Answer:
D) Kinetic.
Explanation:
Kinetic energy is energy in motion.
Answer: D
Explanation: kinetic is also called energy of motion , it is defined at the work needed to accelerate a body of a given mass from rest to its stated velocity.
A series circuit has a total resistance of 1.00 x 10² ohms
and an applied potential difference of 2.00 x 102 volts.
The amount of charge passing any point in the circuit in
2.00 seconds is
Explanation:
First find current inorder to get guantity of
charge, current =volts /resistance
After getting current ( I) we take the formula which say current =quantity of charge / unit of time
Mass of mercury = 57 g Volume of mercury = 4.2 mL
A horse has a kinetic energy of 29/400 J. If the horse has a mass of 300 kg.
what is the horse's speed?
OA. 98 m/s
OB. 33.1 m/s
O C. 14 m/s
OD. 9.9 m/s
The potential energy of a ball at the top of a hill is 15,000 J. Two-thirds of the way down the hill, the potential energy is 5476 J. What is the ball's kinetic energy at
that point?
Answer:
kinitic energy1 + potential energy1 = kinitic energy2+ potential energy2
15000+0=ke2+5476
ke2=15000-5476
ke2=9524
kinetic energy of the Bal at that point= 9524
What is the frequency of a wave if its wavelength is 5 m and its speed is 20 m/s?.
Answer:
v=fy
Explanation:
v=fy
v= speed of light
f=frequency
y=wave lenght
make f subject of formula in this case
v=fy
f=v/y
f=20/5
f=4Hz
In the 4.6 billion year history of the Earth, how many times have continents of our planet gone through major shifts if these shifts happen on average every 395 million years?
Continents have undergone major shifts around 12 times.
To calculate the number of times continents have gone through major shifts in the 4.6 billion year history of the Earth, we can divide the total time span by the average duration between shifts.
Total time span = 4.6 billion years
Average duration between shifts = 395 million years
To convert the total time span to years, we multiply 4.6 billion by 1 billion (1 billion = 1,000 million).
Total time span in years = 4.6 billion years × 1 billion = 4.6 × 10^9 years
Now we can calculate the number of shifts by dividing the total time span by the average duration between shifts:
Number of shifts = Total time span / Average duration between shifts
= (4.6 × 10^9 years) / (395 million years)
≈ 11.65
Therefore, continents of our planet have gone through major shifts approximately 11.65 times in the 4.6 billion year history of the Earth. Since we cannot have a fraction of a shift, we can round the result to the nearest whole number. Thus, continents have undergone major shifts around 12 times.
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Is this answer correct?
There are strong winds on these trees. What makes the wind stronger? Why are they blowing from different directions?
A child holds a sled at rest on frictionless snow covered hill. if the sled weighs 77N,find the force T exerted by the rope on the sled and the force n exerted by the hill on the sled
Answer:62
Explanation:
The weight of the sled is 77 N. The force by the hill on the sled is equal to its weight that is 77 N. Then the tension force exerted by the rope on the sled is being 77N sin θ, where θ be the angle of inclination.
What is force?Force is an external agent acting on an object to change its motion or to deform it. There are various kinds of force like magnetic force, tension force, frictional force, gravitational force etc.
The weight that an object experience on earth is due to the gravitational force. The force that is exerted by a rope on an object is tension force since it is pulling from a side.
The normal force by the hill on the sled is equal to its weight that is 77 N. The tension force on the sled by the rope is dependent on the angle of inclination θ. If know the angle we can find T by the equation:
T = 77 sin θ.
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Old Faithful geyser in Yellowstone National Park shoots water every hour to a height of 40.0 m. With what velocity does the water leave the ground? (Assume no air resistance and that g 9.81 m/s2)
Answer:
Vo = 28 [m/s]
Explanation:
To solve this problem, use the following equation of kinematics.
\(v_{f}^{2}= v_{o}^{2}-(2*g*y)\)
where:
Vf = final velocity = 0
Vo = initial velocity [m/s]
g = gravity acceleration = 9.81 [m/s²]
y = elevation = 40 [m]
Note: when the geyser water reaches the maximum height, the speed is zero. Another important observation is that the negative sign in the equation indicates that the movement of water is contrary to the direction of the acceleration of gravity.
0 = Vo² - (2*9.81*40)
Vo = (784.8)⁰⁵
Vo = 28 [m/s]
A tube with a cap on one end, but open at the other end, has a fundamental frequency of 130.8 Hz. The speed of sound is 343 m/s (a) If the cap is removed, what is the new fundamental frequency of the tube
Answer:
Y = V / f where Y equals wavelength
4 Y1 = V / f1 for a closed pipe the wavelength is 1/4 the length of the pipe
2 Y2 = V / f2 for the open pipe the wavelength is 1/2 the length of the pipe
Y1 / Y2 = 2 = f2 / f1 dividing equations
f2 = 2 f1
the new fundamental frequency is 2 * 130.8 = 261.6
(The new wavelength is 1/2 the original wavelength so the frequency must double to produce the same speed.
The new fundamental frequency of the tube will be 261.6 Hz. Frequency is also the inverse of the time period.
What is the frequency?
Frequency is defined as the number of cycles per second. The time to make one complete cycle is frequency. The unit for frequency is Hertz.
The relation between the wavelength, speed, and the frequency is found as;
\(\lambda = \frac{v}{f}\)
The fundamental frequency is,\(\rm f_1 = 261.6 \ Hz\)
For the given condition the wavelength for the closed pipe will be ;
\(\rm \lambda_1 = \frac{v}{f_1} \\\\ \rm \frac{1}{4}L = \frac{v}{f_1} \\\\\)
For the given condition the wavelength for the open pipe will be ;
\(\rm \lambda_2= \frac{v}{f_2} \\\\ \rm \frac{1}{2}L = \frac{v}{f_2}\)
Divide the wavelength of both cases;
\(\rm \frac{\lambda_2}{\lambda_1} =\frac{f_2}{f_1} \\\\ f_2=2f_1 \\\\ f_2 = 2 \times 13.08 \ Hz \\\\ f_2 = 261.6 Hz.\)
Hence the new fundamental frequency of the tube will be 261.6 Hz.
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when the overcurrent protection for a conductor is located on the load end rather than the supply side of a conductor it is considered to be a(n) .
When the overcurrent protection for a conductor is located on the load end rather than the supply side of a conductor it is considered to be a tap conductor.
The National Electrical Code (NEC), the benchmark for safe electrical design, installation, and inspection to protect people and property from electrical hazards, defines a tap conductor as a conductor, other than a service conductor, that has overcurrent protection rated more than the ampacity of a conductor. A tap conductor has overcurrent protection ahead of its point of supply that exceeds the value permitted for similar conductors that are protected as described in NEC 240.4. Hence, when the overcurrent protection for a conductor is located on the load end rather than the supply side of a conductor it is considered to be a tap conductor.
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A car of mass m = 1090 kg is traveling down a θ = 11 degree incline. When the car's speed is v0 = 16 m/s, a mechanical failure causes all four of its brakes to lock. The coefficient of kinetic friction between the tires and road is μk = 0.45.
Calculate the distance the car travels down the hill L in meters until it comes to a stop at the end.
The distance travelled by the car along the plane is 29.56 m.
What is the acceleration of the car down the incline?The acceleration of the car down the incline is calculated by applying Newton's second law of motion as shown below;
F - Ff = ma
where;
F is the applied force on the car = 0Ff is the frictional force acting on the car, trying to stop it m is the mass of the cara is the acceleration of the car down the inclinefrictional force acting on the car, Ff = μmg cosθ
0 - μmg cosθ = ma
-μmg cosθ = ma
-μg cosθ = a
where;
μ is coefficient of kinetic frictionθ is the angle of inclination of the planea = -(0.45 x 9.8 x cos11)
a = -4.33 m/s²
The distance travelled by the car along the plane is calculated as follows;
v² = u² + 2aL
where;
L is the length of the incline = distance travelled by the carv is the final velocity of the car when it stops = 0u is the initial velocity of the car = 16 m/sa is the acceleration of the car0 = (16²) + 2(-4.33)L
0 = 256 - 8.66L
8.66L = 256
L = 256/8.66
L = 29.56 m
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Which equation would be used to determine the x component of the initial velocity
Explanation:
when an object is projected with an initial velocity at some angle, it has two velocity components.
One along the x-direction and one along the y-direction.
we can draw the free body diagram.
the component of velocity in the x-direction will be
\(v=v_0\cos\theta\)and in y direction is
\(v=v_0\sin\theta\)Thus, the x component of the velocity is
\(v_0\cos\theta\)Which option correctly matches the chemical formula of a compound with its name?
A. N2O3, dinitrogen trioxide
B. N2O, trinitrogen dioxide
C. N2O, dinitrogen trioxide
D. N2O3, trinitrogen dioxide
Answer:
A is indeed correct
Explanation:
just did the question
The option that correctly matches the chemical formula of a compound with its name is N₂O₃ dinitrogen trioxide.
What is dinitrogen trioxide?
Dinitrogen trioxide is one of the simple nitrogen oxide. The chemical compound formula of Dinitrogen trioxide N₂O₃.
That is, it consists of 2 molecules of nitrogen, hence the prefix "Di" and 3 molecules of oxygen given the prefix tri.
Thus, the option that correctly matches the chemical formula of a compound with its name is N₂O₃ dinitrogen trioxide.
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4. A car travels at a speed of v = 54 km/h. During emergency braking, the wagon decelerates (brakes) with a deceleration (braking) of 3m/s per second. a) Convert the speed into the unit m/ s.b) Calculate how long the braking lasts. c) Sketch the v-t diagram and calculate the braking distance!
The given velocity is 54km/hr, which, when converted to m/s using 1km = 1000m and 1 hour = 3600 seconds, equals 15m/s.
How to calculate distance?Now substitute the initial speed u = 15m/s values.
v = 0m/s as the final velocity
Time is 6 seconds.
In the a= -3 m/ s2 equation,
s= ut + 1/2at2 s= 15 6+ 1/2(-3)(6)2 s= 90-45 s = 45m
As a result, after using the brakes, the car will halt for up to 45 meters.
The inverse of acceleration is deceleration. The deceleration will be calculated by dividing the final velocity minus the initial velocity by the time required for the velocity drop.
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suppose you visit another planet: group of answer choices your mass and weight would be the same as they are on earth. your mass would be the same as on earth, but your weight would be different. your weight would be the same as on earth, but your mass would be different. no answer text provided.
If you were to visit another planet, your mass would be the same as on Earth, but your weight would be different.
This is because mass is a measure of the amount of matter in an object, and it does not change regardless of the location of the object. However, weight is a measure of the force of gravity acting on an object, and it is determined by the mass of the object and the strength of the gravitational field it is in.
Therefore, if you were to visit another planet with a different gravitational field than Earth's, your weight would be different even though your mass would remain the same.
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Which individual or group had perhaps the most profound effect on establishing social work as a specialized practice
Answer:
Which individual or group had perhaps the most profound effect on establishing social work as a specialized practice
Explanation:
Badll
Which of the following is an example of
the Law of Inertia?
A. Sitting in a chair and breaking it
B. Throwing a ball in outer space and it goes on forever
unless acted upon by another force
C. Eating a salad to bring chemical energy into the body
D. Driving a car on a track
you apply 2 volts to a piezoelectric material and measure a displacement of 0.5 nm. what is the approximate piezoelectric coefficient d33 for this piezoelectric? you apply 2 volts to a piezoelectric material and measure a displacement of 0.5 nm. what is the approximate piezoelectric coefficient d33 for this piezoelectric? 250 pm/v 250 nm/v 500 nm/v 500 pm/v 1 nm/v
The piezoelectric coefficient, measured in volt meters per Newton, connects the stress placed on a crystal to the resulting electric field.
The definition of a piezoelectric deviceThe ability of piezoelectric devices to transform mechanical energy into electrical energy and through inverse piezoelectric effect makes them useful as actuators in a range of applications. The following benefits apply to actuators made of piezoelectric components. quick reaction. movement with grace.
What type of substance is piezoelectric?When mechanical stress is applied to certain materials, it can result in the production of piezoelectric materials, or piezoelectrics. Quartz is a frequently used piezoelectric substance. When stress is applied, the electron moves, which results in the creation of an electric charge.
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What is the symbol F g mean
Answer:
Disambiguation
Explanation:
Fg is an abbreviation used in physics to describe the amount of force exerted by gravity on an object, normally represented in units such as the newton.
Answer:Gravitational forces
Explanation:Is used in physics, used when asked to calculate the the force attracted to the nucleus
It took 500 newtons of force to push a car 4 meters. How much work was done?
Answer:
The answer is 2000 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distanceFrom the question
force = 500 N
distance = 4 m
We have
workdone = 500 × 4
We have the final answer as
2000 JHope this helps you
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The options that fills the blanks for the radioactive decay of curium are;
1) 243
2) 94
3)Pu
4) Alpha
What is an alpha decay?The term alpha decay has to do with the kind of decay in which the daughter nucleus is formed by the loss of an alpha particle. In this case, the mass number of the daughter nucleus would be less than that of the parent by four units and the atomic number of the daughter nucleus would be less than that of the parent by two units.
Thus, we can see that the image that have been shown in the question is talking about the alpha decay of the curium isotope and we can see that a daughter nucleus is formed in the process.
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What are the most promising theoretical models for describing the strong force interactions between quarks and gluons within a proton and how do these models address the challenge of non-perturbative effects such as confinement and chiral symmetry breaking in Quantum Chromodynamics?
The models provide important tools for understanding the strong force interactions within a proton.
What is Quantum Chromodynamics?The strong force interactions between quarks and gluons within a proton are described by Quantum Chromodynamics (QCD), which is a fundamental theory of the strong nuclear force in particle physics. QCD is a non-Abelian gauge theory, meaning that the interactions between the quarks and gluons are highly nonlinear and non-perturbative.
What is Lattice QCD?One of the most promising theoretical models for describing the strong force interactions within a proton is lattice QCD, which is a numerical approach that uses a discrete grid to represent the space-time continuum. Lattice QCD allows for the calculation of QCD observables from first principles, without resorting to perturbative expansions. This method can handle non-perturbative effects such as confinement and chiral symmetry breaking by allowing for the simulation of the strong interactions on a discrete space-time grid
What is Effective Field Theory?Another promising model is effective field theory, which provides a way to describe the low-energy behavior of QCD by constructing an effective Lagrangian that contains only the degrees of freedom relevant to a particular energy scale. This allows for the calculation of QCD observables in a systematic expansion in powers of a small parameter, such as the ratio of the quark mass to the QCD energy scale.
What is Chiral perturbation theory?Chiral perturbation theory is another effective field theory that focuses on the dynamics of light quarks, which are the building blocks of pions, the lightest hadrons. Chiral perturbation theory provides a systematic expansion for the interactions between pions and nucleons, and can be used to calculate the properties of these particles at low energies.
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2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
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At some instant and location, the electric field associated with an electromagnetic wave in vacuum has the strength 65.9 V/m. Find the magnetic field strength B, the total energy density u, and the power flow per unit area, all at the same instant and location.
Answer:
B = 2.19*10^-7 T
u = 1.92*10^-18 J/m^3
P = (4pi r^2)cεo E^2
Explanation:
In order to find the magnetic field strength of the electromagnetic wave you use the following formula:
\(B=\frac{E}{c}\) (1)
B: magnitude of the magnetic field
E: magnitude of the electric field = 65.9V/m
c: speed of light = 3*10^8m/s
\(B=\frac{65.9V/m}{3*10^8m/s}=2.19*10^{-7}T\)
The magnitude of the magnetic field 2.19*10^-7 T
The energy density of the electromagnetic wave is:
\(u=\frac{1}{2}\epsilon_oE^2\) (2)
εo: dielectric permittivity = 8.85*10^-12C^2/Nm^2
\(u=\frac{1}{2}(8.85*10^{-12}C^2/Nm^2)(65.9V/m)^2=1.92*10^{-8}\frac{J}{m^3}\)
The energy density of the electromagnetic wave is 1.92*10^-8J/m^3
The power is given by:
\(P=IA=c\epsilon_oE^2(4\pi r^2)\)
A car from the beginning was traveling at 27.8m/s when he stepped on the brakes and stopped. According to the DMV, this would leave a skid mark of 60m. What is his acceleration?
Answer:
-6.44 m/s²
Explanation:
Given:
Δx = 60 m
v₀ = 27.8 m/s
v = 0 m/s
Find: a
v² = v₀² + 2aΔx
(0 m/s)² = (27.8 m/s)² + 2a (60 m)
a = -6.44 m/s²
2- A car on a straight highway goes in the positive direction for 8 km and then backs up for 3.6 km. What are the distance and displacement covered by the train?
Answer:
11.6km
4.4km in the negative direction
Explanation:
Distance is the total length of path covered and traveled by a body.
So, for this car on a straight line;
Total distance = 8km + 3.6km = 11.6km
Displacement is the distance traveled along a path and the direction it takes.
It is a vector quantity with magnitude and directional attributes.
For this journey;
Displacement = 8km - 3.6km = 4.4km in the negative direction.
Speed velocity and acceleration puzzle level 2
When describing motion, speed indicates the pace at which an object is travelling. It has one scalar component identifying its magnitude, irrespective of direction.
How to explain the informationThe unit for measuring speed can be either meters per second (m/s) or miles per hour (mph). For velocity, it's a different story. Its definition encompasses both speed and direction since it's a vector quantity. Measureable just like speed using m/s or mph.
In plain physic terms, acceleration reveals how much speed changes over time; hence it is also a vector quantity with not only size but also direction. Depending on whether a physical item is increasing in momentum, slowing down or static, the value could be positive, negative, or zero. Acceleration is calculated using units metres per second squared (m/s2).
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Unit Test
Unit Test Review Active
The diagram shows a position-time graph.
Position (m)
3
2
0
Position vs Time
Mark this and return
1
2
3
Time (s)
4
-2 m
-1 m
3 m
4 m
2
Save and Exit
3
What is the displacement of the object?
4
Next
5
6
7
Submit
8
The displacement of the object is 2 meters.
To determine the displacement of the object, we need to consider the change in position from the initial position to the final position.
Given:
Initial position = 0 meters
Final position = 2 meters
Calculate the displacement:
Displacement = Final position - Initial position
Displacement = 2 meters - 0 meters
Displacement = 2 meters
Therefore, the displacement of the object is 2 meters.
Explanation:
The position-time graph shows the position of an object over a specific time interval. In this case, the graph shows that the object starts at a position of 0 meters and ends at a position of 2 meters. The displacement of the object is the change in position from the initial point to the final point.
In this context, the displacement of 2 meters indicates that the object has moved 2 meters to the right or in the positive direction from its initial position. The negative and positive signs on the graph indicate the direction of motion, where positive values represent motion in one direction and negative values represent motion in the opposite direction.
The time interval is not directly related to the displacement calculation. It simply represents the duration of the object's motion. To determine the displacement, we only need to consider the initial and final positions, which in this case result in a displacement of 2 meters.
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