help, fill in the bottom row, i’ll give you brainiest.

Yes, it is possible to use absolute value when subtracting two negatives and as such it does not only work when one number is negative.

When adding two negative numbers, add the absolute value of the numbers and keep the negative sign.

For example -1 + -2 = - (||-1| + |-2||), which is -(1 + 2) or -3

The absolute value when subtracting two negatives is -2¹/₂ - (-1²/₃) is possible because when subtracting, we will change the subtraction to addition and change the sign of the number being taken away.

Thus, we can conclude that it is possible to use absolute value when subtracting two negatives.

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The notation "m^2" is a shorthand way of saying "square meters".

Chances are you'll simply type in the number and leave out the units, as that's already taken care of.

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Work Shown:

area = base*height

area = 8*3

area = 24 square meters

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Explanation:

We simply multiply the base 8 and height 3 and that's our answer. It's not a trick question even if it might seem like it.

The side that's 7 meters long is never used. The base and height are always perpendicular to one another, which means that they form a right angle (aka 90 degree angle).

The area formula of a parallelogram and rectangle are the same. We can think of a non-rectangular parallelogram as a slanted rectangle in a sense. Imagine you had stacks of blocks to form a rectangle. Now imagine nudging that stack slightly to one side. The blocks themselves don't change, so the area of one wall doesn't change. All that's changed is the shape.

Answer:

10.6 inches squared

Step-by-step explanation:

P = 2(L + W)

P = 2( 1.4 + 3.9)

P = 2 x 5.3

P = 10.6 inches squared

Did u get your answer I really need this fast

Answer:

\(\displaystyle A=\frac{20}{3}\)

Step-by-step explanation:

\(\displaystyle A=\int^2_{-2}(|x|-(x^2-2))\,dx\\\\A=2\int^2_0(x-(x^2-2))\,dx\\\\A=2\int^2_0(-x^2+x+2)\,dx\\\\A=2\biggr(-\frac{x^3}{3}+\frac{x^2}{2}+2x\biggr)\biggr|^2_0\\\\A=2\biggr(-\frac{2^3}{3}+\frac{2^2}{2}+2(2)\biggr)\\\\A=2\biggr(-\frac{8}{3}+2+4\biggr)\\\\A=2\biggr(-\frac{8}{3}+6\biggr)\\\\A=2\biggr(\frac{10}{3}\biggr)\\\\A=\frac{20}{3}\)

Bounds depend on whether you use -x or +x instead of |x|, but you double regardless. See the attached graph for a visual.

Answer:

(A)Step 1; it should be m∠m + m∠n + m∠o = 180 degrees (sum of angles in a triangle)

Step-by-step explanation:

The steps followed by the student are:

Step 1: m∠m + m∠n + m∠p = 180 degrees (sum of angles of a triangle)

Step 2: m∠p + m∠o = 180 degrees (adjacent supplementary angles)

Step 3: Therefore, m∠m + m∠n + m∠o = m∠o + m∠p

Step 4: So, m∠m + m∠n = m∠p

We observe that the student made a mistake in Step 1, it should be m∠m + m∠n + m∠o = 180 degrees (sum of angles in a triangle).

p is outside the triangle, therefore it cannot form one of the angles in the triangle.

Answer:

well ages 5-8 a yo mama joke older just say the same thing to them over and over again or just dont talk to them

Step-by-step explanation:

The value of the functions at f(-4) = 21 and f(0) = 13.

To evaluate f(x)=-2x+13 for f(-4) and f(0), we need to substitute the values into the equation and solve:

f(-4) = -2(-4) + 13 = 8 + 13 = 21

f(0) = -2(0) + 13 = 13

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Option A correctly describes the area of the graph of the function.

How is an area of the graph calculated?

The area of a graph is the area under the function curve enclosed within the X-axis of the graph. Thus, it is the area of the figure formed by enclosing the function graph with the X-axis.

It is the integration of the function polynomial of the possible values of x that the function curve lies in.

Here the function equation is : \(f(x) = ( 25 - x^{2} )\)

From the figure, we can see that the value of x varies from -5 to 5.

Initial x-value of integration = minimum value of x

                                          = -5

Final x-value of integration = maximum value of x

                                          = 5

Thus, the area of the graph can be correctly calculated as. :

               \(Area = \int\limits^{maxX}_ {minX} \, f(x)dx\)

               \(Area = \int\limits^5_ {-5} \, (25-x^{2} )dx\)

Hence, Option A correctly calculates the area of the graph given.

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Answer:

The notation Σ-2 (3η + 5) is incorrect for representing the arithmetic series 8 + 11+ ... + 29.

The correct notation for the arithmetic series 8 + 11 + ... + 29 should be:

Σ_{i=1}^{11} (6i + 2)

The series has 11 terms, and each term can be found by adding 3 to the previous term, starting with the first term 8. Therefore, the general form of the series is 6i + 2, where i represents the index of the term in the series.

In contrast, the notation Σ-2 (3η + 5) appears to have multiple errors. The use of a negative index (-2) is not valid, as the index should start from 1 or 0. Also, the use of the Greek letter eta (η) instead of i as the index variable is unconventional and likely to cause confusion. Finally, the expression inside the parentheses does not appear to correspond to the terms of the arithmetic series.

The correct notation for the arithmetic series 8 + 11 + ... + 29 should be:

Σ_{i=1}^{11} (6i + 2)

To explain the error in the given notation Σ-2 (3η + 5), we can break it down as follows:

The use of a negative index (-2) is incorrect. The index of summation should always be a non-negative integer.

The use of the Greek letter eta (η) instead of i as the index variable is unconventional and may cause confusion or errors.

The expression inside the parentheses, 3η + 5, does not represent the terms of the arithmetic series. In particular, it does not involve the index variable i or the common difference 3.

Therefore, the correct notation for the given arithmetic series is Σ_{i=1}^{11} (6i + 2).

The Prefix notation for the given equation is "\(\pm a \times /bc^{de}^f\)". d.

The Prefix notation for the given equation "\((a+(b/c) \times (d^e)-f)\)" would be:

\(\pm a \times /bc^{de}^f\)

In Prefix notation, also known as Polish notation, the operators come before their operands.

Here's a step-by-step breakdown of converting the given equation to Prefix notation:

Start with the given equation: (a+(b/c)*(d^e)-f)

Replace the arithmetic operators with their corresponding symbols in Prefix notation:

Addition (+) becomes +

Division (/) becomes /

Exponentiation (^) becomes ^

Subtraction (-) becomes -

Rearrange the equation to move the operators before their operands:

Replace \((a+(b/c)(d^e)-f)\) with \((\pm a/bc^{de}^f)\)

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The solution for the given expression is  7 + 5/12

First we need to write the expression, using fractions, we will get:

(5 + 6/8) + (4 + 4/15) - (2 + 6/10)

We can group like terms, and we will get:

(5 + 6/8) + (4 + 4/15) - (2 + 6/10) = (5 + 4 -2) + (6/8 + 4/15 - 6/10)

Now just simplify that to get.

(5 + 4 -2) + (6/8 + 4/15 - 6/10) =  7 + 3/4 + 4/15 - 3/5

                                                =  7 + 3/4 + 4/15 - 9/15

                                                = 7 + 3/4 - 5/15

                                                = 7 + 9/12 - 4/12

                                                 = 7 + 5/12

That is the answer.

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Answer:

Step-by-step explanation:

= -17 = 6m - 4 + 7m

= 6m - 7m = 17 + 4

= 1m = 21

= m = 21 : 1

= m = 21

Answer:

A general rule when dealing when exponents:

An exponent of 0 is will always result in 1

An exponent of 1 results in the base number itself. The answer would be B, 1

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Answer: B. 1

Step-by-step explanation: 4.51 to the power of 0 is 1.

Everything to the power of 0 will always equal 1.

The five fifth roots of -5i in polar form using degree measure for the argument are z5 = \(5^{(\frac{1}{5} )\) [cos(342°) + i sin(342°.

To locate the fifth roots of -5i, we want to discover all complicated numbers z such that z^5 = -5i.

First, we can write -5i in polar shape as follows:

-5i = 5(cos(270°) + i sin(270°))

Next, we can write z in polar shape as z = r(cosθ + i sinθ), the place r is the modulus of z and θ is the argument of z.

Substituting this into the equation \(z^5\) = -5i, we get:

\(r^5\)(cos(5θ) + i sin(5θ)) = 5(cos(270°) + i sin(270°))

Since the modulus of -5i is 5, we understand that r = 5

Equating the actual and imaginary components on each aspects of the equation, we get:

\(r^5\) cos(5θ) = 5 cos(270°)

\(r^5\) sin(5θ) = 5 sin(270°)

Solving for θ, we get:

θ = (270° + 2πk)/5, the place ok = 0, 1, 2, 3, 4.

So, the 5 fifth roots of -5i in polar structure the usage of diploma measure for the argument are:

z1 = \(5^{(\frac{1}{5} )\) [cos((270° + 2π(0))/5) + i sin((270° + 2π(0))/5)]

z2 = \(5^{(\frac{1}{5} )\) [cos((270° + 2π(1))/5) + i sin((270° + 2π(1))/5)]

z3 =  [cos((270° + 2π(2))/5) + i sin((270° + 2π(2))/5)]

z4 = 5^{(\frac{1}{5} ) [cos((270° + 2π(3))/5) + i sin((270° + 2π(3))/5)]

z5 = 5^{(\frac{1}{5} ) [cos((270° + 2π(4))/5) + i sin((270° + 2π(4))/5)]

Simplifying the expressions, we get:

z1 = 5^{(\frac{1}{5} ) [cos(54°) + i sin(54°)]

z2 = 5^{(\frac{1}{5} ) [cos(126°) + i sin(126°)]

z3 = 5^{(\frac{1}{5} ) [cos(198°) + i sin(198°)]

z4 = 5^{(\frac{1}{5} ) [cos(270°) + i sin(270°)]

z5 = 5^{(\frac{1}{5} ) [cos(342°) + i sin(342°)]

The roots are listed in growing order of θ for 0Φ<2:

z1, z2, z3, z4, z5.

Therefore, the 5 fifth roots of -5i in polar structure the usage of diploma measure for the argument are:

z1 = 5^{(\frac{1}{5} ) [cos(54°) + i sin(54°)]

z2 = 5^{(\frac{1}{5} ) [cos(126°) + i sin(126°)]

z3 = 5^{(\frac{1}{5} ) [cos(198°) + i sin(198°)]

z4 = 5^{(\frac{1}{5} ) [cos(270°) + i sin(270°)]

z5 = 5^{(\frac{1}{5} ) [cos(342°) + i sin(342°)

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Answer:

  a² = b² -w² +2wx

Step-by-step explanation:

The algebra is pretty straightforward. Expand the expression in parentheses and add x².

  b² -(w -x)² = e² = a² -x²

  b² -(w² -2wx +x²) = a² -x² . . . . . expand the square

  b² -w² +2wx -x² = a² -x² . . . . . . distribute the minus sign

  b² -w² +2wx = a² . . . . . . . . . . . . add x²

Answer:

4/5

Step-by-step explanation:

Slope

    Slope y-intercept of a line: y = mx + b

Where m is the slope and b is the y-intercept.

 \(\sf y =\dfrac{4}{5}x-3\\\\\boxed{Slope = \dfrac{4}{5}}\)

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\(\large \bold {ANSWER}\)

\(\large \bold {EXPLANATION}\)

This line is in slope-intercept form, y=mx+b, where m represents the slope and b represents the y-intercept.

So that we can conclude that the slope is 4/5.

Answer:

Simple interest=1138.5

Step-by-step explanation:

Simple interest=23000×(5.4/100)×(11/12)

S.I=23000×0.054×(11/12)

S.I=1138.5

Answer:

Factory overhead is a liability account

Factory overhead is a liability account.

"Factory overhead is the costs incurred during the manufacturing process, not including the costs of direct labor and direct materials. Factory overhead is normally aggregated into cost pools and allocated to units produced during the period."

"A liability (generally speaking) is something that is owed to somebody else. Liability can also mean a legal or regulatory risk or obligation. In accounting, companies book liabilities in opposition to assets."

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The number of selfies deleted by Alex is 52.5.

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given that Last week, Alex took 90 selfies and Vic took 75 selfies. Today, they each decided that some of these selfies were not very good and deleted them. Alex deleted three times as many selfies as Vic.

Alex= 90

Vic = 75

Deleted ( Alex = 3 Vic )

Alex = 1 / 2 Vic

Deleted selfies = 90 - 75 /2 = 52.5

Hence, the number of selfies deleted by Alex is 52.5.

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Answer:She receives a monthly salary of $2,500 for which she must sell $20,000 wo

Step-by-step explanation:

The rod would not be accepted If the diameter measurement will be less than 1.495. Then the correct option is A.

The compliance zone of the rod goes over the specification limits of the hole in Imperfect Fit. This indicates that the shaft is big, but the opening is little.

The diameter of a rod is required to be 1.51 inches with an acceptable variance of .015 inches.

The rod would not be accepted If the diameter measurement will be less than 1.495.

Upper limit

→ 1.51 + 0.015

→ 1.525

Lower limit

→ 1.51 - 0.015

→ 1.495

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Answer:

y = -6x + 8

Step-by-step explanation:

\begin{bmatrix}6x+y=8\\ y=-6x+8\end{bmatrix}

I don't know why it came out like this

Answer:

Yttrium

Step-by-step explanation:

The atomic number of yttrium is 39. . An isotope with an atomic mass of 193 has 116 neutrons.

Answer:

77

number of protons is 77. Therefore atomic number atomic number is 77.

Answer:

x + x - 45 = 90

2x - 45 = 90

2x = 135

x = 67.5, so x - 45 = 22.5

The other two angles measure 22.5° and 67.5°.

Step-by-step explanation:

how many people in the party please ?

Answer:

9 9 years 9999999999999

Answer: 156.38 m

Step-by-step explanation:

Using the arc length formula, the answer is \(2\pi(8^2) \cdot \frac{140}{360} \approx 156.38\)

Answer:

Two angles whose sides are opposite rays are called vertical angles. Two coplanar angles with a common side, a common vertex, and no common interior points are called adjacent angles.

Further explanation

Adjacent Angles are two angles that share a common vertex, a common side, and no common interior points. They share a vertex and side, but do not overlap. The example is shown in the picture below.  

Where ∠1 and ∠2 are adjacent angles, ∠ABC and ∠1 are NOT adjacent angles because ∠ABC overlaps ∠1.

Vertical Angles are two angles whose sides form two pairs of opposite rays (straight lines). Vertical angles are located across from one another in the corners of the "X" formed by the two straight lines.  The example is shown in the picture below.

Where ∠1 and ∠2 are vertical angles, ∠3 and ∠4 are vertical angles, Vertical angles are not adjacent.  ∠1 and ∠3 are not vertical angles (they are a linear pair) and Vertical angles are always equal in measure.

Step-by-step explanation: