The magnitude of the force per unit length between two infinite parallel wires, 1 meter apart and carrying 1 amp of current in the same direction, is 4 * 10⁻⁷ N/m. This can be calculated using Ampere's law and the magnetic field produced by the wires.
To calculate the magnitude of the force per unit length between the two parallel wires, we can use Ampere's law.
According to Ampere's law, the magnetic field produced by a long, straight current-carrying wire at a distance r from the wire is given by B = (μ₀ * I) / (2π * r), where μ₀ is the permeability of free space (4π * 10⁻⁷ T·m/A) and I is the current in the wire.
Since we have two wires carrying currents in the same direction, the magnetic field produced by each wire at the position of the other wire will be in the same direction.
Therefore, the total magnetic field between the wires is twice the magnetic field produced by one wire. Thus, the magnetic field between the wires is B = (2 * μ₀ * I) / (2π * r).
The force per unit length between the wires can be calculated using the formula F = B * I, where F is the force per unit length and I is the current in one of the wires.
Substituting the expression for B, we get F = (2 * μ₀ * I²) / (2π * r).
Plugging in the values μ₀ = 4π * 10⁻⁷ T·m/A, I = 1 A, and r = 1 m, we find:
F = (2 * 4π * 10⁻⁷ T·m/A * (1 A)²) / (2π * 1 m) = (8π * 10⁻⁷ N) / (2π * 1 m) = 4 * 10⁻⁷ N/m.
Therefore, the magnitude of the force per unit length between the wires is 4 * 10⁻⁷ N/m.
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If the work required to speed a car up from 10km/h to 20km/h is 5.0 x 10^3 J, what would be the work required to increase the cars speed from 20km/h to 30km/h?
If the work required to speed a car up from 10km/h to 20km/h is 5.0 x 10^3 J, the work required to increase the cars speed from 20km/h to 30km/h is: 8.33 × 10³J.
How to find the work required?Using this formula to determine the work required to increase the cars speed from 20km/h to 30km/h
\(Wii = Wi (V^2_2- V^2_1) /v^2_2 - v^2_1\)
Let plug in the formula
Work required = (5 × 10³) (30² -20²) / (20² -10²)
Work required = (5 × 10³) ( 900 - 400) /(400 - 100)
Work required = (5 × 10³) ( 500) / 300
Work required = 8.33 × 10³J
Therefore the Work required is 8.33 × 10³J.
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a gas absorbs 0.0 j of heat and then performs 30.8 j of work. the change in internal energy of the gas is
A gas does 30.8 j of work after absorbing 0.0 j of heat. the gas's internal energy changed by -30.8 j.
E=change in internal energy and E=q + w
A greater q causes the system to heat up more. When q is negative, the system loses heat.
It is possible to improve the system when w (work completed) is positive. When w is zero, the system executes the operation.
Therefore, if the gas increases heat while losing 0.0 J of heat, q is positive 0.0 J.
The end result is negative, -30.8 J, as a result of the system performing 30.8 J of created labor.
The total of +0.0 J + +0.0 J is equivalent to - 30.8 J. (-30.8 J).
so that internal energy change =-30.8j
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A box has a momentum of
38.0 kg*m/s to the right. A 88.3 N
force pushes it to the right for 0.338
S. What is the final momentum of
the box?
Answer:
67.9 kg*m/s
Explanation:
Pi = 38 kgm/s
F = 88.3N and ∆t = 0.338s
Final momentum Pf = Pi + F∆t = 38 + (88.3)(0.338) = 38 + 29.8454
=) Pf = 67.8454 kgm/s = 67.85kg*m/s
Your answer is 67.9kg*m/s with three significant figures
hope this helps your troubles!
Except for the Local Group, galaxies seem to be isolated and randomly in space. T/F
The statement "Except for the Local Group, galaxies seem to be isolated and randomly in space" is false.
Galaxies are not randomly distributed in space. Instead, they are often found in groups and clusters, which are large structures composed of many galaxies held together by their mutual gravitational attraction. The Local Group, which contains the Milky Way and several other galaxies, is just one example of such a group.
The universe's distribution of galaxies is highly structured and complex, with galaxies often forming large-scale filaments and sheets that span billions of light years. These structures are thought to have arisen due to the effects of dark matter, which is a form of matter that does not emit, absorb, or reflect light, but which exerts a gravitational force on other matter.
Therefore, "Except for the Local Group, galaxies seem to be isolated and randomly in space" is false.
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Refer to science 10 (mirror mirror on the wall)how do the height and width of the object compare with the height and width of the image?
Depends on what type of mirror that is. I am going to assume this is a plain mirror (from the phrase), which means the height and width of the object and image is exactly the same.
The mirror images and the object both show the same ratio of height and width of the particular object. An image is formed due to reflection of light.
What is the relation between mirror image and object?The mirror image of an object or the two-dimensional figure of an object is the virtual image which is formed by the reflection in a plane mirror. It is of the same size as the original object, yet it is different, unless the object or figure has reflection symmetry which is also known as a P-symmetry.
The height and width of the object are the same as the height and width of the image formed in the mirror. A flat mirror is a mirror with a flat, shiny surface, for example, the mirror we use to look for in the mirror. The properties of the plane mirror images are include the image is neither inverted nor upright but it is virtual.
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4. An applied force of 6.2 N acts on a 2.1-kg object, pushing it horizontally across a surface
where the coefficient of kinetic friction is 0.15.
a. Draw a free body diagram for the body
b. Determine the frictional force acting.
c. Determine the net force acting on the body
d. Determine the object's acceleration.
Step by step, thank you
[2C]
[2A]
[2A]
[2A]
The frictional force on the body is 0.25 N the net force on the body is 5.95 N while the acceleration produced is 2.83 m/s^2
What is the net force?The net force is used to describe the resultant force that acts on the object.
The frictional force that acts on the object s obtained from;
Ff = 0.15 * 2.1-kg * 9.8 m/s^2
Ff = 0.25 N
The net force that acts on the body = F - Ff where F is the applied the force
= 6.2 N - 0.25 N
Net force = 5.95 N
Now;
Net force = ma
a= Net force /m
a = 5.95 N/2.1-kg
a = 2.83 m/s^2
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A flashlight can be made that is powered by the induced current from a magnet moving through a coil of wire. The coil and magnet are inside a plastic tube that can be shaken causing the magnet to move back and forth through the coil. Assume the magnet has a maximum field strength of 0. 05 T.
Make reasonable assumptions and specify the size of the coil and the number of turns necessary to light a standard 1-watt, 3-V flashlight bulb
According to the question the length of the coil is (0.004719 × 1).
What is length?Length is a measurement of the distance between two points. It can refer to a physical distance, such as the length of a road or the length of a desk, or it can refer to a temporal distance, such as the length of a movie or the length of a song. Length is usually measured in units such as meters, kilometers, or feet, and can also be measured in time units such as seconds, minutes, or hours. In mathematics, length is also used to describe the size of a line, curve, or circle.
Assuming the magnetic field is uniform throughout the coil and that the current induced in the coil is directly proportional to the field strength, the number of turns in the coil can be calculated using the formula:
N = (V × B) / 4πf
Where:
N = number of turns
V = voltage of the flashlight bulb (3 V)
B = maximum field strength of the magnet (0.05 T)
f = frequency of the magnet moving through the coil (assume to be 1 Hz)
Therefore, the number of turns in the coil is:
N = (3 × 0.05) / (4π × 1) = 0.004719 turns
Assuming the coil is made from copper wire with a cross-sectional area of 1 mm2, the length of the coil is given by the formula:
L = N × A / π
Where:
L = length of the coil
N = number of turns in the coil (0.004719)
A = cross-sectional area of the wire (1 mm2)
Therefore, the length of the coil is:
L = (0.004719 × 1)
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Part of a bird's digestive tract, called a gizzard, is able to break up large chunks of food at an extremely fast rate. It is difficult for
scientists to watch a gizzard functioning in a live bird. How would building a model of a gizzard help a scientist?
A. to analyze how a gizzard works
В.to study bird behavior
C.to determine what type of tissues a real gizzard is made of
D.to watch a gizzard functioning in life
Answer:A:
To analyze how a gizzard works.
Explanation:
What is the unit of measure of work?
Select one:
a. Kilogram/meter
b. Newton/kilogram
c. Meter Kilogram
d. Newton meter
\( \color{aqua} \boxed{\bf{ \colorbox{azure} {\red{Option\:D}}}}\)
d. Newton meter
In equation form: work (joules) = force (newtons) x distance (meters)\(\\\\\)
\(\large\color{red}{\boxed{❥\:gℓσssүρεαяℓ...}}\)
Answer:
Option D
Newton meter
Explanation:
We know the formula to find Work
The product of Applied Force and Total Displacement is called work done.W = F • dThe unit of force is Newton and the unit of displacement is meter.
Thus, The answer is Newton meter or Nm
-TheUnknownScientist 72
How is 'one standard kilogram' defined in SI system?
Explanation:
The standard one kilogram mass is the mass of platinum-iridium cylinder kept at 0 degree Celsius at the International Bureau of Weights and Measures in France. The mass is equal to mass of 1 litre of water at 4 degree Celsius.Use the diagram to explain how convection occurs inside the earth. What could convection cause to occur on earths surface
Answer:
mantle convection is the very slow creeping motion of earths solid silicate mantle caused by convection currents carrying heat from the interior to the planet's surface.
Anyone able to help with this one? The volume of a gas sample is 550 mL and the pressure is 1.8 atm. What will the new volume of the gas be if the pressure increases to 2.2 atm? Round your answer to the correct number of significant figures.
Answer:
450 ML
Explanation:
Given:
Volume of gas sample: 550 mL Pressure: 1.8 atm plus 2.2 atm
To find:
The new volume of the gas after the pressure increases to 2.2 atm.
___
steps
⇒ \(V_1P_1=V_2P_2\)
⇒ \((550\text{ml})(1.8\text{atm})\)
⇒ \(=(x)(2.2\text{atm})\)
⇒ \(x=\frac{(550)(1.8)}{2.2}\)
⇒ \(x=450\text{ml}\)
Answer:
V₂ = 450 mL
Explanation:
Because you are dealing solely with pressure and volume, you can use Boyle's Law to find the missing value. The equation looks like this:
P₁V₁ = P₂V₂
In this formula, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You have been given values for all of the variables except for "V₂". Thus, you can substitute the given values into the equation and simplify to find the answer. The final answer should have 2 sig figs to match the given values.
P₁ = 1.8 atm V₁ = 550 mL
P₂ = 2.2 atm V₂ = ?
P₁V₁ = P₂V₂ <----- Boyle's Law equation
(1.8 atm)(550 mL) = (2.2 atm)V₂ <----- Plug given values in
990 = (2.2 atm)V₂ <----- Multiply 1.8 and 550
450 = V₂ <----- Divide both sides by 2.2
while heating two different samples of water at sea level, one boils at 102°c and one boils at 99.2°c. calculate the percent error for each sample from the theoretical 100.0°c.
In summary, the first sample has a per cent error of 2.0% from the theoretical boiling point of 100.0°C, while the second sample has a per cent error of 0.8%.
The per cent error represents the deviation of the experimental value from the theoretical value, expressed as a percentage of the theoretical value. It provides a measure of the accuracy of the experimental measurements. The per cent error for the first sample, which boils at 102.0°C, can be calculated as follows:
\(\[\text{{Percent error}} = \left|\frac{{\text{{Experimental value}} - \text{{Theoretical value}}}}{{\text{{Theoretical value}}}}\right| \times 100 = \left|\frac{{102.0 - 100.0}}{{100.0}}\right| \times 100 = 2.0\%\]\)
Therefore, the per cent error for the first sample is 2.0%. Similarly, the per cent error for the second sample, which boils at 99.2°C, can be calculated as:
\(\[\text{{Percent error}} = \left|\frac{{\text{{Experimental value}} - \text{{Theoretical value}}}}{{\text{{Theoretical value}}}}\right| \times 100 = \left|\frac{{99.2 - 100.0}}{{100.0}}\right| \times 100 = 0.8\%\]$\)
Thus, the per cent error for the second sample is 0.8%.
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The diagram shows a circuit with a 3-cell battery, a light bulb, and four labeled locations. Which statement describes the direction of conventional current in this circuit?
The statement that correctly describes the direction of conventional current in the circuit is : ( C ) current is directed from A to B to C to D
Conventional currentconventioanl current is simply the flow of protons from the positive terminal of the voltage source ( battery ) to the negative terminal of the battery. Also conventional current is the charge transferred in a given direction per unit time. for a conventional current the charge carrier is irrelevant.
Hence we can conclude that the direction of conventional current in the circuit is : current is directed from A to B to C to D.
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Attached below is the missing part of the question
If a car starts from rest and accelerates at 4 m/s2 for 8 sec, how far did it travel and how fast was it moving at the end of the 8 sec?
-256 m, 12 m/s
- 136 m, 32 m/s
-128 m, 12 m/s
-128 m, 32 m/s
Answer:did you ever get the answer?
Explanation:
If a car starts from rest and accelerates at 4 m/s² for 8 sec,distance it travel, S = 128 m and how fast was it moving is 12 m/sec.
What is acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.
Given in the question If a car starts from rest and accelerates at 4 m/s² for 8 sec, how far did it travel and how fast was it moving at the end of the 8 sec,
Velocity of car is,
v = u + at
v = 0 + 4*8
v = 12 m/sec
Distance travelled by car is,
S = ut + (0.5)at²
S = 0 + 128
S = 128 m
If a car starts from rest and accelerates at 4 m/s² for 8 sec,distance it travel, S = 128 m and how fast was it moving is 12 m/sec.
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Question: How do static and sliding friction affect the speed of a paperback book, a flat
eraser and a key?
Answer:
How do static and sliding friction affect the speed of a paperback book, a flat eraser and a key?
Prediction: Which item (paperback book, flat eraser, or key) will have the most static friction and which item will have the most sliding friction? Make sure your prediction gives an explanation of your reasoning.
Explanation:
what is whether or not each type of glassware can be heated?
Whether or not each type of glassware can be heated depends on the specific type of glassware and the method of heating.
What is method of heating?The method of heating refers to the various ways in which heat energy can be transferred to an object or substance to raise its temperature. Some common methods of heating include:
Conduction: This involves transferring heat through direct contact between two objects or substances. For example, heating a pan on a stove by placing it directly on the burner.Convection: This involves transferring heat through the movement of fluids, such as air or water. For example, a forced-air heating system that circulates warm air through a building.Radiation: This involves transferring heat through electromagnetic waves, such as infrared radiation. For example, the sun heating the earth through radiation.Induction: This involves transferring heat through an electromagnetic field, which induces an electric current and produces heat. For example, an induction cooktop that heats a pot through an electromagnetic field.Whether or not each type of glassware can be heated depends on the specific type of glassware and the method of heating. Some types of glassware, such as borosilicate glass, are designed to withstand high temperatures and are commonly used for heating applications, while other types of glassware may be more susceptible to cracking or breaking when exposed to heat.
Glassware that is designed for heating applications will be labeled as such and will typically have a higher temperature tolerance than glassware that is not intended for heating. Some common types of glassware that are designed for heating include Pyrex, Kimax and Vycor glass.
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A distant planet with a mass of (7.2000x10^26) has a moon with a mass of (5.0000x10^23). The distance between the planet and the moon is (6.10x10^11). What is the gravitational force between the two objects?
A distant planet with a mass of (7.2000x10^26) has a moon with a mass of (5.0000x10^23). The distance between the planet and the moon is (6.10x10^11). What is the gravitational force between the two objects?
Answer:
Explanation:
This is a simple gravitational force problem using the equation:
\(F_g=\frac{Gm_1m_2}{r^2}\) where F is the gravitational force, G is the universal gravitational constant, the m's are the masses of the2 objects, and r is the distance between the centers of the masses. I am going to state G to 3 sig fig's so that is the number of sig fig's we will have in our answer. If we are solving for the gravitational force, we can fill in everything else where it goes. Keep in mind that I am NOT rounding until the very end, even when I show some simplification before the final answer.
Filling in:
\(F_g=\frac{(6.67*19^{-11})(7.2000*10^{26})(5.0000*10^{23})}{(6.10*10^{11})^2}\) I'm going to do the math on the top and then on the bottom and divide at the end.
\(F_g=\frac{2.4012*10^{40}}{3.721*10^{23}}\) and now when I divide I will express my answer to the correct number of sig dig's:
\(Fg=\) 6.45 × 10¹⁶ N
Terrestrial planets are mainly composed of ________, while the giant planets are made predominantly of ________.
Terrestrial planets are mainly composed of rock and metals while the giant planets are made predominantly of volatiles.
What is a solar system?It is a system that collection of all the planets and spatial bodies revolving around the sun because of the gravitational pull of the sun.
Our Solar System is based on a heliocentric model in which the Sun is assumed to reside at the central point of the planetary system.
Celestial bodies like Earth are referred to as terrestrial planets. They have a hard surface and are composed of rocks or metal.
Thus, Terrestrial planets are mainly composed of rock and metals while giant planets are made predominantly of volatiles.
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if the period wave is 6 seconds what is its frequency
Answer:
.17Hz
Explanation:
The formula for frequency is f= 1/T , where T is the period.
f = 1/6 and 1/6 ≈ .17
Frog jumps to the left with average speed of 1.8 m/s for 0.55 s whats the frogs displacement in meters
Answer: 0.99m left
Explanation:
The formula:
Distance / Time = Rate
Fill in the formula
Distance / 0.55s = 1.8 m/s
Multiply both sides by 0.55s
Distance = 0.99m
Displacement = 0.99m to the left.
Answer:
-0.99 (See attached)
Explanation:
(See attached)
(ii) Let R be a rotation and S be a reflection of the euclidean plane E. Give a precise deion of RS, relating it to the classification of isometries of E². Be careful of special cases.
RS is a composition of rotation and reflection in the Euclidean plane E². The precise description of RS depends on the specific properties of the rotation R and reflection S.
In general, if R and S have the same axis or line of symmetry, the composition RS results in a translation. If R and S have intersecting lines of symmetry, RS yields a glide reflection. If R and S have perpendicular lines of symmetry, RS produces a rotation.
It is important to consider special cases, such as parallel lines of symmetry, coinciding axes, or perpendicular lines of reflection, as they may lead to different outcomes. The classification of isometries in E² involves understanding how rotations and reflections combine to create different transformations in the plane.
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a performer seated on a trapeze is swinging back and forth with a period of 8.85 s. if she stands up, thus raising the center of mass of the trapeze performer system by 35.0 cm, what will be the new period of the system?
The new time period of the system is 8.77 sec. If she stands up.
calculation
T = 2π√(L/g)
l = g*(8.85/2π)^2
new length = l -0.35= 8.85-0.35
T = 8.77 sec
Term (T) is the amount of time an oscillating body takes to repeat itself, and Frequency (f or ν) is the variety of instances it repeats in one 2d or unit time. in case you degree time in s (seconds) then frequency is measured in Hz (cycles or durations in keeping with second.
center of mass:
The centroid of a mass distribution in space is the unique point where the weighted relative positions of the distribution masses sum to zero. This is the point where force can be applied to produce linear acceleration without angular acceleration.
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13) How much mechanical energy does a swinging bowling ball have if it has 250J of kinetic energy and
800J of potential energy?
A)
B)
C)
A. ME = PE + KE
ME = mechanical energy
PE = potential energy
KE = kinetic energy
B. ME = 800 + 250
C. 1050 J
Create a simple series circuit with a 20-volt battery, one 10.0 ohm resistor, and one 15-ohm light bulb. Set the wire resistivity to "tiny" and the battery resistance to 0.0 ohms What is the current in the circuit? 0.5A 0.4 A 0.8A 1.0 A
Answer:
O.8A
Explanation:
A physicist is testing a brand new projectile launcher in her lab that is designed to launch human skulls in a vacuum. She can adjust the angle to whatever she wants. She tests it by launching a skull at an angle of 70 degrees above the horizontal at a velocity of 18.0m/s at ground level.
A. What are the x and y components of the skull's initial velocity?
B. How fast is the skull traveling at its peak height?
C. How long until the skulls hits the floor?
D. What is the range of the skull?
A physicist is trying out a new machine in her lab. It can launch human skulls in a space without air. She can change the way it points. She tries it by shooting a skull at the ground. She shoots it up at a 70-degree angle and it goes 18 meters per second.
A. What is the speed of the skull when it goes up and when it goes sideways?
B. How fast is the skull going when it is as high as it can go?
C. How much time passes before the skull hits the ground?
D. How far away does the skull go?
To answer the questions related to this physics problem, you can use the following formulas:
The x-component of the initial velocity (vx) can be found using the formula: vx = v0*cos(theta), where v0 is the initial velocity magnitude (18.0 m/s) and theta is the launch angle (70 degrees).
The y-component of the initial velocity (vy) can be found using the formula: vy = v0*sin(theta).
The time it takes for the skull to hit the ground (t) can be found using the formula: t = (2*vy)/g, where g is the acceleration due to gravity (9.81 m/s^2).
The maximum height reached by the skull (h) can be found using the formula: h = (vy^2)/(2*g).
The range of the skull (R) can be found using the formula: R = (vx*vy)/g.
A. To find the x and y components of the skull's initial velocity, we use the following equations:
Vx = V cosθ
Vy = V sinθ
where V is the magnitude of the velocity, θ is the launch angle, Vx is the velocity in the x-direction, and Vy is the velocity in the y-direction.
Given V = 18.0 m/s and θ = 70 degrees, we have:
Vx = 18.0 m/s × cos(70 degrees) ≈ 5.53 m/s
Vy = 18.0 m/s × sin(70 degrees) ≈ 17.5 m/s
Therefore, the x and y components of the skull's initial velocity are 5.53 m/s and 17.5 m/s, respectively.
B. At the peak height, the skull's vertical velocity (Vy) will be zero. We can use the following equation to find the speed at the peak height:
Vy = V sinθ - gt
where g is the acceleration due to gravity (approximately 9.81 m/s^2).
Setting Vy to zero and solving for V, we have:
V = gt/sinθ ≈ 36.5 m/s
Therefore, the skull is traveling at a speed of approximately 36.5 m/s at its peak height.
C. To find the time it takes for the skull to hit the floor, we can use the following equation:
y = Vyt - 0.5gt^2
where y is the initial height of the skull (assumed to be zero), Vy is the initial velocity in the y-direction, g is the acceleration due to gravity, and t is the time.
Setting y to zero and solving for t using the quadratic formula, we get:
t = [Vy + sqrt(Vy^2 + 2gy)]/g
Substituting the values we have, we get:
t = [17.5 m/s + sqrt((17.5 m/s)^2 + 2 × 9.81 m/s^2 × 0)]/9.81 m/s^2 ≈ 1.79 s
Therefore, the skull will hit the floor after approximately 1.79 seconds.
D. To find the range of the skull, we can use the following equation:
x = Vx × t
Substituting the values we have, we get:
x = 5.53 m/s × 1.79 s ≈ 9.89 m
Therefore, the range of the skull is approximately 9.89 meters.
ChatGPT
A. To find the x and y components of the skull's initial velocity, we first need to break the initial velocity vector into its x and y components. The initial velocity vector can be represented as:
v₀ = 18.0 m/s at an angle of 70 degrees above the horizontalThe x component of the initial velocity can be found using:
v₀x = v₀cosθwhere θ is the angle above the horizontal. Substituting the values, we get:
v₀x = 18.0 m/s cos(70°) = 5.60 m/sThe y component of the initial velocity can be found using:
v₀y = v₀sinθSubstituting the values, we get:
v₀y = 18.0 m/s sin(70°) = 17.22 m/sTherefore, the x and y components of the skull's initial velocity are 5.60 m/s and 17.22 m/s, respectively.B. At the peak height, the vertical component of the velocity becomes zero. Therefore, we can use the equation:
v² = v₀² - 2gywhere v₀ is the initial velocity, g is the acceleration due to gravity, and y is the vertical displacement. At the peak height, y is equal to:
y = (v₀y)² / (2g)Substituting the values, we get:y = (17.22 m/s)² / (2*9.81 m/s²) = 15.00 mUsing this value of y and the initial velocity, we can find the speed of the skull at the peak height:
v = √(v₀x² + 2gy)Substituting the values, we get:
v = √((5.60 m/s)² + 2*(9.81 m/s²)*(15.00 m)) = 22.15 m/sTherefore, the skull is traveling at a speed of 22.15 m/s at its peak height.C. To find the time it takes for the skull to hit the floor, we can use the equation:
y = v₀yt - 1/2gt²where t is the time taken for the skull to hit the floor. At the point of impact, y is equal to zero. Substituting the values, we get:
0 = (17.22 m/s)t - 1/2*(9.81 m/s²)t²Solving for t, we get:
t = 3.53 sTherefore, it takes 3.53 seconds for the skull to hit the floor.D. To find the range of the skull, we can use the equation:
x = v₀x * tSubstituting the values, we get:
x = (5.60 m/s) * (3.53 s) = 19.77 mTherefore, the range of the skull is 19.77 meters.
Si un ciclista tarda 1.45 hrs en recorrer una distancia de 80 km. ¿Cuál será el valor de la velocidad media? Indica tu resultado en unidades del Sistema Internacional.
Answer: 45 kmph, AAAAAAAAAAAAAAAAAAAAAAA
what type of image is formed when rays of light actually intersect?
When rays of light actually intersect, they form a real image. A real image is an image that can be projected onto a screen because it is formed by the actual intersection of light rays.
The real image is always inverted and smaller in size than the object being imaged. The distance between the real image and the lens or mirror that forms it is dependent on the distance between the object and the lens or mirror. Real images are formed by concave mirrors and convex lenses when the object is placed beyond the focal point, as well as by convex mirrors and concave lenses when the object is placed within the focal point.
Real images are used in many applications such as in microscopes, telescopes, and cameras. In these devices, the real image is projected onto a surface such as film or an electronic sensor, which captures the image and converts it into an electrical signal.
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What are used for manufacturing paper along with chemical
Answer:
Dry-strength additives, or dry-strengthening agents, are chemicals that improve paper strength normal conditions. These improve the paper's compression strength, bursting strength, tensile breaking strength, and delamination resistance. Typical chemicals used include cationic starch and polyacrylamide derivatives.
If you were to switch to a green laser pointer(532nm) in the diffraction experiment. The current wavelength is 630nm. Describe what you expect to change when you conduct the experiment (assume you stand the same distance from the wall.
Standing at the same distance from the wall, you can anticipate seeing a diffraction pattern with a possible stronger central maximum when you switch to a green laser pointer (532nm) in a diffraction experiment.
When you switch from a red laser pointer (current wavelength of 630nm) to a green laser pointer (532nm) in a diffraction experiment, you can expect the following changes while standing at the same distance from the wall:
1. The diffraction pattern will have a different spacing between fringes: Since the green laser has a shorter wavelength than the red laser, the spacing between the fringes in the diffraction pattern will be smaller. This is because the fringe spacing is inversely proportional to the wavelength of the light.
2. The central maximum may appear brighter: Green light is generally more easily perceived by the human eye compared to red light. As a result, the central maximum in the diffraction pattern might appear brighter when using the green laser pointer.
To summarize, when you switch to a green laser pointer (532nm) in a diffraction experiment while standing at the same distance from the wall, you can expect to see a diffraction pattern with smaller spacing between the fringes and a potentially brighter central maximum.
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