Glucose, C6H12O6, is best described as a(n) ______. compound. Which of the following is NOT a property of water? It is denser when frozen than when liquid.

Answer:

Explanation:

Carbon

Mercury is used as a liquid in barometers because it has a high density, which means it can accurately measure small changes in atmospheric pressure.

Additionally, mercury is less affected by temperature changes compared to water, which can expand or contract with changes in temperature, affecting the accuracy of the measurement. Mercury also has a low vapor pressure, which means it will not evaporate easily and will remain in the barometer for a long time.

However, it is important to note that mercury is toxic and can be harmful to both humans and the environment if it is not handled and disposed of properly.
Mercury is used in barometers because it has several advantageous properties. Firstly, its high density allows for a shorter column, making the device more compact. Additionally, mercury's low vapor pressure reduces evaporation, ensuring accurate pressure measurements. Moreover, mercury's high surface tension prevents it from sticking to the barometer's glass walls, leading to precise readings. Finally, it does not freeze at standard atmospheric temperatures, allowing for consistent functionality. These properties make mercury a more suitable choice than water for measuring atmospheric pressure in barometers.

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Answer:

Explanation:

3.

Knowns: 100mL of solution; concentration of 0.7M

Unknown: number of moles

Equation: number of moles = volume * concentration

Plug and Chug: number of moles = 100/1000 * 0.7 = 0.07 mole

Final Answer: 0.07mole

2.

Knowns: 5.50L of solution; concentration of 0.400M

Unknown: number of moles

Equation: number of moles = volume * concentration

Plug and Chug: number of moles = 5.5 * 0.4 = 2.20 mole

Final Answer: 2.20 mole

Moles of solute be x

#1

\(\\ \rm\Rrightarrow Molarity=\dfrac{Moles\:of\:solute}{Volume\:of\'solution}\)

\(\\ \rm\Rrightarrow 0.7=\dfrac{x}{0.1}\)

\(\\ \rm\Rrightarrow x=0.1(0.7)\)

\(\\ \rm\Rrightarrow x=0.07mol\)

#2

Same like before

\(\\ \rm\Rrightarrow \dfrac{x}{5.5}=0.4\)

\(\\ \rm\Rrightarrow x=5.5(0.4)\)

\(\\ \rm\Rrightarrow x=2.20mol\)

Answer:

A)0.450 mol N2

B)294 g NH4 NO3

Explanation:Step by step! make sure when you see underneath the multipication eqaution that we are deviding!The arrows is what we are dividing

A)36.0gN H4N O3×1 molN H4NO3×2mol N2

        ↑ 1                   ↑ 80.05gNH4NO3 ↑2mol N H4N O3

B)7.35molH2O×2mol N H4 N O3×80.05gN H4 N O3

    ↑    1                 ↑  4molH2O             ↑   1mol N H4N O3

5) 2 and for the how many moles it is 10.9

Hope this helps!

Answer:

Which of the following substances are ionic?

Check all that apply.

AlCl3

MgI2

C2H5OH

NH3

Explanation:

An ionic substance is formed between a positively charged cation and a negatively charged anion.

Ionic substances are generally formed from metal and nonmetal atoms with the metal atoms forming the cations and the nonmetal atoms forming the anions.

Among the given substances,

MgI2 is an ionic substance.

Since Mg is the metal atom. It forms a cation.

I is a  nonmetal atom. It forms anion.

Hence,

MgI2 is an ionic substance.

Though AlCl3 looks like an ionic substance it is a covalent compound.

This is due to the high polarizability of \(Al^3+\) ion.

The remaining two compounds do not contain any metal atoms.

So, ethanol and NH3 are not ionic compounds.

Answer:

MgI2

The empirical formula of the solvent is CH4.

Relative number of atoms

Of H= 25/1 = 25

Of C= 75/12 = 6.25

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The gas is Argon.

To identify the gas, we need to compare the number of moles calculated for each gas with the given density.

Let's calculate the number of moles for each gas and compare them:

Given:

Density = 1.17 × 10^(-6) g/cm^3

Pressure = 1.00 × 10^(-3) atm

Temperature = 60.0 °C = 60.0 + 273.15 = 333.15 K

Molar mass of Oxygen (O2) = 32.00 g/mol

Molar mass of Neon (Ne) = 20.18 g/mol

Molar mass of Hydrogen (H2) = 2.02 g/mol

Molar mass of Chlorine (Cl2) = 70.90 g/mol

Molar mass of Argon (Ar) = 39.95 g/mol

Molar mass of Nitrogen (N2) = 28.02 g/mol

For Oxygen (O2):

n = (PV) / (RT) = (1.00 × 10^(-3) atm) × (1.17 × 10^(-6) g/cm^3) / ((0.0821 L × atm/(mol × K)) × 333.15 K)

n = 5.88 × 10^(-12) mol

For Neon (Ne):

n = (PV) / (RT) = (1.00 × 10^(-3) atm) × (1.17 × 10^(-6) g/cm^3) / ((0.0821 L × atm/(mol × K)) × 333.15 K)

n = 9.26 × 10^(-12) mol

For Hydrogen (H2):

n = (PV) / (RT) = (1.00 × 10^(-3) atm) × (1.17 × 10^(-6) g/cm^3) / ((0.0821 L × atm/(mol × K)) × 333.15 K)

n = 9.26 × 10^(-11) mol

For Chlorine (Cl2):

n = (PV) / (RT) = (1.00 × 10^(-3) atm) × (1.17 × 10^(-6) g/cm^3) / ((0.0821 L × atm/(mol × K)) × 333.15 K)

n = 2.58 × 10^(-12) mol

For Argon (Ar):

n = (PV) / (RT) = (1.00 × 10^(-3) atm) × (1.17 × 10^(-6) g/cm^3) / ((0.0821 L × atm/(mol × K)) × 333.15 K)

n = 4.64 × 10^(-12) mol

For Nitrogen (N2):

n = (PV) / (RT) = (1.00 × 10^(-3) atm) × (1.17 × 10^(-6) g/cm^3) / ((0.0821 L × atm/(mol × K)) × 333.15 K)

n = 6.45 × 10^(-12) mol

Comparing the number of moles calculated for each gas with the given density, we find that the gas with the closest value is Argon (Ar). Therefore, the gas is Argon.

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Answer:

21409

Explanation:

Please give the brainliest.

Answer:

solid(particles are rightly packed)

liquid(particles are losely packed)

gas(particles move freely)

Explanation:

there u go, hope it helps

Answer:

True

Explanation:

because hydrogen is the first element and the atomic mass is 1 and after that the atomic number is kept increase

The type of fatty acid which do not bind together due to the bend in the structure ae unsaturated fatty acids which have branched chain structures.

The unsaturated fatty acids are those which have one or more carbon-carbon double bonds. For example: palmitoleic acid, oleic acid are considered as unsaturated fatty acids. The unsaturated fatty acids cannot be tightly packed due to which it makes them easier to pass more fluidly through the body.

The monounsaturated fatty acids are also liquid at room temperature due to the bend structure. On the other hand, saturated fatty acids can be easily packed as they are generally straight chain compounds.

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Answer:

A. Wild life survey

Explanation:

The only answer that involved observing the wild life

Answer:

Ethanamine (also known as ethylamine)

Explanation:

The compound that is requested by the question is ethanamine. Its trivial name is ethylamine.

It is a compound that contained the ethyl moiety (CH3CH2-) as well as the amine moiety (-NH2).

Ethanamine has a structure that can easily be determined by the statements in the question.

The structure of ethanamine is shown in the image attached.

Answer:

What is the name of this compound?

                                                                                    H       H

                                                                                    │       │

                                                               H ── N ── C ── C ── H

                                                                          │       │        │

                                                                          H      H        H

❌ A) ethanal

❌ C) ethanoic acid

❌ D) methyl ethanoate

I Took Question Test And Have Day.

The diffusion coefficient is 4.39x10-12 m2/s.

Given information;

Initial nitrogen concentration, c₀ = 0.08 wt %

Nitrogen concentration to be achieved, cₙ = 0.52 wt %

Diffusion coefficient, D = 9.10E-05 m²/s

Temperature, T = 1100 K

Activation energy, Qd = 168 kJ/mol

Gas constant, R = 8.31 J/mol K

To find;

Diffusion coefficient at 1100 K using Arrhenius equation;

The Arrhenius equation for diffusion coefficient is given as;

D = D₀ exp(-Qd / R T)

where; D₀ is the diffusion coefficient at an infinite temperature.

Substituting the given values of D, Qd, R, and T into the equation above;

D = 9.10E-05 m²/s

Qd = 168 kJ/mol

R = 8.31 J/mol

KT = 1100 K

At 1100 K, the value of kT is;

kT = R T

     = 8.31 J/mol K x 1100 K

     = 9141 J/mol

Multiplying by Avogadro's number to get the value in J;

9141 J/mol x (6.022 x 10²³) / (1 mol) = 5.50 x 10²⁹ J-1

                                                          = 5.50 x 10²⁹ m²/kg

Multiplying by the Boltzmann constant to get the value in m²/s;

K = 1.38 x 10⁻²³ J/KD₀ can now be obtained by rearranging the Arrhenius equation as;

D₀ = D / exp(-Qd / R T)

Substituting the values into the equation;

D₀ = 9.10E-05 m²/s / exp(-168 x 10³ J/mol / 8.31 J/mol K x 1100 K)D₀

     = 9.10E-05 m²/s / exp(-21.36)D₀

     = 9.10E-05 m²/s / 1.29E-09D₀

     = 7.05E-04 m²/s

Therefore, the diffusion coefficient at 1,100 K if k = 8.31 is;

D = D₀ exp(-Qd / R T)D

   = 7.05E-04 m²/s exp(-Qd / R T)D

   = 7.05E-04 m²/s exp(-168 x 10³ J/mol / 8.31 J/mol K x 1100 K)

D = 7.05E-04 m²/s exp(-21.36)D

   = 4.39 x 10⁻¹² m²/s

Therefore, the correct option is 4.39x10-12 m2/s.

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The distance that a molecule moves can be graphed as a straight line when compared to: the log of the molecular weight of the proteins.

Correct option is D. the log of the molecular weight of the proteins.

This is known as the "Laws of Electrophoresis", which states that the rate at which different sized molecules move through a gel has an inverse relationship to the molecular weight of the particles being separated. The smaller the size of the particles, the faster they will move, and the greater the charge benefit due to the Coulombic effect.

The ultimate result is that the greater the molecular weight of the molecule being separated, the longer the distance it will travel, thus forming a straight line when graphed on a logarithmic scale. This allows one to calibrate their electrophoresis gels and to accurately estimate the molecular weight of a given set of samples.

This process is a highly effective tool used to isolate and identify different molecules, making it a key technique in many fields.

Correct option is D. the log of the molecular weight of the proteins.

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Complete question is:

When electrophoretic separations are done based on molecular weight, the distance that a molecule moves can be graphed as a straight line when compared to:

A. The molecular weight of the proteins

B. MW /2

C. None of these the negative of the molecular weight of the proteins

D. the log of the molecular weight of the proteins

The volume of the balloon will be 2.70 L after 0.85 moles of gas are released, assuming that the pressure and temperature are held constant.

The ideal gas law can be used to solve this problem: PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is temperature in Kelvin. Since the pressure and temperature are held constant, we can use the formula PV = constant to relate the initial and final volumes of the balloon.

P1V1 = P2V2
P2 = P1
V2 = P1V1 / P2
V2 = (49.05 atm)(2.00 L) / (3.15 mol)(0.0821 L•atm/mol•K)(298 K)
V2 = 2.70 L

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Answer:

It's A.

Atoms that have the same number of valence electrons in their outer shell have similar properties and belong to the same family of elements.

Explanation:

Y has 13 protons and we know that Aluminium (Al) too has 13 protons.

So , element Y = Aluminium

• In an element , no. of protons = no. of electrons. So , Y has 13 electrons.

• Mass no. of Y (Aluminium) = 27.

• Also we know that ,

Mass number = no. of protons + no. of neutrons

So,

No. of neutrons = 27 - 13 = 14

• Valence electrons are the electrons which are present in the outermost shell of an element.

Electronic Configuration of Y = 2,8,3

So, Y has 3 valence electrons.

• We know that Y is Aluminium & Aluminium is a metal. So , Y is a metal.

• Valency of Y = +3

In a 60g sample of tetraethyl-lead, a gasoline is addictive, is found to contain 38.43g lead, 17.83g carbon and 3.74g hydrogen, its empirical formula is PbC₆H₂₀.

The term Empirical formula is defined as the chemical formula of a compound that gives the ratios of the elements present in the compound but not the actual numbers or arrangement of atoms.

The percentage mass of Pb = 38.43/60 × 100

= 64.05 %

The percentage mass of C = 17.83/60 × 100

= 29.71%

The percentage mass of H = 3.74/60 × 100

= 6.23%

Now,

Pb → 64.05/207

= 0.3094

C ⇾ 29.71/12

= 2.475

H ⇾ 6.23/1

= 6.23

Therefore, the ratio is as follows:

Pb : C : H = 1 : 8 : 20

Thus, empirical formula is PbC₆H₂₀.

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When considering only cycloalkanes and ignoring stereoisomers, there are five constitutional isomers for the formula C6H12.

The constitutional isomers for C6H12 can be determined by considering different arrangements of carbon atoms in a cyclic structure. The possible constitutional isomers for C6H12 are as follows:

Cyclohexane: It consists of a six-membered carbon ring with all single bonds.

Methylcyclopentane: It contains a five-membered carbon ring with an additional methyl (CH3) group attached.

Ethylcyclobutane: It consists of a four-membered carbon ring with an additional ethyl (C2H5) group attached.

Dimethylcyclopropane: It contains a three-membered carbon ring with two additional methyl (CH3) groups attached.

Trimethylcyclopropane: It consists of a three-membered carbon ring with three additional methyl (CH3) groups attached.

These five constitutional isomers represent all the different ways the C6H12 formula can be arranged in cycloalkane structures, disregarding stereochemistry.

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Answer:

The plum pudding model is one of several historical scientific models of the atom. ... The plum pudding model has electrons surrounded by a volume of positive charge, like negatively-charged "plums" embedded in a positively-charged "pudding".

Answer:

mass

Explanation:

Answer:

mass mass mass mass mass

Answer:

A

Explanation:

Answer:a

Explanation:cuz ik  this

Charge flowed : 240 Coulombs

Given

t = time = 60 s

I = current = 4 A

Required

Charge

Solution

General formula :

Q = I x t

Q = charge (electricity), C

Input the value :

Q = 4 x 60

Q = 240 Coulombs

Answer:

See answer below

Explanation:

To understand this, we need to make the reaction involved with the given configuration. Configuration R means that the substituents of the molecule, the priority order goes clockwise (From heaviest to lightest) so, if an Sn2 is ocurring in the reaction this means that the nucleophile, which in this case, is the sodium ethoxide will attack the molecule in the opposite side of the leaving group (which is the chlorine).

Also when this occurs, as Sn2 is a bimolecular reaction and is held in one step, it occurs an inversion in the configuration of the product. So, it's the innitial reactant was R, then the final product will be S.

The mechanism and product can be watched in the attached picture

Hope this helps.

The enthalpy of the liquid coming out of the condenser is 2600 kJ/kg.

In a condenser, vapor is converted to liquid by transferring heat out of the vapor. In this case, the vapor has an enthalpy of 2600 kJ/kg. The rate of heat transfer within the condenser is given as 25 MW.

To determine the enthalpy of the liquid coming out of the condenser, we need to consider the conservation of energy. The heat transfer within the condenser is equal to the change in enthalpy of the vapor as it condenses. Since the vapor is being converted to liquid, the enthalpy of the liquid coming out will be the same as the initial enthalpy of the vapor, which is 2600 kJ/kg.

This means that the enthalpy of the liquid coming out of the condenser is 2600 kJ/kg.

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