Answer:
This is the answer hope you have a nice day
5. There are 400 students in the senior class at Oak Creek High School. All 2 points
of these students took the SAT. The distribution of their SAT scores is
approximately normal. The number of students who scored within 2
standard deviations of the mean is approximately *
-3
-2
0
1
2.
3
Answer:
The number of students who scored within 2 standard deviations of the mean is 380.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
The number of students who scored within 2 standard deviations of the mean is approximately
By the Empirical Rule, 95% of the students scored within 2 standard deviations of the mean
Out of 400
0.95*400 = 380
The number of students who scored within 2 standard deviations of the mean is 380.
Answer: 380
Step-by-step explanation: 95% of 400 is 380
Hello
Please what’s the explanation to get the answer (2+2) ² (2+3)³
Answer:
141Step-by-step explanation:
Hello
Please what’s the explanation to get the answer (2+2) ² (2+3)³
we use PEMDAS
Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).
(2 + 2)² + (2 + 3)³ =
4² + 5³ =
16 + 125 =
141
PLZ HELP!!! 25 POINTS I NEED AN ANSWER IN THE NEXT 15 MINUTES!!! I WILL MARK BRAINLIEST!
9514 1404 393
Answer:
6.75 square units
Step-by-step explanation:
The formula for the area of a rectangle of base 'b' and height 'h' is ...
A = bh
The formula for the area of a triangle of base 'b' and height 'h' is ...
A = (1/2)bh
That is, the area of a triangle is half the area of a rectangle with the same base and height. Here, the area of the triangle is ...
(1/2)(13.5 square units) = 6.75 square units
. Given that r satisfies the inequality 20.x > 33,
find the smallest value of x if .r is a prime number.
Answer: x = 2.
Step-by-step explanation:
By an online search, i found that the question is:
"Given that x satisfies the inequality 20*x > 33, find the smallest value of x if x is a prime number."
To find the smallest value of x we need to input different possible values of x (where we have the condition that x must be a prime number) and see which one is the first one that makes the inequality true.
The prime numbers are:
2, 3, 5, ....
Let's start with the smaller one, x = 2
So we input it in the inequality and get:
20*2 > 33
40 > 33
this is true.
Then we can have x = 2, which is the smaller prime number that satisfies the inequality.
in the linear equation y = 3x+8, the y-intercept is
Answer:
(0,8)
Step-by-step explanation:
The slope intercept formula is set up as y=mx+b, where b is the y-intercept value. In the equation y=3x+8, we can see that 8 is the y-intercept. So we plug 8 for y in a coordinate, and 0 for x. The answer is (0,8)
By using graphical method, find optimal solution of the problem max z = 3x + y s.t 2x - y ≤ 5 -x + 3y ≤ 6 x ≥ 0, y ≥ 0
By analyzing the graph and evaluating the objective function at each vertex of the feasible region, we can find the optimal solution, which is the vertex that maximizes the objective function z = 3x + y.
To find the optimal solution of the given problem using the graphical method, we need to plot the feasible region determined by the given constraints and then identify the point within that region that maximizes the objective function.
Let's start by graphing the constraints:
1. Plot the line 2x - y = 5. To do this, find two points on the line by setting x = 0 and solving for y, and setting y = 0 and solving for x. Connect the two points to draw the line.
2. Plot the line -x + 3y = 6 using a similar process.
3. The x-axis and y-axis represent the constraints x ≥ 0 and y ≥ 0, respectively.
Next, identify the feasible region, which is the region where all the constraints are satisfied. This region will be the intersection of the shaded regions determined by each constraint.
Finally, we need to identify the point within the feasible region that maximizes the objective function z = 3x + y. The optimal solution will be the vertex of the feasible region that gives the highest value for the objective function. This can be determined by evaluating the objective function at each vertex and comparing the values.
Note: Without a specific graph or additional information, it is not possible to provide the precise coordinates of the optimal solution in this case.
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Can someone help plz need this to save my grade??
Answer:the first one
Step-by-step explanation:
The average rate of change of g(x) between x = 4 and x = 7 is Five-sixths. Which statement must be true?
Suppose MarketOne is a marketing company that has small businesses for clients. MarketOne charges an upfront cost of $350 for new clients and an additional $195 per month to run and maintain the client's website. A linear equation could be used to relate the total cost, in dollars, of MarketOne's services and the number of months that the client's website is running. Which solution is viable for this situation? For full points, write the equation and show your work.
Find the value of x in the
following parallelogram:
3
5x - 6
3x - 2
x = [?]
Answer:
X=2
Step-by-step explanation:
3=5x2-6=3x2-2
5x2-6=4
3x2-2=4
What’s the correct answer for this question?
Answer:
A and B
Step-by-step explanation:
1) Distance to the focus
From (x,y) to the focus(2,-4) {using distance formula}
=√(x-2)²+(y+4)²
2) Distance to the directrix
Is, y+p where P here is (-6)
So
d2 = y+p
= y+(-6)
= y-6
HELP TIMER Write the equation of a hyperbola centered at the origin with x-intercept +/- 4 and foci of +/-2(squareroot 5)
Answer:
\(\frac{x2}{a} - \frac{y2}{b2} = 1\)
Step-by-step explanation:
A hyperbola is the locus of a point such that its distance from a point to two points (known as foci) is a positive constant.
The standard equation of a hyperbola centered at the origin with transverse on the x axis is given as:
\(\frac{X2}{16} - \frac{b}{4} = 1\)
The coordinates of the foci is at (±c, 0), where c² = a² + b²
Given that a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2√5. Since the x intercept is ±4, this means that at y = 0, x = 4. Substituting in the standard equation:
I don't feel like explaining so...
a. = 4
The foci c is at +/-2√5, using c² = a² + b²:
B = 2
Substituting the value of a and b to get the equation of the hyperbola:
\(\frac{x2}{a2} - \frac{y2}{b2} = 1\)
\(\frac{x2}{16} - \frac{b2}{4} = 1\)
Given AC and BD bisect each other at O prove AC is congruent to c
The Value of CD from the second equation into the first equation:2AC = AB + OC + OD⇒ 2AC = AB + AB (By substituting OC = OA and OD = OB)⇒ 2AC = 2AB⇒ AC Therefore, AC is Congruent to c .
Since AC and BD bisect each other at O, we can say that AO = OC and BO = OD.
We need to prove that AC = CD.To do this, we can use the segment addition postulate which states that if a line segment is divided into two parts, the length of the whole segment is equal to the sum of the lengths of the two parts.
Let us draw a diagram to represent the given information:From the diagram, we can see that:AO + OB = AB (By segment addition postulate)OC + OD = CD (By segment addition postulate)AO = OC (Given)BO = OD (Given)
Now, we can substitute the values of AO and OC as well as BO and OD into the equations above:AO + OB = AB ⇒ OC + OB = AB (Substituting AO = OC)OC + OD = CDNow, we can add both equations:OC + OB + OC + OD = AB + CD ⇒ 2(OC + OD) = AB + CDWe know that OC = AO and OD = BO.
Therefore, we can write:2(AO + BO) = AB + CDSince AO = OC and BO = OD, we can write:2(OA + OD) = AB + CDNow, substituting AO = OC and BO = OD, we can write:2AC = AB + CD
Finally, we can substitute the value of CD from the second equation into the first equation:2AC = AB + OC + OD⇒ 2AC = AB + AB (By substituting OC = OA and OD = OB)⇒ 2AC = 2AB⇒ AC
Therefore, AC is congruent to c .
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-3/16,7/4, -3/8 in order least to greatest
Answer:
-3/8, -3/16, 7/4
Three friends got the prize money worth $105,000. The first friend would get twice the amount of the third friend's portion. The third friend would get twice the amount of the second friend's portion. Determine the amount that each friend would receive.
Answer:
Step-by-step explanation:
The first friend would get $60,000
The second friend would get $15,000
The third friend would get $30,000
4x2 - 4x-8/2x +2
i just need someone to explain how to simplify it so i can graph it
Answer:
10-4x
Step-by-step explanation:
4×2-4x+2
8-4x+2 =10-4x
HELP! WILL GIVE BRANLIEST!
Answer:
44.71 kilometers
Step-by-step explanation:
Answer:
I would say 44.71 kilometers
Step-by-step explanation:
When you add all those values together you get 44.71.
Solve (x+1)2 =13/4 using the square root property
Answer:
Starting with the equation:
(x + 1)^2 = 13/4
We can use the square root property, which states that if a^2 = b, then a is equal to the positive or negative square root of b.
Taking the square root of both sides, we get:
x + 1 = ±√(13/4)
Simplifying under the radical:
x + 1 = ±(√13)/2
Now we can solve for x by subtracting 1 from both sides:
x = -1 ± (√13)/2
Therefore, the solutions to the equation are:
x = -1 + (√13)/2 or x = -1 - (√13)/2
Step-by-step explanation:
Your job in a company is to fill quart-size bottles of oil from a full 150-gallon oil tank. Then you are to pack 24 quarts of oil in a case to ship to a store. How many full cases of oil can you get from a full 150 -gallon oil tank?
Answer:
25
Step-by-step explanation:
150 gallons = 4 * 150 = 600 quarts.
You then put 24 of these quarts into a shipping box.
600 / 24 = 25
That means you can get 25 full cases from 150 gallons.
Triangle ABC has vertices  A (0,2), B (4,4), and C (-1,4). What are the vertices of its image with a scale factor of 4
A(0,8); B(16,16) and C(-4,16) are the vertices of triangle ABC with a scale factor of 4.
Given,
Coordinates of triangle ABC are A(0,2), B(4,4) and C(-1,4)
scale factor=4
if scale factor is 'k' then the coordinates (x,y) of any figure are scaled to (kx,ky).
Formula:
Dimension of scaled figure= Dimension of original figure * scale factor.
Let,
k=4
vertices of scaled triangle ABC be A(kx,ky), B(kx,ky) and C(kx,ky).
From formula,
\(A(kx,ky)= A(4*0,4*2) =A(0,8)\\ B(kx,ky)= B(4*4,4*4) =B(16,16)\\ C(kx,ky)= C(4*(-1),4*4) =C(-4,16)\)
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HELP ME NOW PLEASE! WILL GIVE BRAINLY!!!!!!!!!!!!!!!! PLUS 30 POINTS
Faith is driving to a concert and needs to pay for parking. There is an automatic fee of $7 just to enter the parking lot, and when she leaves the lot, she will have to pay an additional $2 for every hour she had her car in the lot. How much total money would Faith have to pay for parking if she left her car in the lot for 3 hours? How much would Faith have to pay if she left her car in the lot for tt hours?
Cost for 3 hours:
Cost for tt hours:
Answer: 13
Step-by-step explanation:
cost for 3 hours: 7+2(3)=13
cost for t hours: 7+2t
Answer:
13
Step-by-step explanation:
If f(x)= x²+12x+21 and g(x)=x+2, then the value of (f/g)(-2) is
help please!
Answer:
Undefined.
Step-by-step explanation:
g(-2) = -2 + 2 = 0
So (f/g)(-2) = ( (-2)^2 - 24 - 21)/0 which is undefined.
the mean of an iq test are normally distributed with a mean of 100 points and a standard deviaiton of 15. calculate the following probability in r using the pnorm() function. what is the probability a student taking the exam scores below 125 points?
The percentage of scores below 112 is equal to 78.81.
Let X represent a test's score. X is regularly distributed, hence
P(X < 112)
= P[(X - 100)/15 < (112 - 100)/15]
= P[ SNV < 0.8] .8]
SNV stands for Standard Normal Variable,
A normal distribution with a mean of 0 and a standard deviation of 1 is the standard normal distribution. When referring to a random variable that has this typical normal distribution, the letter Z is frequently employed.
z = (X – μ) / σ
If X is a normal random variable, represents its mean, and represents its standard deviation. The normal distribution formula is also available here.
and the value is 0.7881.
Thus, the percentage of scores below 112 is equal to 78.81.
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The full question
If the scores for a test have a mean of 100 and a standard deviation of 15, what is the percentage of scores that will fall below 112? Assuming a normal distribution
Evan is going to invest in an account paying an interest rate of 5.4% compounded annually. How much would Evan need to invest, to the nearest dollar, for the value of the account to reach $1,360 in 5 years
On solving the provided question, we can say that - the value of the simple interest will be $ 881.28.
What is interest ?Multiplying the principal by the interest rate, time, and other factors yields simple interest. Simple return equals principle times interest times hours is the marketed formula. It is easiest to compute interest using this formula. A percentage of the principle balance is how interest is most commonly computed. The interest rate on the loan is known as this percentage.
here,
we have
P = 1360;
R = 5.4 ;
T = 12
so, we get,
SI = 1360 X 5.4 X 12 /100
SI =88128/100
= 881.28
Hence, On solving the provided question, we can say that - the value of the simple interest will be $ 881.28.
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What is the length of the red segment in the graph below?
Answer: 1.32 units
Step-by-step explanation:
Need help asap please
The required value of x is 135° in the given polygon. which is the correct answer would be an option (A).
A polygon is given in the figure
According to the given question, the required solution would be as:
Number of sides = 8
The required value of x is the equal to measure of one Interior angle in the given polygon.
Interior angles of a polygon = (sides - 2) × 180°
In this case, the number of sides is 8
Sum of Interior angles = (8 - 2) × 180
Sum of Interior angles = (6) × 180
Sum of Interior angles = 1080°
the measure of one Interior angle = 180°/8
the measure of one Interior angle = 135°
Thus, the required value of x is 135°.
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Which equation has a graph that includes the point (4.5, 14)? Select all that apply.
Point (4.5, 14) lies on the following equation y = 2x + 5, y = 4x + 4 and y = 5x + 8.5. Options A, C, and D are correct.
What is the equation?The equation is the relationship between variables and is represented as y = ax +c is an example of a polynomial equation.
Since, if the point lies on the equation it must satisfy the equation and must given the given y for given x. (4.5, 14) = (x , y)
For A)
y = 2x + 5
y = 2 * 4.5 + 5
y = 9 + 5
y = 15
Similarly
the procedure can be repeated for the other option,
From the calculation, it is found that Point lies on the equation given in Options A, C, and D.
Thus, (4.5, 14) lies on the following equation y = 2x + 5, y = 4x + 4 and y = 5x + 8.5. Options A, C, and D are correct.
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The question seems to be incomplete, the option can be given as
A) y = 2x + 5
B) y = 3x + 1.5
C) y = 4x + 4
D) y = 5x + 8.5
E = 1/2x + 10
help me!!!!!!!!!!!!!
8/7 ( x - 100/220) + 4 ( x + 8/9) = 38
Find the polar coordinates of rectangular coordinates (-√2,1). Limit θ to the interval [0,2pi) and round 2 dceimal places if needed
The point (-√2,1) can also be represented as (√3, 5.18) in polar coordinates.
To find the polar coordinates of the rectangular coordinates (-√2,1), we can use the following formulas:
r = √(x² + y²)
θ = tan^⁻1(y/x)
Plugging in the given values of (-√2,1), we get:
r = √((-√2)² + 1²) = √(2 + 1) = √3
θ = tan^⁻1(1/(-√2)) ≈ 2.0344 radians
Note that since the point (-√2,1) is in the second quadrant, we need to add π to the value of θ obtained from the inverse tangent in order to obtain an angle in the interval [0,2π). Thus, we have:
θ ≈ 2.0344 + π ≈ 5.1779 radians
Rounding to 2 decimal places as needed, we get the polar coordinates of (-√2,1) as (r,θ) ≈ (√3, 5.18).
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From 1985 to 2003, the total attendance A (in thousands) at NCAA women’s basketball games can be modeled by =−1.95^3 +70.1x^2 −188+2150 where x is the number of years since 1985.
a. What is the initial value of this function (the attendance in 1985)?
b. Find the attendance for the year 1998.
Answer:
21507269Step-by-step explanation:
We assume your intended attendance equation is ...
A = -1.95x^3 +70.1x^2 -188x +2150
a. For x=0 (corresponding to 1985), the first three terms are 0, so we have ...
A = 2150 . . . . the initial value of the function
__
b. For x=13 (corresponding to 1985) we have ...
A = ((-1.95(13) +70.1)(13) -188)(13) +2150 = (44.75(13) -188)(13) +2150
= 393.75(13) +2150 = 7268.75
Attendance in the year 1998 is modeled to be about 7269.