Answer:
Explanation:18kt alloy contains
i) 75% of gold
rhogold=19.3g/cm^3
=75/100×19.3
=14.475g/cm^3
ii) 16% of silver
rhosilver=10.5g/cm^3
=16/100×10.5
=1.68g/cm^3
iii) 9% of copper
rhocopper =8.90g/cm^3
=9/100×8.9
=0.801g/cm^3
Overall density of 18kt gold
=(0.801+1.68+14.475)g/cm^3
=16.956g/cm^3
=17g/cm^3 to 3s.f
The separation distance in B is_____ times greater than in A, the force of attraction is
than A.
The separation distance in B is a number times greater than in A, then the force of attraction in B is less than A.
What is the force of attraction between two object?
The force of attraction between two charged object is determined by applying Coulomb's law.
Coulomb's law states that the force of attraction or repulsion between two charged objects is directly proportional to the product of the charges and inversely proportional to the square of the distance between the charges.
Mathematically, this law is written as;
F = Kq₁q₂/r²
where;
k is Coulomb's constantFrom the formula given above, as the distance of separation increases, the magnitude of the force of attraction between the charges decreases. Also, as the distance of separation between the charges decreases, the magnitude of the force of attraction between the charges increases.
Thus, the magnitude of the force of attraction between charged objects is a function of the magnitude of the charges and distance of separation between the charges.
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Find the Magnitude of the resultant vector (the actual
path of the boat).
The picture is a little blurry, so here are the stats:
Velocity of the boat is 0.75 m/s
Velocity of the river is 1.2 m/s
The magnitude of the resultant vector, representing the actual path of the boat, is approximately 1.42 m/s.
To find the magnitude of the resultant vector, we need to consider the boat's velocity and the velocity of the river. The boat's velocity is given as 0.75 m/s, and the river's velocity is given as 1.2 m/s.
Since the boat is moving in a river, we can think of the boat's velocity as a combination of two velocities: its own velocity and the velocity of the river. The resultant vector represents the actual path of the boat, considering both velocities.
To calculate the resultant vector, we can use vector addition. The magnitude of the resultant vector can be found by taking the square root of the sum of the squares of the boat's velocity and the river's velocity. Mathematically, we have:
Resultant magnitude = √(boat velocity^2 + river velocity^2)
Plugging in the given values, we have:
Resultant magnitude = √(0.75^2 + 1.2^2)
= √(0.5625 + 1.44)
= √2.0025
≈ 1.42 m/s
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1.) A roller coaster travels on a frictionless track as shown in the illustration.
a.) If the speed of the car at Pt A is 5.0 m/s, what is the speed at Pt B
(More in the photo provided)
For the roller coaster on a frictionless track:
a. The speed at Point A is 5.0 m/s, the speed at Point B will also be 5.0 m/s.b. The height between Points A and B where kinetic energy equals potential energy is 5.0 m.c. For the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m.d. For the car to reach Point C, the height at Point A must be greater than or equal to 8.0 m.How to solve speed and height?a. The speed of the car at Point B can be determined using the principle of conservation of energy. The total mechanical energy (sum of kinetic energy and potential energy) remains constant in the absence of external forces like friction. Therefore, if there is no energy loss, the kinetic energy at Point A is equal to the kinetic energy at Point B.
Given that the speed at Point A is 5.0 m/s, the speed at Point B will also be 5.0 m/s.
Answer: A. 5.0 m/s
b. To find the height at which kinetic energy equals potential energy, we can set the equations for kinetic energy and potential energy equal to each other.
At Point A, the roller coaster has both kinetic energy and potential energy. The total mechanical energy is the sum of these two:
Initial mechanical energy at Point A = Kinetic energy at Point A + Potential energy at Point A
At Point B, the roller coaster will have kinetic energy and potential energy, but we want to find the height at which kinetic energy equals potential energy. Let's call this height "h."
Mechanical energy at Point B = Kinetic energy at Point B + Potential energy at Point B
Since the speed at Point B is the same as the speed at Point A (5.0 m/s), the kinetic energy at both points is the same.
Equating the mechanical energy at Point A to the mechanical energy at Point B:
Initial mechanical energy at Point A = Mechanical energy at Point B
Kinetic energy at Point A + Potential energy at Point A = Kinetic energy at Point B + Potential energy at Point B
Since the kinetic energy is the same at both points, simplify the equation:
Potential energy at Point A = Potential energy at Point B
The potential energy at any point is given by the formula mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.
Therefore, at the height h between Points A and B, the potential energy equals the potential energy at Point A:
mgh = mghA
Since the mass and acceleration due to gravity are the same, cancel them out:
h = hA
This means that the height where kinetic energy equals potential energy is the same as the height at Point A.
Answer: The height between Points A and B where kinetic energy equals potential energy is 5.0 m.
c. To determine if the car will reach Point C, compare the potential energy at Point B with the potential energy at Point C. If the potential energy at Point B is greater than or equal to the potential energy at Point C, the car will reach Point C.
Potential energy at Point B = mghB
Potential energy at Point C = mghC
Given that the height at Point C is 8.0 m, compare the potential energies:
Potential energy at Point B ≥ Potential energy at Point C
mghB ≥ mghC
Since the mass (m) and acceleration due to gravity (g) are constant, cancel them out:
hB ≥ hC
Therefore, for the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m.
d. The minimum speed needed at Point A for the car to reach Point C can be determined by comparing the potential energy at Point A with the potential energy at Point C. If the potential energy at Point A is greater than or equal to the potential energy at Point C, the car will have enough energy to reach Point C.
Potential energy at Point A = mghA
Potential energy at Point C = mghC
Given that the height at Point A is 5.0 m, compare the potential energies:
Potential energy at Point A ≥ Potential energy at Point C
mghA ≥ mghC
Since the mass (m) and acceleration due to gravity (g) are constant, cancel them out:
hA ≥ hC
Therefore, for the car to reach Point C, the height at Point A must be greater than or equal to 8.0 m.
To summarize, for the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m, and the height at Point A must also be greater than or equal to 8.0 m.
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I got this information for a lab but I don't know how to do the hypothesis and the conclusion please can you guys help me with it quickly
Answer:
A hypothesis is what you think will happen.
A conclusion is the results of an experiment summarized.
Hope this helps.
11. The measurement of an object's mass is a
a. physical change
b. physical property
c. chemical
d. chemical property
change
Using the information from the movie champions what is one conclusion about the history of the sports
One of the conclusion about the history of sports that can be drawn from the movie "Champions" is that sports have a long and rich history that is intertwined with the history of human civilization.
What is Champions about?From the ancient Olympic Games to the modern-day Olympics, sports have been a way for people to come together and compete in a spirit of sportsmanship and competition. Sports have also been a way for people to express themselves, to build community, and to achieve personal goals.
The movie "Champions" tells the story of a group of young men who come together to form a football team. The team is made up of boys from different backgrounds and with different abilities. However, they are all united by their love of football and their desire to win.
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How does thermal energy change matter?
Answer:
maxed out
Explanation:
A convex mirror has a magnification of 16.6 and the mirror has a height of 5.3 cm. What is the height of the object in cm?Answer will have 2 decimal places and might not follow rules of sig figs.
So for these problems, we are going to need to use the formula
M = image height / object height
in this case, M = 16.6 and the image height is 5.3 cm
Plugging in the numbers, we get 16.6 = 5.3 cm / object height
object height = 5.3/16.6
the object is .3192... cm
rounding to 2 decimal places, the answer is .32 cm
What is the period of a pendulum that swings 20 times in 25 seconds
Answer:
We can use the formula for the period of a pendulum:
T = (2 * pi * sqrt(L/g))
where:
T = period (in seconds)
pi = 3.14159...
L = length of the pendulum (in meters)
g = acceleration due to gravity (9.81 m/s^2)
We can solve for L by rearranging the formula:
L = (T^2 * g) / (4 * pi^2)
We are given that the pendulum swings 20 times in 25 seconds. The period of one swing is the time it takes to complete one full cycle, so the period of 20 swings is 25 seconds divided by 20 swings, or 1.25 seconds.
Using this value for T and plugging in g, we get:
L = (1.25^2 * 9.81) / (4 * 3.14159^2)
L ≈ 0.153 meters or 15.3 centimeters
Therefore, the length of the pendulum is approximately 15.3 centimeters.
What game has worst Physics?
Answer:
Cyberpunk has worst Physics
A test rocket is launched by accelerating it along a 200.0-m incline at 1.60 m/s2
starting from rest at point A (the figure (Figure 1).) The incline rises at 35.0 ∘
above the horizontal, and at the instant the rocket leaves it, its engines turn off and it is subject only to gravity (air resistance can be ignored).
Question: Find the greatest horizontal range of the rocket beyond point A.
Figure 1 attached.
The greatest horizontal range of the rocket beyond point A is approximately 17.89 meters.
To find the greatest horizontal range of the rocket beyond point A, we need to analyze the projectile motion of the rocket after it leaves the incline.
We can break down the rocket's motion into horizontal and vertical components. The horizontal component remains constant, while the vertical component is influenced by gravity. Since the rocket is subject only to gravity after leaving the incline, the horizontal velocity remains constant throughout the motion.
First, let's calculate the initial velocity of the rocket in the horizontal direction. We can use the acceleration and the distance traveled along the incline to find the time taken to reach the end of the incline.
Using the equation of motion: distance = initial velocity × time + (1/2) × acceleration × time^2, we can substitute the given values:
200.0 m = 0 × t + (1/2) × 1.60 m/s^2 × t^2.
Simplifying the equation, we get:
\(1.60 t^2 = 200.0,\\t^2 = 200.0 / 1.60,\\t^2 = 125,\)
t = √125,
t ≈ 11.18 s.
Now that we have the time taken to reach the end of the incline, we can calculate the horizontal distance traveled by the rocket using the formula: distance = velocity × time.
Since the horizontal velocity remains constant at 1.60 m/s, the horizontal distance is:
distance = 1.60 m/s × 11.18 s,
distance ≈ 17.89 m.
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A race driver has made a pit stop to refuel. After refueling, he starts from rest and leaves the pit area with an acceleration whose magnitude is 7.0 m/s2; after 3.8 s he enters the main speedway. At the same instant, another car on the speedway and traveling at a constant velocity of 73.3 m/s overtakes and passes the entering car. The entering car maintains its acceleration. How much time is required for the entering car to catch up with the other car
Answer:
t = 13.3 s
Explanation:
The distance traveled by both cars once they are in the main speedway, assuming that the acceleration of the refueling car is constant, is given by the following kinematic equation:\(x = v_{o}*t + \frac{1}{2} * a * t^{2} (1)\)
The refueling car (which we will call car 1) in the moment that enters to the main speedway, has achieved a speed that can be found from the definition of acceleration, rearranging terms, as follows:\(v_{f1} = a* t = 7.0m/s2*3.8s = 26.6 m/s (2)\)
So, since vf1 = v₀ in (1), we get:\(x_{1} = v_{f1}*t + \frac{1}{2} * a * t^{2} (3)\)
Now, for the other car (which we will call car 2), due to is moving at a constant speed, a=0, so we can write the following equation for x₂:\(x_{2} = v_{f2}*t = 73.3m/s*t (4)\)
When the entering car catches up the other car, both distances will be equal each other, so x₁ = x₂, as follows:\(26.6m/s*t + \frac{1}{2} * 7.0m/s2* t^{2} = 73.3m/s*t\) Rearranging, simplifying and solving for t:\(t =\frac{2*(73.3m/s-26.6m/s}{7.0m/s2} = 13.3 s (5)\)The figure below shows electrons moving along an electric current towards and away from the light bulb.
Electrons traveling along an electric current. Arrow under electrons points right and left both towards and away from the light bulb.
Does this figure show a direct or alternating current? Explain your response.
Based on the information provided, it is likely that the figure shows an alternating current (AC). The arrows under the electrons pointing right and left, both towards and away from the light bulb, indicate that the direction of the electron flow is changing periodically. This is a characteristic of alternating current, where the flow of electric charge reverses direction periodically, typically in a sinusoidal manner.
In an AC circuit, the voltage also changes direction periodically, which is consistent with the changing direction of the electron flow shown in the figure.
In an alternating current, the flow of electrons periodically reverses direction, causing the current to switch between positive and negative values. This is different from direct current (DC), where electrons flow in a single, constant direction.
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Solve the gaussian integration with polar coordinates
Solving Gaussian integration with polar coordinates involves converting the integral into polar coordinates, finding the mean and standard deviation of the function, substituting them into the Gaussian distribution formula, and integrating it over the range of the function in polar coordinates.
Gaussian integration with polar coordinates is the process of finding the integral of a function using polar coordinates and the Gaussian distribution. The polar coordinate system is a two-dimensional coordinate system that uses the radius and angle to locate a point in a plane. The Gaussian distribution is a probability distribution that is often used to describe random variables in statistics.
To solve the Gaussian integration with polar coordinates, we need to convert the integral into polar coordinates. The conversion is done using the following equations:
x = r cos(θ)
y = r sin(θ)
r² = x² + y²
θ = tan⁻¹(y/x)
Once the integral is converted into polar coordinates, we can use the Gaussian distribution to solve it. The Gaussian distribution is given by the following formula:
f(x) = (1/σ√(2π))e^(-(x-μ)²/2σ²)
where μ is the mean of the distribution and σ is the standard deviation. To use this formula, we need to first find the mean and standard deviation of the function we are integrating.
After finding the mean and standard deviation, we can substitute them into the Gaussian distribution formula and integrate it over the range of the function in polar coordinates. The result of the integration will be the value of the integral.
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An object of mass m is attached to a vertically oriented spring. The object is pulled a short distance below its equilibrium position and released from rest. Set the origin of the coordinate system at the equilibrium position of the object and choose upward as the positive direction. Assume air resistance is so small that it can be ignored.
a. Beginning the instant the object is released, select the graph that best matches the position vs. time graph for the object.
b. Beginning the instant the object is released, select the graph that best matches the velocity vs. time graph for the object.
c. Beginning the instant the object is released, select the graph that best matches the acceleration vs. time graph for the object.
Answer:
x = A cos w * t is a good choice where w = angular frequency
a. When the object is released the displacement is a maximum and proceeds towards zero in a quarter of a cycle.
b. When the object is released the velocity is zero and proceeds towards its maximum value in a quarter of a cycle v = -w A sin w t
c. When the object is released the acceleration is a maximum since the quantity F = -K x is a maximum and the acceleration goes to zero in 1/4 cycle.
a = -w^2 A cos w t
A copper wire of resistivity 2.6 × 10-8 Ω m, has a cross sectional area of 35 × 10-4 cm2
. Calculate
the length of this wire required to make a 10 Ω coil.
Answer:
the length of the wire is 134.62 m.
Explanation:
Given;
resistivity of the copper wire, ρ = 2.6 x 10⁻⁸ Ωm
cross-sectional area of the wire, A = 35 x 10⁻⁴ cm² = ( 35 x 10⁻⁴) x 10⁻⁴ m²
resistance of the wire, R = 10Ω
The length of the wire is calculated as follows;
\(R = \frac{\rho L}{A} \\\\L = \frac{RA}{\rho} \\\\L= \frac{10 \times (35\times 10^{-4}) \times 10^{-4}}{2.6 \times 10^{-8}} \\\\L = 134.62 \ m\)
Therefore, the length of the wire is 134.62 m.
all pressure topics in physics
A physics student was studying falling bodies and decided to drop a water balloon from an outdoor stairwell to measure its speed. If the balloon was dropped a distance of 6 meters and it only took 1.1 seconds to fall, how fast was the balloon traveling on average? A. 0.2 m/s B. 6.6 m/s C. 5.5 m/s D. 66 m/s
WILL NAME BRAINLIEST
Answer:
C. 5.5 m/s
Explanation:
How fast the balloon travels is determined from the velocity or v
The formula is v = s/t or velocity equals distance divided by time
So, v = 6 meters divided by 1.1 seconds = 5.5 meters per second
Answer:
C. 5.5 m/s
Explanation:
How fast the balloon travels is determined from the velocity or v
The formula is v = s/t or velocity equals distance divided by time
So, v = 6 meters divided by 1.1 seconds = 5.5 meters per second
What is nature/nurture debate and why is it important in psychology
Collect information about the most modern techniques adapted by Nagaland and Manipur to conserve water
Answer: Nagaland use an indigenous system of conservation of rain water known as the 'Zabo' or 'Ruza' system. In this system, rain water is collected and stored in catchments along mountain slopes for irrigation and other purposes. The system combines water conservation with forestry, agriculture and animal care.
Manipur: The rainwater can be collected from various hard surfaces such as rooftops and other hard surfaces above ground surfaces. Rains are the main sources of water in Manipur and if rainwater is harvested, the scarcity of water in the state can beeliminated or minimize the water stress in the state during the dormant season.
Describe how the appearance of the fringes changes if the slit is made wider
The diffraction pattern narrows with increasing slit width. The interference pattern is produced by the intersection of the two diffraction patterns.
What is the explanation for diffraction?Despite the fact that light waves typically pass close to barriers, where they tend to bend and spread out, light waves do not always move in straight lines as we traditionally believe. Waves spreading as they move through or around an obstruction is referred to as diffraction.
What does diffraction versus refraction mean?When waves move from one medium to another, the direction they travel in changes, which is known as refraction. A shift in wavelength and speed always occurs with refraction. Waves bend over gaps and obstructions in a process known as diffraction. When the wavelength gets longer, more diffraction occurs.
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Your tutor says atomic nuclei are converted to nuclear energy in a nuclear reaction. why should you seek a new tutor?
Answer:
The answer is "Momentum and net Energy(that contains mass)".
Explanation:
No matter which type of nuclear reaction, the momentum always is maintained. According to the formula, E = mc^2 of Einstein, energy conservation on the atomic level requires the change in mass of its core which may have been shared throughout the reaction as mass and energy, that's why we can say that the nuclei aren't fully converted into electrical energy rather rearranged and the mass could be changed and dispensed to the nucleon as energy.
The motor of a table saw is rotating at 3450 rev/min. A pulley attached to the motor shaft drives a second pulley of half the diameter by means of a V-belt. A circular saw blade of diameter 0.208 m is mounted on the same rotating shaft as the second pulley.
Answer: It should be the answer beginning like this
The linear spread is that
The radial acceleration of locations along the blade's outer edge is approximately 17580 \(m/s^2\).
What is Radial acceleration?Radial acceleration describes the acceleration of an object travelling on a circular path towards the circle's center. It can be defined as the rate of change of tangential velocity with regard to time and is also known as centripetal acceleration.
Given:
A table saw's engine rotates at 3450 revolutions per minute.A V-belt connects a pulley that's attached to the motor shaft to a second pulley half the diameter.A 0.208 m circular saw blade is installed on the same rotating shaft as the second pulley.We know that the motor is rotating at 3450 rev/min. One revolution is equal to 2π radians, so we can convert the motor speed to radians per minute:
ω₁ = (3450 rev/min) x (2π rad/rev) = 21675π rad/min
The second pulley is half the diameter of the first pulley, so its angular speed, ω₂, is twice that of ω₁:
ω₂ = 2ω₁ = 43350π rad/min
The circular saw blade is mounted on the same shaft as the second pulley, so it also rotates at the same angular speed:
ω = ω₂ = 43350π rad/min
We can now calculate the linear speed of the small piece of wood moving at the same rate as the rim of the circular saw blade, indicated by v. The circumference of the circle is supplied by the rim of the circular saw blade:
C = πd = π(0.208 m) = 0.6548 m
The linear speed of the little piece of wood is equal to the tangential speed of the circular saw blade's rim:
v = ωr
where r is the circular saw blade's radius, given by half its diameter:
r = d/2 = 0.208/2 = 0.104 m
By substituting the values, we obtain:
v = r = (43350 rad/min) x (0.104 m) x (1/60) = approx. 23.0 m/s
As a result, the linear speed of the little piece of wood moving at the same rate as the rim of the circular saw blade is about 23.0 m/s.
Next, compute the radial acceleration of locations on the blade's outer edge, represented by. The radial acceleration is calculated as follows:
α = rω²
By substituting the values, we obtain:
r2 = (0.104 m) x (43350 rad/min)2 x (1/602) = 17580 m/s2 (approximate)
Therefore, the radial acceleration of points on the outer edge of the blade is approximately 17580 m/s². This high radial acceleration explains why sawdust doesn't stick to the teeth of the saw blade.
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Your question is incomplete, most probably the complete question is:
The motor of a table saw is rotating at 3450{\rm rev/min}. A pulley attached to the motor shaft drives a second pulley of half the diameter by means of a V-belt. A circular saw blade of diameter 0.208{\rm m}is mounted on the same rotating shaft as the second pulley.
The operator is careless and the blade catches and throws back a small piece of wood. This piece of wood moves with linear speed equal to the tangential speed of the rim of the blade. What is this speed?
v =_______________________ m/s
Calculate the radial acceleration of points on the outer edge of the blade to see why sawdust doesn't stick to its teeth.
\alpha=______________________m/s2
Which of the following is most likely the caption for the illustration that was scratched out of the textbook?
A. An electrically-charged object can attract an uncharged object with magnetic properties.
B. An electrically-charged object is stronger than a magnet.
C. A dry cell battery has magnetic properties.
D. An electric circuit can only have one dry cell battery.
IMAGE DOWN BELOW OR UP
The correct statement is " A dry cell battery has magnetic properties.", The correct option is C.
A dry cell battery does generate its own magnetic field due to the flow of electric current through the battery.
The magnetic field is created by the movement of charged particles (electrons) within the battery. This magnetic field is relatively weak and is not typically strong enough to be used for practical applications outside of the battery itself.
So, the magnetic properties of the dry cell battery are important for understanding its behavior within an electrical circuit.
Therefore, The correct answer is option C.
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How is charge transferred from one object to another? What dictates which way the charge moves?
A charge can transfer from one object to another in one of the three ways: Conduction, friction and polarization.
The potential difference causes the charges to move. The direction in which a charge moves depends on the sign of the charge. A negative charge moves from negative potential towards positive potential. A positive charge moves from positive potential towards negative potential.
What would scratch a mineral that registers 8 on the Moh’s hardness scale?
is it Topaz? Please correct me if I'm wrong
Answer:
topaz is 8 so no
Explanation:
it would be diamond
A smooth circular cylinder of radius 1.5m in a triangular grove, one side of which makes 15 °angle and the other 40° angle with the horizontal · Find the reaction. at the surface of contact, if there. is no fiction and the cylinder weigh 100N
Answer:
46.5 N
Explanation:
attached is explanation
A simple mass spectrometer may include an electron ionization (EI) source and magnetic sector mass analyzer. In this type of instrument, singly charged ions are produced and accelerated through the slit to the analyzer by applying high potentials to accelerator plates. If an ion with mass 400 amu and charge z = 1 is accelerated by a potential of 4000 V, what is its kinetic energy (in J)?
Answer:
K.E = 6.4 × 10⁻¹⁶
Velocity = 4.39 × 10⁴ m/sec
Explanation:
From the given information:
The average K.E = P.E (potential energy)
Thus, K.E = q × V
K.E = 1.6 × 10⁻¹⁹ × 4000 V
K.E = 6.4 × 10⁻¹⁶
However,
\(K.E = \dfrac{1}{2}mv^2\)
\(6.4 \times 10^{-16} = \dfrac{1}{2}(400 \times 1.66 \times 10^{-27} ) \times v^2\)
\(\dfrac{6.4 \times 10^{-16} }{\dfrac{1}{2}(400 \times 1.66 \times 10^{-27} )}= v^2\)
\(v^2=1.92771084 \times 10^9\\ \\ v=\sqrt{ 1.92771084 \times 10^9} \\ \\ v = 43905.7 \\ \\ \mathbf{v = 4.39 \times 10^4 \ m/sec}\)
How does methodology in natural science influence knowledge produced
6. A spring is originally 1.5 m long. It is stretched so that it is 1.8 m long. The spring constant is 50 N/m.
Find the potential energy stored in the spring.
Answer:
PE = 1/2 K X^2
K = 50 N/m
X = .3 m
PE = 1/2 * 50 * .3^2 = 2.25 Joules