Hello unsure how to complete the homework question please help

Answer:

The energy possessed by a body because of its motion, equal to one half the mass of the body times the square of its speed is called its kinetic energy. Hence, when velocity is doubled, kinetic energy becomes 4 times.

Explanation:

Answer:

well bricks are heavy so yeah i guess so if you have a ton of them dropped on you lol

Explanation:

The theory of uniform accelerated motion states that the movement of an element is constant in the same acceleration conditions.

The theory of uniform accelerated motion is a scientific statement regarding the acceleration of an object in steady conditions.

This theory (uniform accelerated motion) is fundamentally applied in physic and astrophysics.

In conclusion, the theory of uniform accelerated motion states that the movement of an element is constant in the same acceleration conditions.

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a 150-dB sound is approximately 10 million times louder than an 80-dB sound.

Provide instances of the differences between the audible, ultrasonic, and infrasonic frequency ranges. Three sorts of sound waves, each covering a distinct frequency range, are used. These are what they are:

The difference in decibels between two sounds is related to the ratio of their intensities (or power) by the following formula:

dB₂ - dB₁ = 10 log10(I₂ / I₁)

where dB₁ and dB₂ are the decibel levels of the two sounds, and I₁ and I₂ are their intensities (or power).

Using this formula, we can find the ratio of the intensity of a 150-dB sound to that of an 80-dB sound:

150 dB - 80 dB = 10 log10(I₁₅₀ / I₈₀)

70 = 10 log10(I₁₅₀ / I₈₀)

7 = log10(I₁₅₀ / I₈₀)

10^7 = I₁₅₀ / I₈₀

I₁₅₀  = 10^7 * I₈₀

This shows that the intensity of a 150-dB sound is 10 million times greater than that of an 80-dB sound.

Therefore, a 150-dB sound is approximately 10 million times louder than an 80-dB sound.

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The error in the measurement of sin 90 degrees at the given error in angle is  0.001.

The error in measurement is obtained from the difference between the actual measurement and the observed measurement.

The error of sin 90 degrees is calculated as follows;

Actual measurement = sin 90 = 1

Observed measurement = sin(90 - 0.5)

Observed measurement = sin(89.5) = 0.999

Error in measurement = Actual measurement - Observed measurement Error in measurement = 1 - 0.999

Error in measurement  = 0.001

Thus, the error in the measurement of sin 90 degrees at the given error in angle is  0.001.

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Answer: B im sorry if its wrong

Explanation:

To hit a fish that he sees beneath the water, he should aim directly at the fish.

We'll view the fish a little bit above that it is because of refraction.Therefore, aim your arrow and bow under it (which is its true depth).On the other side, the laser beam will experience refractive error as it reaches the water.Therefore, we should direct the laser beam directly onto the fish.

The foundation of human civilisation is water.Societies have advanced throughout history by increasing access to clean drinking water as drinking, sanitation, and agriculture, as well as by purifying water to benefit public health and the environment.

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Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.

How do digital signals work?

An established or one that represents data as a step made up of discrete values is known as a digital signal. There is no noise produced by digital signals. Electronic signals sent as pulses are used to transmit digital signals to computers. These signals can be found in things like digital phones and computers.

Because digital signals are used to transport data to and from the cloud, it should be noted that videos are said to stream from the cloud to a computer without quality degradation.

Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.

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Answer:

The magnification of an image is equal to the ratio of the image height to the object height.

Note that the wave function of (Px)^2 is given by: (Px)^2 Psi(x) = (h^2/4π^2) [(3α^2 x^2 - α) (α/π)^(1/4) e^(-αx^2/2)]

To find the wave function of (Px)^2, we need to use the momentum operator, which is represented by Px = -i(h/2π) d/dx.

First, let's find the wave function of Px, which is given by:

Px Psi(x) = -i(h/2π) d/dx [Psi(x)]

= -i(h/2π) [-αx Psi(x) + (α^2 x) Psi(x)]

Now, we can find the wave function of (Px)^2 by squaring the wave function of Px:

(Px)^2 Psi(x) = (-i(h/2π) d/dx) (-i(h/2π) d/dx) Psi(x)

= (h^2/4π^2) [α^2 x^2 Psi(x) - 2α x d/dx(Psi(x)) + (d^2/dx^2)(Psi(x))]

Substituting Psi(x) = (α/π)^(1/4) e^(-αx^2/2) into the above expression, we get:

(Px)^2 Psi(x) = (h^2/4π^2) [(3α^2 x^2 - α) (α/π)^(1/4) e^(-αx^2/2)]

Therefore, the wave function of (Px)^2 is given by:

(Px)^2 Psi(x) = (h^2/4π^2) [(3α^2 x^2 - α) (α/π)^(1/4) e^(-αx^2/2)]

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The frame uncertainty depends on various factors such as the quality of the video equipment used, the stability of the platform, the lighting conditions, etc.

The displacement uncertainty (o) would be proportional to the frame uncertainty, as it is determined by the distance traveled by the puck in a certain number of frames.

The displacement uncertainty would also depend on the speed of the puck, as well as the accuracy of the measurement of the length of the arc. In general, a reasonable value for o would be on the order of a few millimeters.

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Answer:

Control groups let the one who is expermenting compare  the effect of the varibles in the expermental group.

Explanation:

Answer:

They are isotopes of each other

Explanation:

Isotopes are atoms of the same element that have the same number of protons but different numbers of neutrons.

For atom A and atom B, their number of protons is the same (10)

But their number of neutrons is different (12) and (10)

Explanation:

500 ml * 15 dtts/ml  / ( 24 hrs/ day * 2 days * 60 min / hr ) = 2.6 gtts/min

Answer:

Explanation: The moon of the Earth is much lighter in mass than the planet itself. In addition to being smaller than Earth, the Moon is also only approximately 60% as dense. A human weighs less on the Moon because there is less gravitational attraction there than there is on Earth.

Moon has lesser mass as conpared to earth, therefore gravitational force exerted by moon on any object is lesser than that of gravitational force exerted by earth on the same object, hence we can say that astronauts weight less on moon, i.e approximately 1/6 th of their weight on earth.

Answer:

Philip Gbeho

Explanation:

The electric charge and the electric force  on each sphere in terms of q is 2

Two metallic spheres, a and b, with a charge of half and a force of two tens of five

F1=k(1/2)(1/2)/r2

Equation F1=k/4r

A and C are two metallic spheres, respectively, so

Equation F2=k/2rsquare

equ1/equ2

2×10^-5/F2=k/4r^2×2r^2/k

F2=4×10^-5

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The child's speed at the lowest point is 5.42 m/s.

At the highest point of the swing, the child is momentarily at rest and has only potential energy. At the lowest point, the child has only kinetic energy.

Using the conservation of mechanical energy, we can write:

Potential energy at highest point = Kinetic energy at lowest point

mgh = (1/2)mv²

where m is the mass of the child, g is the acceleration due to gravity, h is the height of the swing at the highest point, and v is the speed of the child at the lowest point.

First, we need to find the height of the swing at the highest point. Since the swing is supported by two chains, the height of the swing at the highest point is half the length of the chains:

h = (1/2)3.00 m = 1.50 m

Next, we can solve for the child's speed at the lowest point:

mgh = (1/2)mv²

40.0 kg * 9.81 m/s² * 1.50 m = (1/2) * 40.0 kg * v²

588 J = 20.0 kg * v²

v² = 29.4 m²/s²

v = 5.42 m/s

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Answer:

Magnitude of Paula’s acceleration\($a=39 \cdot 8m/sec^{2}$.\)

Explanation:

• An object is said to be accelerated if there is a change in its velocity. At any point on a trajectory, the magnitude of the acceleration is given by the rate of change of velocity in both magnitude and direction at that point.

• To find the magnitude of her acceleration, use the formula:                               \($${v^2} = {u^2} + 2as$$\)

Where, is final velocity, is initial velocity, is acceleration and is displacement.

• Placing the value of the given initial velocity, \($u=0m/s$\), displacement, \($s = 0 \cdot 201m$\) and the final velocity,\($v = 4m/s$\) in the above formula.

\(\[\begin{align}& \therefore{v^2} = {u^2} + 2as \\& \Rightarrow {\left( 4 \right)^2} = 0+ 2\left( a \right) \left( { 0 \cdot 201} \right) \\& \Rightarrow 16 = 0 \cdot 402a \\& \Rightarrow a = 39 \cdot 8m/sec^{2} \\\end{align}\]\)

\(\[& \therefore{v^2} = {u^2} + 2as \\& \Rightarrow {\left( 4 \right)^2} = 0+ 2\left( a \right) \left( { 0 \cdot 201} \right) \\& \Rightarrow 16 = 0 \cdot 402a \\& \Rightarrow a = 39 \cdot 8m/sec^{2} \\\]\)

• Hence, magnitude of her acceleration, \($a=39 \cdot 8m/sec^2$\)

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The third equation of free fall can be applied to determine the acceleration. So that Paola's acceleration during the flight is 39.80 m/\(s^{2}\).

Acceleration is a quantity that has a direct relationship with velocity and also inversely proportional to the time taken. It is a vector quantity.

To determine Paola's acceleration, the third equation of free fall is appropriate.

i.e \(V^{2}\) = \(U^{2}\) ± 2as

where: V is the final velocity, U is the initial velocity, a is the acceleration, and s is the distance covered.

From the given question, s = 20.1 cm (0.201 m), U = 4.0 m/s, V = 0.

So that since Poala flies against gravity, then we have:

\(V^{2}\) = \(U^{2}\) - 2as

0 = \((4)^{2}\) - 2(a x 0.201)

  = 16 - 0.402a

0.402a = 16

a = \(\frac{16}{0.402}\)

  = 39.801

a = 39.80 m/\(s^{2}\)

Therefore Paola's acceleration is 39.80 m/\(s^{2}\).

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Answer:

t = 1.32 s

Explanation:

We are given;. Frequency of C4 note; F_c = 262 Hz

In conversions, we know that 1 Hz = 1 cycle/s

Thus, F_c = 262 cycles/s

Now, we want to find out how much time it takes for 346 air pressure maxima to pass a stationary listener.

346 air pressure maxima denotes that the air pressure maxima is 346 cycles.

Thus, time will be;

t = 346 cycles/262 cycles/s

t = 1.32 s

The time taken for the musical note to pass the stationary listener is 1.32 s.

The given parameters:

The frequency of a sound wave is defined as the number of cycles completed per second by the wave.

\(F = \frac{n}{t}\)

where;

The time taken for the musical note to pass the stationary listener is calculated as follows;

\(262 = \frac{n}{t} \\\\t = \frac{n}{262} \\\\t = \frac{346}{262} \\\\t = 1.32 \ s\)

Thus, the time taken for the musical note to pass the stationary listener is 1.32 s.

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The initial velocity of the ball is given as 36.0 m/s.

The horizontal component of velocity of ball is given as,

The ball is projected vertically, therefore, the angle made by ball is 90 degree.

Plug in the known values,

Therefore, the initial horizontal velocity of ball is 0 m/s.

The vertical component of velocity of ball is given as,

Plug in the known values,

Therefore, the initial vertical velocity of the ball is 36.0 m/s.

The final velocity of the car can be calculated using the formula: final velocity = initial velocity + acceleration * time. Plugging in the values you provided, we get: final velocity = 5.82 m/s + 2.35 m/s² * 3.25 s = 13.44 m/s.

Newton's second law allows us to find the results for the tension of the rope and the angular acceleration of the body are  

      a) The angular acceleration is α = 26.7 rad / s²

      b) The tension of the rope T = 2.67 N

Given parameters

To find

Newton's second law indicates that the net force is proportional to the product of the mass and the acceleration of the bodies

          ∑ F = m a

Where the bold letters indicate vectors, F is the external forces, m the mass and the acceleration of the body

A free body diagram is a diagram of the forces without the details of the bodies, in the attached we see a free body diagram of the system

Let's apply Newton's second law to the block

                     W - T = m a

Body weight is

                     W = mg

Let's substitute

                    mg - T = ma                  (1)

The pulley is a body that is in rotational motion so we use Newton's second law for rotation

           Σ τ = I α  

Where τ is the torque, I the moment of inertia and α the angular acceleration

In this case the reference system is located at the turning point  

            T R = I α

            T = \(\frac{I \alpha }{R}\)  

Linear and angular variables are related

            a = α R

We substitute in equation 1 and write the system of equations

            mg - T = m α R

                    T = \(\frac{I \alpha }{R}\)

We resolve

              mg = α  (m R + I / R)

             α = \(\frac{g}{R + \frac{I}{mR} }\)  

We calculate

            α = \(\frac{ 9.8}{ 0.30+\frac{0.030}{1.50 \ 0.30} }\)  

            α = 26.7 rad / s²

Let's calculate the tension of the rope

           T = \(\frac{I \alpha }{R}\)  

           T = \(\frac{0.030 \ 26.7 }{0.30}\)

           T = 2.67 N

In conclusion with Newton's second law we can find the results for the tension of the rope and the angular acceleration of the body are  

      a) The angular acceleration is alpha = 26.7 rad / s²

      b) The tension of the rope T = 2.67 N

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Answer:

1) aser 1 has the maximum closest to the center

2)  Δy = 0.0866 m ,   3)   Δy = 0.693 m

Explanation:

The interference phenomenon is described by the expression

         d sin θ = m λ                    for constructive interference

         d sin θ = (m + ½) λ           for destructive interference

We can use trigonometry to find the angle

        tan θ = y / L

in trigonometry experiments the angles are small

        tam θ = \(\frac{sin \theta}{cos \theta} = sin \theta\)

        sin θ = y / L

we substitute

         d y / L = m λ       (1)

1) Let's find the first maximum that corresponds to m = 1 for each laser

   laser 1    λ = d / 20

        d y₁ / L = 1 d / 20

        y₁ = L / 20

        y₁ = 5.20 / 20

        y₁ = 0.26 m

Laser 2      λ= d / 15

         d y₂ / L = 1 d / 15

         y₂ = d / 15

         y₂ = 5.20 / 15

         y₂ = 0.346 m

Therefore laser 1 has the maximum closest to the center

2) the difference between these maxima

       Δy = y₂ - y₁

       Δy = 0.3466 - 0.26

       Δy = 0.0866 m

3) we look for the second maximum m = 2 of laser 1, we substitute in equation 1

         y₃ = 2 5.20 / 20

         y₃ = 0.52 m

now let's find the third minimum m = 3 of laser 2

         d y₄ / L = (m + ½) λ

         d y₄ / 5.20 = (3 + ½) d / 15

         y₄ = 3.5 5.20 / 15

         y₄ = 1.213 m

        Δy = y₄ -y₃

        Δy = 1.213 - 0.52

        Δy = 0.693 m

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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