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An object has a mass of 3.8 kg and a force of 11.6 N is applied to it. What is the acceleration that results?

To convert watts to joules, we can use Formula: Energy (joules) = Power (watts) x Time (seconds)

Watts and joules are both units of energy, but they measure different things. Watts are a unit of power, which is the rate at which energy is transferred or used, while joules are a unit of energy itself. To convert watts to joules, you need to know the time over which the power is being used.

The formula for converting watts to joules is:

Energy (joules) = Power (watts) x Time (seconds)

For example, if you have a 100-watt light bulb that is turned on for 5 seconds, the amount of energy used by the light bulb can be calculated as:

Energy (joules) = 100 watts x 5 seconds = 500 joules

In other words, the light bulb used 500 joules of energy during the 5 seconds it was turned on.

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Answer:

An electron added to a noble gas must go in the next higher energy level. The periodic trend for electron affinity values is not as consistent as for other trends.

Answer:

It helps melt the ice away on their walkway.

Explanation:

The salt makes the ice to freeze at a lower temperature. So when a solute (salt) comes into contact with the ice the freezing point is lowered.

the answer is 25 newtons

The maximum force transmitted to the ground through the spring is 2150.9 + 86.117 Cos40t,  through the dashpot is 0, and  through the spring and dashpot together is 2150.9 + 86.117 Cos40t

Maximum force transmitted to the ground through the spring:When the engine is at the highest position, the spring will be fully compressed.

At this point, the spring will exert the maximum force, F1.Force, F1 = m g + m aWhere,m = mass of the engine = 200 kgg = acceleration due to gravity = 9.81 m/s²a = acceleration of the engine = (80 Cos40t)/m= (80 Cos40t)/200a = 0.4 Cos40tF1 = 200 × 9.81 + 200 × 0.4 Cos40t= 200 × (9.81 + 0.4 Cos40t)= 2150.9 + 86.117 Cos40t

Maximum force transmitted to the ground through the dashpot:Force, F2 = 480vWhere, v = velocity of the engine = 0 at maximum height reached by the engine.F2 = 480 × 0= 0

Maximum force transmitted to the ground through the spring and dashpot together:Maximum force transmitted to the ground through the spring and dashpot together will be the sum of F1 and F2.Force, F = F1 + F2= 2150.9 + 86.117 Cos40t + 0= 2150.9 + 86.117 Cos40tThus, the maximum force transmitted to the ground

through the spring is 2150.9 + 86.117 Cos40t,  through the dashpot is 0, and  through the spring and dashpot together is 2150.9 + 86.117 Cos40t.

Given data,Vertical unbalanced force acting on single cylinder engine, F = 80 Cos40tMass of the engine, m = 200 kgSpring stiffness, k = 300 KN/mForce exerted by dashpot, F2 = 480v.

The maximum force transmitted to the ground through the spring, F1 is: F1 = m g + m a = 200 × (9.81 + 0.4 Cos40t) = 2150.9 + 86.117 Cos40t.

The maximum force transmitted to the ground through the dashpot, F2 is: F2 = 480 × 0 = 0The maximum force transmitted to the ground through the spring and dashpot together is: F = F1 + F2 = 2150.9 + 86.117 Cos40t + 0 = 2150.9 + 86.117 Cos40t

In a single cylinder engine, the force transmitted to the ground can be calculated by using the spring system of stiffness and dashpot. In this question, it has been mentioned that a single cylinder engine has a vertical unbalanced force of 80 Cos40t.

Also, the engine weighs 200 kg and is supported by a spring system of stiffness 300KN/m and a dashpot which gives a force of 480v N for a vertical velocity of v m/sec.

This question requires us to calculate the maximum force transmitted to the ground through the spring, dashpot, and spring and dashpot together.

The maximum force transmitted to the ground through the spring will be fully compressed when the engine is at the highest position.

The spring will exert the maximum force, which can be calculated by the formula F1 = m g + m a. By substituting the given values, we get F1 = 2150.9 + 86.117 Cos40t.

The maximum force transmitted to the ground through the dashpot can be calculated by the formula F2 = 480v. As v = 0 at maximum height reached by the engine, F2 will be 0.

The maximum force transmitted to the ground through the spring and dashpot together will be the sum of F1 and F2, which will be equal to 2150.9 + 86.117 Cos40t

Thus, the maximum force transmitted to the ground  through the spring is 2150.9 + 86.117 Cos40t, through the dashpot is 0, and through the spring and dashpot together is 2150.9 + 86.117 Cos40t.This calculation gives us the amount of force that needs to be transmitted to the ground by the spring system and dashpot, which helps in designing the engine and ensuring that the ground can bear the force. In conclusion, the maximum force transmitted to the ground can be calculated using spring stiffness and dashpot.

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Answer:

A

Explanation:

Constant speed (without change in direction) is not accelerating. If you are slowing down, speeding up, or changing direction, you are accelerating

Answer:

Yellow

Explanation:

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Three different alloys used in home are brass, bronze and copper. Brass and bronze are used for utensils and copper is used in the electrical circuits.  

Alloys are the homogeneous mixture of metal mixed with metal or non metal. These alloys can't be separated by physical methods.            

The alloy brass and bronze are used for utensils and copper is used in the electrical circuits.                                                                                                                        

The properties of the alloys make it suitable for that application is the electrical conductivity and their melting point.

Brass and Bronze are bad conductors of electricity. On the other side, copper is used in electrical circuits.

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For a water droplet with a radius of 0.018 mm to remain stationary in the air, it must have an excess of electron charges equal to 4.05 x 10⁴ C.

A water droplet of radius 0.018 mm remains stationary in the air due to the downward-directed electric field of the earth. To determine how many excess electrons charges the water droplet must have, we can use the equation for the force on a charged particle in an electric field:

                                                  F = qE

Where F is the force on the charged particle, q is the charge of the particle, and E is the electric field. We are given the electric field (E) and the radius of the water droplet (r), so we can use the equation for the force of gravity on the water droplet to find the force (F):

                                                   F = mg

Where m is the mass of the water droplet and g is the acceleration due to gravity. The mass of the water droplet can be found using the equation for the volume of a sphere and the density of water:

V = (4/3)πr³
m = ρV

Substituting the equations for V and m into the equation for F gives:
F = (4/3)πr³ρg

Setting the two equations for F equal to each other and solving for q gives:
q = (4/3)πr³ρg/E

Plugging in the given values for r, ρ, g, and E gives:
q = (4/3)π(0.018 mm)³(1000 kg/m³)(9.8 m/s²)/(150 N/C)
q = 6.48 x 10⁻¹⁵ C

To find the number of excess electron charges, we can divide the charge of the water droplet by the charge of a single electron:

                                                                        n = q/e

Where n is the number of excess electron charges, q is the charge of the water droplet, and e is the charge of a single electron. Plugging in the values for q and e gives:
n = (6.48 x 10⁻¹⁵ C)/(1.6 x 10⁻¹⁹ C)
n = 4.05 x 10⁴ C

Therefore, the water droplet must have 4.05 x 10⁴ C excess electron charges to remain stationary in the air.

Your question is incomplete but most probably your full question was:

A water droplet of radius 0.018 mm remains stationary in the air. If the downward directed electric field of the Earth is 150 N/C, how many electron charges must the water droplet have?

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Answer:

a. temperature of the substance increases.

Explanation:

Temperature is defined as a measure of the average kinetic energy of a substance, so as one rises, so will the other. They are directly proportional.

As the kinetic energy of the molecules in a substance increases, the temperature of the substance is also increases because kinetic energy and temperature is proportional to each other.

Kinetic energy is directly related to temperature which means if kinetic energy is increased, the temperature of the solution is also increased and vice versa.

So we can conclude that As the kinetic energy of the molecules in a substance increases, the temperature of the substance is also increases because kinetic energy and temperature is proportional to each other.

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(a) The magnetic force experienced by the wire when it perpendicular is 0.01 N.

(b) The magnetic force experienced by the wire when the angle is  30⁰ is 5 x 10⁻³ N.

(c) The magnetic force experienced by the wire when it parallel is 0 N.

The magnetic force experienced by the wire is calculated by applying the following;

F = BIL x sin(θ)

where;

When the angle of inclination is perpendicular,  

F = 1 x 10⁻² x 10 x 0.1 x sin(90)

F = 0.01 N

When the angle of inclination is 30⁰,

F = BIL x sin(θ)

F = 1 x 10⁻² x 10 x 0.1 x sin(30)

F = 5 x 10⁻³ N

When the wire is parallel, the angle is 0⁰,

F = BIL x sin(θ)

F = 1 x 10⁻² x 10 x 0.1 x sin(0)

F = 0 N

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Answer:

Explanation:

initial velocity u = 54 km/h = 15 m/s

final velocity v = 18 km/h = 5 m/s

distance s = 10 m

1. v^2 = u^2 + 2as

5^2 = 15^2 + 2a × 10

25 = 225 + 20a

25 - 225 = 20a

20 a = -200

a = -200/2

a = -100m/s^2

∴Deacceleration = -100m/s^2

2. v = u + at

5 = 15 -100t

5-15 = -100t

-10 = -100t

t = 100 / 10

∴t = 10 sec

Total distance covered by the car 10 m

To me, the hardest part of this whole thing is keeping the units straight.  We're starting out with information given to us in kilometers, hours, and meters, and we have to come up with answers in m/s² , seconds, and meters.

When I worked this problem, I jumped right in without thinking, and I immediately got bogged down when I had to go off to the side and convert some units.

Now I know better.  THIS time, before we get all tangled up trying to solve anything, let's get clever and change everything to m/s right now !

(54 km/hour) · (1,000m/km) · (1 hour/3600 sec)  =  15 meters/second

(18 km/hour) · (1,000 m/km) · (1 hour/3600 sec) = 5 meters/second

NOW I'll betcha it's gonna be about 70% faster and easier !

i). Acceleration = (change in speed / time for the change)

We know the distance, but not the time.  I know there's a formula for it, but I've learned so many formulas during my lifetime that I can't remember ALL of them.  So I just memorize some of them, and I work things out from the formulas that I know.  Here's how I do time:)

Average speed during the given slow-down = (1/2)·(15+5) = 10 m/s

Distance covered during the given slow-down = 10 m.

Time = (distance) / (average speed) = (10m) / (10 m/s) = 1 second

Acceleration = (change in speed) / (time for the change)

Acceleration = (5 m/s - 15 m/s) / (1 second)

Acceleration = (-10 m/s) / (1 second)

Acceleration = -10 m/s²   (or 'Deceleration' = 10 m/s² )

_____________________________________________

For parts ii). and iii)., there's a big shift in the question.

It only gave you the slow-down from 54 to 18 km/hr for the purpose of calculating the deceleration.  NOW, for the rest of the answers, it's talking about a complete stop ... 0 m/s .

____________________________________________

ii). Time required to stop = (initial speed) / (deceleration)

Time to stop from 54 km/hr = (15 m/s) / (10 m/s²)

Time to stop = 1.5 seconds

iii).  Distance covered = (average speed) · (time to stop)

Distance covered = (7.5 m/s) · (1.5 sec)

Distance covered = 11.25 meters

OR ... use the official formula:

Distance = (1/2) · (acceleration) · (time² )

Distance = (1/2) · (10 m/s²) · (1.5 sec)²

Distance = 11.25 meters           yay !

The statement (each different signal in a 1H NMR spectrum represents a different hydrogen atom. hydrogen atoms that give the same signal) is false because each different signal in a 1H NMR spectrum represents a different set of hydrogen atoms, not necessarily a single hydrogen atom.

Hydrogen atoms that are chemically equivalent, such as those in the same functional group or environment, give the same signal.

In addition to its use in identification, nuclear magnetic resonance (NMR) spectroscopy can provide in-depth knowledge about the structure, dynamics, reaction state, and chemical environment of molecules. Proton and carbon-13 NMR spectroscopy are the most popular forms of nuclear magnetic resonance (NMR), however, this technique can be applied to any kind of sample that has nuclei that have spin.

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Platelets, also known as thrombocytes, are one of the formed elements of the blood.

They differ in structure from the other formed elements, which include red blood cells (erythrocytes) and white blood cells (leukocytes). Here's a step-by-step explanation of how platelets differ in structure:
Size and shape: Platelets are much smaller than red and white blood cells. They are disc-shaped and irregular in shape, resembling small fragments or shards.
Lack of nucleus: Unlike red and white blood cells, platelets lack a nucleus. This allows them to have more space for their essential components, such as enzymes and proteins involved in clotting.
Cytoplasmic granules: Platelets contain numerous cytoplasmic granules that are involved in various functions. These granules contain substances such as clotting factors, growth factors, and enzymes that help in the formation of blood clots and promote wound healing.
Formation: Platelets are formed from large precursor cells called megakaryocytes in the bone marrow. These megakaryocytes release fragments of their cytoplasm into the bloodstream, which then become platelets.
Platelets differ in structure from other formed elements of the blood due to their small size, irregular shape, lack of a nucleus, and the presence of cytoplasmic granules. These unique characteristics enable platelets to play a crucial role in clotting and wound healing processes.
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E_total(θ) = Σ (Eθ e^(j(kd(i-1)cos(θ) + βi)))
This expression represents the total radiated field of the array, considering the individual contributions from horizontally polarized dipole elements with the given electric field Eθ and taking into account their positions and phase shifts within the array.

To find the expression for the total radiated field of the array, we need to consider the individual contributions of each dipole element in the array and sum them up. Since the antenna elements are horizontally polarized dipoles, we can express the radiated electric field Eθ for a single dipole as:

Eθ = âθ jµ (kIol / 4πr) e^(-jkr) |cos θ|

Here, âθ represents the unit vector in the θ direction, j is the imaginary unit, µ is the permeability, k is the wave number, Iol is the current at the location of the dipole, r is the distance from the dipole, and θ is the angle between the observation point and the dipole axis.

Now, we need to consider an array of N dipoles, each with its own location and phase shift. For simplicity, let's assume that all dipoles have the same current amplitude I0 and are uniformly spaced with a distance d along the x-axis.

To find the total radiated field for the array, we need to sum the contributions of each dipole element:

E_total(θ) = Σ E_i(θ)

where E_i(θ) is the radiated field of the i-th dipole, and the summation goes from i=1 to N.

For each dipole in the array, we need to account for the phase shift due to its position along the x-axis and the additional phase shift βi introduced by the array feeding network:

E_i(θ) = Eθ e^(j(kd(i-1)cos(θ) + βi))

So, the total radiated field of the array is given by:

E_total(θ) = Σ (Eθ e^(j(kd(i-1)cos(θ) + βi)))

This expression represents the total radiated field of the array, considering the individual contributions from horizontally polarized dipole elements with the given electric field Eθ and taking into account their positions and phase shifts within the array.

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Answer:

Explanation:

Quantum mechanics tells us that light can behave simultaneously as a particle or a wave. However, there has never been an experiment able to capture both natures of light at the same time; the closest we have come is seeing either wave or particle, but always at different times.When UV light hits a metal surface, it causes an emission of electrons. Albert Einstein explained this "photoelectric" effect by proposing that light – thought to only be a wave – is also a stream of particles

Why is light considered a wave and a particle?

Light behaves mainly like a wave but it can also be considered to consist of tiny packages of energy called photons. Photons carry a fixed amount of energy but have no mass. They also found that increasing the intensity of light increased the number of electrons ejected, but not their speed

1. An example of a flow driven by a horizontal pressure gradient that isn't caused by buoyancy differences is the wind.

2. An example of a large-scale flow in the ocean that is density-driven is the thermohaline circulation, also known as the global conveyor belt.

3. Density-driven or baroclinic flows refer to smaller-scale flows that arise from density differences within a fluid.

1. An example of a flow driven by a horizontal pressure gradient that isn't caused by buoyancy differences is the wind. Wind is the movement of air driven by differences in atmospheric pressure. The horizontal pressure gradient force acts to balance pressure differences, causing air to flow from areas of higher pressure to areas of lower pressure. This movement is not directly related to buoyancy differences but rather the pressure variations in the atmosphere.

2. An example of a large-scale flow in the ocean that is density-driven is the thermohaline circulation, also known as the global conveyor belt. This circulation is driven by differences in water density due to temperature and salinity variations. Cold, dense water sinks in certain regions (such as the North Atlantic), initiating a slow, deep current that transports water masses across vast distances and depths. This circulation plays a crucial role in global heat distribution and nutrient transport.

3. The difference between the density-driven flow in the ocean (such as thermohaline circulation) and a density-driven or baroclinic flow lies in their scales and driving mechanisms. Density-driven flows like thermohaline circulation operate on large scales and are driven by differences in water density due to temperature and salinity variations. These flows involve slow, deep currents that transport water masses over long distances and depths.

On the other hand, density-driven or baroclinic flows refer to smaller-scale flows that arise from density differences within a fluid. These flows typically occur in regions where there are gradients in density, temperature, or salinity. They often involve vertical motions and can be found in various oceanic and atmospheric phenomena, such as coastal upwelling, frontal systems, and eddies. Unlike the large-scale thermohaline circulation, these flows are more localized and occur in specific regions where density gradients exist.

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Answer:

YES

Explanation:

The dependent variable is the variable that is being measured or tested in an experiment. For example, in a study looking at how tutoring impacts test scores, the dependent variable would be the participants' test scores, since that is what is being measured

Answer:

You do measure a dependent variable

Answer:

A

Explanation:

change in direction ,velocity stays the same

Explanation:

The question is not complete, here is the complete question

"Beatrice and the Elevator Beatrice, a middle school student, is visiting a very tall office building and notices that she feels heavier when the elevator car is traveling up and lighter when the elevator car is traveling down. After making these observations, Beatrice comes back to the building and stands on a bathroom scale that measures her weight as she travels up and down in the elevator.

1. . What question is Beatrice trying to answer?

2. What is one variable Beatrice could change in her investigation? What might she figure out if this

variable was changed"

1. Beatrice is trying to observe the influence of the elevator movement on her weight, Hence the question is "will the elevator  movement cause her weight to change"

therefore moving upward the reading on the scale will increase

Reading=mg+ma

downward

Reading will reduce

Reading=mg-ma

2. The independent variable is the acceleration due to gravity g=9.81m/s^2

while the dependent variables are

    i. The elevators acceleration

    ii. Beatrice's mass

The maximum acceleration a car can undergo if the coefficient of static friction between the tires and the ground is 0.90 is 8.82 m/s2.

The maximum acceleration a car can undergo if the coefficient of static friction between the tires and the ground is 0.90 can be calculated using the equation of static friction:

Fs = μs * FN

Where Fs is the force of static friction, μs is the coefficient of static friction, and FN is the normal force.

Since the car is on a horizontal surface, the normal force is equal to the weight of the car:

FN = m * g

Where m is the mass of the car and g is the acceleration due to gravity.

Substituting this into the equation for static friction gives:

Fs = μs * m * g

Since the force of static friction is also equal to the maximum force that can be applied to the car before it begins to slip, this equation can be rearranged to find the maximum acceleration:

Fs = m * amax

μs * m * g = m * amax

amax = μs * g

Plugging in the given value for the coefficient of static friction gives:

amax = 0.90 * g

amax = 0.90 * 9.8 m/s2

amax = 8.82 m/s2
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A liquids resistance to flow is called Viscosity

A phase change from the liquid phase to the vapour phase is called vaporisation (or vaporisation) of an element or molecule. Both evaporation and boiling result in vaporisation. Boiling is a bulk phenomenon, whereas evaporation is a surface phenomenon.

vaporisation is the process by which a material is transformed from its liquid or solid state into its gaseous (vapour) state. Boiling is the term for the vaporisation process when circumstances permit the creation of vapour bubbles within a liquid.

Evaporation is a typical process that takes place when a liquid transforms into a gas while raising the temperature or pressure. Boiling is an unnatural process in which the liquid is continuously heated to a point where it vaporises.

The transformation of a liquid into a gas is known as vaporisation.

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Answer:

O Intense rain or an earthquake

Explanation:

Landslides can be initiated in slopes already on the verge of movement by rainfall, snowmelt, changes in water level, stream erosion, changes in ground water, earthquakes, volcanic activity, disturbance by human activities, or any combination of these factors.

Intense rain or an earthquake can trigger a landslide.

In conclusion, intense rain or an earthquake can trigger a landslide.

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The displacement of the particle for the time interval from t = 0 s to t = 4 s is 16 m in the positive x-direction (i). The correct option is 16i m.

To calculate the displacement of the particle for the given time interval, we need to find the difference in position between the initial time (t = 0 s) and the final time (t = 4 s).

Given the position equation x = t^3 - 3t^2 - 5, we can substitute the initial and final times to find the corresponding positions:

Initial position (t = 0 s):

x_initial = (0^3 - 3(0^2) - 5) m

x_initial = -5 m

Final position (t = 4 s):

x_final = (4^3 - 3(4^2) - 5) m

x_final = (64 - 48 - 5) m

x_final = 11 m

The displacement of the particle is the difference between the final and initial positions:

Displacement = x_final - x_initial

Displacement = 11 m - (-5 m)

Displacement = 16 m

Therefore, the displacement of the particle for the time interval from t = 0 s to t = 4 s is 16 m in the positive x-direction (i).

The correct option is 16i m.

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Energy cannot be generated or destroyed; it can only be changed from one form of energy to another, according to the rule of conservation of energy. This implies that a system always possesses the same amount of energy, barring external energy addition.

According to the rule of conservation of energy, energy cannot be generated or destroyed. It can only be changed from one form to another, though. It is simply changed from a form that we can use to one that is less useful. Energy problem as a result of this

Energy efficiency is necessary to save expenses and extend the life of the resources.

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Answer:

Between 23,000 to 54,000 Hz

If you were to shoot lasers directly forward from your eyes, the lasers would be traveling anteriorly along the sagittal plane.

The sagittal plane is one of the anatomical planes that divides the body into left and right portions. It is a vertical plane that runs from the front (anterior) to the back (posterior) of the body. When the lasers are projected forward from your eyes, they would be moving in the anterior direction, aligning with the sagittal plane.

The lasers would be parallel to the sagittal plane, allowing them to travel forward while maintaining their alignment with the body's midline, which is a characteristic of the sagittal plane.

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The speed at the bottom of the incline is  6.87 m per second.

The conservation of the energy is a fundamentally law of physics, chemistry stating that the total of the energy of an isolated by the system is constant despite internally changes. It is mostly common expressed as “energy can neither to be created nor destroyed”, and it is the basis of the first-ever law of the thermodynamics.

As per the given question

The length of the inclined plane L= 8.00m

angle of inclination is = 37°

Height of the inclined plane h= L sin ø

     (8.00m) sin 37°

     =4.814 m

Let's take m= mass of hoop

Let's take r=radius of hoop

Let's v be the velocity of the hoop bottom to the inclined plane.

Now we can apply conservation of energy at the top of the inclined plane  and at to the bottom of the inclined plane.

mgh = ¹/₂ mv²

mgh = ¹/₂ mv² + ¹/₂ Iω²

Where, I = moment of inertia

ω = angular velocity

I = L/ω

mgh = ¹/₂ mv² + ¹/₂ (L/ω)ω²

mgh = ¹/₂ mv² + ¹/₂ Lω

mgh = ¹/₂ mv² + ¹/₂ mvrω

ω = vr

mgh = ¹/₂ mv² + ¹/₂ mvrvr

gh = ¹/₂ v² + ¹/₂ (vr)²

gh = ¹/₂v² (1 + r²)

v=gh

v=√(9.8m/s^2)(4.814m)

v=6.87 m/s

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