+ H₂O
What are the coefficients for the reaction _Cl2O2O5+_H2O➪ _HCIO3 once it is balanced?

A: 1, 1, 1

B: 1, 1, 2

C: 2, 1, 1

Answer:

=342g

Explanation:

atomic mass of C = 12g

atomic mass of H =  1g

atomic mass of O = 16g

Solution;

    C12 H22 O11

= 12 (12) + 22 (1) + 11(16)

= 144+ 22 + 176

= 342g

Answer:

Convergent boundaries

Explanation:

Answer:

103 mmHg

Explanation:

To find the new pressure, you need to use the Combined Gas Law:

P₁V₁ / T₁ = P₂V₂ / T₂

In this equation, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the final pressure, volume, and temperature. You can find the new pressure (P₂) after converting the temperatures from Celsius to Kelvin.

P₁ = 365.7 mmHg                                        P₂ = ? mmHg

V₁ = 75.1 L                                                    V₂ = 242.9 L

T₁ = 33.2 °C + 273.15 = 306.35 K              T₂ = 6.5 °C + 273.15 = 279.65 K

P₁V₁ / T₁ = P₂V₂ / T₂                                           <----- Combined Gas Law

(365.7 mmHg)(75.1 L) / 306.35 K = P₂(242.9 L) / 279.65 K    <----- Insert values

89.649 = P₂(242.9 L) / 279.65 K                     <----- Simplify left side

25070.433 = P₂(242.9 L)                                 <----- Multiply both sides by 279.65

103 = P₂                                                            <----- Divide both sides by 242.9

Cycloalkanes (n=3, 4, 5):

Cyclopropane (C3H6)

Cyclobutane (C4H8)

Cyclopentane (C5H10)

Alkenes (n=3, 4, 5):

Propene (C3H6)

Butene (C4H8)

Pentene (C5H10)

Cycloalkanes are a type of organic compounds that contain a closed ring of carbon atoms. The carbon atoms in the ring are bonded to each other with single covalent bonds. Cycloalkanes are saturated hydrocarbons because they have the maximum number of hydrogen atoms that can be bonded to each carbon atom. The simplest cycloalkane is cyclopropane, which has three carbon atoms in the ring. Other examples include cyclobutane, cyclopentane, cyclohexane, and so on.

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Answer:

C

Explanation:

Nuclear energy produces radioactive waste. One example, the atomic bomb dropped on Hiroshima and Nagasaki during World War 2 killed many Japanese because of the radioactive waste in the air that caused them to get cancer and pass away as a result.

The mass of the cereal that you would need to consume can be obtained as 84.8 g

The number of moles, denoted by the symbol "n," is a fundamental unit of measurement in chemistry that represents the amount of a substance. It is used to quantify the quantity of atoms, molecules, or ions in a sample.

Number of moles of sucrose in the cereal = 11g/342 g/mol

= 0.03 moles

Now;

0.03 moles of sucrose is contained in 60 g of cereal

0.0424 moles of sucrose would contain 0.0424 moles * 60 g/0.03 moles

= 84.8 g

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The wavelength of the radiation emitted by the argon ion laser is \(4.854 * 10^-7 m\).

Wavelength is a property of any type of wave that refers to the distance between two adjacent points on the wave that is in phase, i.e., at the same point in their respective cycles. It is usually denoted by the Greek letter lambda (λ) and is measured in units of length, such as meters or nanometers.

The energy carried by the photon (E) is related to the wavelength (\(\lambda\)) through the following equation:

\(E=hc/\lambda\); where 'h' is the Plank's Constant and 'c' is the speed of light which is \(3* 10^{-7} m/s\).

We can say that

\(\lambda - hc/E\)

Now after substituting the given values, we get:

\(\lambda = (6.626 * 10^{-34} J.s * 3.00 * 10^8 m/s) / (4.071 * 10^{-19} J)\\\lambda = 4.854 * 10^-7 m\)

Therefore the wavelength of the radiation emitted by the argon ion laser is \(4.854 * 10^-7 m\).

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Calcium sulfate (CaSO4) is a chemical compound made from calcium, oxygen, and sulfur.

The major sources of calcium sulfate naturally happen are gypsum and anhydrite, which occur at many position worldwide as evaporites.

A simple procedure for preparing acicular calcium sulfate dihydrate is on condition that in which a slurry of calcium carbonate carrying 100 to 800 grams per lite of calcium carbonate is assorted with a solution of sulphuric acid carrying 80 to 500 grams per liter sulphuric acid in proportions that construct calcium sulfate.

So we can conclude that Calcium sulfate, CaSO4, is a natural happen calcium salt.

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Structural isomers are molecules with the same molecular formula but with different structural formulae. This means that they have the same number and types of atoms, but they are arranged differently. The following two organic compounds are structural isomers of each other.

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The structural formula of butanol is C4H9OH. It consists of a chain of four carbon atoms, with a hydroxyl (-OH) group attached to one of the carbon atoms. Butanol has several structural isomers, which have the same molecular formula but different structural formulas.

A structural isomer is a compound that has the same molecular formula as another compound but has a different arrangement of its atoms. A string of 4 C atoms are bonded above, below, left, and right to H, except the second C, which is bonded below to O, which is bonded below to H is a structural isomer of butanol.

This is called butan-2-ol. The structural formula of butan-2-ol is CH3CH(OH)CH2CH3. In this isomer, the hydroxyl group is attached to the second carbon atom in the chain, whereas in butanol, the hydroxyl group is attached to the first carbon atom in the chain.

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Answer:

0.43 atm

Explanation:

From the question given above, the following data were obtained:

Initial pressure (P₁) = 0.95 atm

Initial volume (V₁) = 0.55 L

Final volume (V₂) = 1.22 L

Final pressure (P₂) =?

The final pressure of the gas can be obtained by using the Boyle's law equation as follow:

P₁V₁ = P₂V₂

0.95 × 0.55 = P₂ × 1.22

0.5225 = P₂ × 1.22

Divide both side by 1.22

P₂ = 0.5225 / 1.22

P₂ = 0.43 atm

Therefore, the final pressure of the gas is 0.43 atm

The final pressure of the gas is 0.43 atm.

Pressure is the process of force exerted perpendicular to any surface.

Given, the Initial pressure (P₁) is 0.95 atm

The initial volume (V₁) is 0.55 L

The final volume (V₂) is 1.22 L

To find the final pressure (P₂)

By the Boyle's Law

\(\rm P_1V_2= P_2V_2\)

\(\rm 0.95\times 0.55 = P_2\times1.22\\\\0.5225 = P_2 \times 1.22\\\\Divided\;both \;side\;by\;1.22\\\\P_2=\dfrac{0.5225}{1.22} = 0.43 atm.\)

Thus, the final pressure of the gas is 0.43 atm.

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Answer:

an oxygen ion with -2 charge

Explanation:

because a neutral oxygen atom has 8 electrons

and in the first orbit there'll be 2 electrons

and in the second orbit there'll be 6 electrons

but here there are 8 electrons in the outermost orbit and normally there'll be only 6

which means there are extra 2 electrons

and extra electrons means negatively charged

Types of luminous flames:

1. Yellow Luminous Flame

2. Smoky Luminous Flame

3. Orange Luminous Flame

4. Blue Luminous Flame

Luminous flames are characterized by their visible glow, which is caused by the incomplete combustion of fuel. The presence of soot particles in the flame causes the emission of light. There are different types of luminous flames, which can be classified based on their fuel composition and burning conditions. Here are some common types of luminous flames:

1. Yellow Luminous Flame: This is the most common type of luminous flame, often seen in open fires, candles, and gas stoves. It appears yellow due to the presence of soot particles in the flame. Yellow flames indicate incomplete combustion of hydrocarbon fuels, such as methane, propane, or natural gas. The high carbon content in these fuels leads to the formation of soot, which emits visible light.

2. Smoky Luminous Flame: This type of flame is characterized by a significant amount of black smoke and soot production. It is commonly observed in poorly adjusted or malfunctioning burners or engines. The excessive presence of unburned fuel in the flame results in incomplete combustion and the emission of dark smoke particles.

3. Orange Luminous Flame: An orange flame indicates a higher combustion temperature compared to a yellow flame. It is often seen in more efficient burners or when burning fuels with a higher carbon content, such as oil or diesel. The higher temperature helps in burning more of the carbon particles, reducing the amount of soot and making the flame appear less yellow.

4. Blue Luminous Flame: A blue flame is typically associated with complete combustion. It indicates efficient burning of fuel, resulting in minimal soot formation. Blue flames are commonly observed in gas burners or Bunsen burners. The blue color is a result of the combustion of gases, such as methane, in the presence of sufficient oxygen.

It's important to note that the luminosity of a flame can vary depending on factors such as fuel-air mixture, combustion temperature, and the presence of impurities. Achieving complete combustion and minimizing the production of soot is desirable for efficient and cleaner burning processes.

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Answer:

letter: B

Explanation:

thats is the true answer.

pleas heart my heart my answer

The angles as shown are supplementary angles because the add up to 180 degrees.

Two angles are said to be supplementary if they add up to 180 degrees. Now we know that the sum of angles on  straight line is 180 degrees. If we look at the image as shown in the image attached, we can see that the angles lie on a straight line.

As such, we can conclude that the angles as shown are supplementary angles because the add up to 180 degrees.

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Answer:

Explanation:

From the information given :

we can understand the solute is glucose and the solvent is water,

So, the weight of glucose = 20.23 g

the molecular weight of glucose = 180.2 g/mol

weight of water = 95. 75 g

the molecular weight of water = 18.02 g/mol

pure vapor pressure of water \(P_A = 26.7 \ mmHg\) at 27°C

moles of glucose = weight of glucose/ molecular weight of glucose

= 20.23/180.2

= 0.11 mole

moles of water =  weight of water / molecular weight of water

= 95.75/18.02

= 5.31 mole

mole fraction of glucose \(X_{glucose} =\) (moles of glucose)/(moles of glucose+ moles of water)

\(X_{glucose} =\) 0.11/(0.11 + 5.31)

\(X_{glucose} =\)  0.0203

mole fraction of glucose \(X_{water} =\) (moles of water)/(moles of water+ moles of glucose)

\(X_{water} =\) 5.31/ (5.31 + 0.11)

\(X_{water} =\)  0.9797

Using Raoult's Law:

\(P_S = P^0_A \times X_A \ \ \ OR \ \ \ P_A = P^0_A \times X_A\)

where:

\(P_S\) = vapor pressure of the solution

\(P_A\) = total vapor pressure of the solution

\(P^0_A\)= vapor pressure of the solvent in the pure state

\(X_A\) = mole fraction of solvent i.e. water

\(P_A =\) 95.75 ×  0.9797

\(P_A =\)  93.81 mmHg

the total vapor pressure of the solution = 93.81 mmHg

A carbon atom that is joined to four separate atom kinds or groups is known as an asymmetric carbon atom.

Tryptophan is the only amino acid that has two rings on it. At pH 7.4, it looks like this,

You can see the chiral carbon highlighted. You can tell that it's an \($s p^3$\)carbon and that it has four different substituents on it \(( $\mathrm{H}, \mathrm{NH}_3^{+}, \mathrm{COO}^{-}$, and $\mathrm{CH}_2-$ stuff).\)

Therefore it's chiral.

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Answer:

Happy new year

Explanation:

Mucopolysaccharides are long chains of sugar molecules that are found throughout the body, often in mucus and in fluid around the joints. They are more commonly called glycosaminoglycans.

Answer:

Mucopolysaccharides are long chains of sugar molecules found throughout the body, particularly in mucus and joint fluid. Glycosaminoglycans are a more common name for them.

Explanation:

Mucopolysaccharides, also known as glycosaminoglycans (GAGs), are polysaccharides composed of repeating disaccharide units. GAGs accumulate in tissue and urine due to deficiencies in certain lysosomal enzymes.

1. For the pair of half-reactions:

Pt2+(aq) + 2e- → Pt(s)    ... (1)

Sn2+(aq) + 2e- → Sn(s)    ... (2)

To obtain the balanced equation for the overall cell reaction, we need to multiply the half-reactions by appropriate coefficients to ensure that the number of electrons transferred is equal. In this case, we can multiply equation (1) by 2 and equation (2) by 1:

2(Pt2+(aq) + 2e-) → 2(Pt(s))

Sn2+(aq) + 2e- → Sn(s)

Combining the equations, we have:

2Pt2+(aq) + Sn2+(aq) → 2Pt(s) + Sn(s)

The cell notation for this reaction is:

Pt2+(aq) | Pt(s) || Sn2+(aq) | Sn(s)

To calculate the standard cell potential (E°), we need to know the standard reduction potentials for Pt2+/Pt(s) and Sn2+/Sn(s) half-reactions. Referring to standard reduction potential tables, we find:

E°(Pt2+/Pt(s)) = +1.20 V

E°(Sn2+/Sn(s)) = -0.14 V

The overall cell potential (E°cell) is the difference between the reduction potentials:

E°cell = E°(cathode) - E°(anode) = 0.00 V - (-0.14 V) = +0.14 V

Therefore, the standard cell potential for this reaction is +0.14 V.

2. For the pair of half-reactions:

Co2+(aq) + 2e- → Co(s)    ... (3)

Cr3+(aq) + 3e- → Cr(s)    ... (4)

To balance the number of electrons transferred, equation (4) can be multiplied by 2:

2(Co2+(aq) + 2e-) → 2(Co(s))

Cr3+(aq) + 3e- → Cr(s)

Combining the equations, we have:

2Co2+(aq) + Cr3+(aq) → 2Co(s) + Cr(s)

The cell notation for this reaction is:

Co2+(aq) | Co(s) || Cr3+(aq) | Cr(s)

To calculate the standard cell potential (E°), we refer to the standard reduction potentials:

E°(Co2+/Co(s)) = -0.28 V

E°(Cr3+/Cr(s)) = -0.74 V

The overall cell potential (E°cell) is the difference between the reduction potentials:

E°cell = E°(cathode) - E°(anode) = -0.74 V - (-0.28 V) = -0.46 V

Therefore, the standard cell potential for this reaction is -0.46 V.

3. For the pair of half-reactions:

Hg2+(aq) + 2e- → Hg (l)    ... (5)

Cr2+(aq) + 2e- → Cr(s)    ... (6)

The equation for the overall cell reaction can be obtained by multiplying equation (6) by 2:

2(Hg2+(aq) + 2e-) → 2(Hg (l))

Cr2+(aq) + 2e- → Cr(s)

Combining the equations, we have:

2Hg2+(aq) + Cr2+(aq) → 2Hg (l) + Cr(s)

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Answer:

During the early Paleozoic Era, the Earth's surface was very different from what it is today. The continents were arranged differently, forming one large supercontinent called Pangea. This landmass was surrounded by a single large ocean called Panthalassa. The climate was much warmer and wetter than it is today, with no ice caps at the poles.

The first land plants, known as bryophytes, appeared during the early Silurian Period, around 430 million years ago. These plants were small and simple, lacking roots and vascular tissue. They grew in damp environments, such as along the edges of lakes and streams. They were important in the development of soils and in the colonization of land by other organisms, such as insects and other arthropods.

The range of a data set tells us that the difference between the lowest and highest values (option D).

Range in statistics is the length of the smallest interval which contains all the data in a sample i.e. the difference between the largest and smallest observations in the sample.

The range of a data set is a way to measure the central tendency of a data. It is the largest measure or central tendency.

Range describes how well the central tendency represents the data. If the range of a data is large, the central tendency is not as representative of the data as it would be if the range was small.

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Answer: ok, its C

Explanation: I used D=26.4* 3 to calculat it

Answer:

CDE

Explanation:

If your on USA test perp

The questions are most relevant to increasing the strength of the electromagnet are Does increase the current in .....?, Will increasing the number of loops of wire around the.....? and Will positioning the loops of….? Therefore, option C, D and E are correct.

The characteristics known as electromagnetic properties determine how quickly a substance will absorb or emit electromagnetic radiations.

We may be familiar with electromagnetic radiations such as radio waves, microwaves, ultraviolet rays, infrared rays, and visible light rays.

Transverse waves characterize electromagnetic radiation.They move across fluctuating magnetic and electric fields so that they are perpendicular to the wave's path of propagation and at right angles to one other.

Thus, option C, D and E are correct.

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HSO3^- is the conjugate base of H2SO3 (sulfurous acid). When it dissolves in water, it behaves as an acid. In other words, it donates a proton (H+) to a water molecule, producing hydronium ions (H3O+) and sulfite ions (SO32-). Therefore, the products that form when HSO3^- behaves as an acid in water are H3O+ (hydronium ion) and SO32- (sulfite ion).

The chemical reaction can be represented as follows:HSO3^- + H2O → H3O+ + SO32-This is an example of an acid-base reaction, in which HSO3^- is the acid and water is the base. The HSO3^- donates a proton to the water molecule, which acts as a base by accepting the proton to form H3O+.

This reaction is reversible, meaning that H3O+ can also act as an acid by donating a proton to the SO32- ion to reform HSO3^-.The sulfite ion (SO32-) is a weak base and can also react with water to form the hydroxide ion (OH-). This reaction can be represented as follows:SO32- + H2O → HSO3^- + OH-

Overall, when HSO3^- behaves as an acid in water, the products that form are H3O+ and SO32-. This reaction is an example of an acid-base reaction, in which the HSO3^- acts as an acid by donating a proton to water, which acts as a base.

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Answer:  

Sodium metaborate: sodium+boron+oxygen= NaBO 2.

The formula can be written also as Na 2O·B

Explanation:

Answer:

thermal

Explanation:

a p e x

The gravimetric factor for Br- using silver bromide is 0.425.

The gravimetric factor is an expression that is used to convert grams of a compound into grams of a single element.

It is expressed as a ratio of the formula weight (FW) of the substance that is being determined to that of a second substance that is weighed.

For example formula of silver bromide is AgBr and the formula mass of silver bromide is 188 g/mol

Formula mass of bromide ion = 80 g/mol

Gravimetric factor = 80/1188

Gravimetric factor = 0.425

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Yes, s = u+v/2+t, where s is the displacement, u is the beginning velocity, v is the end velocity, and t is the time required, is the equation of motion for a body travelling with uniform acceleration.

The basic law of motion, which states that a body's rate of change in displacement is directly proportional to its velocity, provides the basis for this equation. The equation of motion for a body travelling with constant acceleration, s = ut + 1/2at2, may be used to derive it.

The equation of motion for a body travelling with uniform acceleration is given by replacing the value of an as (v-u)/t and getting s = u+v/2+t. This formula is only accurate when the body's acceleration is constant and uniform.

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