 dimes and 20 quarters

Step-by-step explanation:

40 dimes= $4 because 10 dimes= $1

20 quarters= $5 because 4 quarters= $1

The other options are above $10. I hope this helps!!!! :D

From the given equation y = 30(0.92)d, she should expect 193 phone calls after a week.

An algebraic expression is a number, variable, or the combination of both and operational symbols. On the other hand, an equation is the equality of two expressions separated by "="..

If the number of phone calls she should expect can be represented by the equation y = 30(0.92)d, where y is the number of phone calls after d days, then we can calculate the expected amount phone calls after a week.

To determine how much phone calls she should expect after a week, substitute the value of d.

y = 30(0.92)d

where d = 1 week = 7 days

y = 30(0.92)(7)

y = 193.2

Rounding off to the nearest whole number,

y = 193

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Answer:

the fee at sunset bank will always be more than fee at Oceanview bank.

Answer:

D

Step-by-step explanation:

i got it correct and go to k-12

Question:

A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by h(t)=-16t^2+80t+5, where t is measured in seconds.  Write an equation to determine how long it will take for the ball to reach the ground.

Answer:

\(t = 5.0625\)

Step-by-step explanation:

Given

\(h(t)=-16t^2+80t+5\)

Required

Find t when the ball hits the ground

This implies that h(t) = 0

So, we have:

\(0=-16t^2+80t+5\)

Reorder

\(-16t^2+80t+5 = 0\)

Using quadratic formula, we have:

\(t = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}\)

Where

\(a = -16\)      \(b =80\)      \(c = 5\)

So, we have:

\(t = \frac{-80\±\sqrt{80^2 - 4*-16*5}}{2*-16}\)

\(t = \frac{-80\±\sqrt{6400 +320}}{-32}\)

\(t = \frac{-80\±\sqrt{6720}}{-32}\)

\(t = \frac{-80\±82.0}{-32}\)

This gives:

\(t = \frac{-80+82.0}{-32}\) or \(t = \frac{-80-82.0}{-32}\)

\(t = \frac{2}{-32}\) or \(t = \frac{-162}{-32}\)

\(t = -\frac{2}{32}\) or \(t = \frac{162}{32}\)

But time can not be negative.

So, we have:

\(t = \frac{162}{32}\)

\(t = 5.0625\)

Hence, time to hit the ground is 5.0625 seconds

The correct answer is D. setne 23 47. Based on the provided information, I understand that you have a comparison function in C code and its corresponding assembly code. You are asked to fill in the blanks by selecting the appropriate instructions based on the given values of a and b and the status flags SF, OF, ZF, and CF. Let's go through the options:

A. setg 47 23: This option is incorrect because setg is used to set a byte to 1 if the Greater flag (ZF=0 and SF=OF) is set, but the given values of a and b are 47 and 23, respectively, so it does not satisfy the condition for setg to be set.

B. setl 23 47: This option is incorrect because setl is used to set a byte to 1 if the Less flag (SF≠OF) is set, but the given values of a and b are 23 and 47, respectively, so it does not satisfy the condition for setl to be set.

C. sete 23 23: This option is incorrect because sete is used to set a byte to 1 if the Zero flag (ZF=1) is set, but the given values of a and b are 23 and 23, respectively, so it does not satisfy the condition for sete to be set.

D. setne 23 47: This option is correct. setne is used to set a byte to 1 if the Zero flag (ZF=0) is not set, which means the values of a and b are not equal. In this case, the given values of a and b are 23 and 47, respectively, so they are not equal, and setne should be used.

Therefore, the correct answer is D. setne 23 47

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Answer:

Carter's bedroom

Step-by-step explanation:

Carley's bedroom :12.3 x 6.9 = 84.87 sq feet

Carter's bedroom : 10.4 x 8.2 = 85.28 sq feet

Answer:

Step-by-step explanation:

Carley's bedroom :12.3 x 6.9 = 84.87 sq feet

Carter's bedroom : 10.4 x 8.2 = 85.28 sq feet

Step-by-step explanation:

1)

imagine the trapezoid standing upright (90°) turned.

then the top and bottom lines are parallel, and the 15 side is with its double right angles the height of the trapezoid.

in general, the area of such a trapezoid is

(top + bottom)/2 × height

in our case that is

(3 + 4)/2 × 15 = 7/2 × 15 = 3.5 × 15 = 52.5 units²

2)

this is basically the sum of the lower rectangle and the upper trapezoid.

the area of the lower rectangle is

58×15 = 870 mm²

the area of the upper trapezoid is (the same formula as before)

(47 + 58)/2 × (21 - 15) = 105/2 × 6 = 52.5 × 6 = 315 mm²

so, the total area is

870 + 315 = 1,185 mm² = 1,185.0 mm²

The quadratic function will be f(x) = 2\(x^{2}\) + 4x + 15

General equation of quadratic is

f(x) = a\(x^{2}\) + bx + c

and Standard form is

f(x) =a \((x-h)^{2}\) + k

where h , k are coordinates of vertex

and x , y represent some point on the graph.

By replacing f(x) with y in standard equation we get

y = a\((x-h)^{2}\) + k

Put value of x , y , h , k from the graph.

h = -2

k = 7

x = 0

y = 9

9 = a (4) + 7

a = 2

Now put value of a in standard equation

f(x) = 2 \((x + 2)^{2}\) + 7

f(x) = 2\(x^{2}\) + 4x + 15

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Answer:

The amount invested at an 8% rate would be $184

The amount invested at a 3% rate would be $69

Step-by-step explanation:

The amount invested at an 8% rate would be $184 because 2,300 x 0.08 (8% in a decimal form) x 1 (since it was after 1 year) would come to 184.

The amount invested at an 3% rate would be $69 because 2,300 x 0.03 (3% in a decimal form) x 1 (since it was after 1 year) would come to 69.

The probability that can be chosen by Jake will be 33.5%.

The area of the whole dartboard will be:

= πr²

where r will be:

= 3 + (4 × 4)

= 3 + 16

= 19

Area = π(19)² = 361π²

The area of 30, 40, and 50 points will be:

= π × [3 + (2 × 4)]²

= 121π²

The probability will be:

= (361π - 121π) × 100

= 33.5%

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The system of equations can be graphed using a graphing utility to find their intersection point, which represents the solution to the system.

To graph the system of equations, we first need to rearrange them in slope-intercept form, which is y = mx + b. For the first equation, we can solve for y by subtracting 2x from both sides and then dividing by -4, which gives us y = -0.5x + (5/4). For the second equation, we can solve for y by dividing both sides by -1.2 and then simplifying, which gives us y = -0.5x + (5/8). We can then enter these equations into a graphing utility, such as Desmos or GeoGebra, to plot their graphs. The intersection point of the two graphs represents the solution to the system. In this case, the intersection point is (4.4, 1.3), which means that x = 4.4 and y = 1.3 is the solution to the system of equations.

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The fair swap rate should be not lower than 5.5%.The quoted swap rate of 5.5% on a 3-year fixed-for-floating swap is not fair. To determine the fair swap rate,

we need to calculate the present value of the fixed and floating rate cash flows and equate them. By using the given spot rates, the fair swap rate is found to be lower than 5.5%.

In a fixed-for-floating interest rate swap, one party pays a fixed interest rate while the other pays a floating rate based on market conditions. To determine the fair swap rate, we need to compare the present values of the fixed and floating rate cash flows.

Let's assume that the notional amount is $1.

For the fixed leg, we have three cash flows at rates of 5.5% for each year. Using the spot rates, we can discount these cash flows to their present values:

PV_fixed = (0.055 / (1 + 0.04)) + (0.055 / (1 + 0.05)^2) + (0.055 / (1 + 0.06)^3).

For the floating leg, we have a single cash flow at the 3-year spot rate of 6%. We discount this cash flow to its present value:

PV_floating = (0.06 / (1 + 0.06)^3).

To find the fair swap rate, we equate the present values:

PV_fixed = PV_floating.

Simplifying the equation and solving for the fair swap rate, we find:

(0.055 / (1 + 0.04)) + (0.055 / (1 + 0.05)^2) + (0.055 / (1 + 0.06)^3) = (0.06 / (1 + fair_swap_rate)^3).

By solving this equation, we can determine the fair swap rate. If the calculated rate is lower than 5.5%, then the quoted swap rate of 5.5% is not fair.

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Answer:

770

Step-by-step explanation:

So start by adding 140 + 70 and then you get 210 and then so you muliply 70*11 and you get 770.      :D

Answer:

The market equilibrium price is approximately $36.43 per barrel.

Step-by-step explanation:

To find the market equilibrium price, we need to set the quantity supplied (QS) equal to the quantity demanded (QD) and solve for the price (P).

Given:

QS = -250 + 7P

QD = 260 - 7P

Setting QS equal to QD:

-250 + 7P = 260 - 7P

Now, let's solve for P:

Add 7P to both sides:

-250 + 7P + 7P = 260 - 7P + 7P

Combine like terms:

14P - 250 = 260

Add 250 to both sides:

14P - 250 + 250 = 260 + 250

Simplify:

14P = 510

Divide both sides by 14:

14P/14 = 510/14

Simplify:

P = 36.43

The market equilibrium price can be found by setting the quantity supplied (QS) equal to the quantity demanded (QD) and solving for the price (P) that satisfies this condition.

In the given scenario, the supply function is QS = -250 + 7P, and the demand function is QD = 260 - 7P. To find the equilibrium price, we set QS equal to QD:

-250 + 7P = 260 - 7P

Simplifying the equation, we get:

14P = 510

Dividing both sides by 14, we find:

P = 36.43

Therefore, the market equilibrium price is approximately $36.43 per barrel. At this price, the quantity supplied and quantity demanded will be equal, resulting in a state of equilibrium in the perfectly competitive domestic crude oil market.

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Answer:

48

Step-by-step explanation:

1) 9*8=72

2) 8*3=24

3)72-24=48

Answer:

It takes the toy train 36 minutes to travel 100 yards.

Step-by-step explanation:

100 yards = 300 feet

300 / (divided by) 25 = 6

meaning 300 = 25 x 6

So: 6 x 6 = 36 minutes

(sorry if this was confusing, I'm not the best at explanations lol)

Answer:

384 inches per sec^2

Step-by-step explanation:

What we need to do here is a conversion.

We shall be converting from ft per sec^2 to inches per sec^2

The key to answering this question is to know that 12 inches = 1 feet

So the only conversion necessary here is to convert 32 inches to feet

Thus, that would be 32 * 12 = 384 inches per sec^2

Answer:

384 inches per second squared

Step-by-step explanation:

Just took the test